The coordinates of ADEF are D(-1, 4), E (7,-3), and F (9,5). Write a rule for the translation of ADEF to ADEF. so that the centroid of AD'EF' is
(9,6).
(x,y) -- (x+__y+__) HELP PLEASE

Answer:

A. X= -4

Step-by-step explanation:

8x-3=5(2x+1)

8x-3=10×+5

-3=2×+5

-8=2x

x=-4

Answer:

A: x=-4

Step-by-step explanation:

8x - 3 = 5(2x + 1)

8x - 3 = 10x + 5

-3 = 2x + 5

-8 = 2x

x = -4

Answer:

C, definitely two sides are different in the triangle.

A, it looks as if the bottom is a right triangle if you look at it in a different way.

The polygons that would be used in a net isosceles triangle & right triangle

A pyramid is a structure whose outer surfaces are triangular and converge to a single step at the top,

As, we need a triangular pyramid whose base has all the three sides equal in length.

We can have a net in the form of isosceles triangle whose two are equal

i.e., two sides are different in the triangle.

and also, bottom with the right angle

i.e.,  the bottom is a right triangle if you look at it in a different way.

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Answer:

x = 45°

Step-by-step explanation:

80° + 55° + x = 180°

135° + x = 180°

x = 45°

Given: A regular octagon

To Determine: The interior sum for the given polygon

Solution

The formula for finding the interior angle sum of a polygon is given as

An octagon is a polygon with 8 sides

Substitute the value of n = 8 into the formula

\(x=-14\)

\(-3.5=\frac{x}{4}\)

Swap the sides

\(\frac{x}{4}=-3.5\)

Divide both sides of the equation by the coefficient of variable

\(x=-3.5\times 4\)

Calculate the product or quotient

\(x=-14\)

I hope this helps you

:)

The area of the rhombus, obtained from the dimensions, of the diagonals, found from the trigonometric of sines of the angle can be presented as follows;

Area = 8·√3

The area of a plane figure is the two dimensional space occupied by the figure on a plane.

The measure of the angle ABC, m∠ABC = 60°

The length of the segment AE = 2 units

The diagonals of a rhombus bisect each other at right angles, and the right angles through which they pass, therefore;

BE = ED, m∠AEB = 90°

m∠ABE = 30°

sin(30°) = AE/AB

sin(30°) = 2/AB

AB = 2/(sin(30°)) = 4

AB = 4

BE = √(4² - 2²) = √(12) = 2·√3

Therefore; AC = 2 + 2 = 4

BD = 2·√3 + 2·√3 = 4·√3

The area of a rhombus = (1/2) × The product of the length of the diagonals

Therefore;

Area of the rhombus = (1/2) × (4·√3) × 4 = 8·√3

The area of the rhombus = 8·√3

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The lengths of the other two sides are 6 inches and 5 inches

Let b represent the base of the right triangle, h represent the height of the right triangle and x represent the hypotenuse.

Since the area of the triangle is 15 in², hence:

Area(A) = (1/2) * base * height

15 = (1/2)bh

bh = 30  

b = 30/h         (1)

Applying Pythagoras theorem also:

x² = b² + h²

(√61)² = b² + h²

61 = (30/h)² + h²

61 = 900/h² + h²

61h² = 900 + h⁴

h⁴ - 61h² + 900 = 0

h = -6, -5, 5, 6

Since the length cant be negative, hence h = 5 or h = 6

When h = 5; b = 30/5 = 6

When h = 6; b = 30/6 = 5

Therefore the lengths of the other two sides are 6 inches and 5 inches

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Answer:

Step-by-step explanation:   the best answer is c

Answer:

[-3,5]

Step-by-step explanation:

Interval notation is a shorthand way of writing and interval of values.  To describe an interval, imagine the two endpoints on the number-line.  Then, list the two endpoint values, leftmost point from the number-line first, separated by a comma.  Lastly, include the appropriate brackets for each endpoint:

For our situation, the two endpoints are -3 and 5.  -3 is to the left of 5 on the number-line, so -3 should be listed first

\(-3,5\)

Lastly, the directions say "including -3 and 5", so both endpoints should be included.

The final result for the interval is \([-3,5]\)

Answer:

Step-by-step explanation:

If a shape is scaled by a certain scale factor then :

the area of the new shape =  (the scale factor) times (the area of the original object)

………………………

the new recreation complex was created by enlarging the old community soccer field by a scale factor of 9

Then

The area of the new recreation complex = 9² × 600 = 81×600 = 48 600 yd²

The steps which you would take to determine if these figures are similar include the following:

2. Multiply the vertices of polygon ABCD by 1/2.

5. Reflect the intermediate image.

In Mathematics and Geometry, a dilation is a type of transformation which typically transforms the dimension (size) or side lengths of a geometric object, without affecting its shape.

Therefore, the dimension or side lengths of the dilated geometric object would be stretched or compressed (shrunk) depending on the scale factor that is applied.

