Answer:
45%
Step-by-step explanation:
40 * .45 = 18
40-18 = 22
The percentage decrease of an item would be 45%.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
We can determine the value of the percentage decrease by the following formula,
percentage decrease = (initial value - reduced value) / initial value × 100%
As per the given question, we have
initial value = $40, and reduced value = $22
Substitute the values in the above formula, and we get
percentage decrease = (40 - 22) / 40 × 100%
percentage decrease = (18) / 40 × 100%
percentage decrease = 0.45 × 100%
Apply the multiplication operation, and we get
percentage decrease = 45%
Thus, the percentage decrease of an item would be 45%.
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A group of friends wants to go to the amusement park tey have no more than $115 to spend on parking and admission parking is $15 and the tickets cst $25 per person including tax wrote and solve an inequality which can be used to determine x the number of people who can go to the amuement park
An inequality which can be used to determine x the number of people who can go to the amusement park is: 15 + 25x ≤ 115
Also, approximately 4 people can go to the amusement park.
In the given question,
cost for admission parking = $15
Tickets = $25 per person
Let x be the number of people those who go to the amusement park.
On parking and admission spent not more than $115
So we get an inequality,
15 + 25x ≤ 115
We solve above inequality.
25x ≤ 115 - 15
25x ≤ 100
25x / 25 ≤ 100/25
x ≤ 4
This means that approximately 4people can go to the amusement park.
Therefore, an inequality which can be used to determine x the number of people who can go to the amusement park is: 15 + 25x ≤ 115
Also, approximately 4 people can go to the amusement park.
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HELP ASAP PLEASE!
The net for a triangular prism is shown below. What is the total surface area of the prism? 6.9 cm 8 cm 10 cm 8 cm 0 55.2 square centimeters 0 295.2 square centimeters 0 240 square centimeters 0 552 square centimeters
Answer:
Step-by-step explanation:
The area of each rectangle is Length x width
Therefore Area of rectagle is 8cm x 10 cm=
A= 80 cm 2
There are three rectangles with the same measure so multiply the area by 3
80cm squared x 3= 240 cm 2
Now find the are of the triangle:
A- 1/2 x base x height
Base = 8cm
Height = 6.9 cm
A= (1/2) (8cm) (6.9cm)
A= (1/2) (55.2 cm squared)
A= 27.6 cm squared
Since there are two triangle faces with the same dimensions take the area and multiply it by 2
27.6 cm squared times 2 = 55/2 cm squared
Now add up the area of the rectangles and the area of the triangles.
Rectangles= 240 cm squared
Triangles 55.2 cm squared
240cm sq + 55.2 cm sq.= 295.2 cm squared
2. Suppose the price of good x increased from 4 birr to 5 birr. Because of change price of good x, quantity demand of good y changed from 5,000 to 6,250. a. Find cross price elasticity of demand b. What types of goods (good x and good y) are?
Based on the cross-price elasticity of Demand, we can conclude that good X and good Y are substitutes.
Let's calculate the cross-price elasticity of demand using the given information:
a. Find the percentage change in quantity demanded of good Y:
Percentage Change in Quantity Demanded of Good Y = (New Quantity Demanded - Initial Quantity Demanded) / Initial Quantity Demanded * 100
Percentage Change in Quantity Demanded of Good Y = (6250 - 5000) / 5000 * 100 = 25%
b. Find the percentage change in the price of good X:
Percentage Change in Price of Good X = (New Price - Initial Price) / Initial Price * 100
Percentage Change in Price of Good X = (5 - 4) / 4 * 100 = 25%
Now, we can calculate the cross-price elasticity of demand:
Cross-Price Elasticity of Demand = Percentage Change in Quantity Demanded of Good Y / Percentage Change in Price of Good X
Cross-Price Elasticity of Demand = 25% / 25% = 1
b. Based on the calculated cross-price elasticity of demand, we can determine the types of goods:
If the cross-price elasticity of demand is positive (as in this case, where it is 1), it indicates that the two goods are substitutes. This means that when the price of good X increases, the quantity demanded of good Y also increases, suggesting that consumers view these goods as alternatives to each other.
Therefore, based on the cross-price elasticity of demand, we can conclude that good X and good Y are substitutes.
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Answer:
Step-by-step explanation:
OK for real this is a hard only verified experts can do this!!!!
