By 2020, experts project that _____ of children at 30 years of age will still have living grandparents. 60% 40% 20% 80%. 80%.

Answers

Answer 1

In 2020, 80% of youngsters who are 30 years old will still have living grandparents, according to experts.

The majority of adults under the age of 40 believe adult children have a duty to help out ageing parents. Eight in ten (81%) of this age group, compared to 75% of middle-aged individuals and 68% of those 60 and older, feel this is a responsibility. Parental caregiving enables them to continue working. They frequently play a crucial role following family catastrophes. The interactions between grandparents and their adult grandchildren are typically centred on financial support. The likelihood of adult children and their parents spending their golden years together is rising as people live longer. Middle age, the stage of adulthood for humans that occurs just before the onset of old age.

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Answer 2

Answer: 80

Explanation:


Related Questions


a What is meant by zero error?
b Give an example of when you would have to allow
for it.

Answers

a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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A spherical bowling ball of mass 7 kg and radius 0.18 m rolls down a hill that has a vertical height of 7 m. If the ball started from rest at the top, what is its angular momentum at the bottom of the hill? Use two sig figs.

Answers

Answer:

er so ue 0.984 kg study your self brhh

What is the origin of a warm, wet air masses.
A. over land in polar regions
B. over water in polar regions
C. over land in tropical areas
D. over water in tropical zones

Answers

The answer is D because it the tropical zone

Answer:

An air mass acquires these characteristics above an area of land or water known as its source region. When the air mass sits over a region

You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you have found a plank that is 8 feet long, and you show it to your father.

Which plank will give you the most mechanical advantage? Calculate the MA for each plank.

Answers

Answer:

Explanation:

Provided the planks are each strong enough to support the weight of the rock, the 8 ft plank will have a greater mechanical advantage.

The ideal (no friction) mechanical advantage for each ramp is

ME₈ = 8/3 = 2.67

ME₅ = 5/3 = 1.67

which stage of sleep is marked by long slow delta brain waves

A. stage3
B. stage4
C. stage 1
D.stage 2

Answers

The stage of sleep which is marked by long slow delta brain waves is stage 4 and is therefore denoted as option B.

What is Sleep?

This is referred to as a sedentary state of mind and body and it is characterized by altered consciousness, reduced muscle activity and reduced interactions with surroundings.

In the deepest level of sleep, stage IV sleep it has been observed that it consists of low frequency and high-amplitude fluctuations called delta waves and the sequence from drowsiness to deep stage IV sleep usually takes about an hour thereby making it the correct choice.

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A motorcycle has a mass of 100kg , suppose it travels at 40m/s . Find the kinetic energy possessed by it

Answers

The Kinetic energy possessed by the cycle with a mass of 100 kg and velocity 40 m/s is 80 kJ.

Kinetic energy is the energy of an object when the object is in motion. It is obtained by the product of the mass of the object and the velocity of the object. The unit of kinetic energy is the joule (J).

From the given,

mass of the motorcycle (m) = 100 kg

velocity (v) = 40 m/s

K.E =?

K.E = (mv²) / 2

     = (100×40×40) / 2

    = 160,000 / 2

   = 80,000 J

Thus, the kinetic energy of the motorcycle is 80kJ.

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simple but not plagiarized answer for "what is forces and motion?"​

Answers

FORCE-physical power or strength possessed by a living being:
He used all his force in opening the window.

MOTION-the action or process of moving or of changing place or position; movement.

If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will accelerate and turn about its center of gravity with uniform angular speed. accelerate and turn about its center of gravity with uniform angular acceleration. accelerate and turn until its center of gravity reaches its lowest point. accelerate and spin until its center of gravity reaches its highest point. accelerate but will not spin.

Answers

Answer:

It accelerate but will not spin.

Explanation:

If an irregular shaped object is dropped from rest without feeling any form of air resistance it will accelerate without spinning and this is due to the fact that there is no Torque around  the center of gravity

a 50 kg boy runs at 3 m/s. how much momentum does he have

Answers

Answer:

150   kg-m/s

Explanation:

momentum = m * v

50 * 3 = 150

what could be the possible answer to the question ?

thankyou ~​

what could be the possible answer to the question ?thankyou ~

Answers

The value of the force, F₀, at equilibrium is equal to the horizontal

component of the tension in string 2.

