briefly describe the simplest continuous cooling heat treatment procedure that would be used in converting a 4340 ste
Answers
We must succinctly describe the simplest continuous cooling heat treatment procedure that would be used to alter the microstructure of a 4340 steel in order to overcome this problem. The solution to this problem requires the use of Figure 10.28.
(a) It requires heating to approximately 720°C, allowing for complete austenitization, and then cooling to room temperature at a pace slower than 0.006°C/s in order to go from (martensite + bainite) to (ferrite + pearlite).
(b) The alloy needs to be heated to about 700°C for several hours in order to change from (martensite + bainite) to spheroidite.
(c) To change from (martensite + bainite) to (martensite + bainite + ferrite), it is necessary to heat the material to a temperature over 720°C, let the austenitization process finish, and then cool the material to room temperature between 0.3°C/s and 0.02°C/s.
Heat treatment is a group of thermal, industrial, and metallurgical processes used to modify the physical, and sporadically the chemical, properties of a material. The most common application is in metallurgy. Heat treatments are used to create a variety of different materials, including glass. To harden or soften materials in order to achieve the desired result, heat treatment involves heating or cooling them—typically to very high temperatures. Heat treatment techniques include quenching, annealing, case hardening, precipitation strengthening, tempering, and carburizing. Although the term "heat treatment" only refers to processes where heating and cooling are carried out specifically to change a material's properties, heating and cooling frequently happen by accident during other production processes like hot shaping or welding. Heat treatment is a group of thermal, industrial, and metallurgical processes used to modify the physical, and sporadically the chemical, properties of a material. The most common application is in metallurgy. Heat treatments are used to create a variety of different materials, including glass. To harden or soften materials in order to achieve the desired result, heat treatment involves heating or cooling them—typically to very high temperatures. Heat treatment techniques include quenching, annealing, case hardening, precipitation strengthening, tempering, and carburizing. Although the term "heat treatment" only refers to processes where heating and cooling are carried out specifically to change a material's properties, heating and cooling frequently happen by accident during other production processes like hot shaping or welding.
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Related Questions
By balancing information security and access, a completely secure information system can be created.A. TrueB. False
Answers
Answer: true
Explanation:
20. CNG containers need to be inspected
A) After the vehicle goes through the car wash
B) After the vehicle is rained on
C) After the vehicle is involved in an accident or fire
D) After the vehicle is parked outside for several hours
Answers
Answer:
After the vehicle is involved in an accident or fire.
After the vehicle is involved in an accident or fire. Therefore option C is correct.
CNG (Compressed Natural Gas) containers in vehicles need to be inspected after the vehicle is involved in an accident or fire. This is because accidents or fires can cause structural damage or compromise the integrity of the CNG container.
It's crucial to assess the container's condition thoroughly after such incidents to ensure there are no leaks or damages that could lead to hazardous situations.
Regular inspections help identify any potential safety risks and ensure that the CNG container remains in a safe and functional state, promoting the overall safety of the vehicle and its occupants.
Inspections after other events like car washes, rain, or parking outside are not necessary for CNG container safety.
Therefore option C is correct.
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Statement and decision testing exercise
Scenario: A vending machine dispenses either hot or cold drinks. If you choose a hot drink (e.g. tea or coffee), it asks if you want milk (and adds milk if required), then it asks if you want sugar (and adds sugar if required), then your drink is dispensed.
a. Draw a control flow diagram for this example. (Hint: regard the selection of the type of drink as one statement.)
b. Given the following tests, what is the statement coverage achieved? What is the decision coverage achieved? Test 1: Cold drink Test 2: Hot drink with milk and sugar
c. What additional tests would be needed to achieve 100% statement coverage? What additional tests would be needed to achieve 100% decision coverage?
