Answer: 9.97 g (corrected to 3 significant figures.)
Explanation:
mass = no. of moles x molar mass
Atomic mass of Barium = 137.327; oxygen = 15.999,
so the molar mass of BaO = 137.327 + 15.999
=153.326
Hence, the mass is
0.065 x 153.326
=9.97 g (corrected to 3 significant figures.)
Which metric prefix is used for hundredths ( 0.01) ?
. Afternoon rainstorms are common in the rainforest but not in the desert. What is one factor that make deserts less likely to have an afternoon rainstorm? O Low humidity O Low wind and speeds High air pressure O High temperatures
Answer:
Humidity—water vapor in the air—is near zero in most deserts. Light rains often evaporate in the dry air, never reaching the ground. When the air sinks it creates an area of high pressure. These high-pressure areas experience very dry and warm conditions resulting in a hot desert climate (eg the Sahara and Kalahari deserts). Winds blow from areas of high to low pressure, which transfers the air from where it is sinking to where it is rising.
Temperatures exhibit daily extremes because the atmosphere contains little humidity to block the Sun's rays.
yes yes
how many grams of aluminum are in 2.67 moles of aluminum
Answer:
72.0366 gramos de Al
Explanation:
2.67 moles Al* 26.98 gramos Al/ 1 mol Al= 72.0366 gramos de Al
What are miscible liquids?
Answer:
ones that can be mixed together
Explanation:
like water or ethanol
Answer:
miscible liquids are harder to separate as they dissolve in each other
Explanation:
hope this helps!
What else is produced when sodium carbonate decomposes?
Na2CO3 → Na2O + ?
Answer:
Na2CO3 → Na2O + CO2
Explanation:
CO2 is your answer
Answer:
CO2
Explanation:
I Just Took The Quiz
Have A Good Day :)
You may assume the following combustion event locations when analyzing the figures: \begin{tabular}{|l|c|c|} \hline & Design 1 & Design 2 \\ \hline Spurk Crask Angle & −10 deg & −20 deg \\ \hline 10\% MFB Crank Angle & 0 deg & −5 deg \\ \hline 500 MFB Crank Angle & 10 deg & 10 deg \\ \hline 904 MFB Crank Angle & 25 deg & 30 deg \\ \hline \end{tabular} Note that the data series plotted in c) through f) begin at the spark timing. Please compare the two engines at part load unless told otherwise. For (b) through ( g), a complete discussion will include competing factors that affect the primary and secondary parameters of each process, including those that make an event more or less likely, or make a characteristic increase or decrease for each engine design. (a) Construct a table comparing the important parameters of the two designs. At a minimum, the table should highlight the differences in the compression ratio, Φ,EGR level, intake
A table comparing the important parameters of the two engine designs is shown below:ParametersDesign 1Design 2Compression Ratio 18:118:1Φ (Equivalence Ratio)0.75 (Richer)0.65 (Leaner)EGR Level 10%15%Intake Temperature 80°C100°C Intake Pressure 1 bar0.5 bar Intake Valve Closing −15 deg BTDC−25 deg BTDC.
The compression ratio is the ratio of the volume of the combustion chamber from its largest capacity to its smallest capacity. The compression ratio in Design 1 is 18:1, while in Design 2, it is 18:1. The higher compression ratio is seen in Design 1, which will lead to a higher engine efficiency since more fuel energy is converted into useful work.
The Φ (equivalence ratio) is the ratio of the actual air/fuel ratio to the stoichiometric air/fuel ratio. A Φ value of 1.0 indicates a stoichiometric mixture, whereas values less than 1.0 indicate a lean mixture and values greater than 1.0 indicate a rich mixture. The Equivalence ratio in Design 1 is 0.75, which means it is running rich, while in Design 2, it is 0.65, which means it is running lean.
The design 2 engine has a higher Φ (equivalence ratio) level, which may lead to lower NOx emissions due to lean-burn combustion.The EGR (Exhaust Gas Recirculation) level in Design 1 is 10%, whereas in Design 2, it is 15%. The EGR level in Design 2 is higher than that in Design 1, which can help to reduce NOx emissions by lowering the temperature of combustion.
Intake temperature is 80°C in Design 1, whereas in Design 2, it is 100°C. The higher intake temperature in Design 2 means that the engine will have a higher thermal efficiency due to the increased Carnot efficiency.Intake pressure is 1 bar in Design 1, while in Design 2, it is 0.5 bar. The higher intake pressure in Design 1 results in more air being compressed into the combustion chamber, allowing for more fuel to be burned and greater efficiency.
