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Answer: Blll's family has 70% of driving left.

Step-by-step explanation:

The total mileage of the trip = 3,000 miles.

miles driven so far = 900miles

Miles of diatance left = 3000- 900=2100

Percentage of driving left =  Miles of diatance left / Total miles to cover x 100

=2100/3000 x 100

= 7/10  x100

70%

The dependent variables in the following scenario are whether the bacon becomes moister and more flavorful and the independent variable is the cooking method.

In statistics, a dependent variable is one whose value is determined by another set of variables called independent variables. To put it simply, the dependent variable is the thing that is being tested or calculated. The dependent variable is sometimes known as the "outcome variable." In the given scenario, the chef was curious as to whether or not frying or microwaving the bacon would produce a moister and more flavorful final product. The bacon is the result of the experiment, hence it is a dependent variable.

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Thus, the solutions are: `(-4,2), (16/9, -4/3), (16/9, 4/3)`.

The equation of the curve is y^3=2x^2. Differentiating with respect to x gives `3y^2 dy/dx = 4x`.

`dy/dx` is the gradient of the curve at `(x,y)`.Thus, `dy/dx = 4x/(3y^2)` and the equation of the tangent at `(x,y)` is: `y - y0 = (4x/(3y0^2))(x - x0)`where `(x0,y0)` is any point on the curve. Solving `x-2y-10=0` for `y`, we get `y = (x-10)/2`. The gradient of this line is `-1/2`. For the tangent to be perpendicular to this line, the product of the gradients must be -1.`(4x/(3y^2))(-1/2) = -1` ⇒ `x = -3y^2/8`.Thus, `y^3 = 2x^2 = 27y^4/32`. Solving gives `y = 0, ± 16/3^(1/3)` and `x = -3y^2/8` gives the points where the tangent is perpendicular to the line.

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Answer:

16

Step-by-step explanation:

If x = 3 and  , y = 2.  

2 x 3 = 6  and 5 x 2 = 10.

10 + 6 = 16

The value of the expression 2x + 5y when x = 3 and y = 2 is 16.

We have to determine, the value of the expression 2x + 5y when x = 3 and y = 2.

According to the question,

Expression; 2x + 5y

To determine the value of the expression calculation must be done in a single unit following all the steps given below.

The value of expression 2x+5y,

When the value of x = 3 and y = 2,

Therefore,

\(= 2x + 5y\)

Substitute the value of x = 3 and y = 2 in the given expression,

\(= 2(3)+ 5(2)\\\\= 6 + 10\\\\= 16\)

Hence, The value of the expression 2x + 5y when x = 3 and y = 2 is 16.

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Step-by-step explanation:

3/x=15/30

=> x=(30×3)/15

=> x=6.

hope this helps you.

Step-by-step explanation:

For Pythagoras' Theorem to be valid, the triangle must be a right-angled one.

The formula is:

c^2 = a^2 + b^2

Where c is the longest side. While a,b are the side lengths.

Using the above formula and the measurements given in the question, we can find the value of x.

By Pythagoras' Theorem,

26^2 = (5x)^2 + (12x)^2

676 = 25x^2 + 144x^2

169x^2 = 676

x^2 = 676 ÷ 169

x^2 = 4

x = 2

The correct statement is C.) The proportion of the variation in height that is explained by a regression on age is 0.64.

The coefficient of determination (R2), which ranges from 0 to 1, expresses how accurately a statistical model forecasts a result.

The correlation Coefficient R = 0.8,  which demonstrates the strong correlation between children's age and height. With the correlation coefficient value, we can calculate the coefficient of determination (R2), which indicates the proportion of variation that the regression model can account for.

Coefficient of determination \((R^{2} ) = 0.8^{2}\)

= 0.64.

0.64 of the variation in children's height that can be attributed to age and 0.36 to other factors.

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missing Options :

A.) On average, the height of a child is 80% of the age of the child.

B.) The least-squares regression line of height versus age will have a slope of 0.8.

C.) The proportion of the variation in height that is explained by a regression on age is 0.64.

D.) The least-squares regression line will correctly predict height based on age 80% of the time.

E.) The least-squares regression line will correctly predict height based on age 64% of the time.

\( \fbox{(2,5)}\)

Hello, substitute all the given coordinates & see if RHS match with LHS

given equation,

y = 4x-3

First coordinate,

(x,y) = (2,5)

5= 4×2-3

5=5

Hence, first solution satisfies the given equation,

let's solve for rest other cordinates,

second coordinate,

(x,y) = (5,5)

5= 4×5-3

5 ≠ 17

does not satisfy,

third coordinate,

(x,y) = (4,5)

5= 4×4-3

5 ≠ 13

does not satisfy,

fourth coordinate,

(x,y) = (4,5)

5 = 4×3-3

5 ≠ 9

does not satisfy.

Hence the correct answer is (2,5)

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Answer:

A.   7

B.   6

C.   70 degrees

Answer:

A. x=7

B. x=6

C. x= 40

Step-by-step explanation:

Trust me, I've been doing this kind of problems for 17 years. I'm an algebra teacher.

