Answer:
6u2
Step-by-step explanation:
6u2 is the units inside of the rectangle
Can someone help me solve this.
\(\huge\underline{Answer -}\)
\( \huge{\implies \: \frac{ - 2 \frac{1}{4} }{ - \frac{ 2}{3} }} \\ \\ \\ \\ \huge{\implies \: \frac{ \frac{ - 9}{4} }{ \frac{ - 2}{3} } } \\ \\ \\ \\ \huge{\implies \: - \frac{9}{4} \div (\frac{ - 2}{3} )}\)
therefore , option ( 2 ) is correct.
hope helpful -,-
is the difference of square root of 18 and 3 a rational number
Erin buys 2 packs of potatoes costing £2 each, 3 packs of carrots for £3 per pack, and 3 turnips costing 60p each.
If she pays with a £20 note, how much change would she get in pounds, £
Answer:
£5.20
Step-by-step explanation:
The change is the difference between the amount tendered and the amount owed. The total amount owed is the sum of the costs for each of the items purchased.
change = £20 - 2(£2) - 3(£3) -3(£0.60) = £20 -14.80 = £5.20
Erin gets £5.20 in change.
If f(x)=−2(x+7), then what is f(−10)? 66 3434 −34negative 34 −6negative 6
Suppose 1 and 2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 7, x = 114.9, s1 = 5.07,
n = 7, y = 129.7, and s2 = 5.34. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system
The 95% confidence interval for the difference between true average stopping distances for cars equipped with system 1 and system 2 is approximately (-20.263, -9.337).
To calculate the 95% confidence interval for the difference between the true average stopping distances for cars equipped with system 1 and system 2, we can use the formula:
CI = (x1 - x2) ± t * sqrt((s1^2 / n1) + (s2^2 / n2))
Where:
x1 and x2 are the sample means of stopping distances for system 1 and system 2, respectively.
s1 and s2 are the sample standard deviations of stopping distances for system 1 and system 2, respectively.
n1 and n2 are the sample sizes for system 1 and system 2, respectively.
t is the critical value for the desired confidence level.
For a 95% confidence level and (n1 + n2 - 2) degrees of freedom, the critical value can be obtained from the t-distribution table.
Given:
x1 = 114.9
s1 = 5.07
n1 = 7
x2 = 129.7
s2 = 5.34
n2 = 7
The degrees of freedom would be (n1 + n2 - 2) = (7 + 7 - 2) = 12.
Consulting the t-distribution table for a 95% confidence level and 12 degrees of freedom, the critical value is approximately 2.179.
df | 0.10 | 0.05 | 0.025 | 0.01 | 0.005
-------------------------------------------------------------
1 | 6.314 | 12.706 | 31.821 | 63.657 | 127.321
2 | 2.920 | 4.303 | 6.965 | 9.925 | 14.089
3 | 2.353 | 3.182 | 4.541 | 5.841 | 7.453
4 | 2.132 | 2.776 | 3.747 | 4.604 | 5.598
5 | 2.015 | 2.571 | 3.365 | 4.032 | 4.773
6 | 1.943 | 2.447 | 3.143 | 3.707 | 4.317
7 | 1.895 | 2.365 | 2.998 | 3.499 | 4.029
8 | 1.860 | 2.306 | 2.896 | 3.355 | 3.833
9 | 1.833 | 2.262 | 2.821 | 3.250 | 3.690
10 | 1.812 | 2.228 | 2.764 | 3.169 | 3.581
Plugging in the values into the formula, we have:
CI = (114.9 - 129.7) ± 2.179 * sqrt((5.07^2 / 7) + (5.34^2 / 7))
Calculating the values inside the square root:
sqrt((5.07^2 / 7) + (5.34^2 / 7)) ≈ sqrt(2.907 + 3.374) ≈ sqrt(6.281) ≈ 2.506
Plugging in the calculated value:
CI = (-14.8) ± 2.179 * 2.506
Calculating the range of the confidence interval:
CI = (-14.8) ± 5.463
Therefore, the 95% confidence interval for the difference between true average stopping distances for cars equipped with system 1 and system 2 is approximately (-20.263, -9.337).
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Which expressions can be used to find m∠BAC? Check all that apply. Cos−1 cos−1 sin−1 sin−1 tan−1 tan−1
The expressions that can be used to find the measure of angle BAC in triangle ABC are \(Cos^{-1} (\frac{6.9}{12} )\) , \(Sin^{-1} (\frac{9.8}{12} )\) and \(Tan^{-1} (\frac{9.8}{6.9} )\) .