Response:

The value of F₀ so that string 1 remains vertical is approximately 0.377·M·g

How can the equilibrium of forces be used to find the value of F₀?

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

M·g × L = T₁ × 2·L

Therefore;

\(T_1 = \mathbf{\dfrac{M \cdot g}{2}}\)

Which gives;

\(M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}\)

\(T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})} = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}\)

F₀ = T₂·sin(37°)

Which gives;

\(F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2} \approx \mathbf{0.377 \cdot M \cdot g}\)

F₀ ≈ 0.377·M·g

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What is the equation used to find the angle of refraction? Identify each variable. (1 point)

Answers

Answer:

pictures please

Explanation:

I need a picture so I can tell you

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.0900 N when their center-to-center separation is 48.5 cm. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.0528 N. Of the initial charges on the spheres, with a positive net charge, what was (a) the negative charge on one of them and (b) the positive charge on the other? (Assume the negative charge has smaller magnitude.)

Answers

Answer:

(a)\(-0.75\mu\) Coulomb

(b) \(3.1 \mu\) Coulomb

Explanation:

Let \(q_1\) be the positive charge, in Coulumb, on the one sphere and \(q_2\) be the negative charge, in Coulumb, on the other sphere, where \(q_{1} > q_2\).

The center-to-center distance between the spheres is,

\(d=48.5 cm=0.485 m\).

From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance,\(d\), is

\(F=\frac {1}{4\pi\epsilon_0}\frac{q_1q_2}{d^2}\;\cdots(i)\)

where, \(\epsilon_0\) is the permittivity of free space and

\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.

So, using equation (i), the attractive force between both the spheres is

\(9\times 10^9\frac{q_1q_2}{(0.485)^2}=0.09\)

\(\Rightarrow q_1q_2=2.35225\times 10^{-12}\)

\(\Rightarrow q_1q_2= 2.35225 \mu^2\) [as \(\mu=10^{-6\)]

\(\Rightarrow q_2=\frac{\mu^2 2.35225}{q_1}\;\cdots (ii)\)

When both the sphere is connected by a thin conducting wire, then redistribution of charge take place and net charge , on combining both the spheres, is \(q_1-q_2\) ( as \(q_1>q_2\)).

Finally, the charge density on both the sphere will be the same.

Given that, both the sphere are identical, so, the quantity of charges on of charged on both the conducting spheres, after removing the conduction wire, will be the same.

So, the net charge on the individual sphere is

\(\frac {q_1-q_2}{2}\) which is positive in nature.

From equation (i), the repulsive force between the spheres is

\(9\times 10^9\times \frac{(q_1-q_2)(q_1-q_2)}{4\times 0.485^2}=0.0528\)

\(\Rightarrow (q_1-q_2)^2=5.52\mu^2\) [ as \(\mu=10^{-6}\)]

\(\Rightarrow q_1-q_2=2.35\mu\;\cdots(iii)\)

\(\Rightarrow q_1 - \frac{\mu^2 2.35225}{q_1}= 2.35\mu\) [using equation (ii)]

\(\Rightarrow q_1^2- 2.35\mu q_1- 2.35225\mu^2=0\)

\(\Rightarrow q_1=3.1 \mu\) or \(-0.76 \mu\)

Taking positive sign as \(q_1\) is the magnitude of charge.

So, for \(q1=3.1 \mu\)

\(q_2=3.1- \mu- 2.35\mu=0.75 \mu\) [from equation (iii)]

Hence,

(a) Negative charge on one of the spheres is,

\(q_2=-0.75 \mu\) Coulomb.

