Heating devices can be made by passing an electric current through a conductor of:


high resistance
low resistance
high conductivity
low conductivity

The oxidation of a) 1-hexanol b) 2-hexano c) hexanal with CrO3 in aqueous acid gives 1-hexanoic acid, 2-hexanone and 1-hexanoic acid respectively. The oxidation with PCC gives 1-hexanaldehyde, 2-hexanone and no reaction respectively.

What is PCC?

PCC is also called as pyridinium chlorochromate which is a yellow-orange salt. this is primarily used for the oxidation of alcohols which gives carbonyl compounds as products. It is one of the highly effective oxidizing agents for alcohols.

The oxidation of alcohols with CrO3 gives carbonyl compounds like aldehydes and ketones. With primary alcohol and aldehydes it gives carboxylic acid, whereas with secondary alcohol it gives ketones as products. PCC with primary alcohols give aldehyde, with secondary alcohols give ketone and with aldehyde there is no reaction.

Therefore, CrO3 with 1-hexanol and hexanal gives 1-hexanoic acid, with 2-hexanol gives 2-hexanone. PCC with 1-hexanol gives 1-hexanaldehyde, 2-hexanol gives 2-hexanone and with hexanal there is no reaction.

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Answer:

I think it is b

Explanation:

but I'm not for sure that the answer is right

Molecules are compounds that make covalent bonds between atom. In a covalent bond, the electrons from each atom invoved are shared between them, sticking the atoms together.

In ionic compounds, the electrons of each atoms are not shared, they are part of either of the ions. The ions sticke together because they are charged with opposite charges, so they attract each other.

So, ionic compounds are not considered individual molecules because they don't make covalent bonds, that is, their atoms don't shared electrons, they attract each other because of their opposite charges.

Answer: A

Explanation: A

5. To solve question 5, we need to know the molecular formula of Uraninite, which is UO2.

So we need to know the molar mass of U and of O. We can look for it at the periodic table.

Molar mass of Uranium: 238.02891 g/mol

Molar mass of Oxygen: 15.999 g/mol

In the compound, we have 1 uranium and 2 oxygen.

So to calculate the percent of Uranium, we use a rule of 3:

270.03 ---- 100% (It is the molar mass of the compound)

238.0289 ---- x% (It is the molar mass of uranium)

270.09 * x = 238.0289 * 100

x = 23,802.89/270.09

x = 88.13%

So the percent of uranium in uraninite is 88.13%

Now for oxygen:

We have 2 atoms of oxygen in UO2, so we need to multiply its molar mass by 2: 15.999*2 = 31.998

Now we do the same rule of 3:

270.03 ---- 100% (It is the molar mass of the compound)

31.998 ---- x% (It is the molar mass of 2 atoms of oxygen)

x = 11.72%

The percent of oxygen in uraninite is 11.72%

Answer: As a second follow up to Question 3, uraranite is 88.13% uranium and 11.72% oxygen by mass.

Answer: It will take 68 days for the palladium to decay.

Explanation: ima smart dude

Answer:

my sources say that there is a lot of empty space between then

Explanation:

their forces to attract each other is not strong

kinetic energy is always high in gasses

Answer: The answer is D,

17.93 grams of oxygen gas occupy 12.3L of space at 109.4 kPa and 15.4°C. Details about how to calculate mass can be found below.

The mass of a given gas can be calculated by multiplying the number of moles of the substance by its molar mass.

However, the number of moles of the gas must be calculated first as follows:

PV = nRT

Where;

1.079 × 12.3 = n × 0.0821 × 288.4

13.27 = 23.68n

n = 13.27/23.68

n = 0.56mol

Mass = 0.56 × 32

mass of oxygen gas = 17.93g

Therefore, 17.93 grams of oxygen gas occupy 12.3L of space at 109.4 kPa and 15.4°C.

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Answer:

I thinks something bad will happen but science can change so im not sure

Explanation:

Science changes because of diffrent thing like enviorment

The mass of copper deposited is 9.589 g .

