Kendell's mom buys him a new bowling ball that has a mass of 4 kg. He rolls the ball with an average speed of
30 m/s. What is the average kinetic energy of Kendell's ball when rolling?

Answer:

  \(\frac{Y}{Y_o}\) = 2/3

Explanation:

The yuong modulus of a rod is defined as the relationship between the tensile strength and the strain

         Y =  \(\frac{ \frac{F}{A} }{\frac{\Delta L}{L_o} }\)

let's use the subscript "o" for rod A

         I = \(\frac{ \frac{F}{A_o} }{ \frac{\Delta L}{L_o} }\)

tells us that rod B has

         A = 3 A₀

         L = 2 L₀

we substitute

         Y = \(\frac{ \frac{F}{A} }{ \frac{\Delta L}{L} }\)

          Y = \(\frac{ \frac{F}{3A_o} }{ \frac{\Delta L}{ 2L_o} }\)

         y = ⅔  \(\frac{ \frac{F}{A_o}}{ \frac{\Delta }{L_o} }\)

substituting the value of Y₀

          Y = ⅔  Y₀

           \(\frac{Y}{Y_o}\) = 2/3

Answer:

Hope this helps :)

Explanation:

Let's start b writing down coordinates of all points:

A(0,0,0)

B(0,5,0)

C(3,5,0)

D(3,0,0)

E(3,0,4)

F(0,0,4)

G(0,5,4)

H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)

Reflecting

A(0,0,0)

B(0,5,0)

Reflecting

B(0,-5,0)

C(3,5,0)

Reflecting

C(3,-5,0)

D(3,0,0)

Reflecting

D(3,0,0)

b.)

A(0,0,0)

Moving

A(-2,-3,1)

B(0,-5,0)

Moving

B(-2,-8,1)

C(3,-5,0)

Moving

C(1,-8,1)

D(3,0,0)

Moving

D(1,-3,1)

Answer:

Decreasing the angle to 10

Explanation:

Edge 2020

Given

The intensity is

To find

The relative intensity

Explanation

The relative intensity is given by

Here,

Thus,

Conclusion

The relative intensity is 96.6 dB

Shear stress is tangential tension that results from fluid moving against resistance against a solid surface.  therefore (iii) > (i)  = (ii) option  a).

An item experiences deformation when an exterior force works upon it. if the force's orientation is parallel to the object's surface. Along that line, there will be a distortion. The item in this instance is under tensile or tangential tension.

The stress an object experiences is known as shearing stress or tangential stress when the path of the deforming force or exterior force is parallel to the cross-sectional area.

Shear stress results from forces that are parallel to and reside in the plane of the cross-sectional area, whereas normal stress results from forces that are perpendicular to a cross-sectional area of the substance.

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Answer:

5.03×10¯⁷ N

Explanation:

From the question given above, the following data were obtained:

Mass of the person (M₁) = 55 Kg

Mass of the car (M₂) = 1234 Kg

Distance apart (r) = 3 m

Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²

Force (F) =?

The force between the person and his car can be obtained as follow:

F = GM₁M₂ / r²

F = 6.673×10¯¹¹ × 55 × 1234 / 3²

F = 6.673×10¯¹¹ × 67870/ 9

F = 5.03×10¯⁷ N

Thus, the force between the person and his car is 5.03×10¯⁷ N

Answer:

30 x 0.28 = 3.78 is your answer

Explanation:

the question is asking for the weight of the object so you multiply and get 3.79

Answer:

1. Yes

2. Yes

3. 292 joules

4. 90 watts

5. By increasing the force

Explanation:

Have a wonderful day :)

The diver's net vertical displacement is a downward displacement of 12 meters and the distance to the boat is approximately 14.66 meters.

