Eadweard Muybridge(The horse in motion)
How was the horse in motion created?The horse in motion created by Cameras took stills at evenly-spaced points on a horseracing track to create the illusion of continuous motion.
The series became the first example of chronophotography, an early method to photographically record the passing of time, mainly used to document the different phases of locomotion for scientific study. It formed an important step in the development of motion pictures for years to come.
Therefore,
Eadweard Muybridge (The horse in motion),
Horse in motion is a famous series of photographs documenting a horse in motion were made possible by a number of cameras placed side by side as a horse broke each wire.
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Which of the motion variables is the same in both thex and y axis?
A) velocity
B) acceleration
C) time
D) displacement
Answer:
Acceleration (b) not sure tho
Explanation:
Brian Berg of lowa built a house of cards 4.88 m tall. Suppose Berg throws a ball from ground level
with a velocity of 9.98 m/s straight up. What is the velocity of the ball as it first passes the top of
the card house?
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f}^{2}=v_{o}^{2}-2*g*x\)
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
\(v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]\)
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
Una ambulancia se desplaza por la calle a 34 m/s emitiendo un estruendoso sonido de sirena a 304 Hz, Si usted se ALEJA de la ambulancia a 1 m/s. ¿Cuál será la frecuencia que usted percibe?
Answer:
f = 295.06 Hz
Explanation:
Este es un típico ejercicio de efecto doppler donde tenemos una fuente emisora de una frecuencia.
En este caso, vemos una ambulancia que se está desplazando a cierta velocidad emitiendo una frecuencia particular. Un observador que está en la calle decide alejarse, corriendo a una velocidad, que obviamente es menor que la de la ambulancia, pero el caso es que se está alejando de la fuente emisora del sonido, en este caso de la ambulancia.
Como se están alejando, podemos usar la siguiente expresión:
f = (v - v₀ / v) * f₀
Donde:
f: frecuencia percibida por la persona.
v: velocidad de la ambulancia
v₀: velocidad de la persona
f₀: frecuencia emitida por la ambulancia.
Teniendo todos esos valores, solo debemos reemplazar en la expresión:
f = (34 - 1 / 34) * 304
f = (33/34) * 304
f = 295.06 HzEspero te ayude
Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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(Newton's Law of Cooling): The mathematical formulation of Newton's empirical law of cooling/warming of an object is given by the linear first-order differential equation
dt
dT
=k(T−T
s
), where k is a constant of proportionality, T(t) is the temperature of the object at any time t≥0, and T
s
is the surrounding environmental temeperature, that is, the temperature of the medium around the object. (i). Assuming that T
s
is constant, find the temeperature of the object as a function of time if T(0)=T
0
. (ii). Then what is the temepretauer of the object after 5 minutes?
Newton's Law of Cooling is described by the first-order linear differential equation dt/dT = k(T - Ts), where T(t) is the temperature of the object at time t, Ts is the surrounding environmental temperature, and k is the constant of proportionality.
The temperature of an object, governed by Newton's Law of Cooling
(i) To find the temperature of the object as a function of time, we first solve the differential equation dt/dT = k(T - Ts). This is a separable differential equation, and the solution can be obtained by rearranging and integrating:
dt/dT = k(T - Ts)
dt = k(T - Ts) dT
∫ dt = ∫ k(T - Ts) dT
t = k * ∫ (T - Ts) dT
t = k * (T^2/2 - Ts*T) + C
Now, we apply the initial condition T(0) = T0. At t=0, the temperature of the object is T0:
T(0) = T0
k * (\(T0^2\)/2 - Ts*T0) + C = T0
C = T0 - k * (\(T0^2\)/2 - Ts*T0)
C = T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2
C = T0 - k * (\(T0^2\) - 2 * Ts * T0) / 2
So, the equation becomes:
t = k * (\(T^2\)/2 - Ts*T) + (T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2)
(ii) Now, we can find the temperature of the object after 5 minutes (t = 5 minutes). We'll use the initial condition T(0) = T0 and the formula obtained in part (i):
t = 5 minutes = 5/60 hours = 1/12 hours
T(t) = Ts + (T0 - Ts) * exp(-kt)
T(1/12) = Ts + (T0 - Ts) * exp(-k * (1/12))
This equation gives us the temperature of the object after 5 minutes, considering the given initial temperature T0 and the surrounding environmental temperature Ts.
