Two bicycles head toward each other from opposite ends of a freeway 364 miles long. If the speed of the first bicycle is 15 miles per hour and the speed of the second bicycle is 11 miles per hour, how long will it take before the bicycles pass each other?
hours

Answers

Answer 1

Answer:

how many hours?

Step-by-step explanation:

Answer 2

Answer:

14 hours

Step-by-step explanation:

Let x be the time, in hours, that it takes for the two bikes to meet.  Let A and B be the two bicycles.

The distance travelled by each bike is given by:

Bike A:  15x

Bike B:  11x

At time x, when they meet, both bikes will have travelled a total of 364 miles:

15x + 11x = 364

26x = 364

x =  14 hours

After 14 hours of non-stop cycling, the two bikes will meet.

=====================

Check:

Total miles

A:   210

B:   154

       364  total


Related Questions

The moon is in an orbit around the earth, and the length of this
orbit is 3.844 × 100,000 kilometers.
1. What is the shortcut for multiplying 3.844 by 100,000?

Answers

The product of given numbers is 384400.

What is multiplication?

Multiplication is an operation that represents the basic idea of repeated addition of the same number. The numbers that are multiplied are called the factors and the result that is obtained after the multiplication of two or more numbers is known as the product of those numbers.

Given that, the moon is in an orbit around the earth, and the length of this

orbit is 3.844×100,000 kilometers.

Here, 3.844 multiplied by 1 we get 3.844

When multiplying decimals by 100000, the digits shift five places to the left.

That is, 384400.0

Therefore, the product of given numbers is 384400.

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Sphenathi stated that the distance from Bloemfontein to upington is 16.3 show all calculations whether his claim is correct

Answers

The distance between Bloemfontein and Upington is a distance of 582 kilometers. The distance between two cities may vary depending on the route taken, traffic, and other factors. The distance between these two cities is measured in a straight line, which may not be the actual road distance.

To determine the distance between Bloemfontein and Upington, we used the Haversine formula, which computes the shortest distance between two points on the surface of a sphere. We first begin by finding the latitude and longitude of the two cities.Bloemfontein is located at -29.1211° latitude and 26.2140° longitude.Upington is located at -28.4478° latitude and 21.2561° longitude.Using the Haversine formula, we can determine that the distance between the two cities is about 582 kilometers.Sphenathi's statement that the distance from Bloemfontein to Upington is 16.3 kilometers is incorrect. Perhaps they mistakenly calculated the distance between two points within the cities. They could also have made a typographical mistake while writing their statement. Therefore, the statement is false, and the actual distance between Bloemfontein and Upington is 582 kilometers.

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A rectangular prism has a length of 8in., a width of 4in., and a height of 2 1/4in. The prism is filled with cubes that have edge lengths of 1/4 in. How many cubes are needed to fill the rectangular prism?

Answers

We need 4608 cubes to fill the rectangular prism.

We have,

The rectangular prism has a volume of:

Volume = length x width x height

Volume = 8 in. x 4 in. x 2 1/4 in.

Volume = 72 in³

Each cube has a volume of:

Volume of cube = edge length³

Volume of cube = (1/4 in.)³

Volume of cube = 1/64 in³

To find the number of cubes needed to fill the rectangular prism, we can divide the volume of the prism by the volume of each cube:

Number of cubes = Volume of prism / Volume of a cube

Number of cubes = 72 in³ / (1/64 in³)

Number of cubes = 72 in³ x 64 / 1

Number of cubes = 4608 cubes

Therefore,

We need 4608 cubes to fill the rectangular prism.

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Set of whole numbers from 1 to 10 inclusive greater than seven and odd

Answers

Answer:

{7, 9}

(Numbers from 1 to 10 equal to or greater than 7 are 7 and 9)

Step-by-step explanation:

We have to find the set of whole number greater than and equal to 7 from 1 to 10,

Now, From 1 to 10, the odd numbers are, 1,3,5,7,9,

And of these, 7 and 9 are equal to or greater than 7

So, we get the set,

{7, 9}

if a(x) = 3x+1 and b(x) = \(square root of x-4\), what is the domain of (boa)(x)

Answers

The domain of (boa)(x) is [1, ∞].

What is a domain?

In Mathematics and Geometry, a domain is the set of all real numbers (x-values) for which a particular equation or function is defined.

