The figure shows two waves traveling in the positive x direction. The amplitude
of the resultant wave is

a. 2.0 mm
b. 1.8 mm
c. 1.4 mm
d. 1.0 mm
e. 0.83 mm

Answer:

The car furthest from the finish line: Car III (Choice C).

Explanation:

It's asking for lowest average speed throughout the entire race. Therefore, whoever is last technically has the lowest average speed.

Car III is far behind Car I and Car II so Choice A and B aren't correct. Choice D is incorrect since the three cars aren't in the same position. Choice E is incorrect because there is enough information to see that Choice C has the lowest average speed.

Answer:

a. True

Explanation:

Illumination distance is the distance, up to which the light of the vehicle can reach. Hence, it is a maximum distance from the, that driver can see.

Stopping distance is the minimum distance required by the car to stop after brakes are applied.

So, in order to avoid any accident the illumination distance must be greater than the stopping distance. So, the driver can stop the vehicle in time, when he sees something in front of it.

Since, the stopping distance in this case is two or three times longer than illumination distance. Therefore, low beam light does not provide enough visibility in high speed driving situations.

Hence, the correct option is:

a. True

Answer:

W = 15 N

Explanation:

The moments from the center mus be equal for balance to occur

 center is at 25 cm  ( for a 1/2 meter stick)

moment one :   15 cm * 20 N

moment two :   20 cm * W         these must be equal

   15 * 20 = 20 * W        W = 15 N

Answer:

Explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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The molarity M of a solution is the quotient between the amount of substance n and the volume V:

Substitute n=5.25 mol and V=300 mL = 0.3 L to find the molarity:

Answer:

1.3 and 2.5

Explanation:

I did mental math

Answer:

(a) The change in magnetic flux is equal to the product of the magnetic field strength, the area of the coil, and the cosine of the angle between the magnetic field and the surface of the loop. Therefore, the change in magnetic flux is equal to 0.200T x (π x (25.0cm)^2) x cos(45°) = 7.85 x 10^-3 Tesla-square meters.

(b) The induced emf is equal to the change in magnetic flux divided by the time taken for the change to occur. Therefore, the induced emf is equal to 7.85 x 10^-3 Tesla-square meters / 0.250s = 3.14 Volts.

Answer:

4

Explanation:

The net force on the box a will be 20 N to the left and that on box b is 6 N downwards. The net force on box  c is 90 N to the left and that on box d is zero.

Force is an external agent acting on a body to change its motion or to deform it. The net force acting on a body depends on all the the forces with their magnitudes and directions.

If two same or different forces acts from the same direction they will add up and net force will be their sum. If they acts from the different directions, they will cancel each other in magnitudes.

In box a, the equal forces of 20 N opposes from each direction cancel and the net force will be 20 N to the left. I box b the 15 N cancel each other. Where the 4N and 2 N add up to have net force of 6 N downwards.

In box c, 10 N from opposite direction cancels and the 60 N and 30 N to the left add ups to have the net force of 90 N to the left. On box d, 5 N from opposite directions cancels as 12 N. Hence, net force is zero.

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Total mass lost by the comet is 30.24 x 10¹⁰ kg.

Rate at which mass is lost, R = 35 x 10⁴ kg/s

Time period, T = 100 days = 8.64 x 10⁶s

Therefore,

Total mass lost by the comet, m = R x T

m = 30.24 x 10¹⁰ kg

So,

The fraction of loss = (30.24 x 10¹⁰)/(5 x 10¹⁵) = 60.48 x 10⁻⁵

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Given that,

Bulk modulus \(B= 2.6\times10^{10}\ N/m^2\)

Change in volume \(\Delta V=6.0\times10^{-10}\ m^3\)

Edge \(a= 5.4\times10^{-2}\ m\)

The volume of the cube at the ocean's surface will be

\(V_{0}=a^3\)

Where, a = edge

Put the value into the formula

\(V_{0}=(5.4\times10^{-2})^3\)

