A line passes through the points A(n,4) and B(6,8) and is parallel to y=2x-5. What is the value of n?​

Answer:

should be x^2-9/x-3

Answer: Answer for question 7: 9x -7 is less than or equal to 38, X=5

Step-by-step explanation: Since a number next to a variable means multiplying, we can guess that 9 x 5=45, and 45-7 is less than or equal to 38. There is EZ math for ya

Answer:

7.  x ≤ 5

8. x > 4

9. x < 5

10. x < -7

11.  x < 45

12. x ≥ -10

13. k ≤ 3

14. x < 21

15. x ≥ -50

16. w ≥ 16

17. x  ≥ -15

18. q > 4

Step-by-step explanation:

Given the subtotal of $55.97, apply taxes as shown below (remember that 6.75%=6.75/100=0.0675)

Now, apply the discount (20%=20/100=0.20)

The answer is approximately $47.8 (taxes first, then discount)

The measure of the complement of the angle is A) 54.

Given:

The ratio of the measure of the supplement of an angle to that of a complement of the angle is 8:3.

Let x be the angle.

supplement of the angle of x is = 180-x

complement of the angle of x is = 90 -x

180 - x / 90 -x = 8/3

3(180-x) = 8(90-x)

3*180 - 3*x = 8*90 - 8*x

540 - 3x = 720 - 8x

-3x+8x = 720 - 540

5x = 180

divide by 5 on both sides

x = 180/5

x = 36

Complement of the angle = 90 - 36

= 54

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The n building exemplifies interactive design because it integrates into its façade interactive digital displays.

The n building showcases interactive design by seamlessly incorporating interactive digital displays into its façade. These displays allow for dynamic content, such as visuals, videos, and interactive elements, to be presented on the building's exterior.

By engaging with passersby and creating an interactive experience, the n building transforms a static architectural structure into a vibrant and participatory environment.

This integration of interactive digital displays into the building's façade not only enhances its visual appeal but also fosters a sense of connection and engagement with the surrounding community, blurring the boundaries between the physical and digital realms.

The n building exemplifies interactive design because it integrates into its façade elements that engage and interact with the users. This can include features such as interactive screens, touch-sensitive panels, or interactive lighting displays. These elements encourage user participation and create an immersive and engaging experience for those interacting with the building.

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Answer:

0,3

Step-by-step explanation:

Well 0,3 is the only one that is on here... I apologize if I am wrong!

Answer:

36 = 6(6)

\(x^{2} -(6)^2\)

(x+6)(x-6)

(x+6)(x-6)

The missing reasons in the given two column proof are;StatementReason1. MO bisects ZPMNGiven2. ZPMO 3ZNMO Definition of angle bisector3. MOMO Given4. OM bisects ZPONGiven5. ZPOM ZNOM Definition of angle bisector6. A PMO SANMO CPCTC (corresponding parts of congruent triangles are congruent)

Thus, the correct option is ;Option A: Definition of angle bisector for Statement 2.Option E: Definition of angle bisector for Statement 5.Option F: CPCTC (corresponding parts of congruent triangles are congruent) for Statement 6 The angle bisector theorem states that if a ray bisects an angle of a triangle, then it divides the opposite side into two parts that are proportional to the other two sides of the triangle. A perpendicular bisector of the opposite side is a geometric locus of points that are equidistant from the opposite side of the triangle. The perpendicular bisector is the bisector of the side, and vice versa.

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Answer:

b.

(a) 676,000,000

(b) 98,280,000.

Step-by-step explanation:

If no repetition the number of possible outcomes is:

26P2 * 10P6

= 650 * 151200

= 98,280,000.

If repetitions are allowed it is:

(650 + 26) * 10^6

= 676 * 1,000,000

= 676,000,000.

Answer:

Thebecks u

Step-by-step explanation:

its 93

The greatest number of 130-kilogram crates that can be loaded into the shipping container is 116.

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.

The weight that can be loaded on the container

= Total weight capacity of container - Weight that is already present on the container

= 26,500 kilograms - 11,400 kilograms

= 15,100 kilograms

Now, the number of crates that can be put in the container,

Number of crates

= Weight that can be loaded on the container / Weight of a crate

= 15,100 kilograms / 130 kilograms

= 116.1538 ≈ 116

Hence, the greatest number of 130-kilogram crates that can be loaded into the shipping container is 116.

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Answer:

the first one is about 8

the second one is about 13

Step-by-step explanation:

To find f'(4) for the function f(x) = ln(2x^3), we first need to find the derivative f'(x) using the chain rule.

The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

For f(x) = ln(2x^3), the outer function is ln(u) and the inner function is u = 2x^3.

The derivative of the outer function, ln(u), is 1/u.
The derivative of the inner function, 2x^3, is 6x^2 (using the power rule).

