Using the perpendicularity concept, the values of a and b so that x is perpendicular to y are: a = 39º, b = 38º.
What are perpendicular lines?Two lines are perpendicular if when they intersect two angles of 90º are formed.
Hence, the condition for this problem is given by:
m<2 = 90º.m<3 = 90º.From condition 2, the value of a is found as follows:
3a - 27 = 90º
3a = 117º
a = 117/3
a = 39º.
From condition 3, the value of b is found as follows:
2b + 14 = 90º
2b = 76º
b = 76/2
b = 38º.
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a fair coin is tossed 25 times. what is the probability that at most 22 heads occur?
a) 0.999922
b) 0.000078
c) 0.999990
d) 0.000069
e) 0.000010
0.99999028444 is the probability that at most 22 heads occur.
What does the maths term "probability" mean?
The simple definition of probability is the likelihood that something will occur. We can discuss the probability of different outcomes if we are unclear of how an event will turn out. Probability is a measure of how likely or likely-possible something is to happen.
For instance, there is only one method to receive a head and there are a total of two possible outcomes, hence the chance of flipping a coin and receiving heads is 1 in 2. (a head or tail). P(heads) = 12 is what we write.
probability of getting head, P = 1/2 = 0.5
q = 1 - p = 1 - 0.5 = 0.5 and n = 25
P(X ≤ 22)
P(X = x ) = ⁿCₓ (q)ⁿ⁻ˣ (p)ˣ
= 1 - P(x = 23) - P(24) - P(25)
= 1 - ²⁵C₂₃(0.5)²⁵⁻²³ (0.5)²³ - ²⁵C₂₄ (0.5)²⁵⁻²⁴ (0.5)²⁴ - ²⁵C²⁵ (0.5)²⁵⁻²⁵ (0.5)²⁵
= 0.99999028444
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What is the equation of the line that passes through the coordinates (-2, 11) and (1, -34)?
Answer:
y = 15x - 19
Step-by-step explanation:
In order to pass through both (-2, 11) and (1, -34), then the equation must be y = 15x - 19. Hope this helps!
Find and classify the critical points of the function: f(x, y) = x³y - 2x² - 2y²-y
The critical points of the function f(x, y) = x³y - 2x² - 2y² - y are (0, -1/4) (local maximum), and the solutions to the equation 3x²y - 4 = 0 (additional critical points obtained numerically).
To find the critical points of the function f(x, y) = x³y - 2x² - 2y² - y, we need to find the partial derivatives ∂f/∂x and ∂f/∂y and set them equal to zero:
∂f/∂x = 3x²y - 4x,
∂f/∂y = x³ - 4y - 1.
Setting ∂f/∂x = 0 and ∂f/∂y = 0, we have:
3x²y - 4x = 0,
x³ - 4y - 1 = 0.
From the first equation, we can factor out x:
x(3x²y - 4) = 0.
This gives us two possibilities:
x = 0,
3x²y - 4 = 0.
If x = 0, then substituting into the second equation gives -4y - 1 = 0, which gives y = -1/4.
So one critical point is (x, y) = (0, -1/4).
If 3x²y - 4 = 0, then we can solve for y:
3x²y = 4,
y = 4 / (3x²).
Substituting this into the second equation, we have:
x³ - 4(4 / (3x²)) - 1 = 0,
x³ - 16 / (3x²) - 1 = 0.
To simplify the equation, let's multiply through by 3x² to eliminate the denominator:
3\(x^5\) - 16 - 3x² = 0.
Unfortunately, this equation cannot be easily solved algebraically. We need to use numerical methods or approximation techniques to find the solutions.
To classify the critical point (x, y) = (0, -1/4), we can calculate the second-order partial derivatives:
∂²f/∂x² = 6xy - 4,
∂²f/∂y² = -4,
∂²f/∂x∂y = 3x².
Calculating the discriminant D = (∂²f/∂x²) × (∂²f/∂y²) - (∂²f/∂x∂y)²:
D = (-4) × (6xy - 4) - (3x²)².