Answers
To achieve 100% statement coverage, additional tests are needed to cover different combinations of drink preferences (milk and sugar). For 100% decision coverage, tests should cover both the selection of drink type and the decisions related to adding milk and sugar.
a. Control Flow Diagram:
Start
|
V
Choose Drink Type (Hot or Cold)
|
V
IF Hot Drink
| |
| V
| Ask for Milk Preference
| |
| V
| IF Milk Required
| | |
| | V
| | Add Milk
| | |
| | V
| | Ask for Sugar Preference
| | |
| | V
| | IF Sugar Required
| | | |
| | | V
| | | Add Sugar
| | | |
| | | V
| | V
| V
| Dispense Hot Drink
|
V
ELSE (Cold Drink)
|
V
Dispense Cold Drink
|
V
End
b. Given the tests:
Test 1: Cold drink
Test 2: Hot drink with milk and sugar
Statement Coverage achieved: The statement coverage achieved would be 10 out of 15 statements (66.7%).
Decision Coverage achieved: The decision coverage achieved would be 2 out of 3 decisions (66.7%).
c. Additional tests for 100% statement coverage:
Test 3: Hot drink without milk and sugar
Test 4: Hot drink with milk only
Test 5: Hot drink with sugar only
Test 6: Hot drink without milk and without sugar
Additional tests for 100% decision coverage:
Test 7: Cold drink
Test 8: Hot drink with milk and sugar
Test 9: Hot drink without milk and sugar
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P = 65 lb. The pin at C is attached to member ABCD and passes through the smooth slot in member ECF.
Part 1) Determine the horizontal and vertical components of force that the pin A exerts on member ABCD.
Part 2) Determine the horizontal and vertical components of force that the pin B exerts on member ABCD.
Part 3) Determine the horizontal and vertical components of force that the pin C exerts on member ABCD.
Please help with all parts. Thank you
Answers
The horizontal component of force exerted by pin A on member ABCD is zero, and the vertical component is 65 lb upward.
The horizontal component of force exerted by pin B on member ABCD is zero, and the vertical component is 65 lb downward.
The horizontal component of force exerted by pin C on member ABCD is zero, and the vertical component is 65 lb.
In this system, the forces acting on member ABCD are determined by the pin connections at points A, B, and C. Since the slot in member ECF is smooth, it does not exert any forces on member ABCD. Let's analyze each pin separately:
Part 1) Pin A is attached to member ABCD at point A. Since the slot in member ECF is smooth, there is no horizontal force acting on member ABCD at point A. The vertical component of the force exerted by pin A is equal to the weight of the system, which is 65 lb upward.
Part 2) Pin B is attached to member ABCD at point B. Similar to pin A, there is no horizontal force exerted by pin B on member ABCD. However, the vertical component of the force exerted by pin B is equal to the weight of the system, which is 65 lb downward. The direction is downward because pin B is positioned below the center of gravity.
Part 3) Pin C is attached to member ABCD and passes through the smooth slot in member ECF. As with pins A and B, there is no horizontal force exerted by pin C on member ABCD. The vertical component of the force exerted by pin C is equal to the weight of the system, which is 65 lb.
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WILL MAKE AS BRAINLEST
I answered some of them can anyone help with the rest?
1. What document granted permission to found and established the boundaries of the Georgia Colony?
The charter
2. Why was Georgia founded as a “buffer colony”?
defend the southern British colonies from Spanish Florida.
3. Why did Oglethorpe originally want to start a new colony in the New World?
He wanted to give debtors another chance at life instead of prison
4. According to the Charter of 1732, what are the three reasons for starting the colony of Georgia?
Charity Economics Defense
5. How did the relationship between Oglethorpe and Tomochichi impact the founding and establishment of the colony of Georgia?
6. Who founded the city of Savannah?
James Oglethorpe
7. Describe, in detail, how the following individuals contributed to the founding of Georgia:
Tomochichi:
Mary Musgrove:
8. What were the Salzburgers able to produce that the colonists of Savannah had trouble producing?
9. Who was the interpreter /ambassador between Oglethorpe and Tomochichi?
10. Who was the leader of the Yamacraw Indians?
11. What did the Malcontents want to happen in Georgia? (Think rules)
12. Who is credited with saving the lives of many colonists from disease (cholera) after he and his people were allowed into the colony of Georgia?