Based on the information provided above, we have the following functions:

a(x) = 3x+1

\(b(x) = \sqrt{x-4}\)

Therefore, the composite function (boa)(x) is given by;

\(b(x) = \sqrt{3x+1 -4}\\\\b(x) = \sqrt{3x-3}\)

By critically observing the graph shown in the image attached below, we can logically deduce the following domain:

Domain = [1, ∞] or {x|x ≥ 1}.

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if a(x) = 3x+1 and b(x) = [tex]square root of x-4[/tex], what is the domain of (boa)(x)

The entrance fee to a carnival is $8, and it costs $0.50 for each ride. If Sanjay rides 6 rides, how much will he spend in total?

Answers

They will spend 11 dollars.

Answer:

3 dollars

Step-by-step explanation:

Help please geometry

Help please geometry

Answers

The area of the shaded region = 30.903 in²

From the attached figure we can observe that the radius of the circle R is r = 6 in.

Using the forula for the area of circle, the area of circle R would be,

A₁ = πr²

A₁ = π × 6²

A₁ = 36π

A₁ = 113.097 in²

So, the diameter would be d = 6 × 2 = 12 in.

The circle R is inscribed in a square.

So, the side length of square is equal to the diameter of the circle.

This means the side length 'a' os square = 12 in.

Using the formula of the area of square,

A₂ = side²

A₂ = a²

A₂ = 12²

A₂ = 144 in²

so, the area of the shaded region would be,

A = A₂ - A₁

A = 144 -113.097

A = 30.903 in²

This is the required area.

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Find X.

A. 27.2
B. 12.9
C. 30.3
D. 17.8​

Find X. A. 27.2B. 12.9C. 30.3D. 17.8

Answers

Answer: 27.2

Step-by-step explanation:

\(\sin 54^{\circ}=\frac{22}{x}\\\\x \sin 54^{\circ}=22\\\\x=\frac{22}{\sin 54^{\circ}} \approx \boxed{27.2}\)

If s(x) = 2x² and f(x) = 3x, which value is equivalent to (s-f)(-7)?
O-439
O-141
O 153
O 443

Answers

The value of expression (s - f) (- 7) would be,

⇒ (s - f) (- 7)  = 119

We have to given that,

Functions are defined as,

⇒ s (x) = 2x²

⇒ f (x) = 3x

Now, We can find the value of (s - f) (- 7) is,

⇒ (s - f) (- 7)

⇒ s (- 7) - f (- 7)

⇒ 2 (- 7)² - (3 × - 7)

⇒ 2×49 + 21

⇒ 98 + 21

⇒ 119

Therefore, The value of expression (s - f) (- 7) would be,

⇒ (s - f) (- 7)  = 119

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True OR False
The lengths 35, 37, and 12 make a right triangle.

Answers

Answer:

im pretty sure false. ......... ....................

True

Use Pythagorean theorem

A normal distribution is informally described as a probability distribution that is​ "bell-shaped" when graphed. Draw a rough sketch of a curve having the bell shape that is characteristic of a normal distribution.

Answers

The bell-shaped curve, also known as a Gaussian curve or a symmetrical distribution , showcases a central peak with data symmetrically distributed around it .

What is a bell curve known for ?

Revered for its iconic shape, the bell curve enchants the discerning observer with its symmetrical countenance, reminiscent of a resonant chime.

This majestic distribution unveils its true essence through its discernible apex, a testament to central tendency , where the mean, median, and mode converge, bestowing upon it an air of distinction .

The rough sketch of the curve having the bell shape is shown attached to the question.

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A normal distribution is informally described as a probability distribution that is "bell-shaped" when

2tan(x/2)- csc x=0 interval [0,2pi)

Answers

Answer:

\(x= \dfrac{\pi}{3}, \;\;x=\dfrac{5 \pi}{3}\)

Step-by-step explanation:

Given trigonometric equation:

\(2 \tan\left(\dfrac{x}{2}\right)- \csc x=0\)

To solve the equation for x in the given interval [0, 2π), first rewrite the equation in terms of sin x and cos x using the following trigonometric identities:

\(\boxed{\begin{minipage}{4cm}\underline{Trigonometric identities}\\\\$\tan \left(\dfrac{\theta}{2}\right)=\dfrac{1-\cos \theta}{\sin \theta}$\\\\\\$\csc \theta = \dfrac{1}{\sin \theta}$\\ \end{minipage}}\)

Therefore:

              \(2 \tan\left(\dfrac{x}{2}\right)- \csc x=0\)

\(\implies 2 \left(\dfrac{1-\cos x}{\sin x}\right)- \dfrac{1}{\sin x}=0\)

