The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are ten
centimeters thick. Suppose a submarine is at a depth of 1,000 meters. The weight of water above each square
meter of the submarine is 9,800,000 newtons.
a. What is the pressure? Find the pressure here and show your work! TYPE IN WHAT YOU PUT IN
YOUR CALCULATORSI
Answers
Answer:
9800000N/m²
Explanation:
Given parameters:
Depth of the submarine = 1000m
Weight of the water above = 9,800,000N per unit area
Unknown:
Pressure = ?
Solution:
The pressure at this depth is the force or weight per unit area.
Pressure = \(\frac{Force }{Area}\)
Pressure = \(\frac{9800000}{1}\)
Pressure = 9800000N/m²
Related Questions
Which of the following statements are true of thermal energy and kinetic
energy?
Check all that apply.
A. All the molecules or atoms in motion have kinetic energy.
B. Each molecule or atom in motion has kinetic energy.
C. Each molecule or atom in motion has thermal energy.
D. All the molecules or atoms in motion have thermal energy
Answers
Answer:
a
all the molecules or atoms in motion has kinetic energy
the period of time that we can place a spacecraft into a specified orbit from a specific site is called a:
Answers
The period of time that we can place a spacecraft into a specified orbit from a specific site is called a launch window. A launch window is a specific time period during which a spacecraft can be launched and successfully placed into its desired orbit.
This time period is determined by a variety of factors, including the position of the spacecraft, the position of the target destination, and the performance of the spacecraft's propulsion system. Launch windows can be very narrow, sometimes only a few minutes long, and must be carefully calculated to ensure the spacecraft reaches its destination on time and within budget.
The ability to accurately predict launch windows is critical to the success of space missions, as missing a launch window can result in significant delays and additional costs.
To know more about spacecraft visit:
brainly.com/question/8003060
#SPJ11
PLEASE HURRY Which of the following measurements is a measurement of velocity?
A) 125 cm/s
B) 30 km/h NW
C) 350 m/s N
D) 520 km/h
Answers
Answer:
C) 350 m/s N
Explanation:
Velocity is measured in miles per hour or metres per second.
a 10-h inductor carries a current of 20 a. which current would induce a 50-v emf across it?
Answers
We have a 10 H inductor carrying a current of 20 A. No current would induce a 50 V EMF across the current-carrying inductor.
we need to use Faraday's Law, which states that a change in magnetic flux through a coil induces an electromotive force (EMF) in the coil. The EMF induced is proportional to the rate of change of magnetic flux through the coil.
In this case, we have a 10 H inductor carrying a current of 20 A. We need to find the current that would induce a 50 V EMF across the inductor.
First, we need to calculate the magnetic flux through the inductor. The magnetic flux through a coil is given by the product of the number of turns in the coil, the current through the coil, and the inductance of the coil.
In this case, the number of turns and the inductance are given, so we can calculate the magnetic flux:
Flux = L x I = 10 H x 20 A = 200 Wb
Now we can use Faraday's Law to find the current that would induce a 50 V EMF across the inductor:
EMF = -N x dFlux/dt
where N is the number of turns in the coil.
Since the inductor is not changing, dFlux/dt is zero. Therefore, the induced EMF is zero.
In summary, no current would induce a 50 V EMF across the current-carrying inductor.
To know more about current visit :
https://brainly.com/question/16418638
#SPJ11
What is the relationship between frictional force and the normal force
Answers
Answer: Frictional force is when it happens on purpose and normal force is when it happens normal and you are not trying to make it happen on purpose.
Explanation: friction happens on purpose and sometimes you can't control friction but friction is an important thing.
A solution containing 3.4 moles of pl3 and one l water
Answers
Answer:
c
Explanation:
c
what is the relationship between force and acceleration
Answers
An airplane flies with a constant speed of 620 miles per hour. How far can it travel
in 1/2 hour?
Answers
Answer:
310 miles
Explanation:
If an airplane can travel 620 miles in one hour, then to find how far it traveled in half of an hour, divide 620 by 2 (or multiply by 1/2).
620/2= 310 miles in 1/2 of an hour
how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answers
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
If the acceleration remains constant and the mass decreases by 5, the force required will ____ by _____
Answers
Answer:
The force will be decreased by 5
Explanation:
How much charge is contained in 1 nm of DNA? a. 2 qe b. 6.67 qe c. 0.3 qe d. 1.6x10^19 qe
Answers
3 qe charge is contained in 1 nm of DNA. DNA is negatively charged, therefore, when an electric current is applied to the gel, DNA will migrate towards the positively charged electrode.
