The number of electrons that must be removed from object A and placed on object B is 1.24 * \(10^{19}\)
We know that,
E = k \(q_{1}\) \(q_{2}\) / r²
where,
E = Electrostatic force
k = Coulomb's constant
\(q_{1}\), \(q_{2}\) = Point charges
r = Distance between two charges
Given that,
\(q_{1}\) = 2 + ne C
\(q_{2}\) = - 2 - ne C
r = 3 cm
k = 9 * \(10^{9}\) N m² / C²
E = - 68 N ( Since it is attractive )
- 68 = 9 * \(10^{9}\) ( 2 - ne ) ( - 2 + ne ) / ( 3 * \(10^{-2}\) )²
68 * \(10^{-4}\) / 3 * \(10^{9}\) = ( 2 - ne )²
2.27 * \(10^{-12}\) = ( 2 - ne )²
1.5 * \(10^{-6}\) = 2 - ne
ne = 1.98
n = 1.98 / 1.6 * \(10^{-19}\) = 1.24 * \(10^{19}\)
The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.
Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * \(10^{19}\)
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Describe the buoyant force and explain how
it relates to Archimedes principle.
Answer:
Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.
according to the lecture videos, light has no color, and color exists only in our minds. which of the following are reasons to believe this statement? group of answer choices
Light is perceived as having color because of the way our brains interpret the wavelengths of light that reach our eyes.
This statement above is based on the scientific understanding of color and light. Light is a type of electromagnetic radiation that travels through space in waves. The color we perceive depends on the wavelength of the light; different wavelengths are perceived as different colors. However, light itself does not have a color, it is simply a form of energy.
Our brain interprets the wavelength of light that enters our eye and assigns it a color based on past experiences and cultural norms. This means that the concept of color is a subjective interpretation, and is not inherent in the light itself. So, it can be said that color exists only in our minds.
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Experiment to find ways to make rainbows.
a) Insert at least one setup where light passing through a prism gives a rainbow and describe why a rainbow is formed.
b) Explain why only some types of light will yield rainbows.
Answer:
Explanation:
a) To get a rainbow from a prism arrangement, we will need
A triangular prismA black cardboard boxA source of white light (light from the window will suffice)A pocket knifeFirst, you cut a slit in one end of the cardboard with the pen knife.
Next you open up a space on top of the cardboard through which you can observe the experiment and its result.
Next, you place the triangular prism with its slant face facing the the cut slit.
Finally, position the slit to face the light from the open window, and adjust the prism till the projected bands of colored light (rainbow) is very much obvious on the other end of the box, opposite the slit.
b) For a light to yield rainbow, it most be composed of different component colors of light. The colors of light is due to the difference in wavelength, and dispersion is due to the different in the wavelengths of the component light. So to get rainbow from a light source, the light must not be monochromatic. This means that only light composed of component light of different colors can produce rainbow. Light from the sun for example is composed of 7 distinct colors of light, and white light can be created with just three colors; blue, green, and red light.
A “blink of an eye” is a time interval of about 150 ms for an average adult. The “closure” portion of the blink takes only about 55 ms. Let us model the closure of the upper eyelid as uniform angular acceleration through an angular displacement of 15.5°.
a) What is the value of the angular acceleration the eyelid undergoes while closing? Answer in rad/s^2.
b)What is the tangential acceleration of the edge of the eyelid while closing if the radius of the eyeball is 1.25 cm? Answer in m/s^2
The value of the angular acceleration the eyelid undergoes while closing is 4.91 rad/s².
The tangential acceleration of the edge of the eyelid while closing is is 0.061 m/s².
What is angular acceleration?The angular acceleration of an object is the change in angular displacement of an object with time.
α = θ/t
where;
θ is angular displacement = (15.5⁰/360) x 2π = 0.27 rad/st is time, = 55 ms = 55 x 10⁻³ sα = (0.27/55 x 10⁻³)
α = 4.91 rad/s²
The tangential acceleration of an object is defined as the rate of change of tangential velocity of the matter in the circular path.
a = αr
a = (4.91 rad/s²)(0.0125 m)
a = 0.061 m/s²
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A bicyclist steadily speeds up from rest to 6.00m/s in 7.30s.
How far did she travel during this time?
Answer:
21.899 m
Explanation:
The explanation here is a little differe because we are starting from rest. So, everyone does physics a little differently, but what I would start with is trying to find the accelaration. I've given the formula, now you are able to plug this into the displacement formula where you Velocity Initial = 0m/s (Since you are starting from rest) and V final = 6.00 m/s...