By critically observing the graph representing polygon ABCD, we can logically deduce that a sequence of transformations that would polygon ABCD (pre-image) onto polygon A"B"C"D" (image) is a dilation by a scale factor of 1/2 and a reflection of intermediate image.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

To solve for x, first, we add 3 to the given equation:

Dividing by 2, we get:

Therefore:

Finally, subtracting 5 we get:

Answer:

Answer:

1607

Step-by-step explanation:

To cancel fractions, find a common factor e.g 14/28. 14 and 28 have a common factor of 2. Then divide both number by the common factor.

14÷2=7 28÷2=14. Find if there's another common factor of both numbers. 7 and 14 have a common factor of 7. 7÷7=1 14÷7=2, Therefore 14/28=1/2

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The Propositions are resulting

(a) ∀x∃y(x = y²) is False

(b) ∀x∃y(x² = y) is True.

(c) ∃x∀y(xy = 0) is True.

(d) ∀x∃y(x + y = 1) is True.

(a) ∀x∃y(x = y²)

This proposition states that for every x, there exists a y such that x is equal to y². To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any positive value for x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4 = 2². Similarly, if x = 9, then y = 3 satisfies the equation since 9 = 3².

Therefore, the proposition (a) is false.

(b) ∀x∃y(x² = y)

For any given positive or negative value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4² = 2. Similarly, if x = -4, then y = -2 satisfies the equation since (-4)² = -2.

Therefore, the proposition (b) is true.

(c) ∃x∀y(xy = 0)

The equation xy = 0 can only be satisfied if x = 0, regardless of the value of y. Therefore, there exists an x (x = 0) that makes the equation true for every y.

Therefore, the proposition (c) is true.

(d) ∀x∃y(x + y = 1)

To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 2, then y = -1 satisfies the equation since 2 + (-1) = 1. Similarly, if x = 0, then y = 1 satisfies the equation since 0 + 1 = 1.

Therefore, the proposition (d) is true.

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9514 1404 393

Answer:

  AD = 15

Step-by-step explanation:

The products of the segment lengths are the same.

  (x -2)(x +7) = 4(2x -1)

  x^2 +5x -14 = 8x -4

  x^2 -3x -10 = 0

  (x -5)(x +2) = 0

The positive solution is x=5.

Chord AD is ...

  (x -2) +(x +7) = 2x +5 = 2(5) +5 = 15

Chord AD is 15 units long.

Answer:it’s actually very simple it’s A.

Step-by-step explanation: anything that is below one is negative that’s how I got my answer.

Answer:the answer is A

Step-by-step explanation:i did the test

In Linear equation, The volume of the solution is 100ml.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) component, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                       Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables. Equations with power 1 variables are known as linear equations. axe+b = 0 is a one-variable example in which a and b are real numbers and x is the variable.

Let the volume of the solution be represented by x.

Therefore, we can form an equation based on the information given which will be

= 15% × x = 54

15/100 × x = 54.

0.15 × x = 54

0.15x = 54

x = 54/0.54

x = 100 ml

The volume of the solution is 100ml.

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Answer:

y=8.50x+0.25

Step-by-step explanation:

She/he starts off with 8.50 and throughout the week she can earn 0.25 per joke. We don't know how many times a joke is made so it would be an x.

Answer:     b  8.50+0.25 divoide it by 0.25 th3n do the eqathion back words

The required probabilities for the given sections of the question are a) P(A|B) = 0.111, b) P(B|A) = 0.059.

The probability of occurrence of any occasion A when one more occasion B corresponding to A has proactively happened is known as contingent likelihood.

A = occasion of tackling the first problem

B = occasion of tackling the second problem

Given

P(A) = 0.85

P(B) = 0.45

P(A and B) = 0.05

Section (a)

Jed has tackled the subsequent issue. So we're given that occasion B has occurred. We need to track down P(A|B) which is the likelihood of occasion An occurrence given B has occurred.

Utilize the restrictive likelihood equation

P(A|B) = P(A and B)/P(B)

P(A|B) = 0.05/0.45

P(A|B) = 0.111111

P(A|B) = 0.111

Part (b)

Same thought as to some degree (a), yet presently we need to track down P(B|A). We know occasion A has occurred and we need to find the likelihood of occasion B happening in light of A.

P(B|A) = P(B and A)/P(A)

P(B|A) = P(A and B)/P(A)

P(B|A) = 0.05/0.85

P(B|A) = 0.05882

P(B|A) = 0.059

Thus, required probability are a) P(A|B) = 0.111, b) P(B|A) = 0.059.

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Correct question:

a mathematics professor assigns two problems for homework and knows that the probability of a student solving the first problem is 0.90, the probability of solving the second is 0.45, and the probability of solving both is 0.20. (round your answers to three decimal places.)

(a) Jed has solved the second problem. What is the probability he also solves the first problem? (b) Edna has solved the first problem. What is the probability she also solves the second problem?

The sine is defined as the length of the opposite side divided by the length of the hypotenuse, both of which are positive. Since dividing a positive number by a positive number results in a positive number, the sine must be positive.

Also, since the hypotenuse is the longest side of the triangle, the sine is equal to some positive number less than the length of the hypotenuse being divided by the length of the hypotenuse, resulting in a number less than 1.

