Good energy, Bad energy, Energy used to run, Energy drinks,
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
https://brainly.com/question/29503787
#SPJ8
The glowing dot represents the transmission of a nerve impulse along the nerves that make up the neural pathway. A nerve impulse is an electrical signal that travels from one nerve cell to another.
Which part of the brain processes this signal?
Answer:
The answer is "Cerebral Cortex"
Explanation:
The neurotransmitter diffuses across the short distance of the synapse and ties to a receptor protein of the objective neuron. At the point when the sub-atomic sign ties to the receptor, the cell film of the objective neuron changes its electrical state and another evaluated expected starts. On the off chance that that evaluated potential is sufficiently able to arrive at limit, the subsequent neuron produces an activity potential at its axon hillock. The objective of this neuron is another neuron in the thalamus of the mind, the piece of the CNS that goes about as a transfer for tactile data.
At another neurotransmitter, synapse is delivered and ties to its receptor. The thalamus at that point sends the sensory information to the cerebral cortex, the furthest layer of dark issue in the brain, where cognizant view of that water temperature starts.
A region of the cortex is particular for imparting signs down to the spinal cord for development. The upper engine neuron is in this area, called the precentral gyrus of the frontal cortex, which has an axon that broadens right down the spinal cord. At the degree of the spinal cord at which this axon makes a neurotransmitter, a reviewed potential happens in the cell membrane of a lower engine neuron.
The speed of sound is 344 m/s. You have built a really fantastic car that can really go fast. If the car can accelerate at 22.4 m/s how much time till you reach the speed of sound? How many kilometers will you travel before you reach that speed?
Answer:
About 15 seconds,.344 kilo
Explanation:
Answer:
15.36 [sec]; 2.64143 [km].
Explanation:
all the details are in the attachment, note, the suggested solution consists of two parts: formula and solution.
When oxygen in water interacts with iron it results in O A rust forming O B) a chemical change C) oxidation O D) all of the above
Which of the following is a type of natural disaster that has impacted Florida? A. Avalanche B. Flood C. Typhoon D. Volcano
If you get it right you get 100 points and brainliest
Answer:
B-flood
Explanation:
The Sunshine State is famous all around the world for many great things but also is famous because of a big array of natural disasters.From hurricanes, tropical storms, tornadoes, to fires and floods many natural disasters in Florida affect the lives of residents.
Answer:
B. Flood
Explanation:
I would say Floods because hurricanes creates floods so...yeah
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
For more such questions on decay rate, click on:
https://brainly.com/question/27542728
#SPJ8
1) 1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the centripetal force acting on the car? *
1 point
1 N
100 N
1000 N
10000 N
2) 1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the acceleration of the car? *
1 point
0.1 m/s^2
1 m/s^2
10 m/s^2
100 m/s^2
Answer:
(1) 1000 N (2) 1 m/s²
Explanation:
(1) Given that,
The mass of a car, m = 1000 kg
Radius of a circular track, r = 100 m
Speed of the car, v = 10 m/s
We need to find the magnitude of the centripetal force acting on the car. The magnitude of the centripetal force is given by :
\(F=\dfrac{mv^2}{r}\\\\F=\dfrac{1000\times (10)^2}{100}\\\\F=1000\ N\)
So, the correct option is (c) i.e. 1000 N
(2).The mass of a car, m = 1000 kg
Radius of a circular track, r = 100 m
Speed of the car, v = 10 m/s
We need to find the magnitude of the centripetal acceleration of the car. The magnitude of the centripetal acceleration is given by :
\(a=\dfrac{v^2}{r}\\\\a=\dfrac{(10)^2}{100}\\\\a=1\ m/s^2\)
So, the correct option is (b) i.e. \(1\ m/s^2\)
explain the three scale of temperature and their interconversion from one scale to another how will you convert 50 degree Celsius into Fahrenheit
Answer:
Explanation:
the scales of temperature are kelvin,celsius and fahrenheit so to interconvert them use the formula:
K-273/100 = C/100 = F-32/180
If the car was initially traveling at 96 km/h and came to a stop in 5.0 s along a straight, level road, what was the magnitude of the average force applied to the passenger by the seatbelt? The shoulder strap seatbelt holds a 56kg passenger in place.
The average force exerted by seatbelts on the passenger is 1493.3N.
initial velocity of the car, u = 96km/h
time taken by the car, s = 5.0 sec
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 56 kg
to find out the acceleration of the car we use equation of motion
v = u+ at
0 = 96km/h + ax 5s
a = - 96 x 18/5x5
a = -26.6m/s²
The deceleration of the car is 26.6 m/s²
The force exerted on the passenger by the backward action of the car is calculated as
F = ma
where
m is mass
a is acceleration
F = 56 x 26.6
F = 1493.3 N
Therefore, the average force exerted by seatbelts on the passenger is 1493.3N.
