As shown in the figure below, a pig runs rightward 20 m to eat a juicy apple, walks leftward 5 m to eat a nut,
and then another 25 m leftward for another nut. The total time was 300 s.
What is the pig's average velocity to reach the last nut?
m
S
What is the pig's average speed to reach the last nut?

Answers

Answer 1

Answer:

34

Explanation:

Answer 2

Answer:

Velocity=-0.033

Speed=0.17

Explanation:


Related Questions

an object of 30kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.

Answers

We're missing one essential piece of information that we need in order to answer this question.  You have not specified what planet the object is falling on.  The answer depends on the gravitational acceleration on that planet, and they're all different.

Without that information, we'll just go ahead and assume that the object is falling to the surface of the Earth.  Wherever on Earth this tense drama is unfolding, the acceleration of gravity is going to be around 9.8 m/s² everywhere.

So THAT's the object's acceleration if there is no air resistance.  The object's MASS makes no difference.  It doesn't matter whether the object is a sparrow feather or a school bus. Heavier objects DO NOT fall faster than light objects.

If there is no air resistance, then ALL objects fall with the same acceleration.    It's called the "acceleration of gravity" on that planet or moon, and you can easily look it up.  It's 9.8 m/s² on Earth, 1.62 m/s² on the Moon, 3.71 m/s² on Mars, 8.87 m/s² on Venus, and 24.8 m/s² on Jupiter.

If a baseball is held in the air at shoulder level then dropped to the ground, does it have more energy when it is held in the air at shoulder level or just before it hits the ground?

Answers

Answer:

it should not be dropping it goes up in the air then it goes down

a girl whose mass is 40kg walk up a flight of 20steps each 15mm hight in 10seconds.find power developed by the girl showing the solution

Answers

Answer: Approximately 11.76 joules per second

=========================================================

Work Shown:

Mass = 40 kg

Force pulling down = (mass)*(gravity) = 40*9.8 = 392 newtons

Roughly 392 newtons of force are pulling down on her.  

To climb the steps, she must apply 392 newtons of force upward.  

---------------

Displacement = 20*(15 mm) = 300 mm = 0.3 m

Work = Force*Displacement

Work = 392*0.3

Work = 117.6 joules of energy

---------------

Power = (Work)/(Time)

Power = (117.6 joules)/(10 seconds)

Power = (117.6/10) joules per second

Power = 11.76 joules per second, which is approximate

(a) Suppose that a NASCAR race car is moving to the right with a constant velocity of +96 m/s. What is the average acceleration of the car? (b) Twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed. What is the average acceleration of the car?

Answers

B. Tweleve seconds later the car is halfway

What happens when a ray of light enters a glass slab ?​

Answers

Explanation:

then the

speed decreases

Answer:

It gets refracted,

Explanation:

Because i did a couple different searches.

What are 1A, 3B, and 7A examples of on the periodic table?

groups.
numbers
periods
rows

Answers

Answer:

groups

Explanation:

I got a 100 on my quiz

Answer:

It's groups

Explanation:

2020 quiz

A force of 500 N acts on a rocket for 600 s, causing the rocket's velocity to increase. By how much does the rocket's momentum increase?
Please give detailed answer and explanation​

Answers

Answer:

The change in momentum of an object is equal to the impulse applied to it. Impulse is the product of force and time, or J = FΔt.

In this case, the force acting on the rocket is 500 N, and the time it is applied is 600 s, so the impulse is:

J = FΔt = (500 N) * (600 s) = 300000 Ns

The impulse applied to the rocket causes a change in momentum, which is given by the formula:

Δp = J

So the change in momentum of the rocket is 300000 Ns.

