All galaxies outside the Local Group are moving away from us, and the farther away they are, the faster they're going.
How is Hubble's law defined?We may learn a lot about the nature of the cosmos from Hubble's rule, which states essentially that a known universe velocity (or, as it is commonly displayed, its redshift) is precisely proportionate to its distance. The relationship between distance and speed should not exist if the cosmos is constant and unchanging.
What is the name of Hubble's theory?The Hubble-Lemaître law, commonly referred to as Hubble's law, is the finding in astrophysics that planets are eloping from Earth at rates proportionate to their separation. In other words, they are travelling away from Earth more quickly the more away they are.
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Hi, can someone pls help me solve this? Thanks. It’s physics and the topic is electrostatics
The effective external resistance of the circuit is 3.5 ohms, the current in the circuit is 1.71 A, the lost voltage in the battery is 1.285 V, and the current in one of the 3-ohm resistors is 1.71 A.
What is the effective external resistance?To solve this problem, we can use Kirchhoff's circuit laws and Ohm's law.
First, let's calculate the equivalent resistance of the parallel combination of two 3-ohm resistors:
1/Rp = 1/3 + 1/3
Rp = 1.5 ohm
Now, let's calculate the total external resistance of the circuit:
R = 2 + Rp
R = 2 + 1.5
R = 3.5 ohm
Using Ohm's law, we can calculate the current in the circuit:
V = IR
I = V/R
I = 6/3.5
I = 1.71 A
The lost voltage in the battery is given by:
VL = E - Ir
VL = 23 - 1.711.5
VL = 1.285 V
The current in one of the 3-ohm resistors is the same as the current in the circuit:
I = 1.71 A
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Complete question:
A battery Of 3 cells is arranged in series each of emf 2V and internal resistance of 0.5-ohm and connected to a 2-ohm resistor.
In a series with a parallel combination of two 3-ohm resistors,
calculate the effective external resistancecalculate the current in the circuitthe lost Voltage calculate the current in one of the 3 ohm resistanceI need help on this question.
Answer:
A
Explanation:
there are very large numbers of charged particles in most objects. why, then, don’t most objects exhibit static electric effects?
This is because the phenomenon of static electricity requires the separation of positive and negative charges. When two substances are in contact electrons are transferred from one to the other leaving one with an excess positive charge and the other with an equal negative charge.
There are equal numbers of positive and negative charges so an object is electrically neutral. Because the phenomenon of static electricity requires the separation of positive and negative charges. When two substances are in contact electrons are transferred from one to the other leaving one with an excess positive charge and the other with an equal negative charge.
The negative charge on the earth's surface is balanced by the same positive charge in the atmosphere. An atom has a net positive charge if the number of protons is greater than the number of electrons, and a net negative charge if the number of electrons is greater than the number of protons.
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explain why at the atomic level, conductors move charge easily and insulators do not
How much energy is required to increase the temperature of a 10kg block of iron from 15^oC to 25^oC? The specific heat capacity of iron is 0.44J/kg^oC. Use the equation change in thermal energy=mass*specific heat capacity*temperature change
The amount of thermal energy required to increase the temperature of a 10kg block of iron from 15 °C to 25 °C is 44 J
How do I determine the thermal energy required?First, we shall list out the given parameters from the question. This is given below:
Mass of iron block (M) = 10 kilogramsInitial temperature (T₁) = 15 °CFinal temperature (T₂) = 25 °CChange in temperature (ΔT) = 25 - 15 = 10 °CSpecific heat capacity of iron (C) = 0.44 J/Kg°CThermal energy required (Q) =?The thermal energy required can be obtained by using the formular illustrated below:
Q = MCΔT
Q = 10 × 0.44 × 10
Q = 44 J
Thus, we can conclude that the thermal energy required is 44 J
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A square metal plate 0.180 m on each side is pivoted about an axis through point O at its center and perpendicular to the plate. (See the figure below (Figure 1) .)
Calculate the net torque about this axis due to the three forces shown in the figure if the magnitudes of the forces are F1 = 17.0 N, F2 = 27.0 N, and F3 = 13.0 N. The plate and all forces are in the plane of the page. (N.m)
the answer 1.73 is incorrect
The net torque to that axis due to three forces is 2.554 Nm.
How to calculate the net torque?\(F_1\) = forces 1 = 17 N
\(F_2\) = forces 2 = 27 N
\(F_3\) = forces 3 = 13 N
α = side of metal plate = 0.18 m
Net torque can be calculated by multiple the forces by distance. For the question, the \(F_1\) will be negative because the forces of \(F_3\) will move the square metal plate to that side.