The numeric value of the exponential expression in this problem is given by the following option:
A. 2^12.
How to obtain the numeric value of the exponential expression?The exponential expression for this problem is defined as follows:
8^x/2^y.
8 is the third power of 2, hence:
8 = 2^3.
When a term is elevated to two of it's powers, the powers are multiplied, hence:
(2^3)^x = 2^(3x).
Meaning that the exponential expression is then written as follows:
8^x/2^y = 2^(3x)/2^y.
When two terms of the same base and different exponents are divided, we keep the base and subtract the exponents, hence the expression is given as follows:
2^(3x)/2^y = 2^(3x - y).
As stated in the problem, the numeric value of the expression 3x - y is given as follows:
3x - y = 12.
Hence the entire expression is simplified as follows:
2^(3x - y) = 2^12.
Meaning that the correct option is given by option A.
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Answer:A. 2^12.
Step-by-step explanation:i did it and got it right
Find the measure of 3x-46+14=90
Answer:
Step-by-step explanation:
3x = 90 + 46 - 14
3x = 122
x=\(\frac{122}{3}\)≈40,7
Answer: 40.6 repeated
Step-by-step explanation: combine -46 and 14 which is -32. then add 32 to 90. then divide 3 on both sides. 122/3 is 40.6 repeated
Find the equation (in slope-intercept form) of the line with the given slope that passes through the point with the given coordinates.
Slope: 0
Ordered Pair: (-9,7)
The equation of the line woth slope 0 and passing through (-9,7) in slope-intercept form is y = 7.
If a line L has a slope M and it has the intercept c, then the equation of the line L can be written in the point slope form as,
L : y = Mx + c
This above equation of line is known as slope-intercept form of line.
Here, we have to find the equation of line which has slope m equal to zero and passing through (-9,7).
putting the known values in y = mx+c
y = (0)x+ c
y = c
Putting the value of y = 7
c = 7
Here, we have,
y = 7
So, the equation of the required line is y=7.
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A bag contains two red marbles, four green ones, one lavender one, two yellows, and two orange marbles. HINT [See Example 7.] How many sets of five marbles include either the lavender one or exactly one yellow one but not both colors?
There are 2518 sets of five marbles that include either the lavender one or exactly one yellow one, but not both.
To solve this problem, we need to find the number of sets of five marbles that include either the lavender one or exactly one yellow one, but not both colors. Here's one way to approach the problem:
Number of sets of five marbles that include the lavender one: There is only one lavender marble, so we can choose any 4 other marbles to go with it.
There are a total of 7 marbles to choose from, so there are 7 possible choices for the first marble, 6 for the second, 5 for the third, and 4 for the fourth.
This gives us a total of 7 x 6 x 5 x 4 = 840 possible sets of five marbles that include the lavender one.
Number of sets of five marbles that include exactly one yellow one: There are two yellow marbles,
So there are 2 possible choices for the yellow marble. For each choice, we can choose any 4 other marbles to go with it.
As before, there are 7 marbles to choose from, so there are 7 possible choices for the first marble, 6 for the second, 5 for the third, and 4 for the fourth.
This gives us a total of 2 x (7 x 6 x 5 x 4) = 1680 possible sets of five marbles that include exactly one yellow one.
Number of sets of five marbles that include both the lavender one and exactly one yellow one:
We need to subtract these sets from the total number of sets that include either the lavender one or exactly one yellow one.
We have already found that there are 840 sets of five marbles that include the lavender one, and 1680 that include exactly one yellow one.
To find the number of sets that include both, we can choose any one yellow marble and the lavender one.
There are 2 choices for the yellow marble and 1 choice for the lavender one,
So there are 2 x 1 = 2 possible sets of five marbles that include both the lavender one and exactly one yellow one.
Number of sets of five marbles that include either the lavender one or exactly one yellow one, but not both:
Finally, we need to subtract the number of sets that include both the lavender one and exactly one yellow one from the total number of sets that include either the lavender one or exactly one yellow one.
The total number of sets that include either the lavender one or exactly one yellow one is 840 + 1680 = 2520. The number of sets that include both is 2,
So the number of sets that include either the lavender one or exactly one yellow one, but not both, is 2520 - 2 = 2518.
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Identify the next number in the following sequence
25 49 97 ?
