An aeroplane moving horizontally with a speed of 200 m/s drops a food packet while flying at a height of 396.9 m. The time taken by the food packet to reach the ground and its horizontal range is ...

A.5 s and 1000 m
B.9 s and 1800 m
C.8 s and 1600 m

Answer:

6.8×10^6 m

Explanation:

f = velocity of light/ wavelength

440= 3×10^8 / wavelength

so

wavelength = 3×10^7/ 44

= 6.8×10^6 m

Answer:

mass = 25.5kg

Explanation:

The gravitational force equivalent, or, more commonly, g-force, is a measurement of the type of force per unit mass – typically acceleration – that causes a perception of weight, with a g-force of 1 g equal to the value of gravitational acceleration on Earth, g, of about 9.8 m/s².

Mass, m = \(\frac{Force}{acceleration due to gravity}\)

\(mass,m=\frac{F}{g} = \frac{250}{9.8}= 25.5 kg\)

Answer:

Smart Meters measure both the amount of electrical energy used and the time at which it is being used because they are used to monitor the energy consumption at real time, such that the time of use of energy can be monitored, thereby enabling several utility functions for load sharing and maintenance, including;

i) Time of use  tariffs, where energy is billed based on peak and off peak periods, which increases profits to the producer, reduces cost for some consumers, encourages more even hourly and daily usage of electricity, lower maintenance cost, lower capital expenditure for peak stations, and reduces carbon emission

ii) Guarantees more accurate energy consumption measurement and billing

iii) Accurate crew dispatch to fault locations

iv) Prevent fraud due to tampering with meter

v) Increase customer confidence in billing

Explanation:

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Answer:

it means it will become faster because more force are applied. This means that if you get pushed, the harder you are pushed, the faster you'll move (accelerate). The bigger you are, the slower you'll move.

hope this helps bby<3

The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.

In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.

No atoms gain or lose electrons in this process.

In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.

This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.

A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.

These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.

It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.

Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.

Therefore, statement B, which suggests that each atom gains one electron, is false.

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The laws of conservation of energy and conservation of angular momentum direct that any rotating and collapsing cloud will end up as a spinning disk. That implies cloud will spin faster.

According to law of conservation of angular momentum of same mass, if the size of the collapsing cloud decrease, its it angular velocity should increase.

Formula for Angular momentum,

L =mrω^2

As L and m is constant , when r is decreased ω must increase. Then, cloud will spin faster.

Law of conservation when applied to angular momentum,  mean that momentum of a rotating object does not change unless external torque is applied. Torque here may refer to any outside force that acts upon the object to cause it to twist or rotate.

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If we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

The correct relationship between the frequency of the incident radiation (ν), its wavelength (λ), and speed (c) is:

A. ν = λ/c

This equation is known as the wave equation and describes the relationship between the frequency, wavelength, and speed of a wave. It states that the frequency of a wave is inversely proportional to its wavelength and directly proportional to its speed. The speed of light (c) is a constant in a vacuum and its value is approximately 3.0 x 10^8 m/s.

Therefore, if we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

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Answer:

\(f=5.76\times 10^{14}\ Hz\)

Explanation:

We need to find the frequency of green light having wavelength o\(5.2\times 10^{-7}\ m\). It can be calculated as follows :

\(c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz\)

So, the required frequency of green light is equal to \(5.76\times 10^{14}\ Hz\).

Answer:

both are subject to a person's interpretation.

Answer:

it is a subject to a person's interpretation.

Explanation:

i hope this helps!

Answer:

The final solution is 38 g.

Explanation:

(2.4 (g / mL)) x 15.82 mL

= 37.96800 grams

When rounded, we get 38, so 38 g is the final solution.

Answer:

38 g is the answer

hi <3

i would say it is 'electricity'

hope this helps :)

An equilateral triangle is a triangle whose sides are all equal in length and has three equal angles of 60° each. To draw an equilateral triangle with sides of length 5, you can use a compass and a ruler to measure 5 cm. Using the compass, place the needle at one end of the line segment and draw an arc that intersects the line segment at another point.

Place the needle on the intersection point and draw another arc that intersects the first arc at a third point. The line segments connecting the three points are all of equal length 5 and form an equilateral triangle.To draw an altitude in an equilateral triangle, we need to drop a perpendicular line from one of the vertices to the opposite side. This line is known as the altitude.

