Select the correct answer.
What is the solution for x in the equation? 5/3x+4=2/3x

Answer:the value would be 6-10

Step-by-step explanation:

Answer:

The range is also all real numbers except zero. You can see that there is some point on the curve for every y -value except y=0 . Domains can also be explicitly specified, if there are values for which the function could be defined, but which we don't want to consider for some reason.

Step-by-step explanation:

hope this helps

Answer:

5.99696 or 6

Step-by-step explanation:

It will take approximately 70 minutes to download 420 megabytes at a rate of 100 kilobytes per second.

To calculate how long it will take to download 420 megabytes at a rate of 100 kilobytes per second, we need to convert the units.

First, let's convert 100 kilobytes per second to megabytes per second. Since 1 megabyte is equal to 1000 kilobytes, we divide 100 kilobytes by 1000 to get 0.1 megabytes. So the download speed is 0.1 megabytes per second.

Next, we divide 420 megabytes by 0.1 megabytes per second to find the time it will take to download. This gives us 4200 seconds.

Since we want the answer in minutes, we divide 4200 seconds by 60 (since there are 60 seconds in a minute). This gives us 70 minutes.

Therefore, it will take approximately 70 minutes to download 420 megabytes at a rate of 100 kilobytes per second.

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Answer:2√12 π

Step-by-step explanation:

The formula for area of circle = r^2 π

Since the question tells us that the area of the circle is 12π, we can make r^2 π = 12π, so r^2 = 12 when we cancel π from both sides. Then, r = √12.

The formula for circumference of circle = 2πr

We can now plug in √12 for r and we'll get 2√12 π.

To express the area of the shaded region, set up one or more definite integrals using the given functions as limits of integration, either with respect to x or y.

To express the area of the shaded region in terms of one or more integrals, first identify the functions that bound the region. Let f(x) and g(x) be the functions bounding the region in the x direction, and h(y) and k(y) be the functions bounding it in the y direction.

(a) With respect to x: Area = ∫[g(x) - f(x)] dx, evaluated from a to b, where a and b are the limits of integration in the x direction.

(b) With respect to y: Area = ∫[k(y) - h(y)] dy, evaluated from c to d, where c and d are the limits of integration in the y direction.

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The numbers for the condition are 14 and -5.

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

Given  two numbers,

let the numbers be a and b,

and the product of a and b is -70.

a x b = -70

a = -70/b

addition of numbers is 9

a + b = 9

substitute value of a

-70/b + b = 9

b² - 9b - 70 = 0

factors of equation are

b² + 5b - 14b - 70 = 0

(b + 5)(b - 14) = 0

b = -5 and b = 14

when b = -5, a = 14

and when b = 14, a = -5

Hence the numbers are -5 and 14.

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a. The probability of drawing a red ball from Box 1 is 30%.

b. If a red ball is drawn from Box 1, the probability of drawing another red ball from Box 2 on the second round is 60%.

c. If the first draw from Box 1 was black, the conditional probability of drawing a red ball from Box 3 on the second draw is 80%.

d. The probability of drawing two red balls at both draws, without any prior information, is 46%.

e. The probability of drawing a red ball at the first draw and a black ball at the second draw, without any prior information, is 21%.

a. The probability of drawing a red ball from Box 1 can be calculated by dividing the number of red balls in Box 1 by the total number of balls in Box 1. Therefore, the probability is 3/(3+7) = 3/10 = 0.3 or 30%.

b. Since a red ball was drawn from Box 1, we only consider the balls in Box 2. The probability of drawing a red ball from Box 2 is 6/(6+4) = 6/10 = 0.6 or 60%. Therefore, the probability of drawing another red ball when the first ball drawn from Box 1 is red is 60%.

c. If the first draw from Box 1 was black, we only consider the balls in Box 3. The probability of drawing a red ball from Box 3 is 8/(8+2) = 8/10 = 0.8 or 80%. Therefore, the conditional probability of drawing a red ball from Box 3 when the first ball drawn from Box 1 was black is 80%.

d. Before any draws, the probability of drawing two red balls at both draws can be calculated by multiplying the probabilities of drawing a red ball from Box 1 and a red ball from Box 2. Therefore, the probability is 0.3 * 0.6 = 0.18 or 18%. However, since there are two possible scenarios (drawing red balls from Box 1 and Box 2, or drawing red balls from Box 2 and Box 1), we double the probability to obtain 36%. Adding the individual probabilities of each scenario gives a total probability of 36% + 10% = 46%.