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A resting state through the winter.
Adaptation: Bear sleeping in a cave during the winter months
0 A. Locomotion
B. Hibernation
C. Migration
D. Defense
Answer:
b
Explanation:
Bears hibernate in the winter
10. A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
What is the formula of area science
Answer:
Ans
Explanation:
Length*Breadth
oK
That's it
Answer:
Length×breadth
Explanation:
L × B hope it help youシ︎
Which statement correctly describes the relationship between frequency and wavelength?
A :As the frequency of a wave increases, the longer its wavelength is
B: As the frequency of a wave increases, the shorter its wavelength is.
C: As the frequency of a wave increases, its wavelength remains the same.
Answer:
Answer:
Option B
Explanation:
Option B talks about how the frequency of the wave increases the shorter it's wavelengths
Answer:
b
Explanation
B: As the frequency of a wave increases, the shorter its wavelength is.
The demon drop rode at cedar point amusement park falls freely for 4.33 an after starting from rest. What is it’s velocity at the end of this time?
The velocity of the rode at the end of the time 4.33 seconds is 42.434 m/s.
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity of the, we use the formula below.
Formula:
v = u+gt................. Equation 1Where:
v = Velocity at the end of the timeu = Initial velocityg = Acceleration due to gravityt = TimeFrom the question,
Given:
u = 0 m/s (From rest)g = 9.8 m/s²t = 4.33 secondsSubstitute these values into equation 1
v = 0+9.8×4.33v = 42.434 m/sHence, the velocity at the end of the time is 42.434 m/s.
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When negative charges concentrate at one end of an object that is made of a conducting material, the object is
ANSWER:
polarized
STEP-BY-STEP EXPLANATION:
When negative charges are concentrated at one end of an object that is made of a conductive material, this happens when the object is polarized.
What type of relationship do frequency and wavelength have?
Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.
A model rocket is launched from the ground. It starts from rest and accelerates upward at 15.0 m/s2 for 3.00 s. Disregard gravity. What is the V2? b. Then, it has a downward acceleration of -10.0 m/s2 until it reaches its highest point. What is the highest above the ground that the rocket gets? c. What is the TOTAL time in the air?
Answer:
The final velocity v₂ is 45 m/s
The highest point reached by the rocket is 101.25 m
The total time spent in air by the rocket is 7.5 s
Explanation:
Given;
initial velocity of the rocket, v₁ = 0
final velocity of the rocket, v₂ = ?
upward acceleration of the rocket, a = 15 m/s²
time of acceleration, t = 3 s
The final velocity is given by;
v₂ = v₁ + at
v₂ = 0 + (15 x 3)
v₂ = 45 m/s
The highest point reached by the rocket is given by;
v² = u² + 2ah
where;
u is the initial velocity of rocket when it started decelerating.
thus, u = v₂
v is the final velocity of the rocket at its highest point = 0
0 = v₂² + 2ah
0 = (45)² + (2 x -10 )h
0 = 2025 - 20h
20h = 2025
h = 2025 / 20
h = 101.25 m
Time taken for the rocket to reach its highest point is given by;
h = ut + ¹/₂at²
101.25 = 45t + ¹/₂(-10)t²
101.25 = 45t - 5t²
5t² - 45t + 101.25 = 0
t² - 9t + 20.25 = 0
t = 4.5 s
The total time spent in air by the rocket is given by;
T = upward time + downward time
T = 3 s + 4.5 s
T = 7.5 s
A tennis ball rolls off the edge of a table. the table is 0.55m tall and the tennis ball lands 0.12m away from the table.
Answer:
v = 0.363 m/s
Explanation:
Given that,
The table is 0.55m tall and the tennis ball lands 0.12m away from the table.
Here, u = 0 (at rest) for initial vertical velocity as it rolls off the edge of a table.