Net torque = \(-F_1\frac{a}{2} + F_2\frac{a}{2} + F_3 sin(45)\frac{a}{2} + F_3 cos(45)\frac{a}{2}\)
= \(-17\frac{0.18}{2} + 27\frac{0.18}{2} + 13sin(45)\frac{0.18}{2} + 13 cos(45)\frac{0.18}{2}\)
= -1.53 + 2.43 + 0.827 + 0.827
= 2.554 Nm.
Thus, the net torque for that three forces shown in the figure is 2.554 Nm.
You question is incomplete, but most probably your full question was
(image attached)
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Identify the smallest measurement.
a) attometer
b) nanometer
c) centimeter
d) megameter
e) petameter
Answer:
Attometer
Explanation:
an attometer is the smallest unit of measurement.
Hope it helped!
2 QUESTIONS!! PLEASE HELP QUICK
1. true or false: Balanced forces acting on an object result in constant velocity
2. If one of the cars starts and ends at the same point in the race (making a loop around the track), what is the car's displacement?
0
1
2
7.5
Answer:
1. True 2.0
Explanation:
1. When balanced forces are acting on an object, they have a constant velocity, meaning that the velocity remains the same.
2. When an object begins at a starting point and returns back to that same starting point, its displacement would be 0.
I'm pretty confident in these answers, however, you must have studied this more than me, so let me know if you have any questions or concerns at all, I'll be glad to help. :)
If the wind is blowing from north to south, where are the areas of high and low pressure?
Explanation:
Wind is caused by differences in the atmospheric pressure. When a difference in atmospheric pressure exists, air moves from the higher to the lower pressure area, resulting in winds of various speeds.
Our Earth is a rotating planet. Fast moving air is deflected by the Coriolis effect, except exactly on the equator. This defines the direction of cyclones, hurricanes, and typhoons rotation. The wind flow around a large cyclone is counterclockwise in the Northern Hemisphere and clockwise in the Southern Hemisphere.
Wind forms when the sun heats one part of the atmosphere differently than another part. This causes expansion of warmer air, making less pressure where it is warm than where it is cooler. Air always moves from high pressure to lower pressure, and this movement of air is wind.
The fact that some well-known studies have been repeated without finding results consistent with those in the initial report describes a(n) ________ that is currently affecting research in psychology and other fields.
Answer:
Replication Crisis
Explanation:
Replication crisis in psychology- It refers to the concerns about credibility of finding the results in psychological science.
what are derive quantities
Answer:
Derived quantities are quantities that are calculated from two or more measurements. Derived quantities cannot be measured directly. They can only be computed. Many derived quantities are calculated in physical science. Three examples are area, volume, and density.
Answer:
What is derive quantities?
Derived quantities are those that may be expressed in terms of base or derived quantities by means of the mathematical symbols of multiplication and division only (no addition or subtraction or any other sign). ... The first group consists of derived quantities, which have proper units. Derived quantities are expressed as algebraic combinations of base quantities.
Examples of the Derive quantities
Derive Quantity and their units
Volume, V = m³Density, p = kgm⁻³Velocity, v = ms⁻¹Force, F = NAcceleration, a = ms⁻²How is Venus similar to Earth?
Both have the same day length.
Both rotate in the same direction.
Both have ample water on their surfaces.
Both have a solid inner core and a liquid outer core.
Answer: D
Explanation: I have my answers VS. Go0gle answers (go0gle answers are pics)
(A) Both have the same day length. Well, Venus doesn't havve the same amount of days. (I already know off the top of my head, but I still searched it up)
(B) Both rotate in the same direction. In school (before Virus) they would always show diagrams of the planets on the projector and Venus doesn't rotate
(C) Both have ample water. No. Venus doesn't have much water >_>
(D) Both have a solid inner core and a liquid outer core. Yesh. In my lessons (before), Venus has a solid inner core and liquid outer core.
Find ratio of mass attenuation coefficients of soft x-ray radiation and hard x-ray radiation
( ) after passing the bone tissue. Suppose, that the photon energy for soft radiation was 30 keV and h
for hard radiation 120 keV.
The mass attenuation coefficient is a measure of the probability of a photon interacting with a material as it passes through it. It is represented by the symbol μ/ρ, where μ is the linear attenuation coefficient and ρ is the density of the material.
