Newton's third law is applicable only to objects at rest.
True
False
Answer:
False
Explanation:
Newton's third law - For every action there's an equal and opposite reaction, action and reaction act on different objects
A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point
has a final vertical velocity of 3 m/s just before it hits the ground. How far
from the base of the table did the ball hit the ground?
Answer:
The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.
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Answer:
I e jofh ndoj eohe nc n very nic e
A toy airplane is flying at a speed of 3 m/s with an acceleration of 1.1 m/s squared how fast is it flying after five seconds
Answer:
\(8.5\frac{m}{s}\)
Explanation:
Use Kinematics:
\(v = v_0 + at\)
\(v = 3 + 1.1 * 5\)
\(v = 8.5 \frac{m}{s}\)
What energy transformation occurs when a skydiver first jumps from a plane? Gravitational potential energy transforms into kinetic energy. Gravitational potential energy transforms into thermal energy. Kinetic energy transforms into gravitational potential energy. Thermal energy transforms into gravitational potential energy.
Answer:the first one gravitational potential energy turns into kinetic energy
Explanation:
Answer:
A) Gravitational potential energy transforms into kinetic energy.
Explanation:
Edge
Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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Can you give
an
example of a physical quantity
which cannot be measured?
Answer:
Feeling's.
Explanation:
Nobody can measure the feeling of a person or love , etc
A second pendulum made of brass keeps correct time at 10°C. How many seconds will it lose or gain per Day when the temperature of its surroundings rises to 35°C?
The brass pendulum will lose or gain approximately 0.0015 seconds per day when the temperature of its surroundings rises from 10°C to 35°C
Calculation on the pendulumThe time period of a pendulum is given by the formula:
T = 2π√(L/g)
where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
Since both pendulums have the same length and are located in the same gravitational field, their time periods are equal. Therefore, the time gained or lost by the brass pendulum due to the change in temperature can be calculated using the following formula:
ΔT = T × α × ΔT
where ΔT is the change in temperature, α is the coefficient of linear expansion of brass, and T is the original time period.
The coefficient of linear expansion of brass is approximately 19 × 10^-6 /°C.
Substituting the values given in the problem, we get:
ΔT = T × α × ΔT
= (2π√(L/g)) × (19 × 10^-6 /°C) × (35 - 10) °C
= 2π√(L/g) × (0.000019) × (25) °C
= 2π√(L/g) × 0.000475
Assuming a standard pendulum length of 1 meter, the time gained or lost by the brass pendulum can be calculated as follows:
ΔT = 2π√(L/g) × 0.000475
= 2π√(1/9.81) × 0.000475
≈ 0.0015 seconds
Therefore, the brass pendulum will lose or gain approximately 0.0015 seconds per day when the temperature of its surroundings rises from 10°C to 35°C.
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He much current is needed to operate a radio with a power of 80 watts when a potential difference of 135v is applied across itl
Answer:
593 mAmps
Explanation:
Power = 80 watts = VI
80 = 135 I
80/135 = I =
what is the weight of a 3.67kg ball?
Answer:
mass 3.67 kg, density 600 kg/m3) is fitted
with lead (density 1.14 * 10^4 kg/m3) so that it floats in water with
0.900 of its volume submerged. Find the lead mass if the lead is fitted
to the block’s (a) top and (b) bottom.
What is the mode of 4,7,7,7,4, 6, 6, 6, 7?
6
o7
4
Answer:
7 is your mode
Explanation:
Because its the number that appears the most .
A school bus takes 0.690 h to reach the school from your house. If the average velocity of the bus is 18.7 km/h to the East, what is the displacement.
The displacement is 12.903 km east.
Danny measures the temperature of a 1.0-kg sample of sand and a 1.0-kg sample of soil. He then leaves both samples in the Sun for the 2.0 hours. At the end of this time, he measures their temperatures again.
A.
The soil absorbed more heat than the sand.
B.
The sand absorbed more cold energy than the soil.
C.
The soil absorbed more cold energy than the sand.
