The patient is a 73-yr-old Caucasian male with fair skin who has had 3 melanomas removed in the
past 2 years. He is a self-confessed beach bum since his youth. The mole is located on his right shoulder and is 7 mm in diameter. what could be a solution

Answers

Answer 1

Patients frequently use the word "cope" to describe how they cope with and handle a melanoma diagnosis.

What is the most efficient melanoma treatment?

Surgery. The main course of treatment for melanoma in all stages is surgery to remove the tumour.

The melanoma and some of the surrounding healthy tissue are removed using a broad local excision.

Which type of skin cancer is least frequent yet responsible for the majority of deaths due to skin cancer?

Melanoma, the rarest type of skin cancer, kills more people each year than basal cell and squamous cell cancers combined. Melanoma may also be more difficult to control and more prone to spread

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Related Questions

What is sound waves

Answers

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Characteristics of sound waves

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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e.) calculate the total heat required to change 10kg of ice at 0°c into water at 50°c. ​

Answers

Answer:

the heat change to 10kg of ice to water 0

so quantity of heat required is answer: 5460 J.

hope its helps!

Answer:

Q=ml+mc∆+ml'

=10*80+10*1*(100-0)+10*540

=800+1000+5400

=7200cal.7.2kcel

L=heat of fusion of ice

L'=heat of vapourisation of water

the weight of an object is measured in air to be 7N the object is then immersed in water and its apparent weight is measured to be 4N determined the buoyant force and state whether or not the object float

Answers

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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A point charge q1 has a magnitude of 3.5x10-6 C. A second charge q2 has a magnitude of -1.8x10-6 C and is located 0.15 m from the first charge. Determine the electrostatic force exerts on each other.

Answers

The electrostatic force exerts on each other is 1.134 N

Electrostatic force calculation.

The electrostatic force between the two charges is given by Coulomb's Law:

F = k * |q1| * |q2| / r^2

where k is the Coulomb constant (9.0 x 10^9 N*m^2/C^2), |q1| and |q2| are the magnitudes of the two charges, and r is the distance between them.

Substituting the given values, we have:

F = (9.0 x 10^9 N*m^2/C^2) * (3.5 x 10^-6 C) * (1.8 x 10^-6 C) / (0.15 m)^2

F = 1.134 N

The electrostatic force exerted on each charge is equal in magnitude but opposite in direction, according to Newton's Third Law. Therefore, the magnitude of the force on each charge is 1.134 N, but they point in opposite directions. The force on q1 is attractive (toward q2), while the force on q2 is repulsive (away from q1).

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Learning Goal:To understand and be able to use the rules for determining allowable orbital angular momentum states.Several numbers are necessary to describe the states available to an electron in the hydrogen atom. The principal quantum number ndetermines the energy of the electron. The orbital quantum number l determines the total angular momentum of the electron, and the magnetic quantum number mldetermines the component of the angular momentum parallel to a specific axis, usually the z axis.For a given principal quantum number n, the orbital quantum number can take integer values ranging from zero to n−1. For a given orbital quantum number l, the magnetic quantum number can take integer values from −l to l. A fourth number, the spin ms, is important for interactions with magnetic fields and counting states. The spin can be either +1/2 or −1/2, independent of the values of the other quantum numbers.The energy of an electron in hydrogen is related to the principal quantum number by En=(−13.60eV)/n2. The orbital angular momentum is related to the orbital quantum number by L=ℏl(l+1)−−−−−−√, and the orbital angular momentum in the z direction is related to the magnetic quantum number by Lz=mlℏ.
A. How many different values of I are possible for an electron with principal quantum number n = 5?
B. How many values of mi are possible for an electron with orbital quantum number I = 3? Express your answer as an integer.
C. The quantum state of a particle can be specified by giving a complete set of quantum numbers (n, l, m1, ms). How many different quantum states are possible if the principal quantum number is n = 3? To find the total number of allowed states, first write down the allowed orbital quantum numbers I, and then write down the number of allowed values of mi for each orbital quantum number. Sum these quantities, and then multiply by 2 to account for the two possible orientations of spin.
D. Is the state n = 3,1 = 3, m1 = -2, ms = 1/2 an allowable state? If not, why not?
a. Yes it is an allowable state.
b. No: The magnetic quantum number cannot be negative.
c. No: The magnetic quantum number must equal the orbital quantum number.
d. No: The orbital quantum number cannot equal the principal quantum number.
e. No: The magnetic quantum number must equal the principal quantum number.
E. What is the maximum angular momentum L max that an electron with principal quantum number n = 3 can have? Express your answer in units of h. (You don't need to enter the h, it is in the units field for you.)