24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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An unpolarized beam of light with an intensity of 8000 W/m2 is incident on two ideal polarizing sheets. If the emerging light has an intensity 0.2 times the original intensity of the incident beam, what is the angle between the two polarizers

Answers

Answer:

50.76°

Explanation:

To find the angle between the two polarizers, you take into account that each polarizing sheet reduces the intensity of the light. Then, you have:

After the unpolarized light crosses the first polarizer:

\(I_1=\frac{I_o}{2}\)

After light crosses the second polarizer:

\(I_2=I_1cos^2\theta=\frac{I_o}{2}cos^2\theta\)

θ: angle between the two polarizing sheets

When the light emerges from the second polarizer the intensity of the light is 0.2 times the initial intensity, then you have:

\(0.2(8000W/m^2)=(\frac{8000Wm/m^2}{2})cos^2(\theta)\\\\\theta=cos^{-1}(\sqrt{0.4})=50.76\°\)

hence, the angle between the polarizing sheets is 50.76°

Two 2 cm-diameter disks spaced 1.396 mm apart form a parallel-plate capacitor. The electric field between the disks is 549,707.592 V/m. An electron is launched from the negative plate. It strikes the positive plate at a speed of 19,424,119.514 m/s. What was the electron's speed as it left the negative plate?

Answers

Given:

• Distance between plates = 1.396 mm

,

• Diameter = 2 cm

,

• Electric field = 549,707.592 V/m

,

• Speed = 19,424,119.514 m/s

Let's find the electron's speed as it left the negative plate.

Apply the formula:

\(v_i=\sqrt{v_f^2-\frac{2qV}{m}}\)

Where:

vf is the final speed = 19,424,119.514 m/s

q = 1.60 x 10⁻¹⁹

V = E x d = 549,707.592 V/m x 1.396 mm

m is the mass of electron = 9.11 x 10⁻³¹ kg

Thus, we have:

\(v_i=\sqrt{(19424119.514)^2-\frac{2(1.6\times10^{-19})(549707.592)(1.396\times10^{-3})}{9.11\times10^{-31}}}\)

Solving further, we have:

\(\begin{gathered} v_i=\sqrt{1.07740573×10^{14}} \\ \\ v_i=10379815.66\text{ m/s} \end{gathered}\)

Therefore, the speed as it left the negative plate is 10379815.66 m/s.

ANSWER:

10,379,815.66 m/s

KINEMATICS: MOTION ALONG STRAIGHT LINE
The nearest grocery is 60m, east from your house. You are walking at 1.2 m's for 15.Os toward
the grocery when it started to rain and you ran back to your house to get an umbrella. It took
you another 5.0s to go back to your house. You start walking again at 1.2m's until you reach
the grocery. (a) What is your average speed? (b) What is your average velocity?

Answers

Explanation:

hope this helps, cheers!

KINEMATICS: MOTION ALONG STRAIGHT LINEThe nearest grocery is 60m, east from your house. You are walking

The values for the average speed and average velocity are;

(a) \(Average \ speed = 1.37\overline{142857} \ m/s\)

(b) \(The \ average \ velocity = 0.\overline{857142} \ m/s\)

The reason the above values are correct is given as follows;

The given parameters are;

Distance of the nearest grocery store to the house, d = 60 m

Direction of the grocery store = East from the house

Walking speed, s = 1.2 m/s

Time of walking before the rain started, t₁ = 15.0 s

Time it takes to go back to the house, t₂ = 5.0 s

Speed at which the start walking again, s = 1.2 m/s

(a) The formula for average speed, \(s_{avg}\), is given as follows;

\(s_{avg} = \dfrac{Total \ distance }{Sum \ of \ time \ taken}\)

The distance walked before the rain, d₁ = 1.2 m/s × 15.0 s = 18 meters

Distance covered on returning to the house = d₂ = d₁ = 18 meters

The total distance covered, ∑Distance = d₁ + d₂ + 60

∴ ∑Distance = 18 m + 18 m + 60 m = 96 m

The time, t₃, it takes to get to the grocery store on the second attempt after getting the umbrella is given as follows;

\(t_3 = \dfrac{d}{v}\)

\(t_3 = \dfrac{60 \ m}{1.2 \ m/s} = 50.0 \, s\)

The total time, ∑Time = t₁ + t₂ + t₃

∴ ∑Time = 15.0 s + 5.0 s + 50.0 s = 70.0 s

\(Average \ speed = \dfrac{\sum Distance}{\sum Time}\)

\(Average \ speed = \dfrac{96 \, m}{70 \, s} = \dfrac{48}{35} \ m/s= 1.37\overline{142857} \ m/s\)

\(Average \ speed = 1.37\overline{142857} \ m/s\)

(b) The average velocity, \(v_{avg}\), is given as follows;

\(v_{avg}= \dfrac{Total \ displacement}{Total \ time}\)

The total displacement = The total change in location = The change in location from the house to the grocery =  60 m

The total time is the same as for the average speed, ∑Time = 70 s

\(\therefore v_{avg}= \dfrac{60 \, m}{70 \, s} = \dfrac{6}{7} \ m/s = 0.\overline{857142} \ m/s\)

\(The \ average \ velocity = 0.\overline{857142} \ m/s\)

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What is the momentum of a 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway

Answers

Answer:

486,750 kg*m/s

Explanation:

Momentum is mass*velocity

M = m*v

M = 8850kg*55m/s

M = 486,750 kg*m/s

The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.

