An atom of aluminum (AI) has an atomic number of 13 and a mass number of
27. How many neutrons does it have?

Answer:

Mg + 2HCl=== Mg(Cl)2 + H2

The Reaction is a single displacement reaction.

Yes!

This reaction obeys the law of conservation which states that for a closed system... Matter and energy transfer is constant.

Meaning that the Mass of products must equal mass of Reactants

To prove this

lets Calculate the Mass of reactants

24g + 73g=97g.

Mass of Products...

95g + x.

let's calculate the mass of Hydrogen produced.

Note: You can get it using any of the reactants... I'll use Magnesium

Now from the balanced reaction.... 1mole of Mg reacts to produce 1mole of Hydrogen

Moles of Mg=Mass/Molar Mass

Given Mass=24g

Molar mass of Mg=24

Mole of Mg =24/24

=1mole

Since Mole ratio of Mg and H2 is 1:1.... Therefore 1Mole of Hydrogen is produced too.

To get Mass of H2

Again

Mole=Mass/Mm

Known= 1mole of H2 isproduced

Mass of H2 =2g

Mole=Mass/Mm

Mass =Mole x Mm

= 1 x 2

=2g

Now

Total Mass of products is

95 +2 = 97g.

This is the same with the Mass of Reactants

So The Law of Conservation of Mass Holds.

In liquid-liquid extraction, it is more efficient to do multiple extractions rather than one large one because the solubility of the solute in the solvent may decrease in each extraction.

The amount of solute that dissolves in a solvent decreases with each extraction. Multiple extractions are performed to extract the maximum amount of solute from the mixture being separated in liquid-liquid extraction.

Liquid-liquid extraction is a technique that is used to isolate one or more dissolved or suspended components from a mixture based on their relative solubilities in two immiscible liquids.

Multiple extractions, also known as re-extraction, is a procedure that involves separating a target compound from a mixture by extracting it several times with the same solvent or a series of solvents.

Multiple extractions are done when the solubility of the solute in the solvent decreases with each extraction. This will help to extract the maximum amount of solute from the mixture.

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Given:  

Temperature T = 391KReaction:41" (aq) + Mn0,(s) +2Fe2+ (aq) --Mn?* (aq) + 2Fe2+ (aq) + 2H,001) From the given standard reduction potentials, the balanced chemical reaction taking place can be written as:4H+(aq) + MnO2(s) + 2Fe2+(aq) -> Mn2+(aq) + 2Fe3+(aq) + 2H2O

(l) Standard reduction potentials:

MnO2(s) + 4H+(aq) + 2e- -> Mn2+(aq) + 2H2O(l) E° = 1.23 VFe3+(aq) + e- -> Fe2+(aq) E° = 0.77 V

The balanced chemical reaction can be split into two half-reactions: Oxidation half-reaction: MnO2(s) + 4H+(aq) + 2e- -> Mn2+(aq) + 2H2O(l)Reduction half-reaction: Fe3+(aq) + e- -> Fe2+(aq)The equilibrium constant can be calculated using the Nernst equation, which gives the relationship between equilibrium constants and reduction potentials:log(K) = (nFE°)/2.303RTwhereK = equilibrium constantn = number of electrons transferred in the overall balanced reactionF = Faraday's constantR = gas constantT = temperatureE° = standard reduction potential

We can write the equation for the overall balanced reaction as follows:

Fe3+(aq) + MnO2(s) + 4H+(aq) + 2Fe2+(aq) -> Mn2+(aq) + 2Fe3+(aq) + 2H2O

(l)The standard reduction potential for the overall balanced reaction can be calculated using the standard reduction potentials of the two half-reactions .E° cell = E°(reduction) - E°(oxidation)E° cell = 0.77 V - 1.23 V = -0.46 V Substituting the values in the Nernst equation: log(K) = ((2)(96485 C mol-1)(-0.46 V))/(2.303(8.314 J mol-1 K-1)(391 K))log(K) = -9.7K = 2.0 x 10-10Therefore, the equilibrium constant at 391 K is 2.0 x 10-10.

