Briefly describe earthing system​

Answer:

a) the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Explanation:

Given the data in the question;

Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in

Diameter d = 3/16 in

Unit weight w = 490 pcf

First we determine the area of the wire;

A = π/4 × d²

we substitute

A = π/4 × (3/16)²

A = 0.0276 in²

Next we get the Volume

V = Area × Length of wire

we substitute

V = 0.0276 × 4800

V = 132.48 in³

Weight of the steel wire will be;

W = Unit weight × Volume

we substitute

W = 490 × ( 132.48 / 12³ )

W = 490 × 0.076666

W = 37.57 lb

a) the maximum tensile stress due to the weight of the wire;

σ\(_w\) = W / A

we substitute

σ\(_w\) = 37.57 / 0.0276

= 1361.23 psi

Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi

Maximum load P that the wire can safely support its lower end will be;

P = ( σ\(_{all\) - σ\(_w\) )A

we substitute

P = ( 24000 - 1361.23  )0.0276

P = 22638.77 × 0.0276

P = 624.83 lb

Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb

The correct answer is (a) Signals.

In a computing environment, signals are used to notify a process or a thread of a particular event or condition. Signals are software interrupts that can be sent to a process by another process or by the operating system itself.

Signals can be used to interrupt the normal flow of execution of a process and to handle exceptional conditions, such as segmentation faults, illegal instructions, or user-defined events. They are often used to implement interprocess communication (IPC) mechanisms, allowing processes to send small messages to each other for synchronization or coordination purposes.

Traps, faults, and interrupts are also related to handling exceptional conditions in a computing environment, but they are not used for interprocess communication purposes like signals.

Aborts, on the other hand, refer to a type of error that occurs when a program or system fails to execute properly due to some internal error or external condition.

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Answer:

percentage yield = 63%

Explanation:

The yield efficiency or percentage yield measure the amount of products that are formed from a given amount of reactant. For a percentage yield of 100, all the reactants are completely converted to product. Mathematically, the percentage yield is given by:

\(percentage\ yield = \frac{Actual\ yield}{expected\ yield} \times 100\\Actual\ yield = 10.08kg\\Expected\ yield= 16.00kg\\\\\therefore percentage\ yield = \frac{10.08}{16.00} \times 100 = 63 \%\)

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature \(T_1 = -16^0\ C\)

Quality \(x_1 = 0.2\)

Outlet:

Temperature \(T_2 = -16^0 C\)

Quality  \(x_2 = 1\)

The following data were obtained at saturation properties of R134a at the temperature of -16° C

\(v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\ v_g = 0.1247 \ m^3 /kg\)

\(v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\ v_1 = 0.0255 \ m^3/kg \\ \\ \\ v_2 = v_g = 0.1247 \ m^3/kg\)

\(m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6 \\ \\ \mathbf{m = 0.0534 \ kg/sec}\)

\(\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2 \\ \\ \rho_1v_1 = \rho_2v_2 \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}\)

Answer:

No it is not permitted

Explanation:

It is not permitted  because as per NEC 410.21 policy no other conductor is allowed to be passed through integral junction box luminaries unless such conductor supply recessed luminaries.

The marking will show that the Luminaries is of the right construction or right installation to ensure that the the conductors ( in the outer boxes ) will not be exposed to temperatures greater than the conductor rating, hence the lack of marking makes it not to be permitted.

Answer:

2.9237 ft/s

Explanation:

Given the data in the question;

A₁ = 9-inch × 9-inch = 81 in² = 81 / 144 = 0.5625 ft²

V₁ = 6.1 ft/s

A₂ = 13 in × 13 in = 169 in² = 1.17361 ft²

v₂ = ?

using the the equation if continuity

( Rate of volumetric flow is constant )

A₁V₁ = A₂V₂

we substitute

0.5625 ft² × 6.1 ft/s = 1.17361 ft² × V₂

3.43125 ft³/s = 1.17361 ft² × V₂  

V₂  = 3.43125 ft³/s  / 1.17361 ft²

V₂ = 2.9237 ft/s

Therefore, the speed of the air flowing into the room is 2.9237 ft/s

Answer:

some of the professions and human resource related to engineering are:

Aerospace engineering involves the study, design and development of spacecrafts using Core science principles.