Now, apply the chain rule: f'(x) = (1/u) * 6x^2 = (1/(2x^3)) * 6x^2.

Simplify f'(x): f'(x) = 6x^2 / (2x^3) = 3/x.

Now, find f'(4): f'(4) = 3/4.

So, f'(4) for f(x) = ln(2x^3) is 3/4 or 0.75 when rounded to 2 decimal places.

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In question 16, a 98% confidence interval was computed based on a sample of 41 Veterans' Day celebrations. If the confidence level were decreased to 90%, the margin of error would decrease, and the width of the confidence interval would also decrease.

This is because a lower confidence level requires a smaller range of values to be included in the interval, resulting in a narrower range of possible values. However, it's important to note that decreasing the confidence level also increases the risk of the interval not capturing the true population parameter.

1. Margin of Error: The margin of error is affected by the confidence level because it is directly related to the critical value (or Z-score) associated with the chosen confidence level. As the confidence level decreases, the critical value also decreases. This will result in a smaller margin of error.

2. Confidence Interval: The confidence interval is calculated by adding and subtracting the margin of error from the sample mean. Since the margin of error is smaller when the confidence level is decreased to 90%, the width of the confidence interval will also become narrower.

In summary, decreasing the confidence level from 98% to 90% will result in a smaller margin of error and a narrower confidence interval for the sample of 41 Veterans Day celebrations.

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The statement 'when finding a minimum in a linear programming problem, it is possible to find more than one minimum value' is True.

In this question, we have been given a statement - 'when finding a minimum in a linear programming problem, it is possible to find more than one minimum value.'

We need to state whether it is true or false.

We know that, the minimum value of the objective function Z = ax + by in a linear programming problem can also occur at more than one corner points of the feasible region.

Therefore, when finding a minimum in a linear programming problem, it is possible to find more than one minimum value.

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Answer:

2x - 11, 2x + 11

Step-by-step explanation:

The length of each side must multiply together to get \(4x^2 - 121\) so have to factorise to make 2x-11 and 2x +11.

Answer: 61.51%

Step-by-step explanation:

To find : percentage for a 20 year old man with a cholesterol level less than 190.

20 lies between 18 and 24.

For this , Cholesterol levels are normally distributed with a mean(\(\mu\)) of 178 and a standard deviation(\(\sigma\)) of 41.

let X = cholesterol level in 20 year old man.

Required probability = \(P(X< 190)=P(\dfrac{X-\mu}{\sigma}<\dfrac{190-178}{41})\)

\(=P(z<0.2926)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\= 0.6151 [\text{By p-value table}]\)

hence, the percentage for a 20 year old man with a cholesterol level less than 190 = 61.51%

Answer:

- 10/8= -5/2

Step-by-step explanation:

You go down 10 and right eight to get to each point: rise/run, or in this case fall/run. Simplified it would be -5/2.

Hope this helps ❤

The formula for slope is,

The rate of change of T at the point P (2, 1) with respect to x and y are −17.7778 and −4.4444, respectively.

Given, the temperature at a point (x, y) on a rectangular metal plate is given by T(x, y) = 100/(4x² + y²).

(a) To find the rate of change of T at the point P (2, 1), we have to evaluate partial derivative of T with respect to x and y.

Let's find the partial derivative of T with respect to x:

∂T/∂x = ∂/∂x (100/(4x² + y²))

= −200x/(4x² + y²)²

Now, let's find the partial derivative of T with respect to y:

∂T/∂y = ∂/∂y (100/(4x² + y²))

= −200y/(4x² + y²)²

Now, we can find the rate of change of T at the point P (2, 1) by substituting x = 2 and y = 1 in the above results.

(b) Rate of change of T at point P with respect to x:

∂T/∂x = −200(2)/(4(2)² + 1²)²

= −800/45

≈ −17.7778

(c) Rate of change of T at point P with respect to y:

∂T/∂y = −200(1)/(4(2)² + 1²)²

= −200/45

≈ −4.4444

Therefore, the rate of change of T at the point P (2, 1) with respect to x and y are −800/45 ≈ −17.7778 and −200/45 ≈ −4.4444, respectively.

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Given system of linear equations is:$$ \begin{aligned} x_1 + x_2 + 8x_3 &= 20 \\ x_1 + 5x_2 - x_3 &= 10 \\ 4x_1 + 2x_2 + 6x_3 &= 12 \end{aligned} $$