Intake Valve Closing (IVC) is −15 deg BTDC in Design 1 and −25 deg BTDC in Design 2. The IVC timing is responsible for trapping the charge in the combustion chamber and influencing the engine's breathing. The lower IVC timing in Design 2 provides less resistance to flow, resulting in greater volumetric efficiency.
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to what volume should you dilute 130 ml of an 7.90 m cucl2 solution so that 50.0 ml of the diluted solution contains 4.53 g cucl2 ?
To dilute 130 mL of 7.90 M CuCl2 to 1257 mL to obtain a solution that contains 4.53 g of CuCl2 in 50.0 mL of solution.
What is molarity?
Molarity is a unit of concentration that is widely used in chemistry. It is defined as the number of moles of solute per liter (L) of solution.
Calculation
To dilute 130 mL of a 7.90 M CuCl2 solution so that 50.0 mL of the diluted solution contains 4.53 g CuCl2, you need to determine the moles of CuCl2 in 50.0 mL of the diluted solution and then calculate the final volume of the solution.
First, convert 4.53 g of CuCl2 to moles:
4.53 g / (111.00 g/mol) = 0.0407 moles
Next, calculate the molarity of the diluted solution:
0.0407 moles / 0.05 L = 0.814 M
Finally, multiply the initial volume (130 mL) by the ratio of the initial molarity (7.90 M) to the final molarity (0.814 M) to find the final volume:
130 mL * (7.90 M / 0.814 M) = 130 mL * 9.68 = 1257 mL
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Help me:) please and thanks! Part 3
Answer:
then this picture 11 Venkat and one person is
Explanation:
join date 20th December is not a problem with the topic of your name and address of the topic of your name and address of the topic of your name and address of the topic of your life in general is not available in the equation is the topic of your name and address
so nothing in this picture .
you've been paying attention, you may have noticed that the names of certain types of biomolecules have certain characteristic endings. for example, the names of mono- and disaccharides typically end in -ose (ex: glucose, fructose, lactose). for each of the following names, see if you can use the ending of the name as a clue to what type of biomolecule it is! (hint: look at the names of other biomolecules of that type that might have been mentioned in your textbook or lecture notes.) thyroxine is likely to be a lactase is likely to be a raffinose is likely to be a lipase is likely to be a trehalose is likely to be a ornithine is likely to be a
Thyroxine is likely to be a hormone. Lactase is likely to be an enzyme.
Raffinose is likely to be a carbohydrate. Lipase is likely to be an enzyme.
Trehalose is likely to be a carbohydrate. Ornithine is likely to be an amino acid.
The "-ine" ending is not specific to a particular biomolecule type but often used for hormone names.
The "-ase" ending is commonly used for enzymes, indicating their catalytic activity.
The "-ose" ending suggests that it is a type of sugar or carbohydrate.
The "-ase" ending indicates that it is an enzyme involved in the breakdown or metabolism of lipids (fats).
The "-ose" ending suggests that it is a type of sugar or carbohydrate.
Many amino acids have names ending in "-ine" or "-ate." Ornithine is a non-protein amino acid involved in the urea cycle.
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l Jtudell conducted the following reactions: Nis)+Pb black crystals formed and the Ni solid disintegrated Ni(s)+Fe No rxn a. Write the net ionic equations for both of these reactions, gving the "possible"F the second reaction. b. Rank the three metals: Ni, Pb, and Fe based on these 2 reactions. c. Where would Ni be placed on your activity series? 6. A student conducted the following reactions: Ni(s)+Co dark crystals formed and the Ni solid disintegrated Co(s)+N dark crystals formed and the Co solid disintegrated Explain why the student should have immediately known that something was wrong a repeated the tests. Conclusion: Summarize the purpose of the lab, including what an activity series shows. List your activity series. Discuss discrepancies between your activity series and the correct activity these metals. Suggest improvements to the lab. expo
In the first reaction, The net ionic equation for the reaction is: Ni(s) + Pb²⁺(aq) → Ni²⁺(aq) + Pb(s)
In the second reaction, Ni(s) reacts with Fe but no reaction occurs.
Based on these reactions, we can rank the three metals in the following order of reactivity: Ni > Pb > Fe. This is because Ni is reactive enough to displace Pb, but not reactive enough to displace Fe. Ni would be placed above Pb and below Fe in the activity series. In the student's experiment, Ni(s) reacts with Co to form dark crystals and disintegrates, and Co(s) reacts with N to form dark crystals and disintegrate. The student should have known that something was wrong since both Ni and Co cannot displace each other in their respective reactions. This indicates an error in the experiment or an impurity in the reactants.