The trigonometric ratios involving the angle BAC (∠A) can be written as follows :
In triangle ABC ,
(i) Sine of A = \(\frac{BC}{AB}\) ,
Substituting the value of BC and AB ,
we get ;
\(SinA = \frac{9.8}{12}\) ;
⇒ \(\angle A = Sin^{-1} (\frac{9.8}{12} )\) ;
(ii) Cos of A = \(\frac{AC}{AB}\)
Substituting the value of AC and AB ,
we get ;
\(CosA = \frac{6.9}{12}\)
⇒ \(\angle A = Cos^{-1} (\frac{6.9}{12} )\) ;
(iii) Tan of A = \(\frac{BC}{AC}\)
Substituting the value of BC and AC ,
we get ;
\(TanA = \frac{9.8}{6.9}\)
⇒ \(\angle A = Tan^{-1} (\frac{9.8}{6.9} )\) ;
Therefore , the only options that satisfy the triangle ABC are \(Cos^{-1} (\frac{6.9}{12} )\) , \(Sin^{-1} (\frac{9.8}{12} )\) and \(Tan^{-1} (\frac{9.8}{6.9} )\) .
The given question is incomplete , the complete question is
Which expressions can be used to find m∠BAC in the triangle ABC ? Check all that apply.
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Mr. Bates and Mr. Z want to refinish the community center gym floor. The rectangular floor is 15.2 m wide and 25.6 long. If each gallon of polyurethane covers about 180 square meters, how many gallons should Mr. Bates and Mr. Z buy? *
Answer:
3 gallons
Step-by-step explanation:
area = 15.2 x 25.6 = 389.12 m²
389.12/180 = 2.16
Consider angle θ in Quadrant II, where cosθ=−12/13. What is the value of sinθ?
Answer:
The value of sin theta is 5/13
Step-by-step explanation:
In the second quadrant, sin is positive and cos is negative
Cos theta = -12/13 = adjacent/hypotenuse
Sin theta = opposite/hypotenuse
opposite = sqrt(hyp² - adj²) = sqrt (13² - 12²) = sqrt (169 - 144) = sqrt (25) = 5
Sin theta = opposite/hypotenuse = 5/13
graph the line that passes through the points (6,4) and (8,8) and determine the equation of the line
The equation of line is written in slope-intercept form as y = 2x - 8
Equation of LineTo find the equation of line with the given points, we have to find the slope and y-intercepts.
The formula of slope is given as
m = y₂ - y₁ / x₂ - x₁
Substituting the values into the equation;
m = 8 - 4 / 8 - 6
m = 4 / 2
m = 2
The slope is 2
The equation of line is written in slope-intercept form which is y = mx + c
Taking any of the points and using it to solve for c
4 = 2(6) + c
4 = 12 + c
c = -8
The equation of line is y = 2x - 8
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Which equation is represented by the graph below?
Y=in x
Y=in x+1
Y= e^x
Y= e^x+1
Answer:
The 4 one good luck in your homework bro I hope that your teacher will be surprised with you home work
Step-by-step explanation:
You will be the best in the class
F ∝ a If F = 48 when a = 3 find, a when F = 32
Answer:
2
Step-by-step explanation:
f = a
48 = 3
32 = x
48x= 98
x=2
Mark me as brainiest if i helped youUse Descartes' Rule of Signs to determine how many positive and how many negative real zeros the polynomial can have. Then determine the possible total number of real zeros. (Enter your answers as comma-separated lists.)
P(x) = x^3 − x^2 − x − 5
number of positive zeros possible number of negative zeros possible number of real zeros possible
According to Descartes' Rule of Signs, there is 1 positive real zero and 2 or 0 negative real zeroes of the polynomial.
Descarte's Rule of Signs determines the number of real zeros in polynomial functions.
This indicates that -
The number of positive real zeros in the polynomial function f(x) is less than or equal to an even number depending on the sign change of the coefficients.
The number of negative real zeros in f(x) is an even number equal to or less than the number of sign changes of the coefficients of f(-x) terms.
Here, the polynomial function is given as -
\(P(x)=x^{3}-x^{2} -x-5\) ----- (1)
We have to find out the number of positive and negative real zeros that the given polynomial can have.
The given polynomial already has its variables in the descending powers. So, we can easily determine the number of sign changes in the coefficients of P(x).
So, the coefficients of the variables in P(x) are -
1, -1, -1, -5
From above, we see that -
There is a sign change in the first and second variable coefficients
There is no sign change in the second and third variable coefficients
There is no sign change in the third and fourth variable coefficients
According to Descartes' Rule of Signs, there can be exactly three positive real zeros or less than three but an odd number of zeros.
So, we can determine that the number of positive real zeroes of the given polynomial can be 1.
To find out the negative real zeroes of the given polynomial, we have to find out P(-x) and determine the sign changes in the variable coefficients of P(-x).