You just plug numbers into the formula after solving for accelaration and do some simple algebra! I hope this helps! I am attaching a new pdf for visuals! If you can't open it let me know! Also there is a star by accelaration because I didn't know if I spelled it right, sorry!
What displacement do I have if I travel at 10 m/s E for 10 s? A. 1 m E B. 1 m C. 100 m D. 100 m E Scalar quantities include what 2 things? A. Number and direction B. Numbers and units C. Units and directions D. Size and direction What measures distance in a car? A. Odometer B. Pressure gauge C. Speedometer D. Steering wheel What displacement do I have if I travel 10 m E, then 6 m W, then 12 m E? A. 28 m E B. 16 m E C. 16 m D. 28 m
Should genetic genealogy be used to solve crimes ? Yes or no and why?
Answer:
yes
Explanation:
because it will help find who did the crime and it can also open jobs and opportunities for the people who likes sicnenae
Use the work-energy theorem to find the force required to accelerate an electron (m
9.11 x 10-31 kg) moving along the x axis from 3.50 x 106 m/s to 1.55 x 107 m/s in a
distance of 0.0135m.
By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
Pulmonary circulation involves blood flow to and from the heart and the ____?
body
digestive organs
skin
brain
lungs
Answer: Lungs
Explanation:
What must a scientist do in order to develop a testable hypothesis? O A. Find out whether the idea would be interesting to other scientists. O B. Determine whether the conclusion is supported by popular opinion. C. Ask a question that can be answered by making observations. D. Research accepted scientific theories to find one that is wrong.
Answer: C. Ask a question that can be answered by making observations.
Explanation: Just did it
Barry Bonds hits a 125m (450’) home run. Assuming that the ball left the bat at an
angle of 45° from the horizontal, calculate how long the ball was in the air.
The ball left the bat at an angle of 45° from the horizontal, and then the ball was in the air for 4.51 seconds.
To calculate how long the ball was in the air, we can break down the motion of the ball into its horizontal and vertical components. Given that the ball was hit at an angle of 45° from the horizontal, we can determine the initial velocities in the horizontal and vertical directions.
The horizontal component of the initial velocity (Vx) remains constant throughout the motion because there is no horizontal acceleration. The vertical component of the initial velocity (Vy) can be calculated using trigonometry, knowing that the angle is 45° and the magnitude of the velocity is 125 m (450 ft).
Vy = V * sin(45°)
Vy = 125 m/s * sin(45°)
Vy = 125 m/s * √(2)/2
Vy ≈ 88.4 m/s
Next, we can analyze the vertical motion of the ball. The ball is subject to a constant acceleration due to gravity, which is approximately 9.8 m/s². Using this acceleration, we can calculate the time it takes for the ball to reach its maximum height and then fall back down to the ground.
Using the kinematic equation:
Vy = V0y + a * t
where Vy is the final vertical velocity (which is 0 m/s at the highest point), V0y is the initial vertical velocity, a is the acceleration due to gravity (-9.8 m/s²), and t is the time.
0 = 88.4 m/s - 9.8 m/s² * t
Solving for t:
t = 88.4 m/s / 9.8 m/s²
t ≈ 9.02 s
Since the time calculated is for the total time of the ball's flight (going up and coming back down), we can divide it by 2 to get the time the ball was in the air:
t_air = t / 2
t_air ≈ 4.51 s
Therefore, the ball was in the air for approximately 4.51 seconds.
It's important to note that this calculation assumes ideal conditions and neglects factors such as air resistance, variations in gravitational acceleration, and any other external factors that could affect the ball's flight.
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A car approaches the top of a hill that is shaped like a vertical circle with a radius of 49.9 m. What is the fastest speed that the car can go over the hill without losing contact with the ground?
Answer:
22.11 m/s
Explanation:
The force acting on the car are its weight and the normal force. Then,
\(\begin{gathered} \text{F}_{\text{net}}=mg-N=ma_c \\ mg-N=m\frac{v^2}{r} \end{gathered}\)Since it is a circular path the net force is equal to mass times the centripetal acceleration, so we get the equation above.
When the car loses contact with the ground, the normal force is 0, so the given equation is
\(mg=m\frac{v^2}{r}\)Then, we can solve for v as follows
\(\begin{gathered} g=\frac{v^2}{r} \\ gr=v^2 \\ v=\sqrt[]{gr} \end{gathered}\)Therefore, replacing g = 9.8 m/s² and r = 49.9 m, we get
\(v=\sqrt[]{(9.8)(49.9)}=22.11\text{ m/s}\)So, the fastest speed that the car can go over the hill without losing contact with the ground is 22.11 m/s
A projectile is fired from the origin (at y = 0 m) as shown in the diagram
above. The initial velocity components are Vx = 140 m/s and Vy = 84 m/s.