13. What type of colony was Georgia at first? Who would oversee the colony of Georgia?
14. After the Trustee Colony fell, what type of colony would Georgia become?
15. Who “ran” the colony of Georgia once it became a Royal Colony?
16. What rule did the Malcontents want to change the most?
Land
17. When the slavery ban was lifted, Georgia saw a rapid increase in what between 1750-1775?
Agraculture
18. What did the Royal Governors do that help prove they were trying to keep the settlers satisfied? (Think change in rules/laws)
19. What were the five main goods that were sold in the Georgia Colony? Remember WRIST
20. What increased dramatically after the Royal period began?
What type of shading techniques requires using the side of the pencil to add value.
Answers
Answer:
YES
Explanation:
NO
;-;
How did engineers help to create a ceiling fan
Answers
Answer:
The electric ceiling fan was invented in 1882 by engineer and inventor, Philip Diehl. He had earlier invented an electric sewing machine and adapted the motor from this invention to create the ceiling fan. He called his invention the “Diehl Electric Fan” and it was such a success that he soon had many other people competing with him.
Explanation:
what type of comptuer was name for the cabinet where the brains
Answers
Answer: Central Processing Unit
The most common type of compressor housing used in a domestic refrigerator is the ____________________ type.
Answers
The most common type of compressor housing used in a domestic refrigerator is the hermetic type.
In a domestic refrigerator, the hermetic compressor housing is the most commonly employed design. The hermetic compressor consists of a sealed unit that contains both the compressor and the motor, ensuring they are enclosed and protected from external factors. This design offers several advantages, including improved efficiency, reduced noise, and simplified maintenance. The hermetic housing prevents the leakage of refrigerant and allows for a compact and space-efficient refrigerator design. By incorporating the compressor and motor within a sealed unit, the hermetic type ensures reliable and efficient operation of the refrigerator.
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Identify this instrument.
Refracting telescope
Reflecting telescope
Microscope
Radio Telescope
Answers
What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height
Answers
The approximate average power output is mathematically given as
P=1097.6w
What is the approximate average power output?
Question Parameters:
Iowa with a 10 m2 swept area and 50 m hub height
Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2
Generally, the equation for the average output power is mathematically given as
\(P=0.5 \phi BAu^3*n\\\)
Where
B= Benz coefficient
n=0.8
Therefore
P=0.5*1*0.8*10*7^3*0.8
P=1097.6w
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Complete Question
What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height? Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2
A key joint in a precision machining process has a lower specification limit of a width of 0.99 mm and an upper specification limit of 1.01 mm. The standard deviation is 0.005 mm and the mean is 1 mm. What is the process capability index for the precision machining process
Answers
Answer:
the process capability index for the precision machining process is 0.667
Explanation:
Given the data in the question;
Lower Specification Limits LSL = 0.99 mm
Upper Specification Limits USL = 1.01 mm.
The standard deviation σ = 0.005 mm
mean μ = 1 mm
capability index Cpk = ?
Cpk = min( USL - μ / 3σ, μ - LSL / 3σ )
we substitute
Cpk = min( 1.01 mm - 1 mm / 3(0.005 mm ), 1 - 0.99 mm / 3(0.005 mm) )
Cpk = min( 0.01 mm / 0.015 mm, 0.01 mm / 0.015 mm )
Cpk = min( 0.6666, 0.6666 )
∴ Cpk = 0.6666 ≈ 0.667
Therefore, the process capability index for the precision machining process is 0.667
When you do a vehicle check, what do you NOT need to keep an eye on?
A. Proper tire inflation
B. Cleanliness of windows and mirrors
C. Functioning indicator lights and headlights
D. Blindspot locations
Answers
Answer:
Blindspot Location
Explanation:
Just took the quiz
When you do a vehicle check, you do NOT need to keep an eye on Blind spot locations. The correct option is D.
What is Blind spot location?A blind spot is the area of the road that can't be seen by looking forward through windscreen, or by rear-view and side-view mirrors.
While doing vehicle check, we need to check tire inflation, cleanliness of windows and mirrors along with the functioning indicator lights and headlights.
Blind spot locations does not need to be checked.
Thus, the correct option is D.
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g imagine you are using pulse-width-modulation (pwm) to output an analog voltage signal with your arduino (which can only output 0v or 5v). what duty cycle would you use to output 3v? group of answer choices 40% 2% 20% none of the other answers 60%
Answers
Pulse Width Modulation, or PWM, is a technique for getting analog results with digital means.