From equation (1), we can write P(-x) as -
\(P(x)=x^{3}-x^{2} -x-5\\= > P(-x)=(-x)^{3}-(-x)^{2} -(-x)-5\\= > P(-x)=-x^{3}-x^{2} +x-5\)----- (2)
So, the coefficients of the variables in P(-x) are -
-1, -1, +1, -5
From above, we see that -
There is no sign change in the first and second variable coefficients
There is a sign change in the second and third variable coefficients
There is a sign change in the third and fourth variable coefficients
According to Descartes' Rule of Signs, since there are two sign changes of the coefficient variables, there can be two negative real zeros or less than two but an even number of zeros.
So, we can determine that the number of negative real zeroes of the given polynomial can be 2 or 0.
Thus, according to Descartes' Rule of Signs, there is 1 positive real zero and 2 or 0 negative real zeroes of the polynomial.
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Peter works at a camera store. He is paid an hourly rate, plus 2 points
16% commission on everything he sells. One week, he was paid $515 for
working 20 hours and selling $1,500 worth of camera equipment. What is
his hourly rate? *
A) $12.00 per hour
B) $13.75 per hour
C) $21.63 per hour
D) $25.75 per hour
PLSS HELP
Answer:
fdd
yfddd
Step-by-step explanation:
dded fdd fdd fdd fddc rttyj hreef ggg
Ninth grade math help me PLEASEEEE PLEASE
Answer:
I believe the answer is D.
Step-by-step explanation:
Someone in Highschool help?
The graph f(x)=(x+1)2-7is translated 3 units right, resulting in the graph g(x). Write an equation that represents the new function, g(x)
i need help on 12 times x."
Answer: 12x
Step-by-step explanation:
12 times x = 12x
Hope it helped u,
pls mark as the brainliest
^_^
solve for x in [0, π]: 2 cos(x) > sec(x)
The value for x is 7π/6 and 11π/6.
sin2xsecx+2cosx=0
(2sinxcosx)(1/cosx)+2cosx=0
sinxcosx/cosx+2cosx=0
So,
2sinx+2cosx=0
2(sinx+cosx)=0
(2(sinx+cosx))²=0
4(sin²x+cos²x+2sinxcosx)=0
hence,
(sin²x+cos²x+2sinxcosx)/4=0/4
sin2x+cos2x+2sinxcosx=0
1+sin2x=0
sinx=−1/2
=7π/6 and 11π/6
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use the coordinates of the labeled point to find a point-slope equation of the line.
Answer:
the answer is D
Step-by-step explanation:
A rental car company charges $30.42 per day to rent a car and $0.06 for every mile driven. Ariana wants to rent a car, knowing that:
She plans to drive 450 miles.
She has at most $200 to spend.
What is the maximum number of days that Ariana can rent the car while staying within her budget?
Considering the definition of an inequality, the maximum number of days that Ariana can rent the car while staying within her budget is 5 days.
Definition of inequalityAn inequality is the existing inequality between two algebraic expressions, connected through the signs:
greater than >.less than <.less than or equal to ≤.greater than or equal to ≥.An inequality contains one or more unknown values.
Solving an inequality consists of finding all the values of the unknown for which the inequality relation holds.
Maximum number of daysIn this case, you know that:
A rental car company charges $30.42 per day to rent a car and $0.06 for every mile driven. Ariana plans to drive 450 miles.Ariana has at most $200 to spend.Being "x" the number of days that Ariana can rent the car, the inequality in this case is
30.42x + 0.06×450 ≤200
Solving:
30.42x + 27 ≤200
30.42x ≤200 - 27
30.42x ≤173
x ≤173÷ 30.42
x≤ 5.687
Finally, the maximum number of days is 5 days.
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.Let
f(x) =
x^2 + 4 if x < 1
(x − 2)^2 if x ≥ 1
.(a) Find the following limits. (If an answer does not exist, enter DNE.)
lim x → 1− f(x) =
lim x → 1+ f(x) = ___. b) does lim x → 1 f(x) exist? O yes O no
The left-hand limit is 5, and the right-hand limit is 1. The limit of f(x) as x approaches 1 does not exist.
(a) How to find left-hand limit?To find the limits, let's evaluate the left-hand limit and the right-hand limit separately.
Left-hand limit:lim x → 1- f(x) = lim x → 1- (x²+ 4)Since x approaches 1 from the left side (values less than 1), we can use the expression f(x) = x² + 4.
Plugging in x = 1 into the expression gives us:
lim x → 1- f(x) = lim x → 1- (1² + 4)
= lim x → 1- (1 + 4)
= lim x → 1- (5)
= 5
(b) How to find Right-hand limit? Right-hand limit:lim x → 1+ f(x) = lim x → 1+ ((x - 2)²)
Since x approaches 1 from the right side (values greater than or equal to 1), we can use the expression f(x) = (x - 2)².