  \(\implies \dfrac{2(1-\cos x)}{\sin x}- \dfrac{1}{\sin x}=0\)

\(\textsf{Apply the fraction rule:\;\;$\dfrac{a}{c}-\dfrac{b}{c}=\dfrac{a-b}{c}$}\)

\(\dfrac{2(1-\cos x)-1}{\sin x}=0\)

Simplify the numerator:

\(\dfrac{1-2\cos x}{\sin x}=0\)

Multiply both sides of the equation by sin x:

\(1-2 \cos x=0\)

Add 2 cos x to both sides of the equation:

\(1=2\cos x\)

Divide both sides of the equation by 2:

\(\cos x=\dfrac{1}{2}\)

Now solve for x.

From inspection of the attached unit circle, we can see that the values of x for which cos x = 1/2 are π/3 and 5π/3. As the cosine function is a periodic function with a period of 2π:

\(x=\dfrac{\pi}{3} +2n\pi,\; x=\dfrac{5\pi}{3} +2n\pi \qquad \textsf{(where $n$ is an integer)}\)

Therefore, the values of x in the given interval [0, 2π), are:

\(\boxed{x= \dfrac{\pi}{3}, \;\;x=\dfrac{5 \pi}{3}}\)

2tan(x/2)- csc x=0 interval [0,2pi)

75/1+15e^-0.4x=25 solve for x

Answers

Answer:

\(\frac{75}{1}+15e^-\cdot \:0.4x=25\quad :\quad x=-\frac{25}{3};\quad \ne \mathrm{True},\:e\ne \:0\quad \left(\mathrm{Decimal}:\quad x=-8.33333\dots \right)\)

Step-by-step explanation:

\(\frac{75}{1}+15e^-\cdot \:0.4x=25\)

\(\mathrm{Apply\:rule}\:\frac{a}{1}=a\)

\(\frac{75}{1}=75\)

\(75+15\cdot \:0.4e^-x=25\)

\(\mathrm{Multiply\:the\:numbers:}\:15\cdot \:0.4=6\)

\(75+6e^-x=25\)

\(\mathrm{Subtract\:}75\mathrm{\:from\:both\:sides}\)

\(75+6e^-x-75=25-75\)

\(\mathrm{Simplify}\)

\(6e^-x=-50\)

\(\mathrm{Divide\:both\:sides\:by\:}6e^-;\quad \ne \mathrm{True}\)

\(\frac{6e^-x}{6e^-}=\frac{-50}{6e^-};\quad \ne \mathrm{True}\)

\(\mathrm{Simplify}\)

\(e^{ }x=-\frac{25}{3e^-};\quad \ne \mathrm{True}\)

\(\mathrm{Divide\:both\:sides\:by\:}e;\quad \ne \mathrm{True},\:e\ne \:0\)

\(\frac{e^{ }x}{e}=\frac{-\frac{25}{3e^-}}{e};\quad \ne \mathrm{True},\:e\ne \:0\)

\(\mathrm{Simplify}\)

\(\frac{x}{e}=-\frac{25}{3e^1};\quad \ne \mathrm{True},\:e\ne \:0\)

\(\mathrm{Multiply\:both\:sides\:by\:}e\)

\(\frac{xe}{e}=\left(-\frac{25}{3e^1}\right)e;\quad \ne \mathrm{True},\:e\ne \:0\)

\(\mathrm{Simplify}\)

\(x=-\frac{25}{3};\quad \ne \mathrm{True},\:e\ne \:0\)

I need help please I can only find 2 of these solutions

I need help please I can only find 2 of these solutions

Answers

Step 1: Isolate the Sin Operator

\(8 sin(\frac{\pi }{6} x)=2\\sin(\frac{\pi }{6} x)=0.25\\\\\)

Step 2: Use Inverse Sin(arcsin) to isolate the term with the x variable

Note that since trig functions have 2 general solutions, this will give us one of our general solutions.