Answers

Answer:

Explanation:

1) for a given n value the l value can be from 0 to n-1

So if n= 5 it can take 0,1,2,3,4

i.e it can take 5 values

2)for an electron with l =3

it can be from -3 -2 -1 0 1 2 3

i.e it can take 7 values

3) n = 3 !!

l = 0 , 1 , 2

for l=0 , m = 0 total = 1

for l= 1 ,m = -1,0,1 total = 3

for l = 2, m=-2,-1,0,1,2 total = 5

5+3+1 = 9

total possible states = 9 * 2 = 18

Answer is 168

4)given l=3 and n=3

orbital quantum number cannot be equal to principal quantum number

its max value is l-1 only

5)L = sqrt(l(l+1))x h'

for it to be max l should be max

for n = 3 max l value is 2

therfore it is sqrt(2(2+1)) x h'

\(\sqrt(6) \times h'\)

this is the answer

An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?

Answers

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

1c. Using a metric (SI) measuring tape or ruler:

Measure the length L, width Wand height H of the shoebox shaped object and record

them in centimeters plus millimeters. Transform them to decimal format.

height H

Dimensions of shoebox shaped object measured with ruler

Format

length L

width W

In centimeters and

millimeters

28 cm and 6 mm 19 cm and 1 mm

In decimal

centimeters format

(show your work)

9 cm and 5 mm

Lo

Answers

Answer:

Format ______Length ______width ___ height

cm and mm _26cm 6mm _19cm 1mm_9cm 5mm

Decimal ____ 26.6cm _____ 19.1 cm __ 9.5cm

Explanation:

Dimension of shoebox shaped object :

Format ______Length ______width ___ height

cm and mm _26cm 6mm _19cm 1mm_9cm 5mm

Decimal ____ 26.6cm _____ 19.1 cm __ 9.5cm

Recall:

1mm = 0.1cm

For the length :

26cm + 6mm = 26cm+(6*0.1) = 26 + 0.6 = 26.6cm

Width:

19cm + 1mm = 19cm+(1*0.1) = 19 + 0.1 = 19.1cm

Height:

9cm + 5mm = 9cm+(5*0.1) = 9 + 0.5 = 9.5cm

Calculate the weight of the following objects, or Earth's (assume g=10N/kg).a)12kg b)500g c)20g

Answers

Answer:

a) W = 120 N

b) W = 5 N

c) W = 0.2 N

Explanation:

There are given three objects with different mass values. The formula of weight is:

\( \displaystyle{ W= mg}\)

Where W is weight, m is mass and g is acceleration due to gravity. Since, we are finding the objects' weight on Earth then we have to use g = 10 N/kg (m/s²) which is already given in the problem. Therefore, see below for various parts:

A) 12 kg

Substitute in m = 12 kg, g = 10 N/kg

\( \displaystyle{W = 12 \: \text{kg} \cdot 10 \: \text{N/kg}} \\ \\ \displaystyle{W = 120 \: N}\)

Therefore, a mass of 12 kg on Earth will have weight of 120 N.

B) 500 g

Since the unit is in grams, we have to convert to kilograms in order to evaluate for weight. We know that 1000 gram = 1 kilogram and therefore, 1 gram = 0.001 kg. Hence, 500 grams = 1/1000 * 500 kg which equals to 500 grams = 0.5 kg

\( \displaystyle{W =0.5\: \text{kg} \cdot 10 \: \text{N/kg}} \\ \\ \displaystyle{W = 5\: N} \)

Therefore, a mass of 500 g on Earth will have weight of 5 N.

C) 20 g

We know that 1 gram = 1/1000 kilogram. Therefore, 20 grams = 1/1000 * 20 kg which results in 20 grams = 0.02 kg

\( \displaystyle{W =0.02\: \text{kg} \cdot 10 \: \text{N/kg}} \\ \\ \displaystyle{W = 0.2\: N} \)

Therefore, a mass of 20 g on Earth will have weight of 0.2 N.

While John is traveling along a straight inter-
state highway, he notices that the mile marker
reads 241 km. John travels until he reaches
the 145 km marker and then retraces his path
to the 174 km marker.
What is John's resultant displacement from
the 241 km marker?
Answer in units of km.

Answers

Answer:

His displacement is 260 – 169  = 91 km

His distance traveled is (260 – 134) + ( 169 – 134 ) = 161 km

Explanation:

21) The distance between crest and the adjacent trough of water wave is 3m They pass a given point
at a rate of 5m/sec. find

(a) the frequency?
(b) the speed of the water waves?​

Answers

Answer:

1.67m

5m/s

Explanation:

Given parameters:

Wavelength of the wave = 3m

Speed of the wave  = 5m/s

Unknown:

Frequency of the wave  = ?

Speed of the water waves  = ?

Solution:

The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.

  To find the frequency ;

         V = f∧

V is the speed of the wave

f is the frequency

∧ is the wavelength

   Insert the parameters and find the frequency;

         f  = V/ ∧   = 5 / 3  = 1.67Hz

The rate at which the wave passed a given point is the speed of the wave and it is 5m/s


Have you answered this question

Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.

Answers

A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

What is the carbon cycle?

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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**NEED ANSWER ASAP, H.W QUESTION**
If the proton proton chain produces gamma ray photons, why are the majority of photons we observe from the sun at visible wavelengths?

Answers

The bombardment of the gamma rays with the particles in outer space reduces the energy thus what we see is mostly visible light of lower energy.

What is nuclear fusion?

We know that nuclear fusion is the process by which two light nuclei are combined in order to obtain a heavier nucleus with the emission of a tremendous mount of energy. Due to the tremendous amount of energy that is required when we are carrying out a fusion reaction, it does occur only in the sun.

The  proton proton chain produces gamma ray photons. We know that gamma rays have a very high energy but the energy of the gamma photons is reduced as it is bombarded with the particle in the atmosphere.

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The correct life cycle to death for a very large mass star is_______.


a) supergiant, supernova, main sequence, black hole

b) main sequence, supernova, black hole, supergiant

c) main sequence, supergiant, supernova, black hole

d) supernova, supergiant, black hole, main sequence


NO LINKS

Answers

Answer:

c) main sequence, supergiant, supernova, black hole

A 0.5 kg ball was kicked and was going 15 m/s.What is the kinetic energy of the ball?

Answers

Answer:

\(\boxed {\boxed {\sf 56.25 \ Joules}}\)

Explanation:

Kinetic energy can be found using the following formula:

\(E_k=\frac{1}{2}mv^2\)

where m is the mass and v is the velocity.

The mass of the ball is 0.5 kilograms and the velocity is 15 meters per second

\(m= 0.5 \ kg \\v= 15 \ m/s \\\)

Substitute the values into the formula.

\(E_k=\frac{1}{2} (0.5 \ kg ) * (15 \ m/s)^2\)

First, evaluate the exponent.

(15 m/s)²= (15 m/s) * (15 m/s) = 225 m²/s²

\(E_k=\frac{1}{2} (0.5 \ kg ) *(225 \ m^2/s^2)\)

Multiply 0.5 kg by  225 m²/s²

\(E_k=\frac{1}{2}(112.5 \ kg* m^2/s^2)\)

Multiply 112 kg*m²/s² by 1/2, or divide by 2.

\(E_k=56.25 \ kg*m^2/s^2\)

1 kg*m²/s² is equal to 1 JouleTherefore, our answer of 56.25 kg*m²/s² is equal to 56.25 Joules.

