The new initial pressure of CO₂ in the reduced volume container, before it reaches equilibrium, will be 1.43 times the original pressure (P).
To determine the new initial pressure of CO₂ in the reduced volume container, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature is held constant.
Given that the initial volume of the container is reduced from 2.50 L to 1.75 L, the volume is decreased by a factor of (1.75 L / 2.50 L) = 0.7.
Since volume and pressure are inversely proportional, the pressure will increase by the reciprocal of the volume change factor. Therefore, the new initial pressure of CO₂ will be (1 / 0.7) times the original pressure.
Let's assume the original pressure of CO₂ in the container was P (before it reaches equilibrium). Then, the new initial pressure of CO₂ in the reduced volume container will be:
New initial pressure = (1 / 0.7) * P = 1.43 * P
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what rule/principle states that electrons fill orbitals from lowest energy to highest enegery?
Answer:
The Aufbau Principle
Explanation:
In the ground state of an atom or ion, electrons fill atomic orbitals of the lowest available energy level before occupying higher-energy levels.
Answer:
Aufbau principle
Explanation:
edge 2021
How many moles of sodium hypobromite (NaOBr) should be added to 1.00 L of 0.050 M hypobromous acid (HOBr) to form a buffer solution of pH 8.80? (A) 0.079. (B) 0.050. (C) 0.021. (D) 0.010. (E) 0.110.
0.050 moles of sodium hypobromite (NaOBr) should be added to 1.00 L of 0.050 M hypobromous acid (HOBr) to form a buffer solution of pH 8.80.
The pH of the buffer solution is given as 8.80, which means the pOH is 14.00 - 8.80 = 5.20.
The equilibrium expression for the reaction between hypobromous acid and hypobromite is:
HOBr + OBr^- <=> HOOBr
The pKa of HOBr is 8.63, which means the Ka is 10^(-8.63) = 1.51 x 10^(-9).
The Henderson-Hasselbalch equation for a buffer is:
pH = pKa + log([A^-]/[HA])
where [A^-] is the concentration of the conjugate base (hypobromite) and [HA] is the concentration of the acid (hypobromous acid).
Substituting the values given in the question, we get:
8.80 = 8.63 + log([OBr^-]/[HOBr])
log([OBr^-]/[HOBr]) = 0.17
[OBr^-]/[HOBr] = 1.48
We want the buffer to have a volume of 1.00 L and a concentration of 0.050 M.
Let x be the number of moles of NaOBr required. We know that the moles of HOBr in the buffer must equal the moles of OBr^- in the buffer, so:
0.050 mol/L x 1.00 L = (x mol/L) / (1.00 L)
x = 0.050 mol
Therefore, 0.050 moles of NaOBr should be added to 1.00 L of 0.050 M HOBr to form a buffer solution of pH 8.80.
The answer is (B) 0.050.
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plsssss helppppp asapppppppppp
Answer:
Under the concept of popular sovereignty, the people of each territory would decide whether or not slavery would be permitted.
Explanation:
hopes this help 3> D:
how do fossils get inside rocks
Explanation:
It to be fossilized, the remains usually to be covered by sediment soon after death. sediment can include the sandy seafloor,lava,and even sticky tar. Over time, minerals in the sediment seep in to remains. The remains become fossilized.
Describe two models that show how earth and the sun move in space relative to each other.
the wittig reaction can be used for the synthesis of conjugated dienes such as 1-phenyl- penta-1,3-diene. propose two different sets of organic reagents that could be combined in a wittig reaction to give 1-phenyl-1,3-pentadiene. you do not need to show the phosphorous reagent.
The Wittig reaction can indeed be used to synthesize conjugated dienes like 1-phenyl-penta-1,3-diene. Here are two different sets of organic reagents that can be combined in a Wittig reaction to give 1-phenyl-1,3-pentadiene:
Benzaldehyde and ethyl 2-bromopropanoate: In this case, the Wittig reaction can be carried out by treating benzaldehyde with ethyl 2-bromopropanoate, resulting in the formation of 1-phenyl-1,3-pentadiene. Benzaldehyde and dimethyl 2-bromo-2-methylpropanoate: Another set of reagents that can be combined in a Wittig reaction is benzaldehyde and dimethyl 2-bromo-2-methylpropanoate.
This combination would also lead to the synthesis of 1-phenyl-1,3-pentadiene. It's important to note that the phosphorus reagent, which is typically used in the Wittig reaction, is not specified in this question. However, it plays a crucial role in facilitating the reaction.
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Is freezing an endothermic or exothermic process? how do you know?.