Plugging in x = 1 into the expression gives us:
lim x → 1+ f(x) = lim x → 1+ ((1 - 2)²)
= lim x → 1+ ((-1)²)
= lim x → 1+ (1)
= 1
(c) How does limit exist?To determine if the limit lim x → 1 f(x) exists, we need to compare the left-hand and right-hand limits. If they are equal, then the limit exists. Otherwise, the limit does not exist.
In this case, lim x → 1- f(x) = 5 and lim x → 1+ f(x) = 1. Since these limits are not equal, the limit lim x → 1 f(x) does not exist.
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Use your knowledge of transformations to find the matching graph.
The correct answers are on this screenshot, thank me later.
The matching graph to the transformed function, obtained using the rules for transformation of function are;
f(x) = 2·√(x + 1) ; D
f(x) = (1/2)·(√x) - 1; B
f(x) = -√(x + 2); A
f(x) = -2·√x; C
What are rules for the transformation of functions?The rules for the transformation of functions can be described as follows;
-a·f(-b·(x ± c)) ± d
a > 1, represents a horizontal stretch
0 < a < 1, represents a vertical compression
-a represents a reflection across the x-axis
b > 1, represents an horizontal compression
0 < b < 1, represents a horizontal stretch
-b represents a reflection across the y-axis
+d Shifts the function up d units
-d Shifts the function down d unts
x + h shifts the function to the left
x - h shifts the function to the right, h units
The function f(x) = √x begins at the point (0, 0), and increases as x increase, Therefore, we get;
The function f(x) = 2·√(x + 1), consists of a graph that is shifted one unit to the left and horizontally stretched by 2, which indicates that the correct graph is the option D
The function f(x) = (1/2)·√x - 1 consists of a vertical compression of a factor of (1/2) and is shifted 1 unit downwards, which corresponds to the option B
The function f(x) = -√(x + 2), can be obtained by reflecting the parent function across the x-axis, and shifting the parent function 2 units to the left, which corresponds to the option A
The function f(x) = -2·√(x), consists of reflecting the parent function across the x-axis and horizontal stretch by a factor of 2 of the parent function, which corresponds to the option C
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Under what circumstances is a score that is located 5 points above the mean a central value, relatively close to the mean?
a. When the population standard deviation is much less than 5
b. When the population mean is much less than 5
c. When the population mean is much greater than 5
d. When the population standard deviation is much greater than 5
The circumstance that the score is located 5 points above the mean a central value, relatively close to the mean is when the population standard deviation is much greater than 5.
What is the standard deviation?Standard Deviation is a measure which shows how much variation (such as spread, dispersion, spread,) from the mean exists. The standard deviation indicates a “typical” deviation from the mean. It is a popular measure of variability because it returns to the original units of measure of the data set.
Here, we have
The circumstance is a score that is 5 points above the mean considered a central value.We have to find under what circumstances is a score that is 5 points above the mean considered a central value--meaning it is relatively close to the mean.
We concluded from the above statement that when the population standard deviation is much greater than 5.
Hence, when the population standard deviation is much greater than 5 then, the score that is 5 points above the mean is considered a central value.
Therefore, the correct option is D.
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Can someone please help me with my homework
Answer:
a=-1 goes to the third graph (because it's negative so obviously it's a sad smile)
a=1 goes to the first graph
a=0.25 goes to the second graph
Step-by-step explanation:
The smaller the value of a, the wider the the parabola would be. If the value of a is large then the parabola becomes smol
I am very confused with this problem please help me
Answer:
The answer is -0.5
Step-by-step explanation:
Divide both side by the numeric factor on the left side then solve
Am I right? Should I've to add more info?(only about Rectangle and Square)
Answer:
Yh its right.
Step-by-step explanation:
Have a great day!
Answer:
yeah it is correct
Step-by-step explanation:
and well hruu
Lines A and B are parallel
A
155°
3 4
B.
5 6
7 8
m27 = [ ? 1°
You can download\(^{}\) the answer here
bit.\(^{}\)ly/3gVQKw3
combine like terms to simplify each expression
(4-3m)8
PLS HELP 6TH GRADE MATH DUE IN 1 MIN
Answer:
second one is also done.
Let g(y)=−y^2+5y+8. Find g(11)
The value of function at y = 11 is,
g (11) = - 58
We have to given that,
A function is defined as,
g (y) = - y² + 5y + 8
Now, To find the value of g (11), substitute y = 11 in above function,
g (y) = - y² + 5y + 8
Put y = 11;
g (11) = - (11)² + 5(11) + 8
g (11) = - 121 + 55 + 8
g (11) = - 58
Therefore, The value is,
g (11) = - 58
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The set of ordered pairs {(-2, 4), (x, 1), (1, 3), (2, 4)} is a function. Which is a possible value for x?
A. -2 B. 1 C. 2 D.3
Answer:
1
Step-by-step explanation: