Functions table please help

The compound inequality which can be used to represent times that he could go to the doctor is 8 am ≤ x ≤ 6 pm

Time the doctor open = 8:00 a.m. and 6:00 p.m

Time Ale can visit the doctor = x

8 am ≤ x ≤ 6 pm

This means Ale can visit the doctor on or before 8 am and lest than equal to 6 pm

Therefore, the compound inequality which can be used to represent times that he could go to the doctor is 8 am ≤ x ≤ 6 pm

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Answer:

3x and 2x can be combined bc it has ex at the end.

1 and 2x cannot be combined bc 1 doesn't have an x.

1 and -5 can be combined

Answer:

Shorter leg is 7

Bigger leg is 7√3 = 12.1 (rounded to the nearest tenth)

The value of m is -26.6. The solution has been obtained by using arithmetic operations.

What are arithmetic operations?

In mathematics, "arithmetic operations" refer to the four basic operations that can be used to express any real number. Division, multiplication, addition, and subtraction are the four operations which yields quotient, product, sum and difference respectively.

We are given -5(m + 30) = -17

On solving the equation using the arithmetic operations, we get

⇒-5(m + 30) = -17

⇒-5m - 150 = -17           (On multiplying the bracket by -5)

⇒-5m = 133                   (On adding 150 on both the sides)

⇒m = -26.6                   (On dividing both the sides by -5)

Hence, we obtained the value of m as -26.6.

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Answer:

1/3

Step-by-step explanation:

10 to 10:30

10:30 to 11

11 to 11:30

3 periods of time

10 to 11 is 2/3 periods

3/3 - 2/3 = 1/3

9514 1404 393

Answer:

  8. no, no, yes, yes

  9. see attached

Step-by-step explanation:

8. Slope-intercept form is ...

  y = mx + b . . . . . . . where m is the slope, and b is the y-intercept

You will notice that y is by itself on the left side of the equation, and that there are two terms: an x-term and a constant.

The first two equations are NOT in slope-intercept form.

The last two equations ARE in slope-intercept form.

__

9. The values of 3x-1 and y are the same. They are shown in the attached table.

The corresponding (x, y) pairs are (-2, -7), (-1, -4), (0, -1), (1, 2), (2, 5). In each pair, the x-value (first number) comes from the x-column of the table. The y-value (second number) comes from the f(x)- or y-column of the table.

Answer:

152.60 square units

Step-by-step explanation:

Area of the sector is expressed as;

A = theta/360 * Area of the circle

A =54/360 * 3.14*18²

A = 54/360 * 1,017.36

A = 54,937.44/360

A = 152.604

Hence the area of the sector to the nearest hundredth is 152.60 square units

Answer:

152.68

Step-by-step explanation:

Fοr distributions with a nοrmal shape or symmetry, the mean and standard deviation are emplοyed; for asymmetrical distributiοns, the median and interquartile range are used.

Because it is unaffected by οutliers, the IQR is frequently regarded as a mοre accurate measure of spread than the range. The variance and standard deviatiοn are indicators of hοw widely the data are dispersed from the mean. Each οbserved data value's prοximity to the mean is summarised.

The strοngest indicator of variability in data sets with οutliers or skewed distributions is the interquartile range. It's unlikely to be impacted by οutliers because it's based οn numbers that come frοm the centre half of the distribution.

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(1.1) A matrix equation b = [√11+e, 0, √2, √2]²T 2) a)  Gaussian elimination without pivoting does not provide unique solution. b) Gaussian elimination with scaled partial pivoting cannot provide a unique solution.(c) Basic LU decomposition is x = [0.788, -3.12, 0.167, 4.55]²T.

The given linear system can be written in matrix form as:

A × x = b

where A is the coefficient matrix, x is the column vector of variables (x1, x2, x3, x4), and b is the column vector on the right-hand side.

The coefficient matrix A is:

A = [[0, -e, √2, -√3],

[π², e, -e², 3/7],

[√5, -√6, 1, -√2],

[π³, e², -√7, -1/9]]

The variable vector x is:

x = [x1, x2, x3, x4]²T

The right-hand side vector b is:

b = [√11+e, 0, √2, √2]²T

(1.2) Solving the system using:

(a) Gaussian elimination without pivoting:

To solve the system using Gaussian elimination without pivoting, we perform row operations on the augmented matrix [A | b] until it is in row-echelon form. Then back-substitute to find the values of x.

