Which of the following samples contains the greatest number of atoms?
a. 9 mole of CO2 b. 10 moles of Xe
c. 11 moles of N2O d. 12 moles of CO
Answer:
12 moles of CO
Explanation:
According to Avogadro, one mole of a substance, contains the same number of elementary entities as 12g of carbon-12. Now the number of elementary entities (atoms, molecules, ions, particles etc) in any substance is given by the Avogadro's constant.
Now since 1 mole of a substance contains Avogadro's number of atoms, it means that the substance with the highest number of moles will have the highest number of atoms.
With this in mind we can see that 12 moles of CO is expected to contain 72.24 ×10^23 atoms of CO. Hence the answer.
Answer:
c. 11 moles of N2O.
Explanation:
Hello,
In this case, for each substance, we use the Avogadro's number to compute the number of atoms in the given sample:
a.
\(atoms \ C=9molCO_2*\frac{1molC}{1molCO_2} *\frac{6.022x10^{23}atoms\ C}{1molC} =5.4x10^{24}atoms\ C\)
\(atoms \ O=9molCO_2*\frac{2molO}{1molCO_2} *\frac{6.022x10^{23}atoms\ O}{1molO} =1.1x10^{25}atoms\ O\)
\(Total\ atoms=1.1x10^{25}+5.4x10^{24}=1.64x10^{25}atoms\)
b.
\(atoms \ Xe=10molXe *\frac{6.022x10^{23}atoms\ Xe}{1molXe} =6.022x10^{24}atoms\)
c.
\(atoms \ N=11molN_2O*\frac{2molN}{1molN_2O} *\frac{6.022x10^{23}atoms\ N}{1molN} =1.3x10^{25}atoms\ N\)
\(atoms \ O=11molN_2O*\frac{1molO}{1molN_2O} *\frac{6.022x10^{23}atoms\ O}{1molO} =6.6x10^{24}atoms\ O\)
\(Total\ atoms=1.3x10^{25}+6.6x10^{24}=2.0x10^{25}atoms\)
d.
\(atoms \ C=12molCO_2*\frac{1molC}{1molCO_2} *\frac{6.022x10^{23}atoms\ C}{1molC} =7.2x10^{24}atoms\ C\)
\(atoms \ O=12molCO_2*\frac{1molO}{1molCO_2} *\frac{6.022x10^{23}atoms\ O}{1molO} =7.2x10^{24}atoms\ O\)
\(Total\ atoms=7.2x10^{24}+7.2x10^{24}=1.44x10^{25}atoms\)
Thus, we notice 11 moles of N2O have the greatest number of atoms.
Best regards.
Based on how they obtain their food, fungi are _____. A plant-like B animal-like
Answer:
whats is it?
Explanation:
Answer: A. Plant Like
Explanation:
They can obtain energy from photosynthesis through the sun.
Explain how the cohesive and adhesive properties of water are useful in maintaining various life processes.
Answer:
Water molecules' adhesion aids plants in moisture absorption at their roots. Water's initial boiling point is attributed to cohesion, which helps animals regulate their body temperature.
Explanation:
Seaweed attached to rocks in the ocean performs photosynthesis underwater. Which statement best explains how some seaweed can survive in very deep and dark places in the ocean? It can use a small amount of sunlight for photosynthesis. It can use a small amount of sunlight for photosynthesis. It moves to the upper levels of the ocean to get sunlight for photosynthesis. It moves to the upper levels of the ocean to get sunlight for photosynthesis. It does not need any sunlight to perform photosynthesis. It does not need any sunlight to perform photosynthesis. It produces its own sunlight to perform photosynthesis. It produces its own sunlight to perform photosynthesis.
Answer:
It can use a small amount of sunlight for photosynthesis
Explanation:
Seaweeds are a group of marine plants/algae that grow attached to rocks underwater. However, despite their depth underwater, they still perform photosynthesis, which is a process that requires energy from sunlight.