To find the ratio of mass attenuation coefficients of soft and hard X-ray radiation after passing through bone tissue, we need to compare the values of μ/ρ for both types of radiation at the given photon energies. According to NIST's X-Ray Mass Attenuation Coefficients Database, at a photon energy of 30 keV, the mass attenuation coefficient for bone tissue is 0.95 \(cm^{2}\)/g for soft x-rays. At a photon energy of 120 keV, the mass attenuation coefficient for bone tissue is 0.18 \(cm^{2}\)/g for hard x-rays. Therefore, the ratio of the mass attenuation coefficients of soft and hard x-ray radiation after passing through bone tissue is: 0.95 \(cm^{2}\)/g / 0.18 \(cm^{2}\)/g = 5.28. In other words, the mass attenuation coefficient for soft x-rays is about 5 times higher than that for hard x-rays when passing through bone tissue. This means that soft x-rays are more likely to be absorbed or scattered by bone tissue than hard x-rays, which has implications for imaging techniques that use x-rays, such as radiography and computed tomography (CT).
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why can we not depend on the natural co2 cycle to lower carbon-dioxide levels?
We cannot solely depend on the natural CO2 cycle to lower carbon-dioxide levels because the current rate of anthropogenic emissions, primarily from burning fossil fuels and deforestation, has significantly disrupted the natural balance.
The natural CO2 cycle involves processes like photosynthesis, respiration, and dissolution in oceans, which work to maintain a stable concentration of carbon dioxide in the atmosphere. However, human activities have led to a rapid increase in CO2 emissions, overwhelming the natural cycle's ability to remove excess carbon dioxide. This has resulted in an enhanced greenhouse effect, causing global warming and climate change. Natural processes like photosynthesis and ocean absorption can only remove a limited amount of CO2 per year, and this capacity is not sufficient to counterbalance the excessive emissions produced by human activities.
Moreover, climate change itself can further impact the efficiency of the natural CO2 cycle. For example, warmer temperatures and altered precipitation patterns can affect plant growth and their ability to absorb CO2 through photosynthesis. Additionally, ocean acidification due to increased CO2 dissolution can harm marine ecosystems and reduce their capacity to absorb carbon dioxide.
In conclusion, relying solely on the natural CO2 cycle to lower carbon-dioxide levels is not viable because the system is overwhelmed by anthropogenic emissions, and climate change impacts can further compromise its efficiency. To effectively address this issue, it is essential to reduce human-induced CO2 emissions and explore additional carbon removal technologies.
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Fossil fuels
?
Water cycle
Hydropower
۔۔
Photosynthesis
Sun
2
Nuclear fusion
Plants
A.
Plant life decay
Answer:
nuclear fusion plants are fossil fuels, if you are asking which of the following is a fossil fuel
Explanation:
A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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Two flying fish have an inelastic collision while in mid-flight. One fish has a mass of 0. 650 kg and a velocity of 15. 0 m/s to the right; the other has a mass of 0. 950 kg and a velocity of 13. 5 m/s to the left. Find the change in their kinetic energy after the collision
The change of kinetic energy is -156.7 joules.
\(V1_{i}\) =15
\(V2_{i}\)= -13.5(as towards left)
V= common velocity during collision
On applying momentum conservation during the collision
\(m_{1}V1_{i} + m_{2}V2_{i} = V ( m_{1} + m_{2})\)
\(0.650 \ 15 + 0.950 \ (-13.5) = (0.625 + 0.950) \ V\)
\(\frac{3.075}{1.6}\) =V
V= -1.92 m/s
To kind change in kinetic energy we will subtract final and initial kinetic energy
ΔK=\(\frac{1\ (m_{1} + m_{2} ) \ V}{2} ^{2}\) - \(\frac{1\ (m_{1} ) \ V1_{i} }{2} ^{2}\) - \(\frac{1\ (m_{2} ) \ V2_{i} }{2} ^{2}\)
ΔK= \(\frac{1\ (0.625 + 0.950 ) \ (-13.5)}{2} ^{2}\) - \(\frac{1\ (0.625 ) \ 15 }{2} ^{2}\)- \(\frac{1\ (0.950 ) \ 13.5 }{2} ^{2}\)
ΔK= = - 156.7 J
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Describe how the particles change when a solid turns to liquid and when a liquid turns to a gas
When a solid turns into a liquid, the particles gain energy and vibrate more quickly.
As heat is added to the solid, the particles gain energy and start moving more vigorously. Eventually, the energy overcomes the intermolecular forces holding the particles in place, causing them to break free from their fixed positions.
As a result, the solid's structure breaks down, and the particles become less organized, allowing them to flow freely past one another. This change from a solid to a liquid is known as melting, and it occurs at the melting point of the substance.When a liquid turns into a gas, the particles experience a process called vaporization or evaporation.