What is the charge of an DNA?Deoxyribonucleic acid, or DNA, is a hereditary substance that may be found in all living things, including plants, animals, birds, mammals, and humans, as well as in unicellular amoebas.
Both prokaryotic and eukaryotic cells include the chemical substance DNA, also known as deoxyribonucleic acid, which has a special molecular structure. Nucleotide molecules make up these hereditary components.
A Swiss biologist named Johannes Friedrich Miescher first recognised and discovered DNA in 1869 while studying white blood cells.
James Watson and Francis Crick later revealed that DNA molecules have a double helix structure, which further demonstrated that DNA molecules are primarily responsible for gathering and retaining genetic information in all living species.
To learn more about DNA refer to:
https://brainly.com/question/16099437
#SPJ4
Which conclusion, based on measurements of the ball in the lab in this lesson, is correct? a. The density of the ball was 1.48 g/cm3, so it was made of synthetic or manufactured rubber. b. The density of the ball was 1.23 g/cm3, so it was made of Neoprene rubber. c. The density of the ball was 1.48 g/cm3, so it was made of natural rubber. d. The density of the ball was 0.90 g/cm3, so it was made of gum rubber.
Answers
Option a: The density of the ball was 1.48 g/cm3, so it was made of synthetic or manufactured rubber.
Since the ball has density of 1.48g/cm3 which means that the ball was typically made of synthetic material indicating that the balls is not from the Maya civilization .
Maya civilization ball is made up of natural rubber which inturn means that the ball tend to last longer and spin faster than those made of synthetic material.
Hence, The conclusion Based on the measurements of the ball in the lab i is a. The density of the ball was 1.48 g/cm3, so it was made of synthetic or manufactured rubber.
Learn more here:
https://brainly.com/question/12707959
A bike accelerates from 0.0 m/s to 4.0 m/s in
4 s. What distance does it travel?
Answers
Answer:
d = 8 m
Explanation:
Given that,
Initial speed, u = 0
Final speed, v = 4 m/s
Time, t = 4 s
We need to find the distance traveled by a bike. Let it is equal to d. Using second equation of kinematics as follows :
\(d=ut+\dfrac{1}{2}at^2\\\\\text{a=acceleration of bike and u = 0}\\\\d=\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\d=\dfrac{(v-u)t}{2}\\\\d=\dfrac{(4-0)4}{2}\\\\d=8\ m\)
So, the car cover a distance of 8 m.
The bike will travel the distance of 8 m during the given time interval.
Given data:
The initial speed of bike is, u = 0.0 m/s.
The final speed of bike is, v = 4.0 m/s.
The time interval is, t = 4 s.
In given problem, we need to obtain the magnitude of acceleration first. Then we can use this value in the third kinematic equation of motion, to find the distance covered by bike.
Then by first kinematic equation of motion,
v = u + at
Solving as,
4.0 = 0 + a(4)
a = 1 m/s²
Now, we can use the third kinematic equation of motion to find the distance travelled as,
\(v^{2}=u^{2}+2as\)
Solving as,
\(4.0^{2}=0^{2}+2(1)s\\\\16 = 2s\\\\s = 8\;\rm m\)
Thus, we can conclude that the bike will travel the distance of 8 m during the given time interval.
Learn more about the kinematic equation of motion here:
https://brainly.com/question/13202575
True or False
1)All forces cause a change in an object’s speed and direction.
Answers
Answer:
True
Explanation:
Answer and Explanation:
True I believe bc if you put a certain amount of force on an object it'll move and depending on where you place the force on the object it'll move in that direction. How much force and how much weight the object has will determine the speed...
which two changes would decrease the dencity of ocean water
Answers
The two changes that would decrease the density of ocean water are increasing its temperature and Decreasing it's salinity.
What is density?
Density is a measure of how much mass is contained in a given unit of volume. It is usually expressed in g/cm3 or kg/m3. It is a measure of how tightly the molecules of a substance are packed together. Density is an important physical property of a material because it affects how it interacts with other materials, how it behaves under different conditions, and how it is affected by forces such as gravity.
The density of seawater is determined by its temperature and salinity. As the temperature of seawater increases, the density of the water decreases. This is because the molecules of water expand and move farther apart as they are heated, resulting in a decrease in the mass per unit volume of water. Similarly, as the salinity of seawater decreases, the density of the water also decreases. This is because the salt in seawater increases the mass per unit volume of water, making the water denser. If the amount of salt in the water decreases, then the water will be less dense.