When the altitude is drawn, it creates two smaller right-angled triangles with the base of the equilateral triangle. We can use this to find the length of the altitude.To find the length of the altitude of the equilateral triangle with sides of length 5, we need to use the Pythagorean theorem since we know that the smaller right-angled triangles have a base of 2.5 (half the side length) and a hypotenuse of 5 (side length). Using a² + b² = c², where a and b are the legs of the right triangle and c is the hypotenuse, we get:a² + (2.5)² = (5)²a² + 6.25 = 25a² = 18.75a ≈ 4.33.

Therefore, the length of the altitude is approximately 4.33 units.To compute the trigonometric ratios of this triangle, we can use the sides and altitude of the equilateral triangle. Using SOHCAHTOA (sine, cosine, tangent, cosecant, secant, and cotangent), we can find the ratios for the angles of the triangle.Sin(60°) = Opposite/Hypotenuse = 4.33/5 = 0.866Cos(60°) = Adjacent/Hypotenuse = 2.5/5 = 0.5Tan(60°) = Opposite/Adjacent = 4.33/2.5 = 1.732Cosecant(60°) = Hypotenuse/Opposite = 5/4.33 = 1.154Secant(60°) = Hypotenuse/Adjacent = 5/2.5 = 2Cotangent(60°) = Adjacent/Opposite = 2.5/4.33 = 0.577

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Answer:

sa64

Explanation:

Answer:

it is d all of the above your welcome

Answer:

true

Explanation:

Some factors of heart disease cannot be controlled. A diet rich in high-density lipoproteins (HDLs) can help cleanse and open arteries that are clogged with plaque. Exercise can help prevent heart disease but once you've had a heart attack, it's too late for exercise to help you.

Answer:

(a) The list of angles based on amount of time in the air; 15° < 25° < 45° < 60°, < 80°

(b) The list of angles based on distance = 80° < 15° < 25° < 60° < 45°

Explanation:

(a) The given parameters are;

The angles in which the ball is thrown, θ = 45°, 15°, 60°, 25°, and 80°

The velocity with which the ball is thrown each time = The same velocity

The amount of time the projectile is in the air given as follows;

\(2 \cdot t = \dfrac{2\cdot u \cdot sin (\theta) }{g}\)

Where;

t = Half the amount of time the projectile is in the air

θ = The angle of flight of the projectile

u = The initial velocity of the projectile = Constant for all angles in which the ball is thrown

g = The acceleration due to gravity = 9.8 m/s² = Constant

Therefore, we have;

When θ = 45°;

\(2 \cdot t = \dfrac{2\cdot u \cdot sin (45^ {\circ}) }{g} = \dfrac{2\cdot u \cdot \dfrac{\sqrt{2} }{2} }{g} = \dfrac{\sqrt{2} \cdot u }{g}\)

When θ = 15°;

\(2 \cdot t = \dfrac{2\cdot u \cdot sin (15^ {\circ}) }{g} \approx \dfrac{0.517638\cdot u }{g}\)

When θ = 60°;

\(2 \cdot t = \dfrac{2\cdot u \cdot sin (60^ {\circ}) }{g} = \dfrac{2\cdot u \cdot \dfrac{\sqrt{3} }{2} }{g} = \dfrac{\sqrt{3} \cdot u }{g}\)

When θ = 25°;

\(2 \cdot t = \dfrac{2\cdot u \cdot sin (25^ {\circ}) }{g} = \dfrac{0.8452365\cdot u }{g}\)

When θ = 80°;

\(2 \cdot t = \dfrac{2\cdot u \cdot sin (80^ {\circ}) }{g} = \dfrac{1.9696155\cdot u }{g}\)

Therefore, the list of the angles based on the amount of time in the air from the shortest time to the longest time is given as follows;

List of angles based on amount of time in the air; 15° < 25° < 45° < 60°, < 80°

(b) The horizontal range, R is given as follows;

\(R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}\)

When θ = 45°

\(R = \dfrac{u^2 \cdot sin(2 \times 45 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(90 ^{\circ}) }{g} = \dfrac{u^2 }{g}\)

When θ = 15°

\(R = \dfrac{u^2 \cdot sin(2 \times 15 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(30 ^{\circ}) }{g} = \dfrac{1}{2} \cdot \dfrac{u^2 }{g} = 0.5 \cdot \dfrac{u^2 }{g}\)

