A 472 kg roller coaster is on top of a 12 m high hill. It starts from rest and then goes down the hill. How fast is
it going when it reaches the bottom?

The final velocity of the green ball is 5.0 m/s.

The final speed of the green ball can be determined using the law of conservation of momentum.

The momentum of the system (red and green ball) before the collision is equal to the momentum of the system after the collision, assuming there are no external forces acting on the system.

Before the collision, the momentum of the red ball is given by:

p1 = m1v1 = 0.50 kg   x 10 m/s = 5.0 kg m/s

After the collision, the momentum of the green ball is given by:

p2 = m2  x v2

Using the law of conservation of momentum, we have:

p1 + p2 = (m1 + m2) v1

5.0 kg m/s + p2 = (0.50 kg + 0.50 kg) x 10 m/s

5.0 kg m/s + p2 = 1.0 kg * 10 m/s

5.0 kg m/s + p2 = 10.0 kg m/s

p2 = 10.0 kg m/s - 5.0 kg m/s = 5.0 kg m/s

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Answer:

hellooooo :) ur ans is 33.5 m/s

At time t, the displacement is h/2:

Δy = v₀ t + ½ at²

h/2 = 0 + ½ gt²

h = gt²

At time t+1, the displacement is h.

Δy = v₀ t + ½ at²

h = 0 + ½ g (t + 1)²

h = ½ g (t + 1)²

Set equal and solve for t:

gt² = ½ g (t + 1)²

2t² = (t + 1)²

2t² = t² + 2t + 1

t² − 2t = 1

t² − 2t + 1 = 2

(t − 1)² = 2

t − 1 = ±√2

t = 1 ± √2

Since t > 0, t = 1 + √2.  So t+1 = 2 + √2.

At that time, the speed is:

v = at + v₀

v = g (2 + √2) + 0

v = g (2 + √2)

If g = 9.8 m/s², v = 33.5 m/s.

Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

Answer:

Work transfers energy

Explanation:

Work can affect energy by transfering energy between objects to result to a change in the amount and form of energy

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

1) The velocity of the pin after the collision is 107.4 m/s.

2) The velocity of the two cars as the collision is inelastic is 48.2 m/s.

We know that by the principle of the conservation of linear momentum, the momentum before Collison is equal to the total momentum after collision. Now we have to use this principle in the both questions that we have here.

1) Given that;

Total momentum before collision = Total momentum after collision

(41.7 * 59.1) + (4.17 * 0) = (41.7 * 48.35) + ( 4.17 * v)

We then have;

2464 + 0 = 2016 +  4.17v

2464 - 2016 = 4.17v

v = 2464 - 2016 /4.17

v = 107.4 m/s

2) Given that;

Total momentum before collision = Total momentum after collision

(51.3 * 50.1) + (100 * 47.2) = (100 +  51.3)v

2570 + 4720 = 151.3v

v = 2570 + 4720/151.3

v = 48.2 m/s

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The highest point of a roller coaster is almost always the first hill. In the majority of roller coasters, the hills get smaller as the train travels down the track.

To find the answer, we have to know more about the mechanical energy of a system.

                  Mechanical energy = U = mgh

Where m represents the car mass, g represents gravity, and h represents height

Finally, by applying the principle of energy conservation, we may determine that, the initial hill must be the highest.

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Answer:

C)The mass of the water in the graduated cylinder is equal to the mass of the object.

Explanation:

According to the law of floatation which states that when the volume of a body that is floating is a little bit above the surface of the liquid it is floating in, the volume of the part of the object that is in that liquid is equivalent to the volume of that liquid.

Since Volume is inversely proportional to the mass Therefore, the statement that can be true among them is that The mass of the water in the graduated cylinder is equal to the mass of the object.

Answer:

5.17 x 10^14 1/s

Explanation:

Equation:

c = λ f

c = speed of light

λ = wavelength

f = frequency

Solve:

3.00 x 10^8 m/s = (5.80 x 10^-7m) * f

f = (3.00 x 10^8 m/s) / (5.80 x 10^-7m)

f = 5.17 x 10^14 1/s

Answer:

The gravitational force, or gravity, is the downward force that causes objects to fall towards the surface of a planet or natural satellite. It is computed by multiplying the mass of an object with the acceleration due to gravity of the planet or natural satellite.

Answer:

The minimum force, F, required for the block to just start to move is equal to the force of static friction, f s:

f s = (µ)s x N

where N is the normal force (the force perpendicular to the surface) = m x g = 2.0 kg x 9.8 m/s^2 = 19.6 N

f s = (µ)s x N = 0.50 x 19.6 N = 9.8 N

The force, F, required for the block to continue to move at a constant velocity is equal to the force of kinetic friction, f k:

f k = (µ)k x N = 0.30 x 19.6 N = 5.88 N

If a force is applied greater than the force required for the block to continue to move at a constant velocity, the block will accelerate. If the applied force is greater than the minimum force required for the block to just start to move, the block will begin moving.

Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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Answer:

the answer is 86400seconds.

Explanation:

1day= 24 hours

24hours to seconds =

24×60×60= 86400 seconds.

( 60 second = 1 minutes)

( 60 minutes = 1 hour)

Answer:

A:The dissaperance of a solid stirred in water

The speed of the artillery shell when it hits its target is approximately 118.0 m/s.

The problem is asking for the velocity of the artillery shell when it hits the target. Since it has already been given that the speed of the shell at a height of 100 m is 100 m/s, we can make use of the conservation of energy to find the final velocity.

The total energy of the artillery shell at a height of 100 m above the ground can be given as:

K + U = E(1)where K is the kinetic energy, U is the potential energy, and E is the total energy of the artillery shell.

