7. Research one major corporate scandal that has happened in the past 10 years
(Enron, World Com, AIG, etc). List the major players, what the scandal was
about, and what the outcome was. How do you think these compare to what
happened to Tucker? Do you think this was as big a scandal in his day as the
scandal you chose?
public opinion of him

The measure of the chord-chord angle is 175.5.

A circle's chord is the line segment that connects any two locations on the circle's circumference. It should be remembered that a circle's diameter is defined as the lengthiest chord that runs across the center of the circle.

An angle is a figure created by two rays or lines that have the same termination in plane geometry. The Latin word "angulus," which meaning "corner," is where the term "angle" originates. The common terminal of the two rays—known as the vertex—is referred to as an angle's sides.

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Answer:

Because fluid pressure increases with depth, there is more fluid pressure___outside__ of a submerged object than on the _inside___

Explanation:

As the object is submerged means that it is under water and not on the surface. It tells that water pressure exerting on the object from the outside is higher than inside which is why the object is submerged.

In the other case, the object will not remain submerged if its internal pressure is high, it will float on water.

The maximum current if this inductor is connected to a 50.0 hertz source that produces a 105 v rms voltage is 3.87A

X= ωl

where,

X is inductive reactance

ω is thee angular  frequency

L is the inductance

therefore,

46= 2π60.L                   eq-1

and

X° is inductive reactance when 50 hz source is used

X°=2π50.L                    eq-2

dividing eq 2 by eq 1 we get

X°=38.33 Ω

maximum current (I°) = maximum voltage divided by  inductive reactance

I°=√2Vrms/38.33

I°=3.87A

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The variable resistance that will give 12 seconds from the start of a cycle to a pass of the wipers is, 3.11 ×10⁵ Ω.

A capacitor is a passive device used charge for storing the charge when connected in the circuit, whereas a resistor is a device that creates obstruction in the movement of charges. When both are connected in a single circuit, it is known as RC circuit.

The expression for the instantaneous potential across the capacitor is given as,

V = V₀(1 - \(e^{-\dfrac{t}{RC}}\))

The expression for the voltage using voltage divider rule is given as,

V₁ = \(\dfrac{VR_2}{R_1 + R_2}\)            (2)

Substituting the values in equation 2,

V₁ = \(\dfrac{12 \times 47 \times 10^3}{100 \times 10^3 + 47 \times 10^3}\)

V₁ = 564000/147000

V₁ = 3.83 V

Since,

Va = Vb

The potential across  47 kΩ resistor is equal to potential across capacitor.

Substituting the values in equation 1,

3.83 = 12(1 - \(e^{-\dfrac{t}{RC}}\))

\(e^{-\dfrac{t}{RC}}\) = 0.680

Further solving,

−12/RC = ln(0.680)

RC= 31.11

Substituting the values in above expression,

R = 31.11 / 100 × 10^−6

R = 3.11 × 10 5 Ω

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--The complete question is, Intermittent windshield wipers use a variable resistor in an RC circuit to set the delay between successive passes of the wipers. When the switch closes, the capacitor (initially uncharged) begins to charge and the potential at point b begins to increase. A sensor measures the potential difference between points a and b, triggering a pass of the wipers when Vb = Va. (Another part of the circuit, not shown discharges the capacitor at this time so that the cycle can start again.) What value of the variable resistor will give 12 seconds from the start of a cycle to a pass of the wipers?--

Here's the neat, cool way to convert units like this:

-- 1 kilogram  =  1,000 grams

-- 1 meter  =  100 centimeters

So . . . . .

(1000 kg/m³) x (1000 g/kg) x (1 m/100 cm)³ =

(1,000 kg/m³) x (1,000 g/kg) x (1 m³/1,000,000 cm³) =

(1,000 x 1,000 x 1 / 1,000,000) (kg-g-m³ / m³-kg-cm³)  =  1 g/cm³

B. The best classification for fossilized burrows dug by ancient clams is Trace Fossils.

A trace fossil, is a type of fossil record of biological activity but not the preserved remains of the plant or animal itself.

Some of trace fossils include the following;

Thus, the best classification for fossilized burrows dug by ancient clams is Trace Fossils.

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The correct reaction type for the above chemical equation is decomposition reaction.

A decomposition reaction is the splitting (of e.g. a matrix, an atom or a compound) into constituent parts.

Decomposition reactions are processes in which chemical species (reactant) break up into simpler parts (products). Usually, decomposition reactions require energy input.

The general reaction template of a decomposition reaction is as follows:

AB → A + B

Where;

According to this question, pottasium chloride decomposes into pottasium element and chlorine molecule as follows:

2KCl → 2K+ Cl₂

Therefore, the chemical reaction above is exemplary of a decomposition reaction.