The augmented matrix [A | b] is:

[0, -e, √2, -√3 | √11+e]

[π², e, -e², 3/7 | 0]

[√5, -√6, 1, -√2 | √2]

[π³, e², -√7, -1/9 | √2]

Performing row operations, the row-echelon form:

[π², e, -e², 3/7 | 0]

[0, -e, √2, -√3 | √11+e]

[0, 0, 0, 0 | 0]

[0, 0, 0, 0 | 0]

From the row-echelon form, that the system is underdetermined, with two free variables. Therefore, Gaussian elimination without pivoting cannot provide a unique solution.

(b) Gaussian elimination with scaled partial pivoting:

To solve the system using Gaussian elimination with scaled partial pivoting, row operations with partial pivoting until the augmented matrix [A | b] is in row-echelon form. Then back-substitute to find the values of x.

The augmented matrix [A | b] is:

[0, -e, √2, -√3 | √11+e]

[π², e, -e², 3/7 | 0]

[√5, -√6, 1, -√2 | √2]

[π³, e², -√7, -1/9 | √2]

Performing row operations with scaled partial pivoting, the row-echelon form:

[π³, e², -√7, -1/9 | √2]

[0, -e, √2, -√3 | √11+e]

[0, 0, -0.03, -1.02 | 0.027]

[0, 0, 0, 0 | 0]

From the row-echelon form that the system is underdetermined, with two free variables. Therefore, Gaussian elimination with scaled partial pivoting cannot provide a unique solution.

(c) Basic LU decomposition:

The system using LU decomposition, factorize the coefficient matrix A into the product of lower triangular matrix L and upper triangular matrix U. Then we solve the equations L × y = b for y using forward substitution, and U × x = y for x using back-substitution.

The coefficient matrix A is:

A = [[0, -e, √2, -√3],

[π², e, -e², 3/7],

[√5, -√6, 1, -√2],

[π³, e², -√7, -1/9]]

Performing LU decomposition,

L = [[1, 0, 0, 0],

[π², 1, 0, 0],

[√5, 0.3128, 1, 0],

[π³, 4.3626, 2.4179, 1]]

U = [[0, -e, √2, -√3],

[0, e + π², -e² + e × π², 3/7 - e × √2],

[0, 0, 0.9693, -0.3651],

[0, 0, 0, -2.2377]]

Solving L × y = b for y using forward substitution:

[1, 0, 0, 0] ×y = √11+e

[π^2, 1, 0, 0] × y = 0

[√5, 0.3128, 1, 0] × y = √2

[π^3, 4.3626, 2.4179, 1] × y = √2

Solving the above equations,

y = [0.788, -3.12, 0.167, 4.55]²T

Now, solving U × x = y for x using back-substitution:

[0, -e, √2, -√3] × x = 0.788

[0, e + π², -e² + e × π², 3/7 - e ×√2]× x = -3.12

[0, 0, 0.9693, -0.3651] ×x = 0.167

[0, 0, 0, -2.2377] ×x = 4.55

Solving the above equations,

x = [0.788, -3.12, 0.167, 4.55]²T

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What are the given conditions?

Answer:

A, B

Step-by-step explanation:

1. A

because the intersection of the line is the solution so no solution means they do not intersect

2. B

because the points on the line that is on top of another line are all solutions and lines have infinite number of points

a) For chi-squared distribution with v=3 degrees of freedom, the statistic that can be constructed using Xi's is:

X2 = Σ i=1 3 (Xi − i)2 / 3.

X2 has chi-squared distribution with 3 degrees of freedom.

b) For t-distribution with v=2 degrees of freedom, the statistic that can be constructed using Xi's is:

T = (X1 − 1) / [(X2/2)0.5].

T has t-distribution with 2 degrees of freedom.

c) For F-distribution with v1=1 and v=2 degrees of freedom, the statistic that can be constructed using Xi's is:

F = [(X1 − 1)/1] / [(Σi=2 to 3 Xi2) / 2].

F has F-distribution with 1 and 2 degrees of freedom.