Therefore, increasing its temperature and Decreasing it's salinity decrease the density of ocean water.
To learn more about density from the link
https://brainly.com/question/29775886
#SPJ1
Q2. A stone leaves a slingshot horizontally with an initial speed of 15.2 m/s from a
height 1.1 m above the ground. Determine the stone's:
a) total air time
b) maximum height
c) range
d) final velocity
Horizontal
VX =
dx = ?
t = ?
Vertical
dy = -1.1m
v1y =
v2y= ?
a =
t = ?
Answers
Answer:
Assume that \(g = 9.81\; {\rm m\cdot s^{-2}}\). Also assume that that the air resistance on this stone is negligible.
The total air time of this stone is approximately \(1.5\; {\rm s}\).
The maximum height of this stone is \(1.1\; {\rm m}\), same as the height of the slingshot.
The range of this stone is approximately \(23\; {\rm m}\).
The final velocity of this stone is approximately \(21\; {\rm m \cdot s^{-1}}\).
Explanation:
If the air resistance on this stone is negligible, this stone will accelerate towards the ground with a vertical acceleration \(a_{y}\) of \(a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\).
At the same time, the horizontal velocity \(v_{x}\) of this stone will stay the same during the entire flight: \(v_{x} = 15.2\; {\rm m\cdot s^{-1}}\).
The stone was launched from a height of \(1.1\; {\rm m}\) above the ground. Therefore, the vertical displacement \(x_{y}\) of the stone will be \(x_{y} = (-1.1)\; {\rm m}\) when the stone hits the ground.
The initial vertical velocity \(u_{y}\) of this stone would be \(u_{y} = 0\; {\rm m\cdot s^{-1}}\) since the stone was launched horizontally.
Let \(v_{y}\) denote the final vertical velocity of this stone right before landing. Apply the SUVAT equation \((v_{y})^{2} - (u_{y})^{2} = 2\, a\, x\) to find \(v_{y}\!\):
\((v_{y})^{2} - (u_{y})^{2} = 2\, a\, x\).
\((v_{y})^{2} = (u_{y})^{2} + 2\, a\, x\).
\(\begin{aligned}v_{y} &= -\sqrt{(u_{y})^{2} + 2\, a\, x} \\ &= -\sqrt{0^{2} + 2\, (-9.81) \, (-1.1)}\; {\rm m\cdot s^{-1}} \\ &\approx -14.6908 \end{aligned}\).
(Final vertical velocity \(v_{y}\) is negative since the stone is travelling downwards toward the ground.)
Let \(t\) denote the duration of this flight. Apply the SUVAT equation \(t = (v_{y} - u_{y}) / (a)\) to find \(t\!\):
\(\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-14.6908) - 0}{(-9.81)}\; {\rm s} \\ &\approx 1.49753\; {\rm s} \end{aligned}\).
In other words, this stone was in the air for approximately \(1.5\; {\rm s}\).
Also because the stone was launched horizontally, the vertical velocity of this stone started at \(u_{y} = 0\; {\rm m\cdot s^{-1}}\) and became negative (toward the ground) immediately after.
Hence, this stone would not have travelled upward during the entire flight. The height of this stone would be maximized immediately after the stone was launched: \(1.1\; {\rm m}\).
Multiple the horizontal velocity \(v_{x} = 15.2\; {\rm m\cdot s^{-1}}\) of this stone by the duration of the flight \(t \approx 1.49753\; {\rm s}\) to find the range (horizontal displacement) of this stone:
\(\begin{aligned} (\text{range}) &= v_{x}\, t \\ &\approx (15.2\; {\rm m\cdot s^{-1}})\, (1.49753\; {\rm s}) \\ &\approx 23\; {\rm m} \end{aligned}\).
Right before landing, the stone would be travelling with a vertical velocity of \(v_{y} \approx (-14.6908)\; {\rm m\cdot s^{-1}}\) and a horizontal velocity of \(v_{x} = 15.2\; {\rm m\cdot s^{-1}}\). Apply the Pythagorean Theorem to find the overall velocity of this stone at that moment:
\(\begin{aligned} v &= \sqrt{{(v_{x})}^{2}\, {(v_{y})^{2}} \\ &\approx \sqrt{(15.2\; {\rm m\cdot s^{-1})^{2} + (-14.6908)^{2}}\; {\rm m\cdot s^{-1}} \\ &\approx 21\; {\rm m\cdot s^{-1}} \end{aligned}\).
