The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t , where the time tis in seconds. The
particle is momentarily at rest at t is:
Select one:
a. 9.3s
b. 1.3s
C. 0.75s
d.5.3s
e. 7.3s
​

Answer:

Stars are the light bulbs of the universe.

Answer:

Stars are the recycling centers of the universe

Explanation:

I just did on edge C

Answer:

000.83

Explanation:

i dont know how to explain it bt i did something on paper for it

Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

Answer:

when they hit puberty

Explanation:

.

have a good day

Answer:

Their inner lining of uterus sheds

Explanation:

this occurs typically in females between 9-15

Given data

*The speed of the ranger who is driving at 11.4 m/s

*The given acceleration is a = -3.80 m/s^2

The formula for the distance covered by the ranger's vehicle is given by the kinematic equation of motion as

*Here v = 0 m/s is the initial speed of the ranger's vehicle

Substitute the values in the above expression as

The distance is required for the ranger's vehicle to come to rest is calculated as

The stopping time is calculated as

Substitute the values in the above expression as

The cannon will completely stop when it collides with the barrier.

To calculate the speed at which the cannon collides with the barrier, we can follow these step-by-step calculations:

Determine the initial momentum of the system.

Since the cannon is initially stationary, the initial momentum is zero.

Apply the conservation of linear momentum.

According to the principle of conservation of linear momentum, the initial momentum of the system (zero) is equal to the final momentum of the system. The final momentum is the momentum of the cannon after firing.

Calculate the final momentum of the system.

Let's assume the mass of the cannon is represented by 'm' and the final velocity of the cannon is represented by 'v'. The final momentum of the system is given by: final momentum = m × v.

Set up the equation.

Since the initial momentum is zero, we have: 0 = m × v.

Solve for the final velocity of the cannon.

Dividing both sides of the equation by 'm', we get: v = 0.

Interpret the result.

The calculation shows that the final velocity of the cannon is zero. This means that the cannon comes to a complete stop when it collides with the barrier.

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a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

Answer: All the planets in our solar system rotate around it without the sun itself moving therefore all the planets make a cicular shape and the sun is in the middle

Explanation:

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

The sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.

The amplitude of a sound wave is the maximum vertical displacement of the sound wave.

The sound mixer will need to increase the amplitude of the sound wave produced by the singer.

The increase in the amplitude of the sound wave produced by the lower tune singer will result in increased loudness of the sound.

Thus, the sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.

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Answer:

A)  λ = 4.88 10² nm,  B)   λ = 4.08 10² nm

Explanation:

The spectrum of hydrogen is correctly explained by the Bohr model, where the energy of each level is

          Eₙ = -13.606 /n²       [eV]

the transition generally occurs from a given level to a lower state nf <no, so a transition is

          ΔE = E_f -Eₙ = -13,606 ( \(\frac{1}{n_f^2} - \frac{1}{n_o^2}\) )

to find the wavelength let's use the planck relation

          ΔE = h f

the speed of light is

          c = λ f

we substitute

          ΔE = h c /λ

          λ = \(\frac{h \ c}{ \Delta \lambda}\)

let's apply this equation to our case

the Balmer series has as final state the level n_f = 2

A) initial state n₀ = 4, final state n_f = 2

         ΔE = -13.606 ( \(\frac{1}{2^2} - \frac{1}{4^2}\) )

         ΔE = 2.55 eV

let's reduce to SI units

         ΔE = 2.55 eV (1.6 10⁻¹⁹ J / 1 eV) = 4.08 10⁻¹⁹ J

we calculate

         λ = 6.63 10⁻³⁴ 3 10⁸ / 4.08 10⁻¹⁹

         λ = 4.875 10⁻⁻⁷ m

we reduce to nm

         λ = 4.875 10⁻⁷ m (10⁹ nm / 1m)

         λ = 487.5 nm

we reduce to three significant figures

         λ = 4.88 10² nm

B) initial state n₀ = 5

          ΔE = -13,606 ( \(\frac{1}{2^2} - \frac{1}{5^2}\) )

          ΔE = 2,857 eV

we repeat the process of the previous point

         ΔE= 2,857 1.6 10⁺¹⁹ = 4.286 10⁻¹⁹J

we look for the wavelength

           λ = 6.63 10⁻³⁴ 3 10⁸ / 4.88 10⁻¹⁹

           λ = 4.0758 10⁻⁷ m

we reduce to nm

           λ = 4.0758 10² nm

ignificant numbers

           λ = 4.08 10² nm

Answer:

94.25 seconds

Explanation:

Solve for period (T) using: v=(2*pi*r)/T

rearrange: vT=2*pi*r

rearrange: T=(2*pi*r)/v

Plug in values.