To know more about force.
https://brainly.com/question/11027219
#SPJ1
A 2000 kg car moves at a speed of 30 m/s. To reach this speed, it was necessary to burn 0.1 l of gas. Burning gas provides 30 MJ/l of source energy. Determine the energy efficiency (in %) of this car.
The energy efficiency of the car is approximately 16.7%.
The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:
Efficiency = Useful work output / Total energy inputThe useful work output can be calculated as the kinetic energy of the car using the equation:
KE = 0.5mv²where m is the mass of the car and v is its velocity.
Substituting the given values:
KE = 0.5 x 2000 kg x (30 m/s)² = 900,000 JThe total energy input is the energy released by burning 0.1 L of gasoline, which is:
Total energy input = 0.1 L x 30 MJ/L = 3 MJ = 3,000,000 JSubstituting these values into the equation for efficiency:
Efficiency = (900,000 J / 3,000,000 J) x 100% = 0.3 x 100% = 16.7%Therefore, the energy efficiency of the car is approximately 16.7%.
To learn more about energy efficiency, here
https://brainly.com/question/28939461
#SPJ1
Please help me in questions 4_5_6
Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.
How to explain the forceAs the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.
The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.
The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.
Learn more about force on
https://brainly.com/question/12970081
#SPJ1
A weightlifter lifts a weight of 500 N from the ground over her head, a distance of 1.8 m. How much work has been done to move the weight?
Only charged particles can be accelerated in a linear accelerator. Is this true or false?
ANSWER
True
EXPLANATION
A linear accelerator is a particle accelerator that accelerates particles by subjecting them to electric potentials - oscillating electric potentials. If the particles where not charged, these potentials would do nothing to them. Therefore, a linear accelerator only can accelerate subatomic charged particles.
A 20-g bullet is shot vertically into an 2.8-kg block. The block lifts upward 9 mm. The bullet penetrates the block and comes to rest in it in a time interval of 5 ms. Assume the force on the bullet is constant during penetration and that air resistance is negligible. What is the speed of the bullet just before the impact
Answer:
The speed of the bullet just before the impact is 701 m/s
Explanation:
Given;
mass of the bullet, m₁ = 20 g = 0.02 kg
mass of the block, m₂ = 2.8 kg
displacement of the block, d = 9 mm = 9 x 10⁻³ m
duration of motion of the bullet, t = 5 ms = 5 x 10⁻³ s
Apply the principle of conservation of energy;
The final kinetic energy of the bullet = maximum potential energy of the block
\(\frac{1}{2} m_1v^2 = m_2gh\\\\v^2 = \frac{2m_2gh}{m_1} \\\\v= \sqrt{\frac{2m_2gh}{m_1} } \\\\v = \sqrt{\frac{2 \times 2.8 \times 9.8 \times (9\times 10^{-3})}{0.02} } \\\\v = 4.97 \ m/s\)
Apply the principle of conservation of linear momentum, to determine the initial velocity of the bullet before the impact.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
u₁ is the initial velocity of the bullet
u₂ is the initial velocity of the block = 0
m₁u₁ + 0 = v(m₁ + m₂)
m₁u₁ = v(m₁ + m₂)
0.02u₁ = 4.97(2.8 + 0.02)
0.02u₁ = 14.02
u₁ = 14.02 / 0.02
u₁ = 701 m/s
Therefore, the speed of the bullet just before the impact is 701 m/s
Tamika pushes her 6.0 kg skateboard 4.0 m with a force of 12 N. What is the skateboard’s acceleration?
After considering the given data we conclude that the total acceleration attained by the skateboard is 2.0 m/s², under the condition that Tamika pushes her 6.0 kg skateboard 4.0 m with a force of 12 N.
The skateboard's acceleration can be evaluated applying the formula:
\(a = \frac{F }{m }\)
Here, F is the force applied on the skateboard, and m is the mass of the skateboard.
For the given case, Tamika applies a push on her 6.0 kg skateboard making a distance of 4.0 m with a force of 12 N. Therefore, the skateboard's acceleration is:
\(a = \frac{F }{m }\)
= 12 N / 6.0 kg
= 2.0 m/s²
So the skateboard's acceleration is 2.0 m/s².