The purpose of this lab is to determine the activity series of metals, which shows the reactivity of metals in decreasing order. The activity series is useful in predicting the outcomes of single displacement reactions. Based on the given data, the activity series is Ni > Pb > Fe. To improve the lab, ensure the purity of reactants and use accurate measuring tools. Additionally, conduct more tests with different metals to confirm the activity series and account for any discrepancies.
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There are 8.6 x 1025 atoms in a block of Tin (Sn). How many moles is the block of Tin?
Answer:
142.8096978mol
Explanation:
Balance the following equations. Enter 1 as a coefficient for reactants and products which have no coefficient.
___(NH4)2Cr2O7(s)➡️__Cr2O3(s) +___N2(g)+__H2O(g)
CO2(g) +__H20(l)__C6H12O6(s) +__C2(g)
1(NH4)2Cr2O7(s) → 1Cr2O3(s) + 1N2(g) + 4H2O(g).
6CO2(g) + 6H2O(i) → 1C6H12O6(s) + 6C2(g).
What types of reactants and the products are examples?Energy (the candlewick & wax) & oxygen are the reactants in the burning of a candle (in the air).Carbon dioxide and water vapor are the end results.
What distinguishes reactants from products?When K is bigger than 1, the reaction's products are preferred.The reactants inside the reaction were favored if K is much less than 1.When K is 1, neither the reactants nor the products are preferred.
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your teacher presents you with an unlabeled sample of an element. which of the following might you use to determine if the sample is a metal or a non-metal?
Hydrogen, helium, carbon, nitrogen, oxygen, fluorine, neon, phosphorus, sulfur, chlorine, argon, selenium, bromine, krypton, iodine, xenon, and radon are among the 17 nonmetal elements.
Which element is categorically not a metal? There are 17 non-metal elements, including helium, hydrogen, carbon, nitrogen, oxygen, fluorine, neon, phosphorus, sulfur, chlorine, argon, selenium, bromine, krypton, iodine, xenon, and radon.Copper is a highly conductive metal that is only surpassed by silver.As a result, electricity can move through it more easily, making it perfect for use in electrical wires.All substances have consistent boiling points, melting points, specific heats, and densities.Unknown chemicals in a mixture can be located using these characteristics.The valence electrons in them are equal in number.The nonmetals are to the right of the line, the metalloids are exactly next to it, and the metals are to the left of the line (except from hydrogen, which is a nonmetal).To learn more about nonmetal elements refer
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Q.does salt make water boil at a higher temperature?
Answer:
Yes
Explanation:
The salt increases the boiling point, meaning it make water boil at a higher temperature, and it decreases the specific heat capacity, meaning it will heat up quick.
Mass (g) to mass (g)
2Na + 2H2O >2NaOH+ H2
How many moles of NaOH are produced if 120 grams of H2O are available?
Answer:
4.44 g
Explanation:
First, we need to determine the limiting reactant. The balanced chemical equation is:
2Na + 2H2O → 2NaOH + H2
From the equation, we see that 2 moles of sodium reacts with 2 moles of water to produce 1 mole of hydrogen.
Moles of Na in 120 g of Na:
Molar mass of Na = 22.99 g/mol
Number of moles of Na = mass/molar mass = 120 g / 22.99 g/mol = 5.22 mol
Moles of water in 80 g of H2O:
Molar mass of H2O = 18.02 g/mol
Number of moles of H2O = mass/molar mass = 80 g / 18.02 g/mol = 4.44 mol
Since 5.22 moles of Na requires 5.22 moles of H2O, water is the limiting reactant.
The moles of hydrogen produced is equal to the moles of the limiting reactant, which is 4.44 mol.
The mass of hydrogen produced is:
Mass = number of moles x molar mass
Mass = 4.44 mol x 1 g/mol = 4.44 g
So the grams of hydrogen produced by the 120 grams Na and 80 grams of water is 4.44 grams.
This piece of paper has been tuned into a work of art with many vibrant colors and decorated with multiple shapes, but it is still a piece of paper. Coloring and drawing on paper is an example of the [ Select ] properties of paper.
Answer:
Physical property
Explanation:
As the piece of paper is being colored, no change has really occurred, in the end it's still a paper, unless a substance was mixed with it or etc then it would be considered to be a chemical property but not in this case.
Describe how you could feel weightless on earth
Answer:
gravity is the explination
Explanation:
the original cell density in a sample if 2.79 x 106 cfu/ml. which sample volume should yield a countable plate? (express your answer as 10x ml).
If the original cell density in a sample if 2.79 x 106 cfu/ml, \(10^{-1}\) mL or 0.1 mL. which sample volume should yield a countable plate.
