50 Points
Atoms contain subatomic particles called protons and neutrons. When these protons and neutrons split, a lot of energy is released.

What kind of energy is this?

nuclear
radiant
thermal
chemical

The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. The frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. However, for the photoelectric effect to occur, the frequency of the incident light must be above a certain threshold frequency.

The threshold frequency is the minimum frequency of light required to dislodge electrons from the material. Below this threshold frequency, regardless of the intensity or duration of the light, no electrons will be emitted.

This behavior can be explained by the particle-like nature of light, where light is composed of discrete packets of energy called photons. The energy of a photon is directly proportional to its frequency. Only photons with energy greater than or equal to the binding energy of the electrons in the material can dislodge them.

Therefore, the frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

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Answer:

giant covalent structures

Explanation:

Covalent solids are made up of atoms joined to one another by covalent bonds to form a giant lattice. The covalent bonds are very strong, this makes the giant covalent solids to be hard and possess high melting points. Covalent solids are nonconductors of electricity due to the absence of free electrons in the structure.

Diamond, graphite and boron nitride are all examples of giant covalent structures.

Answer:

its number 3 trust me

Explanation:

Answer:

Lithosphere

Explanation:

The lithosphere is the solid, outer part of the Earth. The lithosphere includes the brittle upper portion of the mantle and the crust, the outermost layers of Earth's structure. It is bounded by the atmosphere above and the asthenosphere (another part of the upper mantle) below.

MARK ME AS BRAINLIEST PLS

The value of the equilibrium constant shows the relative amounts or concentrations of the reactants and products.

Answer:

The horizontal axis represents years and the vertical axis represents units of sales. The graph presents both the increase and decline in sales for both products, as sales fluctuated during the ten-year period.

Explanation:

The final temperature of the mixture given that 25 g of water at 25 °C is mixed with 25 g of water at 65 °C, is 45 °C

The final temperature of the mixture can be obtained by calculating the equilibrium temperature of the mixture. This is shown below:

Heat loss by warm water = Heat gain by cold water

MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)

Cancel out C

Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)

25× (65 - Tₑ) = 25 × (Tₑ - 25)

Cancel out 25

65 - Tₑ = Tₑ - 25

Collect like terms

65 + 25 = Tₑ + Tₑ

90 = 2Tₑ

Divide both side by 2

Tₑ = 90 / 2

Tₑ = 45 °C

Thus, we can conclude that the final temperature the mixture is 45 °C

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Answer:

4.0561×0.03÷63.5= 0.001916 mol cu

A coin is 3.00% Cu by mass. If the mass of the coin is 4.0561g, moles of Cu does it contain 0.001916 mole of Cu.

It is the most fundamental characteristic of matter and one of the fundamental quantities in physics.

Mass is a term used to describe how much matter is there in a body. The kilogramme is the SI unit of mass (kg). A body's mass does not alter at any point in time.

Given mass of coin = 4.0561g , moles =? , Cu by mass= 3.00%

4.0561×0.03÷63.5= 0.001916 mole Cu.

Thus, A coin is 3.00% Cu by mass. If the mass of the coin is 4.0561g, moles of Cu does it contain 0.001916 mole of Cu.

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Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

Period 2 element would the 4th ionization energy be much larger than the 3rd ionization energy is Boron.

Boron belongs to period second. atomic no. of boron is 5 and the electronic configuration is given as :

B₅  =   1s² 2s² 3p₁

The 1st ionization energy = 800.6

the 2nd ionization energy = 2427.1

the 3rd ionization energy = 3659.7

the 4th ionization energy = 25025.8

So. we can see that the 3rd ionization energy is much lower than 4th ionization energy because after removing the 3rd electron from 2s boron will attain the stable electronic configuration of helium. now to remove electron from filled orbital it will require much larger energy the 3rd ionization energy.

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Explanation:

The intermolecular forces present in the bonding of CH₃F are dipole-dipole interactions and London dispersion forces.

1.) No, CH₃F does not exhibit hydrogen bonding. Hydrogen bonding occurs when a hydrogen atom is bonded to a highly electronegative atom such as fluorine, oxygen, or nitrogen. In CH₃F, the hydrogen atom is bonded to carbon, which is not highly electronegative.