The scuba diver's net vertical displacement vector is obtained by summing the individual vertical displacements. In this case, the diver first descends 9.0 m but encounters a problem and ascends 3.0 m, resulting in a vertical displacement of -3.0 m. The diver then continues descending for 12.0 m, resulting in a vertical displacement of +12.0 m. Afterwards, the diver ascends 4.0 m and then descends 18.0 m, resulting in a vertical displacement of -14.0 m. Finally, the diver ascends 7.0 m and descends 24.0 m, resulting in a vertical displacement of -17.0 m.

Summing these individual displacements gives a net vertical displacement of -3.0 + 12.0 - 4.0 - 14.0 + 7.0 - 24.0 = -12.0 m. Therefore, the diver's net vertical displacement is a downward displacement of 12 meters.

To find the distance to the boat, we can consider the diver's horizontal displacement of 9.0 m. Using the Pythagorean theorem, the distance to the boat is given by the square root of the sum of the squares of the vertical and horizontal displacements. Thus, the distance to the boat is approximately \(\sqrt{(-12)^2 + 9^2} = \sqrt{144 + 81} = \sqrt{225} = 15.0m\). Therefore, the diver's distance to the boat is approximately 14.66 meters (rounded to two decimal places).

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If an object must be slowed quickly, the force applied to it must be greater than that required for gradual slowing. For example, the greater the force applied to a bicycle's brakes, the faster it will slow or stop.

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.

Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.

Force is defined as the tendency of a body to modify or change its state as a result of an external cause. When applied force, the body can also change shape, size, and direction.

The same force that was used to accelerate something can be used to slow it down. It will stop faster if more force is applied.

Thus, it can be concluded that it take more force to slow something down than to speed it up.

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Answer:8.3mins

Explanation:

S=Vt

where V=average speed

S=4000m V=8m/s

4000=8×t

t=4000/8

t=500s

t=500/60

t=8.3min

500 sec

8 min 20 sec

Hi there !

8 m ................ 1 s

4000 m ........ x s

x = 4000m×1s/8m = 500 sec = 8 min 20 sec

Good luck !

The current and resistance changes as the potential difference across a resistor changes for both ohmic and nonohmic cases are described as follows:

Ohmic case:

In the case of ohmic, current through a resistor increases linearly with the potential difference applied to it. The potential difference across a conductor is directly proportional to the current passing through it if the physical state, temperature and other physical factors of the conductor remain unchanged. Ohm's law describes this relationship mathematically.

V = IR   where, V is the potential difference across the conductor, I is the current passing through the conductor, and R is the resistance of the conductor. If the temperature of the resistor remains constant, the resistance of the resistor remains constant as well.

Nonohmic case:

For nonohmic cases, resistance changes with changes in the potential difference applied to the conductor. The resistivity of the conductor changes with the changes in the physical state, temperature and other factors of the conductor. The relationship between voltage, current, and resistance is nonlinear.

In a nonohmic case, the resistivity of the conductor changes with changes in the physical state, temperature and other factors of the conductor and does not follow the relationship between voltage and current as in the case of ohmic resistors.

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a ) The relationship between the tension T1 and m1g is T1 > m1a

b ) The relationship between the magnitudes of the accelerations is I a1 I = I a2 I

Since m2 is larger than m1, the m2 will move downwards while m1 moves up. So the net force is given by,

∑ Fy = T1 - W1

m1 a = T1 - m1 g

T1 = m1 a + m1 g

So T1 > m1a

Since it is a single system connected through a pulley, the acceleration of m1 and M2 will be of same magnitude but in opposite directions.

a1 = - a2

I a1 I = I a2 I

Therefore,

1 ) T1 > m1a

2 ) I a1 I = I a2 I

The given question is incomplete. The complete question is:

A pulley (in the form of a uniform disk) with mass M, and radius Rp is attached to the ceiling in a uniform gravitational field g and rotates with no friction about its pivot. Mass M2 is larger than mass m1, and they are connected by a massless inextensible cord. T1, T2, and T3 are magnitudes of the tensions. The system is shown in the image attached.