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Answer:

t = 2.01 seconds

Explanation:

It is given that,

The acceleration of the elevator is 4.55 m/s².

We need to find time taken by you to reach a speed of 11 m/s

The initial velocity of the person is equal to 0 (at rest). Let t is the time.

Using equation of kinematics as follows :

v = u +at

Acceleration = g-a and u = 0

So,

\(t=\dfrac{v}{g-a}\\\\t=\dfrac{11}{10-4.55}\\\\t=2.01\ s\)

So, 2.01 seconds is taken to reach a speed of 11 m/s.

Answer:

Explanation:

Compared to a coastal location of the same elevation and latitude, an inland location is likely to have **cooler summers and warmer winters** . Coastal climates tend to have wetter winters and drier summers, whereas inland climates have more humid summers and drier winters . Coastal climates are typically limited to narrow strips along the edges of continents, whereas inland climates tend to occur over broad swaths of continental interiors .

I hope this helps answer your question!

Answer:

a.  653.79 kgm²/s b. 440 Nm

Explanation:

a. The initial angular momentum

The initial angular momentum L of the boy and merry-go-round is

L = Iω where I = moment of inertia of merry-go-round + moment of inertia of Lindsey about merry-go-round and ω = initial angular velocity = 3.45 rad/s

moment of inertia of merry-go-round I₁ = 1/2MR² where M = mass of merry-go-round = 78 kg and R = radius of merry-go-round = 2.20 m

I₁ = 1/2MR² = 1/2 × 78 kg ×(2.20 m)² = 188.76 kgm²

moment of inertia of Lindsey about merry-go-round I₂ = mh² where m = mass of boy = 33.0 kg and h = distance of Lindsey from center of merry-go-round = 0.150 m

I₂ = mh² = 33.0 kg × (0.150 m)² = 0.743 kgm²

I = I₁ + I₂ = 188.76 kgm² + 0.743 kgm² = 189.503 kgm²

So, L = Iω = 189.503 kgm² × 3.45 rad/s = 653.79 kgm²/s

b. How much torque does Mike apply?

Since torque τ = FRsinθ where F = force = 200 N, R = radius of merry-go-round = 2.20 m and θ = 90° (since the force is applied tangentially to the merry-go-round)

τ = FRcosθ

= 200 N × 2.20 m × sin90°

= 440 Nm

When an electron is moved from point A to point B, the potential energy of the system increases by 3 eV. The voltage VBA is -3 V.

To find the voltage VBA, follow these steps:

1. Recall that voltage is defined as the electric potential energy difference per unit charge.
2. Use the formula V = ΔE / q, where V is the voltage, ΔE is the change in electric potential energy, and q is the charge of the electron.
3. The change in electric potential energy (ΔE) is given as 3 eV.
4. The charge of an electron (q) is -1.6 x 10^(-19) C.
5. Substitute these values into the formula: V = (3 eV) / (-1.6 x 10^(-19) C).

Before solving, note that 1 eV = 1.6 x 10^(-19) J. So, we have:

V = (3 x 1.6 x 10^(-19) J) / (-1.6 x 10^(-19) C)
V = (3 / -1) V
V = -3 V

The voltage VBA is -3 V, which corresponds to answer choice (c).

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Answer:

\(30 \div 33750 = 0.008888\)

An object has a speed of 3.5 m/s and kinetic energy of 14 J at t = 0, then (a) the mass of the object is 2.2857kg (b) At t = 5.0 s the object has a speed of 4.7 m/s. then the kinetic energy is 25.2457J. (C) work done by the object is 11.2457J.

When a body of mass m is moving with a velocity v, Then the kinetic energy of the body is given by.

KE=1/2 mv²

given question.

At t=0

velocity u=3.5m/s

KE =14J

and at t=5s

v=4.7m/s

(A)

Then the mass of the body is

m= 2KE/u²=2×14/3.5²

m=2.2857kg.

(B)

The kinetic energy of the object at t= 5.0 s

KE=1/2mv²=1/2×2.2857×4.7²

KE (at t=5s) =25.2457J

(C)

Work was done on the object between t = 0 and

t = 5.0 s

W= 1/2 mv² -1/2/ mu²

W=25.2457-14

W=11.2457J

Hence the mass of the body is m=2.2857kg, The kinetic energy of the object at t= 5.0s, is KE =25.2457J, and the Work done on the object is W=11.2457J.

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Answer:

Emperor penguins are near the top of the Southern Ocean’s food chain. They have a varied menu that changes with the season. Some prey items are more important than others. One of the most frequently eaten prey species is the Antarctic silverfish Pleuragramma antarcticum. They also eat other fish, Antarctic krill and some species of squid. Most prey items are small. Since they are very cold when ingested, their small size makes it easier to bring food up to body temperature to digest it.

Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :

Step 1: Calculate the velocity using the equation:

\(v = u + at\)

where:

- \(v\) is the final velocity

- \(u\) is the initial velocity (0 m/s, as the car starts from rest)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)

Step 2: Calculate the distance traveled using the equation:

\(s = ut + \frac{1}{2}at^2\)

where:

- \(s\) is the distance traveled

- \(u\) is the initial velocity (0 m/s)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)

Now, let's simplify these equations:

\(v = 3 \times 50\)

\(s = \frac{1}{2} \times 3 \times 50^2\)

Calculating the results:

\(v = 150\) m/s

\(s = 3750\) meters

Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.

The volume of the rectangular prism is 480 cubic centimeters.

The question asks us to find the volume of a rectangular prism with dimensions 12 cm by 8 cm by 5 cm. A rectangular prism is a 3-dimensional shape with six rectangular faces, where opposite faces are congruent and parallel.

To find the volume of a rectangular prism, we use the formula:

Volume = length x width x height

In this case, the length is 12 cm, the width is 8 cm, and the height is 5 cm. So, we substitute these values into the formula:

Volume = 12 cm x 8 cm x 5 cm

Volume = 480 cubic centimeters

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From the calculations, we have the coefficient of friction as  0.026.

We know that friction has to do with the force that tends to oppose the motion of an object. As such, the point where the force of friction acts is actually the surface that lies between two bodies.

Now, we can see that It takes 6 people pulling with a force of 500 N each to begin moving the opposing team which was pulling with a combined force of 2500 N. This implies that the total force of the people that are pulling from this other side is 6 (500N) = 3000 N

Now we have the net force that is acting on the the rope as; 3000 N - 2500 N = 500 N

Then;

Coefficient of friction = Net force/ Normal reaction

= 500 N/(2000 * 9.8) N

= 0.026

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Answer:

the three are scavengers predators and decomposers

Explanation:

The three biotic factors that can affect an organism after death are scavengers, predators, and decomposers that can breakdown and destroy the organism. an abiotic factor that can prevent the organism from becoming preserved after it has been buried would be groundwater.

In a typical internal combustion engine, such as those found in most automobiles, energy is wasted in a number of ways:

1. Thermal Energy: The majority of the energy from the combustion process is lost as heat through the exhaust. This is because the combustion process is far from perfectly efficient.

2. Mechanical Energy: Some energy is lost through mechanical inefficiencies in the engine itself, such as friction between moving parts.

3. Pumping Losses: Engines lose energy through the work required to pump air and fuel into the cylinders and push out the exhaust gases.

4. Radiated Energy: Some energy is lost through heat radiated from the engine block itself, particularly when the engine is running hot.

5. Idle Losses: When the engine is running but the vehicle is not moving (idling), all of the energy being used by the engine is essentially wasted.

6. Accessory Load: Energy is used to power the various accessories in a vehicle, such as the alternator, power steering pump, air conditioning compressor, etc. While these are necessary for the operation of the vehicle, they do represent a form of energy loss in terms of the overall efficiency of the engine.

7. Incomplete Combustion: Not all of the fuel that enters the engine's combustion chamber is burned. Some is expelled as unburned hydrocarbons, which is not only a waste of energy but also a source of pollution.

8. Transmission Losses: Some energy is lost in the transmission as the power is transferred from the engine to the wheels.

It's important to note that these are inherent to the design of internal combustion engines, and while engineers continually work on improving the efficiency of these engines, these forms of energy loss are difficult to completely eliminate.

a. The probability that a randomly selected soda can has a volume less than 12 fluid ounces is approximately 0.3085

b. The probability that the sample mean volume is less than 12 fluid ounces, when a sample of size n = 32 is taken, is approximately 0.0023

c. The distribution of the sample mean becomes narrower and more concentrated around the population mean. Consequently, the probability of obtaining a sample mean less than 12 fluid ounces decreases because the sample mean is less likely to deviate significantly from the population mean.

a) Let X be the volume of a randomly selected soda can. We are given that the mean (μ) is 12.01 fluid ounces and the standard deviation (σ) is 0.02 fluid ounces.

