brake fluid serves as a lubricant for the parts of the hydraulic system and ensures smooth and even operation.

Answer:

The answer is within the picture.

Explanation:

Based on the description provided, the diagram that correctly illustrates the movement of the ball from the child's perspective is C.

Considering the child is rotating and he or she catches the ball some seconds after throwing it, it can be concluded the trajectory is closed, which means the diagram should show the ball returning to the initial point.

Based on the above, diagrams A and B are not possible because the ball is not retruning to the child.

Considering the child is moving at a constant speed and in a defined circular area, it is expected the movement resembles a circle; however as the ball will be affected by a leftward force in case the child is moving clockwise the movement will not be exactly a circle. Based on the above, the best option is diagram C.

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Answer:

a has a faster period

Explanation:

Period only depends on the length, irrelevant to the mass.

a has a shorter length, so has a small period, or faster.

Answer:Lack of experience.

Explanation:

Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.

The required length and compressed length of the spring at the given force values are 13 cm and 8 cm respectively.

Explanation:

F = ke

k = spring constant ;

e = extension;

e = (Final length - Initial length)

Initial length, l = 10

Final length = L1 = 11

F = k(11 - 10)

F = k;

Length for a restoring force of 3F ;

3F = k(Final length - Initial length)

k = F

3F = F(L1 - 10)

3F = - 10F + F(L1)

F(L1) = 3F + 10F

F(L1) = 13F

L1 = 13

Hence, required length ls 13 cm

B.)

Let compressed length = c

2F = F(initial length - compressed length)

2F = F(10 - c)

2F = 10F - F(c)

F(c) = 10F - 2F

F(c) = 8F

c = 8F / F

c = 8 cm

Therefore, the required compressed length ls 8 cm

Spring:

A spring is an elastic body that stores mechanical energy. Coil springs are often used in daily life, but there are many different types of springs. Modern quills are usually made of spring steel, but non-metallic items like bows are also quills.

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Answer:

WATER TO A VAPOR

Explanation:

Explanation:

During transpiration, water goes from a root to a stomata.

Answer: C

Explanation: i have played sports in my life now i am no physics person but in order to follow the rules you have  to be a team player. and a part of being a team player is being positive and so b=a*d  

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

BS33

Explanation:

its a cable length meter used for measuring length of all kinds of wires.

1. People have to prepare for natural disasters in order to reduce the risk of injury, death, and property damage caused by the disaster.

Natural disasters are adverse events that occur naturally and are a result of the interaction between the physical environment and human activities. They can include floods, hurricanes, tornadoes, earthquakes, tsunamis, wildfires, landslides, volcanic eruptions, and extreme weather events. Natural disasters can have devastating impacts on communities, including loss of life, damage to property, displacement, and destruction of livelihoods. Governments, organizations, and individuals are increasingly working to reduce the impacts of natural disasters through improved risk management, infrastructure planning, and disaster response and recovery efforts.

2. People have to prepare for natural disasters in order to be able to respond quickly and efficiently in the event of an emergency.

3. People have to prepare for natural disasters in order to plan for the financial impacts of the disaster.

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The object accelerates for the first 4 s (0 to 4), then moves at a constant speed for the next 4 s (4 to 8), then speeds up again for the next 2 s (8 to 10), moves at another constant speed for 6 s (10 to 16), then slows to a stop for the last 4 s (16 to 20).

In the times where the speed is linearly increasing, the acceleration is constant and equal to the slope of those line segments. Where the speed is constant, acceleration is 0.

Recall that average acceleration is given by

a = ∆v / ∆t

So we get

[i] a = (20 m/s - 0) / (4 s - 0) = 5 m/s²

[ii] a = 0 (because the speed is constant at 12 s)

[iii] Not really sure what is meant by "total acceleration" here... Is it the sum of all accelerations observed here? If so, we know the acceleration 5 m/s² on [0, 4]; it's 0 for both [4, 8] and [10, 16]; and we can compute the acceleration for the remaining two intervals to be

[8, 10]: a = (30 m/s - 20 m/s) / (10 s - 8 s) = 5 m/s²

[16, 20]: a = (0 m/s - 30 m/s) / (20 s - 16 s) = -7.5 m/s²

Then the total might be 2.5 m/s². Maybe.