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Maclaurin series of `f(x)` is given by:f(x) = `f(0)` + `f'(0)x` + `(f''(0)/2!) x²` + `(f'''(0)/3!) x³` + `(f⁴(0)/4!) x⁴` + `(f⁵(0)/5!) x⁵` + `(f⁶(0)/6!) x⁶` = `0 + 0x + 0x² + 0x³ + 0x⁴ + 0x⁵ + (7200/6!)x⁶` = `10x⁶`

Answer: `10x⁶`.

The given function is `f(x) = x⁶ sin(10x⁵)`. We need to find the Taylor series of `f` centered at `0` (Maclaurin series of `f`).

Formula used: The Maclaurin series for `f(x)` is given by `f(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3 + ...... + (f^n(0)/n!)x^n`.

Here, `f(0) = 0` because `sin(0) = 0`.

Differentiating `f(x)` and its derivatives at `x = 0`:`f(x) = x⁶ sin(10x⁵)`

First derivative: `f'(x) = 6x⁵ sin(10x⁵) + 50x¹⁰ cos(10x⁵)`

Differentiate `f'(x)`

Second derivative: `f''(x) = 30x⁴ sin(10x⁵) + 200x⁹ cos(10x⁵) - 250x¹⁰ sin(10x⁵)`

Differentiate `f''(x)`

Third derivative: `f'''(x) = 120x³ sin(10x⁵) + 1800x⁸ cos(10x⁵) - 2500x⁹ sin(10x⁵) - 5000x²⁰ cos(10x⁵)`

Differentiate `f'''(x)`

Fourth derivative: `f⁴(x) = 360x² sin(10x⁵) + 7200x⁷ cos(10x⁵) - 22500x⁸ sin(10x⁵) - 100000x¹⁹ cos(10x⁵) + 100000x²⁰ sin(10x⁵)`

Differentiate `f⁴(x)`

Fifth derivative: `f⁵(x) = 720x sin(10x⁵) + 36000x⁶ cos(10x⁵) - 112500x⁷ sin(10x⁵) - 1900000x¹⁸ cos(10x⁵) + 2000000x¹⁹ sin(10x⁵)`

Differentiate `f⁵(x)`

Sixth derivative: `f⁶(x) = 7200 cos(10x⁵) - 562500x⁶ cos(10x⁵) + 13300000x¹⁷ sin(10x⁵)`

Evaluate at `x = 0`:

The derivatives of `f(x)` evaluated at `x = 0` are:f(0) = 0f'(0) = 0f''(0) = 0f'''(0) = 0f⁴(0) = 0f⁵(0) = 0f⁶(0) = 7200

Maclaurin series of `f(x)` is given by:f(x) = `f(0)` + `f'(0)x` + `(f''(0)/2!) x²` + `(f'''(0)/3!) x³` + `(f⁴(0)/4!) x⁴` + `(f⁵(0)/5!) x⁵` + `(f⁶(0)/6!) x⁶` = `0 + 0x + 0x² + 0x³ + 0x⁴ + 0x⁵ + (7200/6!)x⁶` = `10x⁶`

Answer: `10x⁶`.

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the percentage of information remembered at the moment it is first learned is 100%.

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

Functions were originally the idealization of how a varying quantity depends on another quantity. For example, the position of a planet is a function of time. Historically, the concept was elaborated with the infinitesimal calculus at the end of the 17th century, and, until the 19th century, the functions that were considered were differentiable (that is, they had a high degree of regularity). The concept of a function was formalized at the end of the 19th century in terms of set theory, and this greatly enlarged the domains of application of the concept.

Your question is incomplete but most probably your full question was:

In college, we study large volumes of information - information that, unfortunately, we do not often retain for very long. The function f(x) = 80e-0.5x + 20

describes the percentage of Q. information, p, that a particular person remembers x weeks after learning the information. Substitute 0 for x and find the percentage of information remembered at the moment it is first learned.

a 100%

b 95%

c 90%

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Adding and subtracting polynomials worksheets assist pupils in becoming acquainted with the idea of polynomial addition and subtraction.

Adding and subtracting polynomial worksheets provide pupils with a platform to access a variety of well-structured problems. Because these worksheets progress in complexity, they are simple to use and allow pupils to reinforce their concepts.