To learn more about acceleration
https://brainly.com/question/30595126
#SPJ1
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
For more questions on Mass
https://brainly.com/question/28853889
#SPJ8
Researchers studying the possible effects of “heading” a soccer ball--hitting it with the head--use a force plate to measure the interaction force between a ball and a hard surface. (Figure 1) shows smoothed data of the force when a 430 g
soccer ball is fired horizontally at the force plate with a speed of 15 m/s
With what speed does the ball rebound from the plate?
The speed of the ball rebounding from the plate is approximately 13.2 m/s.
According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.
The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.
The speed of the ball rebounding can be calculated using the formula:
(1/2)mv²= (1/2)mv_0²
where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).
Solving for v, we get:
v = sqrt(v_0² - (2F/m))
where F is the maximum force exerted on the force plate (1900 N).
Plugging in the values, we get:
v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s
Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.
learn more about speed here
https://brainly.com/question/13943409
#SPJ1
What is Moral subjectivism?
Answer:
What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.
Twelve identical point charges q are equally spaced around the circumference of a circle of radius R The circle is centered at the origin. One of the twelve charges, which happens to be on the positive x axis, is now moved to the center of the circle.
Determine the magnitude of the total electric force exerted on this charge.
Answer: the magnitude of the total electric force exerted on the moved charge is proportional to the square of the charge q and inversely proportional to the square of the radius R.
Explanation:
The total electric force exerted on a charge moved to the center of a circle with 12 equally spaced charges can be found by calculating the electric field at the center due to the remaining 11 charges and multiplying by the charge of the moved particle. Coulomb's law gives the electric field at the center due to a single charge located at a distance R from the center as
E = kq/R^2
The total electric field due to the 11 other charges is
E_total = 11E
Thus, the force on the moved charge is
F = qE_total = 11kq^2/R^2.
Therefore, the force is proportional to the square of the charge q and inversely proportional to the square of the radius R.
learn more about Coulomb's law
https://brainly.in/question/332179#:~:text=Coulomb's%20law%20states%20that%20the,square%20of%20distance%20between%20them.
Which equation is correct according to Ohm’s law? Which equation is correct according to Ohm’s law? A.) V = IR B.) I = R/V C.) R = I/V D.) R = IV
Answer:
\(V = IR\)
Explanation:
Required
Which equation represents ohm's law?
Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).
Mathematically, this can be represented as:
\(I\ \alpha\ \frac{V}{R}\)
Convert the expression to an equation
\(I\ =\ \frac{V}{R}\)
Multiply both sides by R to make V the subject
\(I\ * R\ =\ \frac{V}{R} * R\)
\(I\ * R\ =V\)
Reorder
\(V = I\ * R\)
\(V = IR\)
Option (a) is correct; Others are not
Answer:
V=ir
Explanation:
Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. The correct answers from the choices are:
v = ir
A Ferris wheel at a carnival has a radius of 10 m and turns so that the speed of the riders is 8 m/s.A. What is the magnitude of the acceleration of the riders?B. What is the magnitude of the net force required to produce this centripetal acceleration for a rider with a mass of 60 kg?
Given
Radius = 10 m
r = 10 m
speed = 8 m/s
Explanation
A. centripetal acceleration, the acceleration of a body traversing a circular path.
\(\begin{gathered} a_c=\frac{v^2}{r} \\ a_c=\frac{8^2}{10} \\ a_c=6.4\text{ m/s}^2 \end{gathered}\)B. Net force
\(\begin{gathered} F=ma \\ F=60\text{ kg*6.4m/s}^2 \\ F=384\text{ N} \end{gathered}\)A tennis ball with a mass of 0.2 kg is thrown upwards from the ground at a velocity of 30 m/s. What
is the height of the ball when it has a velocity of 20 m/s?
The height of the ball when it has a velocity of 20 m/s is 45m.
What is mass?
It is the most fundamental feature of matter and one of the fundamental quantities in Physics. Mass can be defined as the amount of matter in a body. Kilogram is the SI unit of mass (kg).
It should be noted that a body's mass does not alter with time. Only in severe instances where a massive amount of energy is provided or removed from the body. In a nuclear reaction, for example, a tiny bit of matter is turned into a massive amount of energy, reducing the mass of the substance.
Given Initial velocity of ball, u=30 m/s
Let the maximum height reached and time taken to reach that height be H and t respectively.
Assumption: g=9.8 m/s2
holds true (maximum height reached is small compared to the radius of earth)
30/g=30/9.8=3 seconds
as the time taken to reach max height.
h(3)=-4.9(3²)+30(3)
=90–45
=45m
The height of the ball when it has a velocity of 20 m/s is 45m.