Electrical engineering involves the study and application of core science principles especially physics and mathematics into providing Electrical related solutions

Explanation:

Engineering is a major branch of applied science. In general Engineering is concerned with the design and building of engines ( i.e. application of scientific/science facts   )

some of the professions and human resource related to engineering are:

Aerospace engineering involves the study, design and development of spacecrafts using Core science principles.

Electrical engineering involves the study and application of core science principles especially physics and mathematics into providing Electrical related solutions

If you are following a truck that swings left before making a right turn at an intersection, it is very dangerous to assume that the truck is making a left turn and attempt to pass it on the right.

When a truck swings left before making a right turn, it is likely performing what is known as a "wide right turn." This maneuver is often necessary for larger vehicles to negotiate turns safely without encroaching into other lanes or hitting curbs. It allows the truck driver to create sufficient space for the rear wheels to clear the turn.

As a driver behind the truck, it is crucial to recognize and understand this maneuver. Attempting to pass the truck on the right can put you in the truck's blind spot and increase the risk of a collision when the truck completes its right turn. It is safer to wait until the truck has completed its turn and the way is clear before proceeding.

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Answer:

mark me brainliest

Explanation:

Superposition theorem is one of those strokes of genius that takes a complex subject and simplifies it in a way that makes perfect sense. A theorem like Millman’s certainly works well, but it is not quite obvious why it works so well. Superposition, on the other hand, is obvious.

Answer:

can you please not dealet my answer i dont understand the question mostly because the pic is blury for me

Explanation:

have a nice day

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

Ts = 311.86 K = 38.86°C

Explanation:

The convection heat transfer coefficient for vertical orientation of the board is given by the formula:

\(h = 1.42(\frac{T_{s} - T_{f} }{L})^{0.25}\)

where,

h = heat transfer coefficient

\(T_{s}\) = surface temperature

\(T_{f}\) = Temperature of fluid (air) = 30°C + 273 = 303 K

L = Characteristic Length = 50 cm = 0.5 m

Since the heat transfer through convection is given as:

\(Q_{conv} = hA_{s}(T_{s} - T_{f})\)

using value of h, we get:

\(Q_{conv} = 1.42(\frac{T_{s} - T_{f} }{L})^{0.25} A_{s} (T_{s} - T_{f} )\)

\(Q_{conv} = 1.42 A_{s} \frac{(T_{s} - T_{f} )^{1.25} }{L^{0.25} }\)

where,

\(A_{s}\) = Surface Area = (0.5 m)(0.5 m) = 0.25 m²

Now, the radiation heat transfer is given by:

\(Q_{rad} =\) εσ\(A_{s} [(T_{s})^{4} - (T_{surr})^{4}]\)

where,

ε = emissivity of surface = 0.7

σ = Stefan Boltzman Constant = 5.67 x 10⁻⁸ W/m².k⁴

\(T_{surr}\) = Temperature of surroundings = 25°C +273 = 298 k

Now, the total heat transfer rate will be:

\(Q_{total} = Q_{conv} + Q_{rad}\)

using values:

\(Q_{total} =\) \(1.42 A_{s} \frac{(T_{s} - T_{f} )^{1.25} }{L^{0.25} } +\) εσ\(A_{s} [(T_{s})^{4} - (T_{surr})^{4}]\)

we know that the total heat transfer from the board can be found out by:

\(Q_{total} = (0.18 W) (121) = 21.78 W\)

using values in the equation:

21.78 = (1.42)(0.25)\((T_{s} - 303)^{1.25}/0.5^{0.25}\) + (0.7)(5.67 x 10⁻⁸)(0.25)\([(T_{s})^{4} - 298^{4}]\)

21.78 = (0.4222)\((T_{s} - 303)^{1.25}\) + 9.922 x 10⁻⁹\((T_{s} )^{4}\) - 78.25

100.03 = (0.4222)\((T_{s} - 303)^{1.25}\)+ 9.922 x 10⁻⁹\((T_{s} )^{4}\)

Solving this equation numerically by Newton - Raphson Method (Here, any numerical method or an equation solver can be used), we get the value of Ts to be:

Ts = 311.86 K = 38.86°C

The film temperature is the average of surface temperature and surrounding temperature. Therefore,

Film Temperature = (25°C + 38.86°C)/2 = 31.93°C

Since, this is very close to 30°C.