We need to calculate P(X < 12). To do this, we standardize the variable using the z-score formula:

z = (X - μ) / σ

Substituting the given values, we have:

z = (12 - 12.01) / 0.02

= -0.5

Now, we can use a standard normal distribution table or calculator to find the probability associated with the z-score of -0.5. From the table, we find that the probability is approximately 0.3085.

b) When a sample of size n = 32 soda cans is drawn randomly from the population, the mean volume of the sample (denoted by X-bar) follows a normal distribution with the same mean (μ = 12.01 fluid ounces) but a smaller standard deviation (σ-bar) given by:

σ-bar = σ / sqrt(n)

Substituting the values, we have:

σ-bar = \(0.02 / \sqrt{(32)\)

= 0.02 / 5.6569

≈ 0.00354

Now, we need to calculate P(X-bar < 12). Again, we standardize the variable using the z-score formula:

z = (X-bar - μ) / σ-bar

Substituting the given values, we have:

z = (12 - 12.01) / 0.00354

≈ -2.8249

Using the standard normal distribution table or calculator, we find that the probability associated with the z-score of -2.8249 is approximately 0.0023.

c) As larger and larger sample sizes are taken, the probability that the sample mean volume is less than 12 fluid ounces tends to decrease. This is because as the sample size increases, the sample mean becomes a better estimate of the population mean. The larger the sample size, the more reliable and representative the sample mean is of the true mean. Hence, the sample mean is more likely to be closer to the population mean.

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The displacement over the time interval [0, 10] is -130 meters, and the distance traveled is 130 meters.To find the displacement and distance traveled over the time interval [0, 10] for the particle with velocity v(t) = 3t^2 - 30t + 63, we need to integrate the velocity function.

The displacement is given by the definite integral of the velocity function over the interval [0, 10]:

Displacement = ∫[0, 10] (3t^2 - 30t + 63) dt

To calculate this integral, we need to find the antiderivative of the velocity function. Taking the antiderivative of each term, we get:

Displacement = t^3 - 15t^2 + 63t | [0, 10]

Now we substitute the upper and lower limits of integration:

Displacement = (10^3 - 15(10)^2 + 63(10)) - (0^3 - 15(0)^2 + 63(0))

Simplifying the expression:

Displacement = (1000 - 1500 + 630) - (0 - 0 + 0)

Displacement = -130 meters

The displacement over the time interval [0, 10] is -130 meters.

To find the distance traveled, we take the integral of the absolute value of the velocity function over the interval [0, 10]:

Distance = ∫[0, 10] |3t^2 - 30t + 63| dt

This involves evaluating the integral separately for the positive and negative parts of the velocity function. However, since the velocity function is always positive over the interval [0, 10], the distance traveled is equal to the displacement, which is 130 meters.

Therefore, the displacement over the time interval [0, 10] is -130 meters, and the distance traveled is 130 meters.

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Answer:

it must move back and forth during sex

The area of the triangle in this coordinate plane with vertices at (0, 0), (4, 0), and (0, 7) is 14 units².

To find the area of a triangle in a coordinate plane, we can use the formula:

Area = 0.5 * base * height

In this case, the base is the distance between the points (0, 0) and (4, 0), which is 4 units. The height is the distance between the point (0, 0) and the line containing the point (0, 7).

The line containing the point (0, 7) is vertical and parallel to the y-axis, so the height is simply the y-coordinate of the point (0, 7), which is 7 units.

Plugging these values into the formula, we have:

Area = 0.5 * 4 * 7

= 14 units²

Therefore, the area of the triangle is 14 units².

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--The complete Question is, Consider a triangle in a coordinate plane with vertices at (0, 0), (4, 0), and (0, 7). What is the area of the triangle? --

Sounds are produced by vibrations.

Sounds are produced by vibration.

Hope it helps! byeeee

Answer:

\(I_2=0.8586A\)

Explanation:

From the question we are told that:

Turns Ratio i.e\(\frac{N_2}{N_1}=\frac{1}{106} (step down)\)

Voltage \(v=170v\)

Primary current amplitude\(I_1= 8.10 mA =>8.10*10^{-3}A\)

Generally the equation for a Transformer is mathematically given by

\(\frac{E_1}{E_2}=\frac{I_2}{I_1}=\frac{N_1}{N_2}\)

Therefore

\(I_2=\frac{N_1}{N_2}*I_1\)

\(I_2=106*8.10*10^{-3}\)

\(I_2=0.8586A\)

Using the equation for height in free fall, the height of the building is approximately 14.7499 meters.

To find the height of the building, we can use the equations of motion for an object in free fall. The equation we'll use is:

h = (1/2) × g × t²

Where:

h = Height of the building

g = Acceleration due to gravity (approximately 9.8 m/s^2)

t = Time is taken for the brick to strike the ground

Given that the time taken (t) is 1.69 seconds, we can substitute the values:

h = (1/2) × 9.8 m/s² × (1.69 s)²

h = 0.5 × 9.8 m/s² × (1.69 s)²

h = 0.5 × 9.8 m/s² × 2.8561 s²

h = 14.7499 m

Therefore, the height of the building is approximately 14.7499 meters.

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