Learn more about mass from given link
https://brainly.com/question/19385703
#SPJ1
An insulating sphere of radius 0.30 m has positive charge distributed uniformly inside it. A student measures the electric field at a point 0.50 m from the center of the sphere and finds it to have a magnitude of 15000 N/C. at that point. What is the maximum magnitude of the electric field that this sphere produces?
O 36,000 N/C
O 48,000 N/C
O 15000 N/C
O 25,000 N/C
O 42,000 N/C
O 30,000 N/C
The maximum strength of the electric field produced by this sphere is 41653 N/C
An electric field is a physical force that surrounds a charged particle and exerts a force on all other charged particles within the field to attract or repel them. It's a place. It also refers to the physical field of a charged particle system.
Calculation:-
Charges are evenly distributed inside a non-conducting sphere with a radius of 0.30 m. The electric field at point p, 0.50 m from the center of the sphere, is 17,000 N/C and is directed radially outward. The radius of the
sphere is R = 0.3 m
r = 0.5 m then E = 15000 N/C
r > R for this value of r
E = k Q / r2
where k is the coulomb is the force constant, value 8.99*10^9 N.m2/ C^2 and Q is the total charge on the sphere.
Q = E r^2 / k
Q = 15000 * 0,5 * 0,5 / 8,99 * 10 ^ 9
Q = 41653 N/C
Learn more about Electric Field here:
https://brainly.com/question/1592046
#SPJ4
Question #2: Do all supply curves look basically the
same (forget about the numbers attached to them,
just answer in terms of slope (steepness) and shape
(direction)? Why or why not (use the terms you
defined above to answer this)?
Answer:
No, all supply curves do not look basically the same in terms of slope and shape. The slope and shape of a supply curve depend on the specific market conditions and the behavior of the suppliers. The supply curve can have different slopes, ranging from being perfectly elastic to perfectly inelastic. The slope of the supply curve reflects the responsiveness of the quantity supplied to changes in the price of the good or service.
In terms of shape, the supply curve can take on different forms such as being linear or curved. The shape of the supply curve depends on the behavior of the suppliers and their ability to adjust the quantity supplied to changes in the price of the good or service. For example, if suppliers can easily adjust their production levels in response to changes in price, then the supply curve may be flatter or more horizontal, indicating a more elastic supply. On the other hand, if suppliers face higher costs or constraints on their ability to increase production, the supply curve may be steeper or more vertical, indicating a less elastic supply.
Therefore, the slope and shape of a supply curve can vary depending on the market conditions and the behavior of the suppliers, and cannot be generalized as being the same for all supply curves.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
Learn more about earthquakes from the given link.
https://brainly.com/question/25843505
What is the direct path and direction from point A to B? Question 4 options: Motion Time Displacement Distance
Answer:
Motion
Explanation:
Motion is change in distance. Which means it is a vector quantity, it has both magnitude and direction
The direct path and direction from point A to B is motion
what are the types of motion ?there are into three types of motion such as Linear Motion
Rotary Motion, Oscillatory Motion
In linear motion, the particles pass from one point to another in either a straight line or a curved path, it depend on the path of motion, is further divided as follows
Rectilinear Motion where The path of the motion is a straight line and Curvilinear Motion where The path of the motion is curved.
Rotatory Motion where the body rotates on its own axis. A few examples of the rotatory motion are as The motion of the earth about its own axis around the sun is an example of rotary motion.
Oscillatory motion is the motion of a body about its mean position. A few examples of oscillatory motion are When a child on a swing is pushed, the swing moves to and fro about its mean position.
For more details motion, visit
https://brainly.com/question/3421105
#SPJ2
Write an equation using alpha, beta, and gamma decay for Lead-205.
Answer:A nucleus of uranium-238 (the parent nuclide) undergoes α decay to form thorium-234 (the daughter nuclide). The alpha particle removes two protons (green) and two neutrons (gray) from the uranium-238 nucleus.
Explanation:
A nucleus of uranium-238 (the parent nuclide) undergoes α decay to form thorium-234 (the daughter nuclide). The alpha particle removes two protons (green) and two neutrons (gray) from the uranium-238 nucleus.
During the middle of a family picnic, Barry Allen received a message that his friends Bruce and Hal
to be saved. Barry promised his wife Iris that he would be back in exactly 5 minutes. From that that picnic
location, Barry runs at a speed of 600 m/s for 2 minutes at a heading of 35° north of west to save Bruce.