Let t is the time to fall from the vertical height. So,
\(h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 0.55}{9.8}} \\\\t=0.33\ s\)
It can be assumed to find the initial horizontal velocity of the tennis ball. It can be given by :
\(v_x=\dfrac{x}{t}\\\\v_x=\dfrac{0.12}{0.33}\\\\v_x=0.363\ m/s\)
Hence, the initial horizontal velocity is 0.363 m/s.
what can i about charges that were made against me but dropped by the pwerson who made them but are still on record
If you have charges that were made against you but were dropped by the person who made them but are still on record, you can still take steps to address the situation. It is important to note that having charges on your record can have negative effects on your life, such as hindering your ability to secure employment and housing.
To address this situation, you may need to seek legal advice or the assistance of a criminal defense attorney. They will be able to guide you through the process of getting the charges removed from your record, or having them expunged. This will involve filing a petition to the court, providing evidence that the charges were dropped, and demonstrating that you meet the eligibility criteria for expungement or record sealing
. The process may vary depending on your location and the type of charges you faced, so it is important to seek guidance from a legal professional.To summarize, if you have charges that were made against you but were dropped by the person who made them but are still on record, you can seek legal advice or the assistance of a criminal defense attorney to have the charges removed from your record through a petition to the court.
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In the decimal number 40.04672, what number is in the 100th's (hundredths, 1/100s)place?
Answer:
6
Explanation:
because the numbers before the decimal point are whole numbers so that would mean the 4 & 0 before the points the ones and tens place. and anything behind a decimal goes in order as usual ones,tens,hundredths, thousandths, ten thousandths, and so on. so that what makes the 6 be in the hundredths place.
A gas has a variable volume.
True
False
Answer:
True
Explanation:
Gas always live in free state but some gas is not . We can said that mostly gas volume can be changeable during disturbing by environment situation.
A restaurant records the number of tables served each night, and the results have the values: minimum = 3, lower quartile = 14, median = 23, upper quartile = 29, and maximum = 40. Which box plot represents the data?
To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.
How to identify the median?In a box plot, this value is represented by a vertical line located in the middle of the graph.
How to identify the maximum and the minimum?The maximum is the value located on the farthest right, while the minimum is located on the farthest left.
How to identify the quartiles?Divide the graph into 4 and analyze how much each quartile represents.
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Answer:
To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.
Explanation:
which particles most likely will be dispositive first as a velocity of a stream carrying a mixture of particles decreases
As the velocity of a stream carrying a mixture of particles decreases, the heaviest particles will most likely be deposited first. This phenomenon is known as sedimentation.
The process of sedimentation separates particles of different sizes and densities from a mixture by allowing them to settle at different rates due to gravity. The heavier particles settle faster than lighter ones. Therefore, they are the first to be deposited.Sedimentation can occur naturally or artificially. For example, in a river, sedimentation can occur naturally due to changes in water flow and velocity. Artificial sedimentation can be used in water treatment plants to remove impurities from water
The heaviest particles will most likely be deposited first as the velocity of a stream carrying a mixture of particles decreases.Explanation: This is due to the process of sedimentation, which separates particles of different sizes and densities from a mixture by allowing them to settle at different rates due to gravity. The heavier particles settle faster than lighter ones, and hence they are the first to be deposited.
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A marble is released from rest at the top of a ramp and it rolls down the ramp for 5 seconds. The position of the marble is shown once every second. The angle of the ramp allows the force due to gravity to accelerate the marble at 4.5 m/s^2. How far does the marble travel from the top of the ramp after 5 seconds?
The marble travel from the top of the ramp is 56.25 m.
Ramp is can be understand in physics, such as the inclined planes, also referred to as ramps . That means,ramp is a type of simple machine which manipulate the direction and magnitude of a force. It is very useful machine by which we can understand the problems in mechenics .
We are given that,
The marble rolls down from the ramp in time = t = 5s
Acceleration of the marble due to gravity = a = 4.5 m/s²
Therefore , for getting the distance (s) of the marble which travelled from the top of the ramp by using the equation of motion i.e. given as,
s = ut + (1/2) at²
Here the marble released from thew rest at the top of the ramp so that initial velocity u = 0 , therefore after putting the value above equation can be written as,
s = (1/2)× 4.5 m/s²×5s × 5s
s = 56.25 m
Hence, the marble travel from the top of the ramp 56.25 m after 5 seconds.