What duty cycle would you use to output 3v?
To get 3V from a microcontroller digital pin which can either be high at 5V or LOW at 0V, we need to use a PWM signal of 60% duty cycle .The duty cycle controls the analog voltage in a very direct way; the higher the duty cycle the higher the voltage. In the case of the BASIC Stamp, the duty cycle can range from 0 to 255. Duty is literally the proportion of 1s to 0s output by the PWM command.Duty cycle can take on values only between 0 and 1; therefore, the output voltage of a boost regulator is always higher than the input voltage. The duty cycle is between 0 and 1. It can be 0 if the chopper switch is never on and it can be 1 when the chopper switch is always on. 9. If T is the time period for a chopper circuit and α is its duty cycle, then the chopping frequency is. a) Ton/α.To learn more about duty cycle refers to:
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pipelines are cleaned by pushing through them a close-fitting cylinder called a pig. the name comes from the squealing noise it makes sliding along. a new non-toxic pig is driven by compressed air for cleaning cosmetic and beverage pipes. the pig diameter is 5-15/16 in and its length 121 in. it cleans a 6-in-diameter pipe at a speed of 1.2 m/s. if the clearance is filled with glycerin at 20°c, what pressure difference, in pascals, is needed to drive the pig? assume a linear velocity profile in the oil and neglect air drag.
Answers
The pressure difference of 317.6 Pa is needed to drive the pig through the glycerin-filled pipe at the given speed.
We have,
The pig's diameter is 5-15/16 in and its length is 121 in. it cleans a 6-in-diameter pipe at a speed of 1.2 m/s.
Now, For the pressure difference needed to drive the pig, we can use the pressure drop equation for flow in a pipe:
ΔP = (128μLQ)/(πd⁴)
where: ΔP = pressure drop (Pa)
μ = dynamic viscosity of glycerin at 20°C (Pa × s)
L = length of the pipe (m)
= volumetric flow rate (m³/s)
d = diameter of the pipe (m)
First, we need to calculate the volumetric flow rate of glycerin through the 6-inch pipe.
The pig is moving at a speed of 1.2 m/s, so the volumetric flow rate can be calculated as:
Q = π/4 (6/39.37)² × 1.2
Q = 0.02188 m³/s
Next, we need to look up the dynamic viscosity of glycerin at 20°C.
We know that the dynamic viscosity of glycerin at 20°C is 0.00149 Pa × s.
Using these values, we can calculate the pressure drop:
ΔP = (128 × 0.00149 × 121 × 0.02188)/(π(5.9375/39.37)⁴)
= 317.6 Pa
Therefore, a pressure difference of 317.6 Pa is needed to drive the pig through the glycerin-filled pipe at the given speed.
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: (a) A 3-phase induction motor has 8 poles and operates with a slip of 0.05 for a certain load Compute (in rpm): i. The speed of the rotor with respect to the stator ii. The speed of the rotor with respect to the stator magnetic field iii. The speed of the rotor magnetic field with respect to the rotor iv. The speed of the rotor magnetic field with respect to the stator V. The speed of the rotor magnetic field with respect to the stator magnetic field
Answers
The speed of the rotor with respect to the stator is 2,856 rpm, and the speed of the rotor with respect to the stator magnetic field is 2,860 rpm.
The synchronous speed of a 3-phase induction motor is given by the formula: Ns = 120f/p, where Ns is the synchronous speed in rpm, f is the frequency of the power supply, and p is the number of poles. In this case, since the motor has 8 poles, the synchronous speed is Ns = 120f/8 = 15f.
The speed of the rotor with respect to the stator is given by the formula: Nr = (1 - s)Ns, where Nr is the rotor speed, and s is the slip. The slip is given as 0.05, so the rotor speed is Nr = (1 - 0.05)15f = 14.25f.
The speed of the rotor with respect to the stator magnetic field is given by the formula: Nrm = Nr - Ns = 14.25f - 15f = -0.75f. This indicates that the rotor is rotating in the opposite direction to the stator magnetic field, with a speed of 0.75 times the frequency.