In a liquid, the particles are loosely packed and move more freely compared to a solid. As heat is applied to the liquid, the particles gain even more energy and move faster. Some particles near the surface gain enough energy to overcome the attractive forces of neighboring particles and escape into the surrounding space as gas molecules.
This transition from a liquid to a gas occurs at the boiling point of the substance. The remaining liquid continues to evaporate until all the liquid has been converted into gas or until equilibrium is reached.In both processes, the arrangement and motion of the particles change significantly.
The transition from a solid to a liquid involves a breakdown of the fixed positions of the particles, while the transition from a liquid to a gas involves the escape of particles from the liquid's surface.
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A square nonconducting plate, 2a on a side, has a total charge Q uniformly spread over its surface. Calculate the electric field vector E at distance z above the plate's center. Use the electric field at a distance z above the midpoint of a line of charge of length 2L as a shortcut when solving.
Answer:
E' = Qa/4πε[√(a² + z²)]³
Explanation:
Since the non-conducting plate is symmetric, a small charge element dq generates an electric field dE at a distance R from itself and a distance z above the center of the plate. Since the plate is symmetric, we only have the vertical component of the electric field acting at the center so dE' = dEcosθ where θ is the angle between R and the plate.
So, dE' = dEcosθ = dqcosθ/4πεR²
Let σ represent the surface charge density of the plate. So, for a small elemental area dA, dq = σdA.
Substituting this into dE' we have
dE' = σdAcosθ/4πεR²
Also cosθ = a/R where a is half the length of side of the plate of side length, 2a.
So, dE' = σdAa/4πεR³
Also R² = a² + z²
R = √(a² + z²)
So, dE' = σdAa/4πε[√(a² + z²)]³
Now, dA = dxdy
dE' = σadxdy/4πε[√(a² + z²)]³
So, the total electric field at z is obtain by integrating dE'
E' = ∫dE' = ∫σadxdy/4πε[√(a² + z²)]³ = σa∫dxdy/4πε[√(a² + z²)]³
We integrate dx and dy from -a to a.
So,
E' = σa[2a][2a]/4πε[√(a² + z²)]³
E' = σa³/πε[√(a² + z²)]³
Since the total chare Q = σA where A is the are of the plate. A = (2a)² = 4a²
Q = σA = 4σa²
σ = Q/4a²
substituting σ into E', we have
E' = (Q/4a²)a³/πε[√(a² + z²)]³
E' = Qa/4πε[√(a² + z²)]³
Which of these is true about pure substances?
A. They can only contain one type of molecule.
B. They can contain different types of atoms and molecules.
C. They may contain one type of atom or one type of molecule.
D. They can only contain one type of atom.
Answer:
the answer is c bc to be pure it must be the same atom or molecule
One point charge has a magnitude of 5.4 x 10-7 C. A second charge that is 0.25 m away has a magnitude of 1.1 x 10-17 C. What is the electric force magnitude of one charge on the other?
The magnitude of the electric force between the two charges is 8.99 x 10^9 N, Where one point charge has a magnitude of 5.4 x 10-7 C and second charge that is 0.25 m away has a magnitude of 1.1 x 10-17 C.
The electric force between two point charges can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, the magnitude of the electric force can be calculated as:
Electric force = (k * |q1| * |q2|) / r^2
Where k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges (5.4 x 10^-7 C and 1.1 x 10^-17 C, respectively), and r is the distance between the charges (0.25 m).
Plugging in the values, we can calculate the magnitude of the electric force as 8.99 x 10^9 N.
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A car accelerates uniformly from rest and
reaches a speed of 16.3 m/s in 12.4 s. The
diameter of a tire is 34.5 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev
I have an image solution for this, don't worry.
a horse track is a loop where the starting point and the finish line are at the same point. a horse gallops around a 400 m track in 20 s. calculate the velocity of the horse.
The velocity of the horse as it travels through the track is 20 m/s.
What is velocity?Velocity can be defined as the ratio of distance or displacement to time.
To calculate the velocity of the the horse, we use the formula below.
Formula:
v = d/t............... Equation 1Where:
v = velocity of the horsed = distancet = timeFrom the question,
Given:
d = 400 mt = 20 sSubstitute these values into equation 1
v = 400/20v = 20 m/s²Hence, the velocity of the horse as it travels through the track is 20 m/s.
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Answer:
A. 2s
Explanation:
time = distance ÷ speed
T = .2 ÷.1
T= 2
Which describes a condition of the neritic zone?
few organisms
ample sunlight
changing salinity
frigid temperatures
Answer:
ample sunlight
Explanation:
Neritic zone have ample of sunlight
What is Neritic zone ?The neritic zone is covered with generally well - oxygenated water , receives plenty of sunlight , have relatively stable temperature , has low water pressure and stable salinity levels .