To determine the sample volume that should yield a countable plate, we need to estimate the number of colonies that will grow on the plate. A countable plate is one that has between 30 and 300 colonies.
Assuming we want to use a standard Petri dish with a diameter of 90 mm, the surface area of the plate is:
\(Area = \pi * (diameter/2)^2 = 3.14 * (90/2)^2 = 6351 mm^2\)
To estimate the number of colonies that will grow on the plate, we need to dilute the original sample to a concentration that will yield between 30 and 300 colonies. A common dilution factor used in microbiology is \(10^{-6\), which means we will dilute the original sample by a factor of 1 million.
The calculation for dilution is:
\(C_1V_1 = C_2V_2\)
where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.
Let's assume we want to plate 0.1 mL of the diluted sample on the plate. We can calculate the dilution factor as follows:
\(C_1V_1 = C_2V_2\)
\((2.79 * 10^6 \ cfu/mL) * V_1 = (2.79 *\ 10^6 \ cfu/mL) * 10^{-6} * 0.1 mL\\V_1 = 0.1 mL / 10^{-6} = 10^5 mL\)
This means we need to take 0.1 mL of the \(10^{-6\) diluted sample (which is equivalent to \(10^5\) times diluted) and plate it on the agar surface.
To check if this sample volume will yield a countable plate, we can estimate the number of colonies that will grow on the plate:
Number of colonies = (CFU/mL) × (plated volume) × (reciprocal of dilution factor)
Number of colonies = \((2.79 * 10^6 cfu/mL) * 0.1 mL * 10^6 = 279 colonies\)
This is within the range of 30 to 300 colonies, so a sample volume of 0.1 mL should yield a countable plate.
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The electron configuration of an element is 1s²2s22p5. Will a bond form if an atom of this element moves towards an atom with
one valence electron? Why or why not?
The given electron configuration belongs to the element fluorine (F).
If an atom of fluorine approaches an atom with one valence electron (such as an alkali metal atom), a bond can form. Fluorine has seven valence electrons, and it requires one more electron to complete its octet (i.e., eight valence electrons) and achieve a stable electron configuration.
Therefore, fluorine will tend to gain one electron from the atom with one valence electron, forming a stable ionic compound. Alternatively, fluorine could share one electron with the atom with one valence electron, forming a covalent bond, but this is less likely due to the large difference in electronegativity between fluorine and alkali metals.
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Forensic psychiatry focuses on the relationship between human behavior and criminal justice.
O True
O False
what type of reaction takes place between methane and chlorine
Answer and Explanation:
When methane (CH4) and chlorine (Cl2) react, a substitution reaction takes place. Specifically, the reaction is a halogenation reaction, in which one or more hydrogen atoms in the methane molecule are replaced by chlorine atoms. The reaction can be represented by the following equation:
CH4 + Cl2 → CH3Cl + HCl
In this equation, CH3Cl represents chloromethane, which is a type of organochlorine compound. The reaction is typically initiated by ultraviolet (UV) light or heat, and it proceeds through a series of free radical chain reactions. The products of the reaction are typically a mixture of chloromethane and hydrogen chloride (HCl) gas.
What volume will 250. mL of gas at STP occupy ig the pressure changes to 2.0 atmospheres and the temperature changes at 30 degrees Celsius
Answer:
it is 75 degrees
Explanation:
Volume is 138.7 mL.
The equation for calculation of volume is as follows:-
\(\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}\)
STP:-
Temperature=273 K
Pressure=1 atm
\(\frac{1 atm\times250mL}{273 K} =\frac{2 atm\times V_2}{303\ K}\\V_2=138.7\ mL\)
Hence, the volume is 138.7 mL.
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Which of the following 1H-NMR signals would allow for researchers to differentiate between colchicine and IA? A. Large peaks at 7 ppm B. Several peaks between 0 and 5 ppm C. A doublet at 8.5 ppm D. A signal at 3.4 ppm
Peaks around 5-8.5 ppm indicate amide (R(C=O)NR₂) hydrogens in NMR which help researchers to differentiate between colchicine and IA.
Nuclear magnetic resonance (NMR) is a physical phenomenon in which nuclei are placed in a strong constant magnetic field are perturbed by a weak oscillating magnetic field (in the near field) and respond to an electromagnetic signal which has a frequency which is indicative of the magnetic field at the nucleus. Thus help in differentiation of peaks.
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unicellular organisms reproduce using sexual or
asexual reproduction?
