A 1,000 kg car is moving in a straight line at an acceleration of 9 m/s/s. What is the force on
the car

Answer:

36g

Explanation:

formula;

density=mass/volume

density*volume=mass

3*12=36g

hope this helps :D

Answer:

3.34g/cm

Explanation:

Answer:

i = 0.483 A

Explanation:

B = \(\frac{U.i}{2pi*r}\)

So, here the r is 0.225 m

The Magnetic field is 4.29 x \(10^{-7}\) t

U. = 4π x \(10^{-7}\) x i

4.29 x \(10^{-7}\) = (4π x \(10^{-7}\) x i) / (2π * 0.225)

Cutting  \(10^{-7}\)

4.29 = \(\frac{4π * i}{2π * 0.225}\)

4π and 2π canceled, left with 2

4.29 = \(\frac{2i}{0.225}\)

4.29*0.225 = 2i

0.96525 = 2i

i = \(\frac{0.96525}{2}\)

i = 0.482625 A

Rounding to 3 digits after decimal, we get

∴ i = 0.483 A

Plugging in these values gives an electric field of -1.07 x 10-8 N/C.

Electric field is a physical phenomenon that occurs when an electric charge is present in a space.

The electric field of a -3.2 nC charge from a distance of 6 m can be calculated using the equation E = kQ/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q is the charge of the particle (in this case, -3.2 nC), and r is the distance from the particle (6 m). Plugging in these values gives an electric field of -1.07 x 10-8 N/C.

2. The electric field of a +3.2 nC charge from a distance of 6 m can be calculated using the same equation as in #1, E = kQ/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q is the charge of the particle (in this case, +3.2 nC), and r is the distance from the particle (6 m). Plugging in these values gives an electric field of +1.07 x 10-8 N/C.

3. To find the distance between two +3.4 μC particles that experience a force of 0.01 C/m, we can use the equation F = kQ1Q2/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q1 and Q2 are the charges of the two particles (in this case, +3.4 μC each), and r is the distance between them. Plugging in these values gives a distance of 5.81 m.

4. To find the distance between two -6 μC particles that experience a force of 0.03 C/m, we can use the same equation as in #3, F = kQ1Q2/r2, where k is Coulomb's constant (8.99x109 Nm2/C2), Q1 and Q2 are the charges of the two particles (in this case, -6 μC each), and r is the distance between them. Plugging in these values gives a distance of 1.31 m.

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The plane was flying at 39.6 m/s when the bottle was released .

\(h = ut + 1/2at^2\)

distance fallen h= 500m

Initial velocity u=0

a=98 m/s2

\(h = 1/2at^2\)

\(t^2 = 2h/a\)

\(t^2 = 1000/9.8 = 10.1s\)

\(d_h = 400, t = 10.1s\)

\(v = d_h/t\\v = 400/10.1\)

v = 39.6 m/s

Altitude or Height  (also known as depth) is a measurement of the distance between a reference point and a point or object, usually in a vertical or "upward" direction. The exact definition and reference value varies depending on the context (eg, aeronautics, geometry, geodesy, sports, or barometric pressure). Although the term height is often used to refer to the height of a place above sea level, in geography the term height is often preferred for this use.

The vertical measurement of distance in the "down" direction is usually called depth.

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Answer:

ok?

Explanation:

Answer:

B) the surface has a high coefficient of friction

When an object is not moving despite an applied force, it means that the frictional force is equal to or greater than the applied force. A high coefficient of friction indicates that the frictional force is strong, making it difficult to move the object. In this case, the frictional force is equal to the 100 N of force that Devon is applying, so the coefficient of friction for the surface must be high.

Answer:

Explanation:

The wording on some of these choices is very strange; I'm not sure exactly what they are stating. First of all, A. is definitely a choice because if both the charges were opposite, they would be attracted to one another as opposed to be repelled away from one another, as they are when they are both positive. What happens is that the charges go OUT from the positive charge and INTO the negative; so as far as the field lines around both charges would change direction...no; only the direction of the field lines would change on the positive charge (which is the one on the left). In that space where D is filled in by the field lines going OUT of the positive charge and INTO the negative one, the lines there are naturally closer together, and that is the point where the charge is the greatest. So if that is what is meant by the field lines getting closer together, then yes, they do. As far as choice D. again the field lines on the negative charge don't change, only the ones on the positive charge change.

The arrows on the field lines surrounding the negative charge would need to point toward instead of away from the charge.

These pattern of lines, sometimes referred to as electric field lines, point in the direction that a positive test charge would accelerate if placed upon the line. As such, the lines are directed away from positively charged source charges and toward negatively charged source charges.

“ When an object has more electrons than protons then the object is said to be negatively charged.”

“When an object has more protons than electrons, the object is said to be positively charged.”