Select only one answer
- 124
- 171
- 139
- 193
Answer:
the correct answer is 193
Step-by-step explanation:
25×1-0=25
25×2-1=49
49×2-1=97
97×2-1=193
K
Each of the following three data sets represents the IQ scores of a random sample of adults. IQ
scores are known to have a mean and median of 100
105
105
111
105
111
102
106
91
99
99
109
99
109
111
115
112
Sample of Size 5
91
91
111
Sample of Size 12
888888 888
100
110
97
104
Sample of Size 30
91
111
113
113
108
113
108
91
118
110
Full data set o
101
109
101
109
91
97
95
CELES
m
For each data set, compute the mean and median
What is the mean of the sample of size 5?
(Type an integer or decimal rounded to one decimal place as needed
A 1.5 standard deviations above the mean IQ score is 122.5.
How do equations work?An expression that depicts the relationship between two or more numbers and variables is called an equation.
A dependent variable is one that depends on another variable, whereas an independent variable does not depend on any other variable for its value.
Giving the z score are:
z is calculated as (raw score - mean) / standard deviation.
with a standard deviation of 15 and a mean of 100. The z-score of 1.5 is equal to the IQ score that is 1.5 standard deviations above the mean, so:
1.5 = (x - 100)/15
x = 122.5
A 1.5 standard deviations above the mean IQ score is 122.5.
The Complete Question is IQ score.
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How do you solve -8>v-3?
Answer:
v < -5
Step-by-step explanation:
Add 3 to both sides. This gives -8+(-3)>v-3+3, or -5>v. Rewriting the inequality gives v < -5.
What is the surface area of this 3-D solid?
Answer:
I think its flat sorry if it's wrong
so this is a test that's due tomorrow and I don't understand anything (I'm probably gonna fail)
Answer:
20%
Step-by-step explanation:
760 over 950 is .8, so the difference is 20%
NO LINKS!! URGENT HELP PLEASE!!!
11. Write the equation for the graph
This is the same as writing y = sqrt(4(x+5)) - 1
===============================================
Explanation:
The given graph appears to be a square root function.
The marked points on the curve are:
(-4,1)(-1,3)(4,5)Reflect those points over the line y = x. This will have us swap the x and y coordinates.
(-4,1) becomes (1,-4)(-1,3) becomes (3,-1)(4,5) becomes (5,4)Recall the process of reflecting over y = x means we're looking at the inverse. The inverse of a square root function is a quadratic.
----------
Let's find the quadratic curve that passes through (1,-4), (3,-1) and (5,4).
Plug the coordinates of each point into the template y = ax^2+bx+c.
For instance, plug in x = 1 and y = -4 to get...
y = ax^2+bx+c
-4 = a*1^2+b*1+c
-4 = a+b+c
Do the same for (3,-1) and you should get the equation -1 = 9a+3b+c
Repeat for (5,4) and you should get 4 = 25a+5b+c
We have this system of equations
-4 = a+b+c-1 = 9a+3b+c4 = 25a+5b+cUse substitution, elimination, or a matrix to solve that system. I'll skip steps, but you should get (a,b,c) = (1/4, 1/2, -19/4) as the solution to that system.
In other words
a = 1/4, b = 1/2, c = -19/4
We go from y = ax^2+bx+c to y = (1/4)x^2+(1/2)x-19/4
----------
Next we complete the square
y = (1/4)x^2+(1/2)x-19/4
y = (1/4)( x^2+2x )-19/4
y = (1/4)( x^2+2x+0 )-19/4
y = (1/4)( x^2+2x+1-1 )-19/4
y = (1/4)( (x^2+2x+1)-1 )-19/4
y = (1/4)( (x+1)^2-1 )-19/4
y = (1/4)(x+1)^2- 1/4 - 19/4
y = (1/4)(x+1)^2 + (-1-19)/4
y = (1/4)(x+1)^2 - 20/4
y = (1/4)(x+1)^2 - 5
The equation is in vertex form with (-1,-5) as the vertex. It's the lowest point on this parabola. Placing it into vertex form allows us to find the inverse fairly quickly.
----------
The last batch of steps is to find the inverse.
Swap x and y. Then solve for y.
y = (1/4)(x+1)^2 - 5
x = (1/4)(y+1)^2 - 5
x+5 = (1/4)(y+1)^2
(1/4)(y+1)^2 = x+5
(y+1)^2 = 4(x+5)
y+1 = sqrt(4(x+5))
y = sqrt(4(x+5)) - 1
I'll let the student check each point to confirm they are on the curve y = sqrt(4(x+5)) - 1.