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Answer:

its 210

Explanation:

Just add all atomic mass used in the formula together: 2*(14+16*3)+88= 2*62+88=124+88=210

Hope this was helpful

The relative formula mass of strontium nitrate Sr(NO₃)₂ is 210

The relative atomic masses of N, O and Sr are 14,16 and 88 respectively.

In calculating the relative atomic mass of an element with isotopes, the relative mass and proportion of each is taken into account. Adding the atomic masses together gives the relative formula mass of a compound

So, relative atomic mass of Sr(NO₃)₂ is calculated as

88+ 2(14+16×3) = 210

The atomic mass constant (symbol: mu) is defined as being 1/12 th of the mass of a carbon-12 atom. Since both quantities in the ratio are masses, the resulting value is dimensionless; hence the value is said to be relative atomic mass.

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Answer:

A: cell membrane

B: cell wall

C: cytoplasm

D: vacuole

E: Nucleus

F: if it's green, it's chloroplast

G: probably centrioles

H: I think mitochondria

Explanation:

checked with my notes and with the internt to be sure that it's mostly correct.

This is hard to learn, you need to memorize it. It's way easier to know how the part looks like and what it does than knowing the name and not knowing what it's function.

Good luck

The statement a spontaneous process is also spontaneous in the reverse direction is not true about a spontaneous process (Option e).

A spontaneous process in physics makes reference to any phenomenon in which it can be triggered naturally without requiring an input of energy to carry out, which occurs when continues on its own once begun.

Therefore, with this data, we can see that a spontaneous process in physics refers to all phenomena that may progress with the need of a given input of energy to be produced.

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Electron affinity tend to become more exothermic as you move right across a period because the effective nuclear charge increases as you move right across the period, resulting in greater attraction for an electron. The correct answer is: D.

Electron affinity is the energy change that occurs when an electron is added to a neutral atom in the gaseous state. It is measured in kJ/mol and is typically reported as a positive or negative value.

A positive electron affinity means that energy is required to add an electron to the atom, while a negative electron affinity means that energy is released when an electron is added to the atom.

The effective nuclear charge is the net positive charge experienced by an electron in an atom. It is calculated by subtracting the number of shielding electrons from the number of protons in the nucleus.

As you move right across a period, the effective nuclear charge increases because each successive element has one more proton in its nucleus.

This increase in effective nuclear charge results in a greater attraction for an electron, which makes it more likely for an atom to gain an electron.

Therefore, electron affinity tends to become more exothermic as you move right across a period because the effective nuclear charge increases, resulting in greater attraction for an electron.

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The earth's mantle will not change in the future because this region is safe from the intervention of human beings.

The transfer of heat and material in the mantle helps us to determine the landscape of Earth. Activity in the mantle moves the plate tectonics, that contributes to volcanoes, seafloor spreading, earthquakes, and building of mountains.

So we can conclude that the earth's mantle will not change in the future because this region is safe from the intervention of human beings.

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Answer:

The parts of an atom cannot be directly observed.

Explanation:

An atom is the smallest indivisible particle of a substance that can take part in a chemical reaction.

Atoms are not observed with naked eyes because they are found in the realm of very small particles. It is impossible to observe the parts of an atom directly.

As a result of this, models suffice in explaining the parts of an atom. Hence the answer.

The decay of Gallium-67 follows the exponential decay formula:

\(N = N_0 * (1/2)^(^t^/^T^1^/^2^)\)

Where:

N = final amount remaining

\(N_0\)= initial amount

t = time elapsed

\(T_1_/_2\) = half-life

The first thing we can do is find out how many half-lives have passed in 127 hours:

Number of half-lives = t / T1/2 = 127 hours / 78.2 hours = 1.624

Next, we can determine how much Gallium-67 is left using this value:

Rounding to the nearest decimal point, N = N0 * (1/2) * (t/T1/2) = 51.3 mg * (1/2) * (1.624) = 25.6 mg.

Therefore, after 127 hours about 25.6 mg of gallium-67 remains.

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The pKa of N-benzyl-1,1-diphenylmethanimine (imine) is not readily available in the literature,it is important to note that imines, in general, have a pKa range of 5-7 depending on the substituents attached to the nitrogen atom.