Answer:

plazzz get lost bro fast

Answer:

2.33 x  10^24  kilograms

Step-by-step explanation:

hope this helps!!

=2.33 × \(10{^{21}\)

scientific notation

= 2.33e21

scientific e notation

= 2.33 × \(10{^{21}\)

engineering notation

= 2.33 × \(10{^{21}\)

21

Order of Magnitude

for scientific and standard forms

two setillion three hundred thirty quintillion

Answer:

252 eggs in 7 weeks

Step-by-step explanation:

\(12 \times 3 = 36 \\ 36 \times 7 = 252\)

Answer:

Step-by-step explanation:

First we compute \(9^n\), for \(n = 0,1,2,3,4,5\)

\(9^0=1,9^1=9,9^2=81,9^3=729,9^4=6561,9^5=59049\)

We have the unit digit of \(9^n\), is either 1 or 9

Therefore, the conjecture can be state as follows

Conjecture; the unit of digit of \(9^n\), is 1, when n is even and 9 when n is odd

Let the property p(n) be the formula;

"The unit digit of \(9^n\), is 1 when n is even and 9 when n is odd"↔ P(n)

To show p(n) is true , we will use strong mathematical inductive

Show tgat p(0) and p(1) are true

We have  to show the unit digit of \(9^0\) is 1 and \(9^1\) is 9

Since any integer with zero power is one and hence

\(9^0=1\) and \(9^1 = 9\)

Therefore, p(0) and p(1) are true

Show that for al integer \(k\geq 1\), if  p(i) is true for all integer i from o through k, then p(k+1) is also true

let k be any integer with \(k \geq 1\) and suppose that for all integer i with \(0 \leq i \leq \leq k\)

the unit digit of \(9^i\) is 1 when is even and 9 when n is odd

we must show that \(9^{k +1}\) equals 1 when n is even and 9 when n is odd

Case I; (k +1 is odd)

in this case k is even and so, by inductive hypothesis, the unit digit of \(9^k\) is 1 and hence there is some non negative integer q such that

\(9^k = 10q + 1\)

now, \(9^{k+1}=9^k(9)\)

= (10q + 1)9

= 90q + 9

= 10.9q + 9

Note that for any non negative integer q , 9q is also an integer and this implies the unit digit of \(9^{k+1}\) is 9

Case II

(k +1 is even)

in this case k is odd and so, by inductive hypothesis, the unit digit of \(9^k\) is 9 and hence there is some non negative integer q such that

\(9^k=10q+9\)

Now,

\(9^{k+1}=9^k.9\\=(10q+9)9\\=90q+81\\=10(9q+8)+1\)

Note that any non negative integer q, 9q + 8 is also an integer and this implies the unit of \(9^{k+1}\) is 1

Since we have proved both the basis and the inductive step of the strong mathematical induction, we conclude that the given statement is true

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Answer: 36u^6-12u^3v + v^2

Explanation:

I hope this helped!

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- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

The equation of a parabola is: \(y = a(x - h)^2 + k\) where (h,k) represents the vertex.

The equation of the parabola is: \(y = \frac{18}{625}(x - 25)^2 + 90\)

We have:

\((h,k) = (25,90)\) --- the vertex

\((x,y) = (50,0)\) -- one of its point.

Recall that:

\(y = a(x - h)^2 + k\)

Substitute \((h,k) = (25,90)\)

\(y = a(x - 25)^2 + 90\)

To solve for a, we substitute \((x,y) = (50,0)\)

\(0 = a(50 - 25)^2 + 90\)

\(0 = a(25)^2 + 90\)

Collect like terms

\(a(25)^2 = 90\)

\(625a = 90\)

Solve for a

\(a = \frac{90}{625}\)

\(a = \frac{18}{125}\)

Recall that:

\(y = a(x - 25)^2 + 90\)

Hence, the equation of the parabola is:

\(y = \frac{18}{625}(x - 25)^2 + 90\)

See attachment for the graph of \(y = \frac{18}{625}(x - 25)^2 + 90\)

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By the substitution property of equality, ∠AOB ≅ ∠COD. Then the correct option is B.

The inclination is the separation seen between planes or vectors that meet. Degrees are another way to indicate the slope. For a full rotation, the angle is 360°.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

Given: Line segment AC and line segment BD intersect at O.

Prove: ∠AOB ≅ ∠COD

By the supplementary angles property, the equations are given as,

∠AOB + ∠BOC = 180°            .....1

∠BOC + ∠COD = 180°            ....2

By the substitution property of equality, ∠AOB ≅ ∠COD. Then the correct option is B.

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Answer: By the congruent complements theorem

Step-by-step explanation: I took the test

Answer:

The answer is **D. 30x+15y**.

```

5(6x + 3y) = 5*6x + 5*3y = 30x + 15y

```

Step-by-step explanation:

1. Distribute the 5:

```

5(6x + 3y) = (5 * 6x) + (5 * 3y)

```

2. Simplify:

```

5(6x + 3y) = 30x + 15y

```

Therefore, 5(6x + 3y) is equivalent to 30x + 15y.