Hence, the assumption is good.

Answer:

Thermal energy is measured using a thermometer denominated in Fahrenheit, Celsius and Kelvin

Then  you go to find the system requirements are the D. None of these as none of it dictates about the  find the system requirements hen needed.

User necessities describe what the person ought to do . System necessities describe how will the person acquire person necessities while interacting with the device plus nonpurposeful necessities such as "the device ought to cope with one hundred thousand customers on the identical time". So: User requirement : The person ought to see their check results.Where is device necessities.

For packaged products, device necessities are regularly imprinted on the packaging. For downloadable products, the device necessities are regularly indicated at the download page. System necessities may be widely categorized as purposeful necessities, records necessities, pleasant necessities and constraints.

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Answer:fall arrest harness

Explanation:cuz it’s just right

a. This is because an increase in pressure raises the boiling point of a substance by increasing the energy required for its molecules to overcome the external pressure and change from a liquid to a gas state.

b. The critical point represents the highest temperature and pressure at which a substance can exist as a distinct liquid and gas phase. The triple point, on the other hand, is the temperature and pressure at which the three phases (solid, liquid, and gas) of a substance coexist in equilibrium.

a. When pressure is increased, it compresses the gas phase and makes it more difficult for molecules to escape into the gas phase. This increases the energy required for the liquid to overcome the external pressure and change into a gas. As a result, the boiling point of water increases at higher pressures. For example, at sea level (normal atmospheric pressure), water boils at 100 degrees Celsius. However, if the pressure is increased, such as in a pressure cooker, the boiling point can rise above 100 degrees Celsius.

b. The critical point of a substance is the temperature and pressure at which the distinction between the liquid and gas phases disappears. At this point, the substance exhibits unique properties and is in a supercritical fluid state. The triple point, on the other hand, is the temperature and pressure at which the three phases (solid, liquid, and gas) of a substance coexist in equilibrium. It is the only combination of temperature and pressure at which all three phases can exist together. The triple point is used as a reference point in thermodynamics to define the temperature scale.

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To determine the highest gain available under the given conditions, we need to consider the bandwidth requirement and the 3-dB frequency of the circuit.

The 3-dB frequency represents the point at which the gain drops by 3 dB (approximately 70.7% of the maximum gain). In a noninverting op-amp circuit, the 3-dB frequency is given by the formula:

f = 1 / (2πRC)

where f is the 3-dB frequency and RC is the product of the resistor (R) and capacitor (C) values in the feedback network.

Given that the 3-dB frequency is 15 kHz, we can rearrange the formula to solve for RC:

RC = 1 / (2πf) = 1 / (2π * 15,000 Hz) = 1.06 × 10^(-5) s

To achieve a bandwidth of 32 kHz, we need to set the 3-dB frequency to half of the bandwidth. Therefore, the new RC value is:

RC = 1 / (2π * 16,000 Hz) = 9.95 × 10^(-6) s

Now, to calculate the highest gain available, we can rearrange the formula for the 3-dB frequency:

f = 1 / (2πRC)

and solve for the gain (A):

A = 1 + (Rf / Rin)

where Rf is the feedback resistor and Rin is the input resistor.

Rearranging the formula for gain:

Rf / Rin = A - 1

Since we want to find the highest gain, we want Rf / Rin to be as large as possible. This can be achieved by setting Rin to a very small value (close to 0) while keeping Rf relatively large.

Therefore, the highest gain available under these conditions can be obtained by using a feedback resistor (Rf) that is much larger than the input resistor (Rin).