The projectile reaches maximum height at point P, then it falls and strikes
the ground at point Q, which is 20 m below the launch point. Assuming air
resistance is negligible, what is the horizontal component of the velocity
(Vx) of the projectile at point P?
Answer:
\(v_{x}\) = \(v_{ox}\) = 140 m / s
Explanation:
This is a projectile launch, in this case the components of the initial velocity are seen
Since there is no rice in the X axis, so the velocity is vx, it must be constant, at all times
\(v_{x}\) = \(v_{ox}\) = 140 m / s
The vertical component of velocity changes due to having applied the gravity fiate
\(v_{y}\) = \(v_{oy}\) - g t
A particle changed q= 3,10x10^-6 C stays still on point P, a second particle with the same value q and a mass of 1,80x10^-2 kg is initially in repose at a distance of r1 = 9,00 cm from point P. This is second particle is released and repelled by the first. Determine the velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P.
note 1: from what i know i have to use the potential energy formula (U= mV^2/2), and possible calculate the electric force ? but from there i get lost
note 2: sorry if this isn't grammatically correct, i translated it from spanish
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is 17.22 m/s.
What is the electric force between the two particles?The electric force between the two particles is calculated from Coulomb's law of electrostatic force.
F = kq₁q₂/r²
where;
k is Coulomb's constantq₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the two chargesF = (9 x 10⁹ x 3.10 x 10⁻⁶ x 3.10 x 10⁻⁶) / (0.09 m)²
F = 10.68 N
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is calculated by applying the principle of conservation of energy.
W = ΔK.E
where;
W is work doneΔK.E is kinetic energy of the particleFr = ¹/₂mv²
2Fr = mv²
v² = 2Fr/m
v = √(2Fr/m)
v = √(2 x 10.68 x 0.25 / 1.8 x 10⁻²)
v = 17.22 m/s
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During a phase change the temperature of a substance remains constant this is because during a phase heat changes the ____ energy of particles in a substance without changing their ____ energy
Answer:
Explanation:
individual and then net
hope that helps I could be wrong about this one though
What type of force is gravity?
Answer:
A force of attraction that exists between any two masses, bodies, or particles.
Explanation:
Answer:
The gravitational force is a force that attracts any objects with mass. You, right now, are pulling on every other object in the entire universe! This is called Newton's Universal Law of Gravitation. ... And if you triple the distance between two objects, you reduce the force to a ninth.
Explanation:
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that have adjustable force constants. Its function is to dampen wind-driven oscillations of the building by oscillating at the same frequency as the building is being driven—the driving force is transferred to the object, which oscillates instead of the entire building.(a) What effective force constant (in N/m) should the springs have to make the object oscillate with a period of 2.10 s? N/m(b) What energy (in J) is stored in the springs for a 1.80 m displacement from equilibrium? J
ANSWERS
(a) 3.58 x 10⁶ N/m
(b) 5.8 x 10⁶ J
EXPLANATION
Given:
• The mass of the object hanging from the spring, m = 4.00 x 10⁵ kg
Find:
• (a), The force constant the springs should have to make the object oscillate with a period of 2.10 s
,• (b), The energy stored in the springs for a 1.80 m displacement from equilibrium.
(a) The period of an object in a spring is,
\(T=2\pi\sqrt{\frac{m}{k}}\)Where m is the mass of the object and k is the spring constant.
We want to find k for T = 2.10 s, so we have to solve this equation for k, which gives us,
\(k=m\cdot\left(\frac{2\pi}{T}\right)^2\)Replace the known values and solve,
\(k=4\cdot10^5\cdot\frac{4\pi^2}{(2.1)^2}\approx3,580,808.85N/m\approx3.58\cdot10^^6N/m\)Hence, the force constant is 3.58 x 10⁶ N/m.
(b) The energy stored in a spring with force constant k when the mass is displaced x meters from equilibrium is,
\(U_s=\frac{1}{2}kx^2\)Replace the known values and solve to find the energy stored in this spring,
\(U_s=\frac{1}{2}\cdot3.58\cdot10^6N/m\cdot1.8^2m^2\approx5.8\cdot10^6J\)Hence, the energy stored in the spring for a 1.80 m displacement from equilibrium is 5.8 x 10⁶ J.
What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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jacob is kayaking across the chattooga river at a velocity of 2.5 m/s east. the river current today is 6 m/s south. find is velocity and direction,
The resultant velocity of the jacob while crossing chattooga river is found as 6.5 m/s with the direction heading south east.