T=(2*pi*150)/10

T=94.25 seconds

If a race car goes around a circular track of a radius of 150 m at speed of 10.0 m/s ,then the time taken to complete the one lap would be 94.25 seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

As given in the problem a race car goes around a circular track of radius 150 m at speed of 10.0 m/s.

vT = 2 × π × r

T = (2 × π × r)/ v

T = (2 × π× 150)/10

T = 94.25 seconds

Thus, the time taken to complete the one lap would be 94.25 seconds.

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Answer:

Net torque in positive direction:

Fz = -450 * cos 30 deg * 1.5 = -585 N-M

Fz = 200 * 3.5 = 700 N-M

Net F = 115 N-M

Torque is generally defined as L = R X F

X cross Y = Z     normal coordinate system

Note that Z will be out of the page giving the positive value for the torque.

There is no change in an object's momentum because momentum is still a conserved quantity. Direct correlation exists between an object's momentum and speed.

The definition of momentum is pretty much any motion-related activity. In physics, it is a fundamental idea. Momentum is a term frequently used in sports. For instance, if a team is moving and needs to be stopped, it has momentum and will need some work.

Motivation is the feeling that propels you into the uncertainty of making a change by ejecting you from the security of passivity. Your forward motion is sustained by momentum. Though it is an emotion, motivation.

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Answer:

A) 2.1 × 1010 Hz

Explanation:

I think this is the answer you're looking for but it may change depending on mass and charge of electron. Hope this helps :)

Answer:

282 m

Explanation:

Given:

v₀ = 20.1 m/s

v = 33.2 m/s

t = 10.6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (33.2 m/s + 20.1 m/s) (10.6 s)

Δx ≈ 282 m

78% of the houses in Elizabeth's town were for sale last summer.

To find the percentage of houses that were for sale last summer in Elizabeth's town, we need to divide the number of houses for sale by the total number of houses and then multiply by 100.

The total number of houses in Elizabeth's town is given as 9,000. Last summer, 7,020 houses were for sale. To calculate the percentage, we divide 7,020 by 9,000:

Percentage = (7,020 / 9,000) * 100

Simplifying the calculation:

Percentage = 0.780 * 100

Percentage = 78.0%

To explain further, we take the number of houses for sale (7,020) and divide it by the total number of houses (9,000) to get the ratio of houses for sale to the total. Multiplying this ratio by 100 gives us the percentage. In this case, 78.0% indicates that a significant portion of the houses in Elizabeth's town were available for sale during the summer.

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Answer:

D potential energy at the top of the stairs, kinetic energy as she walks down

Explanation:

The potential energy of a body is the energy due to the position of the body.

At the top of the stair case, the student is at a significant height.

Kinetic energy is the energy due to the motion of the body.

As the student descends, the potential energy is changed to kinetic energy.

 To find the potential energy;

          P.E  = mgH

 m is the mass

 g is the acceleration due to gravity

 H is the height of the body

 To find the kinetic energy;

         K.E  = \(\frac{1}{2}\) m v²

   m is the mass

   v is the velocity

(a) The angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.

(b) The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .

The angular acceleration of the rod is calculated as follows;

Apply the principle of conservation of angular momentum;

τ = Iα

where;

τ = Fr = mg(L/2) cosθ

I = mL²/3

mg(L/2) cosθ =  mL²/3(α)

g(1/2) cosθ =  L/3(α)

(³/₂)g cosθ  = L(α)

(³/₂ L)g cosθ  = α

1.5Lg cosθ  = α

1.5(2.1) cos (70.4) = α

1.06 rad/s² = α

ωf² = ω₁² + 2αθ

ωf² = 0 + 2(1.06)(70.4π/180)

ωf² = 2.605

ωf = √2.605

ωf = 1.61 rad/s

Thus, the angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.

The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .

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The maximum bending stress in the beam is 1.46 ksi.

All of the sections of a beam will experience a bending moment when it is loaded externally.

The internal stresses in the beam fight against the bending that the bending moment at a section tends to cause in the beam.

Bending stress is the term used to describe the resistance provided by internal stresses to bending.

In other words, bending stresses are the internal resistance to an external force that bends a member.

The symbol for it is.

N/mm2 will serve as its unit.

\($ I =\frac{1}{12}^{b'h'3} - \frac{1}{12}^{bh3}\)

\($ I = \frac{1}{12} \times 8 \times 10^3 - \frac{1}{12} \times 6 \times 8^3\)

I = 410.667 inch

Depth of neutral axis

d = 10/2 = 5 inch

Maximum bending stress (σmax) = md/I

σmax = md/I

          \($ =\frac{ (10 \times 12)\times 5}{410.667}\)

          = 1.46 ksi

Thus, the maximum bending stress in the beam is 1.46 ksi.