(b) Positive charge on the other sphere is,

\(q_1=3.1 \mu\) Coulomb.

a block with a mass of m slides at a constant velocty v0 on a horizontal frictionless surface. if the spring constant iis k , what ii the maximm compresion in the spring

Answers

If the block's mass is m, block's initial velocity is v and the spring constant is k, the maximum compression in the spring is  sqrt(mv² /k)

Applying the law of conservation of energy, since it is a frictionless surface, all the kinetic energy of the block will be converted to the potential energy of the spring.

The kinetic energy of the block:

Ek = 1/2 . mv²

Where:

m = mass of block

v = block's initial velocity

The potential energy of the spring:

Ep = 1/2 . kx²

Where:

k = spring constant

x = maximum compression in the spring

It holds:

Ek = Ep

1/2 . mv² =  1/2 . kx²

x = sqrt(mv² /k)

Hence, the maximum compression in the spring is sqrt(mv² /k)

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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?

Answer in kg

Answers

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Which phrase describes a scientific law?
A. A statement that matter cannot be created or destroyed
B. A claim that experiments cannot verify whether matter has been
destroyed
O C. An explanation for why matter cannot be created or destroyed
D. A prediction of how much matter exists in the universe
SUBMIT
In

Answers

Answer:

C- An explanation for why matter cannot be created or destroyed

Explanation:

Answer: A. A statement that matter cannot be created or destroyed.

Explanation:

Apex

if the hoist h is moving upward at 6 ft/s , determine the speed at which the motor m must draw in the supporting cable. if the hoist is moving upward at 6 , determine the speed at which the motor must draw in the supporting cable. vp/h

Answers

The magnitude of the motor shaft's rotational velocity is used to describe a motor's speed.

The motor velocity of the supporting cable exists 18 ft/s.

What is meant by Motor velocity?

A motor's speed is defined as the magnitude of the motor shaft's rotational velocity. The number of full rotations per unit of time for an axis rotation in a motion application depends on the motor's speed.

When given 11.1 V and a motor with a velocity constant and back EMF constant of 5,700 rpm/V, the motor will spin at a nominal speed of 63,270 rpm (= 5,700 rpm/V 11.1 V). The non-linear mechanical losses may prevent the motor from operating at this theoretical speed.

Motor velocity = Number of vertical strings × upward velocity

substitute the values in the above equation, we get

18 fp/s = 3 × 6

3 × 6 = 18 fp/s.

The motor velocity of the supporting cable exists 18 ft/s.

Therefore, the correct answer is option [D]. VP/H = 18 ft/s.

The complete question is:

If the hoist H is moving upward at 6 ft/s, determine the speed at which the motor M must draw in the supporting cable.

[A]. VP/H = 6 ft/s

[B]. VP/H = 2 ft/s

[C]. VP/H = 12 ft/s

[D]. VP/H = 18 ft/s

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if the hoist h is moving upward at 6 ft/s , determine the speed at which the motor m must draw in the

20 copper wires of length l and diameter d are connected in parallel to form a single composite conductor of resistance R. What is the ratio of the diameter of a single copper wire to d, if its length is also l and it has the same resistance?

Please show work and type out answer.

Answers

Answer:

D = 4.47d

Explanation:

given that

1/R(eq) = 20/R

R(eq) = R/20

also, we know that the formula for resistance is given by the relation

R = pl/A, where A is πd²/4

If we substitute the value of A, we have

R = pl/(πd²/4)

R = 4pl/πd²

Now, we substitute this in the earlier derived equation

R(eq) = (4pl/πd²) / 20

R(eq) = pl/5πd²

To find the resistance of a single wire made of the same material, the resistance is

R(D) = 4pl / πD²

R(eq) = R(D), and thus

pl/5πd² = 4pl/πD²

1/5d² = 4/D²

D² = 20d²

D = √20d²

D = 4.47 d

Small frogs that are good jumpers are capable of remarkable acceleration. One species of small frog reaches a takeoff speed of 3.7 m/s in 60 ms.
How high can the frog jump given it's acceleration is 62 m/s^2?

Answers

Hi there!

