A branch swept into a Category 3 hurricane has a centripetal acceleration of 0.028 m/s2. Estimate the radius of the storm is wind speeds are
53 m/s

Radii is a vital feature of the elements, and it can be useful in determining the characteristics of elements in various chemical and physical processes. The radii of atoms and ions of the same element differ due to their various charge and mass characteristics.

Atomic and ionic radii increase as you move down a group on the periodic table, and decrease as you move across a period from left to right due to increased nuclear charge, making the electrons closer to the nucleus. The size of an atom and ion also changes due to the number of electrons charge, and electronic configuration.In order of increasing radius, the arrangement of \(Ne, F-, O2-, Br-, Rb\) is given as follows:

\(Ne < F- < O2- < Br- < Rb+\)

Rb+ has the smallest radius due to its large nuclear charge and fewer electrons in the valence shell.

As a result, they are larger than Rb+. O2- has more electrons than Ne and is the largest among the given ions and atoms. It is important to note that in certain conditions, the trends in radii may not be valid because of hybridization and other factors. Nonetheless, this arrangement is valid for the given ions and atoms.

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The car covers a distance d after time t of

d = (2.8 m/s²) t²

Solve for t when d = 69 m:

69 m = (2.8 m/s²) t²

t² = (69 m) / (2.8 m/s²)

t ≈ 4.96 s

Answer:

2. Mathew Maury

Explanation:

2. Mathew Maury

4. Cousteau and Gagnon

Explanation:

they made the first successful scuba in 1942

The magnitude and direction of the resultant force are 10.0N and 101.36⁰

The sum of force along the force horizontal is expressed as:

\(\sum F_x=-15.0N+15cos30\\\sum F_x = -15.0N + 12.99N\\\sum F_x = -2.01N\)

The sum of force along the vertical is expressed as:

\(\sum F_y = +10N\)

Calculate the magnitude of the force:

\(F=\sqrt{(\sum F_x)^2+(\sum F_y)^2} \\F=\sqrt{(-2.01)^2+(10)^2} \\F=\sqrt{104.0401}\\F= 10.2N\)

Hence the magnitude of the resultant force is 10.2N

Find the direction

\(\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{10}{-2.01}\\\theta =tan^{-1}(-4.9751)\\\theta =-78.63^0\\\theta = 180-78.63 = 101.36^0\)

Hence the magnitude and direction of the resultant force are 10.0N and 101.36⁰

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The direction of the resultant acceleration is 17° North of West. The correct answer is D. The first step is to break down the forces into their horizontal and vertical components.

The eastward force from the ocean tide is purely horizontal, while the wind force has both horizontal and vertical components. To find the horizontal component, we use the cosine of the angle between the force and the horizontal axis:
1500 N * cos(45°) = 1060 N

To find the vertical component, we use the sine of the angle:
1500 N * sin(45°) = 1060 N

So the total horizontal force acting on the sailboat is:
4500 N + 1060 N = 5560 N

And the total vertical force is:
1060 N

To find the direction of the resultant acceleration, we can use trigonometry to find the angle that the acceleration vector makes with the horizontal axis. The tangent of this angle is equal to the vertical component of the acceleration divided by the horizontal component:
tan(θ) = 1060 N / 5560 N

θ = tan^-1(1060/5560) = 10.9°

Therefore, the direction of the resultant acceleration is 17° North of West. The correct answer is D.

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The term above which describes the amount of force exerted on a given area is pressure

However, pressure is derived quantity.

What are derived quantities?

Derived quantities are those quantities which are obtained from the combination of fundamental quantities either by addition, division or multiplication

In conclusion, the term above which describes the amount of force exerted on a given area is pressure

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Pressure is the term which describes the amount of force exerted on a given area and is denoted as option D.

This is described as the force per unit area of a substance and the unit is mmHg or pascal.

This is why pressure was chosen as the most appropriate choice in this type of scenario.

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Answer: 0.28 A

Explanation:

Answer:

46.98 kg m/s

Explanation:

P = mv

P = 5.8*8.1 = 46.98 kg m/s

The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

The height of the player above the ground can be calculated using the formula below.

Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

⇒ Solve for s.

Hence, The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

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The magnitude of the emu's acceleration is 0.827 m/s². Since the emu is slowing down, the acceleration is in the opposite direction to the initial velocity, which is south (negative y-axis).

a) To calculate the magnitude of the emu's acceleration, we can use the formula:

\(\[a = \frac{{v_f - v_i}}{{t}}\]\)

where \(a\) is the acceleration,\(\(v_i\)\) and\(\(v_f\)\) are the initial and final velocities of the object, and\(\(t\)\)is the time elapsed.