Answer:

Anywhere between -$21 and -$20

Step-by-step explanation:

\(x < -20\) AND \(x > -21\)

Examples include:
\(-$20.01\)

\(-$20.10\)

\(-$20.20\)

\(-$20.30\)

\(-$20.40\)

\(-$20.50\)

\(-$20.60\)

\(-$20.70\)

Answer:

19

Step-by-step explanation:

Add up all the numbers:

3,2,2,2,1,1,1,4,2,1

Then you get 19.

Or you can say it as

3^2 + 2^4 + 1^4 + 4

The y-intercept of a function is the point at which it intersects the y-axis. In other words, it is the value of the function when the input (x) is zero.

Whether or not a function has a y-intercept depends on its equation and the nature of the function. For example, a linear function of the form y = mx + b (where m is the slope and b is the y-intercept) will always have a y-intercept, since b represents the value of y when x = 0. On the other hand, some functions (such as circles or exponential functions) do not intersect the y-axis and therefore do not have a y-intercept.

If a function does have a y-intercept, its value can provide useful information about the behavior of the function. For example, in a linear function, the y-intercept represents the starting point of the line and can be used to calculate the value of the function at any point along the line. In a quadratic function, the y-intercept represents the point at which the parabola intersects the y-axis and can provide information about the maximum or minimum value of the function.

In summary, the y-intercept is an important concept in mathematics that can provide valuable information about the behavior of a function. However, it is not always applicable, depending on the equation and nature of the function in question.

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Answer:1.18 inches Hope this helps

Step-by-step explanation:

divide 1 by seven in long division it will be 0.142857 then it repeat it self ...so to the nearest thousand is 0.143

Answer:

Step-by-step explanation:

Data

• Morning: 156 times

• Lunch: x times

• Afternoon: 201 times

• Whole day: 562 times

Procedure

To know how many times did it ring at lunch, we have to build a relation, in which we know that the addition of the times in the morning, lunch, and afternoon equal the times it rang the whole day:

Then, we have to solve for x considering that it represents the times it rang during the lunch.

Answer: It rang 205 times during the afternoon.

(A) To show that E[g'(Z)]=E[Zg(Z)], we use integration by parts.

(B) To show that E[Zn+1]=nE[Zn-1], we use integration by parts again.

(C) To find E[Z^4], we use the result from part (B).

(A) To show that E[g'(Z)]=E[Zg(Z)], we use integration by parts. Let u=g(Z) and dv=dZ, then du=g'(Z)dZ and v=Z. Using the formula for integration by parts, we get:

E[g'(Z)] = ∫g'(Z)φ(Z)dZ = g(Z)φ(Z)|-∞^∞ - ∫g(Z)φ'(Z)dZ

= - ∫Zg(Z)φ'(Z)dZ = E[Zg(Z)],

where φ(Z) is the probability density function of a standard normal random variable Z. Therefore, we have shown that the expected value of the derivative of a differentiable function g evaluated at a standard normal random variable Z is equal to the expected value of the product of Z and g(Z).

(B) To show that E[Zn+1]=nE[Zn-1], we use integration by parts again. Let u=Z^n and dv=dZ, then du=nZ^(n-1)dZ and v=Z. Using the formula for integration by parts, we get:

E[Z^n+1] = ∫Z^n+1φ(Z)dZ = Z^nφ(Z)|-∞^∞ - ∫nZ^nφ(Z)dZ

= n∫Z^nφ(Z)dZ = nE[Z^n],

where φ(Z) is the probability density function of a standard normal random variable Z. Therefore, we have shown that the expected value of Z raised to the power of n+1 is equal to n times the expected value of Z raised to the power of n.

(C) To find E[Z^4], we use the result from part (B). First, we have:

E[Z^2] = 1

because the variance of a standard normal random variable Z is equal to 1. Then, we have:

E[Z^4] = 3E[Z^2] = 3

because of the result from part (B) with n=2. Therefore, the fourth moment of a standard normal random variable Z is equal to 3.

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Answer:

Independent: the number of cups, c, that he sells

Dependent: the amount of money, m, that he makes each day

Step-by-step explanation:

* The independent variable determines the value of the dependent variable. The number of cups of frozen juice that Richard sells each day determines the amount of money that he makes each day.

* Side note: For your information, the linear equation that models this relationship would be m = 1.25 c. You would graph that as y = 1.25 x, and since x is independent while y is dependent, you know that c is independent and m is dependent.

* Good luck completing the table! I would help out with that if I could see it!

The transformations where an object will remain congruent with its transformation are:

When shapes are said to be congruent, or when a transformation is congruent with an object, it means that the objects have the same shape, the same size, and the same angles within.

There are only three transformations that lead a shape and its transformation to be congruent and they are translation, reflection, and rotation. They are therefore called the congruent transformations.

These transformations might change the orientation of the transformed shape, but it will still be the same size, shape, and have the same angles as the original.