The speed of the rotor magnetic field with respect to the rotor is the slip speed, which is given as Nsr = sNs = 0.05*15f = 0.75f.
The speed of the rotor magnetic field with respect to the stator is the sum of the rotor speed and the rotor magnetic field speed, which is Ns + Nsr = 15f + 0.75f = 15.75f.
The speed of the rotor magnetic field with respect to the stator magnetic field is the difference between the rotor speed and the rotor magnetic field speed, which is Nr - Nsr = 14.25f - 0.75f = 13.5f.
Therefore, the calculated speeds are as follows: i) the speed of the rotor with respect to the stator is 14.25f or 2,856 rpm (assuming a 50 Hz power supply), ii) the speed of the rotor with respect to the stator magnetic field is -0.75f or -150 rpm, iii) the speed of the rotor magnetic field with respect to the rotor is 0.75f or 150 rpm, iv) the speed of the rotor magnetic field with respect to the stator is 15.75f or 3,150 rpm, and v) the speed of the rotor magnetic field with respect to the stator magnetic field is 13.5f or 2,700 rpm.
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A boat leaves port and follows a course of N75E st 9 knots for 3 hr and 20 min. Then, the boat changes to a new course of S29 E at 12 knots for 5 hr. Part: 0/3 Part 1 of 3 (*) How far is the boat from port? Round the answer to one decimal place if necessary The boat is approximately from port Х
Answers
The boat is approximately 67.3 nautical miles from the port (rounded to one decimal place).
To determine the distance of the boat from the port, we can break down the boat's movement into two legs: the first leg traveling on the N75E course and the second leg traveling on the S29E course.
First, let's calculate the distance covered in the first leg:
Distance = Speed × Time
Speed = 9 knots
Time = 3 hours and 20 minutes = 3.33 hours (rounded to two decimal places)
Distance of the first leg = 9 knots × 3.33 hours = 29.97 nautical miles (rounded to two decimal places)
Next, let's calculate the distance covered in the second leg:
Speed = 12 knots
Time = 5 hours
Distance of the second leg = 12 knots × 5 hours = 60 nautical miles
To find the total distance from the port, we need to calculate the vector sum of the two distances:
Total distance = √((Distance of first leg)² + (Distance of second leg)²)
Total distance = √((29.97)² + (60)²) ≈ 67.34 nautical miles (rounded to two decimal places).
Therefore, the boat is approximately 67.3 nautical miles from the port (rounded to one decimal place).
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INSTRUCTIONS
Create a "starter" risk register for the two projects (A and B) described below. Include at least 6 risks for project A
Project A
Description
Building a garden shed. This includes the design of the shed, sourcing all the materials required for construction, and putting all of the various pieces together to get the finished shed.
Outcome
A finished garden shed.
Proposed Tasks
There are going to be certain tasks that depend on others. You’re going to need to:
Get a set of blueprints for the shed and clear and prepare the area for construction
Source all of the materials for the construction
Prepare the foundation and start constructing the beams of the floor
Lay the floorboards
Construct the frames of the walls and raise and fit each of them
Frame the roof and attach the roofing
Fit in all the siding for the walls
Fit in the windows and the doors
From this, it’s obvious that you won’t be able to start fitting the walls until the floor is in place or start work on the roof until walls have been raised.
Stakeholders
Besides yourself and those living in your home, your team can be neighbors, or friends. You’ll need to lead them and give them direction on the tasks you want them to do. Outside risks include bad weather or the hardware store not having certain items or being closed when you need it.
Timeline
For a project like this that is relatively simple, the timeline depends on how large your team is. With 10 people working on a garden shed, it could be finished in a matter of hours, but doing it alone may take 2-3 weekends of time.
Answers
A risk register is a log of all potential hazards, risks, and uncertainties that a project may encounter. It also has an explanation of the probability of the danger occurring and its potential impact.
A risk register's purpose is to assist in the identification, assessment, and management of risks associated with a project and is an essential part of a successful risk management strategy. As such, the risk register has six components, including the risk description, risk cause, impact, risk likelihood, risk impact, and risk ranking.The following are six potential hazards for Project A and their explanations:
1. Weather Issues: Bad weather can slow down the construction process, make it dangerous to work outside, or damage materials.
2. Availability of Materials: If materials are scarce, it can delay or halt the construction project.
3. Time Constraints: Limited time can result in project delays or cutting corners, which can impact the quality of work.
4. Cost Overruns: Unexpected or uncontrollable costs can result in the project being halted or completed poorly.
5. Inadequate or Faulty Tools: This can affect work quality, safety, and efficiency, ultimately impacting the project schedule and costs.
6. Safety Issues: Inadequate safety protocols can result in accidents that could lead to injury or death of workers on the site.In conclusion, the risk register for Project A should outline potential hazards, their causes, impact, likelihood, and ranking, as well as mitigation strategies. The risk register should be reviewed and updated regularly to ensure that new risks are identified and addressed.
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how do you check effectiveness of the parking brake?
Answers
To test the effectiveness of the parking brake, engage the brake, shift to neutral/park and try to move the vehicle gently with the gas pedal.
To test the effectiveness of the parking brake, follow these steps:
1: Find a flat and safe location to park the vehicle.
2: Engage the parking brake by pulling the lever or pressing the pedal and shift the vehicle into neutral or park.
3: Attempt to move the vehicle by gently pressing on the gas pedal.
4: If the parking brake is working properly, the vehicle should not move.
5: If the vehicle moves, it could indicate a problem with the parking brake.
6: In this case, it is recommended to have the parking brake system inspected by a professional mechanic.
Regularly testing the parking brake is important to ensure the safety of your vehicle and those around you.
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What prevented this weld from becoming ropey?
A lower ampera
A higher voltage
The position of the weld
The stepping motion of the weld
Answers
Answer:
If I am not mistaken I believe it is a higher voltage.
Explanation:
Hope this helps
While discussing PCV valve operation: Technician A says that the PCV valve opening is decreased at part-throttle operation compared to idle operation. Technician B says that the PCV valve opening is decreased at wide-open throttle compared to part throttle. Who is correct?
Answers
Answer:
Both are incorrect.
Explanation:
PCV valve opening is dependent on amount of manifold vacuum value. The opening cannot decrease due to part throttle operation. The PCV system is a tampered valve whose opening depend upon intake manifold vacuum. PCV valve is supported by a spring and is initially in a closed position.
An AC bridge has 4 arms. In arm AB, a 120 kilo-ohm resistor and a 47 microfarads capacitor are connected in parallel while arm BC has 330 microfarads capacitor. If arm AD has a 330 kilo-ohm resistor, calculate the value of the unknown capacitor and resistor in arm CD connected in series. (AC power is supplied through A and C while the detector is connected across BD)
Answers
The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.
To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)
Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).
Therefore, Cseries = 330 microfarads.
Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).
Using the following formula:
Rtotal = R + 1/Xc
Where Xc = 1/2πfC,
f is the frequency and C is the capacitance.
For this problem,
Xc = 1/2π(50)(330 x 10-6)
=> 100 kilo-ohm.
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You should always try to put out a fire if you see one, no matter how large it is.
Answers
Answer:
That's not true, if your house is burning down, leave. Let the firefighters do their jobs.
Explanation:
Consider a condenser in which steam at a specified temperature is condensed by rejecting heat to the cooling water. If the heat transfer rate in the condenser and the temperature rise of the cooling water is known, explain how the rate of condensation of the steam and the mass flow rate of the cooling water can be determined. Also, explain how the total thermal resistance R of this condenser can be evaluated in this case.
Answers
Answer:
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Explanation:
How will the rate of condensation of the steam and the mass flow rate of the cooling water can be determined
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
compare and contrast workshop technology and workshop practice
Answers
Answer:
1.1 Introduction
Workshop practice is a very vast one and it is very difficult for anyone to claim a mastery over it. It provides the basic working knowledge of the production and properties of different materials used in the industry. It also explains the use of different tools, equipments, machinery and techniques of manufacturing, which ultimately facilitate shaping of these materials into various usable forms. In general, various mechanical workshops know by long training how to use workshop tools, machine tools and equipment. Trained and competent persons should be admitted to this type of mechanical works and permitted to operate equipment.
A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 75 MPa (68.25 ksi). If the plate is exposed to a tensile stress of 361 MPa (52360 psi) during use, determine the minimum length of a surface crack that will lead to fracture. Assume a value of 1.03 for Y.
Answers
Answer:
Explanation:
From the given information:
Strain fracture toughness \(K_k\)= 75 MPa\(\sqrt{m}\)
Tensile stress \(\sigma\) = 361 MPa
Value of Y = 1.03
Thus, the minimum length of the critical interior surface crack which will result to fracture can be determined by using the formula:
\(a_c = \dfrac{1}{\pi} ( \dfrac{k_k}{\sigma Y})^2 \\ \\ a_c = \dfrac{1}{\pi} \Big [ \dfrac{75 \times \sqrt{10^3}}{361 \times 1.03 } \Big]^2 \\ \\ a_c = \dfrac{1}{\pi} \Big [ 6.378474693\Big]^2 \\ \\ \mathbf{ a_c = 12.95 \ mm}\)
The compound beam shown in figure is pin connected at B. Determine the components of reaction at its supports. Neglect its weight and thickness.
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The values based on the information given will be Ra = 1000N and Rc= 90N
What is weight?Weight refers to the measure of the force of gravity on an object, and is typically measured in units of mass, such as kilograms or pounds. Weight is influenced by the mass of the object and the strength of the gravitational field it is in.
Thickness, on the other hand, refers to the measure of how thick an object is, or the distance between opposite surfaces of an object. Thickness is typically measured in units of length, such as millimeters or inches.
While weight and thickness are not directly related to each other, they can both play important roles in determining the properties and uses of an object. For example, a thin piece of metal may be lightweight, but may not be strong enough to support heavy loads. Conversely, a thicker piece of metal may be heavier, but may be able to support heavier loads due to its increased strength.
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while viewing a site plan, you notice that the contour lines have elevation numbers that increase toward the middle. this would indicate a
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while viewing a site plan, you notice that the contour lines have elevation numbers that increase toward the middle. this would indicate a hill
On your map, contour lines indicate the height above sea level at various locations. On a map, the relief depicts the elevational difference between two places. You may calculate the relief or elevation change between two points by removing the elevation differences between them.
On a topographic map, a contour line is a line drawn to denote a dip or elevation of the ground. The vertical separation or elevation difference between contour lines is known as a contour interval. Every fifth contour line has an index contour, which is a bolder or thicker line.
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Engineering ethics include ideas and directives related to: (a) Urban infrastructure (b) Contracts (c) Integrity (d) Corporate business practices
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Note that Engineering ethics include ideas and directives related to: All the above, that is Option A-D.
What is Engineering Ethics?Engineering ethics are the norms and principles that engineers must follow as a moral commitment to their profession and the world. Engineering is a professional occupation that has a significant influence on people's lives.
Engineers have a professional obligation to design and maintain infrastructure in a way that is safe, effective, and sustainable. This includes ensuring that urban infrastructure, such as roads, bridges, and buildings, meets the needs of the community and does not pose a risk to public safety.
All engineers often work under contracts with clients, and they have a professional obligation to fulfill the terms of these contracts in a timely and competent manner.
They are expected to act with integrity in all aspects of their work, including honesty, fairness, and respect for others.
Engineers working for corporations or other organizations have a professional obligation to uphold ethical standards. Hence, all the above options are related to Engineering Ethics.
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what is the division of demand
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2. Recycled tires are frequently turned into?
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Answer:
Play ground cover
Explanation:
Recycled tires are frequently turned into crumb rubber and tire-derived fuel
What are recycled?Recycled can be defined as a product that can be used for reuse by creating another material or a product or using the same products rather than destroying if it is being given a new form.
Recycle helps in various things while energy conservation and it also is pollution that is being created it is basically using of the material which is going to be trashed
Recycling one can easily convert tires into crumb rubber, and also it helps in deriving fuel as it can be used as coal which is being transformed into a heating purpose. It just helps in creating various substances that is basically lightweight it and eco-friendly product. It can create various other products like mouse pad or it can be used in an architectural purpose
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