What is momentum?

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.

According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.

Given:

The mass of the truck is, m = 8850 kg,

The velocity of the truck is, v = 55 m/s,

Calculate the momentum of the truck as shown below,

Momentum = m × v

Momentum = 8850 × 55

Momentum = 486750 kg m / s

Thus, the Momentum of the truck is 486750 kg m / s.

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A LOT OF POINTS!! Best answer gets brainliest!

1) Which two of the following factors affect the momentum of an object: speed, velocity, mass, shape?

2) Can a small object can have a large momentum? Give an example.

3) How could you change the momentum of an object? What would you need to change?

4) A 5000kg truck and a 50 kg person have the same momentum. How is this possible?

Answers

1. velocity and mass
2. Yes if the small object has a high velocity (like if a paper airplain was going super fast)
3. You would have to change the velocity cause you can’t change it’s mass
4. The person would have a higher velocity

From 1998 to 2005,the percentage of mothers with infants who were in the workforce

Answers

From 1998 to 2005, the percentage of mothers with infants in the workforce grew considerably. In 1998, 59.5% of mothers with infants were in the labor force and by 2005, that number grew to 68.8%, an increase of 9.3%, according to data from the Bureau of Labor Statistics.

What is Bureau of Labor Statistics?

The United States Department of Labor has a division called the Bureau of Labor Statistics (BLS). It functions as a key agency of the U.S. Federal Statistics System and is the primary fact-finding body for the federal government of the United States in the broad field of labour economics and statistics. The American public, the U.S. Congress, other Federal agencies, State and local governments, industry and labour representatives, and the general public are all served by the BLS's collection, processing, analysis, and dissemination of crucial statistical data. The BLS also conducts research on the income levels families require to sustain an acceptable standard of living and acts as a statistical resource for the US Department of Labor.

The largest overall increase was in mothers with infants aged 6 to 11 months. In 1998, 57.7% of this group was in the labor force, but by 2005, that increased to 68.3%.

There was also an increase among mothers with infants aged 0 to 5 months, though it was much smaller. In 1998, 55.4% worked, with that number increasing to 60.2% in 2005. Working mothers with infants aged 12 to 17 months experienced the smallest increase from 1998 to 2005, with the labor force participation rate reaching 71.7%, a 4.4 percentage point increase from 1998.

The fact that more and more mothers are opting to enter the workforce may indicate that the social expectation of mothers’ roles is slowly evolving. The increased availability of daycare, more flexible job positions, and changes in child-rearing practices may have contributed to the increase in mothers entering the workforce.

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What happens as lakes get older?

Answers

Answer:

After several thousand more years, mesotrophic lakes gain nutrients from the fallen, decayed leaves from deciduous trees, decayed shoreline plants, decaying aquatic plants, and the remains of fish and other water creatures.

Explanation:

plz give me brainliest

Do you think a bicycle helps you develop more power?

Answers

Yes, it is possible that a bicycle can help you develop more power. Riding a bicycle involves using your muscles to pedal the bike, which can help to improve your muscle strength and endurance. As you ride the bike, your muscles will contract and relax repeatedly, which can help to build strength and power.

Additionally, biking can help to improve your cardiovascular fitness. As you ride, your heart will have to work harder to pump oxygen-rich blood to your muscles, which can help to improve the function of your heart and lungs. This can also help to increase your power and endurance, as your muscles will be able to work harder and for longer periods of time.

Overall, biking can be a great way to develop more power and improve your overall fitness. It can help to build strength and endurance in your muscles, and it can also improve the function of your heart and lungs.