[iv] We can compute distance traveled by finding the area under the velocity curve. The area under the curve for the first 10 s can be split up into a triangle on [0, 2] with height 20 m/s and base 4 s; a rectangle on [4, 8] with height 20 m/s and base 4 s; and a trapezoid on [8, 10] with "base" lengths 20 m/s and 30 m/s, and "height" 2s. The total area is then

1/2 (20 m/s) (4 s) + (20 m/s) (4 s) + 1/2 (20 m/s + 30 m/s) (2 s) = 170 m

[v] We already have the distance traveled over the first 10 s, so just subtract the area of the trapezoid:

1/2 (20 m/s) (4 s) + (20 m/s) (4 s) = 120 m

[vi] This would be the acceleration we found in [iii] over the interval [16, 20]:

a = (0 m/s - 30 m/s) / (20 s - 16 s) = -7.5 m/s²

[vii] According to the plot, the velocity at 16 s is 30 m/s.

[viii] According to the plot, at 2s the velocity is 10 m/s.

Answer:

The alignment of the sun, earth, and moon being in a straight line causes very low and extra-high, low and high tides respectively due to the additive effect of the solar tide on the lunar tide.

Explanation:

Tides can be defined as the rise and fall of water level in water bodies such as lakes and oceans due to the gravitational force of attraction exerted by the moon on earth. The side closest to the moon creates a bulge of water known as high tide. Low tides are generally experienced when a sea level is not within the bulge.

Generally, the gravitational pull of the Moon cause visible changes on planet Earth's surface.

This ultimately implies that, the pull of the Moon's gravity causes high and low tides on planet Earth's surface.

The various types of ocean tides based on the position of the Earth, Moon and the Sun are;

I. Neap tides.

II. Spring tides.

III. Low tide.

IV. High tide.

V. Brown tide.

VI. Rip tide.

VII. Red tide.

Generally, the alignment of the sun, earth, and moon being in a straight line causes very low and extra-high, low and high tides respectively due to the additive effect of the solar tide on the lunar tide. Thus, this alignment of the sun, earth, and moon being in a straight line gives rise to spring tides.

Answer:

Go to this site.

Not a link, a suggestion, quizlet

Explanation:

Answer:

the canoe moved 1.2234 m in the water

Explanation:

Given that;

A man whose mass = 69 kg

A woman whose mass = 52 kg

at opposite ends of a canoe 5 m long, whose mass is 20 kg

now let;

x1 = position of the man

x2 = position of canoe

x3 = position of the woman

Now,

Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3

= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20

= (0 + 260 + 50 ) / ( 141 )

= 310 / 141

= 2.19858 m

Centre of mass is 2.19858 m

Now, New center of mass will be;

52 × 2.5 / ( 69 + 52 + 20 )

= 130 / 141

= 0.9219858 m  { away from the man }

To get how far, the canoe moved;

⇒ 2.5 + 0.9219858 - 2.19858

= 1.2234 m

Therefore, the canoe moved 1.2234 m in the water

The canoe move in the water will be 1.2234 m. The canoe move depending on the center of mass of the bodies.

The center of mass of an item or set of objects is a place specified relative to it. It's the average location of all the system's components, weighted by their mass.

The centroid is the location of the center of mass for simple rigid objects with homogeneous density. The center of mass of a uniform disc shape, for example, would be at its center.

The given data in the problem is;

m₁ is the mass of man = 69 kg

m₂ is the mass of woman whose= 52 kg

m₃ is the mass  of  canoe =  20 kg

L is the length of canoe = 5 m

x₁ is the position of the man

x₂ is the position of the canoe

x₃ is the position of the woman

The center of mass will be;

\(\rm COM= \frac{[m_1x_1 + m_2x_2 + m_3x_3]}{ m1 + m2 + m3} \\\\ \rm COM= \frac{[69 \times 0 +52 \times 5 + 20 \times 2.5]}{ 69+ 52 + 20} \\\\ \rm COM= (0 + 260 + 50 ) / ( 141 )\\\\ \rm COM = 310 / 141 \\\\ \rm COM = 2.19858 m\)

The new center of mass is;

\(\rm COM= \frac{52 \times 2.5 }{69+52+20} \\\\ \rm COM=\frac{130}{141} \\\\ \rm COM= 0.9219 m\)

The distance to find how the canoe moved will be found by;

\(\rm x= 2.5+0.9219-2.1985 = 1.2234\)

Hence the canoe move in the water will be 1.2234 m.