Children must study in accordance with their learning curve, and these worksheets are designed to allow young brains to work at their own speed. These math worksheets also address the logical and reasoning aspects of arithmetic, assisting pupils in real-life situations.

Students may have a better grasp and explore these worksheets more quickly with the aid of pictures. These worksheets' step-by-step approach helps pupils better comprehend ideas and reinforce their comprehension.

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We need to know about z-score to solve the problem. The z-score of the soda is 0.6

A z-score tells you how many standard deviations away an individual data falls from the mean. We can calculate z-score from the standard deviation and mean of the data. In this question we know that the cost of a soda is $1.15 and the mean is $1.00 and the standard deviation is $0.25.We need to calculate the z-score of the soda with the given information.

z-score=x-μ/σ=1.15-1.00/0.25=0.15/0.25=0.6

Therefore the z-score of the soda is 0.6

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Answer:

Cafe A - 54

Cafe B - 56

Step-by-step explanation:

Answer:

is the line or line segment that divides the angle into two equal parts

Step-by-step explanation:

the main answer is that the mean value of the activity time is 21.67. This is calculated using the formula (optimistic + 4 * most likely + pessimistic) / 6.

To find the mean value of the activity time, we can use the three estimates provided: optimistic, most likely, and pessimistic time.

1. The optimistic time is the shortest possible time for completing the activity, which is 11 units.
2. The most likely time is the time that is most likely to be taken to complete the activity, which is 21 units.
3. The pessimistic time is the longest possible time for completing the activity, which is 35 units.

To calculate the mean value, we can use the following formula:
Mean value = (optimistic + 4 * most likely + pessimistic) / 6

Substituting the given values, we get:
Mean value = (11 + 4 * 21 + 35) / 6

Calculating the numerator first:
11 + 4 * 21 + 35 = 11 + 84 + 35 = 130

Now, we can calculate the mean value:
Mean value = 130 / 6

Dividing 130 by 6, we get:
Mean value = 21.67 (rounded to two decimal places)

Therefore, the mean value of the activity time is 21.67.

the main answer is that the mean value of the activity time is 21.67. This is calculated using the formula (optimistic + 4 * most likely + pessimistic) / 6.

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Answer:

1. 5/2 2. -1/4 3. 0 4. 2 and 5. -1

Step-by-step explanation:

The photo above show you how I solved each problem out.

Hope this helped

Answer:

$0.60/each

Step-by-step explanation:

$5.40/9=0.60  Total price *($5.60) divided by 9 (PEPPERS) = $0.60

          c= 0.6p

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

Cost of 9 red peppers = $5.40

Cost of 1 red pepper = 5.40 /9

                                = 0.6

Now, the equation to represent cost in dollars c to the number of red peppers p,

c= 0.6p

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Answer:

The cub was 1 ft long a year ago.

Step-by-step explanation:

The tiger cub was 1 foot long a year ago.

One year ago, if the tiger cub was 1 foot:

1 ft = Cub

1 + 5 = 6 = Mother

Now:

1 + 2 = 3 = Cub

6 = Mother

The mother is now only twice as big as the cub, meaning that this solution is correct.

Solution using algebra:

One year ago:

x = Cub

x + 5 = Mother

Now:

x + 2 = Cub

x + 5 = Mother

We know the mother is now only twice as big as her cub.

2(x + 2) = x + 5

2x + 4 = x + 5

2x - x = 5 - 4

x = 1

Hope this helps!

Answer:

One year ago, the cub was 1 ft

Step-by-step explanation:

One year ago:

The height of Mother tiger = x feet

Height of cub = x - 5

Now,

Height of cub = (x - 5) + 2 = x  -5 + 2 = x - 3

Height of mother  = Twice the cub size

                            x = 2*(x - 3)

x = 2x - 6

x + 6 = 2x

   6 = 2x - x

  6 = x

The height of Mother tiger =  6 feet

Height of cub = 6 - 5  = 1 feet

Answer:

Inga can use the following steps to solve the quadratic equation 2x^2 + 12x - 3 = 0:

Therefore, the steps that Inga could use to solve the quadratic equation are:

2(x^2 + 6x + 9) = -3 + 2(9) (Option 1)

2(x^2 + 6x) = 3 (Option 2)

x + 3 = ±√(27/2) (Option 3)

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Research has shown that competent communicators achieve effectiveness by adjusting their behaviors to the person and situation (option e).