However, it is important to note that imines, in general, have a pKa range of 5-7 depending on the substituents attached to the nitrogen atom. The presence of the benzyl and diphenyl groups in N-benzyl-1,1-diphenylmethanimine may affect its pKa compared to other imines.

It is also important to note that the pKa value of a compound indicates the acidity or basicity of the molecule, which affects its reactivity and solubility properties.

Therefore, knowing the pKa value of N-benzyl-1,1-diphenylmethanimine can provide important information for synthetic chemists when designing and optimizing reaction conditions.

The pKa of N-benzyl-1,1-diphenylmethanimine, which is an imine, refers to the acidity constant of the compound. Imines are compounds featuring a carbon-nitrogen double bond, and in this specific case, N-benzyl-1,1-diphenylmethanimine is characterized by a benzyl group and two phenyl groups connected to the imine carbon. However, It is bit difficult to provide a specific pKa value for N-benzyl-1,1-diphenylmethanimine as it appears that the experimental value for this particular compound is not readily available in the literature.

Typically, imines have pKa values in the range of 9-11. The specific pKa value depends on the electronic and steric effects of the substituent groups on the imine nitrogen and carbon. In the case of N-benzyl-1,1-diphenylmethanimine, the presence of the benzyl and diphenyl groups could potentially influence the pKa value, making it different from other imines. To determine the exact pKa value for this compound, one would need to either consult specialized literature or perform experimental measurements.

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There are three kinds of rock cycle in Earth's Crust:

Rocks is one of the main raw materials of the Earth's crust. This is because the rock that decomposes becomes soil which is used as a medium for plant growth and as a place to live for all living things on Earth. There are three kinds of rocks that exist on Earth with a long process of formation. Each of these rocks forms a layer in the Earth's atmosphere with different shapes and textures.

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Answer:

Reflection

Explanation:

Answer:

b

Explanation:

The given reaction is already balanced, that is to say tha the number of atoms in the reactants matches the number of atoms in the products. In the reaction, we can see the relationship between CaC2 and H2O. For each mole of CaC2 two moles of H2O react.

So, if 4.8 moles of CaC2 are consumed the moles of H2O needed will be:

Mol of H2O = Mol of CaC2 x 2

Mol of H2O = 4.8 x 2 = 9.6 mol of H2O

Now, to calculate the grams of H2O we will use the following equation and the mass molar of H2O.

Mass molar of H2O =18.01 g/mol

So, if 4.8 moles of CaC2 are consumed in this reaction, 172.9 g of H2O are needed

Answer:

1.8 x 10^ 24 atoms of oxygen

Explanation:

The molecular weight of ozone is known to be 48 grams / mol. Here we are given a sample of 48 grams of ozone as well, so in 48 grams of ozone the number of moles = 48 / 48 = 1,

_______________________________________________________

1 mole of ozone is equal to 6.0221415 × 10^23 molecules of ozone. Respectively, 1 molecule of ozone has 3 atoms of oxygen. Thus, you can conclude the following -

3 * 6.0221415 × 10^23 =  ( About ) 1.8 x 10^ 24 atoms of oxygen

Hope that helps!

The volume of 48 grams of ozone at room temperature and pressure (r.t.p) is equal to 24 \(dm^3\).

Given the following data:

Scientific data:

To determine the volume of 48 grams of ozone at room temperature and pressure (r.t.p):

First of all, we would calculate the number of moles of ozone contained in 48 grams of ozone by using the formula:

\(Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{48}{48}\)

Number of moles = 1.0 moles

By stoichiometry:

1 mole of ozone =  24 \(dm^3\)

Note: At room temperature and pressure (r.t.p), the volume of any gas is equal to 24 \(dm^3\) or 24,000 \(cm^3\).

In conclusion, the volume of 48 grams of ozone at room temperature and pressure (r.t.p) is equal to 24 \(dm^3\).