Answer:
When water becomes a solid, it releases heat, warming up its surroundings. This makes freezing an exothermic reaction
Explanation: i think
you decide to blow bubbles (soapy water) outside on a snowy day. which answer best explains what has happened to the molecule arrangement of the water?
The water molecule positioning has become farther apart, forming rings. Thus, B is the correct option.
The molecules at the surface of water do not have water molecules above them to cling to, so they grow a stronger bond with the water molecules which are adjacent to them. Thus, the surface of the water develops a thin, flexible ‘skin’. Scientists call this surface tension.
Surface tension acts a bit like an elastic layer. Some insects can walk on water because their weight is little enough so it does not break through the surface tension. If we look carefully at the insect’s feet, we can see that the water looks as if it is stretched.
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The correct question is:
you decide to blow bubbles (soapy water) outside on a snowy day. which answer best explains what has happened to the molecule arrangement of the water?
A) The WATER molecule ARRANGEMENT has become CLOSER.
B) The WATER molecule ARRANGEMENT has become FARTHER APART, forming rings.
C) The WATER molecule ARRANGEMENT has become CLOSER, forming squares.
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An ethylene glycol solution contains 30.8 g of ethylene glycol (C2H6O2) in 96.6 mL of water. (Assume a density of 1.00 g/mL for water.) Determine the freezing point of the solution. Determine the boiling point of the solution
The freezing point of the solution is -11.8 °C.
The boiling point of the solution is 103.31 °C.
To determine the freezing point of the solution, we can use the equation:
ΔTf = Kf * m
where:
ΔTf is the freezing point depression,
Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),
m is the molality of the solution (moles of solute per kilogram of solvent).
First, let's calculate the molality (m) of the solution:
Molar mass of ethylene glycol (C2H6O2):
C = 12.01 g/mol
H = 1.01 g/mol (x 6) = 6.06 g/mol
O = 16.00 g/mol (x 2) = 32.00 g/mol
Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol
Number of moles of ethylene glycol (C2H6O2) = mass / molar mass
Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol
Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g
Now, let's calculate the molality:
Molality (m) = moles of solute / mass of solvent (in kg)
Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg
Now we can calculate the freezing point depression (ΔTf):
ΔTf = Kf * m
ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C
To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):
Freezing point = 0 °C - 11.8 °C = -11.8 °C
To determine the boiling point of the solution, we can use the equation:
ΔTb = Kb * m
where:
ΔTb is the boiling point elevation,
Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),
m is the molality of the solution (same value as calculated before: 6.36 mol/kg).
ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C
To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):
Boiling point = 100 °C + 3.31 °C = 103.31 °C
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What type of stress results when two plates converge? Compression Shear Hot spot
Answer:
Compression
Explanation:
Hi! When two convergent plates collide, they should create compressive pressure, or compression.
a piece of magnesium with a mass of 5.867 g was heated in a crucible which was open to the air. after the magnesium had combusted and allowed to cool down the product was found to have a mass of 8.956 g. i. determine the empirical formula of the magnesium oxide formed. ii. the actual empirical formula of magnesium oxide is mgo. suggest three possible reasons why the value obtained in the experiment described above did not produce the correct formula.
The empirical formula for magnesium oxide is Mg₅O₄.
The empirical formula is defined as the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles. So calculate the molar ratio of Mg to O.
Mass of magnesium oxide = mass of Mg + mass of O
8.956 g = 5.867 g + mass of Oxygen
Mass of Oxygen = (8.956– 5.867) g = 3.08 g
Moles of Mg=(5.867g Mg×1 mol Mg) / 24.3g Mg=0.24 mol Mg
Moles of Oxygen =(3.08g O×1 mol O) / 16.00g O = 0.192 mol O
Element mass moles ratio integers
Magnesium 5.867 0.24 1.25 × 4 5
Oxygen 3.08 0.192 1 × 4 4
The empirical formula of magnesium oxide is Mg₅O₄.
b)
Students sometimes get different results from these tests. These might lead to change in emperical formula:-
1.) Magnesium oxide product can escape as they lift the lid
2). Not all magnesium is likely to react (the product may look grayer than white)
3.) they are more likely to run the product with their splint so it's not all rated (more common than you might expect)
4.) misalignment when measuring size
5.) that magnesium is tightly bound so that it does not turn over.
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3. what will happen if ammonia is added to a mixture of ag , fe3 and co2 ? describe the subsequent steps that could be performed to separate the three cations.
When ammonia is added to a mixture of Ag+, Fe3+, and CO32-, Ag+ ions will form a soluble complex with ammonia to form [Ag(NH3)2]+ while Fe3+ and CO32- will remain in their original forms.