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Answer:

A) 5 × 1011nm

I think It's A

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

\(v = f\lambda\)

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

v = 30 m/s

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

v = 5 m/s

3.

v = 20 m/s

λ = 0.5 m

\(f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}\)

f = 40 Hz

4.

v = 80 m/s

λ = 0.2 m

\(f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}\)

f = 400 Hz

5.

v = 120 m/s

λ = 0.4 m

\(f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}\)

f = 300 Hz

6.

v = 340 m/s

f = 440 Hz

\(\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\\)

λ = 0.772 m

7.

v = 340 m/s

f = 880 Hz

\(\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\\)

λ = 0.386 m

8.

v = 250 m/s

f = 400 Hz

\(\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\\)

λ = 0.625 m

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

v = 100 m/s

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

v = 50 m/s

Answer:

it B

Explanation:

I KNOW IT

Therefore, to rank the potential energies from largest to smallest, we need to rank the distances from smallest to largest: d1, d2, d3, d4.

The potential energy between two charges depends on their magnitudes and the distance between them.

When charges have the same magnitude, the potential energy between them is directly proportional to the square of the distance between them.
To rank the potential energies from largest to smallest, we need to consider the distances between the charges.

Let's label the pairs of charges as (a, b), (c, d), (e, f), and (g, h). Since each symbol represents the same amount of charge, we can assume that the magnitudes of the charges are equal in each pair.

Now, let's compare the distances between the charges:

- Pair (a, b): Let's say the distance between a and b is d1.
- Pair (c, d): Let's say the distance between c and d is d2.
- Pair (e, f): Let's say the distance between e and f is d3.
- Pair (g, h): Let's say the distance between g and h is d4.

The potential energy between charges decreases as the distance between them increases. So, the potential energy is highest for the pair with the smallest distance and lowest for the pair with the largest distance.

Therefore, to rank the potential energies from largest to smallest, we need to rank the distances from smallest to largest: d1, d2, d3, d4.

After ordering the distances, we can conclude that the potential energies will be ordered accordingly. So, the largest potential energy corresponds to the pair with the smallest distance, and the smallest potential energy corresponds to the pair with the largest distance.

Please note that the specific values of the distances are not given, so we cannot provide an exact ranking. However, with the given information, you can conclude that the potential energy will be largest for the pair with the smallest distance and smallest for the pair with the largest distance.

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Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

\(d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m\)

Next, you calculate the wavelength of the sound waves by using the following formula:

\(\lambda=\frac{v_s}{f}\)

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

\(\lambda=\frac{343m/s}{400Hz}=0.8575m\)

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\(\Delta d=3.827m-2.10m=1.727m\)

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\(\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2\)

Then, there will be a constructive interference, and the sound who the observer hears is loud.

When a spherical shell completely filled with a frictionless fluid is released from rest and rolls without slipping down an incline, the acceleration of the shell can be determined by considering the forces.

The acceleration of the shell down the incline can be found by considering the net force acting on it. The forces involved include the gravitational force and the force due to the fluid. The gravitational force can be decomposed into two components: one parallel to the incline (mg sinθ) and one perpendicular to the incline (mg cosθ), where m is the total mass of the shell and fluid, and θ is the angle of the incline.

The force due to the fluid exerts a torque on the shell, causing it to roll without slipping. This force depends on the mass of the fluid and the radius of the shell. The net force can be calculated by subtracting the force due to the fluid from the gravitational force component parallel to the incline: Fnet = mg sinθ - (2/5)mr^2 α, where r is the radius of the shell, and α is the angular acceleration.

Since the shell rolls without slipping, the relationship between linear and angular acceleration is given by α = a/r, where a is the linear acceleration of the shell. By substituting α = a/r into the net force equation, we can solve for the acceleration: a = (5/7)g sinθ.

Therefore, the acceleration of the shell down the incline just after it is released is given by a = (5/7)g sinθ, where g is the acceleration due to gravity and θ is the angle of the incline.

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Answer: y = yo + Vyot + ayt = =2ay y− yo . 5. vy. 2. −voy. 2. =−2 g y− yo

Explanation: since both the displacement and acceleration are negative, they cancel each other when divided, so the result is positive. ... As you can see, as the height displacement (height) increases, the longer it takes for the robocopter to fall.  

Answer:

If it is pure, the substance is either an element or a compound. If a substance can be separated into its elements, it is a compound. If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. If its composition is uniform throughout, it is a homogeneous mixture.

Explanation:

The Big Bang is still visible today due to the Cosmic Microwave Background (CMB) radiation, which is a form of electromagnetic radiation left over from the Big Bang.

This radiation was detected in the 1960s by two American astronomers, Arno Penzias and Robert Wilson. Due to its low intensity, the CMB was only detectable with the help of very sensitive radio telescopes.