\(V_{0}=0.00016\ m^3\)

We need to calculate the change in pressure

Using formula of pressure

\(\Delta P=-B\dfrac{\Delta V}{V_{0}}\)

Put the value into the formula

\(\Delta P=-(2.6\times10^{10})\times\dfrac{(-6.0\times10^{-10})}{0.00016}\)

\(\Delta P=97500\ N/m^2\)

The pressure increases by \(1.0\times 10^{4}\ N/m^2\) for every meter of depth

We need to calculate the depth

Using formula for depth

\(depth=\dfrac{97500}{1.0\times10^{4}}\)

\(depth=9.75\ m\)

Hence,  The depth is 9.75 m.

Answer:

Given, DE is parallel to BC. From the figure, in ADE and ABC ∠ A = ∠ A (Common angle) Since, DE is parallel to BC therefore the below angles will be equal because they are corresponding angles. ⇒ ∠ D = ∠ B (Corresponding angles) and (Corresponding angles) Therefore, by AAA congruence criteria, the triangles ADE and ABC

Explanation:

Answer:3000

Explanation:

given:u=0v=20m/st= 8sec

thereforea=v-u/t=20-0/8=20/8=5/2 m/som=1200 kg

thereforef=ma=1200*5/2=600*5=3000N

a) The main advantages of an epicyclic gearbox are:

b) i) Using the formula for the gear ratio of an epicyclic gear train:

T4/T3 = (t2/t1) x (t5/t2) x (t4/t5)

T4/30 = (1/2) x (60/20) x (40/60)

T4 = 40 Nm

ii) From the law of gearing for an epicyclic gear train:

w21 = (t3/t2) x (t5/t4) x w31 - (t3/t2) x w2

Substituting the given values:

w21 = (30/20) x (60/40) x 200 - (30/20) x 100

w21 = 150 rad/s

iii) The fixing couple that must be applied to wheel 5 can be found from the power transmitted by the gear train:

P = w3 x T3 = w2 x T2 = w1 x T1

Substituting the given values:

9 kW = 200 rad/s x 30 Nm = w2 x T2 = w2 x 20 Nm

w2 = 450 rad/s

T2 = (9 kW) / (450 rad/s) = 20 Nm

The fixing couple that must be applied to wheel 5 is equal in magnitude and opposite in direction to T2, so it is -20 Nm.

iv) The tangential force at the pitch point between wheels 3 and 4 can be found from the formula:

Ft = (2 x Pd) / (m x z3)

where Pd is the diametral pitch, m is the module, and z3 is the number of teeth on wheel 3.

Substituting the given values:

Pd = 25.4 / 5 = 5.08 teeth/inch

z3 = t3 / m = 30 / 5 = 6 teeth

Ft = (2 x 5.08) / (5 x 6) = 0.846 N

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The metal with the highest heat capacity between metals A.25 B.35 C.10 and D.15 is metal A.

Heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius. Metal A has a heat capacity of 400 J/kg°C, which means that it takes 400 joules of heat to raise the temperature of one kilogram of metal A by one degree Celsius.

Metal B has a heat capacity of 285.7 J/kg°C, metal C has a heat capacity of 1000 J/kg°C, and metal D has a heat capacity of 666.7 J/kg°C. Therefore, metal A has the highest heat capacity of the four metals.

Metal A's high heat capacity means that it can absorb a lot of heat without its temperature changing very much. This makes metal A a good material for things like heat sinks and thermal insulation.