D.
The sand absorbed more heat than the soil.
Answer:
The sand absorbed more heat than the soil.
Explanation:
your welcome
A player kicks a football from ground level with an initial velocity of 27.0 30.0 above the horizontal Find the ball's maximum height
Answer:
Given
initial velocity (u) =27.030
Force of gravidity g) =9.8
Rtc maximum height Hmix =?
\( sln \\ \ hmix = u {}^{2} \div 2g \\ 27.030 \div 2 \times 9 \\ \\ hmix = 38.025m\)
A driver in a 500 kg car going 20 m/s sees a large box in the middle of the road 100 meters away. How much net force is required to get the car to stop without hitting the box?
WILL GIVE BRAINLY AND 50 POINTS
Answer:
620
Explanation:
Answer:
100
correct me if I am wrong
COULOMB’S LAW PhET LAB SIMULATION GUIDED QUESTIONSDirections:
TYPE ALL of YOUR ANSWERS IN A DIFFERENT COLOR (not black!)
PART 1: DATA COLLECTION
Go to this link: Coulombs Law PhET Lab
Once you are in the simulation, which looks like the image below, follow the instructions as you go through each question in order to work your way through the simulation and answer the questions.
Identify the three variables in the simulation...remember, variables are things that can be changed or tested. There are 3 things in the simulation that can be changed directly or indirectly…..
Fill in the blank, highlight one choice:
Variable 1 is and it is : (Independent OR Dependent)
Variable 2 is and it is: (Independent OR Dependent)
Variable 3 is and it is: (Independent OR Dependent)
a. Which variable(s) do you change to increase force? (list them)
b. What do you do to the variable(s) listed above to increase the force? (describe what you change to make the force go up) decrease distance and/or increase charge.
a. Which variable(s) do you change to decrease force? (list them)
b. What do you do to the variable(s) listed above to decrease the force? (describe what you change to make the force go down)
Variable 1 is distance and it is Independent.
Variable 2 is charge and it is Independent.
Variable 3 is force and it is Dependent.
a. To increase force, you need to change distance and/or charge.
b. To increase the force, you need to decrease the distance between the charges and/or increase the magnitude of the charges.
a. To decrease force, you need to change distance and/or charge.
b. To decrease the force, you need to increase the distance between the charges and/or decrease the magnitude of the charges.
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an asteroid is 180,000km away from the moon on a collision course. how much time will it take before the asteroid is 10km away if it is moving at a constant velocity of 36,000m/s?
Answer:
See below
Explanation:
(180 000 - 10) km / 36 km/s = 4999.7 =~ 5000 seconds = 83 .3 min
help me please i dont understand
The choose C. 1.33
Tanθ =opposite / adjacent
Tanθ =20/15
Tanθ =1.33
I hope I helped you^_^
The volume of a certain wooden block is 63 cm². The mass is 11 g. Find the
density
Answer:
Density = 0.174 grams/ cm³Explanation:
Given:
The volume of a certain wooden block is 63 cm². The mass is 11 g.To Find:
DensitySolutioN:
We know that,
p = M/Vhere,
p is density,m is mass,v is volumeSubstituting the required values:
Density = 11g /63 cm³
Density = 0.174 grams/ cm³
Hence,
Required density = 0.174 g/ cm³\(\large\boxed{\bold{Formula: d=\frac{m}{V}}}\)
Let's solve!
In this question all the values are given so we'll simply have to substitute and solve.
So, we'll have to divide mass by volume.
Substitute the values according to the formula.
\(d= \frac{11}{63}\)
Calculator value:
\(\bold{d= 0.174603174 \: g/ {cm}^{3}}\)
Now, we can round off to 3 significant figures.
The value in ten thousandths place is greater than 5 so we'll have to round up by adding 1 to the thousandths place.
Final answer:
\(\large\boxed{\bold{d= 0.175 \: g/ {cm}^{3}}}\)
what is the relationship between electric field lines and equipotential surfaces?