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Answer:

A object having kinetic energy is in motion state.And the object whi posses potential energy i s in state of podition.

Answer:

Objects are relative to other moving and stationary objects.

Kinetic energy can be transferred from one moving object to another.

Potential energy is stored energy in an object.

Answer:

d) blue light + yellow light

Explanation:

The color combination that will produce white light is blue light + yellow light. White light is the combination of all colors of the visible spectrum. When blue and yellow light are mixed together, they create a white light because blue and yellow are complementary colors. Complementary colors are pairs of colors that are opposite each other on the color wheel, and when they are mixed together, they create a neutral color (in this case, white). Therefore, the correct answer is d) blue light + yellow light.

This question involves the concepts of thickness and length.

"40" gold atoms could stack on top of one another in the gold foil.

We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.

Therefore,

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Explanation:

b) a fixed shape is describing a solid state

a) The angular velocity of the turntable after 0.200 s is 0.430 rev/s. b) the turntable has spun through 0.0088 revolutions in this time interval. c) the tangential speed of a point on the rim of the turntable at t = 0.002 s is 0.094 m/s.

The coefficient of kinetic friction between the object and the rough surface is 0.083. We can use the work-energy principle to solve this problem. According to the principle, the work done by all forces acting on an object is equal to the change in its kinetic energy.

The work done by the force of friction is given by W_friction = -f_k * d, where f_k is the force of kinetic friction and d is the distance traveled. The change in kinetic energy of the object is given by ΔK = K_f - K_i = (1/2) * m * v_\(f^2\) - (1/2) * m * v_\(i^2.\)

Since the object is moving on a horizontal surface, the work done by gravity is zero. Therefore, we have W_friction = ΔK.

Substituting the given values, we get:

-f_k * d = (1/2) * m * v_f^2 - (1/2) * m * v_\(i^2\)

-f_k * 8.0 m = (1/2) * m * (2.0 \(m/s)^2\) - (1/2) * m * (9.0\(m/s)^2\)

Simplifying and solving for f_k, we get:

f_k = (m/8.0 m) * [(1/2) * (2.0 \(m/s)^2\)- (1/2) * (9.0 \(m/s)^2\)]

f_k = 0.813 \(m/s^2\)

The coefficient of kinetic friction is given by μ_k = f_k / N, where N is the normal force. Since the object is moving horizontally, the normal force is equal to the weight of the object, which is N = m * g, where g is the acceleration due to gravity.

Substituting the value of f_k and N, we get:

μ_k = f_k / N = 0.813 \(m/s^2\) / (m * g)

The value of g is approximately 9.8 \(m/s^2\). Therefore, the coefficient of kinetic friction is:

μ_k = 0.083

Therefore, the coefficient of kinetic friction between the object and the rough surface is 0.083.

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Answer:

12J

Explanation:

Right before it hits the ground, the initial potential energy and the final kinetic energy will equal each other due to conservation of energy.

Answer:

 y = y₀ (1 - ½ g y₀ / v²)

Explanation:

This is a free fall problem. Let's start with the ball that is released from the window, with initial velocity vo = 0 and a height of the window i

          y = y₀ + v₀ t - ½ g t²

          y = y₀ - ½ g t²

for the ball thrown from the ground with initial velocity v₀₂ = v

         y₂ = y₀₂ + v₀₂ t - ½ g t²

in this case y₀ = 0

         y₂2 = v t - ½ g t²

at the point where the two balls meet, they have the same height

         y = y₂

         y₀ - ½ g t² = vt - ½ g t²

         y₀i = v t

         t = y₀ / v

since we have the time it takes to reach the point, we can substitute in either of the two equations to find the height

         y = y₀ - ½ g t²

         y = y₀ - ½ g (y₀ / v)²

         y = y₀ - ½ g y₀² / v²

        y = y₀ (1 - ½ g y₀ / v²)

with this expression we can find the meeting point of the two balls

Answer:

8m

8m towards the mailbox

Explanation:

Given parameters:

Length of path  = 8m

Unknown:

Distance  = ?