Plugging in the critical point (0, -1/4), we have:
D(0, -1/4) = (-4) × (-4) - (3(0)²)² = 16 - 0 = 16.
Since D(0, -1/4) = 16 > 0 and ∂²f/∂x²|(0, -1/4) = -4 < 0, the critical point (0, -1/4) is a local maximum.
Therefore, the critical points of the function f(x, y) = x³y - 2x² - 2y² - y are (0, -1/4) (local maximum), and the solutions to the equation 3x²y - 4 = 0 (additional critical points obtained numerically).
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What is image in maths class 11?
An image may be defined as that point, where the light rays coming from an object meet or appears to meet after reflection or refraction.
In this definition, the word 'object' may be defined as anything from which light rays are coming.
A function f from a set A to a set B is a special relation in
which, every element of set A has unique image in set B.
The function f from A to B is denoted by f : A →
If, f(a) = b, then ‘b’ is called the image of ‘a’ under f and ‘a’
is called the pre image of ‘b’ under f.
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A new laptop costs $1 ,245 a new printer costs $365, an external hard drive costs $345, and a -year protection plan costs $329. Estimate the total cost by rounding each number to the nearest hundred.
To the nearest hundred, the cost of each item is:
Laptop: $1,200
Printer: $400
External hard drive: $300
Protection plan: $300
Add the rounded costs of the items to estimate the total cost:
\(\begin{gathered} 1200+400+300+300 \\ =1600+300+300 \\ =1900+300 \\ =2200 \end{gathered}\)Therefore, the estimated total cost is:
\(\text{ \$2200}\)use
algebra tiles to represent polynomial.
13 POINTS
Simplify the following expression
To simplify the expression "a^0b^-2c," we can apply the rules of exponents:
First, any number raised to the power of 0 is equal to 1. Therefore, "a^0" simplifies to 1.
Next, to simplify "b^-2," we can apply the rule that states "a^-n = 1/a^n." In this case, "b^-2" simplifies to "1/b^2."
Finally, we have "1 * 1/b^2 * c," which can be simplified as "c/b^2."
Therefore, the simplified exponents is "c/b^2."
The term "power" refers to the repeated multiplication of a factor, while the term "exponent" refers to the number increased to that base factor. The primary distinction between expression and power is this. The power 32, for instance, has a base of 3 and an exponent of 2.
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Determine whether the events are overlapping or disjoint. You draw a card from a standard deck of 52 playing cards. Event a: you draw a heart. Event b: you draw an odd-numbered card. Responses overlapping overlapping disjoint disjoint question 2 state the number of ways in which a or b can occur. Ways
There are 33 ways in which event a or b can occur.
For the given events:
Event a: You draw a heart.
Event b: You draw an odd-numbered card.
The events are overlapping because it is possible for a card to satisfy both conditions (being a heart and an odd-numbered card). Specifically, the card "3 of Hearts" satisfies both events.
To determine the number of ways in which either event a or b can occur, we can calculate the number of cards that satisfy each event and then subtract the overlap (the card that satisfies both events).
Number of ways event a can occur:
There are 13 hearts in a deck, so there are 13 ways to draw a heart.
Number of ways event b can occur:
There are 26 odd-numbered cards in a deck (Ace, 3, 5, 7, 9, Jack), so there are 26 ways to draw an odd-numbered card.
Number of ways event a and b can occur:
There are 6 odd-numbered hearts in a deck (3 of Hearts, 5 of Hearts, 7 of Hearts, 9 of Hearts, Ace of Hearts, Jack of Hearts), so there are 6 ways to draw a card that satisfies both events.
Therefore, the number of ways in which either event a or b can occur is:
Ways = (Number of ways event a can occur) + (Number of ways event b can occur) - (Number of ways event a and b can occur)
= 13 + 26 - 6
= 33
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Question 4 of 10
The standard form of the equation of a parabola is y=x²-6x+14.
What is the vertex form of the equation?
OA y=(x-3)2 +15
OB. y = (x+3)(x-3) +5
O C. y=(x-3)2 +23
OD. y=(x-3)² +5
The vertex form of the equation is y = (x - 3)² - 4, which corresponds to option OD.