To separate the three cations, the following steps can be performed:Precipitation of Ag+ as Ag(NH3)2Cl: The mixture is treated with a chloride salt, such as NaCl, to form a precipitate of AgCl, which can be filtered out.Precipitation of Fe3+ as Fe(OH)3: The mixture is treated with an alkali, such as NaOH, to form a precipitate of Fe(OH)3, which can be filtered out.Removal of CO32- by complexation: The mixture can be treated with a complexing agent, such as EDTA, to form a soluble complex with CO32-, which can be removed by filtration or extraction.You can learn more about ammonia at
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Please select the word from the list that best fits the definition.
Science lab, bring water and sodium
a) term calendar
b) weekly schedule
c) daily organizer
Answer:
C. Daily Organizer. Also called an agenda. We usually write notes in them for school related things so the answer is pretty self explanatory.
A 1. 477 g sample of khp required 30. 27 ml of naoh solution to reach endpoint. Calculate the molarity of the NaOH.
The molarity of the NaOH is 0.238 M when 1. 477 g sample of KHP required 30. 27 ml of NaOH solution to reach endpoint.
Calculation ,
Mass of KHP = 1. 477 g
Number of moles of KHP = given mass / molar mass of KHP
Number of moles of KHP = 1. 477 g × 1 mol / 204.23 g KHP = 0.007 mol
Since , one mole KHP requires one mole of NaOH .
Number of moles of NaOH required by 0.007 mol of KHP = 0.007 mol
Molarity of NaOH = number of moles / volume in lit = 0.007mol/0.03027ml = 0.238 M
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How many meters did a car travel if it went 65mi/hr for 4.5 hours?
Answer:
292.5
Explanation:
65x4=260
65 divded by 2 = 32.5
260+32.5=292.5
write at balanced equation for the reaction of sulfuric acid with barium hydroxide.
The double replacement reaction between barium chloride and sulfuric acid has the balanced equation 2BaCl + H2SO4 Ba2SO4 + 2HCl.
The exchange of components from two ionic compounds to create two new compounds is known as a double replacement reaction. Another name for the double replacement reaction is the double displacement reaction.
A type of reaction called a twofold displacement reaction involves the transfer of a portion of one reactant by a portion of another reactant. The formula for the double displacement reaction is AB + CD AD + CB. For instance, AgCl + NaCl = AgNO3 + NaCl. An illustration of a twofold replacement reaction is the interaction of sulfuric acid wh barium chloride.
The balanced equation is therefore 2BaCl + H2SO4 Ba2SO4 + 2HCl for the double replacement reaction between barium chloride and sulfuric acid.
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calculate the ph of 1.00 l of a buffer that is 1.00 m in acetic acid and 1.00 m in sodium acetate after the addition of 0.400 mole of naoh.
Initial moles of sodium acetate = acetic acid = 1 m * 1 L = 1 moles
Concentration of acetate after adding NaOH = 1 mole + 0.40 mole = 1.40 M
Concentration of acetic acid after adding NaOH = 1 mol - 0.40 mol = 0.60 M
According to Handerson - Hasselblach equation:
pH = Pka + ㏒ [ acetate]/[acetic acid]
we know that,
for acetic acid, pKa = 4.74
so, by substitution:
∴pH = 4.74 + ㏒[1.40/0.60]
∴ pH = 5.10
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Which of the following is NOT a part of adenosine diphosphate?
glucose, ribose, adenine, two phosphate groups
Answer:
a. glucose c. ribose b. adenine d. two phosphate groups user: all organisms need energy to perform different functions. cells are able to ...
1. Compare endothermic and exothermic reactions. Include an explanation of enthalpy in your comparison and provide examples to support your comparison
2. Describe the relationship between particle collisions and the rate of chemical reactions. What is the collision theory and why is it important?
Endothermic and exothermic reactions are two types of chemical reactions that differ in terms of the heat energy involved and the direction of heat flow.
Endothermic reactions absorb heat energy from the surroundings, resulting in a decrease in temperature. These reactions have a positive change in enthalpy (ΔH), meaning that the products have higher energy than the reactants. An example of an endothermic reaction is the process of photosynthesis, where plants absorb energy from sunlight to convert carbon dioxide and water into glucose and oxygen.Exothermic reactions release heat energy into the surroundings, leading to an increase in temperature. These reactions have a negative change in enthalpy (ΔH), indicating that the products have lower energy than the reactants. Combustion reactions, such as burning wood or fuel, are common examples of exothermic reactions.Enthalpy (H) is a thermodynamic quantity that represents the total heat content of a system. It includes both the internal energy of a system and the work done by or on the system. In the context of chemical reactions, the enthalpy change (ΔH) represents the heat energy exchanged during the reaction. For endothermic reactions, ΔH is positive, while for exothermic reactions, ΔH is negative.The rate of a chemical reaction is closely related to the frequency and effectiveness of particle collisions. The collision theory states that for a reaction to occur, particles must collide with sufficient energy and proper orientation.