Which one of the following statements is false?
Select one:
a. Air resistance and friction both oppose an object's motion
b. Friction opposes motion and can be reduced with lubrication
c. Air resistance is greater the faster the object is travelling
d. Air resistance only occurs when the wind is blowing
e. To keep a boat moving a driving force is needed to overcome water resistance
Answers
The statement which is false is as follows:
Air resistance only occurs when the wind is blowing.Thus, the correct option for this question is D.
What is Friction?Friction may be defined as a type of force that resists the sliding or rolling of one solid object over another through the surface that acts on it.
Friction is a force that takes place as the resistance of motion when one object rubs over another. Friction force always opposes the motion along with air resistance.
Friction can also be somehow reduced with the impact of lubrication over the rubbing surface. It is true that air resistance is greater the faster the object is traveling.
Air resistance does not depend on the blowing of the wind. It does not mean that if there is no wind blowing, the air resistance is negligible.
Therefore, the correct option for this question is D.
To learn more about Frictional force, refer to the link:
https://brainly.com/question/23161460
#SPJ6
what is acceleration time-graph and velocity time-graph
Answers
Answer:
The acceleration time graph is the graph that is used to determine the change in velocity in the given interval of the time. ... The acceleration time graph is used to find the change in the velocity of the moving object for the given period of time and this can be determined by finding the area under the curve
Explanation:
A rock is thrown horizontally from the top of a 494.9 m high cliff on Earth near sea level with an initial velocity of 27.6. The ground below the cliff is level. How long, in seconds, will it take the rock to hit the ground below the cliff? Enter your answer at least to the nearest tenth of a second, but do not include units in your answer.
Answers
Answer:
Time 10.0 s
Explanation:
Given:
H = 494.9 m
V = 27.6 m/s
g = 9.8 m/s²
___________
t - ?
The fall time is found from the formula:
H = g·t² / 2
t = √ (2·H / g) = √ (2·494.9 / 9.8 ) ≈ 10.0 s
Attention! An extra given is speed. Find the distance from the base of the rock to the point where the stone fell:
L = V·t = 27.6·10.0 = 276 m
the emotion that occurs more often to more drivers is
Answers
The emotion that occurs more often to more drivers is frustration.
What is frustration? Frustration is a feeling of dissatisfaction, displeasure, and discontent that arises as a result of an inability to fulfill a need or a goal. In driving, frustration is a common emotional state that occurs when a person is prevented from driving at their preferred pace, or when a person experiences unexpected events while driving, such as traffic jams or sudden accidents. Frustration may be caused by a variety of factors, including:
Driving conditions: Poor weather conditions or heavy traffic, for example, can be stressful and frustrating for drivers.Road rage: Aggressive driving, tailgating, and other reckless behavior on the road may contribute to frustration in other drivers.Inattention: Drivers who are distracted or preoccupied may become frustrated and irritated more easily, particularly when they encounter unexpected situations.Inconvenience: Road construction, detours, and other delays can cause frustration in drivers who are in a hurry to reach their destination.Learn more about emotions: https://brainly.com/question/6450214
#SPJ11
Imagine you are an astronomer who recently discovered a new planet orbiting a distant star.
Which set of characteristics would you use to classify this planet as an inner or terrestrial planet? Check all that apply.
D dense and solid
D- very large
O thick atmosphere containing hydrogen and helium
D lacking a solid surface
D located near a star
Answers
Answer:
I think its dense and solid and located near a star.
Explanation:
Hope this helps, good luck.
a sound wave can cause the particles in a medium to vibrate slowly or quickly what is this rate of vibration called?
a. compression
b. wavelenght
c. frequency
d. amplitude
Answers
Answer:
FREQUENCY
Explanation:
Answer: C:frequency
the rate of the vibration is called frequency
Why do you think plants surround the seeds with a yummy fruit?
Answers
Answer:Cross-pollination is two plants that work together to pollinate and self-pollinate is when a flower pollinates itself. ... Why do you think plants surround the seeds with a yummy fruit? To protect the seeds so that they can reproduce. How is cross-pollination different from self-pollination?
Explanation:
Plants seeds and fruits are the outcome of fertilization.Gymnosperms and angiosperms both produce seeds.