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L 6.3.2 Test (CST): Applications of Waves Question 5 of 10 Which event provides evidence that matter can reflect waves? O A. An audience member covers her ears during a loud concert. B. A laser beam bounces off a series of mirrors. C. A performer makes shadow puppets on a wall. D. The light from a fireworks show is seen miles away.
An audience member covers her ears during a loud concert shows evidence that matter can reflect waves.
Which event provides evidence that matter can reflect waves?An audience member covers her ears during a loud concert is an event that provides evidence that matter can reflect waves because a sound is heard again and again due to the reflection of waves. This repetition of sound is due to the property of reflection of sound waves.
So we can conclude that an audience member covers her ears during a loud concert shows evidence that matter can reflect waves.
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Answer:
A laser beam bounces off a series of mirrors
Explanation:
a) how many seconds will it take a 10.0 hp motor to lift a 2000 lb elevator a distance of 19.3 feet?
It will take the 10.0 hp motor 5.18 seconds to lift the 2000 lb elevator a distance of 19.3 feet.
The time it will take a 10.0 hp motor to lift a 2000 lb elevator a distance of 19.3 feet can be determined using the formula for work, which is
Work = Force × Distance.
In this case, the force is the weight of the elevator, which is 2000 lbs, and the distance is 19.3 feet. Therefore, the work done is:
Work = Force × Distance = 2000 lbs × 19.3 feet = 38600 ft-lbs
To convert the work done to time, we use the formula for power, which is
Power = Work ÷ Time.
Here, the power of the motor is 10.0 hp, which is equivalent to 7457 watts.
Therefore, we can substitute the values we have into the formula to solve for time:
Power = Work ÷ Time7457 watts = 38600 ft-lbs ÷ TimeTime = 38600 ft-lbs ÷ 7457 watts = 5.18 seconds
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The time it would take a 10.0 hp motor to lift a 2000 lb elevator a distance of 19.3 feet would be 7.01 seconds. This is calculated using the conversions and the concept of power which is work done per unit time.
Explanation:To calculate how many seconds it will take a 10.0 hp motor to lift a 2000 lb elevator a distance of 19.3 feet, we need to understand the relationship between power, force, distance and time. Power (P) is the rate at which work is done, or energy is transferred. In this case, we can use the formula P = work/time. The work done in lifting the elevator can be found by multiplying the force (weight of the elevator) by the distance.
First, convert the power from horsepower to watts: 1 hp = 745.7 watts, so 10.0 hp = 7457 watts. Secondly, convert the weight of the elevator to Newtons (N), knowing that 1 lb is approximately equals to 4.448 N, thus 2000 lbs = 8896 N. Lastly, convert the distance from feet to meters: 1 foot = 0.3048 meters, therefore 19.3 feet = 5.88 meters.
The work done is therefore 8896 N * 5.88 m = 52303.68 Joules. Using the power formula P = work/time, we can rearrange to solve for time: time = work / power, thus the time taken is 52303.68J / 7457W = 7.01 seconds.
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What is the correct answer to the following product? NOTE: You must use the appropriate number of significant figures. 2.856 x 0.45
Using the appropriate number of significant figures, the product of 2.856 x 0.45 is 1.3.
The correct answer to the product 2.856 x 0.45 is 1.2852. However, we must use the appropriate number of significant figures. The number with the least amount of significant figures in the product is 0.45, which has two significant figures. Therefore, the final answer should also have two significant figures.
To round to two significant figures, we look at the third significant figure. If it is 5 or greater, we round up the second significant figure. If it is less than 5, we keep the second significant figure as is. In this case, the third significant figure is 8, so we round up the second significant figure from 2 to 3.
Therefore, the final answer with the appropriate number of significant figures is 1.3.
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Fill in the blank with either “insulators” or “conductors” to complete the sentence. The conductivity of a material is determined by the number of free electrons. have few or no free electrons.