Hence , correct option is option b) ample sunlight
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If the car in the problem above, then climbs a 12.2 m tall hill, how fast will it be going at the hump? Show your work with
units.
Since the car is moving horizontally, we can use the conservation of energy principle:
Initial kinetic energy + Initial potential energy = Final kinetic energy + Final potential energy
We know that the initial kinetic energy is 1/2 mv^2 and the initial potential energy is mgh, where m is the mass of the car, v is its velocity, h is the height of the hump and g is the acceleration due to gravity.
At the top of the hump, the car's potential energy is converted entirely into kinetic energy, so we have:
1/2 mv^2 = mgh
Solving for v, we get:
v = √(2gh)
Substituting the values, we get:
v = √(2 x 9.8 m/s^2 x 12.2 m) = 11.9 m/s
Therefore, the car will be going at 11.9 m/s (rounded to one decimal place) when it reaches the top of the 12.2 m tall hill.
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Answer :
We can use the conservation of energy principle, since the car is moving horizontal
According to the Principle:
Initial kinetic energy + Initial potential energy = Final kinetic energy + Final potential energy
We know that the initial kinetic energy is 1/2 mv^2 and the initial potential energy is mgh, where m is the mass of the car, v is its velocity, h is the height of the hump and g is the acceleration due to gravity.
At the top of the hump, the car's potential energy is converted entirely into kinetic energy, so we have:
1/2 mv^2 = mgh
Solving for v, we get:
v = √(2gh)
Substituting the values, we get:
v = √(2 x 9.8 m/s^2 x 12.2 m) = 11.9 m/s
Therefore, the car will be going at 11.9 m/s (rounded to one decimal place) when it reaches the top of the 12.2 m tall hill.
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Cual es el cambio de energía cinética de un cuerpo de 800kg que disminuye su velocidad de 90 km/h a 50 km/h
How many degrees are there between the direction of motion and the force of
friction?
A. 270
B. 90
C. 180
D.0
Answer:
180°
Explanation:
Friction, if it exists, ALWAYS opposes motion or attempted motion.
A pure gold ring with a volume of 1.91 cm
3
is initially at 10.0
∘
C. When it is put on, it warms to 27.3
∘
C. Part A How much heat did the ring absorb? (density of gold =19.3 g/cm
3
)
The amount of heat absorbed by the gold ring can be calculated using the formula:
Q = mcΔT
where Q is the heat absorbed, m is the mass of the gold ring, c is the specific heat capacity of gold, and ΔT is the change in temperature.
To find the mass of the gold ring, we can use the formula:
\(\[V = \frac{m}{ρ}\]\)
where \(V\) is the volume of the gold ring and \(ρ\) is the density of gold.
Given:
Volume of the gold ring (V) = 1.91 cm³
Density of gold (ρ) = 19.3 g/cm³
Change in temperature (ΔT) = 27.3 °C - 10.0 °C = 17.3 °C
Specific heat capacity of gold (c) = 0.129 J/g°C
First, let's calculate the mass of the gold ring:
\(\[m = V \times ρ = 1.91 \, \text{cm}³ \times 19.3 \, \text{g/cm}³\]\)
Then, we can calculate the amount of heat absorbed:
\(\[Q = m \times c \times ΔT\]\)
Now we can substitute the values into the formulas and calculate the heat absorbed.
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How is kinetic energy different from potential energy? akinetic energy is stored energy that has the capacity to do work, and potential energy is the energy of motionbkinetic energy is energy that an object possesses as a result of its location, and potential is the same as heat energyckinetic energy is energy of a moving object, whereas potential energy is energy possessed by matter as a result of its location or structuredkinetic energy can be created or destroyed, while potential energy cannot be created and destroyed
We will have that kinetic energy is different from potential energy as follows:
Kinetic energy is energy of a moving object, whereas potential energy is energy possessed by matter as a result of its location or structure. [Option C]
calculate the magnitude of distance and displacement of a body moving in a complete circle
Answer:
Total distance = 2πr
Total displacement = 0
Explanation:
To Calculate the magnitude of distance and displacement of a body moving in a complete circle, we must come to these facts that:
The distance = circumference of the circle which is equal to the product of 2 ,pi and radius r
That is
Circumference = 2πr
Since velocity is changing and not constant, it is a vector quantity. Likewise displacement is a vector quantity.
The total displacement will be equal to zero.
Therefore, total distance is equal to the circumference of a circle while total displacement is equal to zero.