\(E_k= 56.25 \ J\)

The kinetic energy of the ball is 56.25 Joules

A 125 kg mail bag hangs by a vertical rope 3.3 m long. A postal worker then displaces the bag to a position 2.2 m sideways from its original position, always keeping the rope taut.
1) What horizontal force is necessary to hold the bag in the new position?
2) As the bag is moved to this position, how much work is done by the rope?
3) As the bag is moved to this position, how much work is done by the worker?

Answers

Answer:

1) the required horizontal force F is 1095.6 N

2) W = 0 J { work done by rope will be 0 since tension perpendicular }

3) work is done by the worker is 1029.4 J

Explanation:

Given that;

mass of bag m = 125 kg

length of rope \(l\) = 3.3 m

displacement of bag d = 2.2 m

1) What horizontal force is necessary to hold the bag in the new position?

from the figure below; ( triangle )

SOH CAH TOA

sin = opp / hyp

sin\(\theta\) = d / \(l\)

sin\(\theta\) = 2.2/ 3.3

sin\(\theta\) = 0.6666

\(\theta\) = sin⁻¹ ( 0.6666 )

\(\theta\)  = 41.81°

Now, tension in the string is resolved into components as illustrated in the image below;

Tsin\(\theta\) = F  

Tcos\(\theta\) = mg

so

Tsin\(\theta\) / Tcos\(\theta\) = F / mg

sin\(\theta\) / cos\(\theta\) = F / mg

we know that; tangent = sine/cosine

so

tan\(\theta\) = F / mg

F = mg tan\(\theta\)

we substitute

Horizontal force F = (125kg)( 9.8 m/s²) tan( 41.81° )

F = 1225 × 0.8944

F = 1095.6 N

Therefore, the required horizontal force F is 1095.6 N

2)  As the bag is moved to this position, how much work is done by the rope?

Tension in the rope and displacement of mass are perpendicular,

so, work done will be;

W = Tdcos90°

W = Td × 0

W = 0 J { work done by rope will be 0 since tension perpendicular }

3) As the bag is moved to this position, how much work is done by the worker

from the diagram in the image below;

SOH CAH TOA

cos = adj / hyp

cos\(\theta\)  = (\(l\) - h) / \(l\)

we substitute

cos\(\theta\)  = (\(l\) - h) / \(l\)  = 1 - h/\(l\)

cos\(\theta\) = 1 - h/\(l\)

h/\(l\) = 1 - cos\(\theta\)

h = \(l\)( 1 - cos\(\theta\) )

now, work done by the worker against gravity will be;

W = mgh = mf\(l\)( 1 - cos\(\theta\) )

W = mf\(l\)( 1 - cos\(\theta\) )

we substitute

W = (125 kg)((9.8 m/s²)(3.3 m)( 1 - cos41.81° )

W = 4042.5 × ( 1 - 0.745359 )

W = 4042.5 × 0.254641

W = 1029.4 J

Therefore,  work is done by the worker is 1029.4 J

A 125 kg mail bag hangs by a vertical rope 3.3 m long. A postal worker then displaces the bag to a position

. A convertible moves toward you and then passes you; all the while, its loudspeakers are producing a sound. The speed of the car is a constant 9.30 m/s, and the speed of sound is 342 m/s. What is the ratio of the frequency you hear while the car is approaching to the frequency you hear while the car is moving away

Answers

Answer:

\(1.056\)

Explanation:

v = Velocity of sound = 342 m/s

\(v_s\) = Velocity of source of sound = 9.3 m/s

\(f_a\) = Frequency when car is approaching

\(f_m\) = Frequency when car is moving away

\(f_s\) = Frequecy of source of sound

The required ratio is

\(\dfrac{f_a}{f_m}=\dfrac{\dfrac{v}{v-v_s}f_s}{\dfrac{v}{v+v_s}f_s}\\\Rightarrow \dfrac{f_a}{f_m}=\dfrac{v+v_s}{v-v_s}\\\Rightarrow \dfrac{f_a}{f_m}=\dfrac{342+9.3}{342-9.3}\\\Rightarrow \dfrac{f_a}{f_m}=1.056\)