In this case, the initial velocity of the emu,\(\(v_i\)\), is 13.0 m/s (north). The final velocity, \(\(v_f\)\), is 10.6 m/s (north), and the time taken, \(t\), is 2.90 s.

Substituting these values into the formula, we have:

\(\[a = \frac{{10.6 \, \text{m/s} - 13.0 \, \text{m/s}}}{{2.90 \, \text{s}}} = -0.827 \, \text{m/s}^2\]\)

b) To calculate the final velocity of the emu after an additional 1.60 s has elapsed, we can use the kinematic equation:

\(\[v_f = v_i + at\]\)

where\(\(v_i\)\)is the initial velocity, \(\(a\)\) is the acceleration, \(\(t\)\)is the time elapsed, and\(\(v_f\)\) is the final velocity.

Assuming the acceleration remains the same as in part (a), we can substitute the given values into the equation:

\(\[v_f = 10.6 \, \text{m/s} + (-0.827 \, \text{m/s}^2) \\)times \((1.60 \, \text{s}) = 9.23 \, \tet{m/xs}\]\)

Therefore, the final velocity of the emu after an additional 1.60 s has elapsed is 9.23 m/s (north).

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Answer:

(R=6. 4×106m)

Explanation:

The height above the surface of earth at which acceleration due to gravity is half the acceleration due to gravity at surface of earth

Explanation:

acceleration due to gravity at surface of earth is (R=6. 4×106m)

hope this answer helps you

Answer:

\(a_{c} = 50\ m/s^2\)

Explanation:

In uniform circular motion, the acceleration of the object is due to the changing direction of velocity of the object. this acceleration is referred to as centripetal acceleration. It can be calculated by following formula:

\(a_{c} = \frac{v^2}{r}\)

where,

ac = centripetal acceleration = ?

v = speed of the object = 15 m/s

r= radius of circular motion = distance of object from center of rotation = 4.5 m

Therefore, using these values in equation, we get:

\(a_{c} = \frac{(15\ m/s)^2}{4.5\ m}\\\\a_{c} = 50\ m/s^2\)

The composition of two reflections across non-parallel lines results in a translation, with the same center results in a single rotation, with the same center but in opposite directions results in a single rotation, with different centers results in a single rotation, the composition of a rotation and a reflection results in a single reflection and the composition of a rotation and a reflection results in a single reflection.

To determine the single rigid motion represented by the given composition, we need to analyze the properties and transformations involved.

A. (reflection in line n) o (reflection in line m), when lines n and m are not parallel:

The composition of two reflections across non-parallel lines results in a translation.

B. (rotation, center P, x⁰ cw) o (rotation, center P, y⁰ cw):

The composition of two rotations with the same center results in a single rotation.

C. (rotation, center Q, a⁰ cw) o (rotation, center Q, b⁰ ccw):

The composition of two rotations with the same center but in opposite directions results in a single rotation.

D. (rotation, center R, 50⁰ cw) o (rotation, center S, 60⁰ cw), where R and S are different:

The composition of two rotations with different centers results in a single rotation.

E. (rotation, center T, 40⁰ cw) o (reflection in line p), where line p goes through point T:

The composition of a rotation and a reflection results in a single reflection.

F. (rotation, center T, 40⁰ cw) o (reflection in line q), where line q misses point T:

The composition of a rotation and a reflection results in a single reflection.

Based on the given options, the correct answer would depend on the specific properties and transformations described by the problem statement. Without additional information or a diagram, it is not possible to determine the exact answer.

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The statement that is true is that; nuclear fission is used to produce electric power in nuclear reactors.

We know that a fission reaction has to do with a kind of reaction in which a radioactive nucleus is bombarded by the use of a particle and then there is the disintegration of the atomic nucleus in order to produce energy.

This has been one of the ways by which we can be able to generate electricity in several power plants across the world. The loss in the mass of the reactants is the equivalent of the energy produced.

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Answer:

A regulation game consists of 7 innings unless extended because of a tie score or unless shortened because the home team needs none or only a fraction of its 7th inning or unless 1 team is leading by 10 runs after 5 innings.

Explanation:

Answer:

88N

Explanation:

m = 9kg

a = 9.8m/s²

F = ma = 9 × 9.8

F = 88N

In order for a region to be classified as having a polar climate, the mean temperature of the warmest month must be below 10°C (50°F).

This criterion helps define the extreme cold conditions characteristic of polar regions.

The warmest month's mean temperature being below 10°C is indicative of the persistent cold climate prevailing throughout the year in polar regions. These areas, such as the Arctic and Antarctica, experience long, harsh winters and relatively short, cool summers.