To convert the given equation from standard form to vertex form, we need to complete the square.
The vertex form of a parabola's equation is y = a(x-h)² + k, where (h, k) represents the vertex of the parabola.
Given equation: y = x² - 6x + 14
Move the constant term to the right side:
y - 14 = x² - 6x
Complete the square by adding and subtracting the square of half the coefficient of x:
y - 14 + 9 = x² - 6x + 9 - 9
Group the terms and factor the quadratic:
(y - 5) = (x² - 6x + 9) - 9
Rewrite the quadratic as a perfect square:
(y - 5) = (x - 3)² - 9
Simplify the equation:
y - 5 = (x - 3)² - 9
Move the constant term to the right side:
y = (x - 3)² - 9 + 5
Combine the constants:
y = (x - 3)² - 4
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can you please solve ax+z=w-y for a please???
Answer:
\(ax + z = w - y \\ ax = w - y - z \\ a = \frac{w - y - z}{x} \\ thank \: you \: \)
what is 132÷577(29×787) and the awnser is rounded to the nearest hundredth
Answer:
5221
Step-by-step explanation:
132÷577 (29 x 787)
132÷ 577 = 22823
3012636 ÷ 577 = 5221.2
= 5221
The staff of Mr. Wayne Wertz, VP of Operations at Portland Peoples Bank, prepared a frequency histogram of waiting time for walk-in customers. Approximately how many walk-in customers waited at least 6 minutes? (Note the position of the labels on the x-axis — the first column is the number of customers who waited 1 minute and the last column is the number of customers who waited 10 minutes)
The number of people who waited at least 6 minutes is given as follows:
50 people.
What is shown by the histogram?The height of each bin of the histogram represents the number of observations of the data-set in the desired interval.
The desired outcomes for this problem are given as follows:
Between 6 and 7 minutes: 20 people.Between 7 and 8 minutes: 15 people.Between 8 and 9 minutes: 10 people.Between 9 and 10 minutes: 5 people.Hence the number of people who waited at least 6 minutes is given as follows:
20 + 15 + 10 + 5 = 50 people.
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For options A– E choose all of the expressions that are equivalent to 3(4x + 3).
A. 12x + 3
B. 3(3 + 4x)
C. 7x + 6
D. 4x + 3 + 4x + 3 + 4x + 3
E. 12x + 9
The expression 3(4x + 3) is equivalent to the expression 12x + 9. Then the correct option is E.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
The expression is given below.
⇒ 3(4x + 3)
Simplify the expression, then we have
⇒ 3(4x + 3)
⇒ 3 · 4x + 3 · 3
⇒ 12x + 9
The expression 3(4x + 3) is equivalent to the expression 12x + 9. Then the correct option is E.
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The sides of a central angle are two_____ of the circle
Answer:
The sides of a central angle are two radii (aka radius) of the circle
Step-by-step explanation:
Answer:
Radii
Step-by-step explanation:
Determine which of the four levels of measurement is most appropriate. Doctors measure the weights (in pounds) of preterm babies. A) Categorical B) Ordinal C) Quantitative D) Nominal
Interval data are numerical measurements, while ratio data are numerical measurements with a true zero value.
The most appropriate level of measurement for doctors who measure the weights of preterm babies is quantitative data. Quantitative data is a type of numerical data that can be measured. The weights of preterm babies are numerical, and they can be measured using a scale in pounds, which makes them quantitative.
Levels of measurement, often known as scales of measurement, are a method of defining and categorizing the different types of data that are collected in research. This is because the levels of measurement have a direct relationship to how the data may be utilized for various statistical analyses.
Levels of measurement are divided into four categories, including nominal, ordinal, interval, and ratio levels, and quantitative data falls into the last two categories. Interval data are numerical measurements, while ratio data are numerical measurements with a true zero value.
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40 kişinin katıldığı bir davete 5 evli çift daha
katılırsa, davete katılan erkeklerin sayısı, ka-
dınların sayısının 2 katından 13 eksik oluyor.
Buna göre, son durumda davete kaç erkek-
katılmıştır?
a) 30 D) 29 C) 26
D) 24
sen türksün be ne işin var senin burada
Pleaseeeeee helpppppp!
I will mark brainliest, but pls only if you know the answer
Its Geometry A
Answer:
see explanation
Step-by-step explanation:
A base angle
B leg
C vertex angle
D leg
E base angle
F base
in any isosceles triangle there are 2 congruent legs and 2 congruent base angles.
the base angles are opposite the congruent legs
the remaining side, the base is the 3rd side of the triangle
the vertex angle is formed by the 2 congruent legs
in a contest in which 10 contestants are entered, in how many ways can the 4 distinct prizes be awarded?
By using Permutation, The number of ways in which 4 distinct prizes be awarded is 5,040.
Number of Contestants = 10
Number of distinct prizes = 4
We will use permutation to evaluate the number of ways in which 4 distinct prizes be awarded,
The first prize can be given in 10 ways
The second prize can be given in 9 ways
The third prize can be given in 8 ways
The fourth prize can be given in 7 ways
Now, Total number of ways 4 prizes can be awarded = 10 * 9 * 8* 7 = 5,040
Thus, the number of ways in which 4 distinct prizes be awarded is 5,040
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Problems 1-5: We want to know the true proportion of students that are ok with online courses. We take a sample of 120 students, and 72 said they are ok with online courses. We want to create a 95% confidence interval. Answer the questions below:1) What is the point estimate for the population proportion?2) What is the standard error?3) What is the z score for 95% confidence?4) What is a 95% confidence interval for this data?5) What is the margin of error for this data?
Answer:
Step-by-step explanation:
ima a braintlest
Save
How many pounds of candy that sells for $0.79 per lb must be mixed with candy that sells for $1.35 per to to obtain 8 of a midure that should sell for $335 per to
50.79-per-to cardyb
(Type an integer or decimal rounded to two decimal places as needed)
The number of pounds of candy that sells for $0.79 per lb that must be mixed with candy that sells for $1.35 per lb to obtain 8 tons of a mixture that should sell for $335 per ton is 580 pounds
How to know the amount of pounds of candy requiredTake x as the number of pounds of candy that sells for $0.79 per lb, and y as the number of pounds of candy that sells for $1.35 per lb.
x + y = 8 (i.e total amount of candy to be mixed)
0.79x + 1.35y = 335 (desired selling price per ton)
solve for x
y = 8 - x
0.79x + 1.35(8 - x) = 335
0.79x + 10.8 - 1.35x = 335
-0.56x = 324.2
x = 579.64
Thus x ≈ 580 to the nearest pound
Hence, about 580 pounds of candy that sells for $0.79 per lb must be mixed with candy that sells for $1.35 per lb to obtain 8 tons of a mixture that should sell for $335 per ton.
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Juan tiene un bidón de 5 litros de capacidad, llenado hasta los 2 1/3 litros. ¿Cuántos litros le faltan para llenarlo?
Answer:
nwhbjwhr
Step-by-step explanation:
ewrwrwrwewe
Two balls are thrown upward from the edge of a cliff 432 ft above the ground. The first is thrown with a speed of 48 ft/s and the other is thrown a second later with a speed of 24 ft/s.(a) Do the balls ever pass each other?(b) If they pass each other, give the time when this occurs. If they do not pass each other, enter NONE.
As per the given speed, the ball will cross each other at the time of 5 seconds.
Given,
Two balls are thrown upward from the edge of a cliff 432 ft above the ground. The first is thrown with a speed of 48 ft/s and the other is thrown a second later with a speed of 24 ft/s.
Here we need to find if the ball will cross each other.
Let us find the equation for your first ball and it can be identified by using "f" for fast, since it's thrown at twice the speed of the other.
Here we have given the equation is ft/sec, so g = -32.
So, it can be written as,
=> yf = 1/2gt² + v₀ft + y₀f
Apply the values, then we get,
=> yf = -16t² + 48t + 432
Here we know that the second ball, or "slow" ball, is thrown a second later which means all of t values are shifted to the right by 1 second.
So, here we put (t - 1) instead of t
Then we get,
=> ys = 1/2g(t - 1)² + v₀s(t - 1) + y₀s
We know that, the Gravity remains the same.
So, the value of v₀s will be 24, and y₀s will also be 432 ft.
So, the equation is,
=> ys = -16(t - 1)² + 24(t - 1) + 432
When we compare these then we get,
=> -16t² + 48t + 432 = -16(t - 1)² + 24(t - 1) + 432
=> -16t² + 48t = -16(t² - 2t + 1) + 24(t - 1)
=> -16t²+ 48t = -16t² + 32t - 16 + 24t - 24
=> 48t = 56t - 40
=> 8t = 40
=> t = 5
Therefore, it looks like the balls cross each other at t = 5.
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please help I will give you any award
Answer:
218.57
Step-by-step explanation:
Since it is an isoceles triangle, the sides are 32, 32, and 14.
Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2, we can calculate the area.
(A+B+C)/2 = (32+32+14)/2=39.
A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.
Hope this helps have a great day :)
Check the picture below.
so let's find the height "h" of the triangle with base of 14.
\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)
\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)
Find the probability of drawing the given cards from a standard deck of 52 cards with replacement. Leave answers as decimals rounded to 3 decimal places if the decimal does not end.
A face card, then a 2
The answer to this question is 0.077
what is the volume of the solid generated when the region in the first quadrant bounded by the graph of y=x3, the y-axis, and the horizontal line y=1 is revolved about the y-axis?
The volume of the solid is 4/5π.
The volume of a solid generated by revolving a region around a line is given by V = ∫a b π(y)2dy, where a and b are the lower and upper limits of the region, respectively, and y is a function of x.
In this case, the region is bounded by the graph of y=x3, the y-axis, and the horizontal line y=1. Therefore, the volume of the solid generated when the region is revolved about the y-axis is given by
V = ∫0 1 π(y)2dy
= ∫0 1 πx6dx
= π/7
= 4/5π
The volume of the solid is calculated using the formula V = ∫a b π(y)2dy, where a and b are the lower and upper limits of the region and y is a function of x. In this case, the lower limit is a=0 and the upper limit is b=1, since the region is bounded by the graph of y=x3, the y-axis, and the horizontal line y=1. Integrating from a=0 to b=1 gives the volume of the solid as V = ∫0 1 πx6dx = π/7 = 4/5π.
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it has been observed that some persons who suffer colitis, again suffer colitis within one year of the first episode. this is due, in part, to damage from the first episode. the performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. in order to do this two groups of people suffering a first episode are selected. there are 55 people in the first group and this group will be administered the new drug. there are 45 people in the second group and this group will be administered a placebo. after one year, 11% of the first group has a second episode and 9% of the second group has a second episode. conduct a hypothesis test to determine, at the significance level 0.1, whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode? select the [alternative hypothesis, value of the test statistic].
The value of the test statistic is 0.
The alternative hypothesis states that there is a difference between the true percentage of the first group who suffer a second episode and the true percentage of the second group who suffer a second episode.
The null hypothesis states that there is no difference between the true percentage
of the first group who suffer a second episode and the true percentage of the second group who suffer a second episode. Let us compute the value of the test
statistic
First, let us determine the proportion of people in each group who suffer a second episode:First group: p1 = 11/55 = 0.2Second group: p2 = 9/45 = 0.2
The sample proportion
of both groups is 0.2. Let us now calculate the standard error of the difference of proportions:SE(p1 - p2) = sqrt{ [p1(1 - p1) / n1 ] + [ p2(1 - p2) / n2 ] }= sqrt{ [0.2(0.8) / 55] + [0.2(0.8) / 45] }= sqrt{ 0.0029 + 0.0044 }= sqrt{ 0.0073 }= 0.0853
Now we can calculate the test statistic:Z = [(p1 - p2) - 0] / SE(p1 - p2)Z = [(0.2 - 0.2) - 0] / 0.0853Z = 0 / 0.0853Z = 0
The value of the test statistic is 0. The alternative hypothesis states that there is a difference between the true percentage of the first group who suffer a second episode and the true percentage of the second group who suffer a second episode. However, the test statistic is 0.
