+
x <-3
Find f(-5), 76-2), and 119 forfiz)=
X 0
-3<<0
N
f(-5) =
f(-2)
11
=
F(4) =

Answer: A

Step-by-step explanation: I would say A because the angle is greater than 90 degrees

Answer:

We have supplementary angles.

76 + 3x + 2 = 180

3x + 78 = 180

3x = 102

x = 34

Answer:

2t+16

Step-by-step explanation:

this should 2t+16

because 2t contains a variable and there are no available numbers/figits that match up

and 9 +7 is 16

hope i could help

Answer:

2t +16

Step-by-step explanation:

2t + 9 + 7

Combine like terms

2t +16

Answer:

EF = 7 + 39 = 46

Step-by-step explanation:

EF = FG

x + 39 = 7x - 3

39 + 3 = 7x - x

42 = 6x

x = 42/6

x = 7

hope this helps :)

Answer:

  B. 0, 1, 2, 3

Step-by-step explanation:

You want to know the numbers from 0–9 that could be used to represent success if the probability of success is 40%.

To model a 40% success rate, we want 40% of the possible outcomes to represent success. There are 10 numbers in the range 0–9, so we need to have 40%×10 = 4 of the numbers represent success.

A suitable choice for 4 of the numbers is ...

  0, 1, 2, 3 . . . . . choice B

<95141404393>

To arrive at school on time with 40 minutes available, you would need to maintain an average speed of 22.5 miles per hour.

To calculate the average speed needed to arrive at school on time, we need to determine the distance traveled and the time available.

Given that you live 15 miles from school and have 40 minutes until school starts, we can convert the time to hours by dividing by 60:

40 minutes = 40/60 = 2/3 hours

Now, we can use the formula speed = distance/time to find the required average speed:

Average speed = 15 miles / (2/3 hours)

= 15 miles * (3/2) hours

= 22.5 miles per hour

It's important to note that this calculation assumes a constant speed and doesn't account for factors such as traffic or stops along the way. Adjustments may be necessary to ensure a timely arrival based on real-world conditions.

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Research on aging uses a **longitudinal** design.

A longitudinal design is a research design in which the same participants are studied over time. This is in contrast to a **cross-sectional** design, in which different participants are studied at different times.

Because age cannot be manipulated as an independent variable, research on aging must use a longitudinal design. This allows researchers to track changes in participants' behavior, cognition, and other factors as they age.

Longitudinal studies can be expensive and time-consuming to conduct, but they can provide valuable insights into the aging process. For example, longitudinal studies have shown that cognitive decline is not inevitable with age, and that certain lifestyle factors, such as exercise and social engagement, can help to protect against cognitive decline.

Here are some examples of longitudinal studies on aging:

* The Baltimore Longitudinal Study of Aging, which has been following a group of adults for over 70 years.

* The Framingham Heart Study, which has been following a group of adults for over 70 years.

* The Study of Adult Development and Aging, which has been following a group of adults for over 80 years.

These studies have provided valuable insights into the aging process, and they continue to be an important source of information for researchers and policymakers.

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Historical scientists deal with falsification by rigorously analyzing evidence, using peer review and scholarly discourse, and revising hypotheses based on new discoveries and interpretations.



Historical scientists deal with falsification by employing rigorous methodologies and critical analysis of evidence. They strive to gather as much relevant data as possible to test hypotheses and theories. This is done through meticulous research, including the examination of primary sources, archaeological artifacts, historical records, and other forms of evidence. Historical scientists also engage in peer review and scholarly discourse to subject their findings to scrutiny and criticism.

The mechanism used by historical scientists to falsify hypotheses involves a combination of evidence-based reasoning and the application of established principles of historical analysis. They aim to construct coherent and logical explanations that are supported by the available evidence. If a hypothesis fails to withstand scrutiny or is contradicted by new evidence, it is considered falsified or in need of revision. Historical scientists constantly reassess and refine their hypotheses based on new discoveries, reinterpretation of existing evidence, and advancements in research techniques. This iterative process helps to refine our understanding of the past and ensures that historical knowledge remains dynamic and subject to revision.

Therefore, Historical scientists deal with falsification by rigorously analyzing evidence, using peer review and scholarly discourse, and revising hypotheses based on new discoveries and interpretations.