To solve the system by Jacobi's iterative method, write each equation in terms of the corresponding variable (i.e., isolate each variable on the left-hand side of the equation) as follows:$$ \begin{aligned} x_1 &= 20 - x_2 - 8x_3 \\ x_2 &= 10 - x_1 + x_3 \\ x_3 &= \frac{12 - 4x_1 - 2x_2}{6} \\ \end{aligned} $$Using initial estimates of x as [0, 0, 0], start the iteration process:$$ \begin{aligned} \text{Iteration 1:} & & \\ x_1^{(1)} &= 20 - 0 - 8(0) = 20 \\ x_2^{(1)} &= 10 - 0 + 0 = 10 \\ x_3^{(1)} &= \frac{12 - 4(0) - 2(0)}{6} = 2 \\ \text{Iteration 2:} & & \\ x_1^{(2)} &= 20 - 10 - 8(2) = -6 \\ x_2^{(2)} &= 10 - (-6) + 2 = 18 \\ x_3^{(2)} &= \frac{12 - 4(-6) - 2(18)}{6} = -4 \\ \text{Iteration 3:} & & \\ x_1^{(3)} &= 20 - 18 - 8(-4) = -10 \\ x_2^{(3)} &= 10 - (-10) - 4 = 24 \\ x_3^{(3)} &= \frac{12 - 4(-10) - 2(24)}{6} = -10 \\ \text{Iteration 4:} & & \\ x_1^{(4)} &= 20 - 24 - 8(-10) = 102 \\ x_2^{(4)} &= 10 - (102) - 10 = -102 \\ x_3^{(4)} &= \frac{12 - 4(102) - 2(-102)}{6} = 34 \\ \text{Iteration 5:} & & \\ x_1^{(5)} &= 20 - (-102) - 8(34) = 302 \\ x_2^{(5)} &= 10 - (302) + 34 = -258 \\ x_3^{(5)} &= \frac{12 - 4(302) - 2(-258)}{6} = 110 \\ \end{aligned} $$The iteration stops when the error of each estimate is less than the tolerance of 10³. In this case, since the magnitude of the third estimate exceeds the tolerance, the process must continue until the tolerance is met:$$ \begin{aligned} \text{Iteration 6:} & & \\ x_1^{(6)} &= 20 - (-258) - 8(110) = 1,118 \\ x_2^{(6)} &= 10 - (1,118) + 110 = -998 \\ x_3^{(6)} &= \frac{12 - 4(1,118) - 2(-998)}{6} = 330 \\ \end{aligned} $$Therefore, the solution to the system of linear equations by Jacobi's iterative method with initial estimate [0, 0, 0] and tolerance of 10³ in the norm is:$$ \boxed{x \approx [1,118, -998, 330]} $$

The iterative method is used to solve a system of linear equations, as in the Jacobi iteration method. The method is used when the original method is not effective or too complex. Iterative techniques are popular because they can compute a large number of equations using a computer quickly and accurately.Jacobi's iterative method is a technique used to solve a set of linear equations with n variables that requires at least n iterations to converge. It works by isolating each variable on one side of the equation and then iteratively substituting the previous estimate of each variable into the corresponding equation until the estimated values converge within a certain tolerance.The iteration formula for Jacobi's method is given by$$ x_i^{(k+1)} = \frac{1}{a_{ii}} \left(b_i - \sum_{j=1, j \ne i}^{n} a_{ij} x_j^{(k)} \right) $$where k is the iteration number and x^(k) is the vector of previous estimates. In this formula, the diagonal element aii is isolated on one side of the equation, and the summation term represents the contribution of all other variables except xi. The previous estimate xi^(k) is then substituted into the equation to compute the updated estimate xi^(k+1).

Jacobi's method is a powerful tool for solving a system of linear equations with multiple variables. The method involves iterative substitution of the previous estimate of each variable into the corresponding equation until the estimated values converge within a certain tolerance. The process continues until the desired level of accuracy is reached. This method can be effectively used to solve many problems that would otherwise be too difficult or complex.

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Answer:

Yes I agree with Andre's example. I agree with Andre's example because ants have 6 legs so you would write L= 1/6 x a.

Step-by-step explanation:

Hope this helps :)))

Answer:

b/w 19 & 55

Step-by-step explanation:

average of four equally weighted 100-point tests,

mark has scored 90, 86, and 85 on the first three.

C average = 70 and 79

90+86+85+x = 4*70 = 280, so x=19

90+86+85+x = 4*79 = 316, so x=55

In order to create a program that calculates the factorial of the number entered by the user, follow the steps given below:

Step 1: Start the program.

Step 2: Take input from the user in the form of an integer.

Step 3: Initialize a variable to store the factorial of the input integer. Let's name it 'fact'.

Step 4: Assign the value of fact to 1.

Step 5: Start a for loop and run it from 1 to the input integer. Assign the loop variable to i.

Step 6: Inside the loop, update the value of fact as fact=fact*i.

Step 7: End the loop.

Step 8: Print the value of fact as output.

Step 9: End the program.

Here is the code that implements the above steps:

import java. util.Scanner;

public class Main {public static void main(String[] args)

{

Scanner input = new Scanner(System.in);

System. out.println("Enter a number: ");

int n = input.nextInt();

int fact = 1;

for (int i=1; i<=n; i++)

{

fact = fact * i;

}

System.out.println("Factorial of "+n+" is "+fact);

}

}

The above program first prompts the user to enter a number.