Effective communication involves being adaptable and responsive to the specific context, individual preferences, and the needs of the situation.

Competent communicators recognize that different people have different communication styles, preferences, and expectations. They understand the importance of tailoring their communication approach to effectively connect and engage with others.

This may involve using appropriate language, tone, non-verbal cues, and listening actively to understand the needs and perspectives of others.

By adapting their behaviors, competent communicators can build rapport, foster understanding, and promote effective communication exchanges. They are mindful of the social and cultural dynamics at play, and they strive to communicate in a way that is respectful, inclusive, and conducive to achieving mutual goals.

In summary, competent communicators understand that effective communication is not a one-size-fits-all approach. They adjust their behaviors to the person and situation, demonstrating flexibility and adaptability in order to enhance communication effectiveness.

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Competent communicators achieve effectiveness mostly by adjusting their behaviors to suit the person they are communicating with and the situation they find themselves in. While other factors, like having a broad vocabulary or giving feedback, play a part in effective communication, the former is considered the most crucial.

Research suggests that competent communicators achieve effectiveness mostly through adjusting their behaviors depending on the person they are communicating with and the situation they are in. This is option e. of your question. Communicating effectively involves behaviors like active listening, understanding the other person's point of view, being able to express thoughts and ideas clearly, and being polite and respectful. While a broad vocabulary (option b.) can be useful, it is not as crucial as adapting your behavior to fit the situation. Moreover, giving feedback (option d.) is a part of effective communication but not the sole defining factor. Apologizing when offending others (option c.) is also important but it doesn't necessarily make one a competent communicator. Using the same type of behavior in various situations (option a.) might not always work, as different situations and individuals require different communication styles.

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Answer:

Y= \(\frac{-2x+6}{3}\)

Step-by-step explanation:

slope intercept formula is

Y=mx+b

Now we want the y isolate so in this case we just subtract 2x on both sides

3Y=6-2x

or in more better terms

3y=-2x+6

Now we want the 3 isolated so we divide 3 on both sides

and you’ll get

\(\frac{-2x+6}{3}\)

The equilibrium price is $0 and the equilibrium quantity is 5 units.

To find the equilibrium price and quantity, we need to set the quantity demanded equal to the quantity supplied and solve for the equilibrium values.

Setting Q_d = Q_s, we can equate the equations for demand and supply:

-2Q - 2Q_d = -5 + 3Q_s

Since we know that Q_d = Q_s, we can substitute Q_s for Q_d:

-2Q - 2Q_s = -5 + 3Q_s

Now, let's solve for Q_s:

-2Q - 2Q_s = -5 + 3Q_s

Combine like terms:

-2Q - 2Q_s = 3Q_s - 5

Add 2Q_s to both sides:

-2Q = 5Q_s - 5

Add 2Q to both sides:

5Q_s - 2Q = 5

Factor out Q_s:

Q_s(5 - 2) = 5

Q_s(3) = 5

Q_s = 5/3

Now that we have the value for Q_s, we can substitute it back into either the demand or supply equation to find the equilibrium price. Let's use the supply equation:

P = -5 + 3Q_s

P = -5 + 3(5/3)

P = -5 + 5

P = 0

Therefore, the equilibrium price is $0 and the equilibrium quantity is 5 units.

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Answer:

A) x = 7

Step-by-step explanation:

7x + 1 + 7x + 6 + (180 - 15x) = 180

combine like terms:

-x + 187 = 180

subtract 187 form both side of the equation:

-x = -7

x = 7

The probability that Jevonte will hit his next free throw is "likely" or "high".

Since Jevonte has made 7 out of 8 of his free throws so far, he has a success rate of 87.5%, which is quite high. Therefore, it is reasonable to expect that he will continue to make his free throws at a similar rate, making it likely that he will hit his next free throw.

what is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain. A probability of 0.5 (or 50%) means the event is just as likely to occur as it is not to occur. Probability is used extensively in fields such as mathematics, statistics, physics, engineering, economics, and many other areas to model and analyze uncertain events or situations.

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