With a balanced chemical equation state five ways to prepare a base
There are several ways to prepare a base, also known as an alkaline solution, using balanced chemical equations. Here are five examples:
CaO + H2O → Ca(OH)2
NaOH + HCl → NaCl + H2O
K2CO3 + H2SO4 → K2SO4 + H2O + CO2
NH3 + H2O → NH4OH
2K + 2H2O → 2KOH + H2
Reaction between a metal oxide and water:
Metal oxide + water → metal hydroxide
For instance, when calcium oxide (CaO) reacts with water (H2O), it forms calcium hydroxide (Ca(OH)2):
CaO + H2O → Ca(OH)2
Reaction between a metal hydroxide and an acid:
Metal hydroxide + acid → salt + water
An example is the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl), producing sodium chloride (NaCl) and water (H2O):
NaOH + HCl → NaCl + H2O
Reaction between a metal carbonate and an acid:
Metal carbonate + acid → salt + water + carbon dioxide
An example is the reaction between potassium carbonate (K2CO3) and sulfuric acid (H2SO4), resulting in potassium sulfate (K2SO4), water (H2O), and carbon dioxide (CO2):
K2CO3 + H2SO4 → K2SO4 + H2O + CO2
Reaction between ammonia gas and water:
Ammonia gas + water → ammonium hydroxide
When ammonia gas (NH3) dissolves in water (H2O), it forms ammonium hydroxide (NH4OH):
NH3 + H2O → NH4OH
Reaction between an alkali metal and water:
Alkali metal + water → metal hydroxide + hydrogen gas
For example, when potassium (K) reacts with water (H2O), it forms potassium hydroxide (KOH) and releases hydrogen gas (H2):
2K + 2H2O → 2KOH + H2
These are just a few examples of how bases can be prepared through chemical reactions.
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how is natural gas similar to solar energy?
Natural gas and solar energy, both are obtained by nature. Solar energy is much more ecofriendly as compared to natural gas.
Like oil and coal, natural gas represents a fossil fuel which was created when extinct animals and plants from the past were gradually buried behind layers of rock. On the contrary hand, solar energy is generated by the sun, which is unbounded. Biomass, geothermal, hydroelectricity, solar, wind, and other alternative energy resources are some of the most prevalent types. Natural gas and solar energy, both are obtained by nature. Solar energy is much more ecofriendly as compared to natural gas.
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(06.06 MC)
A gaseous product has a mass of 2.34 g and occupies a volume of 0.854 L. The
temperature in the laboratory is 302 K, and the air pressure is 1.04 atm. Calculate
the molar mass of the gas. (3 points)
1) 22.4 g/mol
2) 44.0 g/mol
3) 65.3 g/mol
4) 86.9 g/mol
The molar mass of the gas is 65.3 g/mol
How to determine the mole of the gas Volume (V) = 0.854 L.Temperature (T) = 302 KPressure (P) = 1.04 atmGas constant (R) = 0.0821 atm.L/Kmol Number of mole (n) =?The number of mole of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side by RT
n = PV / RT
n = (1.04 × 0.854) / (0.0821 × 302)
n = 0.0358 mole
How to determine the molar mass Mass = 2.34 gNumber of mole = 0.0358 mole Molar mass =?Molar mass = mass / mole
Molar mass = 2.34 / 0.0358
Molar mass of gas = 65.3 g/mol
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Answer:
65.3 g/mol
Explanation:
use the ideal gas law with molar mass formula
M = mRT/PV
m= 2.34 g
V = 0.854 L
T = 302k
P = 1.04
R = 0.0821
just plug those in and solve
how do isotopes of a given element differ?
Answer:
they have different mass numbers
Explanation:
The following equation represents what type of chemical reaction?
2Ag + H2S → Ag2S + H2
A. Double Replacement
B. Single Replacement
C. Decomposition
D. Synthesis
Answer:
single replacement
Explanation: N/A
1. State the general period and group trends among
main-group elements with respect to each of the
following properties:
a. atomic radii
b. first ionization energy
c. electron affinity
d. ionic radii
e. electronegativity
2. a. In general, how do the periodic properties of
the d-block elements compare with those of
the main-group elements?
b. Explain the comparison made in (a).
3. For each main-group element, what is the
relationship between its group number and
the number of valence electrons that the group
members have?
Explanation:
ok so I believe:
a. increase in atomic radii going down a group and decrease going across a period.
b. increase in IE1 going across a period and up a group. the highest IE1 elements are like He, Ne, F and first ionization energy decreases moving further away from those elements moving south west on the periodic table.
c. electron affinity increases moving across a period left to right.
d. ionic radii increases going down a group and decreases going across a period left to right
e. electronegativity increases across a period but decreases down a group. (opposite for electropositivity)
what is meant by the d-block elements? are you referring to the spdf location?