It takes more force to move an object with less mass.
True or false

When soaking items in hot water to heat sanitize them, the minimum temperature required is 171°F (77°C).

Hot water sanitizing is a common method of disinfecting dishes, utensils, and other food contact surfaces in commercial kitchens. To effectively sanitize items using hot water, the water temperature must be hot enough to kill potentially harmful bacteria, viruses, and other pathogens. The minimum temperature required for hot water sanitizing is 171°F (77°C). Items should be submerged in the hot water for at least 30 seconds to ensure proper sanitization. It's important to note that hot water sanitizing is only effective if the items being sanitized have already been thoroughly cleaned, as dirt and debris can shield bacteria from the heat.

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The reason complex ion formation can increase the solubility of insoluble compounds is due to the process of chelation, where a central metal ion is surrounded by molecules or ions, called ligands.

When an insoluble compound interacts with ligands, a complex ion is formed, which is more soluble than the initial compound. This increase in solubility is attributed to the formation of a stable coordination complex, where the ligands donate their lone pair of electrons to the central metal ion, forming coordinate covalent bonds.

In the context of solubility, Le Chatelier's principle states that a system at equilibrium will counteract changes to restore equilibrium. When an insoluble compound forms a complex ion, the equilibrium shifts to favor the formation of more complex ions, leading to an increased solubility.

The formation constant is a measure of the equilibrium between the complex ion and its constituent species, with larger values indicating a more stable complex and greater solubility.

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Glycerol and three fatty acids react via condensation to produce a triglyceride.

Triglycerides, also known as triacylglycerols, are a type of lipid or fat that are commonly found in foods and stored in the body. They are composed of three fatty acids that are linked to a glycerol molecule through ester bonds.

The process of forming a triglyceride is called esterification or condensation reaction, which involves the removal of a water molecule between the carboxyl group of the fatty acid and the hydroxyl group of the glycerol molecule. This process is catalyzed by enzymes called lipases and occurs in both plants and animals.

The three fatty acids that make up a triglyceride can vary in length, degree of saturation, and location of double bonds, which affects the properties and function of the triglyceride. For example, saturated fatty acids tend to be solid at room temperature and are commonly found in animal fats, while unsaturated fatty acids tend to be liquid at room temperature and are commonly found in plant oils.

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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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D is the answer cause two h20 + o2(g)

Answer:

goggles

Explanation:

...................

Answer:

A Bacteria

Explanation:

The empirical formula of this unknown compound with carbon, hydrogen and nitrogen is C2HN3.

Originally, chemical formulas were generated by determining the masses of all the components that combine to create a molecule, and this resulted in two main types of chemistry formulae: molecular formulas and empirical formulas.

A compound's empirical formula offers the simplest ratio of the number of various atoms present, but the molecular formula specifies the actual number of each single element present in a molecule. It is an empirical formula if the formula is simplified. The molecular formula, which is a multiple of the empirical formula, is often employed.

Mass of compound is 0.1156 g

mass of CO2 = 0.1638 g

mass of H2O = 0.1676 g

Molecular weight of CO2 = 44 g

Molecular weight of H2O = 18 g

moles of CO2 = 0.00372

0.00372 x 12 = 0.04464 = C

H = 0.00931 x 2 = 0.01862

N = 0.1156 - (0.04464 + 0.01862) = 0.05234

Empirical formula is,

C:H:N = 0.04464 : 0.01862 : 0.05234 = 0.04 : 0.02 : 0.06

C : H : N = 2 : 1 : 3

So Empirical formula is C2HN3.

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Answer:

Carbon:  14

Oxygen: 16

Nitrogen: 15

Sulpher: 16

Answer: Electrolysis is defined as the process by which electrolyte allows electric current to pass through it and is decomposed in the process.

Explanation:

Substances that allow the passage of electric current are known as conductors. Examples of conductors are metals, graphites. Metals are good conductors of electricity of which an example is LEAD.

Lead is a metal which can be extracted through the process of electrolysis. A substance in solution or liquid state like lead (II) bromide which allows electric current to pass through it and at the same time decompose by it is known as an ELECTROLYTE.

In the electrolysis of lead (II) bromide to obtain Lead,the electrolyte ionize into positive and negative ions. The positive ions migrate to the cathode and are known as captions. The negative ions migrate to the anode and are known as anions.

--> At the CATHODE: Pb2+ gains electrons and Lead is deposited

Pb2+(aq) + 2e -----> Pb(s)

--> At the anode: Br- gives up electrons and is liberated as bromine vapour.

2Br- (aq) ------> Br2(g) + 2e.