Explain about the resultant velocity vector?An object's total vector velocity is indeed the sum of its component vector velocities. This scalar product of an object's mass and acceleration vector equals the sum of a vector forces acting on it.Due to kayaker and the river, we obtain two perpendicular velocities: 2.5 m/s across the river in an easterly direction, and 6 m/s downstream in a southerly direction.
The Pythagorean Theorem predicts the size of a resultant velocity as follows:
v = √(2.5)² + (6)²
v = √42.25
v = 6.5 m/s
The resultant direction will be south east.
Thus, the resultant velocity of the jacob while crossing chattooga river is found as 6.5 m/s with the direction heading south east.
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Activity: I Remember! List all the Social Sciences you can remember from your class on Disciplines and Ideas in the Social Sciences.
Answer:
Anthropology, Economics and management, History, Human services, political science, psychology, sociology
using the human species as an example, explain what is meant by variation of traits
Which best describes a neutralization reaction?
a reaction between an acid and a base
a reaction between two acids
a reaction between a base and a salt
a reaction between two salts
Answer:
a reaction between an acid and a base
Explanation:
Answer:
The answer is A. A reaction between an acid and a base
Explanation:
A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.
What is the acceleration of the SRB and main engine during the first 2.0 minutes of flight?
A. 52 m/s2
B. 13 m/s2
C. 9.8 m/s2
D. 11 m/s2
The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².
The given parameters;
initial velocity of the engine, u = 1341 m/sfinal velocity of the engine, v = 7600 m/stime of motion, t = 2 minutes = 2 x 60 s = 120 sThe acceleration of the SRB and main engine is calculated as follows;
\(a = \frac{\Delta v}{\Delta t } \\\\a = \frac{7600 - 1341}{2 \times 60 s} \\\\a = 52.16 \ m/s^2\)
Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².
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Which term best describes a question that can be tested?
A. Phenomenon
B. Hypothesis
C. Experiment
D. Observation
Answer:
Hypothesis
Explanation:
because in science a hypothesis is a guess/question that you test. it can be changed many times
Answer:
C) experiment. Is the answer.
hypothesis is the educated guess about what the result of the experiment is before conducting the experiment.
Observation is what you see and record during the experiment.
Determine the percentage of kinetic energy lost by a small ball when it makes an elastic head-on collision with stationary bigger ball. The mass of the bigger ball is 12 times bigger than the mass of the small ball.
The small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.
\(\frac{Kf}{Ki} =\) \(1- [\frac{1}{2}][ \frac{M}{m}] [\frac{2mv^{2} }{[M+m]^{2} }\)
M = 12m
Kf/Ki = 1 - (1/2)(12m/m)[(2mv^2)/(13m)^2]
Kf/Ki = 165/169
(1 - Kf/Ki) x 100% = (1 - 165/169) x 100% = 2.37%
So, the small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.
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2. Gerard is riding his bicycle directly east. His maximum
instantaneous velocity was 8 meters per second and his
minimum instantaneous velocity was 0 meters per second. He
covered 7.20 kilometers in 20.0 minutes. What is his average
velocity for the ride?
Gerard's average velocity for the ride is 6 meters per second.
To find Gerard's average velocity for the ride, we can use the formula:
Average velocity = Total displacement / Total time
First, we need to convert the distance traveled from kilometers to meters:
7.20 kilometers * 1000 = 7200 meters
Next, we convert the time from minutes to seconds:
20.0 minutes * 60 = 1200 seconds
Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:
Total displacement = 7200 meters
Finally, we substitute the values into the average velocity formula:
Average velocity = 7200 meters / 1200 seconds
Average velocity = 6 meters per second
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what is measured by the ammeter
Answer:
amperes
Ammeter, instrument for measuring either direct or alternating electric current, in amperes. An ammeter can measure a wide range of current values because at high values only a small portion of the current is directed through the meter mechanism; a shunt in parallel with the meter carries the major portion.
Explanation:
hope it helps
how much is need to lift a load of 100n placed at a distance of 29 cm from fulcrum if effort is applied at 60cm from the fulcrum on opposite side of the load? calculate mechanical advantage and velocity ratio of the lever
Answer:
206.8965517 n
Explanation:
First, we need to see that 60:29 is 2.078965517:1. Then we need to multiply the energy put 29 cm from the fulcrum by 2.078965517, giving us the end result of our answer.
(A) Electricity and Magnetism
A). Three point charges are aligned along the x axis as shown in
Fig. Find the electric field at (a) the position (2, 0) and (b) the
position (0, 2).
electricity
Explanation:
the position (2,o