Particle collisions play a crucial role in chemical reactions because they bring reactant molecules into close proximity, allowing them to interact and form new products. When particles collide, their kinetic energy determines whether the collision will result in a successful reaction. If the collision has sufficient energy (equal to or greater than the activation energy), and the particles are correctly oriented, they can overcome the energy barrier and undergo a chemical transformation.The collision theory helps explain factors that influence reaction rates, such as temperature, concentration, and catalysts. Increasing the temperature provides particles with more kinetic energy, leading to a higher collision frequency and increased reaction rate. Similarly, higher reactant concentrations increase the likelihood of collisions and, consequently, the reaction rate. Catalysts work by providing an alternative reaction pathway with lower activation energy, enabling more successful collisions and accelerating the reaction.Understanding the collision theory is essential for predicting and controlling reaction rates, optimizing reaction conditions, and designing efficient chemical processes.
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4. Consider a gas sample with a volume of 10 L at a pressure of 0. 500 atm. What volume will this gas sample occupy if the pressure is increased to 2. 00 atm? Assume that the temperature remains constant and the gas sample obeys the ideal gas law. (2pts)
quickly pls
10.0 L volume will this gas sample occupy if the pressure is increased to 2. 00 atm.
What is volume?Volume is a measure of the amount of space an object occupies. It is a three-dimensional measure, meaning that it takes into account length, width, and height. Volume is measured in cubic units, such as cubic meters (m³), cubic centimeters (cm³), cubic feet (ft³), and so on. Volume is an important concept in many scientific fields, such as chemistry, physics, and engineering.
The volume of the gas sample can be calculated using the ideal gas law equation: PV = nRT
where P is the pressure, V is the volume, n is the amount of substance, R is the ideal gas constant, and T is the temperature.
Since the temperature and amount of substance remain constant, we can rearrange the equation to solve for V: V = nRT/P
Plugging in the known values, we get:
V = (n)(0.0821 atm•L/mol•K)(298 K)/(2.00 atm)
V = 10.0 L
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1a.calculate the relative formula mass of magnesium oxide when the relative atomic masses are O=16 Mg=24
1b.calculate the percentage by mass of magnesium in magnesium oxide
here's the answer to your question
The relative mass of the magnesium oxide (MgO) is equal to 40 g. The percentage by mass of magnesium in MgO is 60 %.
What is the mass percentage?The mass percentage of any element in a particular compound can be calculated from the number of parts by mass of the element in 100 parts by mass of a given compound.
Calculate the molar mass of the given compound by adding the atomic masses of the present elements. Then, the percentage of each element can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.
Given, the molecular formula of magnesium oxide is MgO. The atomic mass of Mg and O is 24 g and 16 g respectively.
The relative formula mass of the MgO = 40 g/mol
The mass percentage of the Mg = (24/40) × 100 = 60 %
Therefore, the mass percentage of the Mg in MgO is equal to 60 %.
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Mrs. Hillis runs 5.6 miles every evening. How far does she run in feet? (5,280 ft = 1
mile)
Answer:
29565 feet
Explanation:
multiply 5.6 by 5280
Which type of soil can retain the greatest amount of water?One that has low permeabilityOne that has low porosityOne that has high permeabilityOne that has high porosity
The type of the soil that can retain the greatest amount of the water is the one that has high prosperity. The clay soil has retain the mor amount of the water.
The porosity means the space in between the soil particles, that will filled with air or the water. The clay soil has the large pore space , that means it can retain the greatest amount of the water. The clay soil has the greatest water holding capacity. The clay soil has the high porosity and least permeable.
Thus, the soil which can retain the greatest amount of the water is the soil with the high porosity.
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Q1) You isolate evolutionarily very similar sucrases from E. coli and from a thermophilic microorganism. They catalyze the same reaction. You compare the rates of sucrose hydrolysis at 37C. Which one of the following will be TRUE for BOTH enzymes? The final extent of glucose + fructose formation will be lesser for the E. coli enzyme (final extent = ratio of products/reactants). The final extent of glucose + fructose formation will be greater for the E. coli enzyme (final extent = ratio of products/reactants). The −ΔG ∘ for catalysis will be greater for the E. coli enzyme The −ΔG ∘ for catalysis will be the same for both enzymes
The right response is d. Both enzymes will have the same ΔG for catalysis.
