Let the vector v have an initial point at (6, 3) and a terminal point at (2, 2).
Determine the components of vector V.

Answer:

\( \frac{1}{18} \)

Answer:

3/54

Step-by-step explanation:

6 and 9 both go into 54

1/6=9/54

7/9=42/54

42+9=51

3/54

Answer:

y = 1/2x + 4

Step-by-step explanation:

Answer:

4,680,000

Step-by-step explanation:

Whenever multiplying by 10s, 100s or 1000s, just add the 0s to the answer.

So 4680 plus three 0s would be 4,680,000

Have a good day :)                                                                                                                        

Answer:

4680000

Step-by-step explanation:

pls brainliest

The height of Jeremy is 159 cm.

To find the height of Jeremy:

So,

Then, Jeremy = 135 + 24 = 159 cm.

Therefore, the height of Jeremy is 159 cm.

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Answer:

2x-3

Step-by-step explanation:

3/x-4=x-5/x=

first what you need to do  is

3/x-4 so its both a fraction 3/x and 5x and subtraction on both sides makes it easer for us so

3/x-5/x=2/x

4-x=3

if wondering why 4x-x = 3 because x basicly means 1 so then you answer will be

2/x-3

am not really sure if you wanted simplifyed but it might be this

When performing a 3-D problem analysis, in general, you have three scalar equations of equilibrium. Therefore, the answer is (b) 3.

In a 3-D problem analysis, we consider forces and moments acting in three perpendicular directions: x, y, and z. For each direction, we can apply the principle of equilibrium to derive a scalar equation. The equations of equilibrium are as follows:

ΣFx = 0 (Sum of forces in the x-direction is zero)

ΣFy = 0 (Sum of forces in the y-direction is zero)

ΣFz = 0 (Sum of forces in the z-direction is zero)

These three scalar equations of equilibrium represent the conditions for a body to be in static equilibrium in three-dimensional space.

When analyzing 3-D problems, we typically have three scalar equations of equilibrium. These equations help us determine the unknown forces and moments acting on a body by setting the sums of forces and moments in each direction equal to zero. By solving these equations simultaneously, we can find the equilibrium conditions and obtain the desired solutions.

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The income elasticity of demand is positive, implying that chocolate is a normal good = 0.037

The demand function, Q = 54−5P + 4PA + 0.1Y.

Where Q is the quantity of chocolate demanded, P is the price of chocolate, PA is the price of an apple, and Y is income.

(i) The own-price elasticity of demand for chocolate, we first need to find the expression for it.

The own-price elasticity of demand can be expressed as:

Own-price elasticity of demand = (Percentage change in quantity demanded) / (Percentage change in price)Or,E

P = (ΔQ / Q) / (ΔP / P)E P = dQ / dP * P / Q

Let's calculate the own-price elasticity of demand:

EP= dQ / dP * P / Q= (-5) / (54 - 5P + 4PA + 0.1Y) * 3 / 30

= -0.1667

So, the own-price elasticity of demand for chocolate is -0.1667.

(ii) The cross-price elasticity of demand, we must first determine the expression for it.

The cross-price elasticity of demand can be expressed as:

Cross-price elasticity of demand

= (Percentage change in quantity demanded of chocolate) / (Percentage change in price of apples) Or, E

PA = (ΔQ / Q) / (ΔPA / PA)E PA = dQ / dPA * PA / Q

Let's calculate the cross-price elasticity of demand:

EP = dQ / dPA * PA / Q= (4) / (54 - 5P + 4PA + 0.1Y) * 2 / 30= 0.0296

So, the cross-price elasticity of demand is 0.0296.

(iii) The income elasticity of demand can be expressed as:

Income elasticity of demand = (Percentage change in quantity demanded) / (Percentage change in income)Or,E

Y = (ΔQ / Q) / (ΔY / Y)E Y = dQ / dY * Y / Q

Let's calculate the income elasticity of demand: EY = dQ / dY * Y / Q= (0.1) / (54 - 5P + 4PA + 0.1Y) * 100 / 30

= 0.037

The own-price elasticity of demand is negative, meaning that the quantity demanded of chocolate decreases when the price of chocolate increases.

The cross-price elasticity of demand is positive, indicating that chocolate and apples are substitute goods.

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The value of the trigonometric functions given that the point (-112, -15) is on the terminal side of an angle, θ is sin(θ)= y/r = -15/ 113 cos(θ)= x/r = -112/ 113 tan(θ)= y/x = -15/ -112 csc(θ)= r/y = 113/ -15 sec(θ)= r/x = 113/ -112.