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Answer:

C: petal

D:stamen

Answer:

Pistil

sepal

petal

stamen

To determine the number of moles of potassium chloride (KCl) required to react with 9.27 moles of oxygen gas ( O_{2}), we need to use the stoichiometry of the balanced chemical equation. The balanced equation shows that 2 moles of potassium chloride react with 3 moles of oxygen gas to produce 2 moles of potassium chlorate (\(KClO_{3}\)).

According to the stoichiometry of the balanced chemical equation, 2 moles of potassium chloride react with 3 moles of oxygen gas to produce 2 moles of potassium chlorate. Therefore, we can set up a ratio based on this stoichiometry:

2 moles KCl / 3 moles O_{2}= x moles KCl / 9.27 moles O_{2}

Solving for x, we can find the number of moles of potassium chloride required:

x = (2 moles KCl / 3 moles O_{2}) * 9.27 moles \(O_{2}\)

x = 6.18 moles KCl

Therefore, 6.18 moles of potassium chloride are needed to react with 9.27 moles of oxygen gas. The stoichiometry of the balanced equation allows us to determine the appropriate amounts of reactants required for the given reaction.

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Answer:

it is C

Explanation:

I saw from Google. Hope it helps.

I cant get the full picture

sorry

Answer:

Explanation:

Decomposition reaction, also known as analysis or dissociation, is a type of chemical reaction in which a compound breaks down into simpler substances or elements. In this reaction, a single reactant undergoes a chemical change and produces two or more products.

The decomposition reaction can be represented by the general equation:

AB → A + B

Where AB is the reactant, and A and B are the products. The reactant AB is usually a compound, and it breaks down into its constituent elements or simpler compounds.

There are different types of decomposition reactions, including:

Thermal decomposition: It occurs when a compound is heated, resulting in its decomposition into simpler substances. For example, the thermal decomposition of calcium carbonate (CaCO3) produces calcium oxide (CaO) and carbon dioxide (CO2):

CaCO3 → CaO + CO2

Electrolytic decomposition: It takes place when an electric current is passed through an electrolyte, causing it to break down into its component ions. For instance, the electrolysis of water (H2O) leads to the decomposition into hydrogen gas (H2) and oxygen gas (O2):

2H2O → 2H2 + O2

Photochemical decomposition: It occurs when a compound undergoes decomposition due to exposure to light energy. Chlorine gas (Cl2) can decompose into chlorine atoms (Cl) under the influence of light:

Cl2 → 2Cl

These are just a few examples of decomposition reactions. They are important in various chemical processes and are used in industries, laboratory experiments, and natural phenomena. By understanding and controlling decomposition reactions, scientists can gain insights into the behavior of different compounds and develop practical applications in fields such as chemistry, materials science, and environmental science.

Answer:

Explanation:

reaction in which a compound breaks down into simpler substances or elements

Empirical formulae are the ratios of atoms in a compound that show the lowest possible ratio of atoms per mole of compound.

In this question, we are to find the empirical formulae for the following ions:

OCl³⁻, NH⁴⁺, CH₃CO₂⁻ and Pb⁴⁺

Empirical formula for OCl³⁻:Oxygen (O) forms an anion by gaining three electrons to form the oxide ion, O²⁻

The ClO₃⁻ ion has one O²⁻ and three Cl⁺ ions. Therefore, the empirical formula is OCl³⁻

Empirical formula for NH₄⁺ :Nitrogen (N) forms a cation by losing three electrons to form N₃⁺ while Hydrogen (H) forms a cation by losing an electron to form H⁺. Therefore, the empirical formula for NH₄⁺ is NH₄⁺

Empirical formula for CH₃CO₂⁻

The ion contains 2 Carbon atoms, 3 Oxygen atoms, and 4 Hydrogen atoms. Divide each number of atoms by the lowest number (2) to give the empirical formula: CH₃CO₂⁻

Empirical formula for Pb⁴⁺:Lead (Pb) forms a cation by losing four electrons to form Pb⁴⁺.Therefore, the empirical formula for Pb⁴⁺+ is Pb⁴⁺.

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The composition of each compound as the mass percent of its elements is as follows:

Concentration is expressed as mass percent. Additionally, the ingredients in a particular mixture are described. Solution composition can be understood in terms of mass percent. It indicates the mass of solute present in a solution of a given mass. The amount of solute is expressed in mass or moles.