\(x=\frac{6 arcsin(0.25)}{\pi } =0.48\)

x₁= 0.48

Solving for x₂

Use the period identity for Sin Functions

\(sin(x)=sin(\pi -x)\)

X in this case is arcsin(0.25)

\(\frac{\pi }{6} x=\pi -arcsin(0.25) = 5.52\)

So our two general solutions are 0.48 and 5.52

Step 3: Period

Trig Functions have periodic behavior and this function period is

\(\frac{2\pi }{1} (\frac{6}{\pi } )= 12\)

So our general solutions are

0.48±12k, where k is an integer

5.52±12k, where k is an integer

Let k=1, and we get our next set of solutions:

12.48 and 17.52

So our answer is 0.48,5.52,12.48,17.52

Help will give Brainly points

Help will give Brainly points

Answers

\(b = \sqrt{ {95}^{2} + {60}^{2} - 2 \times 60 \times 95 \times \cos(70) } = 93.4\)

pentru dotarea unei clase sunt necesare 15 banci si 30 de scaune.Cate piese de mobilier sunt necesare pentru 5 clase? ( rezolvă in doua moduri)repede

Answers

Answer:

75 banci si 150 scaune

Step-by-step explanation:

Ce stim:

1 clasa → 15 banci si 30 scaune

Ce aflam in modul 1:

5 clase → (15+15+15+15+15) banci si (30+30+30+30+30) scaune

Raspuns:

5 clase → 75 banci si 150 scaune

Ce aflam in modul 2:

5 clase → 15·5 = 75 banci si 30·5 = 150 scaune

Raspuns:

5 clase → 75 banci si 150 scaune

Suppose N1 can be exchanged for £0.12, what is the value of N12 in pounds?

Answers

Answer:

£1.44

Step-by-step explanation:

N1 = £0.12

N12 = 12 × N1 = 12 × £0.12 = £1.44

What is the marginal revenue product of the fourth worker?
$600
$2,400
$400
$1,200

Answers

Option c. $400 is the correct answer. The marginal revenue product of the fourth worker is $400.

The efficient organizations compare to its competitor generates higher marginal revenue product at each level of labour input. They invest heavily in training, skilling, and re-skilling their labour force with a transparent organizational culture.

The incremental total revenue earned for additional labour recruited is termed as marginal revenue product. The marginal revenue product of the fourth worker is calculated as under

The total revenues generated by employing three labourers is $1,120

The total revenues generated by employing four labourers is $1,520

Marginal revenue product of the fourth worker = Total revenues generated by employing four labourers - Total revenues generated by employing three labours

=$1,520 - $1,120

=$400

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Match each inequality to the number line that represents its solution

Match each inequality to the number line that represents its solution

Answers

Answer:

x - 51 \(\leq\) 43

x - 99 \(\leq\) -104

75 < 69 - x

150 + x ≤ 144

Step-by-step explanation:

If o=12, find the sample size to estimate the mean with an error of +4 and 95 percent confidence (rounded to the next higher integer).
Multiple Choice
75
35
58
113
URGENT

Answers

We need to round up to the next higher integer, the sample size required to estimate the mean with an error of +4 and 95 Percent confidence is 170.

To find the sample size to estimate the mean with an error of +4 and 95 percent confidence, we need to use the formula:

n = [(z*sigma)/E]^2

Where:
n = sample size
z = z-score for 95% confidence level (which is 1.96)
sigma = standard deviation (unknown in this case)
E = maximum allowable error (which is +4 in this case)

We are given that o=12, which is the population standard deviation. Since we do not have any information about the sample standard deviation, we can use the population standard deviation as an estimate. Therefore, we can substitute o=12 in the above formula to get:

n = [(1.96*12)/4]^2
n = 169.64

Since we need to round up to the next higher integer, the sample size required to estimate the mean with an error of +4 and 95 percent confidence is 170.

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Mr. McMurry wants to get a gym membership. Planet fitness charges $25 a month. Everyday Fitn
charges membership fee of $30 and charges $10 a month. How many months would it take for E
options To be equal?
Equation

Solution

Answers

Answer:

pp

Step-by-step explanation:

The measures of the angles between the resultant and two applied forces are 26° and
20°, and the magnitude of the resultant is 80 pounds. Find the magnitude of the
larger force, to the nearest 10th of a pound.

Answers

Answer:

  48.8 lbs

Step-by-step explanation:

The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:

  a/sin(A) = c/sin(C)

  x/sin(26°) = 80/sin(134°)

  x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds

The larger component force is about 48.8 pounds.