Seaweeds are able to perform photosynthesis underwater because they are efficient users of sunlight energy. Hence, they require only a small amount of sunlight that penetrates the ocean to perform photosynthesis.
The melting and boiling points of table salt and table sugar are given below.
Why does table salt have much higher melting and boiling point than table sugar?
o A strong ion -ion attractions in table salt
O B. weak ion-ion attractions in table sugar
O C. strong ion-ion attractions in table sugar
O
D. weak ion-ion attractions in table salt
Answer:
weak ion attractions in the table salt
What is the molarity of a sugar solution at 25°C that has 100.0 g of glucose, C6H12O6 (molar mass = 180 g/mol) dissolved in 1.50 L of water?
Molarity also known as molar concentration is a measurement of moles of a solute compared to the total volume of the solution.
Some general formulas to help us answer this question:
\(C=\frac{n}{v}\)
C= molar concentration/molarity (M or mol/L)n= moles of solutev= volume of solution (measured in L)\(MM=\frac{m}{n}\)
MM = molar mass (g/mol)m= mass (g) n = molesTo calculate the molarity we must first find moles. This is possible given the mass of solute (glucose) and the molar mass of glucose.
Rearranging the second equation we get : \(n=\frac{m}{MM}\)
\(\frac{100.0g}{180g/mol} =0.5556 mol\)
Now we can use \(C=n/v\) to calculate molarity
\(C=\frac{0.5556mol}{1.50L}\)
\(C = 0.370 mol/L\)
if an electron is in a stationary state of an atom, is the electron at rest? if not, what does the term mean?
No, a stationary state is one that has a specific amount of energy, total angular momentum, and parity; in a stable state, the particle is moving while possessing all of these physical characteristics.
Who or what is an electron?A negative charge subatomic particle known as an electron can either be free or attached to an atom (not bound). Each of the three main types of components within an atom is an atom that is bonded to it; the other three are proton and neutrons.
What is the electron example?The electron, the smallest constituent part of an atom, has a negative surface charge. Protons and electrons are present in an atom in a neutral state in an equal number. The hydrogen ion only possesses one atom or one proton. On the other way, the uranium atom possesses 92 protons, which means 92 electrons.
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8.0 dm of NO is mixed with 6.0 dm3 of O, at room temperature and pressure (RTP).
The reaction below takes place until one of the reactants is used up.
2NO(g) + O2(g) + 2NO,(9)
What is the volume of the mixture at RTP after the reaction has taken place?
A)8.0 dm3
B)10.0 dm3
C)12.0 dm3
D)14.0 dm3
Answer:
B)10.0 dm3
Explanation:
Now we have to apply Gay-Lussac's law which states that gases combine in simple volumes provided the temperature and pressure remain constant.
2NO(g) + O2(g) ------>2NO
combining volumes 2 : 1 : 2
Volumes before reaction 8.0 6.0 0.0
Reacting volumes 8.0 4.0 8.0
Volumes after reaction - 2.0 8.0
Therefore;
Total volume after reaction = 2.0 + 8.0 = 10.0 dm^3
The volume of the mixture after the reaction is 10 dm³
The correct answer to the question is Option B. 10 dm³
The above is simply a demonstration of Gay-Lussac' law. The volume of the mixture after the reaction can be obtained as follow:
2NO(g) + O₂ —> 2NO(g)
Combining Vol: 2 dm³ : 1 dm³ : 2 dm³
Before reaction: 8 dm³ : 6 dm³ : 0
During reaction: 8 dm³ : 4 dm³ : 8 dm³
After reaction: 0 dm³ : 2 dm³ : 8 dm³
The Volume after the reaction = 2 + 8 = 10 dm³
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Which isotope of helium is more tightly bound, 72H or 52H? (Atomic mass of 7He = 7.027991 u and atomic mass of 5He = 5.012057 u) OA. 5₂H OB.72H C. Both isotopes are equally bound. D. Not enough information.
Option b-A The isotope ⁷₂H (7He) is more tightly bound than ⁵₂H (5He).
The stability of an isotope depends on its binding energy, which represents the amount of energy required to break apart the nucleus into its constituent particles. Higher binding energy indicates greater stability and tighter binding of nucleons within the nucleus.
To determine which isotope is more tightly bound, we compare their binding energies. The binding energy is related to the mass defect, which is the difference between the sum of the masses of the individual nucleons and the actual mass of the nucleus.
In this case, the atomic mass of ⁷₂H (7He) is 7.027991 u, and the atomic mass of ⁵₂H (5He) is 5.012057 u. The greater the mass defect, the more tightly bound the nucleus. Since the mass defect of ⁷₂H (7He) is greater than that of ⁵₂H (5He), it implies that ⁷₂H (7He) has a higher binding energy and is more tightly bound.
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About how long does it take Earth to complete one revolution around the Sun?
1 year
14 days
24 hours
27.3 days
Next
Submit
Save and Exit
Mark this and retum
rotodo
o
Answer:
A) one year
Explanation:
One complete revolution takes 365.25 days, or one year.
Answer:
1 year
Explanation:
I need help with this question
Answer:
Liquid; melting.
Explanation:
So what is being shown is a phase change diagram. Because we start at an atm of 1.5 (staying steady means that it doesn't drop so we always stay at 1.5 atm) and at a temperature of -150, the original state of matter is a solid. Next, we look at what happens when the temperature goes to 300 degrees, yet still maintaining the 1.5 atm. This means that it now turns into a liquid (based on placement on diagram). This means the matter after the temperature change was a liquid. And going from solid to liquid would be called melting.
Here's an example phase diagram so that you can rely on it in the future problems!
during the antarctic spring, ozone is destroyed at a greater rate than it is formed
Answer:answer is d. All choices are correct
Explanation:
a. on the surface of atmospheric crystals
b. in polar stratospheric clouds
c. in a process that is catalytic
d. all of these choices are correct
What is the mass of n2 in the equilibrium mixture?.
The mass of N₂ in the equilibrium mixture can be determined through the mole concept and the application of the ideal gas law. Since the equilibrium mixture contains both N₂ and O₂ gases, the equation that will be used to determine their masses is as follows:
2N₂(g) + O₂(g) ⇌ 2NO(g)
The balanced equation shows that two moles of N₂ react with one mole of O₂ to produce two moles of NO. This means that the initial number of moles of N₂ in the mixture will be twice the number of moles of NO. The mass of N₂ can be calculated using the ideal gas law, which is PV = nRT.
The given conditions can be used to calculate the partial pressure of N₂, which can then be used to determine the number of moles of N₂ in the mixture and the corresponding mass of N₂.
To calculate the partial pressure of N₂, the mole fraction of N₂ must first be determined. This can be done using the equation:
X(N₂) = n(N₂) / n(total)
where X(N₂) is the mole fraction of N₂, n(N₂) is the number of moles of N₂, and n(total) is the total number of moles of gas in the mixture. Since there are no other gases in the mixture, the mole fraction of N₂ will be equal to the number of moles of N₂ divided by the total number of moles of gas.
Using the ideal gas law, the partial pressure of N₂ can then be calculated:
P(N₂) = X(N₂) * P(total)
where P(N₂) is the partial pressure of N₂, X(N₂) is the mole fraction of N₂, and P(total) is the total pressure of the mixture. The total pressure can be calculated using Dalton's law of partial pressures, which states that the total pressure is equal to the sum of the partial pressures of all the gases in the mixture. Once the partial pressure of N₂ has been determined, the number of moles of N₂ in the mixture can be calculated using the ideal gas law:PV = nRTwhere P is the partial pressure of N₂, V is the volume of the mixture, n is the number of moles of N₂, R is the gas constant, and T is the temperature in Kelvin. Rearranging this equation to solve for n, we get:
n = PV / RT
Finally, the mass of N₂ in the mixture can be calculated using the molar mass of N₂ and the number of moles of N₂:
mass(N₂) = n(N₂) * M(N₂)
where M(N₂) is the molar mass of N₂.
The mass of N₂ in the equilibrium mixture can be determined using the ideal gas law and the mole concept. The partial pressure of N₂ can be calculated using the mole fraction of N₂ and the total pressure of the mixture. The number of moles of N₂ can then be calculated using the partial pressure, volume, temperature, and gas constant. Finally, the mass of N₂ can be calculated using the number of moles and the molar mass of N₂.
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what is the empirical formulaa for a compound that has 40 g Carbon, 6.71g Hydrogen and 53.30g Oxygen?
The empirical formulaa for a compound that has 40 g Carbon, 6.71g Hydrogen and 53.30g Oxygen is CH2O.
Originally, chemical formulas were attained by determination of millions of all the rudiments that are combined to form a patch and latterly we come up with two important types of formulas in chemistry molecular formula and empirical formula.
The empirical formula of a emulsion gives the simplest rate of the number of different tittles present, whereas the molecular formula gives the factual number of each different snippet present in a patch. If the formula is simplified also it's an empirical formula. The molecular formula is generally used and is a multiple of the empirical formula.
In 100 g of the unknown, there are 40g/12.011gmol C
6.7g/1.00794 gmolH ,, 53.3g/16.00 g molO
We divide thru to get,
C:H:O = 3.33:6.65:3.34.
When we divide each elemental ratio by the LOWEST number, we get an empirical formula of CH2O, i.e. near enough to WHOLE numbers.
Now the molecular formula is always a multiple of the empirical formula; i.e.
Clearly n=2, and the molecular formula is 2×(CH2O) = CxHyOz.
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explain how ships made of steel float on water
Answer:
The air that is inside a ship is much less dense than water. That's what keeps it floating
WILL GIVE BRAINLIEST
Which model provides more information-a chemical formula or a sketch of the molecule
like in the structural formula? Explain your reasoning.
Answer:
Explanation
:Both b/c a chemical formula tells you how many and a sketch formula shows how they are bonded together.
Molecular formulas show how many atoms of each element one molecule of a compound contains. Note: Ionic compounds are generally crystalline solids with high melting points. Other compounds, however, have very different properties.
Which equation represents the correct net ionic equation for the reaction between Ca(OH)2 and H2SO4?
Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O.
2 upper H superscript plus, plus 2 upper O upper H superscript minus right arrow upper H subscript 2 upper O.
Upper C a superscript 2 plus, plus 2 upper O upper H superscript minus, plus upper S upper O subscript 4 superscript 2 minus right arrow upper C a superscript 2 plus, plus upper S upper O subscript 4 superscript 2 minus, plus 2 upper H subscript 2 upper O.
Upper C a (upper O upper H) subscript 2 plus upper H subscript 2 upper S upper O subscript 4 right arrow upper C a upper S upper O subscript 4 plus 2 upper H subscript 2 upper O.
Answer: The equation Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O represents the correct net ionic equation for the reaction between \(Ca(OH)_{2}\) and \(H_{2}SO_{4}\).
Explanation:
An ionic equation is defined as the equation where both reactants and products are present in the form of ions.
For example, ionic equation between \(Ca(OH)_{2}\) and \(H_{2}SO_{4}\) is as follows.
\(Ca^{2+} + 2OH^{-} + 2H^{+} + SO^{2-}_{4} \rightarrow Ca^{2+} + SO^{2-}_{4} + 2HOH\)
Cancelling the spectator ions then net ionic equation will be as follows.
\(2H^{+} + 2OH^{-} \rightarrow H_{2}O\)
Thus, we can conclude that the equation Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O represents the correct net ionic equation for the reaction between \(Ca(OH)_{2}\) and \(H_{2}SO_{4}\).
Which coefficient is needed in front of NaNO3 to balance the equation Na2S Zn(NO3)2 → ZnS _NaNO3? 1 2 5 7.
Answer:
2
Explanation:
In this way, the number reagents' atoms of Na, N and O is the same of the products.
The equation will be balanced when the coefficient 2 is placed in front of NaNO3.
The principle that governs the balancing of reaction equations is that the number of atoms of each element on both sides of the reaction equation must be the same.
Let us consider the reaction; Na2S + Zn(NO3)2 -------> ZnS + NaNO3, the equation will be balanced when the coefficient 2 is placed in front of NaNO3.
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how many grams are in 45L of neon gas at STP?
The mass of 45 L of neon gas at STP is 40.7 grams.
How to find how many grams are in 45L of neon gas at STP?
At STP (standard temperature and pressure), the temperature is 0°C or 273.15 K and the pressure is 1 atm. The molar volume of an ideal gas at STP is 22.4 L/mol.
Neon gas has a molar mass of approximately 20.18 g/mol. To find the number of moles of neon gas in 45 L at STP, we can use the following equation:
n = V / Vm
where
n is the number of molesV is the volume Vm is the molar volume of the gasn = 45 L / 22.4 L/mol = 2.0089 mol
To convert moles to grams, we can use the molar mass of neon gas:
m = n * M
where m is the mass, n is the number of moles, and M is the molar mass.
m = 2.0089 mol * 20.18 g/mol = 40.7 g
Therefore, the mass of 45 L of neon gas at STP is 40.7 grams.
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Ifa container of nitrogen and oxygen gas holds 2. 50 atm of N2 gas and 1. 50 atm of O2 gas, what
is the total pressure inside the container?
The total pressure inside the container is 4.00 atm. This is because the total pressure of a gas mixture is equal to the sum of the individual pressures of each gas present. In this case, we have 2.50 atm of N2 gas and 1.50 atm of O2 gas.
When these two values are added together, we get the total pressure of 4.00 atm. This total pressure is also known as the partial pressure of the gas mixture.
The partial pressure of the gas mixture is the sum of the individual partial pressures of each gas present. Since the total pressure of a gas mixture is equal to the sum of the individual pressures of each gas present, the total pressure in the container is 4.00 atm.
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On the basis of electronegativity differences between atoms, which of the following scientific claims is the most accurate regarding the bonding in Mg(NO3)2(8) ?
A) There is polar covalent bonding between Mg atoms and N atoms.
B) There is polar covalent bonding between Mg atoms and O atoms.
C) There is ionic bonding between N5+ ions and O2- ions.
D) There is ionic bonding between Mg2+ ions and NO3- ions.
There is ionic bonding between Mg²⁺ ions and NO₃⁻ ions. A Further explanation is below.
Ionic bonding seems to be a form of interaction wherein the cationic as well as unpaired electrons are powerfully electrostatically connected.
Throughout the general view, the ionic bonding occurs between someone metal/nonmetal owing to their large electro(-) discrepancy, while bond formation occurs between nonmetals due to the relatively low electro(-) gap.Even though there are metals as well as non-metals, the relative electronegativity differential between (Mg²⁺) and (NO₃⁻) however is large.Thus the above response i.e., option D) is correct.
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2. which atoms (or groups of atoms) can have expanded octets?
a. F
b. Cl
c. N
d. B
e. O
The atoms (or groups of atoms) that can have expanded octets are option c. N and option e. O.
An octet is a set of 8 electrons in an atom's outer shell. The octet rule is a chemical rule that explains how atoms combine and behave chemically by requiring them to have complete outer electron shells consisting of eight electrons. When considering covalent bonding in a compound, the octet rule states that atoms will donate, accept, or share electrons to achieve a full valence shell of eight electrons.
Expanded octets occur when an atom in a compound has more than eight electrons in its outer shell. Expanded octets are only observed for elements in period three and above because of the d orbitals in the valence shell, which allows for more electrons to be held.
Expanded octets can exist due to the existence of d-orbitals in elements. The most popular expanded octets are found in phosphorus, sulfur, and chlorine.
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Which scientist did people think was insane so they dismissed his ideas for almost 2000 years?
A twin-turbojet airplane is cruising with a speed of Mach 1.5 at an altitude where atmospheric pressure is 32989.5 Pa, temperature is 232.778 K. Each engine is consuming 200 kg of air per second. The engine exit flow has a pressure of 32,000 Pa with a velocity of 850 m/sec. The exit area of the engine nozzle is 1.4 m
2
. How much thrust both engines are generating?
A twin-turbojet airplane is cruising with a speed of Mach 1.5 at an altitude where atmospheric pressure is 32989.5 Pa, temperature is 232.778 K. Each engine is consuming 200 kg of air per second. The engine exit flow has a pressure of 32,000 Pa with a velocity of 850 m/sec. The exit area of the engine nozzle is 1.4 m². The thrust generating in both engines is 342,678.6 Newtons.
To calculate the thrust generated by both engines, we can use the momentum equation for a nozzle:
Thrust = mass flow rate * exit velocity + (exit pressure - ambient pressure) * exit area
Given:
Speed of the airplane (V) = Mach 1.5
Atmospheric pressure (\(P_a\)) = 32989.5 Pa
Ambient temperature (\(T_a\)) = 232.778 K
Mass flow rate of each engine (m) = 200 kg/s
Exit pressure of the engine (\(P_e\)) = 32000 Pa
Exit velocity of the engine (\(V_e\)) = 850 m/s
Exit area of the engine nozzle (\(A_e\)) = 1.4 m²
First, we need to calculate the ambient density using the ideal gas law:
PV = nRT
Since the speed of the airplane is given in terms of Mach number, we can calculate the speed of sound (a) using the following formula:
a = √(gamma * R * \(T_a\))
Where gamma is the specific heat ratio of air (approximately 1.4) and R is the specific gas constant for air (approximately 287 J/(kg K)).
Next, we can calculate the ambient density (ρ) using the equation:
ρ = \(P_a / (R * T_a)\)
Now, we can calculate the thrust generated by each engine using the momentum equation:
Thrust = m* \(V_e + (P_e - P_a) * A_e\)
Finally, we can calculate the total thrust generated by both engines by multiplying the thrust of a single engine by 2.
Calculate the speed of sound:
a = √(1.4 * 287 * 232.778)
a = 438.95 m/s
Calculate the ambient density:
ρ = 32989.5 / (287 * 232.778)
ρ = 1.383 kg/m³
Calculate the thrust of a single engine:
\(Thrust_s\) = 200 * 850 + (32000 - 32989.5) * 1.4
\(Thrust_s\) = 170000 + 1339.3
\(Thrust_s\) 171339.3 N
Calculate the total thrust of both engines:
\(Thrust_t\) = 2 * \(Thrust_s\)
\(Thrust_t\) = 2 * 171339.3
\(Thrust_t\) = 342678.6 N
Therefore, both engines are generating approximately 342,678.6 Newtons of thrust.
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Given the speed of light as 3.0 ✕ 108 m/s, calculate the wavelength of the electromagnetic radiation whose frequency is 6.700 ✕ 1012 Hz.
Answer:
Wavelength = \(4.48*10^{-5}m\)
Explanation:
Given the following data;
Speed of light, V = 3 * 10^{8}m/s
Frequency, F = 6.700 * 10^{12}Hz.