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5 second is the time it takes for Theodore to splash down running at 2m/s  velocity as he runs off a bluff and drops 10 meters into a water filled rock

quarry.

velocity= 2m/s

distance=10 meters

velocity=distance/time

time=distance/velocity

time=10 meters/2m/s

time=5 second

A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

the moment of inertia is 4.5 × 10⁻⁵ kg.m²  

Explanation:

Given that;

point mass m = 0.005 g = ( 0.005 / 1000 ) = 5 × 10⁻⁶ kg

perpendicular distance r = 3m

We know that a point mass doesn't have a moment of inertia around its own axis but, but using the parallel axis theorem, a moment of inertia around a distant axis of rotation can be determined using;

\(I_{}\) = mr²

so we substitute

\(I_{}\) = (5 × 10⁻⁶ kg) × (3 m)²

\(I_{}\) = (5 × 10⁻⁶ kg) × 9 m²

\(I_{}\)  = 4.5 × 10⁻⁵ kg.m²  

Therefore; the moment of inertia is 4.5 × 10⁻⁵ kg.m²  

The moment of inertia of given point mass is 4.5 × 10⁻⁵ kgm² at a perpendicular distance of 3 m.

The moment of inertia of given point mass can be determined by,

\(I = mr^2\)

Where,

\(I\)- moment of inertia

\(m\)- mass = 0.005 g = ( 0.005 / 1000 ) = 5 × 10⁻⁶ kg

\(r\) - perpendicular distance = 3 m

Put the values in the formula,

\(I = (5 \times 10^{-6}{\rm \ kg}) \times (3 {\rm \ m})^2\\\\I = 5 \times 10^{-6}{\rm \ kg} \times 9 {\rm \ m}\\\\I = 4.5 \times 10^{-5} kgm^2\)

Therefore; the moment of inertia of given point mass is 4.5 × 10⁻⁵ kgm².

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Answer:

D

Explanation:

Continuous data is a characteristic of analog signals though been smooth is a subject of question. The smooth signal is after it's been processed. However a wave can still stay continuous defined by what we call duty circle.

Smooth and continuous data is one of the major features of an analog signal.

Analog signal isn't as accurate as the digital signal and it contains minimum

and maximum values which could be positive or negative.

Analog signal comprises of smooth and continuous data. This is explained

by one time-varying quantity representing another time-based variable.In

this type of signal , a variable is an analog of the other.

Analog signals examples include the following : Human voice, Thermometers, analog clocks etc

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In the context of society, it focuses upon experiences or processes. b. It always advances theory. A force in qualitative research is grounded theory research.

The term "force" has a defined meaning in science. A energy is not something an object "has in it" or that it "contains." A force is applied to one item by another. Neither live organisms nor inanimate objects are the only things that can be considered forces.

The newton, represented by the letter N, is the Standard unit of force. The metre, a unit of length with the sign m, is one of the fundamental units that relate to force. the kilogram

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Correct question is;

A tiny water droplet of radius 0.010 cm descends through air from a high building .Calculate its terminal velocity . Given that η of air = 19 × 10^(-6) kg/m.s and density of water ρ = 1000kg/ms

Answer:

1.146 m/s

Explanation:

We are given;

Radius; r = 0.010 cm = 0.01 × 10^(-2) m

η = 19 × 10^(-6) kg/m.s

ρ = 1000 kg/ms

The formula for the terminal velocity is given by;

V_t = 2r²ρg/9η

g is acceleration due to gravity = 9.8 m/s²

Thus;

V_t = (2 × (0.01 × 10^(-2))² × 1000 × 9.8)/(9 × 19 × 10^(-6))

V_t = 1.146 m/s

Answer:

F = G M1 M2 / R^2      attractive force

F = 6.67 * 10E-11 * 5.683 * 10E26 * 1.345 * 10E23 / (1.222 * 106)^2  N

F = 6.67 * 5.683 * 1.345 / 1.493 * 10E26 N = 3.414 * 10E27 N

The distance traveled by the Spacecraft is  2.3 x 10² m.

To have a constant velocity, the change in velocity or speed of the object must be zero.

Constant speed will elapse equal distance in an identical period of time as a result is an example of steady speed.

For a Spacecraft is traveling in inner planetary space at a constant velocity and a given time of motion, the distance traveled by the Spacecraft is calculated as follows;

Distance = speed x time

the speed is given as 24.21 m/s

the time of motion is given as 9.5 seconds

distance = 24.21 m/s  x 9.5 s

distance = 2.3 x 10² m

Thus, the distance traveled by the Spacecraft is  2.3 x 10² m.