Answer:

The formula AgNO3 gives us 1 Ag atom,

1 N atom and

3 oxygen atoms.

From the periodic table we get the atomic mass of each of these atoms:

Ag 108 g/mol,

N 14.0 g/mol,

O 16.0 g/mol

For each atom, mutiply the number of atoms by its atomic mass, and then sum the values:

molar mass of

AgNO3 = (1 x 108) + (1 x 14.0) + (3 x 16.0) = 170 g/mol

So now let’s return to our four step process to solve the problem.

Here’s the updated data:

n = ? mol,

m = 80.00 g,

M = 170 g/mol

Here’s the formula: n = m / M

Now, substitute the data values into the formula:

n = 80.00 / 170

And calculate the answer: n = 0.4705882353 mol

Rounding the answer to 3 significant figures:

DO MARK AS BRAINLIEST

The partial pressure of carbon dioxide gas in the collected sample is 709 mmHg, and the fraction of the mixture that is CO2 is 0.974 or about 97.4%.

The method used to find the density of carbon dioxide gas is by collecting the gas by displacing water in a bottle.

To find the partial pressure of carbon dioxide gas in the collected sample, we need to subtract the partial pressure of water vapor from the total pressure of the mixture:

Partial pressure of CO2 = Total pressure - Partial pressure of water vapor

Partial pressure of CO2 = 730 mmHg - 21 mmHg

Partial pressure of CO2 = 709 mmHg

To find the fraction of the mixture that is CO2, we need to use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Assuming that the volume of the sample is constant and that the temperature is constant at room temperature (around 298 K), we can simplify the ideal gas law to:

P = nRT/V

Since the pressure of the mixture is equal to the sum of the partial pressures of the gases, we can write:

P(total) = P(CO2) + P(H2O)

Solving for n/V for carbon dioxide, we get:

n/V(CO2) = P(CO2)/RT

Substituting the values we have

n/V(CO2) = (709 mmHg)/(0.0821 L atm/K mol x 298 K)

n/V(CO2) = 0.0285 mol/L

Now, we need to find the total number of moles in the sample. We can do this by using the ideal gas law again, this time for water vapor:

P(H2O) = n(H2O)RT/V

Solving for n/V(H2O), we get:

n/V(H2O) = P(H2O)/(RT)

Substituting the values we have:

n/V(H2O) = (21 mmHg)/(0.0821 L atm/K mol x 298 K)

n/V(H2O) = 0.00083 mol/L

Since the volume of the sample is constant, the total number of moles is equal to the sum of the number of moles of CO2 and water vapor:

n(total) = n(CO2) + n(H2O)

Substituting the values we have:

n(total) = (0.0285 mol/L)(V) + (0.00083 mol/L)(V)

n(total) = (0.0293 mol/L)(V)

The fraction of the mixture that is CO2 is:

Fraction CO2 = n(CO2)/n(total)

Fraction CO2 = (0.0285 mol/L)(V)/(0.0293 mol/L)(V)

Fraction CO2 = 0.974

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Answer:

D

Explanation:

Atoms make up all matter on earth, basically atoms make up everything, even air.

Answer:

A one mL per minute rate (or slower) is recommended for best results in a fractional distillation; simple can go faster. Slow, gradual distillation essentially allows the best equilibration and heat transfer. If you heat too fast, vapors may not condense as quickly as desired, and may waste some of the column.

According to the electron sea model, the melting points of metals are not as extreme as the boiling points. Therefore, the given statement is correct is true.

The Electron Sea Model's whole hypothesis relies around the behavior of atoms throughout this bonding. The movement of unpaired electrons between positively charged metal ions in a mesh is known as metallic bonding.

According to the electron sea model, the melting points of metals are not as extreme as the boiling points. This is because the cations and electrons are - in a metal. It does not take much energy for a solid to become liquid. But metallic bonds are very - , so it does require a lot of energy to separate atoms from the cations in their sea of electrons. This statement is true.

Therefore, the given statement is correct is true.

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water at the surface of the ocean can become water vapor and move into the atmosphere with little added energy from the sun through the process called evaporation. The water droplets that form are what we call clouds

Answer:

Over 96% of total global water is in the ocean, so let's start there. Energy from the sun causes water on the surface to evaporate into water vapor – a gas. This invisible vapor rises into the atmosphere, where the air is colder, and condenses into clouds.

Explanation:

Answer:

55,000,000

Explanation:

550 hectometers [hm] = 55,000,000 millimeters [mm]

Answer:

K

Explanation:

Just say that it went below 0/average.