The ratio of the frequency you hear while the car is approaching to the frequency you hear while the car is moving away is \(1.056\)

Which of the following changes would double the force between two charged particles? O A. Decreasing the distance between the particles by a factor of 2 B. Increasing the distance between the particles by a factor of 2 O C. Doubling the amount of charge on one of the particles O D. Doubling the amount of charge on each particle

Answers

Let's check

\(\\ \rm\dashrightarrow F=\dfrac{k}{q_1q_2}{r^2}\)

\(\\ \rm\dashrightarrow F\propto Q\)

\(\\ \rm\dashrightarrow F\propto \dfrac{1}{r^2}\)

So

Option A and C can be used

Answer:

Decreasing the distance between the particles by a factor of 2

Explanation:

To double the force between the two charge particles, the distance between the particles should be reduced by a factor of two.

According to coulombs law "force is directly proportional to the potential between the two charges and inversely proportional to the square of their distances".

       \(\sf{F  = \dfrac{kq_{1} q_{2} }{r^{2} }}\)

F is the electric force

k is the coulomb constant

q is the charge

r is the distance or separation

As the separation between the charges is reduced the force increases and vice versa.

Need this by midnight!!!

E= \(\frac{kQ}{r^{2} }\)
Calculate the magnitude of the electric field (in N/C), due to a small charged sphere (Q = + 129 nC), at a point in space that is a distance 5.2 m away.

Round to nearest whole number.

Answers

The electric field strength of this field on the charge molecule is 31358.5N/C.

What is Electric field strength?

Electric field strength can be defined as a quantitative expression of the intensity of an electric field at a particular location. The electric field strength can be calculated:

E = ∣q∣/4πε₀r²

q = +129 nC

r = 5.2m

E = 129 × 10⁻⁹ × 8.99 × 10⁹ ×  (5.2)²

E = 1159.71 × 27.04

E = 31358.5N/C

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Which of the following is true for valence electrons?
Valence electrons are always located in the outer most energy level.
Valence electrons are found only in radioactive isotopes.
Valence electrons are always located in the innermost energy level
Valence electrons are found only in negatively charged ions.

Answers

Answer:

Valence electrons are always located in the outer most energy level.

Explanation:

Valence electrons are the ones that are involved in chemical bonds. In order to take part in a chemical bonding, the outermost/valence electron needs to be involved. Thus, the answer is Valence electrons are always located in the outer most energy level.

Two football players, one with a mass of 89.3 kg and the other with a mass of 94.8 kg, are running at a velocity of 8.32 m/s. If they are both headed in the same direction, what is the total momentum?

Answers

The momentum of first player can be given as,

\(p_1=m_1v\)

The momentum of second player can be given as,

\(p_2=m_2v\)

The total momentum of both the players can be given as,

\(p=p_1+p_2\)

Plug in the known expressions,

\(\begin{gathered} p=m_1v+m_2v \\ =(m_1+m_2)v \end{gathered}\)

Substitute the known values,

\(\begin{gathered} p=(89.3\text{ kg+94.8 kg)(8.32 m/s)} \\ =(184.1\text{ kg)(8.32 m/s)}(\frac{1\text{ N}}{1kgm/s^2}) \\ =1531.7\text{ Ns} \end{gathered}\)

Thus, the total momentum of both the players is 1531.7 Ns.

A power plant burns coal at
830 K, and exhausts to air at
288 K. If it runs at the Carnot
efficiency, how much input heat
must be fed into the plant to
produce 230,000 J of work?
(Unit = J)

Answers

The amount of heat fed to the plant is 353846.15JEfficiency of engine:

The efficiency of an engine is defined as ratio of the useful work done to the heat provided or,

in terms of temperature of the source and the sink the efficiency of heat engine is given by \(1-\frac{T_{2} }{T_{1} }\)

Thus, we have two formulae to calculate the efficiency of a heat engine.