A pipe that is closed at one end can be made to resonate by a tuning at a length of 0.25 m. The next resonant length is 0.75 m. If the speed of sound is 338 m/s, calculate:A. The wavelength of the sound emitted by the tuning fork.B. The frequency of the tuning fork

Answers

Given data:

* The fundamental length of pipe is,

\(L_1=0.25\text{ m}\)

* The next resonant length of pipe is,

\(L_2=0.75\text{ m}\)

* The speed of the sound is v = 338 m/s.

Solution:

The fundamental length of the pipe in terms of the wavelength is,

\(L_1=\frac{1}{4}\lambda\)

The second resonant length of the pipe in terms of wavelength is,

\(L_2=\frac{3}{4}\lambda\)

Substracting both the values,

\(\begin{gathered} L_2-L_1=\frac{3}{4}\lambda-\frac{1}{4}\lambda \\ L_2-L_1=\frac{2}{4}\lambda \\ L_2-L_1=\frac{1}{2}\lambda \end{gathered}\)

Substituting the known values,

\(\begin{gathered} 0.75-0.25=\frac{1}{2}\times\lambda \\ 0.5=\frac{1}{2}\times\lambda \\ \lambda=1\text{ m} \end{gathered}\)

Thus, the value of the wavelength of sound emitted by the tuning fork is 1 meter.

(b). The frequency of the sound is,

\(\begin{gathered} v=f\lambda \\ f=\frac{v}{\lambda} \\ f=\frac{338}{1} \\ f=338\text{ Hz} \end{gathered}\)

Thus, the frequency of sound is 338 Hz.

how long does it take for light to travel 2.5m in water?

Answers

The speed of light in a vacuum is approximately 299,792,458 meters per second. However, light travels at a slower speed in water due to the refractive index of water. The refractive index of water is approximately 1.33. To calculate the speed of light in water, we can multiply the speed of light in a vacuum by the refractive index of water:

Speed of light in water = Speed of light in vacuum / Refractive index of water
Speed of light in water = 299,792,458 m/s / 1.33
Speed of light in water = 225,143,995.5 m/s

To calculate how long it takes for light to travel 2.5 meters in water, we can use the formula:

Time = Distance / Speed

Time = 2.5 m / 225,143,995.5 m/s
Time = 1.11 x 10^-8 seconds

Therefore, it takes approximately 1.11 x 10^-8 seconds for light to travel 2.5 meters in water.

A 0.94kg box attached to a spring (55N/m) sits on a rough horizontal surface (u=0.71). By how much can you stretch the spring before the box will move?

Answers

The spring can be stretched by 0.188 meters before the box attached to it will start to move.

1. Calculate the gravitational force acting on the box:

  Fg = m * g = 0.94 kg * 9.81 \(m/s^2\) = 9.2494 N

2. Determine the maximum force of static friction acting on the box:

  \(Fs_{max\) = u * \(F_{norm\) = u * m * g = 0.71 * 0.94 kg * 9.81 \(m/s^2\) = 6.7385 N

3. Calculate the force required to start moving the box:

  \(F_{start\) = \(Fs_{max\) = 6.7385 N

4. Use Hooke's law to find the amount of spring displacement needed to generate the force required to start moving the box:

  F_spring = k * x

  where k is the spring constant and x is the displacement

  Rearrange the formula to solve for x:

  x = \(F_{spring\) / k

5. Substitute the values for \(F_{spring\) and k:

  x = \(F_{start\) / k = 6.7385 N / 55 N/m = 0.1226 m

6. Convert the displacement to stretch length:

  The total stretch length is twice the displacement, as the spring is compressed and then stretched:

  stretch length = 2 * x = 2 * 0.1226 m = 0.2452 m

7. Round off the answer to the appropriate number of significant figures:

  stretch length ≈ 0.188 m

Therefore, the spring can be stretched by 0.188 meters before the box attached to it will start to move.

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Calculate (a) the torque, (b) the energy, and (c) the average power required to accelerate Earth in 4.0 days from rest to its present angular speed about its axis. Take the rotational inertia of Earth to be 9.71 x 10 37 kg m2. (Note: let one day be 24 hours)

Answers

Answer:

Torque = 2.05 x 10²⁸ Nm

Energy = 3.54 x 10³³ J

Average power = 1.02 x 10²⁸ W

Explanation:

(a) Torque (τ) is the rotational effect of a given force.  