e. Before any draws, the probability of drawing a red ball at the first draw and a black ball at the second draw can be calculated by multiplying the probability of drawing a red ball from Box 1 and the probability of drawing a black ball from Box 2 or Box 3. The probability of drawing a red ball from Box 1 is 0.3, and the probability of drawing a black ball from Box 2 or Box 3 is (7/10) + (2/10) = 0.9. Therefore, the probability is 0.3 * 0.9 = 0.27 or 27%. However, since there are two possible scenarios (drawing a red ball from Box 1 and a black ball from Box 2 or drawing a red ball from Box 1 and a black ball from Box 3), we double the probability to obtain 54%. Adding the individual probabilities of each scenario gives a total probability of 54% + 10% = 64%.

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Answer:

1

Step-by-step explanation:

Tickets prices (per unit):

Adults: $4

Students: $3

Tickets sold: 2480

Earnings: $8250

If the school sold A adult tickets and S student tickets, then we have:

A + S = 2480

or

S = 2480 - A ...(1)

For the total earnings:

Earnings for adult tickets = 4*A

Earnings for student tickets = 3*S

Total earnings = 4A + 3S = 8250 ...(2)

If we replace (1) on (2):

4A + 3*(2480 - A) = 8250

Solving for A:

4A - 3A + 7440 = 8250

A = 8250 - 7440

A = 810

Now, from (1):

S = 2480 - 810

S = 1670

We conclude that 810 adult tickets and 1670 student tickets were sold during the school fair.

The weight of the melted ice cream would be the same as the weight of the original ice cream, which is 5 ounces.

a quantity or thing weighing a fixed and usually specified amount. : a heavy object (such as a metal ball) thrown, put, or lifted as an athletic exercise or contest. 3. : a unit of weight or mass see Metric System Table.

When the ice cream melts, it undergoes a change in state from solid to liquid, but the total mass or weight remains unchanged. Therefore, the weight of the melted ice cream is still 5 ounces.

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The answer  is 4 - 4yi + y2, .We need to expand it using the rules of exponents.

We need to expand the expression (2 - yi)2 using FOIL (First, Outer, Inner, Last). (2 - yi)2 = (2 - yi)(2 - yi)
= 2(2) - 2(yi) - y(i)(2) + (yi)(i)
= 4 - 4yi + yi2
= 4 - 4yi + y2
So the simplest form of (2 - yi)2 is 4 - 4yi + y2.

To find the simplest form of (2 - yi)², where i is the imaginary unit, you need to expand and simplify the expression. First, you'll apply the formula (a - b)² = a² - 2ab + b². In this case, a = 2 and b = yi. After applying the formula, you'll get (2)² - 2(2)(yi) + (yi)². Next, you'll simplify each term. (2)² = 4, -2(2)(yi) = -4yi, and (yi)² = (y²)(i²). Since i² = -1, then (yi)² = -y². Finally, combining the terms, you'll have 4 - 4yi - y² as the simplest form of (2 - yi)².

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Answer:

The linear equation is y = 450 - 30 x, where y is the number of pages

Lourdes has left to read after x days

Step-by-step explanation:

Each day, Lourdes reads 30 pages of a 450-page book

- We need to write a linear equation to represent the number of pages

 Lourdes has left to read after x days

∵ Lourdes reads 30 pages each day

∵ Lourdes will read for x days

∴ The number of pages Lourdes will read in x day = 30 x

- The left pages will be the difference between the total pages of the

 book and the pages Lourdes read

∵ The book has 450 pages

∵ Loured will read 30 x in x days

∴ The number of pages left = 450 - 30 x

- Assume that y represents the number of pages Lourdes has left

 to read after x days

∴ y = 450 - 30 x

The linear equation is y = 450 - 30 x, where y is the number of

pages Lourdes has left to read after x days

No, the tangents cannot intersect outside the circle.

When tangents intersect outside a circle, the measure of the angle they form is one half the difference of the intercepted arcs. Since the tangents are at the endpoints of the same diameter, both intercepted arcs would have to measure 180 degrees.

tangent

a tangent is the line drawn from an external point and passes through a point on the curve.

One real-life example of a tangent is when you ride a bicycle, every point on the circumference of the wheel makes a tangent with the road.

curve

A curve is a shape or a line which is smoothly drawn in a plane having a bent or turns in it.

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Answer:

y= -6/5x - 8

Step-by-step explanation:

I just used desmos easy to use and you understand how graphs work more.

a. Var[X] = E[X^2] = 1/10.

b. Expected cost E[70X^4] is 3.

We need to first find E[X^2]. Since E[X] = 0, the variance Var[X] = E[X^2].

∫ x^2 * f(x) dx,
We assume the domain of the PDF to be [-1, 1], as f(x) = 0.75(1-x^2) is only positive in that range.
E[X^2] = ∫(-1 to 1) x^2 * 0.75(1-x^2) dx
E[X^2] = 0.75 ∫(-1 to 1) x^2 - x^4 dx
E[X^2] = 0.75 * (1/3 - 1/5) = 0.75 * (2/15) = 1/10
Thus, Var[X] = E[X^2] = 1/10.

To calculate ∫ 70x^4 * f(x) dx over the domain [-1, 1].
E[70X^4] = ∫(-1 to 1) 70x^4 * 0.75(1-x^2) dx
Now, compute the integral:
E[70X^4] = 52.5 ∫(-1 to 1) x^4 - x^6 dx
E[70X^4] = 52.5 * (1/5 - 1/7) = 52.5 * (2/35) = 3
Thus, the expected cost E[70X^4] is 3.

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Explanation:

The range is y ≤ 2 which means that y = 2 is the largest y can get. The parabola opens downward to form a sort of "frowny face" so to speak. When moving down the parabola, we'll cross the x axis at two different spots. An example of this is shown below with the equation y = -x^2+2.

There's no connection between the '2' in y ≤ 2 and the final answer of 2 roots. We could easily have a range of something like y ≤ 5 or y ≤ 8 and the answer will still remain as 2. The most roots a parabola can have is 2.

Answer:

2

Step-by-step explanation:

i got it right

Answer:

Y=-65.25x

Step-by-step explanation:

Answer:

v = 2/5    Or    v = 0.4

Step-by-step explanation:

12/5 = 6v

to isolate V divide both sides by 6

(12/5) : (6)= 6v : (6)

For the left side because there is a fraction when you devide you change it into multiplication, flipping the addent and quotient so you’ll have

12/5 * 1/6  (you semplify the cross numbers) you’ll have 2/5

on the right side the 6 cancel each other. Because 6/6 = 1. so you will have 1v which is v.

2/5 = v

or decimal form

0.4 = V

Answer:

The rate of change is: as x increases by 10, y increases by 30. In other words, the rate of change is +30

Step-by-step explanation:

When calculating rate of change you see how much the y increases/decreases each time the x increases/decreases as we see, each time the x goes up by 10 the y goes up by 30.

In a comprehensive headache treatment program, people who were low users of analgesic medications achieved at least a 50 percent reduction in headache pain.

A comprehensive headache treatment program is a multi-disciplinary approach to managing and treating headaches. It typically involves a team of healthcare professionals, such as neurologists, pain specialists, psychologists, physical therapists, and nutritionists, who work together to develop a personalized treatment plan for the patient.

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Based on the information provided, 2 is not a solution of x>5 because a possible solution requires a number greater than 5.

Inequalities include symbols such as >, ≤, ≥, among others that should be interpreted correctly to solve the inequality. In this case, the symbol in the inequality is >, which means greater than. Based on this, the value of x should be greater than 5, for example, 7, 19, 2948, etc.

Therefore, 2 is not a solution to the inequality x>5 because a number greater than 5 rather than less than 5 is required to solve this expression.

Note: This question is incorrect and incomplete; here is the complete question:

Explain why 2 is NOT a solution of x>5

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Since the quadrilaterals are similar, then, corresponding sides of them are proportional. Then:

Substitute the length of each segment into the equation and solve for x:

Therefore:

Answer:

Step-by-step explanation:

g to the power of 8 *h hope this helped

nh to the power of 8

a. The equation in slope-intercept form is y = -2x + 2.

b. A table for the equation is shown below.

c. A graph of the points with a line for the inequality is shown below.

d. The solution area for the inequality has been shaded.

e. Yes, the test point (0, 0) satisfy the conditions of the original inequality.

In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;

y = mx + b

Where:

Part a.