The CMB radiation has an extremely uniform temperature of about 2.7 degrees above absolute zero, and it has a slight variations in temperature across the sky, which provides evidence of the Big Bang.

These variations are thought to be the seeds of the galaxies and other cosmic structures that form the universe today.

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Answer:

4.0208 x 10^16 meters

Explanation:

speed of light in m/s   *      # seconds in a year      * 4.25 years =

2.99792 x 10^8   *        3600*24*365.25  *     4.25 = 4.0208 x 10^16 m

Wave a carries more energy than wave b. Wave b has a smaller amplitude than wave a.

Those waves carry an amount of energy that can be measured. The energy in a wave is determined by two variables. One is amplitude, which is the distance from the rest position of a wave to the top or bottom. Large amplitude waves contain more energy. Wave A has greater intensity and transfers more energy. Wave B has greater intensity and transfers more energy. Waves that require matter to transfer energy are mechanical waves. The matter through which a mechanical wave travels is called a medium. A mechanical wave travels as energy is transferred from particle to particle in the medium. There are two kinds of mechanical waves. The greater the amplitude of the wave the greater the wave's energy. ... A wavelength will travel only as long as it has the energy to carry. Gamma rays

Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies. Radio waves, on the other hand, have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. Electromagnetic waves cause oscillations in electrical and magnetic fields. It is important to remember that all waves transfer energy but they do not transfer matter. For example, if a ball is placed on the surface of a pond when ripples move across it, the ball will move up and down but not outwards with the wave.

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To calculate the gradient of the stream, we need to determine the change in elevation per unit of horizontal distance.

In this case, the stream drops 45 meters over a horizontal distance of 15 kilometers. To find the gradient, we divide the vertical drop (45 meters) by the horizontal distance (15 kilometers). However, to ensure consistent units, we convert the 15 kilometers to meters by multiplying it by 1,000 (since there are 1,000 meters in a kilometer).

So, the calculation becomes:

Gradient = Vertical drop / Horizontal distance

        = 45 meters / (15,000 meters)

        = 0.003 meters per meter

This means that for every meter of horizontal distance, the stream drops by 0.003 meters vertically. Simplifying the expression, we can also express it as 3 millimeters (mm) per meter.

Therefore, the correct answer is d) 0.003 meters per kilometer.

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Answer:

The locus of points where the electric field due to these lines is zero is;

Along the line between the lines closer to line#1 than line #2

Explanation:

The charges on the parallel lines #1 and #2 = Positive linear charge

The charge density on line #2, λ₂ = 2 × The charge density on line #1, λ₁

Therefore, we have;

λ₂ = 2 ×  λ₁

Electric field strength, E, is given as follows;

\(E = \dfrac{\lambda}{2\cdot \pi\cdot \epsilon_0\cdot d}\)

Therefore;

\(E_1 = \dfrac{\lambda_1}{2\cdot \pi\cdot \epsilon_0\cdot d}\)

\(E_2 = \dfrac{\lambda_2}{2\cdot \pi\cdot \epsilon_0\cdot d} = 2 \times\dfrac{\lambda_1}{2\cdot \pi\cdot \epsilon_0\cdot d}\)

E₂ = 2·E₁

E₂/2 = E₁

E₂/(2·d) = E₁/d

The strength of the electric field at a given distance from line #2 is 2 times the strength of the electric field from line #1 at the same distance

Therefore the strength of the electric field will be the same at a point twice the distance from line #2 than from line #1 which is a point closer to line #1 than line #2.

To determine the distance spanned by the diffraction spot, we need to consider the properties of the diffraction pattern and the given information.

Given:

- The screen is 30 cm behind the fish.

- The entire path of the laser, including the water and tissue, has an index of refraction close to that of water.

- The properties of the diffraction pattern are determined by the wavelength in water.

Since the diffraction pattern is formed by the interaction of light waves with obstacles or apertures, the spot's size or spread depends on factors such as the wavelength of light and the size of the aperture.

Without specific information about the wavelength or aperture size, it is not possible to determine the exact distance spanned by the diffraction spot. Additional details regarding the specific setup or measurements would be necessary to calculate or estimate the distance spanned by the diffraction spot.

Please provide further information or clarify the parameters related to the diffraction setup if you require a more specific answer.

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Given the amount of work done in pushing the car over the given distance, the amount of force applied is 2400 Newtons.

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where f is force applied and d is distance travelled.

Given that;

W = F × d

60000kgm²/s² = F × 25m

F = 60000kgm²/s² ÷ 25m

F = 2400kgm/s²

F = 2400N

Given the amount of work done in pushing the car over the given distance, the amount of force applied is 2400 Newtons.