Displacement  = ?

Solution:

Distance is the length of path and it has magnitude but no direction.

The distance covered is 8m

Displacement is the length of path and it has magnitude and direction.

 Displacement is 8m towards the mailbox

A stiff wire bent into a semicircle of radius a = 1.4 cm. The frequency is 30 Hertz and the amplitude of the emf induced in the loop is 1.16 x 10⁻³ V

Formula for the angular frequency is:

ω = 2πf

Where:

ω = angular frequency (rad/s)

f = frequency (Hertz)

In the given problem,

ω = 30 rev/sec = 30 x 2π rad/s

a) f = ω / 2π

f = 30 x 2π / 2π = 30 Hertz

b) The induced emf is:

ε = Bπ²a²f sin(ωt)

Where:

B = magnetic field

a = radius

In the given problem,

B = 20 x 10⁻³ T

a = 1.4 x 10⁻² m

Hence, the amplitude or the maximum emf is:

ε_max = Bπ²a²f

           = (20 x 10⁻³) π² (1.4 x 10⁻²)² (30) = 1.16 x 10⁻³ Volt

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El lanzamiento de proyectiles permite calcular el angulo de lanzamiento o elevación  para alcanzar el objetivo es:  9.3º

El lanzamiento de proyectiles es una aplicación de la cinemática donde en el eje x ( horizontal) no hay aceleración y el el eje y (vertical) con sentido positivo hacia arriba tiene la aceleración de la gravedad.

El rango de lanzamiento de proyectiles es la distancia horizontal recorrida para la misma altura inicial.

               \(R = \frac{vo^2 sen 2 \theta}{g}\)  

Donde R es el alcance, v₀ la velocidad inicial, θ el angulo de lanzamiento o elevación y g la aceleración de la gravedad.

             sen 2θ =  \(\frac{gR}{vo^2 }\)

             2θ = sen⁻¹ \(\frac{gR}{vo^2}\)  

calculemos

              2θ = sin⁻¹ ( \(\frac{9.8 \ 4000}{350^2 }\) )

              θ =  18,662 /2

              θ =  9.3º

En conclusion usando el lanzamiento de proyectiles podemos calcular el angulo de lanzamiento para alcanzar el objetivo es:  9.3º

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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Answer: Start by writing down the problem in your own words using as much detail as possible. Be as specific as possible in your description.

Explanation:

The angular speed of the earth, the linear speed of an object on the surface, and the acceleration of the object will be 7.288 × 10⁻⁵ m/sec,446.36 m/sec, and 31.27 m/s² respectively.

The rate of velocity change concerning time is known as acceleration.

Unit conversion;

1 hour = 3600 sec

Given data;

Velocity, v= m/s

Time elapsed, t = 23 hours 56 minutes and 4 seconds

The radius of the earth is, R= 6.37×103 km.

The total taken in the second is;

T=23  hr × 3600 sec  + 56 min  × 60 sec  + 4 sec

T= 86164 sec

The angular speed of the earth;

\(\rm \omega_e = \frac{2 \pi}{T} \\\\ \omega_e =\frac{ 2 \times 3.14 }{86164 \ sec} \\\\ \omega_e =7.28 8 \times 10^{-5 } \ rad /sec\)

The linear speed of an object on the surface of the radius vector from the center of the earth is;

\(\rm v = r \times \omega \\\\ v= 6123 \ km \times 7.29 \times 10 ^{-5} \\\\ v = 446.36 \ m/sec\)

The acceleration of the object on the surface of the earth is;

\(\rm a = \frac{v^2}{r} \\\\ a=\frac{4446.32^2}{6.37 \times 10^3} \\\\ a= 31.27 \ m/s^2\)

Hence,the angular speed of the earth, the linear speed of an object on the surface, and the acceleration of the object will be 7.288 × 10⁻⁵ m/sec,446.36 m/sec, and 31.27 m/s²

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Nuclear power is generated by heating water to high-pressure steam that drives a turbine. It is a main source of energy.

Nuclear energy refers to the different sources of energy that depend on the properties of atomic nuclei.

The main types of nuclear energy can be divided into nuclear fusion and nuclear fission.

Nowadays, nuclear plants around the world use nuclear fission to produce a huge amount of energy.

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