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The 3-month simple moving average for May is 132.

To calculate the 3-month simple moving average for May, we need to take the average of the demand values for the three preceding months (February, March, and April).

The demand values for these months are 120, 134, and 142, respectively. To find the moving average, we sum these values and divide by 3 (the number of months):

Moving Average = (120 + 134 + 142) / 3 = 396 / 3 = 132

Therefore, the 3-month simple moving average for May is 132.

The simple moving average is a commonly used method to smooth out fluctuations in data and provide a clearer trend over a specific time period. It helps in identifying the overall direction of demand changes. By calculating the moving average, we can observe that the average demand over the past three months is 132 units. This provides an indication of the demand trend leading up to May. It's important to note that the moving average is a lagging indicator, as it relies on past data to calculate the average.

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Answer:

a=27.1

Step-by-step explanation:

We're given both b and c of the Pythagorean formula, hence we work backwards to find A:

\(a^2+b^2=c^2\\a^2+17^2+32^2\\a^2+289=1024\\a^2=735\\\sqrt{a^2} =\sqrt{735}\\\\a=27.1\)

Answer:

\(6\frac{3}{5}\)

Step-by-step explanation:

\(8 \div 5 = 1\frac{3}{5} \\\\1\frac{3}{5} + 7 = 8\frac{3}{5}\\\\8\frac{3}{5} - 2 = 6\frac{3}{5}\)

The expression 3-14x is equivalent to -5+8-6x-8x.

The phrase has the same meaning as,

=-5+8-6x-8x

=(3)-(14x)

=3-14x

Any combination of terms that have undergone operations like addition, subtraction, multiplication, division, etc. is known  variable expression. Let's use the equation 5x + 7 as an example. Thus, 5x + 7 is an illustration of an algebraic expression.

There are three primary categories of algebraic expressions, including: Numeral Expression. Binary Expression of a polynomial.

Properties:

Hence, the expression 3-14x  is equivalent to -5+8-6x-8x.

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Answer: -14x + 13

Step-by-step explanation:

A quarterback throws an incomplete pass. The height of the football at time t is modeled by the equation h(t) = –16t² + 40t + 7. Rounded to the nearest tenth, the solutions to the equation when h(t) = 0 feet are –0.2 s and 2.7 s.

the solution to be eliminated is -0.2s this is because time do not have negative values

ax² + bx + c = 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. a.

It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be real or complex.

Considering the given function, the answer is both real one is negative the other is positive.

The solution in this case represents time, and time of negative value do not apply in real life

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The Lagrangian for maximizing Will's utility subject to his budget constraint can be written as the correct answer is A. L = xy^4 - λ(12x + 11y - 118).

The Lagrangian for maximizing Will's utility subject to his budget constraint can be written as

L = xy^4 - λ(p_x*x + p_y*y - m),

where x and y are goods, p_x and p_y are the prices of goods x and y respectively, and m is income.
In this case, Will has a Cobb-Douglas utility function, xy^4. His income is $118, the price of x is $12, and the price of y is $11.
To find the Lagrangian for maximizing Will's utility, we substitute the values into the equation:
L = xy^4 - λ(12x + 11y - 118).
Therefore, the correct answer is A. L = xy^4 - λ(12x + 11y - 118).

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The candidate key for the relation schema R(A,B,C,D,E): A→B, C→B, D→A, D→B, D→C, C→D, D→E.

Candidate key for the given relation: To find the candidate key for the relation schema R(A,B,C,D,E), we need to follow the below steps:

Here, we have the following functional dependencies: A→B, C→B, D→ABC, AC→D, D→E.

Step 1: To normalize the given dependencies, we have the following dependencies:

A→B, C→B, D→ABC, AC→D, D→E becomes

A→B, C→B, D→A, D→B, D→C, D→E.

Step 2: To check for the minimal dependency, we can eliminate the redundancy by eliminating D→ABC. Therefore, we have the following dependency:

A→B, C→B, D→A, D→B, D→C, D→E.

Step 3: Find the closure on each attribute, which is as follows:

1. A+ = {A,B}

2. B+ = {B}

3. C+ = {B}

4. D+ = {A,B,C,D,E}

5. E+ = {E}

Step 4: The combination of attributes that have all attributes of the relation schema, and it will be a candidate key is AD. Therefore, the candidate key is AD.