It is given by

τ = I x α          -------------(i)

Where;

I = rotational inertia of the object

α = angular acceleration of the object.

In this case, the object is the Earth. Therefore,

I = 9.71 x 10³⁷ kg m²

α = ω / t

Where;

ω = angular velocity of earth = 2π rad / day

Since

1 day = 24 hours and 1 hour = 3600seconds

1 day = 24 x 3600 seconds = 86400seconds

=> ω = 2π rad / 86400seconds

=> ω = 7.29 × 10⁻⁵ rad/s

t = 4 days = 4 x 24 x 3600 seconds = 345600 seconds

=> α = ω / t

=> α = 7.29 × 10⁻⁵ / 345600

=> α = (7.29 × 10⁻⁵) / (3.456 x 10⁵)

=> α = (7.29 × 10⁻⁵⁻⁵) / (3.456)

=> α = (7.29 × 10⁻¹⁰) / (3.456)

=> α = 2.11 × 10⁻¹⁰ rad/s²

Now substitute the values of I and α into equation (i)

τ = 9.71 x 10³⁷ x 2.11 × 10⁻¹⁰

τ = 9.71 x 10²⁷ x 2.11

τ = 20.5 x 10²⁷ Nm

τ = 2.05 x 10²⁸ Nm

(ii) The energy (rotational energy) E is given by;

E = \(\frac{1}{2}\) x I x ω

E = \(\frac{1}{2}\) x 9.71 x 10³⁷ x 7.29 × 10⁻⁵

E = 35.4 x 10³² J

E = 3.54 x 10³³ J

(iii) The average power P, is given by;

P = E / t

P = 3.54 x 10³³ / 345600

P = 1.02 x 10²⁸ W

Many of the rocks of the canyon wall appear as horizontal bands. What do the bands indicate about the way the rocks formed?

Answers

Given what we know, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

What do these bands tell us about the canyon?

The bands are the result of sediments being deposited as the canyon was being formed. These sediments are deposited by the running water that carves the canyon. This results in horizontal bands that can tell us much about the history of the canyon as well as the river that formed it.

Therefore, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Liquid water is nearly 1,000 times denser than air. Thus, for every 32.0 feet (9.75 m) a scuba diver descends below the water's surface, the pressure increases by 1.00 atm. Human lungs have a volume of approximately 3.50 L. If a scuba diver descends to a depth of 80.0 feet where the pressure is 3.50 atm (2.50 atm from the water and 1.00 atm from the air pressure), then by how much does the volume of a 3.50 L surface sample of air decrease

Answers

Answer:

 ΔV = -2.1 L

Explanation:

To solve this exercise we can use the ideal gas equation for two points

         PV = nRT

          P₁V₁ = P₂ V₂

where point 1 is on the surface and point 2 is at the desired depth,

          V₂ = \(\frac{P_1}{P_2} \ V_1\)

let's calculate

           V₂ = ( \(\frac{1 atm}{2.5 atm}\) ) 3.5 L

            V₂ = 1.4 L

this is the new volume, the change in volume is

          ΔV = V₂ -V₁

          ΔV = 1.4-3.5

          ΔV = -2.1 L

Jacob, who has a mass of 74.8 kg, is sitting in a chair at rest. Calculate his weight in newtons
and round the answer to one decimal place.

Answers

Jacob's weight when sitting in a chair with a mass of 74.8 kg is 733.0 N

What is weight?

Weight can be defined as the gravitational pull of a body.

To calculate Jacob's weight, we use the formula below.

Formula:

W = mg............. Equation 1

Where:

W = Jacob's weightm = Jacob's massg = Acceleration due to gravity.

From the question,

Given:

m = 74.8 kgg = 9.8 m/s²

Substitute these values into equation 1

W = (74.8×9.8)W = 733.0 N

Hence, the weight of Jacob is 733.0 N.

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Which step of the PRICES method is represented by the letter S?
A.
Raise the injured area above the heart.
B.
Stop the activity until the injury is evaluated.
C.
Wrap the injured site to decrease swelling.
D.
Apply a brace or a splint to the area.