The measures of the angles between the resultant and two applied forces are 26 and20, and the magnitude

Medical records indicate that people with more education tend to live longer; the correlation is 0.48. The slope of the linear model that predicts lifespan from years of education suggests that on average people tend to live 0.8 extra years for each additional year of education they have. The slope of the line that would predict years of education from lifespan is

Answers

Answer:

0.288

Step-by-step explanation:

Given that :

Correlation (R) = 0.48

Slope of linear model which predicts Lifespan from years of education (m) = 0.8

To determine the value of slope of the model which predicts years of eductauoon from lifespan:

The square of the regression Coefficient is multiplied by the inverse of the slope of linear model which predicts Lifespan from years of education

Hence,

(R² * 1/m)

0.48² * 1/0.8

0.2304 * 1.25

= 0.288

10. Prime numbers from 1 to 100 are running a restaurant - PRIME SPOT, near a tourist point. On a winter holiday, 1 and the composite numbers up to 100 enter the restaurant for dinner after their picnic at the same point. The dining hall has tables with seating capacity 15 for each. If they occupy tables without leaving any chair free, how many tables are required? If each prime number attender has to serve equal number of customers, how many customers should each one get to serve? ​

Answers

6 tables are required. Each prime number attender should serve 3 customers each.

The prime numbers between 1 and 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

All the numbers other than prime numbers are composite numbers.

The composite numbers from 1 to 100 are: 1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.

Now, as there are 25 primes and 75 composites in the group that visited the restaurant, we can calculate the number of tables required by dividing the number of people by the seating capacity of each table.

Each table has a seating capacity of 15, so the number of tables required will be: Number of tables = (Number of customers)/(Seating capacity of each table)Number of customers = 25 (the number of primes) + 75 (the number of composites) = 100Number of tables = 100/15 = 6 tables

Therefore, 6 tables are required.

Now, as each prime number attender has to serve an equal number of customers, we need to calculate how many customers each one should serve.

Each prime attender has to serve 75/25 = 3 customers each, as there are 75 composites and 25 primes.

Thus, each prime number attender should serve 3 customers each.

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What is the constant up a proportionally in a equation y=x/g

Answers

Answer:

Step-by-step explanation:

\(y=(\frac{1}{g} )x\)

Constant up a proportionally is  \(\frac{1}{g}\).

Function c
is defined by the equation c(n)=50+4n
. It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits, n
.

True or False? The inverse function is as follows:

n=(c(n) − 50)×4
Responses

Answers

Answer:

False

Step-by-step explanation:

1. The inverse function should have c(n) isolated
2. When finding the inverse of a function, the variables c(n) and n are interchanged (and then c(n) is isolated).
It would look like this --->c(n)=50+4n--->n=50+4(c(n)) ---> c(n)=(n-50)/4

Simplify -2(-5) - 7 + 1(-3)

Answers

Answer:

Step-by-step explanation:

BRUH YOU STUPID

Answer:

0

\( \\ solution \\ - 2( -5) - 7 + 1( - 3) \\ = 10 - 7 + ( - 3) \\ = 10 - 7 - 3 \\ = 3 - 3 \\ = 0 \\ hop \: it \: helps...\)

5 customers entered a store over the course of 15 minutes. Fill out a table of equivalent ratios and plot the points on the coordinate axes provided.
THE CORRECT ONE GETS BRAINLIEST

5 customers entered a store over the course of 15 minutes. Fill out a table of equivalent ratios and

Answers

1. 1:3
2. 2:6

when 5 customers entered the store, 15 minutes elapsed. the ratio here is 5:15, which simplifies to 1:3. (5/5 = 1; 15/5 = 3 —> 1:3)
when the minutes elapsed is 3, that means the customer amount must be 1, and when there are 2 customers, the amount of minutes that go by is 6. 1:3 —> 2:6 (multiply both numbers by 2). hope this helps.

Is it true that the only nontrivial maximally planar regular graphs are the triangle, the tetrahedron, the octahedron, and the icosahedron?
No answer needed!

Answers

Answer:

. Have a goodnight.

URGENT PLEASE

One number is 5 more than two times the other. Their sum is 11.

Answers

Answer:

the numbers are 8 and 3.

I think it us 8 and 3 I hope I’m right
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What type of hormones use second messengers in a cascade of reactions that trigger a cell response?. what would be the final volume when 2.20 M solution is made from 25.0 mL of a 12.0 M solution? plzz show work "The 'grand design' view of Justinian's reign sees all his actions as the deliberate restoration of the ancient Roman empire, though a Roman empire raised to new heights of glory as a Christian empire confessing the orthodox faith. According to this view, reconquest restored something like the traditional geographical area of the empire; law reform encapsulated the vision of a Christian Roman empire, governed by God's vicegerent, the emperor; the capital's splendid buildings, not least the churches, celebrated the Christian court of New Rome, with the defensive buildings described by Procopius in the later books of his Buildings serving to preserve in perpetuity the newly reconquered Roman world." 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