You can also use a tool like GeoGebra to verify the answer.
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 4 students' scores on the exam after completing the course: 12,7,13,11 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 3 of 4 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The 80% confidence interval for the average net change is (8.596, 12.904).
Critical value t=1.638.
Step-by-step explanation:
First, we calculate the mean and standard deviation of the sample:
\(M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{4}(12+7+13+11)\\\\\\M=\dfrac{43}{4}\\\\\\M=10.75\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{3}((12-10.75)^2+(7-10.75)^2+(13-10.75)^2+(11-10.75)^2)\\\\\\s=\dfrac{20.75}{3}\\\\\\s=6.92\\\\\\\)
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=10.75.
The sample size is N=4.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
\(s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.63}{\sqrt{4}}=\dfrac{2.63}{2}=1.315\)
The degrees of freedom for this sample size are:
\(df=n-1=4-1=3\)
The t-value for a 80% confidence interval and 3 degrees of freedom is t=1.638.
The margin of error (MOE) can be calculated as:
\(MOE=t\cdot s_M=1.638 \cdot 1.315=2.154\)
Then, the lower and upper bounds of the confidence interval are:
\(LL=M-t \cdot s_M = 10.75-2.154=8.596\\\\UL=M+t \cdot s_M = 10.75+2.154=12.904\)
The 80% confidence interval for the average net change is (8.596, 12.904).
4(5a + 3) = 20a + 12 represent which property of multiplication?
Answer:
Distributive property of multiplication
Step-by-step explanation:
The distributive property of multiplication is basically distributing the terms outside the bracket to all the terms inside the bracket. In this case, 4 is multiplied to 5a as well as 3.
A random sample is selected from a population with mean = 100 and standard deviation = 10. Determine the mean and standard deviation of the x sampling distribution for each of the following sample sizes. (Round the answers to three decimal places.)
If N=41
If N=130
The mean and standard deviation of the x sampling distribution for each of the following sample sizes will be \(N(100,10/\sqrt{41} ), N(100,10/\sqrt{130} )\).
What is the distribution of the sample mean for large samples?Suppose X has a distribution with mean \(\mu\) and standard deviation \(\sigma,\)then,
the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with a mean equal to the mean of X, and a standard deviation equal to \(\sigma/\sqrt{n}\)
Symbolically, we write it as:
\(X \sim N(\mu, \sigma) \implies \overline{X} \sim N(\mu,\sigma/\sqrt{n} )\)
A random sample is selected from a population with a mean = of 100 and a standard deviation = of 10.
The mean and standard deviation of the x sampling distribution for each of the following sample sizes.
If N=41
\(X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{41} )\)
If N=130
\(X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{130} )\)
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A density graph for all of the possible times from 50 seconds to 200 seconds
can be used to find which of the following?
OA. The probability of a time from 150 seconds to 250 seconds
OB. The probability of a time from 75 seconds to 250 seconds
OC. The probability of a time from 75 seconds to 150 seconds
OD. The probability of a time from 25 seconds to 150 seconds
The Probability of a time from 25 seconds to 150 seconds
To determine which option can be found using the given density graph, we need to understand the concept of probability and how it relates to a density graph.
A density graph represents the probability distribution of a continuous random variable. The area under the density graph within a specific interval corresponds to the probability of the variable falling within that interval.
Let's analyze the given options one by one:
OA. The probability of a time from 150 seconds to 250 seconds.
To find this probability, we need to determine the area under the density graph between 150 seconds and 250 seconds. However, the given density graph only provides information from 50 seconds to 200 seconds, so we cannot accurately determine the probability for this interval. Therefore, option OA cannot be found using the given graph.
OB. The probability of a time from 75 seconds to 250 seconds.
Again, to find this probability, we need to calculate the area under the density graph between 75 seconds and 250 seconds. Since the given density graph only covers up to 200 seconds, we cannot accurately determine the probability for this interval. Thus, option OB cannot be found using the given graph.
OC. The probability of a time from 75 seconds to 150 seconds.
Now, we can determine the probability for this interval by calculating the area under the density graph between 75 seconds and 150 seconds. As long as this interval falls within the range covered by the graph (50 seconds to 200 seconds), we can accurately find the probability for it. Therefore, option OC can be determined using the given graph.
OD. The probability of a time from 25 seconds to 150 seconds.