Answer:
Insulators is the correct answer
Explanation:
A few electrons make up the insulators, which allow for very little electrical current to flow. While the conductors are excellent electrical conductors. Rubber is a poor insulator compared to metal, which is a very good conductor.
What are insulators?The insulator is a material that consists of a few electrons and they permit very little flow of electrical current. While the conductors are very good conductors of electricity. Metal is a very good conductor while rubber is a poor insulator.
Hence the answer is conductors possess free electrons, while insulators have few free electrons
The conductor has thus been used for wiring purposes and can be effectively used made to use energy; The insulator is a poor absorber and thus are unable to transfer energy.
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a magnet at rest inside a coil of wire will induce a current.
a. true
b. false
The given statement "a magnet at rest inside a coil of wire will induce a current" is true. Option A. As the magnet is moved in and out of the coil, an electric current is induced.
Faraday's law of electromagnetic induction states that if there is a change in magnetic flux linkage through a coil of wire, an emf is induced in the coil. This emf induces an electric current if a circuit is present around the coil. Thus, a magnet at rest inside a coil of wire will induce a current. As the magnet is moved in and out of the coil, the magnetic field around the coil changes, which induces an emf in the coil. This emf causes a current to flow in the coil if there is a closed circuit around it. Answer option A.
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A car with a mass of 1,200 kg has a
velocity of 30 m/s west. What is the car's
momentum?
Answer:
slow
Explanation
because it weighs 1,200 kg and has a velocity of 30 m/s west. with all the friction causing it to become slower.
When 2 small figures are both pulling in the same direction, their individual forces are
Answer:
The net force is equal to the sum of the two forces
Explanation:
Forces Acting in the Same Direction
If two forces act on an object in the same direction, the net force is equal to the sum of the two forces. This always results in a stronger force than either of the individual forces alone.
Experiment 1: Exploring Charge with Scotch® Tape
In this experiment, you will observe the behavior of charged objects using pieces of Scotch® tape.
Materials
Scotch® Tape
Ruler
*Pen
*Flat Work Surface
Procedure
Part 1
1. Use the ruler to measure a piece of tape that is 10 cm long.
2. Tear the tape to remove the 10 cm piece from the roll.
3. Create a "handle" on one side of the piece of tape by folding down the piece of tape 1 cm from the end, leaving a 9 cm sticky piece with a 1 cm handle.
4. Stick the entire sticky surface of the tape to a table top, counter top, or another flat surface.
5. Repeat Steps 1 – 4 with a second 10 cm piece of tape. Stick the second piece of tape at least 15 cm away from the first piece on the same surface.
6. Quickly pull off both strips of tape from the surface and ensure that the pieces do not touch.
7. Carefully bring the non-sticky sides of the tape together and record observations about the behavior of the pieces in Table 1.
8. Discard the tape.
Part 2
1. Use the ruler to measure a piece of tape that is 10 cm long.
2. Tear the tape to remove the 10 cm piece from the roll.
3. Create a "handle" on one side of the piece of tape by folding down 1 cm of tape from one end.
4. Stick the entire sticky surface of the tape to a table top, counter top, or another flat surface.
5. Use a pen and write "B1" on the tape. "B" stands for bottom.
6. Repeat Steps 1 – 4 with a second 10 cm piece of tape. This time, press the second strip of tape on top of the one labeled "B1".
7. Use the pen to label the top piece with a "T1". "T" stands for top.
8. Create a second pair of pieces of tape by repeating Steps 1 – 7. This time, label the bottom piece "B2" and the top piece "T2".
9. Use the T1 handle to quickly pull off T1 strip of tape from the flat surface.
10. Use the B1 handle to peel off the bottom strip from the flat surface. Keep both B1 and T1 pieces away from each other.
11. Bring the non-sticky sides of B1 and T1 together and record observations about the behavior of the pieces in Table 1.
12. Set the pieces of tape, non-sticky side down, on the table approximately 15 cm away from each other. Do not stick them back on the table!
13. Repeat Steps 9 - 12 for B2 and T2.
14. Carefully bring the non-sticky sides of piece "T1" and "B2". Record observations about the behavior of the pieces in Table 1.