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The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

If the given turbine is assumed to be reversible;

\(\rm P_I\)(Initial pressure)=60 mpa = 60 bar

\(\rm T_i\)(Initial temperature)=600° C

\(\rm P_e\) (Exit pressure)=600 kpa=6 bar

The heat balance equation is;

\(\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e\)

The change in the entropy is;

\(\rm S_2-S_1=\frac{\delta q}{dt}\)

The work done by the turbine is;

\(\rm W_t = h_i-h_e\\\\ W_t =3658.4 -29.5019\\\\ W_t =708.2 \ kJ/kg\)

Hence,the work done by the turbine will be 708.2 kJ/kg.

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Answer: T₂ ≈ 246.7 °C, Wout ≈ 708.2 kJ/kg

Explanation:

The "expert verified answer" is blatantly incorrect and incomplete, I have no idea how Brainly keeps getting away with this.

I am assuming this is a reversible adiabatic system, s₂=s₁.

Looking up s₁ in thermodynamic table B.1.2 at 6Mpa & 600°C:

s₂=s₁=7.1676

We'll use the NKEPE turbine equation:

Wout = h₁-h₂

For this equation we'll need h₁ from the same table:

h₁=3658.4

Using the same table at 600kPa, interpolate T₂ using the value of s we previously determined:

T₂= 246.7 °C

Using the same table at 600kPa, interpolate h₂ using either T₂ or s₂:

h₂≈2950.1931

Back to the aforementioned equation:

Wout = h₁-h₂

Wout ≈ 3658.4-2950.1931

Wout ≈ 708.2 kJ/kg

The velocity of the roller coaster at the top of the second hill is 24.25 m/s.

Velocity is the rate of change of displacement. The s.i unit is m/s

To calculate the velocity of the coaster car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Solve for v

Hence, The velocity of the roller coaster at the top of the second hill is 24.25 m/s.

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The notch sensitivity and fatigue stress concentration factors for the bar are calculated to determine the mean and alternating stresses and find the fatigue strength for different cycles.

To calculate the notch sensitivity and fatigue stress concentration factors, we need to consider the presence of the 10 mm hole in the center of the 30 mm side of the bar. The notch sensitivity factor quantifies the effect of the hole on the stress concentration, while the fatigue stress concentration factor determines the increase in stress due to cyclic loading.

The mean stress (σm) is the average of the minimum (F_min) and maximum (F_max) axial loads applied to the bar. The alternating stress (σa) is half the difference between F_max and F_min.

The fatigue strength for a certain number of cycles is determined by applying the appropriate factors to the ultimate tensile strength (S_Ut) or yield strength (S_y) of the material. The fatigue strength is typically given for a specified number of cycles, such as 100, 10,000, 100,000, or 1,000,000 cycles. The fatigue strength for infinite life refers to the stress level below which the material can withstand an unlimited number of cycles without failure.

To provide accurate values for the notch sensitivity, fatigue stress concentration factors, mean and alternating stresses, and fatigue strength for the specified number of cycles, further calculations and data specific to the material properties and geometry of the bar are required.

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According to the Theory of Continental Drift, we can predict that:

Continental Drift can be defined as a hypothesis that was put forth, that the Earth's continents have moved over  time relative to each other and as the time goes its keeps on moving, increasing the distance between them.

Continental Drift makes the continents look like they have drifted across the ocean.

In conclusion, Our predictions are stated above.

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The amount of work done by a box that is pushed 9 meters across a horizontal floor by a force of 3000N is 27000J.

Work in physics refers to the measure of energy expended in moving an object; most commonly, force times distance.

It is said that no work is done if the object does not move. The work done on an object can be calculated by multiplying the force of the object by its distance as follows:

W = F × d

W = 3000N × 9m

Work done = 27,000J

Therefore, 27,000Joules is the work done on the box.

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Answer:

A. 290,400

Explanation:

The kinetic energy of a car is 290,400J.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2.

ke = 1/2mv^2

By using the formula, we get

= 1/2 * 1200 * 22^2

= 600 * 484

= 290,400 J

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

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Newton's Third Law states that for every action there is an opposite and equal reaction:

If the gravitational force of the Earth on the Moon is F then the gravitational force of the Moon on the Earth is also F

If the magnitude of the gravitational force of Earth on the Moon is F, the magnitude of the gravitational force of the Moon on Earth is equal to F. The correct option is 3.

Gravity, also known as gravitational force, pulls objects with mass toward each other. We frequently consider the force of gravity from Earth.

This force is responsible for keeping your body on the ground. Any object with mass, on the other hand, exerts a gravitational force on all other objects with mass.

The magnitude of the Moon's gravitational force on Earth is calculated using Newton's third law of motion.

Newton's third law of motion states that there is an equal and opposite reaction to every action. That is, the Earth's force on the moon is equal to the moon's force on Earth, but in the opposite direction.

Thus, the correct option is 3.

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