The reaction rate and equilibrium constant have an impact on the Gibbs free energy (ΔG). No matter the source of the enzyme, such as E. coli or a thermophilic microbe, the ΔG for a reaction is the same. As a result, both enzymes will have the same ΔG for sucrose hydrolysis.
The ΔG may be written mathematically as:
ΔG = -RT ln (K)
T is the temperature, K is the equilibrium constant, and R is the gas constant..
As both enzymes have the same reaction rate (K) and temperature (T), the reaction's ΔG value will likewise be the same.
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How much heat is required to raise the temperature of 20.0g of ice from-12°C to 0°C?
Answer:
https://socratic.org/questions/how-much-heat-is-required-to-convert-5-88-g-of-ice-at-12-0-c-to-water-at-25-0-c-
Explanation:
Which state of matter represented by the particles
Answer:
A solid
the internolecular forces are packed and leave no space behind
An isotope has a half life of 5 minutes. How much of a 100 gram sample of this isotope is left after 20 minutes?
Answer:
6.25 gram
Explanation:
Applying,
R = R'(\(2^{a/n}\))................ Equation 1
Where R = Original mass of the isotope, R' = mass of the isotope left after disintegration, a = Total time, n = half life.
make R' the subject of the equation
R' = R/(\(2^{a/n}\))................. Equation 2
From the question,
Given: R = 100 gram, a = 20 munites, n = 5 minutes.
Substitute these values into equation 2
R' = 100/(\(2^{20/5}\))
R' = 100/\(2^{4}\)
R' = 100/16
R' = 6.25 gram
the amount of fluorine in a metal fluoride is 14.96%. 2 Chromium are connected to the metal when metal chromate is formed. What is the relative atomic mass of the metal
Answer:
The relative atomic mass of the metal is 207.2 u
Explanation:
Metal chromate
Given that;
1) The mass of fluorine is 14.96% of the metal fluoride
2) 2 Chromium are connected to the metal when the metal chromate, CrO²⁻, is formed
We have;
Number of ions available in the metal = Cr₂O₇²⁻ = +2 ionic
Molar mass of fluorine = 18.998 g/mole
Ionization of fluorine = -1
Number of moles of fluorine required per metal +2 ion= 2 moles
3) Number of moles of fluorine per mole of compound of the metal fluoride = 2 × moles
Mass of fluorine per mole of compound = 2 × 18.998 = 37.996 grams
Percentage by mass of fluorine = 14.96%
Fluoride
Let the mass of the compound = X
Therefore;
14.96% of X = 37.996 grams
X = 37.996/(0.1496) = 253.984 grams
Therefore the mass of the metal in the compound = 253.984 - 37.996 = Molar mass 215.99 grams
Given that the metal forms a chromate with 2 chromium atoms and a mass of 215.99 grams, the likely candidate is lead, Pb with a molar mass of 207.2 grams and a chromate of Pb(CrO₄)₂.
The fluoride, lead fluoride, F₂
The relative atomic mass of lead is 207.2 u
How many different uncharged (neutral) stable hydrogen atoms can you build? In the space below, briefly describe the similarities and differences in their composition.
The number of different uncharged (neutral) stable hydrogen atoms which one can build is two and the similarity is that they both have a single proton while the difference is that one has a neutron while the other has zero neutron.
What is an Atom?This is referred to as the smallest particle of an element which can exist and has subatomic particles such as proton and neutron.
The different uncharged (neutral) stable hydrogen atoms which one can build include:
1p & 0n & 1e1p & 1n & 1eFrom this we can infer that they both have one proton and electron and one has no neutron while the other has just one.
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Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point elevation constant of 2.53°C•kg/mol.
Answer: The boiling point of a 3.70 m solution of phenol in benzene is \(89.5^0C\)
Explanation:
Elevation in boiling point:
\(\Delta T_b=i\times k_b\times m\)
where,
\(\Delta T_b\) = change in boiling point
i= vant hoff factor = 1 (for benzene which is a non electrolyte )
\(k_b\) = boiling point constant = \(2.53^0C/kgmol\)
m = molality = 3.70
\(T_{solution}-T_{solvent}=i\times k_b\times m\)
\(T_{solution}-80.1^0C=1\times 2.53\times 3.70\)
\(T_{solution}=89.5^0C\)
Thus the boiling point of a 3.70 m solution of phenol in benzene is \(89.5^0C\)
Answer:
First Question:
C. ΔTb = Kbm
Second Question:
C. 9.36° C
Third Question:
89.5
Explanation:
Got it right.