Begin by solving for the time it takes the frog to reach the top of its trajectory. (Vertical velocity = 0 m/s)

\(\large\boxed{v_f = v_i + at}\)

vf = final velocity (0 m/s)

vi = initial velocity (3.7 m/s)

a = acceleration due to gravity (9.8 m/s²)

t = time (s)

Plug in the known values:

\(0 = 3.7 - 9.8t\\\\-3.7/(-9.8) = t = 0.378 s\)

Now, we can use the following kinematic equation:

\(\large\boxed{d = v_it + \frac{1}{2}at^2}\)

d = displacement (m)

vi = initial velocity (3.7 m/s)

a = acceleration (9.8 m/s²)

t = time (0.378 sec)

Plug in the given values:

\(d = 3.7(0.378) - \frac{1}{2}(9.8)(0.378)^2 = \boxed{0.698 \approx 0.7m}\)

Find distance between two object of radius 6 cm and 2 cm

Answers

The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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Question 3 (5 points)
Match the images with the correct fossil type,
А
B
C
D
E

Answers

Answer:

There no image

Explanation:

You leave your home at 1pm. At 3pm, you are 100 km east of your house. What was your average velocity in km/hr

Answers

Answer:

50km/h

Explanation:

Average velocity = change in distance (or distance travelled) divided by/ the change in time (or time taken.)

The change in distance has been given as 100km.

The change in time is 3pm-1pm = 2 hours.

Therefore the average velocity was 100/2 = 50km/h (to the east).

Hope this helped!

1. Draw a quantitative motion map for the following description: A bicyclist speeds along a road at 10 m/s for 6 seconds. Then she stops for three seconds to make a 180˚ turn and then travels at 5 m/s for 3 seconds.






Answers

Answer:

Please find the attached file for the figure.

Explanation:

Given that a bicyclist speeds along a road at 10 m/s for 6 seconds.

Its acceleration = 10/6 = 1.667 m/s^2

The distance covered = 1/2 × 10 × 6

Distance covered = 30 m

That is, displacement = 30 m

Then she stops for three seconds to make a 180˚ turn and then travels at 5 m/s for 3 seconds.

The acceleration = 5/3 = 1.667 m/s^2

The displacement = 1/2 × 5 × 3

Displacement = 7.5 m

The resultant acceleration will be equal to zero.

While the resultant displacement will be:

Displacement = 30 - 7.5 = 22.5 m

Please find the attached file for the sketch.

1.Draw a quantitative motion map for the following description: A bicyclist speeds along a road at 10

A 30 Kg mass is 5 m above the ground. a) What is its potential energy on Earth (g=10 m/s2) and b) what would its potential energy be on the moon (g=1.6 m/s2)

Answers

Answers:

a) PE = 1500 J

b) PE = 240 J

Explanation:

The potential energy is calculated as follows

PE = mgh

Where m is the mass, g is the gravity and h is the height.

Now, we can calculate the potential energy in Earth replacing g = 10 m/s², m = 30 kg and h = 5 m, so

PE = (30 kg)(10 m/s²)(5m)

PE = 1500 J

In the same way, the potential energy in the moon with g = 1.6 m/s² is equal to

PE = (30 kg)(1.6 m/s²)(5 m)

PE = 240 J

Therefore, the answers are

a) PE = 1500 J

b) PE = 240 J

N2 + 3H2 + 2NH3
What type of reaction is this

Answers

Answer:It is a combination reaction; nitrogen and hydrogen combine to form ammonia

Explanation:

This is the reaction that is used to make ammonia from hydrogen and nitrogen. In this reaction, only one product is formed. Therefore, this reaction is known as a combination reaction.

An object with a mass of 7 kg accelerates 8 m/s2 when an unknown force is applied to it. What is the amount of the force?

Answers

The amount of force applied to the 7kg object that caused it to accelerate at 8m/s² is 56 newtons.

What is the force applied to the object?

A force is simply a push or a pull of an object resulting from the object's interaction with another object.

From newton's second law;

Force = mass × acceleration

Given the data in the question;

Mass of the object = 7kgAcceleration = 8m/s²Applied force = ?

Plug the given values into the formula to determine the applied force.