The low temperatures in polar regions can be attributed to several factors. One key factor is the angle of sunlight. Due to the tilt of the Earth's axis, polar regions receive sunlight at a shallow angle, resulting in less intense solar radiation and lower temperatures. Additionally, the presence of ice and snow cover contributes to the cooling effect by reflecting sunlight rather than absorbing it.

The significance of the 10°C threshold lies in the fact that it represents a distinct temperature boundary. Once the mean temperature of the warmest month exceeds this value, the climate transitions from polar to subpolar or even temperate. In these regions, the winters may still be cold, but the summers become notably warmer.

Understanding this threshold helps in classifying and characterizing climates, which is crucial for studying ecosystems, planning human activities, and comprehending the impacts of climate change. The low temperatures and unique environmental conditions in polar regions shape their distinct ecosystems and provide important insights into Earth's climate dynamics.

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Given,

The mass is m=1200kg

Height is h=14 m

Power is P=9kW

We know

Energy per unit time is power.

Thus,

P=mgh/t

where t is the time.

Thus,

The time is 18.312 sec.

The frequency heard by car A is determined as 398.4 Hz.

The frequency heard by car A is determined by applying the following equation.

f = fs(v - v₀) / (v - vs)

where;

f = 395(343 - 19.2) / (343 - 22)

f = 395(1.0087)

f = 398.4 Hz

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Answer:

Explanation:

57.8 m/s

The three considerations diamond discusses as he ponders Yali's question in guns, germs and steel are:

The stage of human social and cultural development and organization that is considered the most advanced is termed as civilization.

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Negative zero error describes the situation in which the vernier caliper's jaws are just closed as well as the reading deviates in the negative direction from the true reading of 0.00 mm.

The dial, digital, layout & spring, and vernier subcategories of calipers are the main ones. External measurements are taken by all four categories. The inside, step, and depth measurements are handled by others. Four-way calipers are also referred as calipers that can measure each type of quantity.

The n-1 divide on the main scale corresponds to the width n division of the graduations on the vernier scale, which is the basis for the vernier calliper. Vernier scales typically have a division count of 10.

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For the particle with the position function r(t) = ⟨\(t^{2}\)+t,\(t^{2}\)−t,\(7t^{3}\)⟩, the velocity is ⟨2t+1,2t-1,\(21t^{2}\)⟩, the acceleration is ⟨2,2,42t⟩, and the speed is √(\((2t+1)^{2}\) + \((2t-1)^{2}\) + \((21t^{2})^{2}\).

To find the velocity, acceleration, and speed of the particle, we need to differentiate the position function with respect to time.

Given the position function r(t) = ⟨\(t^{2}\)+t,\(t^{2}\)−t,\(7t^{3}\)⟩, we can differentiate it to find the velocity function v(t):

v(t) = r'(t) = ⟨2t+1,2t-1,\(21t^{2}\)⟩.

Thus, the velocity of the particle is given by ⟨2t+1,2t-1,\(21t^{2}\)⟩.

To find the acceleration, we differentiate the velocity function v(t):

a(t) = v'(t) = ⟨2,2,42t⟩.

Hence, the acceleration of the particle is ⟨2,2,42t⟩.

Finally, the speed of the particle is the magnitude of the velocity vector, which can be calculated as follows:

speed = √(\((2t+1)^{2}\) + \((2t-1)^{2}\) + \((21t^{2})^{2}\).

Therefore, the velocity of the particle is ⟨2t+1,2t-1,\(21t^{2}\)⟩, the acceleration is ⟨2,2,42t⟩, and the speed is √(\((2t+1)^{2}\) + \((2t-1)^{2}\) + \((21t^{2})^{2}\).

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The information given on the X-axis of the graph attached is the years from 1920-2005 (option B).

A graph in mathematics or statistics is a data chart (graphical representation of data) intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.

A graph consists of two axes namely; X-axis and Y-axis. The x-axis on a graph is usually drawn left to right and usually shows the range of values of an independent variable.

On the other hand, the Y-axis is the axis on a graph that is usually drawn from bottom to top and usually shows the range of values of variable dependent on one other variable.

Therefore, according to the graph illustrated above, the x-axis shows the years from 1920-2005.

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The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979

To find the magnification of the image, we need to use the formula:

magnification = -v/u,

where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979  (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.

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Answer:

a = 30 km / h²

Explanation:

Dado que

Velocidad inicial, u = 70 km / h

Velocidad final, v = 95 km / h

Tiempo, t = 30 s = 0.1 h

Lo sabemos

v = u + a t

a = aceleración

Ahora poniendo los valores en la ecuación anterior

\(95 = 70 + a \ times 0.1 \)

\(a = \ dfrac {95-70} {0.1} = 30 \ km / h ^ 2 \)

Por lo tanto, la aceleración será

a = 30 km / h²