When θ = 60°;

\(R = \dfrac{u^2 \cdot sin(2 \times 60 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(120 ^{\circ}) }{g} = \dfrac{u^2 }{g} \cdot \dfrac{\sqrt{3} }{2} =0.866025 \cdot \dfrac{u^2 }{g}\)

When θ = 25°;

\(R = \dfrac{u^2 \cdot sin(2 \times 25 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(50 ^{\circ}) }{g} = \dfrac{0.7660444 \cdot u^2 }{g}\)

When θ = 80°

\(R = \dfrac{u^2 \cdot sin(2 \times 80 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(160 ^{\circ}) }{g} = \dfrac{0.34202 \cdot u^2 }{g}\)

Therefore the list of angles based on the horizontal range the baseball travels from the shortest distance to the longest distance is given as follows;

List of angles based on distance = 80° < 15° < 25° < 60° < 45°.

The thermal efficiency of the heat engine is half that of the Carnot engine, with a relative efficiency of 0.365.

The thermal efficiency of a Carnot engine is given by:

η = 1 - (T2/T1)

Where T1 and T2 are the temperature of the heat source and heat sink respectively.

In this case, T1 = 100°C and T2 = 375°C, so the thermal efficiency of the Carnot engine is:

η = 1 - (375/100) = 0.73

The thermal efficiency of the heat engine is therefore half of that of the Carnot engine, so its relative efficiency is 0.365.

If the heat engine absorbs heat at a rate of 50kW, then the rate of heat exhausted would be 50kW multiplied by the relative efficiency of 0.365, which is 18.25kW.

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The elevation at point B is 740 ft. Therefore, option B is correct.

The height above or below a specified reference point, most frequently a reference geoid, which is a mathematical representation of the Earth's sea level as an equipotential gravitational surface, determines a location's elevation.

Four points are displayed on the accompanying map, ranging from A to D. Between these four places, there are still a few additional lines. The height between these points and lines is indicated on the map in feet, and from point A onwards there is an elevation difference of 20 feet.

Thus, option B is correct.

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The cannonball travels horizontally before it reaches the ground at an angle of 30° above the horizontal with an initial velocity of 26 m/s is 59.73 meters.

When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.

Given:

The initial velocity of a cannonball, u = 26 m/s,

Calculate the range of the cannonball by following the formula,

R = \(u^2\)sin2θ / g

Here R is the range, and θ is the angle of projection.

Substitute the values,

R = \(26^2\) sin2*30 / 9.8

R  = 59.73 meters

Therefore, the cannonball travels horizontally before it reaches the ground at an angle of 30° above the horizontal with an initial velocity of 26 m/s is 59.73 meters.

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Since the centripetal force and the net force are in opposite directions, we can subtract the centripetal force from the net force to find the net force towards the center of the track. So, the net force towards the center is 3562.4 N - 19796.4 N = -16234 N.
Therefore, the net force towards the center of the track is -16234 N.

To find the car's acceleration, we can use the formula for acceleration, which is change in velocity divided by time. In this case, the change in velocity is from 0 m/s to 37 m/s, and the time is 11 s. So, the acceleration is (37 m/s - 0 m/s) / 11 s = 3.36 m/s².

Now, let's find the net force acting on the car. We can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. The mass of the car is 1060 kg, and the acceleration we just calculated is 3.36 m/s². So, the net force is (1060 kg) * (3.36 m/s²) = 3562.4 N.

Next, let's find the net force acting towards the center of the circular track. This force is provided by the friction between the tires and the track, and it is called the centripetal force. The centripetal force is given by the formula: centripetal force = mass * velocity² / radius. Plugging in the values, we get: centripetal force = (1060 kg) * (37 m/s)² / 500 m = 19796.4 N.

Since the centripetal force and the net force are in opposite directions, we can subtract the centripetal force from the net force to find the net force towards the center of the track. So, the net force towards the center is 3562.4 N - 19796.4 N = -16234 N.

Therefore, the net force towards the center of the track is -16234 N.

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Answer:

For eons, the world's oceans have been sucking carbon dioxide out of the atmosphere and releasing it again in a steady inhale and exhale. The ocean takes up carbon dioxide through photosynthesis by plant-like organisms (phytoplankton), as well as by simple chemistry: carbon dioxide dissolves in water.