η= \(\frac{useful work done}{heat absorbed}\) ....1

η= \(1-\frac{T_2}{T_1}\)             ....2   (where \(T_{2}\) and \(T_{1}\) are temperatures of sink and source respectively)

Given quantities are,

\(T_{1}\) = 830K\(T_1\) =288KWork done = 230000J

Now, by equating (1) and (2) equation,

⇒ \(1-\frac{T_2}{T_1}\) = \(\frac{Useful work done}{Heat absorbed}\)

Substituting the given values;

⇒ \(1-\frac{288}{830}\) = \(\frac{230000}{heat absorbed}\)

⇒therefore, heat absorbed = 353846.15 J

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What is Moral subjectivism?

Answers

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

A toy car is given an initial velocity of 0.0 m/s and experiences a constant acceleration of 2.0 m/s2. What is the final velocity after 12.0 s?​

Answers

Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

What happened to the pod during those seconds when communication was lost?

Answers

Answer:

Explanation:

From our investigation of what forces are like in a collision, we learned that when two

objects collide, a force is exerted on each object. The two forces are in opposite

directions but the same strength. This allowed us to infer that an equal strength force

was exerted on the space station and the pod, but in opposite directions.

As a result, the space station and the pod are moving in opposite directions. We need to

learn more about the effects of collisions on each object’s motion so we can report back

to Dr. Gonzales at the space agency.

You will use physical materials to gather data about

forces in a collision. You will also notice how objects

are affected by collisions. Students will use their

data to infer the force direction for objects in a

collision.

Based on the velocity change of each object,

what did you infer about the direction of forces

during a collision?

• We observed that the velocity of each object changed during a collision, so we can infer

that a force had to be exerted on each object. However, the motion of the objects

changed in different ways.

• The object that was moving forward slowed down, so I can infer that the force must have

pushed backward on this object.

• The other object started moving forward, so the force must have pushed forward on that

object. If one force was backward and one force was forward, then the forces pushed

the objects in opposite directions.

Why is the mass of an atom's electrons not included in the atom's mass number?
A. The electrons move so fast that their mass cannot be measured.
B. The electrons' negative charge cancels out their masses.
C. The electrons' mass is represented in the atomic number.
D. The electrons are much less massive than the rest of the atom.

Answers

Answer: A: the electrons move so fast that their mass cannot be measured

Explanation: because they are so fast  scientist and other people cannot measure them

Answer:

A

Explanation:

What force causes the passengers in a car to move forward when the car comes to a sudden stop?

Answers

Answer:

You and the car have inertia. If the car comes to a sudden stop, your body tends to keep moving forward. When the car starts moving again, your body tends to stay at rest. You move forward because the car seat exerts an unbalanced force on your body.

Explanation:

This is due to inertia. When the speeding bus stops suddenly, lower part of the body comes to rest while the upper part of the body tends to maintain uniform motion. Hence, the passenger's are thrown forward.

Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.

Answers

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

How do we explain?

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and

a student rises their 15 kg back pack from the froor at a constant velocity of 5.0 m/s. How much force must the student apply

Answers

a student rises their 15 kg back pack from the floor at a constant velocity of 5.0 m/s then they apply of 37.5 N of force.

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force.

In this problem student rises 15 kg of backpack at constant velocity and it happens in 2s, so consider time t = 2s.

Force is change in velocity with respect to time multiplied by mass.

F = m dv/dt

F = 15 kg × 5.0 m/s/2s

F = 37.5 N

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A train is moving at a velocity of 15 m/s is accelerated to 24 m/s over a 12 second period. What is the trains acceleration?

Answers

Answer:

Explanation:

velocity = 15 m/s

accelerated to = 24 m/s

time = 12 seconds

a = acceleration

u = final velocity

u0 = starting velocity

t = time  

a = u - u0 = t

a = (24 m/s  - 15m/s) / 12 s  = (9 m/s) / 12  =0,75 (m*s^2)  

QUICK HELP ILL MARK U BRAINLIEST
_____can be used to calculate how much energy is being wasted or lost. I​

Answers

Answer:

Microscope

Explanation:

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