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The complete question is below;

Spacecraft is traveling in inner planetary space at a constant velocity of 24.1 m/s. What it estimated distance traveled by the spacecraft in 9.50 seconds?

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

When there is a point source used without directing the light or sound in a direction, the area of a sphere = 4πr 2 is used instead of the area of circle for calculating intensity. The minimum intensity of sound that a human can hear is 10 -12 Wm -2 and the maximum is 1 Wm -2.

Explanation:

An integrated circuit is a small electronic device that incorporates many linked transistors, capacitors, resistors, and other electronic components on a single piece of semiconductor material.

A semiconductor is a substance with electrical conductivity intermediate between that of a conductor and that of an insulator. This implies that semiconductors can conduct electricity, but not as well as metals like copper or aluminum. At the same time, they are not as electrically robust as insulators such as rubber or plastic.

Here,

"Integrated Circuit" is the right answer (IC). An integrated circuit is a small electronic device that incorporates many linked transistors, capacitors, resistors, and other electronic components on a single piece of semiconductor material.

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The small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.

\(\frac{Kf}{Ki} =\) \(1- [\frac{1}{2}][ \frac{M}{m}] [\frac{2mv^{2} }{[M+m]^{2} }\)

M = 12m

Kf/Ki = 1 - (1/2)(12m/m)[(2mv^2)/(13m)^2]

Kf/Ki = 165/169

(1 - Kf/Ki) x 100% = (1 - 165/169) x 100% = 2.37%

So, the small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.

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Answer:

the rate of doing work is called power...

the capacity of doing work is called energy...

work is said to be done when the body moves in the direction of force applied....

Explanation:

i don't know what you want of those topics.i was confused and I write definition of them. I hope this will help you

The initial common temperature of the water and copper is approximately 2.68°C.

To find the hidden typical temperature of the water and copper, we need to use the norm of protection of energy, which communicates that energy can't be made or obliterated, recently moved or changed beginning with one design then onto the following.

The force lost by the ice as it breaks up is identical to the power obtained by the water and the calorimeter. We can impart this using the recipe:

Q_ice = Q_water + Q_calorimeter

where Q_ice is the force lost by the ice, Q_water is the power procured by the water, and Q_calorimeter is the force gained by the calorimeter.

We can determine the power lost by the ice using the recipe:

Q_ice = m_ice * L_f

where m_ice is the mass of the ice and L_f is the force of blend of water, which is 333 J/g.

Q_ice = (10.0 g) * (333 J/g) = 3330 J

We can sort out the force obtained by the water using the condition:

Q_water = m_water * c * (T_f - T_i)

where m_water is the mass of the water, c is the specific power breaking point of water, which is 4.184 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.

Q_water = (300.0 g) * (4.184 J/g°C) * (18.0°C - T_i)

We can figure the force obtained by the calorimeter using the recipe:

Q_calorimeter = m_calorimeter * c_calorimeter * (T_f - T_i)

where m_calorimeter is the mass of the calorimeter, which is 200.0 g, c_calorimeter is the specific force breaking point of copper, which is 0.385 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.

Q_calorimeter = (200.0 g) * (0.385 J/g°C) * (18.0°C - T_i)

Subbing these circumstances into the norm of conservation of energy, we get:

m_ice * L_f = m_water * c * (T_f - T_i) + m_calorimeter * c_calorimeter * (T_f - T_i)

Tending to for T_i, we get:

T_i = T_f - [(m_ice * L_f)/(m_water * c + m_calorimeter * c_calorimeter)]

T_i = 18.0°C - [(10.0 g) * (333 J/g)/(300.0 g * 4.184 J/g°C + 200.0 g * 0.385 J/g°C)]

T_i = 2.68°C

As needs be, the basic ordinary temperature of the water and copper was 2.68°C (conveyed to three immense figures).

To learn more about temperature, refer:

https://brainly.com/question/31909880

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