Therefore, there is no evidence to support the alternative hypothesis. The value of the test statistic is 0.
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To calculate the test statistic, we can use the formula (p1 - p2) / sqrt((p1*(1-p1)/n1) + (p2*(1-p2)/n2)), where p1 and p2 are the sample proportions, and n1 and n2 are the sample sizes.
Given that p1 = 0.11, p2 = 0.09, n1 = 55, and n2 = 45, we can substitute these values into the formula to find the test statistic:
Test statistic = (0.11 - 0.09) / sqrt((0.11*(1-0.11)/55) + (0.09*(1-0.09)/45))
To conduct a hypothesis test, we need to define our null and alternative hypotheses. In this case, our null hypothesis (H0) states that the true percentage of those in the first group who suffer a second episode is the same as the true percentage of those in the second group who suffer a second episode. Our alternative hypothesis (Ha) states that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode.
Next, we calculate the test statistic, which is the difference between the sample proportions of the two groups. The sample proportion for the first group is 11% (or 0.11), and for the second group is 9% (or 0.09). The test statistic can be calculated as (p1 - p2) / sqrt((p1*(1-p1)/n1) + (p2*(1-p2)/n2)), where p1 and p2 are the sample proportions, and n1 and n2 are the sample sizes.
Substituting the values, the test statistic is (0.11 - 0.09) / sqrt((0.11*(1-0.11)/55) + (0.09*(1-0.09)/45)).
Finally, we compare the test statistic to the critical value at the significance level of 0.1. If the test statistic falls outside the critical value range, we reject the null hypothesis and conclude that there is reason to believe that the true percentages are different. Otherwise, we fail to reject the null hypothesis.
In this case, the alternative hypothesis is that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode. The value of the test statistic can be calculated using the formula provided above.
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In the following exercises, multiply the binomials. Use any method.
241. (x + 8)(x + 3)
Answer:
Hence the expression \($(x+8)(x+3)=x^{2}+11 x+24$\).
Step-by-step explanation:
- The given expression is (x+8)(x+3).
- We have to multiply the given expression.
- Multiply the (x+8) by 3 , multiply the (x+8) by x then add like terms.
\($$\begin{array}{r}x+8 \\\underline {\times \quad x+3} \\3 x+24 \\\underline {x^{2}+8 x+24} \\x^{2}+11 x+24\end{array}$$\)
Compare / Contrast Exponential Equations
1.) 2 (1/5)x-5
2.) y=4x
The functions y = 2 (1/5)^x - 5 and y = 4^x are compared as follows
y = 2 (1/5)^x - 5 y = 4^x
Initial value: 2 1
base function: 1/5 = decay function 4 = growth function
Translation: 5 units down no transformation
What is a decay function?
A decay function is a mathematical function used in various fields such as physics, engineering, economics, and machine learning, to model the reduction or decline of a value over time.
It is a type of function that decreases at a rate proportional to its current value, so that it approaches zero as time progresses.
Decay function are exponential functions with the base function as
0 < k < 1This is the opposite of growth function which has values greater than 1
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Please help! Find the area of a polygon
where? i dont see it sorry
can someone help me find the values of y and z?
Answer:
y= 134.5 and z= 44.5 :)
Step-by-step explanation:
6z-87=180
6z=267
267/6=44.5
180-44.5=134.5
Answer:
y=99, z=81
Step-by-step explanation:
the angle above y is corresponding to 81, so if you substitute 81 in that place then it'll be angles on a straight line;
81 + y =180
(add like terms)
y =180 - 81
=99.
thus, y is 99. Once you do that, y and z are on a straight line so you solve for x using the formula for angles on a straight line;
y + (6z - 87)
(substitute y with 99)
99 + 6z - 87 =180
6z + 12 =180
(add like terms)
6z =180-12
6z =168
(divide both sides by six)
6z /6= 168/6
z = 28
(then you solve everything that was in the bracket for z)
(6z - 87)
(substitute z with 28)
=6 × 28 - 87
=168 - 87
=81
therefore, y =99 and z =81