Compute the minimal cover of F:

Minimal Cover: The minimal set of dependencies that is equivalent to the given set of dependencies is the minimal cover.

We have the following functional dependencies:

A→B, C→B, D→ABC, AC→D, D→E.

The process to compute the minimal cover of F is as follows:

Step 1: To find the redundant dependencies, we need to split the dependencies. We have the following dependencies:

A→B, C→B, D→ABC, AC→D, D→E  becomes

A→B, C→B, D→A, D→B, D→C, D→E.

Step 2: To eliminate the dependencies with three attributes, we can use the following steps:

If X→YZ, then X→Y and X→Z.

Therefore, we have the following dependency:

D→A, D→B, D→C.

Step 3: To eliminate the dependency with two attributes, we can use the following steps:

If X→Y and Y→Z, then X→Z.

We have the following dependency: AC→D, C→D.

Step 4: Therefore, the minimal cover of F is A→B, C→B, D→A, D→B, D→C, C→D, D→E.

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Answer:

$1890

Step-by-step explanation: add up both taxes paid and the total of that which was calculated to be $442 then minus it from his monthly earnings

\(2332-442=1890\)

9514 1404 393

Answer:

  at most 63

Step-by-step explanation:

The inequality Jody can use to determine the number of sheets (s) of paper she can buy will be ...

  18.25 + 0.34s ≤ 40

  0.34s ≤ 21.75

  s ≤ 21.75/0.34 ≈ 63.97

Jody can buy up to 63 sheets of paper.

The amount of money each person gets is $12.

For a total amount of $36, each person gets a fraction of 1/3 of the whole amount.

What is fraction?

In mathematics, a fraction is used to denote a portion or component of the whole. It stands for the proportionate pieces of the whole. Numerator and denominator are the two components that make up a fraction. The numerator is the number at the top, and the denominator is the number at the bottom.

The number of people are = 3

The amount of money to be shred equally is = $36

Let the amount of money each person gets be = x

Then for 3 people the amount will be = 3x.

The formula to find the value of x is -

3x = 36

x = 36/3

x = 12

Therefore, each person get $12.

The fraction that represents the amount will be -

share of each person / total amount

Substitute the value into the expression -

12/36 = 1/3

Therefore, each person shares 1/3 of the money.

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The statement "Consistent system of equations has at least one solution, and an inconsistent system has no solution" is true.

In the context of systems of linear equations, a consistent system refers to a system where there exists at least one solution that satisfies all the equations in the system. This means that the equations can be simultaneously satisfied by a set of values for the variables.

On the other hand, an inconsistent system refers to a system of equations that has no solution. This occurs when the equations are contradictory or cannot be satisfied simultaneously by any values for the variables.

Therefore, a consistent system guarantees the existence of at least one solution, while an inconsistent system does not have any solution.

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Answer:

Step-by-step explanation:

Multiply all terms by the same value to eliminate fraction denominators

14÷(3y+5)=3÷y

\(\frac {14} {3y+5}= \frac {3}{y}\)

\((3y+5)(y( \frac {14}{3y+5})=\) (3y+5)·y·\(\frac {3} {y}\)

Simplify

Combine multiplied terms into a single fraction

Re-order terms so constants are on the left

Cancel terms that are in both the numerator and denominator

Divide by 1

Cancel multiplied terms that are in the denominator

Re-order terms so constants are on the left

Distribute:

14y=9y+15

Subtract  9

Answer:

PQ = 98.21

Step-by-step explanation:

PQ/23 = 47/11

PQ × 11

23 × 47

11PQ = 1081

11PQ/11 = 1081/11

PQ = 98.21

The inverse of the statement is "If a number does not have exactly two distinct factors, then the number is not prime." Thus Option 2 is the answer.

   When a conditional statement is reversed, the hypothesis and conclusion are both negated. The hypothesis in the original statement is "a number with exactly two distinct factors," while the conclusion is "is prime."

  To make the inverse, we negate both sections. "A number does not have exactly two distinct factors" is the antonym of "A number that has exactly two distinct factors." "Is not prime" is the opposite of "is prime."