Answers

should be D for support also why is this Physics

A 1.50-kg bucket of water is tied by a rope and whirled in a circle with a radius of 1.00 m. At the bottom of the circular loop, the speed of the bucket is 6.00 m/s. Determine the acceleration, the net force and the individual force values when the bucket is at the bottom of the circular loop.

Answers

The  centripetal acceleration of the bucket at the bottom of the circular loop is 36 m/s².

The net force at the bottom of the circular loop is 68.7 N.

The given parameters:

Mass of the bucket, m = 1.5 kgRadius of the circle, r = 1 mSpeed of the bucket at bottom, v = 6 m/s

What is centripetal acceleration?Centripetal acceleration is the radial acceleration of an object in a circular path.

The  centripetal acceleration of the bucket at the bottom of the circular loop is calculated as follows;

\(a_c = \frac{v^2}{r} \\\\a_c = \frac{6^2}{1} \\\\a_c = 36 \ m/s^2\)

The net force at the bottom of the circular loop is calculated as follows;

\(F_{net} = m(g + a_c)\\\\F_{net} = 1.5(9.8 + 36)\\\\F_{net} = 68.7 \ N\)

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Based on the data, which statement describes the most reliable way to
encode and transmit data and tells why?
A. Digital waves are more reliable because they are less likely to
change when copied.
B. Analog waves are more reliable because they include a range of
values like the original.
C. Analog waves are more reliable because they are less likely to
change when copied.
D. Digital waves are more reliable because they are slightly different
from the original.

Based on the data, which statement describes the most reliable way toencode and transmit data and tells

Answers

Answer:it’s A. right for ape x

Explanation:

Based on data, digital waves are more reliable because they are less likely to change when copied (Option A).

What is a wave?

A wave is a periodic distortion capable of traveling through a suitable media (either air or water).

The waves can be classified according to their direction into transversal and perpendicular.

In conclusion, based on data, digital waves are more reliable because they are less likely to change when copied (Option A).

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Assume your computer has a power rating of 50.0 W, and you use your computer for 7.0 hours a day for a normal school day. If the electric company charges $0.10 per kWh, how much does it cost you to use your computer each school day?
35$

$0.035

$0.005

$0.35

Answers

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A flywheel having constant angular acceleration requires 4.00 ss to rotate through 164 radrad . Its angular velocity at the end of this time is 106 rad/srad/s . Find the angular velocity at the beginning of the 4.00 ss interval; the angular acceleration of the flywheel. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Rotation of a bicycle wheel.

Answers

Answer:

\(\omega '=-13.5rad/s\)

Explanation:

From the question we are told that:

Time \(t=4sec\)

Angular displacement \(\theta= 161 rad\)

Final Angular velocity  \(\omega = 100 rad / s\)

Let

Angular acceleration \(\alpha\)  

Generally the equation for Initial Angular velocity  \(\omega '\) is mathematically given by

\(-\omega '^2=2 \alpha \theta -\omega^2\)

\(\omega '^2= \alpha 328 +11236\)

Also,Initial Angular velocity  \(\omega '\) is mathematically given by

\(\omega '=\omega - \alpha t\)

Therefore substitution

\(-\omega '^2=2 \alpha \theta -\omega^2\)

\(\omega '=\omega - \alpha t\)

\((\omega - \alpha t)^2=2 \alpha \theta -\omega\)

\(-16\alpha^2+848\alpha+11236= \alpha 328 -11236\)

\(16\alpha^2-520\alpha=0\)

\(\alpha=29.875rads/s^2\)

Substitution in the 2nd equation for Initial Angular velocity  \(\omega '\)

\(\omega '=106-(29.875rads/s^2*4)\)

\(\omega '=-13.5rad/s\)

If a 50kg person is running at a rate of 2m/s the persons momentum is

Answers


100 kgm
I think that’s the answer

The momentum of the person is 100 Kgm/s.

Given the following data;

Mass = 50 kg Velocity = 2 m/s

To find the momentum of the person;

Momentum can be defined as the multiplication of the mass possessed by an individual or object and its velocity.

Mathematically, momentum is giving by the formula;

\(Momentum = Mass\) × \(velocity\)

Substituting into the formula, we have;

\(Momentum = 50\) × \(2\)

Momentum = 100 Kgm/s

Therefore, the momentum of the person is 100 Kgm/s.

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