Given ,

A volatile cell using Cu/Cu2+ and Sn/Sn2+ half cells is set up at standard conditions ,and each compartment has a volume of 345 ml .

current = 0.17 A

time = 48 hrs =48 (60) (60) =172800 sec

we know , I = Q/t

thus , Q ,charge= It = 0.17 (17280) =29376 C

Then ,atomic mass of copper is 63 g

And valency of Cu is 2.

Thus , the equivalent mass of copper is 63/2 = 31.5

We know , 96500 coulombs of electricity produce copper = 31.5 g

29376 C of electricity produce copper =9.589 g

Hence , 9.589 g of Copper is deposited .

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Answer:

it can be increased by the number of atoms on each side

The vertical jumps in the plot at the melting and boiling points represent the abrupt increase in entropy that occurs during phase transitions from solid to liquid and from liquid to gas.

The plot shows vertical jumps at the melting and boiling points because the transition from one phase to another involves a change in the entropy (S) of the substance. At the melting point, the substance undergoes a phase transition from solid to liquid, resulting in an abrupt increase in entropy. Similarly, at the boiling point, the substance transitions from liquid to gas, leading to another sudden increase in entropy.

The melting and boiling points represent phase transitions where the substance undergoes a change in its physical state. During these transitions, the arrangement and movement of particles change, leading to a significant alteration in entropy.

At the melting point, a solid substance absorbs energy to overcome intermolecular forces and transition into a liquid state. This transition involves an increase in entropy as the particles gain more freedom to move around, leading to a jump in the entropy value on the plot.

Similarly, at the boiling point, a liquid substance absorbs energy to overcome intermolecular forces and transition into a gaseous state. This transition also results in an increase in entropy as the particles gain even more freedom of movement and are dispersed in the gas phase, causing another vertical jump in the entropy value on the plot.

In summary, the vertical jumps in the plot at the melting and boiling points represent the abrupt increase in entropy that occurs during phase transitions from solid to liquid and from liquid to gas.


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Answer:

it is 0.24 M

Explanation

Find the molarity of all ions in a solution that contains 0.165 moles of aluminum chloride in 820. ml solution. " Answer: [Al 3+1= 0.201 M. (CI) = 0.603M. ... 2) Find the molartiy  of each ion present after mixing 27 ml of 0.25 M HNO3 with 36 ml of ... of each ion and the mass of any precipitate when a 0.300 mole of aluminum.

Answer: This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May i have brainliest please and don't forget to drop a heart

Answer:

437 g

Explanation:

as mass = density × volume

Answer:  50 nm

Explanation:  Two steps:

1.  Divide 3.25/6.5 = 0.5

2.  Divide 10^8/10^6 = 10^2

nm^2/nm = nm

Combine:  0.5x10^2 nm

or 50 nm

The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:

2 SO2(g) + O2(g) → 2 SO3(g)

To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.

To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:

S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol

Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:

2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1

Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:

2 SO2(g) + O2(g) → 2 SO3(g) ΔH2

Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:

ΔH2 = ΔHf° - ΔH1

Substituting the given values, we get:

ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol

Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.

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The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:

2 SO2(g) + O2(g) → 2 SO3(g)

To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.

To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:

S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol

Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:

2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1

Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:

2 SO2(g) + O2(g) → 2 SO3(g) ΔH2

Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:

ΔH2 = ΔHf° - ΔH1

Substituting the given values, we get:

ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol

Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.

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They would be molecular based off of molecule structure I believe.  

(refer to a molecular model)

Answer:

I would say B but you don't have to take my word for it

Answer:

D

Explanation:

The concentration of Na ions in the final solution is 2.67 M.

To determine the concentration of Na ions in the final solution, we need to consider the amount of Na ions contributed by each compound.