A culture of bacteria has an initial population of 64000 bacteria and doubles every 2 hours.Using the formula Pt = Po . 2^t/d where P is the population after t hours, Po is the initial population, t is the time in hours and d is the doubling time; what is the population ofbacteria in the culture after 3 hours, to the nearest whole number?
After 3 hours, the population of bacteria in the culture is approximately 180,992 bacteria.
let's plug in the values for the initial population (Po), doubling time (d), and the time (t) into the formula \(P_{t}=P_{o}\times 2^{\left( t/d \right)}\)
Initial population (Po) = 64,000 bacteria
Doubling time (d) = 2 hours
Time (t) = 3 hours
Now, we can plug these values into the formula:
\(P_{t}= 64000\times 2^{\left( 3/2 \right)}\)
To simplify the exponent, 3 divided by 2 equals 1.5. Therefore:
Now,
\(2^{\left( 1.5 \right)}\) ≈ 2.828
Now, we multiply the initial population by this value:
\(P_{t}= 64000\times 2^{\left( 1.5 \right)}\) ≈ 180,992
To get the nearest whole number, we can round the population:
Pt ≈ 180,992 (nearest whole number)
After 3 hours, the population of bacteria in the culture is approximately 180,992 bacteria.
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Can you fit a plot of Fe vs r with an equation of the form F = C/r^2 where C is a constant?
Yes, you can fit a plot of Fe vs r with the equation F = C/\(r^2\), where C is a constant.
Certainly, fitting a plot of force (Fe) versus distance (r) with the equation F = C/\(r^2\) is feasible, especially when dealing with phenomena that obey the inverse square law, such as gravitational or electrostatic forces.
In these cases, C represents a constant that depends on the specific context, like the product of masses or charges involved.
By analyzing experimental data and using curve fitting techniques, you can determine the value of C that best represents the relationship between Fe and r according to the given equation.
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At 55 mph, how long does it take for a truck to fully stop?.
The time taken by a truck to fully stop will be 2 hours. The time taken is found with the help of Newtons second equation of motion.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
The given data Is;
u is the velocity of truck = 55 mph
v is the final velocity of truck = 0 mph
S is the distance travelled by the truck before stop= 302 feet
1 feet = 0.000189394 mile
302 feet = 302 × 0.000189394 mile= 0.057197 mile
From the Newtons's second equation of motion;
\(\rm v^2 = u^2-2as\)
The formula for the acceleration is found as;.
\(a = \frac{v-u}{t}\)
By rearranging the equation, we get;
\(\rm u^2 =2as \\\\ u^2 =2[ \frac{v-u}{t}]s \\\\ u = \sqrt{2[ \frac{v-u}{t}]s} \\\\ 55 = \sqrt{2[ \frac{55-0}{t}]} \\\\ 55= \frac{2 \times 55}{t} \\\\ t= 2 \ hour\)
Hence, the time taken by a truck to fully stop will be 2 hours.
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A traves de una manguera de 1 in de diámetro fluye gasolina con una velocidad media de 5ft/s ¿cuál es el gasto?
Answer:
El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.
Explanation:
El gasto es el flujo volumétrico de gasolina (\(Q\)), medido en pies cúbicos por segundo, que sale de la manguera. Asumiendo que la velocidad de salida es constante, tenemos que el gasto a través de la manguera es:
\(Q = \frac{\pi}{4}\cdot D^{2}\cdot v\) (1)
Donde:
\(D\) - Diámetro de la manguera, medido en pies.
\(v\) - Velocidad medida de salida, medida en pies por segundo.
Si sabemos que \(D = \frac{1}{12}\,ft\) y \(v = 5\,\frac{ft}{s }\), entonces el gasto de gasolina es:
\(Q = \frac{\pi}{4}\cdot \left(\frac{1}{12}\,ft \right)^{2} \cdot \left(5\,\frac{ft}{s} \right)\)
\(Q \approx 0.0273\,\frac{ft^{3}}{s}\)
El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.
