Bro why cant I post this T-T

I will go to school tomorrow .....is this present tense or past tense or future tense

Answer:

D

Explanation:

The given vector can be broken down into two components (as shown in the figure).

Which results ; vector (s) = 3x + 4y.

Doubling the value of L in a resonant circuit with fixed R and C will result in the peak frequency doubling and the peak height being half as great, while the rms current at resonance will be unchanged.

When the value of L is doubled in a circuit with electrical components L, R, and C and resonant frequency omega_0, the new resonance curve differs from the original one in the following way: the peak frequency will double, and the peak height will be half as great.

The new rms current at resonance I_rms will be unchanged since it is only dependent on the voltage amplitude of the ac source and the impedance of the circuit at resonance, which does not change with the value of L. Therefore, the answer is: The peak height will be half as great, and the peak frequency will double. I_rms is unchanged.

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For practical reasons, we can consider each side of the square as an infinite wire. This can be seen on the following drawing:

This way, the field on the center will be the sum of the contribution of each wire. We can calculate the contribution of a single wire as:

Then, the total field will be this, multiplied by the number of wires:

Then, the resulting field will be Bt=36.46uT

Answer:

Part A: \(1.97ms^{-1}\) (2 s.f.)
Part B: 0.33m (2 s.f.)

Explanation:

Part A:

Frequency = \(\frac{1}{period} = \frac{1}{3}\) Hz

Wavespeed = frequency x wavelength
Wavelength = distance between two crests = 5.90

Freq = 1/3 Hz

Therefore: Wavespeed = 1/3 x 5.90

                  Wavespeed = 1.967 ms^-1

Part B:
Amplitude = \(\frac{peak-to-peak- amplitude }{2}\)

Peak to peak amplitude = 0.65m

Amplitude = 0.65/2 = 0.325m = 0.33m 2sf

The longest side of the right angled triangle is known as hypotenuse of the triangle. The right angled triangle can be shown as,

In the diagram, AC is the perpendicular, AB is the base and BC is the hypotenuse.

Answer:

100 m

Explanation:

Answer: 112 meters

Explanation:

Use the equation: d = vi+vf/2 x t which turned into: 28/2 times 8 = 112 meters

No, the youngster is mistaken. The leaf won't float to the edge of the pond due to the stone's waves.

When a stone is put into a body of water, it creates waves that change in a stunning pattern, radiating outward from a centre that eventually goes still. The growing ring is referred to as a wave packet.

A circle-shaped pattern of ripples is created on the water's surface when a stone is tossed into stillness. The particles vibrate due to the stone's kinetic energy. The particles in the subsequent layers receive the energy.

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Chauffeur: car: pilot: cockpit, flower: stem: tree: trunk, bottom: top: basement: attic, mend: repair:: break: fix December: winter; September: fall; fade: maid: graceful: awkward; late: early; true: false; milk: liquid; broccoli: vegetable; canine: puppy; child: adult

You need to choose a word that appropriately completes the second pair in order to resolve the analogy. The words in an analogy may appear to be unrelated to one another at first look, but they are always logically connected. The link between the first and second word pairs is comparable.

In the testing analogies, only the first set of words is provided. Therefore, you must first determine how these two words are related. To complete the analogy, you must select a word or words that have an analogous relationship to the pair.

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Answer:

Explanation:

momentum of sedan of 1600 kg = 1600x v , where v is its velocity

momentum of suv of 2300 kg = 2300 x u where u is its velocity .

force of friction = ( 1600 + 2300 ) x 9.8 x  .75 ( fiction = μ mg )

= 28665 N

distance by which friction acted = √ (5.54² + 6.19²)