Force = mass × acceleration

Force = 7kg × 8m/s²

Force = 56kgm/s²

Force = 56 N

Therefore, the applied force is 56 newtons.

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What is cubical expansivity of liquid while freezing

Answers

Answer:

"the ratio of increase in the volume of a solid per degree rise of temperature to its initial volume" -web

Explanation:

tbh up above ✅

Answer:

cubic meter

Explanation:

Increase in volume of a body on heating is referred to as volumetric expansion or cubical expansion

Which of these surfaces would have the least amount of friction?
grass
sand paper
concrete
satin cloth

Answers

Answer:

D.   Satin Cloth

Explanation:

i thought it said glass, not grass lol

satin it the smoothest surface and therefore the least amount of friction.

The answer would be Satin Cloth

The hour hand on a certain clock is 8.1 cm long.
Find the tangential speed of the tip of this hand.

Answers

The tangential speed of the tip of the hour hand is 4.05 cm/minute.

What is Tangential speed?

Tangential speed, also known as linear speed, is the speed at which an object travels along a circular path. It is defined as the distance traveled per unit of time along an arc or circular path, with the direction of motion tangential to the circle. Tangential speed is dependent on the radius of the circular path and the angular speed, which is the rate at which the object rotates around the center of the circle.

The tangential speed of the tip of the hand is given by:

v = rω

where r is the length of the hour hand and ω is the angular velocity of the hand.

To find ω, we need to convert the time elapsed to an angle. The hour hand completes one revolution (360 degrees) in 12 hours, or 720 minutes. Therefore, the angle swept out by the hour hand in one minute is:

θ = 360 degrees / 720 minutes = 0.5 degrees/minute

At any given time, the angle swept out by the hour hand is proportional to the elapsed time since the last hour mark. If t is the time elapsed in minutes since the last hour mark, then the angle swept out is:

θ = 0.5 degrees/minute * t

Since the hour hand is 8.1 cm long, its tangential speed is:

v = rω = r(dθ/dt)

Substituting for θ, we get:

v = 8.1 cm * (0.5 degrees/minute) = 4.05 cm/minute

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If the vector below is multiplied by 2, what will be its end point?

A. (-2,2)
B. (-2,1)
C. (-1,2)
D. (2,2)

If the vector below is multiplied by 2, what will be its end point?A. (-2,2)B. (-2,1)C. (-1,2)D. (2,2)

Answers

If the vector below is multiplied by 2, option D will be its end point

How did we get the value?

If a vector is multiplied by 2, its end point will be scaled up by a factor of 2. So, if the original vector has end point (x,y), its end point after being multiplied by 2 will be (2x, 2y).

Given the vector below, its end point is (1,1):

^

|

|

|

|

---+--->

After being multiplied by 2, the end point of the vector will be (2 * 1, 2 * 1) = (2, 2), which corresponds to answer choice (D).

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An object of mass 2 kg has a speed of 6 m/s and moves a distance of 8 m. What is its kinetic energy in joules?

Answers

Answer:

36 Joules

Explanation:

Mass ( m ) = 2 kg

Speed of the object (v) = 6 metre per second

Kinetic energy =?

Now,

We have,

Kinetic Energy = \( \frac{1}{2} \times m \times {v}^{2} \)

Plugging the values,

\( = \frac{1}{2} \times 2 \times {(6)}^{2} \)

Reduce the numbers with Greatest Common Factor 2

\( = {(6)}^{2} \)

Calculate

\( = 36 \: joule\)

Hope this helps...

Good luck on your assignment...

The Kinetic energy of the object will be "36 joules".

Kinetic energy

The excess energy of moving can be observed as that of the movement of an object, component, as well as the group of components. There would never be a negative (-) amount of kinetic energy.

According to the question,

Mass of object, m = 2 kg

Speed of object, v = 6 m/s

As we know the formula,

→ Kinetic energy (K.E),

= \(\frac{1}{2}\) × m × v²

By substituting the values, we get

= \(\frac{1}{2}\) × 2 × (6)²

=  \(\frac{1}{2}\) × 2 × 36

= 36 joule

Thus the above answer is appropriate.

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