You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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a particle moving along the x axis has a position given by where 22 m/s, 3.8 m/s3 and is measured in seconds. what is the magnitude of the acceleration of the particle at the instant when its velocity is zero? please give your answer in units of m/s2.
Answer:
Therefore, the magnitude of the acceleration of the particle at the instant when its velocity is zero is approximately 18.258 m/s².
Explanation:
To find the magnitude of acceleration at the instant when velocity is zero, we need to differentiate the given velocity equation with respect to time (t) to obtain the acceleration equation.
Given:
Velocity equation: v(t) = 22 - 3.8t^2
Differentiating the velocity equation with respect to time, we get:
a(t) = d(v(t))/dt = -2 * 3.8t
To find the magnitude of acceleration at the instant when velocity is zero, we need to solve for t when v(t) = 0.
0 = 22 - 3.8t^2
3.8t^2 = 22
t^2 = 22/3.8
t^2 ≈ 5.789
Taking the square root of both sides, we find:
t ≈ √(5.789)
t ≈ 2.403
Now we can substitute this value of t into the acceleration equation to find the magnitude of acceleration at that instant:
a(t) = -2 * 3.8 * 2.403
a(t) ≈ -18.258
Therefore, the magnitude of the acceleration of the particle at the instant when its velocity is zero is approximately 18.258 m/s².
The 70 kg student in figure p14. 43 balances a 1200 kg elephant on a hydraulic lift. What is the diameter of the piston the student is standing on?.
The diameter of the piston the student is standing on is 0.22 times greater than that of the piston the elephant is standing on.
What is mechanical advantage of a hydraulic lift?An illustration of Pascal's law is the hydraulic system.By exerting a modest force on the small piston, we can generate a bigger force on the large piston.At each piston, the ratios of force to area must be the same.Three practical tools that make use of Pascal's law are hydraulic brakes, lifts, and presses.Given parameters:
Mass of the student: m = 70 kg.
Mass of the elephant: M = 1200 kg.
Let the diameter of the piston the student is standing on is d.
and the diameter of the piston the elephant is standing on is D.
Using Pascal's law,
Weight of the student ÷ area of the piston the student is standing on = Weight of the elephant ÷ area of the piston the elephant is standing on.
⇒ 70 kg × g / π d² = 1200 kg × g / π D²
⇒ 1400 d² = 70 D²
⇒ d= 0.22D.
Hence, the diameter of the piston the student is standing on is 0.22 times greater than that of the piston the elephant is standing on.
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Which of the following is a vector quantity?
O speed
O time
O force
O displacement
O temperature
O momentum
O velocity
O acceleration
According to the given information temperature and velocity of the following is a vector quantity
Is temperature a vector quantity?A vector quantity is one that just has magnitude, whereas a vector quantity has both orientation and magnitude. Given that it is direction-independent at a given position, heat is a scalar number.
Is the force of gravity a vector?Vectors include gravity and displacement. They possess both a value and a direction. The fact that gravity and displacement are pointing in the same direction in this instance allows us to derive a scalar energy from them (in this example, their direction are down and down, respectively).
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easy one giving brainly if correct
Answer:
c) Liquid
Explanation:
Liquid takes the shape of its container and has a specific volume. On the other hand, solid and gas don't.
A plane is moving at a constant velocity.
That means
A. there is no net force on the plane.
B. there is a net upward force on the plane.
C. there is a net backward force on the plane.
D. there is a net forward force on the plane.
A. There is zero net force acting on the plane.
Lab partner says in newton second law by pushing a 10 KG object with 10 N and then pushed a 20 KG object with 20 in. They wanted to see effect of doubling the force of an object which choice explains why this I cannot be used to show the effect of
Answer:
must double the force, with the same masses you get twice the acceleration.
Explanation:
Newton's second law establishes a relationship between force and acceleration where the constant of proportionality is mass
F = m a
To prove these relationships you must double the force, with the same masses you get twice the acceleration.
2F = m 2a
The downside is that if you double the mass, the acceleration stays the same.
2F = 2m a