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Answer:

2z+9

Step-by-step explanation:

(6z+2)+(7-4z)

Combine like term

6z-4z  + 2+7

2z+9

Answer:

A

Step-by-step explanation:

Answer:

The slope of the line on the graph is \(\frac{3}{2}\).

Step-by-step explanation:

The slope of a line can be found with \(\frac{\Delta y}{\Delta x}\). The points (3,2) and (-1,-4) lie on the line, so we can subtitute \(\Delta y = -4 -2 = -6\) and \(\Delta x = -1-3 = -4\) to see that the slope equals \(\frac{-6}{-4} = \frac{3}{2}\). This answer makes sense because the slope is going up when \(x\) becomes larger (the slope is positive), and we travel more in the \(y\)-direction than in the \(x\)-direction (the slope is greater than 1).

Answer:

=>1

=> \(\frac{-3}{-3}\)

=> Simplify:minus and minus simplify each other and so do 3 and 3

=> So were are left with 1

Thus,the answer is 1

Step-by-step explanation:

Answer:

\( \frac{9}{11} = \frac{x}{22} \\ \frac{9}{11} \times 22 = x \\ 2 ×9= x=18 \\ thank \: you\)

a) The initial population is \(N_0\) = 125 / \(e^{(2k)}\).

b) The exponential growth model for the bacteria population is N = \(N_0\) × \(e^{(kt)}\).

c) The number of bacteria after 8 hours is N = \(N_0\) × \(e^{(8k)}\).

d) After t = ln(25,000 / \(N_0\)) / k hours the bacteria count will be 25,000.

(a) To calculate the beginning population, we must first establish the bacterium population's exponential growth rate. Assume that the initial bacterial population is \(N_0\). The exponential growth model is given by:

N = \(N_0\) × \(e^{(kt)}\)

Where N is the number of bacteria at time t, \(N_0\) is the starting population, e is the natural logarithm base, k is the growth rate constant, and t is time in hours.

We have two data sets: N = 125 after two hours and N = 350 after four hours. We can solve using these two equations \(N_0\) and k.

(125) = \(N_0\) × \(e^{(2k)}\)

(350) = \(N_0\) × \(e^{(4k)}\)

Dividing the second equation by the first equation:

(350/125) = \(e^{(2k)}\)

Taking the natural logarithm of both sides:

ln(350/125) = 2k

Solving for k:

k = ln(350/125) / 2

Now that we have k, we can plug it into either equation and solve for it. \(N_0\):

\(N_0\) = 125 / \(e^{(2k)}\)

(b) The bacterium population's exponential growth model is:

N = \(N_0\) × \(e^{(kt)}\)

Where \(N_0\) = 125 / \(e^{(2k)}\) and k = ln(350/125) / 2

(c) To calculate the number of bacteria present after 8 hours, we use the exponential growth model with t = 8:

N = \(N_0\) × \(e^{(8k)}\)

(d) To calculate the time when the bacterium count reaches 25,000, enter N = 25,000 into the exponentially growing model and solve for t:

25,000 = \(N_0\) × \(e^{(kt)}\)

t = ln(25,000 / \(N_0\)) / k

However, in the absence of a specified growth rate constant (k) and starting population (\(N_0\)), we are unable to determine a precise value for t.

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The question is -

The number of bacteria in the culture is increasing according to the law of exponential growth. There are 125 bacteria in the culture after 2 hours and 350 bacteria after 4 hours.

(a) Find the initial population.

(b) Write an exponential growth model for the bacteria population. (Let t represent time in hours)

(c) Use the model to determine the number of bacteria after 8 hours.

(d) After how many hours will the bacteria count be 25,000?

To determine if a function crosses the horizontal asymptote, analyse the behavior of the function as it approaches the asymptote and on either side of it.

1. Identify the horizontal asymptote of the function. The horizontal asymptote is a horizontal line that the function approaches as the independent variable (usually denoted as x) goes to positive or negative infinity. It is often denoted by a horizontal line y = a, where "a" is a constant.

2. Examine the behavior of the function as x approaches positive infinity. Evaluate the limit of the function as x goes to positive infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. However, if the limit does not equal the asymptote, move to the next step.

3. Examine the behavior of the function as x approaches negative infinity. Evaluate the limit of the function as x goes to negative infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. If the limit does not equal the asymptote, proceed to the next step.

4. Investigate the behavior of the function around critical points or points where the function changes its behavior. These points may include the x-intercepts or vertical asymptotes. Determine if the function crosses the asymptote around these points by analyzing the behavior of the function in their vicinity.

If, at any point in this process, the function crosses the horizontal asymptote, then it does not have a true horizontal asymptote. However, if the function approaches the asymptote and does not cross it at any point, then it has a horizontal asymptote.

It's important to note that some functions may have multiple horizontal asymptotes or no horizontal asymptote at all. The steps outlined above are a general guideline, but the specific behavior of the function needs to be analyzed to make a conclusive determination.

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