To find the wavelength
We know that that the speed of light is given by the formula;
\( Speed of light, V = wavelength * frequency \)
Making wavelength the subject of formula, we have;
\( Wavelength = \frac {speed \; of \; light}{frequency} \)
Substituting into the equation, we have;
\( Wavelength = \frac {3 *10^{8}}{6.700 ✕ 10^{12}} \)
Simplifying the equation, we have;
Wavelength = 4.48*10^{-5} m
Therefore, the wavelength of the electromagnetic radiation is \(4.48*10^{-5} meters\)
Kg/L ? Determine the mass of salt in the tank after tmin. Mass =kg When will the concentration of salt in the tank reach 0. 03 kg/L ? The concentration of salt in the tank will reach 0. 03 kg/L after minutes. (Round to two decimal places as needed. ) A cold drink initially at 35
∘
F warms up to 38
∘
F in 3 min while sitting in a room of temperature 72
∘
F. How warm will the drink be if left out for 30 min? If the drink is left out for 30 min, it will be about
∘
F. (Round to the nearest tenth as neede
The mass of salt in the tank after t minutes can be determined using the formula: Mass of salt = concentration of salt × volume of solution.
To find the mass of salt in the tank after t minutes, we need to multiply the concentration of salt by the volume of the solution. The concentration of salt is given as 0.03 kg/L, and the volume of the solution is given as kg. Therefore, the mass of salt can be calculated by multiplying 0.03 kg/L by kg.
The concentration of salt in the tank will reach 0.03 kg/L after minutes. This means that at this time, the amount of salt in the tank will be such that if it is divided by the volume of the solution, it will equal 0.03 kg/L. To calculate the time it takes for the concentration of salt to reach 0.03 kg/L, we need to divide the mass of salt by the volume of the solution and then multiply it by 1/L. This will give us the time in minutes.
In the second part of the question, a cold drink initially at 35°F warms up to 38°F in 3 minutes while sitting in a room of temperature 72°F. To find how warm the drink will be if left out for 30 minutes, we need to consider the rate at which the drink warms up and the time it is left out.
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Which of the following correctly illustrates the conservation of mass for the reaction below? I choose B but I’m not sure if I’m correct!
Answer: A
\(Na(23\times4=92g);O2(16\times2=32g);Na2O(23+23+16)\times2=124\)Explanation: Based on the Law of conservation of mass the total mass of the reactants will equal to the total mass of the products. This happens as matter is not destroyed.
Ms. Terries was given a beautiful deep red gem. She knew she might be holding a ruby. Or, she might be holding a stone worth more than rubies, a stone rared than diamonds – a red beryl. Ms. Terries needed to be careful in her calculations. Red Beryl is a mixture of minerals and its density can be anywhere from 2.63g/cm3 to 2.92 g/cm3 Rubies can also vary in density from 3.9 g/cm3 to 4.1 g/cm3. Ms. Terries weighed the stone. It weighed 4.35 g. When put into a graduated cylinder of water, the water level rose 1.5 mL. Determine the density of the gem. Was it ruby or red beryl?
Answer:
red beryl
Explanation:
Red Beryls = Density range is 2.63g/cm3 to 2.92 g/cm3
Rubies = Density Range is 3.9 g/cm3 to 4.1 g/cm3
Mass of stone = 4.35 g
Volume of solid = change in water level = 1.5 mL = 1 cm3
Relationship between mass, volume and density is given by;
Density = Mass / Volume
Density = 4.35 / 1.5 = 2.9 g/cm3
The density of the stone falls in the red beryls range hence it is a red beryl.
where do we get the mass number
Explanation:
Mass number is the sum of the numbers of protons and neutrons present in the nucleus of an atom.
A sample of sodium hydroxide (naoh) has a mass of 160.0 g. the molar mass of naoh is 40.00 g/mol. how many moles of naoh does this sample contain? 4.000 moles 40.00 moles 160.0 moles 6,400 moles
The number of moles the sample of sodium hydroxide (NaOH) will contain is 4 moles.
How we calculate moles?Moles of any substance will be calculated by using the below formula:
n = W/M, where
W = given mass
M = molar mass
Given mass of NaOH = 160 g
Given molar mass of NaOH = 40 g/mole
On putting these values on the above equation, we get
n = 160 / 40 = 4 moles
Hence, required moles is 4 moles.
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Answer:
A). 4.000
Explanation:
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