1 ) What is the relationship between the tension T1 and m1g?

2 ) What is the relationship between the magnitudes of the accelerations?

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The equivalent resistance of the three 10^12 ohm resistors connected in parallel is approximately 3.33 x 10^11 ohms.

The formula for calculating the equivalent resistance (R_eq) of resistors connected in parallel is given by:

\(\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots\)

In this case, we have three resistors connected in parallel, each with a resistance of 10^12 ohms. Substituting the values into the formula, we can calculate the equivalent resistance:

\(\frac{1}{R_{\text{eq}}} = \frac{1}{10^{12}} + \frac{1}{10^{12}} + \frac{1}{10^{12}}\)

Simplifying the equation, we get:

\(\frac{1}{R_{\text{eq}}} = \frac{3}{10^{12}}\)

Taking the reciprocal of both sides, we find:

\(R_{\text{eq}} = \frac{10^{12}}{3}\)

Thus, The equivalent resistance (R_eq) of three 10^12 ohm resistors connected in parallel is approximately 3.33 x 10^11 ohms.

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With reference to an ideal diode, a) It is associated with hole injection and electron injection. b) It is associated with the flow of minority charge carriers. c) It is because of the small number of minority carriers available to cross the junction. d) It is negligible throughout the depletion region as the carriers have a low density.

(a) The forward-bias current is associated with hole injection and electron injection. The electron current flows from the n-type material toward the p-type material, whereas the hole current flows from the p-type material toward the n-type material.

(b) In reverse-bias operation, the diode does not conduct an electric current. The reverse-bias current is associated with the flow of minority charge carriers (electrons in the p-type and holes in the n-type).

(c) The reverse-bias current is small in magnitude because of the small number of minority carriers available to cross the junction. The minority carriers which cross the junction do so by thermal generation, and thus the reverse-bias current increases with increasing reverse voltage.

Nevertheless, the reverse-bias current is still small as compared to the forward-bias current due to the lesser availability of minority carriers, and thus saturates at a small reverse voltage.

(d) The recombination generation is negligible throughout the depletion region as the carriers have a low density in the region. They do not stay long enough to recombine or generate other carriers in that region. Thus, they diffuse into the region, cross it, and exit as fast as they entered, without much interaction between them.

This is also the reason why the depletion region is nearly devoid of carriers, except for those near the edges.

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Answer:

The part of an experiment that is not being tested but is used for comparison is the controls or the controlled variables.

Answer:

The final velocity is 50 m/s.

Explanation:

Below is the calculation of velocity:

v = u + a*t

v = final velocity

u = initial velocity

a = accreleration

Since, u = 0, a = 10m/s^2, and t = 5 seconds. Now plug these values in the formula.

v = u + a*t

v = 0 + 10 x 5

v = 50 m/s

The final velocity is 50 m/s.

The total time the bullet is in contact with the board is 8 x 10^-5 seconds

V1 = 400ms − the initial velocity of the bullet;

V2 = 300 ms− final velocity of the bullet;

d = 10cm = 0.1m − thickness of the board;

a − acceleration inside the board.

t − total time that the bullet is in contact with the board

To find the total time that the bullet is in contact with the board we can use formula :

t =  V1 -V2 / a

where a has been found to be 1.25 x 10^6 m/s²

Substituting the values, we have that total time that the bullet is in contact with the board = 8 x 10^-5 seconds

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The magnitude of the smallest charge in the box is approximately 19.28 µC.

To solve this problem, we'll use Gauss's law, which states that the net electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of a vacuum.

Net electric flux through the box (Φ) = 6.8 × 10^7 N·m^2/C

Permittivity of vacuum (ε₀) = 8.85419 × 10^−12 C^2/(N·m^2)

Let's assume the magnitude of the first charge placed in the box is q. Since each subsequent charge has a magnitude twice that of the previous one, the charges in the box will be q, 2q, 4q, 8q, and 16q.

Using Gauss's law, we can write the equation:

Φ = (q + 2q + 4q + 8q + 16q) / ε₀

Simplifying the equation:

Φ = 31q / ε₀

Now we can solve for q:

q = (Φ * ε₀) / 31

Substituting the given values:

q = (6.8 × 10^7 N·m^2/C * 8.85419 × 10^−12 C^2/(N·m^2)) / 31

Calculating the result:

q ≈ 1.928 × 10^−5 C

To convert the charge to microcoulombs (µC):

q ≈ 19.28 µC

Therefore, the magnitude of the smallest charge in the box is approximately 19.28 µC.

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Compared to the emitted radio waves, the radio waves reflected from the vehicle and received by the radar gun have a higher frequency.

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second. Its unit is Hz. Frequency is given by the formula as,

A moving car is targeted by radio waves sent from a radar gun by a police officer standing still.

The radio waves reflected off the vehicle and picked up by the radar gun have a greater frequency than the radio waves that were transmitted.

A stationary police officer directs radio waves emitted by a radar gun at a vehicle moving toward the officer.

Compared to the emitted radio waves, the radio waves reflected from the vehicle and received by the radar gun have a higher frequency.

Hence the higher frequency is the correct answer for blanks.

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Answer:

the price per gallon of gas leah paid is 8.58

Explanation:

42.90/5=8.58

2.18X103 N force must be exerted on a nail with a circular tip of 1.00 mm diameter to create a pressure.

diameter, d = 0.95 mm = 0.95x10-3m

P = 3.1X10^9 Pa

r = d/2 = 0.95/2 x 10^-3 m

= 0.475 x 10^-3 m

Area = \(\pi\) r2

= 3.14 x ( 0.475 x 10^-3 m)2

=  = 3.14 x 0.225 x 10^-6

= 0.706 × 10-6 m2

Force = PXA

= 3.1 x 10^9 x 0.70 6 × 10^-6

F = 2.18X103 N

Pressure , within the physical sciences, the perpendicular force in step with unit per area , or the stress at a factor inside a restricted fluid.

A easy instance of pressure can be seen by retaining a knife to a bit of fruit. In case you keep the flat part of the knife towards the fruit, it might not reduce the area. The force is spread out of a massive vicinity (low strain).

The SI unit of pressure is pascal (represented as Pa) which is identical to one newton in line with rectangular metre (N/m2 or kg m-1s-2).

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As a result, the racer's final velocity is 13.00 m/s after accelerating at 0.500 m/s2 for 7.00 s.

Velocity is a vector representation of an object's or particle's displacement with respect to time. The meter per second (m/s) is the standard unit of velocity magnitude (also known as speed). Alternatively, velocity magnitude can be expressed in centimeters per second (cm/s). The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.

Here,

The final velocity can be found using the equation of motion,

vf = vi + at,

where vf is the final velocity, vi is the initial velocity (11.5 m/s), a is the acceleration (0.500 m/s^2), and t is the time for which the acceleration was applied (7.00 s).

Substituting the values we get,

vf = 11.5 + 0.500 * 7.00 = 13.00 m/s.

So, the racer's final velocity is 13.00 m/s as he accelerates at the rate of 0.500 m/s2 for 7.00 s.

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An object's mass, rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force due to an existing field (In most cases, gravitational field) that is experienced by the body. The weight of the same body can be different in different environments it's observed.

However, the mass of the body is the exact measure of the amount of matter contained in a body. Which is constant, regardless of the environment, or conditions the body is observed.

Hence, for real-world calculations and experimentation, the mass of the body is considered to represent the amount of matter it contains rather than its weight.

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The point p on the x-axis that minimizes the sum of distances pq and pr is (2.5, 0).

        Length of pq: sqrt((x-0)^2 + (0-6)^2) = sqrt(x^2 + 36)

        Length of pr: sqrt((x-5)^2 + (0-7)^2) = sqrt((x-5)^2 + 49)

        sqrt(x^2 + 36) + sqrt((x-5)^2 + 49)

        d/dx [sqrt(x^2 + 36) + sqrt((x-5)^2 + 49)] = 0

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Answer:

Reflection involves a change in direction of waves when they bounce off a barrier.

Explanation:

Refraction of waves involves a change in the direction of waves as they pass from one medium to another. Refraction, or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.

a) Required chip rateThe processing gain is given by\[G_p = 10{\log _{10}}\left( {{\rm{\Gamma }}{N_{ch}}/{B_c}} \right)\]where Γ is the number of chips per symbol, Nch is the number of hopping channels, and Bc is the chip rate.To determine the chip rate, we must first determine the symbol rate. In this case, the symbol rate is the same as the sampling rate of the PCM modulator, which is 256 × 3.4 kHz = 870.4 kHz.

Since there are Γ chips per symbol, and the processing gain must be at least 23 dB,\[\begin{gathered}

 23{\rm{ dB}} = 10{\log _{10}}\left( {\Gamma {N_{ch}}/{B_c}} \right) \Rightarrow \hfill \\

 10^{23/10} = \Gamma {N_{ch}}/{B_c} \Rightarrow \hfill \\

 {B_c} = \Gamma {N_{ch}}/{{10}^{23/10}} \hfill \\

\end{gathered} \]Let us suppose that we use a pseudo-random sequence of length m = 4. In this case, the number of chips per symbol is given by\[{\Gamma _{DS-SS}} = {2^m} - 1 = 15\]Thus, substituting into the previous equation, we get\[B_c = \left( {15\, \times \,{N_{ch}}} \right)/{6.309}\]Solving for Bc and substituting the processing gain requirement of 23 dB, we get\[B_c \ge 3.194\,{\rm{MHz}}\]Thus, the required chip rate is at least 3.194 MHz.

b) Number of hopping channels if the speech was transmitted by a frequency-hopping spread spectrum (FH-SS) systemThe number of hopping channels can be determined using the relationship\[N_{ch} \le B_c/W\]where W is the frequency range covered by the frequency-hopping sequence. In a FH-SS system, this frequency range must be larger than the baseband bandwidth of the signal, which in this case is 3.4 kHz. If we choose a frequency range of W = 4 kHz, then we get\[N_{ch} \le B_c/W = 3.194/4 = 798.5\]Since Nch must be an integer, we can choose Nch = 798. Therefore, the number of hopping channels is 798.

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-- impurities in the water

-- air pressure is higher than standard

Answer:

Explanation:

Seatbelts are essential in a car because they serve to hold the vehicle's passengers firmly in their seats during a collision. This reduces the danger of serious injury or death by protecting people from being flung from the vehicle or colliding with hard objects inside the vehicle.

In addition to wearing seatbelts, the following steps can be done to lessen the severity of an accident:

1. Airbags: In modern automobiles, airbags release following a collision to absorb the impact and prevent the occupants from hitting hard objects within the vehicle.

2. Kid safety seats: Children should be properly strapped in a child safety seat that is age and size appropriate.

3. Headrests: Properly positioned headrests can help lessen the risk of whiplash injuries in the event of an accident.

4. Avoiding distractions: One of the primary causes of accidents is distracted driving. Avoiding distractions while driving, such as using a mobile phone, eating, or applying make-up, can assist to lower the chance of an accident.

5. Regular car maintenance, such as regular servicing, tyre pressure checks, and brake checks, may assist to ensure that the vehicle is in excellent condition and lower the danger of an accident.

6. Avoiding aggressive driving: Speeding, tailgating, and making rapid lane changes all raise the chance of an accident.

7. Following traffic rules, such as respecting speed limits, traffic signs, and signals, as well as maintaining a safe distance from other cars, can assist to lessen the likelihood of an accident.