    As a result, the inverse statement is "If a number does not have exactly two distinct factors, then the number is not prime."

     It's crucial to remember that a statement's inverse could or might not be accurate. In this instance, the inverse is true since the definition of a prime number is incompatible with the fact that a number has more than two components if it has more than exactly two different factors.

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The probability that a randomly selected group of 16 individuals from the campus will be selected is 0.8023 or 80.23%

Based on the sign in the elevator of the college library, the limit of 16 persons and weight limit of 2,500 pounds need to be adhered to. To ensure compliance with both limits, we need to consider both the number of people and their weight.

Assuming that the distribution of weights of individuals on campus is approximately normal with an average weight of 155 pounds and a standard deviation of 29 pounds, we can use this information to estimate the total weight of a group of 16 randomly selected individuals.

The total weight of a group of 16 individuals can be estimated as follows:

Total weight = 16 x average weight = 16 x 155 = 2480 pounds

To determine if this total weight is within the weight limit of 2,500 pounds, we need to consider the variability in the weights of the individuals. We can do this by calculating the standard deviation of the total weight using the following formula:

Standard deviation of total weight = square root of (n x variance)

where n is the sample size (16) and variance is the square of the standard deviation (29 squared).

Standard deviation of total weight = square root of (16 x 29^2) = 232.74

Using this standard deviation, we can calculate the probability that the total weight of the group of 16 individuals is less than or equal to the weight limit of 2,500 pounds:

Z-score = (2,500 - 2,480) / 232.74 = 0.86

Using a standard normal distribution table or calculator, we can find that the probability of a Z-score less than or equal to 0.86 is approximately 0.8023.

Therefore, the probability that a randomly selected group of 16 individuals from the campus will comply with both the number and weight limits in the elevator of the college library is approximately 0.8023 or 80.23%.

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The solution of the given initial value problem is y(t) = sin(t) + H(t-2π)cos(t-2π), where H(t) is the Heaviside step function.

To solve the initial value problem, we start by finding the complementary solution, which satisfies the homogeneous differential equation y'' + y = 0. The complementary solution is given by y_c(t) = A sin(t) + B cos(t), where A and B are constants to be determined.

Next, we find the particular solution for the given non-homogeneous term δ(t-2π)cos(t). Since the forcing term is a Dirac delta function at t = 2π, we can write the particular solution as y_p(t) = K(t-2π)cos(t-2π), where K is a constant to be determined.

Applying the initial conditions y(0) = 0 and y'(0) = 1, we can solve for the constants A, B, and K. Plugging in these initial conditions into the general solution, we find A = 0, B = 1, and K = 1.

Therefore, the solution of the initial value problem is y(t) = sin(t) + H(t-2π)cos(t-2π), where H(t) is the Heaviside step function.

The initial value problem with the given conditions is solved by finding the complementary solution and the particular solution. The solution is y(t) = sin(t) + H(t-2π)cos(t-2π), where H(t) is the Heaviside step function. This solution satisfies the given initial conditions y(0) = 0 and y'(0) = 1.

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Boris Milkem the transactions take place, the number of dollars and francs Boris desires to have must not be negative.

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Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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Answer:  median would be less than the mean.

Answer:

no

Step-by-step explanation:

The possible rational zeros of ƒ(x) = 3x³ + 22x² +28x - 35 are the factors of -35 divided by the factors of 3. These are:

-35/1 = -35, -35/-1 = 35

-35/3 = -5, -35/-3 = 5

Using the Rational Root Theorem, we can now test these values to see if they are zeros of the function:

-35: 3(-35)³ + 22(-35)² + 28(-35) - 35 = -8,925 + 30,950 + -980 - 35 = -9,880 which is not a zero

35: 3(35)³ + 22(35)² + 28(35) - 35 = 42,875 + 30,950 + 980 - 35 = 74,770 which is not a zero

-5: 3(-5)³ + 22(-5)² + 28(-5) - 35 = -125 + -100 + -140 - 35 = -400 which is not a zero

5: 3(5)³ + 22(5)² + 28(5) - 35 = 125 + 100 + 140 - 35 = 330 which is not a zero

So the function ƒ(x) = 3x³ + 22x² +28x - 35 has no rational zeros.

С

Answer:

Step-by-step explanation: this should help