Then it calculates and prints the factorial of the number entered by the user using the formula given below:

n! = n*(n-1)*(n-2)*...*3*2*1

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Answer:

Addition Property of Equality

Step-by-step explanation:

Addition Property of Equality.

The addition property of equality justifies the work done in Line 3. This is because it essentially states that if you add something to one side of an equation, you must add it to the other side as well. In this case, we are adding 22 to both sides of the equation, therefore we are making use of the Addition Property of Equality.

We can simplify \((16x^4)^(-1/2) to 1/(4x^2)\) using the properties of rational exponents.

Certainly! Here's an example:

Simplify the expression: \((16x^4)^(-1/2)\)

We can apply the property of rational exponents which states that \((a^m)^n = a^(m*n)\). Using this property, we get:

\((16x^4)^(-1/2) = 16^(-1/2) * (x^4)^(-1/2)\)

Next, we can simplify \(16^(-1/2)\) using the rule that \(a^(-n) = 1/a^n\):

\(16^(-1/2) = 1/16^(1/2) = 1/4\)

Similarly, we can simplify \((x^4)^(-1/2)\) using the rule that \((a^m)^n = a^(m*n)\):

\((x^4)^(-1/2) = x^(4*(-1/2)) = x^(-2)\)

Substituting these simplifications back into the original expression, we get:

\((16x^4)^(-1/2) = 1/4 * x^(-2) = 1/(4x^2)\)

Therefore, the simplified expression is \(1/(4x^2).\)

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The average value of the function f(x) = \(3x^2\) - 4x on the interval [0, 3] is c. 3. To find the average value of the function f(x) = \(3x^2\) - 4x on the interval [0, 3], we need to compute the definite integral of the function over the given interval and divide it by the length of the interval.

The average value of a function f(x) on the interval [a, b] is given by the formula:

Average value = (1 / (b - a)) * ∫[a to b] f(x) dx

In this case, we have the function f(x) = \(3x^2\) - 4x and the interval [0, 3]. To find the average value, we need to evaluate the definite integral of f(x) over the interval [0, 3] and divide it by the length of the interval, which is 3 - 0 = 3.

Computing the definite integral, we have:

∫[0 to 3] (\(3x^2\) - 4x) dx = \([x^3 - 2x^2]\) evaluated from 0 to 3

= \((3^3 - 2(3^2)) - (0^3 - 2(0^2))\)

= (27 - 18) - (0 - 0)

= 9

Finally, we divide the result by the length of the interval:

Average value = 9 / 3 = 3

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Answer:

$20 i think

Step-by-step explanation: have a good day bye bye yup yup

8m + 6 = 7m + 5

Subtract 7m from both sides:

M+ 6 = 5

Subtract 6 from both sides:

M = -1

Answer:

m=-1

Step-by-step explanation:

8m-7m=5-6

m=-1

As we are finding the value of m which is the unknown we have to make it positive while moving the rest of the numeric values to the other side we move 7m because 7m and 8m are like terms and to evaluate the unknowns value

In this question, we have to find an equation for two lines, depending on the input x, which creates the following piecewise function for this graph:

\(y = t, 0 \leq t \leq 10, -t + 20, 10 \leq t \leq 20\)

Equation of a line:

The equation of a line is given by:

\(y = mt + b\)

In which m is the slope and b is the y-intercept(value of y when x = 0).

This situation:

x between 0 and 10:

From here, we can take two points (t,y). I will take (0,0) and (10,10).

From point (0,0), we get that when \(x = 0, y = 0\), which means that the y-intercept is \(b = 0\), thus:

\(y_1 = mt\)

To find the slope, when we have two points, it is given by change in y divided by change in t, so:

Change in t: 10 - 0 = 10

Change in y: 10 - 0 = 10

Slope: \(m = \frac{10}{10} = 1\)

Thus, the first definition is:

\(y_1 = t, 0 \leq t < 10\)

x between 10 and 20:

I will take the points (10,10) and (20,0).

First, we find the slope:

Change in t: 20 - 10 = 10

Change in y: 0 - 10 = -10

Slope: \(m = \frac{-10}{10} = -1\)

Thus:

\(y_2 = -t + b\)

For the intercept, we have point (20,0), which means that when \(t = 20, y = 0\). So

\(0 = -20 + b\)

\(b = 20\)

Thus, the second definition is:

\(y_2 = -t + 20, 10 \leq t \leq 20\)

Write an equation for the graph.

We use the two definitions, that is:

\(y = y_1, 0 \leq t \leq 10, y_2, 10 \leq t \leq 20\)

So

\(y = t, 0 \leq t \leq 10, -t + 20, 10 \leq t \leq 20\)

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