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Answer:

the force produced between magnetic objects

Explanation:

Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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The highest point in a ball's trajectory is when it is thrown vertically. The average speed of a plane is 254 m/s/s. A carousel rotates continuously.

seconds per metre Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation.

Galileo Galilei, an Italian physicist, is typically attributed with being the first to quantify speed by taking into account the distance travelled and the time required. Galileo defined speed as the amount of distance travelled in a given amount of time.

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Answer:

16

Explanation:

6+10=16

the box will go forward but it will be a little harder.

16432 N force is required  to accelerate a 1,264 kg car at a rate of 13 m/s²

Force is an external agent that may change the condition of rest or motion of a body. It has a magnitude as well as a direction. The direction of the force is the place where force is applied, and the application of force is the location where force is applied. Newton (N) is the SI unit of force.

Given that,

Mass of the car (m) = 1264 kg

Acceleration (a) = 13 m/s²

Now calculate how much force (F) is required,

F = m × a

F = 1264 × 13 kg m/s²

F = 16432 N

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Answer:

hmmmmm ill get back later

Explanation:

Answer:

I think it is movement height and mass.  Let me know if I am wrong.

Explanation:

The factors affecting the gravitation potential energy of an object are given as follows,

The mass of the object .

The height attained by the object.

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

ME= PE+KE

As given in the problem we have to select all of the factors that influence the gravitational potential energy of an object,

The gravitational potential energy acquired by any object is given by the expression,

PE = mgh

where m is the mass, g is the gravity and h is the height

Thus, the gravitational potential energy depends upon the mass of the object as well as the height attained by the object.

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a. The two cars are moving at the same speed at t = 3.88 seconds.

b. The two autos are moving at a speed of 4.18 cm/s at that moment.

c. The cars pass each other at time t = 1.05 s and t = 2.54 s, respectively.

d. At t = 1.05 seconds, the first car is located at 12.15 cm, and the second car is located at 16.55 cm. At t = 2.54 seconds, the first car is located at 10.69 cm, and the second car is located at 17.39 cm.

What is the speed of the two cars?

The speed of the cars is derived using the formula for linear velocity.

The velocity of the first car is calculated as follows:

v = v₀ + at

where;

The velocity of the second car can be calculated as:

v = v₀

where;

v₀ is the initial velocity since there is no acceleration.

We equate the two velocities of the two cars and solve for time:

-4.40 + 2.70t = 6.10

2.70t = 10.50

t = 3.88 seconds

b. To find the speeds of the cars at time t, we can substitute t = 3.88 seconds in the velocity equation for the first car:

For the first car:

v = -4.40 + 2.70 * 3.88

v = 4.18 cm/s

c. Solving for the time when the positions of the cars are equal allows us to determine when they pass one another.

The position of the first car will be:

x = x₀ + v₀t + 1/2 at²

where x₀ is the initial position.

The position of the second car will be:

x = x₀ + v₀t

equating the two positions equal and solving for time:

13.5 - 4.40t + 1/2 * 2.70t² = 10.5 + 6.10t

1.35t² + 1.70t + 3.00 = 0

Solving the quadratic equation, we get two times:

t = 1.05 s and t = 2.54 s

d. We can re-insert the time values into the position equation for each car to determine where the automobiles were at the times indicated in (c).

For t = 1.05 seconds:

First car:

x = 13.5 - 4.40 * 1.05 + 1/2 * 2.70 * 1.05²

x = 12.15 cm

Second car:

x = 10.5 + 6.10 * 1.05

x = 16.55 cm

For t = 2.54 seconds:

First car:

x = 13.5 - 4.40 * 2.54 + 1/2 * 2.70 * 2.54²

x = 10.69 cm

Second car:

x = 10.5 + 6.10 * 2.54

x = 17.39 cm

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An object with an initial velocity of 5m/s has a constant acceleration of \(2m/s^2\) .The object has traveled a distance of 50 meters when it is speed is 15m/s how far has us travelled​

To find the distance traveled by the object, we can use the equation:

\(v^2 = u^2 + 2as\)

where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Given:

Initial velocity (u) = 5 m/s

Acceleration (a) = 2\(m/s^2\)

Final velocity (v) = 15 m/s

We need to solve for s.

Rearranging the equation, we have:

s =\((v^2 - u^2)\) / (2a)

Substituting the given values, we get:

s = \((15^2 - 5^2)\)/ (2 * 2)

s = (225 - 25) / 4

s = 200 / 4

s = 50 m

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