Since the density graph only covers the range from 50 seconds to 200 seconds, we cannot determine the probability for an interval starting at 25 seconds. Therefore, option OD cannot be found using the given graph.
In conclusion, based on the information provided, option OC (the probability of a time from 75 seconds to 150 seconds) can be determined using the given density graph.
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50 Points! Multiple choice algebra question. Photo attached. Thank you!
The angle θ = 90° is not a solution to trigonometric equation sin 2θ = 1. (Right choice: A)
How to solve a trigonometric equation
In this problem we must determine what angle is not a solution of a given trigonometric equation. The solution set is found by means of algebra properties and trigonometric formulas:
sin 2θ = 1
2θ = 90° + 360° · i, where i is a whole number.
θ = 45° + 180° · i
According to this expression, θ₁ = 45°, θ₂ = 225° and θ₃ = - 135° are solutions to this equation. θ = 90° is not a solution of sin 2θ = 1.
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The table shows the age of a painting (x) in years, and its estimated dollar value (y).
A 4-column table with 6 rows. Column 1 is labeled x with entries 50, 54, 62, 65, 68, sigma-summation x = 299. Column 2 is labeled y with entries 1,200, 1,500, 2,400, 3,200, 4,100, sigma-summation y = 12,400. Column 3 is labeled x squared with entries 2,500, 2,916, 3,844, 4,225, 4,624, sigma-summation x squared = 18,109. Column 4 is labeled x y with entries 60,000, 81,000, 148,800, 208,000, 278,800, sigma-summation x y = 776,600.
Which regression equation correctly models the data?
y = 41.47x + 0.09
y = 41.47x + 1,279.93
y = 153.32x – 6,688.54
y = 153.32x – 6,325.76
Regression equation correctly models the data is: y = -43.98x + 1,279.93
To determine the regression equation that correctly models the data, we can use the method of linear regression. The regression equation for a straight line is generally expressed as y = mx + b, where m is the slope and b is the y-intercept.
Using the given table, we can calculate the necessary values to determine the regression equation. Let's denote the sigma notation as Σ.
The slope (m) can be calculated using the formula:
\(m = (Σxy - (Σx)(Σy) / n(Σx^2) - (Σx)^2)\)
Plugging in the values from the table:
m =\((776,600 - (299)(12,400) / 6(18,109) - (299)^2)\)
m = (776,600 - 3,708,800 / 6(18,109) - 89,401)
m = (-2,932,200 / 66,654)
m ≈ -43.98
The y-intercept (b) can be calculated using the formula:
b = (Σy - m(Σx)) / n
Plugging in the values from the table:
b = (12,400 - (-43.98)(299)) / 6
b ≈ 1,279.93
The correct regression equation that models the data is:
y = -43.98x + 1,279.93
Out of the given options, the correct regression equation is:
y = -43.98x + 1,279.93
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Hubble's constant H is about 70 km/sec per megaparsec. (The prefix "mega" means million.) Convert this value for Hubble's constant to km/s/million LY. Hint: -A parsec is 3.26 light-years, and therefore a megaparsec is 3.26 million LY. If you take the given value of the Hubble constant (namely, 70 km/s per megaparsec) and replace the megaparsec with 3.26 million LY, then you will have converted to the desired units.
Hubble's constant in units of km/s/million LY is approximately 21.47.
what is approximately ?
Approximately means close to or nearly, but not exactly. It is used to indicate that a value or number is an estimation or approximation, rather than an exact value. It is often used when a precise value is not necessary or when the exact value is unknown or difficult to determine.
In the given question,
To convert Hubble's constant from km/s/Mpc to km/s/million LY, we need to multiply it by a conversion factor that accounts for the difference in distance units. We can use the fact that 1 Mpc is equal to 3.26 million LY:
1 Mpc = 3.26 million LY
Therefore, to convert Hubble's constant from km/s/Mpc to km/s/million LY, we can use the following conversion factor:
1 Mpc / 3.26 million LY
Multiplying Hubble's constant by this conversion factor gives:
H = 70 km/s/Mpc x (1 Mpc / 3.26 million LY) = 21.47 km/s/million LY
Therefore, Hubble's constant in units of km/s/million LY is approximately 21.47.