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

The terminal points are given as follows:

x = -112 and y = -15

Using the Pythagorean theorem we have:

x^2 + y^2 = r^2

(-112)^2 + (-15)^2 = r^2

12544 + 225 = r^2

r = 113

Now, the trigonometric functions is given as:

sin(θ)= y/r = -15/ 113

cos(θ)= x/r = -112/ 113

tan(θ)= y/x = -15/ -112

csc(θ)= r/y = 113/ -15

sec(θ)= r/x = 113/ -112

cot(θ)= x/y = -112/ -15

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Answer:

46 laps

Step-by-step explanation:

Set up a ratio:

38/95 =  s/115

cross multiply

4370  = 95s

divide both sides by 95

s= 46

Answer:

y=0.625

Step-by-step explanation:

Answer:

Sorry about the way it is, I don't know how to fix it But I hope you can try and understand it.

Step-by-step explanation:

y

=

3

8

x

−

3

4

in standard form is

3

x

−

8

y

=

6

.

Explanation:

Standard form for a linear equation is

A

x

+

B

y

=

C

.

y

=

3

8

x

−

3

4

Simplify

3

8

x

to

3

x

8

.

Subtract

3

x

8

from both sides of the equation.

−

3

x

8

+

y

=

−

3

4

Multiply both sides by

−

1

.

−

3

x

8

(

−

1

)

+

y

(

−

1

)

=

−

3

4

(

−

1

)

=

3

x

8

−

y

=

3

4

Multiply both sides by

8

.

(

3

x

)

⋅

8

8

−

y

(

8

)

=

(

3

)

⋅

8

4

=

(

3

x

)

⋅

8

1

8

1

−

y

(

8

)

=

(

3

)

⋅

8

2

4

1

=

3

x

−

8

y

=

6

The magnitude of the projection of f1 onto the line of action of f2 is approximately 3.99.

To find the magnitude of the projection of vector f1 onto the line of action of vector f2, you can use the formula:

Magnitude of the projection = |f1| * cos(θ)

where |f1| is the magnitude of vector f1, and θ is the angle between vectors f1 and f2.

First, let's calculate the magnitude of f1:

|f1| = √(\((3.8)^2 + (6.3)^2)\)

|f1| = √(14.44 + 39.69)

|f1| = √54.13

|f1| ≈ 7.36

Next, we need to find the angle θ between f1 and f2. The dot product of two vectors is given by:

f1 · f2 = |f1| * |f2| * cos(θ)

where f1 · f2 represents the dot product of f1 and f2.

f1 · f2 = (3.8 * 9.3) + (6.3 * 3.0)

f1 · f2 = 35.34

Now we can solve for cos(θ):

cos(θ) = (f1 · f2) / (|f1| * |f2|)

cos(θ) = 35.34 / (7.36 * 9.3)

cos(θ) ≈ 0.542

Finally, we can calculate the magnitude of the projection:

Magnitude of the projection = |f1| * cos(θ)

Magnitude of the projection ≈ 7.36 * 0.542

Magnitude of the projection ≈ 3.99

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Answer:

456748

Step-by-step explanation:

you 463uy2iuswhk then 13456

The recursive and the explicit formulas are f(n) = 3f(n - 1), where f(1) = 250 and f(n) = 250(3)ⁿ‐¹

From the question, we have the following parameters that can be used in our computation:

This means that

Initial, a = 250 bacterial cultures.

Rate = 3

So, the recursive formulas is

f(n) = 3f(n - 1), where f(1) = 250

For the explicit formula, we have

f(n) = 250(3)ⁿ‐¹

Hence, the recursive and the explicit formulas are f(n) = 3f(n - 1), where f(1) = 250 and f(n) = 250(3)ⁿ‐¹

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Answer: Line EF Edge GL!

Answer:

Answer above is correct! Option C. Line EF is correct on Edge :D

Step-by-step explanation:

Just answered it correctly on the assignment - hope this helps :P

Answer:

Your answer (x + 4)2 =-11 x + 4)2 13 x + 4)221 Correct answer.

Answer:

Let total pages be x

ATQ,

(x/5)+40=7x/10

(x+200)/5=7x/10

Cross multiply

10x+2000=35x

10x-35x=-2000

-25x=-2000

x=2000/25

x=80 pages

Therefore pages left= 3/10 of pages

=3*80/10=24 pages

Answer:

(x/5)+40=7x/10

(x+200)/5=7x/10

Cross multiply

10x+2000=35x

10x-35x=-2000

-25x=-2000

x=2000/25

x=80 pages

Therefore pages left= 3/10 of pages

=3*80/10=24 pages

ther u is good person

The approximate length of a side of the rhombus is 10.67 cm.

A rhombus is a quadrilateral with all sides of equal length.

The diagonals of a rhombus bisect each other at right angles.

Let's label the length of one diagonal as d1 and the other diagonal as d2.

In the given rugby-shaped figure, the length of d1 is 14 cm, and the length of d2 is 12 cm.

Since the diagonals of a rhombus bisect each other at right angles, we can divide the figure into four right-angled triangles.

Using the Pythagorean theorem, we can find the length of the sides of these triangles.

In one of the triangles, the hypotenuse is d1/2 (half of the diagonal) and one of the legs is x (the length of a side of the rhombus).

Applying the Pythagorean theorem, we have \((x/2)^2 + (x/2)^2 = (d1/2)^2\).

Simplifying the equation, we get \(x^{2/4} + x^{2/4} = 14^{2/4\).

Combining like terms, we have \(2x^{2/4} = 14^{2/4\).

Further simplifying, we get \(x^2 = (14^{2/4)\) * 4/2.

\(x^2 = 14^2\).

Taking the square root of both sides, we have x = √(\(14^2\)).

Evaluating the square root, we find x ≈ 10.67 cm.

Therefore, the approximate length of a side of the rhombus is 10.67 cm.

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The graph of f(x)=√x+3+2 is shifted 3 units up and 2 units to the right from the parent graph of f(x)=√x.

We have,

Graph is a type of data structure that consists of a set of nodes (also called vertices) and edges. Each node is connected to other nodes by edges. Graphs are used to represent networks of communication, data organization, computational devices, the flow of computation, etc. They are also very useful for visualizing relationships between data points in a variety of fields.

The translation of the parent graph of f(x)=√x+3+2 is a vertical shift upward 3 units, followed by a horizontal shift to the right 2 units. This is represented by the bold line in the graph. In terms of the equation, the translation is represented by the addition of the 3 and the 2 to the function. The 3 causes the graph to shift vertically upward and the 2 causes the graph to shift horizontally to the right. As a result, the graph of f(x)=√x+3+2 is shifted 3 units up and 2 units to the right from the parent graph of f(x)=√x.

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complete question:

Below, the graph of f(x) = √x +3 + 2 is sketched in bold. Its parent function f(x)=√x is represented

by the thin curve.

1) Describe the

translation of the parent

graph.

2) How does the translation relate to the equation?

Answer:

∠ UVX = 126.8°

Step-by-step explanation:

∠ WVS and ∠ UVX are vertical angles and congruent, then

∠ UVX = 126.8°

Answer: 624 were girls

Step-by-step explanation: 1560 times 8/20 is 624.

To know which girl ate the most, we have to compare the two fractions.

To be able to compare the fractions, we can:

1.- We convert to decimal numbers.

2.- We modify the fractions such that both fractions have the same denominator.

To compare the fraction we will change them in a way that both have the same denominator.

Recall that a fraction represents the same number if we multiply it and divide it by the same number.

Notice that:

Since both fractions are the same, we can conclude that both girls ate the same amount.

Answer: 3/6 is equal to 4/8.

Both girls ate the same amount

Here it is

.,.,.,.,..,.,.,.

Answer:

Find the total number of oranges.

Total oranges = 90 × 5

= 450

Since 1/5 were rotten oranges,

Fraction of oranges that were not rotten

= Fraction of total oranges - Fraction of rotten oranges

= 5/5 - 1/5

= 4/5

Number of oranges not rotten = 4/5 × 450

= 360

Answer:

We can find two other points on the line passing through (1,5) and (3,-1) by using the slope-intercept form of a line: y = mx + b where m is the slope of the line, and b is the y-intercept.

To find the slope (m) of the line, we can use the formula: m = (y2 - y1) / (x2 - x1)

Plugging in the coordinates of the two given points: m = (-1 - 5) / (3 - 1) = -6 / 2 = -3

To find the y-intercept (b) of the line, we can use one of the given points and substitute the values of x, y and m into the equation y = mx + b.

Plugging in the coordinates of the point (1,5) and the value of m: 5 = -3(1) + b, b = 8

So the equation of the line is y = -3x + 8

We can use this equation and any x value to find two other points on the line. For example, if we choose x = -2, we get y = -3(-2) + 8 = 2

so the point (-2,2) is on the line.

If we choose x = 0, we get y = -3(0) + 8 = 8

so the point (0,8) is on the line.

So two other points on the line passing through (1,5) and (3,-1) are (-2,2) and (0,8)

If I helped you, could you please make my answer best?

Answer:

x + y = 4

m = -1

Step-by-step explanation:

(3 - 5) / (1 - (-1))

m = -2/2

(y - 5) = -1 × (x - (-1))

y - 5 = - x - 1 = 0

The number of combinations of 6 boys and 20 girls that can exist among 26 children born in a hospital on a given day is 230,230.

]To calculate the number of combinations, we can use the concept of binomial coefficients. The formula for calculating the number of combinations is C(n, k) = n! / (k!(n-k)!), where n is the total number of objects and k is the number of objects we want to select.

In this case, we have 26 children in total, and we want to select 6 boys and 20 girls. Plugging these values into the formula, we get C(26, 6) = 26! / (6!(26-6)!) = 230,230. Therefore, there are 230,230 different combinations of 6 boys and 20 girls that can exist among the 26 children born in the hospital on that given day.

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a) The reverse-time process {Yr} of a discrete Markov chain {Xt} is a Markov chain. b) The transition matrix of {Yr} is P' = P^T, and {Yr} is reversible if the detailed balance equations are satisfied. c) For a continuous Markov chain, the reverse chain {Yr} has generator matrix Q' = -Q^T, and reversibility is determined by the detailed balance equations.

The reverse-time process {Yr} of a discrete Markov chain {Xt} is defined as {Yr} = {X−t}. Let's address each part of the question:
a) To show that {Yr} is a Markov chain, we need to demonstrate that it satisfies the Markov property, which states that the future states only depend on the current state and not on the past states. In other words, the conditional probability of transitioning to a future state depends only on the current state.

b) Assuming that {Xt} is a stationary Markov chain with distribution π (denoted as π(t) = π for all t), we can compute the transition matrix of the reverse chain {Yr} as follows:

Let P' be the transition matrix of {Yr}. Since {Yr} = {X−t}, the probability of transitioning from state i at time t to state j at time r in {Yr} is equal to the probability of transitioning from state j at time −t to state i at time −r in {Xt}. Therefore, the (i,j) entry of P' is equal to the (j,i) entry of P. In matrix notation, we can express this as P' = P^T, where T denotes matrix transpose.

To show that the Markov chain {Yr} is reversible, we need to prove that the transition matrix P' of {Yr} is the same as the transition matrix P of {Xt}. This is true if and only if the detailed balance equations are satisfied. The detailed balance equations state that for all states i and j, the product of the transition probability from state i to state j and the stationary distribution at state i is equal to the product of the transition probability from state j to state i and the stationary distribution at state j.

c) To repeat parts a) and b) for a continuous Markov chain with generator matrix Q, we can follow a similar approach. The reverse-time process {Yr} will be defined as {Yr} = {X−t}. We need to show that {Yr} is a Markov chain by demonstrating that it satisfies the Markov property.

Assuming that {Xt} is a stationary Markov chain with distribution π (π(t) = π for all t), we can compute the generator matrix Q' of the reverse chain {Yr} as follows:
Q' = -Q^T,
where Q^T denotes the matrix transpose of Q.
To show that the continuous Markov chain {Yr} is reversible, we need to prove that the generator matrix Q' of {Yr} is the same as the generator matrix Q of {Xt}. This is true if and only if the detailed balance equations are satisfied, which are the same as in the discrete case.

Overall, the reverse-time process of a Markov chain can be analyzed by considering the transition matrix (in the discrete case) or the generator matrix (in the continuous case). By showing that the reverse chain satisfies the Markov property and that the detailed balance equations are satisfied, we can conclude that it is indeed a Markov chain and that it is reversible.

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The test statistic for this sample and the p-value for this sample is  t = 0.467.

Given:

sample of size n=305

M=83.6

SD=14.9.

Significance level of α = 0.001 . H o : μ = 82.4 H a : μ ≠ 82.4

To find the Test statistic

\(test=\frac{\bar x-\mu}{\frac{s.t}{\sqrt{n} } }\)

    \(=\frac{82.4.6-83.6}{\frac{14.9}{\sqrt{305} } }\)

     \(0.467\)

P-value:

With t = 0.467.

p-value = (1 - 0.467)

0.533 > 0.001

So, fail to reject H₀

Therefore, the failing to reject the Null Hypothesis.

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The graph of the equation y = -4 + 4 cos²θ represents a cardioid, which is a heart-shaped curve.

To convert the polar equation r = -4 sin θ to rectangular form, we can use the following relationships between polar and rectangular coordinates:

x = r cos θ

y = r sinθ

Substituting the given polar equation into these equations, we have:

x = -4 sinθ cosθ and y = -4 sinθ sinθ

x= -4 sinθ cosθ and y = -4 sin²θ

Since sin²θ = 1 - cos²θ, we can rewrite the equation for y as:

y = -4 (1 - cos²θ)

y = -4 + 4 cos²θ

Now we have the rectangular form of the equation, with x and y in terms of cosθ.

The graph of the equation y = -4 + 4 cos²θ represents a cardioid, which is a heart-shaped curve.

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