In this exercise, we would change each of the inequality to an equation in slope-intercept form by replacing the inequality symbols with an equal sign as follows;

2x + y ≤ 2

y = -2x + 2

Part b.

Next, we would complete the table for each equation based on the given x-values as follows;

x       -1        0        1

y        4        2       0

Part c.

In this scenario, we would use an online graphing tool to plot the inequality as shown in the graph attached below.

Part d.

The solution area for this inequality y ≤ -2x + 2 has been shaded and a possible solution is (-1, 1).

Part e.

In conclusion, we would use the test point (0, 0) to evaluate the original inequality.

2x + y ≤ 2

2(0) + 0 ≤ 2

0 ≤ 2 (True).

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Answer/Step-by-step Explanation:

Given, \(\frac{3}{4}*-4\frac{2}{9}\)

Ivy solves this problem by writing each number as a fraction and then multiplies as shown below:

\( \frac{3}{4}*-4\frac{2}{9} = \frac{3}{4}* -\frac{38}{9} \)

\( = \frac{3}{4}*-\frac{38}{9} = -\frac{3*38}{4*9} = -\frac{1*19}{2*3}\)

\(= -\frac{19}{6}\)

Fabian solves this problem by writing the mixed number as a sum and applies the distributive method of multiplication as shown below:

\( \frac{3}{4}*-4\frac{2}{9} = \frac{3}{4}(-4 + -\frac{2}{9}) \)

\( = \frac{3}{4}*-4 + \frac{3}{4}*-\frac{2}{9} \)

\( = -\frac{3}{1} + \frac{1}{2}*-\frac{1}{3} \)

\( = -3 + (-\frac{1}{6}) \)

\( = -3 - \frac{1}{6} = -3\frac{1}{6} \)

You need 12 bags of mulch to cover 200 ft^2 to a depth of 4 in. The answer is A. 12 bags.

Joint variation is a type of variation in which a quantity varies directly with two or more other quantities. In other words, the value of the first quantity depends on the values of the other two quantities, and changes in the values of either of the other two quantities will affect the value of the first quantity.

The joint variation formula can be expressed as follows:

y = kx1x2

where y is the dependent variable, x1 and x2 are the independent variables, and k is a constant of variation that is specific to the particular problem. The constant k can be found by substituting the values of the variables and solving for k.

For example, if y is the amount of paint needed to paint a wall, and x1 is the length of the wall and x2 is the height of the wall, then the joint variation formula would be:

y = kx1x2

where k is a constant that depends on the type of paint being used and other factors.

Joint variation can be used to model various types of real-world problems, such as the amount of water required for irrigation based on the area of land and the type of crop being grown, or the amount of force required to lift an object based on its weight and the angle of the lift.

In summary, joint variation is a type of variation in which a quantity varies directly with two or more other quantities. The joint variation formula is y = kx1x2, where y is the dependent variable, x1 and x2 are the independent variables, and k is a constant of variation. Joint variation can be used to model various types of real-world problems.

We can use the joint variation formula to solve this problem, which states that:

k = a * d * b

where k is a constant of variation, a is the area to be mulched, d is the depth of the mulch, and b is the number of bags needed to mulch the area and depth specified.

We can start by using the given information to find the value of k:

10 = 120 * (3/12) * b

10 = 30 * b

b = 10/30

b = 1/3

Now we can use k to find the number of bags needed to mulch 200 ft^2 to a depth of 4 in.:

k = a * d * b

k = 200 * (4/12) * (1/3)

k = 80/3

So the number of bags needed is:

b = k / (a * d)

b = (80/3) / (200 * (4/12))

b = 12

Therefore, you need 12 bags of mulch to cover 200 ft^2 to a depth of 4 in. The answer is A. 12 bags.

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Answer:

Option 4

Step-by-step explanation:

You divide 1/2 by the whole problem

5x-15=20

and go from there its too long to explain but its option 4

Answer:

6cm

Step-by-step explanation:

Given data

Width= 4.6cm

Length= 9cm

Volume= 82.8cm^3

The expression for the volume is given as

V= lwh/3

82.8= 9*4.6*h/3

cross multiply

82.8*3= 9*4.6*h

248.4= 41.4h

h= 248.4/41.4

h= 6cm

Answer:

true

to find missing side u need to use Pythagoras theorem

hope it helps