Mass Percent = (Component Mass ÷ Total Mass) x 100% or

(mass of solute ÷ mass of solution) x 100%

a. Sucrose (C₁₂H₂₂O₁₁) with molecular mass of 342.296 u composed of:

Carbon: (12 x 12.01) / 342.296 = 42.18%

Hydrogen: (22 x 1.01) / 342.296 = 6.44%

Oxygen: (11 x 16) / 342.296 = 51.38%

b. Aluminum sulfate (Al₂(SO₄)₃) with molecular mass of 342.14 u is composed of:

Aluminum: (2 x 26.98) / 342.14 = 3.99%

Sulfur: (3 x 32.06) / 342.14 = 4.57%

Oxygen: (18 x 16) / 342.14 = 87.44%

c. Magnetite (Fe₃O₄) with molecular mass of 231.534 u is composed of:

Iron: (3 x 55.85) / 231.534 = 71.83%

Oxygen: (4 x 16) / 231.534 = 28.17%

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Correct question is;

Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is?

Answer:

6%

Explanation:

From ohms law, we know that;

R = V/I

Where;

R is resistance

V is voltage

I is current

Now, the percentage error in the resistance is given by the formula;

ΔR/R = ΔV/V+ ΔI/I

We are told that the current and the voltage difference have a percentage error of 3% each. Thus;

ΔR/R = 3% + 3% = 6%

Answer:

Explanation:

The hydrogen ion concentration can be found by finding the antilog of the pH

\(pH = - log [ {H}^{+} ]\)

We have

\(2.11 = - log({H}^{+}) \\ find \: \: antilog \: of \: both \: \: sides \\ \\ |{H}^{+}| = {10 }^{ - 2.11} \\ = 0.00776...\)

We have the final answer as

0.01 M to 2 decimal places

Hope this helps you

Reproduced, transferred their genes to progeny, died from natural causes, fell ill or contracted a disease, became prey for a predator or were devoured by a scavenger, or moved to a new area.

Non-living things include items like rocks, water, the atmosphere, the climate, and natural occurrences like earthquakes and rockfalls. One of the qualities that characterises living beings is their capacity for reproduction.

Its definition includes glass, the sun, water, sand, and rock as non-living objects. They show absolutely no signs of life. Some people define a non-living object as anything that once belonged to a live entity.

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It is  necessary to adjust the height of the graduated cylinder when measuring the volume of co2 (g) produced to maintain atmospheric pressure.

Pressure is defined as force/area. To illustrate the pressure from snow on a roof, divide the weight of the snow by the surface area of the roof. Gases are a typical pressure source in chemistry. A "vacuum" is used to describe the absence of pressure. Humans have long held the belief that vacuums are both improbably rare and unnatural since "nature abhors a vacuum." Actually, this is not the case.

The number of pressure units is ridiculous. It's common to use the torr or mmHg unit. This discussion is solely focused on the height of a mercury column. The atmosphere contains 760 torr, or mmHg. You could also look at mmH2O, which makes use of a comparable idea.

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The volume of the dry nitrogen gas at STP is 57.4 mL

From the question given above, the following data were obtained:

Initial volume (V₁) = 77 mL

Initial temperature (T₁) = 50 °C = 50 + 273 = 323 K

Initial pressure (P₁) = 763 – 92.5 = 670.5 mmHg

Final temperature (T₂) = STP = 273 K

Final pressure (P₂) = 760 mmHg

The volume of the dry nitrogen can be obtained by using the combine gas equation as follow:

\( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\ \\ \frac{670.5 \times 77}{323} = \frac{760 \times V_2}{273} \\ \\ cross \: multiply \\ \\ 323 \times 760 \times V_2 = 670.5 \times 77 \times 273 \\ \\ divide \: both \: side \: by \: 323 \times 760 \\ \\ V_2 = \: \frac{670.5 \times 77 \times 273 }{323 \times 760} \\ \\ V_2 = 57.4 \: ml\)

Therefore, the volume of the dry nitrogen gas is 57.4 mL

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