Depending on the toxin, yes. Many things, including proteins, will surely be denatured or degraded and finally turn harmless if we adopt the colloquial definition of the word and include toxins and poisons.

For instance, ricin, botulinum, tetrodotoxin, etc. They are rather delicate, so I'm hoping this toxin has the lowest shelf life.

For a poison, "not up to quality" might indicate anything. It might be more harmful or less toxic. It might be more toxic than before, which would make it less effective against the intended target but extremely harmful to other species. It only indicates that a single chemical may have begun to breakdown, and the final result of that deterioration may be something entirely else.

Small organic molecules make up a lot of other toxins. These include nerve agents like nicotine, sarin, and VX, all of which are capable of being broken down through air oxidation, UV exposure, hydrolysis, and other processes. Numerous nerve agents have a shelf life of several years, and studies have been done to extend their use in weapons.

Lead, mercury, and cadmium are just a few examples of metals that are hazardous because they are toxic not only in their elemental forms but also as inorganic and organic compounds. Although the toxicity of the various forms can varies substantially (see, for example, methylmercury and elemental mercury), the majority of them are nevertheless at least harmful.

These can persist for a very long period since the reactions that can happen under usual circumstances might not be safe, such as a sizable piece of cinnabar left on a desk even throughout the course of a geological time scale. any substantial modification to ensure safety.

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Answer:

Its the second one.

Explanation:

Answer: The volume of the solution is 85.7 mL

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\(\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}\) .....(1)

We are given:

Molarity of solution = 0.600 M

Given mass of \(BaSO_4\) = 12.00 g

We know, molar mass of \(BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol\)

Putting values in equation 1, we get:

\(0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL\)

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL

The inorganic substance with the chemical formula BaSO4 is barium sulfate (or sulphate). It is a tasteless, crystalline white substance that is insoluble in water.

A barium cation and a sulfate anion are the two elements that make up barium sulfate. There are four oxygen atoms joined to the sulfur. A sulfate salt of barium, known as BaSO4, is present in the mineral barite. It is a white crystalline substance that is soluble in strong acids but insoluble in water and alcohol.

Elements include both barium and bromine. Barium is a metal belonging to Group 2 of the modern periodic table, and bromine is a non-metal belonging to Group 17 (halogen).

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The residents of Kansas were overwhelmingly opposed to the Lecompton Constitution. This was large because the document protected slavery and allowed the state government to decide whether slavery should be allowed in the new state.

The people of the state saw this as an affront to their values and democratic rights and worked to defeat the constitution in a state referendum.

After much debate and campaigning, the Lecompton Constitution was defeated by over 10,000 votes. This was a major victory for antislavery advocates, who had worked hard to make sure the constitution was rejected in Kansas.

The residents of Kansas were overwhelmingly opposed to the Lecompton Constitution. This document was drafted by pro-slavery advocates and would have made slavery a permanent institution in the state.

The citizens of Kansas were furious, and it sparked a great deal of debate and conflict. Many residents were so opposed to the document that they decided to form an independent government and reject the Lecompton Constitution in a referendum.

The referendum passed in an overwhelming majority, and the Lecompton Constitution was rejected. This event was a major milestone in the struggle for free-state rights in the Midwest and demonstrated the power of the people to resist oppressive legislation.

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Answer: The answer is B. The pressure inside the tires increased.

Explanation:

The relationship between the pressure, volume, and temperature of a gas is described by the ideal gas law, which is usually written as:

\($$PV = nRT$$\)

where:

- \(\(P\)\) is the pressure,

- \(\(V\)\) is the volume,

- \(\(n\)\) is the number of moles of gas,

- \(\(R\)\) is the ideal gas constant, and

- \(\(T\)\) is the temperature (in Kelvin).

In this case, the volume \(\(V\)\) and the number of moles \(\(n\)\) of air in the tires stay the same. The temperature \(\(T\)\) is increasing. Therefore, for the equation to remain balanced, the pressure \(\(P\)\) must also increase.

So, the answer is B. The pressure inside the tires increased.

Answer

H₂O₂ undergoes oxidation

KMnO₄ undergoes reduction

Explanation

Given equation:

3H2SO4 + 2KMnO4 + 5H2O2 --> 5O2 + 2MnSO4 + 8H2O + K2SO4

The oxidation number of O in H₂O₂ is -1 and this changes to o in O₂ on the product side. Hence, H₂O₂ undergoes oxidation.

The oxidation number of Mn in KMnO₄ is +7 and changes to +2 in MnSO₄ on the product side. Therefore, KMnO₄ undergoes reduction.