What is cross-pollionation?Cross-pollination, also known as heterogamy, is a form of pollination in which egg cells pollen are transmitted from one soil's cones or flowers to another's omelette cones or flowers.
Cross-pollination occurs in both angiosperms and gymnospermsand it aids in cross-fertilization and outbreeding.
Plants seeds and fruits are the outcome of fertilization..Gymnosperms and angiosperms both produce seeds.
In angiosperms, the ovary develops into the fruit, while the ovules grow into the seeds that are encased within the fruit.Gymnosperms and angiosperms both produce seeds.
Hence plants seeds and fruits are the outcome of fertilization.Gymnosperms and angiosperms both produce seeds.
To learn more aboutv the cross-pollionation refer to the link;
https://brainly.com/question/21076663
What is the maximum speed at which a car can safely travel around a circular track of radius 142 meters if the coefficient of friction between the tires and the road is 1.07? Include units in your answer. Answer must be in 3 significant digits.
Answers
Given that the radius of the circular path is r = 142 m and the coefficient of the friction is
\(\mu=1.07\)The condition for the car to travel safely is
Frictional force = centrifugal force
\(\mu mg=\frac{mv^2}{r}\)Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
\(\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}\)A uniform stick has a mass of 4.42 kg and a length of 1.23 m. It is initially lying flat at rest on a frictionless horizontal surface and is struck perpendicularly by a puck imparting a horizontal impulsive force of impulse 12.8 N s at a distance of 46.4 cm from the center. Determine the subsequent motion of the stick.
Answers
10.7 rad/s is the final angular velocity of the stick.
Given:
Mass of the stick = 4.42 kg
Length of the stick = 1.23m
Force of impulse (I) = 12.8 N s
The linear velocity of the stick, \(v=\frac{I}{m}\)
\(v=\frac{12.8 N.s (\frac{1 kg m/s^2}{1 N}) }{4.42 kg}\)
\(v\) \(= 2.89 m/s\)
Therefore, the final linear velocity of the stick is 2.89 m/s
∴\(w=\frac{12 Ir}{ml^{2} }\)
\(w=\frac{12 ( 12.8 N.s ) ( 46.4 cm)}{(4.42 kg) (1.23 m)^2}\)
\(w= \frac{12 (12.8 N.s) (46.4 cm) (\frac{10^-^2 m}{1 cm} )}{(4.42 kg) (1.23m)2}\)
\(w=10.7 rad/s\)
Therefore, 10.7 rad/s is the final angular velocity of the stick.
Learn more about linear velocity here:
https://brainly.com/question/15154527
#SPJ4
1.) Is it possible for an object to move in a direction that is different from the direction of the net force acting on the object? (an example would be much appreciated).
Answers
Answer:
No,unless the force is balanced and the object doesn't move .
An object completes 2500 cycles in
26s. The radius of motion is 3.5m.
Answers
Answer:
That statement is correct.
Explanation:
An object that completes 2500 cycles in 26 seconds has a radius of motion of 3.5.
estimate the added power (in hp) required for the car when the cartop carrier is used and the car is driven at 100 km/h in a 25 km/h headwind over that required when the carrier is not used in the same conditions.
Answers
Approximately 10-20 hp of added power is required when using a cartop carrier and driving at 100 km/h in a 25 km/h headwind, compared to not using the carrier in the same conditions.
The added power required when using a cartop carrier and driving at 100 km/h in a 25 km/h headwind is due to the increased drag on the car caused by the carrier and the wind. The exact amount of added power required will depend on the size and shape of the carrier, as well as the specific car and engine being used. However, estimates suggest that this added power could be in the range of 10-20 hp. It is important to note that using a cartop carrier can also impact the handling and stability of the car, so it is important to follow the manufacturer's instructions and drive with caution.
Learn more about required here:
https://brainly.com/question/4130932
#SPJ11
If the distance of a force arm (FA) is 4 feet and the resistance arm (RA) is 2 feet, then the mechanical advantage would be
Answers
Answer: 2
Explanation:
From the question, we are informed that the distance of a force arm (FA) is 4 feet and the resistance arm (RA) is 2 feet.
Based on the information given, the mechanical advantage would be calculated as:
= Force Arm / Resistance Arm
= 4 feet / 2 feet
= 2
Using the diagram, what season is it in the northern hemisphere?
OWinter
OSummer
OAutumn (fall)
O Spring
Answers
Summer
Fall
Spring
I would go with winter