15. Set them back down, non-sticky side down.
16. Repeat Steps 14 - 15 for "T1" and "T2". Record your observations in Table 1.
17. Repeat Steps 14 - 15 for "B1" and "B2". Record your observations in Table 1.
18. Repeat Steps 14 and 15 for "T1" and the hair on your leg or arm. Record your observations in Table 1.
19. Repeat Steps 14 and 15 for "B1" and the hair on your leg or arm. Record your observations in Table 1.
Table 1: Electric Charge Observations
procedure
interacting pieces observation
Part 1 Two pieces on table Part 2 T1 / B1 T2 / B2 T1 / B2 T2 / B1 B1 / B2 T1 / Arm Hair B1 / Arm Hair ***The observation is filled.
Post-Lab Questions
1. Describe the interaction between the top and bottom strips as they relate to electric charge. Did the behavior of the pieces change when the tape was from different sets?
2. Describe the interaction between two top and two bottom pieces of tape as they relate to electric charge. Is this consistent with the existence of only two types of charge? Use your results to support your answer.
3. Did the top tape attract your arm hair? Did the bottom tape attract your arm hair? Usually arm hair is neutral; it has equal number positive and negative charges. Use this information to explain your results.
4. Which pieces of tape are positively charged? Which pieces of tape are negatively charged? Explain your reasoning.
5. Use your data to create a rule describing how like charges, opposite charges, and neutral bodies interact.
6. What do you observe about the force of attraction or repulsion when the pieces of tape are closer together and farther apart? Does this change happen gradually or quickly?
1.When the non-sticky sides of the two pieces of tape recording are brought together, they repel each other. This is due to the buildup of electric charge on the face of the tape recording when it was hulled off from the flat face.
2.The pieces didn't change when the tape recording was from different sets. When two top or two nethermost pieces of tape recording are brought together, they repel each other.
3.When a top and nethermost piece of tape recording are brought together, they attract each other. This is harmonious with the actuality of only two types of charge, positive and negative. The results support the fact that the top and nethermost pieces of tape recording had contrary charges. The top tape recording attracted the arm hair, while the bottom tape recording didn't attract the arm hair. Arm hair is generally neutral, but it can be concentrated by the electric field of the charged tape recording.
4.The top tape recording is negatively charged, and it concentrated the arm hair, which has a positive charge. This redounded in magnet between the top tape recording and the arm hair. The pieces of tape recording labeled" T1" and" B2" are appreciatively charged, while the pieces of tape recording labeled" B1" and" T2" are negatively charged. This can be determined from the compliances.
5.When the appreciatively charged tape recording was brought near to a negatively charged tape recording, they attracted each other. When two appreciatively charged videotapes or two negatively charged videotapes were brought near together, they repelled each other. Like charges repel each other, contrary charges attract each other, and neutral bodies aren't affected by electric fields.
6.The force of magnet or aversion between the pieces of tape recording increases as they get near together and decreases as they move further piecemeal. This change happens gradationally, not snappily.
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do you think your real?
Answer: Yes I am alive.
3) A photon is emitted as the electron in a hydrogen
atom drops from the n = 5 energy level directly to
the n = 3 energy level. What is the energy of the
emitted photon?
(1) 0.85 eV
(2) 0.97 eV
(3) 1.51 eV
(4) 2.05 eV
From the information provided and the calculations, the energy of the drop is 1.51 eV
What is the Rydberg formula?The Rydberg formula is used to obtain the energy of a photon or the wavelength of a photon.
Thus;
1/λ = 1.097 * 10^7 (1/3^2 - 1/5^2)
1/λ = 1.097 * 10^7(0.11 - 0.04)
λ = 1.3 * 10^-6 m
Since;
E = hc/λ
E = 6.6 * 10^-34 * 3 * 10^8/1.3 * 10^-6
E = 1.51 * 10^-19 J or 1.51 eV
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Answer:
0.97eV
Explanation:
The energy emitted during n=5 is 0.54 eV
The energy emitted during n=3 is 1.51 eV
(This information is on the Physics Reference Table 2006 edition)
We find the change in the energy level which is:
1.51eV-0.54eV = 0.97eV
Therefore the energy emitted by the photon is 0.97eV.