He then changed his heading to 30° west of north, slows down to 400 m/s and runs for 1 minute to save
Hal. (The changes in speed are essentially instantaneous and not part of solving this problem).
(aPray a physical representation of the displacement during Barry's full trip.
The kinematics of the uniform motion and the addition of vectors allow finding the results are:
The Barry's initial trajectory is 94.30 10³ m with n angles of θ = 138.8º The return trajectory and speed are v = 785.9 m / s, with an angle of 41.2º to the South of the East
Vectors are quantities that have modulus and direction, so they must be added using vector algebra.
A simple method to perform this addition in the algebraic method which has several parts:
Vectors are decomposed into a coordinate system The components are added The resulting vector is constructed
Indicate that Barry's velocity is constant, let's find using the uniform motion thatthe distance traveled in ad case
v = \(\frac{\Delta d}{t}\)
Δd = v t
Where v is the average velocity, Δd the displacement and t the time
We look for the first distance traveled at speed v₁ = 600 m / s for a time
t₁ = 2 min = 120 s
Δd₁ = v₁ t₁
Δd₁ = 600 120
Δd₁ = 72 10³ m
Now we look for the second distance traveled for the velocity v₂ = 400 m/s
time t₂ = 1 min = 60 s
Δd₂ = v₂ t₂
Δd₂ = 400 60
Δd₂ = 24 103 m
In the attached we can see a diagram of the different Barry trajectories and the coordinate system for the decomposition,
We must be careful all the angles must be measured counterclockwise from the positive side of the axis ax (East)
Let's use trigonometry for each distance
Route 1
cos (180 -35) = \(\frac{x_1}{\Delta d_1}\)
sin 145 = \(\frac{y_1}{\Delta d1}\)
x₁ = Δd₁ cos 125
y₁ = Δd₁ sin 125
x₁ = 72 103 are 145 = -58.98 103 m
y₁ = 72 103 sin 155 = 41.30 10³ m
Route 2
cos (90+ 30) = \(\frac{x_2}{\Delta d_2}\)
sin (120) = \(\frac{y_2}{\Delta d_2}\)
x₂ = Δd₂ cos 120
y₂ = Δd₂ sin 120
x₂ = 24 103 cos 120 = -12 10³ m
y₂ = 24 103 sin 120 = 20,78 10³ m
The component of the resultant vector are
Rₓ = x₁ + x₂
R_y = y₁ + y₂
Rx = - (58.98 + 12) 10³ = -70.98 10³ m
Ry = (41.30 + 20.78) 10³ m = 62.08 10³ m
We construct the resulting vector
Let's use the Pythagoras' Theorem for the module
R = \(\sqrt{R_x^2 +R_y^2}\)
R = \(\sqrt{70.98^2 + 62.08^2}\) 10³
R = 94.30 10³ m
We use trigonometry for the angle
tan θ ’= \(\frac{R_y}{R_x}\)
θ '= tan⁻¹ \(\frac{R_y}{R_x}\)
θ '= tan⁻¹ \(\frac{62.08}{70.98}\)
θ ’= 41.2º
Since the offset in the x axis is negative and the displacement in the y axis is positive, this vector is in the second quadrant, to be written with respect to the positive side of the x axis in a counterclockwise direction
θ = 180 - θ'
θ = 180 -41.2
θ = 138.8º
Finally, let's calculate the speed for the way back, since the total of the trajectory must be 5 min and on the outward trip I spend 3 min, for the return there is a time of t₃ = 2 min = 120 s.
The average speed of the trip should be
v = \(\frac{\Delta R}{t_3}\)
v = \(\frac{94.30}{120} \ 10^3\)
v = 785.9 m / s
in the opposite direction, that is, the angle must be
41.2º to the South of the East
In conclusion, using the kinematics of the uniform motion and the addition of vectors, results are:
To find the initial Barry trajectory is 94.30 10³ m with n angles of 138.8º The return trajectory and speed is v = 785.9 m / s, with an angle of 41.2º to the South of the East
Learn more here: brainly.com/question/15074838
Match the measurements with the proper SI unit.
Acceleration:
A. Meters
B. Meters per second
C. Meters per second squared
Velocity:
A. Meters
B. Meters per second
C. Meters per second squared
Distance:
A. Meters
B. Meters per second
C. Meters per second squared
Explanation:
C. meter per second squared
B. meter per second
A. meter
Answer:
b. meters per second
c.meters per second squared
c.meters
Explanation:
ginawa ko na rin KC toh
If a projectile is launched at a velocity of 20 m/s, is it in equilibrium?
Why or why not?
Answer:
Why notExplanation:
.....make me brainlyest