The kinetic energy of the artillery shell at a height of 100 m is given as:

K = (1/2)mv²

where m is the mass of the artillery shell and v is its velocity at a height of 100 m above the ground.

The potential energy of the artillery shell at a height of 100 m is given as:

U = mgh

where m is the mass of the artillery shell, g is the acceleration due to gravity (taken to be 9.81 m/s²), and h is the height of the artillery shell above the ground (in this case, h = 100 m).

Substituting the values of K and U into Equation (1), we have:

(1/2)mv² + mgh = E

where E is the total energy of the artillery shell.

The total energy of the artillery shell when it hits the target can be given as:

E = K' + U'

where K' is the kinetic energy of the artillery shell just before it hits the target, and U' is its potential energy just before it hits the target.

Since the problem states that there is no air friction, the total energy of the artillery shell is conserved (i.e., E = K + U = K' + U').

Therefore:

(1/2)mv² + mgh = K' + U'(1/2)mv² + mgh = (1/2)mv'² + mgh'(where v' is the velocity of the artillery shell just before it hits the target, and h' is its height just before it hits the target).

Solving for v', we have:

v' = sqrt(v² + 2gh)

Substituting the given values, we get:

v' = sqrt((100 m/s)² + 2(9.81 m/s²)(200 m)) = sqrt(10000 + 3924.4) m/s = sqrt(13924.4) m/s = 118.0 m/s

Therefore, the speed of the artillery shell when it hits its target is approximately 118.0 m/s.

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Answer:

chris i guess

Explanation:

Answer:

Chris

Explanation:

He told Techno to stop being so loud that one time...

\($\begin{aligned} (a) &=1 m^{3} \\ V_{1} &=110 \times 10^{3} \mathrm{~Pa} \\ T_{1} &=15+273=288 \mathrm{~K} \end{aligned}$\)

\($c_{p}=1005 \frac{\mathrm{J}}{\mathrm{kg} K}$\)

\($P_{2}=1400 \times 10^{3} \mathrm{~Pa}$\)

\((i)$$P_{1} V_{1}^{1 / 3}=P_{2} V_{2}^{1 / 3}$$\)

\($\Rightarrow \quad\left(\frac{110}{1400}\right)=\left(\frac{V_{2}}{1}\right)^{\$ 1 \cdot 3} \Rightarrow V_{2}=A \cdot 85 \times 10^{4} / \ln ^{3}$\)

\($\Rightarrow \quad V_{2}=0.1413 \mathrm{~m}^{3}$\)

\($T_{2}=T_{1}\left(\frac{p_{2}}{p_{1}}\right)^{\frac{1 \cdot 3 \cdot 1}{1 \cdot 3}}=$\) \($288\left(\frac{1400}{110}\right)^{\frac{1 \cdot 3-1}{1 \cdot 3}}=518 \mathrm{~K}$\)

\((ii) $W=\frac{P_{1} v_{1}-P_{2} V_{2}}{n-1}=\frac{\left(110 \times 10^{3} \times 1\right)-\left(1400 \times 10^{3}\right)(0.1413)}{1.3-1}$\)

\($\Rightarrow W=-292.73 \mathrm{~kJ}$\)

\((iii) $\quad \Delta U=m C_{V} \Delta T$\)

\($=\frac{p_{1} V_{1}}{p_{1}}\left( R-C_{p}\right) \times\left(T_{2}-T_{1}\right)$\)

\($=\frac{110 \times 10^{3} \times 1(-287+1005)(518-288)}{287 \times 288}$\)

\($\Delta U=219.77 \mathrm{~kJ}$\)

\((iv)$$Q-W=\Delta U$$\)

\($\Rightarrow Q-(-292.73)=219.7 7$\)

\($\Rightarrow Q=-72.96 \mathrm{~kJ}$\)

\($\rightarrow$\) Heat is flowing form surrounding

(b) Since, Tempererature is contant So, change in Internal energy \($\Rightarrow \Delta U=m C_{v} \Delta T^{\circ} \Rightarrow \Delta U=0$\)

What is Internal energy ?

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Explanation:

P=E/T

E=15N

T=2s

P=15/2

P=7.5

There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

Answer:

D

Explanation:

Process of elimnination + it's the only one that makes sense

An object will begin moving from rest when acted upon by forces that are greater in one direction than in any other direction. Hence, Option (D) is correct.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

When  forces that are greater in one direction than in any other direction, resultant will be  unbalanced forces.  Unbalanced forces are those acting on a body when the net force acting on the body is greater than zero. The body alters its state of motion when unbalanced forces act on it.

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Answer:

Mirror used in automobile and trucks for wider area and smaller image is convex mirror.

Answer:

163n

Explanation:

Weight is force due to gravity, weight of object is 980 N

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.

Weight = mass.gravity

Weight = 100*9.8

Weight = 980 N

Weight is force due to gravity, weight of object is 980 N

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(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:

F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N

The acceleration of the train is given by the formula:

a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²

Therefore, the acceleration of the train is 0.3 m/s².

(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:

Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z

(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:

R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N

The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:

a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²

Therefore, the new acceleration of the train is 0 m/s².

(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:

F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N

The force in the coupling between trucks Y and Z is a tension.

When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:

F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N

The force in the coupling between trucks Y and Z is a thrust.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

Your answer is A) 3.33ft/min E

Explanation:

i know this because i know to find the velocity you have to divide distance and time. So for this question your distance=10 and your time=3.

Answer:

19

Explanation:

I legit did this and it took 19.

Answer:

0.33m/\(s^{2}\) East.

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