Explanation:

c. A current is induced in the coiled wire, which lights the light bulb.

If we kept the bar magnet stationary and moved the coil back and forth within the magnetic field an electric current would be induced in the coil.

Then by either moving the wire or changing the magnetic field we can induce a voltage and current within the coil and this process is known as Electromagnetic Induction and is the basic principle of operation of transformers, motors and generators.

When the magnet shown below is moved “towards” the coil, the pointer or needle of the Galvanometer, which is basically a very sensitive center zeroed moving-coil ammeter, will deflect away from its center position in one direction only.

When the magnet stops moving and is held stationary with regards to the coil the needle of the galvanometer returns back to zero as there is no physical movement of the magnetic field.

Therefore ,

If you move a bar magnet back and forth along the axis of the coiled wire shown below then a current is induced in the coiled wire, which lights the light bulb.

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The image here is not found here but star formation is characterized by clouds of dust where stars are born.

Star formation is a physical phenomenon where molecular clouds in space need to collapse to generate stars.

Stellar evolution is a process that initiates when a star is formed and ends when it dies (formation of a red giant).

Stars can be generated inside clouds of dust which are dispersed in different types of galaxies in the universe.

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At the ball's highest point, it has no vertical velocity, so the 6 m/s is purely horizontal. A projectile's horizontal velocity does not change, which means the ball was initially thrown with speed v such that

v cos(53°) = 6 m/s   ==>   v = (6 m/s) sec(53°) ≈ 9.97 m/s

The player shoots the ball from a height of 2.0 m, so that the ball's horizontal and vertical positions, respectively x and y, at time t are

x = (9.97 m/s) cos(53°) t = (6 m/s) t

y = 2.0 m + (9.97 m/s) sin(53°) t - 1/2 gt ²

Find the times t for which the ball reaches a height of 3.00 m:

3.00 m = 2.0 m + (9.97 m/s) sin(53°) t - 1/2 gt ²

==>   t ≈ 0.137 s   or   t ≈ 1.49 s

The second time is the one we care about, because it's the one for which the ball would be falling into the basket.

Now find the distance x traveled by the ball after this time:

x = (6 m/s) (1.49 s) ≈ 8.93 m

The answer of the question is

(a)Voltage or Volt

(b)Ampere (A)

(c)Ohm

The height to which the ball rises is approximately 20.3 meters.

We can use the principle of conservation of energy to determine the height to which the ball rises. At the instant the ball leaves the foot, the total initial energy is the kinetic energy of the ball:

K_i = 1/2 * m * v_i^2

where m is the mass of the ball, and v_i is the initial velocity of the ball, which is 20 m/s. Substituting the given values, we get:

K_i = 1/2 * 0.45 kg * (20 m/s)^2 = 90.0 J

At the highest point of the ball's trajectory, its kinetic energy is zero, so all the initial energy has been converted into gravitational potential energy, given by:

U_f = m * g * h

where g is the acceleration due to gravity, which we take as 9.81 m/s^2, and h is the height to which the ball rises. Substituting the given values, we get:

U_f = 0.45 kg * 9.81 m/s^2 * h = 4.3965 h

Now we need to find the height h. To do this, we can use the principle of impulse and momentum, which states that the impulse of a force acting on an object is equal to the change in the object's momentum:

I = F * t = m * (v_f - v_i)

where I is the impulse of the force, F is the average resultant force acting on the ball, t is the time for which the force acts, and v_f is the final velocity of the ball, which is zero at the highest point of the ball's trajectory. Solving for v_f and substituting the given values, we get:

v_f = v_i - (F * t) / m

v_f = 20 m/s - (180 N * 0.050 s) / 0.45 kg

v_f = 2.2222 m/s

Now we can use the principle of conservation of energy to find the height h:

K_i = U_f

1/2 * m * v_i^2 = m * g * h

h = (1/2 * v_i^2) / g

h = (1/2 * (20 m/s)^2) / 9.81 m/s^2

h = 20.3 m

Therefore, the height to which the ball rises is approximately 20.3 meters.

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The volume of the square tank is

(10cm • 10cm • 10cm) = 1,000 cm^3 .

The volume of liquid in the cylinder is

500 m^3 = 500,000,000 cm^3 .

(500,000,000) / (1,000) = 500,000

The liquid in the measuring cylinder can fill the square tank 500,000 times.