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Answer:

identify function of the system unit and its components

Answer:

approaching a lady or a man

The five requirements for a valid offer are: 1) Intent to create legal relations, 2) Definite and certain terms, 3) Communication to the offeree,  4) Capability to form a contract, 5) Absence of termination or revocation.

Intent to create legal relations: In order for an offer to be valid, there must be an intention by the offeror to create a legally binding agreement. This means that the offeror must genuinely intend to be legally obligated if the offer is accepted.

Definite and certain terms: An offer must have clear and specific terms that outline the rights and obligations of the parties involved. This includes details such as the subject matter, price, quantity, and any other essential terms that are necessary for the formation of a contract.

Communication to the offeree: The offer must be effectively communicated to the offeree, the party to whom the offer is made. It is important that the offeree is aware of the offer and understands its terms in order to consider acceptance.

Capability to form a contract: Both the offeror and the offeree must have the legal capacity to enter into a contract. This means they must be of sound mind, of legal age, and not under any legal disability that would prevent them from forming a valid contract.

Absence of termination or revocation: The offer must not be terminated or revoked before it is accepted. Once an offer is terminated, it can no longer be accepted by the offeree. Similarly, if the offeror revokes the offer before it is accepted, it becomes invalid.

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The statement "Forging is a deformation process in which the work is compressed between two dies, using either impact or gradual pressure to form the part" is true because the dies exert pressure on the workpiece, causing it to deform.

Forging is indeed a deformation process in which a workpiece is compressed between two dies to shape it into the desired form. Let's take a closer look at how forging works.

In the forging process, the workpiece, often a heated metal billet or ingot, is positioned between two dies. These dies have specific contours and shapes that correspond to the desired final shape of the forged part. The dies are typically made of hardened steel and are usually mounted in a forging press or hammer.

When the forging process begins, compressive forces are applied to the workpiece by closing or striking the dies together. This pressure causes the material to flow and deform, taking the shape defined by the dies. The applied force can be achieved through impact, where a hammer or similar tool strikes the workpiece, or through gradual pressure exerted by a hydraulic or mechanical press.

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Answer:

20a=1000

Explanation:

Answer:

The answer is: c. reinsulate the hole with room temperature vulcanizing (RTV) silicone.

Answer: The correct way to achieve proper drive pinion gear bearing preload is to torque the pinion nut to the manufacturer’s specifications and then check for preload.

Explanation: Typical starting points for torque specifications are 55 lb-ft for 3/8-inch bolts/nuts, 75 lb-in for 7/16-inch bolt/nuts, and 125 lb-in for 1/2-inch nuts/bolts. Once the nut is properly torqued, check for preload by tapping the end of the pinion gear with a punch to ensure the races are fully seated, shake it to evaluate for excessive play.

Pinion bearings are bearings that support the weight of the drive shaft and transfer power from the differential to the wheels. Preload is the tension that is put on a bearing. In the case of pinion bearings, preload takes place in the form of a collapsible spacer that stays between the bearings. The required amount of tension is obtained by adjusting the space manually.

Other ways to achieve proper drive pinion gear bearing preload include using a crush sleeve or shims. Crush sleeves are used in place of spacers and are designed to be crushed when the pinion nut is tightened. This crushes the sleeve and creates tension on the bearings. Shims can also be used to adjust the space between bearings.

Common problems with drive pinion gear bearing preload include over-tightening or under-tightening of the pinion nut, which can lead to damage or failure of the bearings. It is important to follow manufacturer specifications when torquing the pinion nut and checking for preload.

Hope this helps, and have a great day!

Answer:

A) 2.6666666668.

B) 0.4999999999π.

Step-by-step:

a. We can use the three-point Gauss quadrature formula to approximate the integral of f(x) = 2x^2 + 1 over the interval [−1, 1] as follows:

∫[-1, 1] (2x^2 + 1) dx ≈ (1/3) [f(-1/√3)w1 + f(0)w2 + f(1/√3)w3]

where w1, w2, and w3 are the weights and −1/√3, 0, and 1/√3 are the sampling coordinates given in Table 4.1.

Substituting the values from the table, we get:

∫[-1, 1] (2x^2 + 1) dx ≈ (1/3) [(2(-1/√3)^2 + 1) 0.5555555556 + (2(0)^2 + 1) 0.8888888889 + (2(1/√3)^2 + 1) 0.5555555556]

≈ 2.6666666668

Therefore, the approximate value of the integral using three-point Gauss quadrature is 2.6666666668.

b. We can use the three-point Gauss quadrature formula to approximate the integral of f(x) = sin(x)cos(x) overthe interval [0, π/2] as follows:

∫[0, π/2] sin(x)cos(x) dx ≈ (π/6) [f(π/6)w1 + f(π/2)w2 + f(5π/6)w3]

where w1, w2, and w3 are the weights and π/6, π/2, and 5π/6 are the sampling coordinates given in Table 4.1.

Substituting the values from the table, we get:

∫[0, π/2] sin(x)cos(x) dx ≈ (π/6) [(sin(π/6)cos(π/6)) 0.5555555556 + (sin(π/2)cos(π/2)) 0.8888888889 + (sin(5π/6)cos(5π/6)) 0.5555555556]

≈ 0.4999999999π

Therefore, the approximate value of the integral using three-point Gauss quadrature is 0.4999999999π.

The answers I provided are approximations obtained using the three-point Gauss quadrature formula with the given weights and sampling coordinates. These approximations are not exact, but they should be close to the true values of the integrals.

To check the accuracy of the approximations, you can compare them with the exact values of the integrals. For example, the exact value of the integral ∫[-1, 1] (2x^2 + 1) dx is 4/3, and the exact value of the integral ∫[0, π/2] sin(x)cos(x) dx is 1/2.

Comparing the approximate values obtained using the three-point Gauss quadrature with the exact values, we can see that:

For the integral ∫[-1, 1] (2x^2 + 1) dx, the approximate value obtained using the three-point Gauss quadrature is 2.6666666668, which is close to the exact value of 4/3.

For the integral ∫[0, π/2] sin(x)cos(x) dx, the approximate value obtained using the three-point Gauss quadrature is 0.4999999999π, which is close to the exact value of 1/2.

Therefore, the answers I provided are reasonable approximations of the integrals using the three-point Gauss quadrature.

Hope this helps!

Answer:

Email etiquette is important

Explanation:

It is important to understand how to use correct email etiquette because it helps you communicate more clearly. It also makes you seem a bit more professional too. For example depending in who you're emailing like say you're emailing your teacher for help then here's how it'd go:

Dear(teacher name, capitalize, never use first name unless they allow it)

Hello (teacher name), my name is (first and last name) from your (number class) and I was wondering if you could please help me out with (situation, be clear on what you need help with otherwise it won't get through to them)? If you could that would be greatly appreciated!

Sincerely,

(your name first and last)

Answer:

The idle speed of a running compression should be between 50-75 PSI and that is about half of the static compression.

Explanation:

The Running or Dynamic compression is used to determine how well the cylinder in an engine  is absorbing air, reserving it for the proper length of time, and releasing it to the exhaust. The static or cranking compression test is used to check the sealing of the cylinder. Before performing the running compression test, the static compression test is first performed to rule out other issues like bent valves.

The standard value for the static compression is given by;

Compression ratio * 14.7 = Manufacturers Specification

The running compression should always be half of the static compression.

(a) The combinational logic circuit depicted in (a) is a circuit. One output LED and two input switches make up the device. Only when both input switches are closed or turned on does the output LED turn on.

Combinational logic is a subset of digital logic that is used in electronics and computer science to create circuits where the output is fully reliant on the input variables. The logical combinations of the input variables are the outputs in combinational logic. Gates like AND, OR, and NOT carry out the logical processes. Combinational logic's key benefit is that it is straightforward to build and simple to comprehend. Digital electronics frequently employs combinational circuits for tasks including data processing, signal processing, and mathematical computations. Adders, multiplexers, and demultiplexers are a few typical examples of combinational logic circuits.

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