= 8.3 m

work done by friction

= 28665 x 8.3

= 237919.5 J

Total kinetic energy of cars = work done by friction

1/2 x 1600 x v² + 1/2 x 2300 u² = 237919.5

16 v² + 23 u² = 4758.4

1600 x v / 2300 u = 6.19 / 5.54

v / u = 1.6

v = 1.6 u

putting this equation in fist equation

40.96 u² + 23 u² = 4758.4

= 63.96 u² = 4758.4

u² = 74.4

u = 8.62 m /s

v = 13.8  m /s

At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

1/f1 = 1/v - 1/u1

1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)

1/f1 = 0 - 4

1/f1 = -4

f1 = -1/4

f1 = -0.25 meters

The initial lens power (P1) is the reciprocal of the focal length:

P1 = 1/f1

P1 = 1/-0.25

P1 = -4 diopters

Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:

1/f2 = 1/v2 - 1/u1

1/f2 = 1/0.40 - 1/0.25

1/f2 = 2.5 - 4

1/f2 = -1.5

f2 = -1/1.5

f2 = -0.67 meters

The final lens power (P2) is the reciprocal of the focal length:

P2 = 1/f2

P2 = 1/-0.67

P2 ≈ -1.49 diopters

Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

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Answer:

Vp = velocity of plane

Vpx = Vp cos 55 = 8 * .57 = 4.59 m/s      velocity of plane along x-axis

Vpy = Vp sin 55 = 8 * .82 = 6.55 m/s        velocity of plane along y-axis

If Wx = -3 m/s then

Vx = 4.59 - 3 = 1.59 m/s

Vy = 6.55 m/s      wind does not affect vertical speed

tan theta = Vy / Vx = 6.55 / 1,59 = 4.12

theta = 76.4 deg    above x-axis

V = (1.59^2 + 6.55^2)^1/2 = 6.74 m/s

Answer:

12\(s^{-1}\)

Explanation:

Period= how long for each revolution

Since we have 10 revolutions in 120 seconds.

120/10=12s

Answer:

The value is  \(u = 72.69 \ m/s\)

Explanation:

From the question we are told that

The amount of force a square meter of an aircraft wing should produce is \(F = 1000 \ N\)

 The air speed relative to the bottom of the wing is  \(v = 61.1 \ m/s\)

   The air level density of air is  \(\rho_s = 1.29\ kg/m^3\)

Gnerally this  force per square meter  of an aircraft wing is mathematically represented as

              \(F = \frac{1}{2} * \rho_s * A * [ u^2 - v^2 ]\)

Here u is the speed air need to go over the top surface to create the ideal lift

          A  is the area of a square meter i.e   \(A = 1 \ m^2\)

So              

           \(1000 = \frac{1}{2} * 1.29 * 1 * [ u^2 - 61.1 ^2 ]\)

=>         \(u = 72.69 \ m/s\)            

Answer:

To determine the maximum speed that the 8.3 kg mass can have without breaking the string, we need to consider the tension in the string when it reaches its maximum. At maximum speed, the tension in the string will be equal to the breaking strength of the string.

Given:

Mass (m) = 8.3 kg

Breaking strength of the string (Tension) = 1500 N

Radius of the circle (r) = 80 cm = 0.8 m

The centripetal force required to keep an object moving in a circular path is given by the formula:

F = m * v² / r

Where:

F = Centripetal force

m = Mass

v = Velocity

r = Radius

In this case, the centripetal force is provided by the tension in the string. So we have:

Tension = m * v² / r

Plugging in the values:

1500 N = (8.3 kg) * v² / 0.8 m

To find the maximum speed (v), we can rearrange the equation and solve for it:

v² = (1500 N * 0.8 m) / 8.3 kg

v² ≈ 144.58 m²/s²

v ≈ √(144.58 m²/s²)

v ≈ 12.03 m/s

Therefore, the maximum speed that the 8.3 kg mass can have without breaking the string is approximately 12.03 m/s.

Explanation:

Answer: Delta U = 30 - 80; -50 jules

Explanation:

The system is losing 80 J, but it is also gaining 30 J because the surroundings are doing work on it. So the net change in energy is -50 J

The scenario presented is an example of negative punishment.

Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.

In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.

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The work needed to stop an object is equal to the kinetic energy of the object:

Write the speed in meters per second using the fact that 1m/s=3.6km/h. Then, the work needed to stop the car is:

Therefore, the work that must be done to stop the car is approximately 390,139J.

Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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25mn type of focal length was primarily used in citizen kane.

The focal lengths and lenses used by 19 notable directors are analyzed in a new video essay by Wolfcrow, starting with Orson Welles' use of 25mm for Citizen Kane and 18mm for Touch of Evil.

In Orson Welles' Citizen Kane, deep focus was frequently used to provide the audience with insight into Charles Foster Kane's thoughts or to reveal more about his life. With deep focus, the foreground, middle ground, and backdrop are all sharply in focus at once.

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Answer:

c thats the answer yep

Answer:

D.

Explanation:

The wire allows the current to follow the quickest path & will therefore follow the XY wire, restricting the energy source from reaching bulbs 1 and 2 which are beyond that wire.

The efficiency of an engine is defined as ratio of the useful work done to the heat provided or,

in terms of temperature of the source and the sink the efficiency of heat engine is given by \(1-\frac{T_{2} }{T_{1} }\)

Thus, we have two formulae to calculate the efficiency of a heat engine.

η= \(\frac{useful work done}{heat absorbed}\) ....1

η= \(1-\frac{T_2}{T_1}\)             ....2   (where \(T_{2}\) and \(T_{1}\) are temperatures of sink and source respectively)

Given quantities are,

Now, by equating (1) and (2) equation,

⇒ \(1-\frac{T_2}{T_1}\) = \(\frac{Useful work done}{Heat absorbed}\)

Substituting the given values;

⇒ \(1-\frac{288}{830}\) = \(\frac{230000}{heat absorbed}\)

⇒therefore, heat absorbed = 353846.15 J

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F = m*a

a = F /m

Where:

F= sum of forces

m = mass

a= acceleration

Sum of forces = thrust of the rocket - air resistance = 1.5 x 10^7 N - 4.7x10^6 N = 10,300,000 = 1.03 x 10^7 N

A = 1.03 x 10^7 / 4.75 x 10^5

A = 21.68 m/s^2

In a cartesian coordinate system with three axes along three edges of room, fly changes its position from point (4.00 m, 1.50 m, 2.50 m) to (1.57 m, 2.7 m, 0.55 m), then Displacement vector = -2.43 i + 1.2 j - 1.95 m

A geometric object which encodes both displacement and direction is called displacement vector. Displacement vector from one point to another is an arrow with its tail at first point and its tip at second.

Given (4.00 m, 1.50 m, 2.50 m) to (1.57 m, 2.7 m, 0.55 m).

Displacement vector along x axes is 1.57 - 4.00= -2.43 m

Displacement vector along y axes is 2.7 - 1.50 = 1.2 m

Displacement vector along z axis is 0.55- 2.50 = - 1.95 m

Displacement vector is -2.43 i + 1.2 j - 1.95 m.

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Note: The given question on the portal is not incomplete. Here is the complete question.

Question: a fly enters through an open window and zooms around the room. in a cartesian coordinate system with three axes along three edges of the room, the fly changes its position from point (4.00 m, 1.50 m, 2.50 m) to (1.57 m, 2.7 m, 0.55 m). Find the scalar components of the flies displacement vector (in m).

Answer:

\(-5.39\times10^{33} J\)

Explanation:

Potential energy =

\(-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J\)

Answer:

Antonie van Leeuwenhoek

Explanation:

Answer:

hi-

Explanation:

During the early teenage years, friendships become more intense, close and supportive. The amount that teenagers communicate with their friends increases. Teenage friendships tend to be based on personal similarity, acceptance and sharing. Same gender friendships are most common during the early high school years.

The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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