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answer the question correctly for brainliest
Answer:
15p + 10
Step-by-step explanation:
5 (3p+2)
15p + 10
f(x) = 12x+5 find f(11)
Answer:
f(11)= 12x+5=137
Step-by-step explanation:
Multiply 12 times 11 to get 132 then add 5 and you get 137 :)
5432
-2
X
Which linear inequality is represented by the graph?
Oy< ²x + 3
Oy> ²x+3
Oy> ²x + 3
Oy< ²x + 3
Help please
The graph of an inequality in two variables is the set of points that represents all solutions to the inequality.
How do you find the linear inequality of a graph?The boundary line that separates the coordinate plane into two halves by a linear inequality represents the solutions to the inequality in one half. For > and, the border line is solid, and for and, it is dashed.
To determine the equation governing the inequality line, enter your slope and a point into the formula y = mx + B, where "m" denotes the slope, "x, y" denotes a point on the line, and "b" is the y-intercept. By inserting (0, 0), you get 0 = 0 + b, which equals 0.
When you rewrite the equation, you get y = x/2. The linear inequality x - 5 > 3x - 10 is an illustration. Due to the greater than symbol being utilised in this inequality, the LHS is clearly greater than the RHS.
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The signal from a certain satellite takes approximately 0.0029 seconds to reach earth. Write this number in a scientific notation
Given:
The signal from a certain satellite takes approximately 0.0029 seconds to reach earth.
we will write the number in a scientific notation
The scientific notation is the number that is between 1 and 9 multiplied by 10 raised to an exponent
So, the given number will be:
\(0.0029=\frac{29}{10000}=\frac{29}{10}\times\frac{1}{1000}=2.9\times10^{-3}\)Look below for problem
Answer:
Step-by-step explanation:
(3x^2 + 2x) + (-x + 9) Remove the brackets
3x^2 + 2x - x + 9 Watch out for the sign in front of the x
3x^2 + x + 9 No more reduction can take place.
(-2x^2 + 5x - 7) + (3x + 7) Remove the brackets
-2x^2 + 5x - 7 + 3x + 7
-2x^2 + 5x + 3x - 7 + 7 Combine
-2x^2 + 8x The 7s cancel -- they are of opposite signs.
No more reduction can take place. The powers on the variables have to be equal before any cancelation can take place.
PLEASE HELP ME ANSWER THIS PROBLEM
Answer:
9
Step-by-step explanation:
because 3*4=12 then divide 108 by 12 giving you 9
Which of the following equations are equivalent? Select three options. 2 + x = 5 x + 1 = 4 9 + x = 6 x + (negative 4) = 7 Negative 5 + x = negative 2
The three equivalent equations are 2 + x = 5, x + 1 = 4 and -5 + x = -2. So, correct options are A, B and E.
Two equations are considered equivalent if they have the same solution set. In other words, if we solve both equations, we should get the same value for the variable.
To determine which of the given equations are equivalent, we need to solve them for x and see if they have the same solution.
Let's start with the first equation:
2 + x = 5
Subtract 2 from both sides:
x = 3
Now let's move on to the second equation:
x + 1 = 4
Subtract 1 from both sides:
x = 3
Notice that we got the same value of x for both equations, so they are equivalent.
Next, let's look at the third equation:
9 + x = 6
Subtract 9 from both sides:
x = -3
Since this value of x is different from the previous two equations, we can conclude that it is not equivalent to them.
Now, let's move on to the fourth equation:
x + (-4) = 7
Add 4 to both sides:
x = 11
This value of x is also different from the first two equations, so it is not equivalent to them.
Finally, let's look at the fifth equation:
-5 + x = -2
Add 5 to both sides:
x = 3
Notice that we got the same value of x as the first two equations, so this equation is also equivalent to them.
So, correct options are A, B and E.
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Complete question is:
Which of the following equations are equivalent? Select three options.
2 + x = 5
x + 1 = 4
9 + x = 6
x + (- 4) = 7
- 5 + x = - 2
please answer this question
Answer:
-1/2arctan(x) - 1/4ln|x + 1| + 1/4ln|x - 1| + C
Step-by-step explanation:
Write the income equation for a small business that begins with $150 and grows by 20% each year. When wil the company's income income be $300?
Answer:
f(x)=150+30x
150+30x=300
30x=150
x=5
after 5 years
0.9t
t² + 64
Find the time
The concentration of a drug t hours after being injected is given by C(t) =
when the concentration is at a maximum. Give your answer accurate to at least 2 decimal places.
hours.
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