From 100 mL of 1.60 M Na2SO4, we have:

Na ions = 2 * (1.60 M) * (0.100 L) = 0.320 moles

From 200 mL of 2.40 M NaI, we have:

Na ions = 1 * (2.40 M) * (0.200 L) = 0.480 moles

To find the total moles of Na ions in the final solution, we add the moles from Na2SO4 and NaI:

Total Na ions = 0.320 moles + 0.480 moles = 0.800 moles

To calculate the concentration of Na ions in the final solution, divide the total moles by the total volume of the solution:

Concentration = Total moles / Total volume

Concentration = 0.800 moles / (100 mL + 200 mL) = 0.800 moles / 0.300 L = 2.67 M

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Answer:

the solvent =water+coffee powder

the solute =sugar

Explanation:

Breaking up, crushing or grinding a sugar cube before adding it to water increases the sugar's surface area. The more surface area a solute has, the faster it will dissolve because more particles of the sugar can interact with the water. This means the finer the sugar particles meaning a larger surface area which leads to an increase in a faster reaction

Answer: 3.156 * 10^7

Explanation: I do not really understand your question. You answered it yourself!

Scientific notation shortens large numbers. The number right after the decimal point can only be between 1 and 9, which you did correctly. When converting to scientific notation, the exponent of ten is based on how many places you moved the decimal and the direction you moved it (left, positive; right, negative). In this case, the exponent of ten is a positive seven.

You did everything correctly :) Good job!

Answer:

escribe esa pregunta en una región de Latinoamérica

\(\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the Concept of the Chemistry.

The reaction that Is opposite of the decomposition is

==> Synthesis Reaction.

==> Catalyst always Speeds up any reaction, so that it quickly reaches to it's Equilibrium point and gets stabilize.

Burning coal cause acid precipitation to enter the air.

Acid rain is defined as all kinds of rain with a pH below 5.6. Rain is naturally acidic (pH slightly below 6) because carbon dioxide (CO2) in the air which dissolves with rainwater has the form a weak acid . This type of acid in rain is very useful because it helps dissolve the minerals in the soil which are needed by plants and animals.

Acid rain is caused by Sulfur which is an impurity in fossil fuels as well as nitrogen in the air which reacts with oxygen to form sulfur dioxide and nitrogen oxides. These substances diffuse into the atmosphere and react with water to form sulfuric acid and nitric acid which are easily soluble so that they fall with the rainwater. This acidic rainwater will increase the acidity of the soil and surface water which will prove harmful to fish and plant life. Efforts to overcome this are currently being intensively implemented.

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The mass of eicosadienoic acid, in grams, in thisorchid sample is 0.0084 grams.

In this particular question, we are asked for the mass of eicosadienoic acid, in grams, in a 12-gram sample of an orchid plant based on an estimate that 0.07% (percent by mass), of the sample consists of this fatty acid. To solve this problem, we can use a simple proportion:

0.07/100 = x/12

where x is the mass of eicosadienoic acid, in grams, in the 12-gram sample. To solve for x, we can cross-multiply and simplify:

0.07 × 12 = 100 × x

0.84 = 100x

x = 0.0084 grams

Therefore, the mass of eicosadienoic acid in the 12-gram sample of the orchid plant is 0.0084 grams.

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A hydrated sample of sodium acetate is found to have a molar mass of 263. 183g. water molecules are associated with each sodium acetate 1000mL/L of sodium acetate make up the bulk.

sodium volume in mL, molar mass, and molarity = \s1000 \s500 \s​ \s ×0.375×82.0245=15.38. g.The number of moles per litre is the molarity of a solution. In 500 ml, you have 0.75 moles. As a result, you have 0.75 moles per liter, or 1.5 moles per liter, or one pound. A hydrated sample of sodium acetate is found to have a molar mass of 263. 183g. water molecules are associated with each sodium acetate 1000mL/L of sodium acetate make up the bulk.The mass percentage of water in a 20% solution with 100g of water is equal to 100 - 20%, or 80%. <br> 100 grams of the solution, or 80%, 100% of the answer is equal to "(100)/(80)" gram. 20% of the answer is equal to (100/(80) xx 20) = 25 grams. Therefore, 25 grams of sodium sulphate are required to make a 20% (w/w) solution in 100 g of water.

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