2.) Yes, CH₃F exhibits dipole-dipole interactions. Dipole-dipole interactions occur between molecules that have permanent dipoles due to the electronegativity difference between the atoms. In CH₃F, the fluorine atom is more electronegative than the carbon and hydrogen atoms, resulting in a polar molecule with a permanent dipole moment.

3.) Yes, CH₃F exhibits London dispersion forces. London's dispersion forces, also known as Van der Waals forces, are present in all molecules and arise from temporary fluctuations in electron distribution. Although CH₃F has dipole-dipole interactions, it also experiences London dispersion forces due to the temporary shifts in electron density.

Hence, the bonding in CH₃F was explained above.

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Explanation:

2. \(2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O\)

First, we need to find the number of moles of \(CO_2\) at 300K and 1.5 atm using the ideal gas law:

\(n= \dfrac{PV}{RT}= \dfrac{(1.5\:\text {atm})(33\:L)}{(0.082\:\text{L-atm/mol-K})(300K)}\)

\(=2.0\:\text{mol}\:CO_2\)

Now use the molar ratios to find the number of moles of ethane to produce this much \(CO_2\).

\(2.0\:\text{mol}\:CO_2 \times \left(\dfrac{2\:\text{mol}\:C_2H_6}{4\:\text{mol}\:CO_2}\right)\)

\(=1.0\:\text{mol}\:C_2H_6\)

Finally, convert this amount to grams using its molar mass:

\(1.0\:\text {mol}\:C_2H_6 \times \left(\dfrac{30.07\:\text g\:C_2H_6}{1\:\text{mol}\:C_2H_6} \right)\)

\(=30.1\:g\:C_2H_6\)

3. \(3Zn + 2H_3PO_4 \rightarrow 3H_2 + Zn_3(PO_4)_2\)

Convert 75 g Zn into moles:

\(75\:\text g\:Zn \times \left(\dfrac{65.38\:\text g\:Zn}{1\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:Zn\)

Then use the molar ratios to find the amount of H2 produced.

\(1.1\:\text{mol}\:Zn \times \left(\dfrac{3\:\text{mol}\:H_2}{3\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:H_2\)

Now use the ideal gas law \(PV=nRT\) to find the volume of H2 produced at 23°C and 4 atm:

\(V= \dfrac{nRT}{P}= \dfrac{(1.1\:\text{mol}\:H_2)(0.082\:\text{L-atm/mol-K})(296K)}{4\:\text{atm}}\)

\(=8.9\:\text L\:H_2\)

The desired reaction is 2Al(s) + 3CO2 from Al2O3(s) + 3CO(g) (g) The reactions include 2 Al(s), 3/2 O2(g), and Al2O3(s), with H = 1675.7kJ. ————————— (1) CO(g) = CO2 + 1/2 O2(g) (g).

As a result, the enthalpies of a reactants and products are added together, and the result is used to compute the enthalpy of a reaction. This endothermic process generates and absorbs environmental heat if H is positive. This reaction is exothermic so emits heat into the environment if H is negative.

A negative H indicates that heat is transferred from the a system towards its surroundings, whereas a positive H indicates that heat is transferred from the surroundings into the system. An enthalpy of reaction (Hrxn) for a chemical reaction is the difference of enthalpy between the products and reactants; Hrxn is measured in kilojoules per mole.

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A faraday is equal to one mole of electric charge. Because each aluminum ion gains 3 electrons, 0.1 faraday of charge will reduce 0.1/3 moles of aluminum, or 0.033 moles of aluminum.

What is meant by aluminum ?

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The mass percentage of each element in baking soda is:

The calculation of mass percentage for each element is as follows:

In this way, the mass percentage should be calculated by dividing each one from the baking soda sample.

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Answer:

The mass percentages of sodium, hydrogen, carbon, and oxygen are 27.37%, 1.20%, 14.30%, and 57%, respectively.

Explanation:

The mass percentage (%mass) of an element present in a compound is calculated using the following expression:

\(\rm \%mass=\dfrac{mass\;of\;the\;element}{mass\;of\;the\;compound}\times 100\%\)

According to the given problem, the mass of \(\rm NaHCO_3\) is 168.02 g.

The mass of sodium in the given sample is 45.98 g.

So, the %mass of sodium in the given sample is calculated as shown below:

\(\rm \%mass\;of\;sodium=\dfrac{45.98\;g}{168.02\;g}\times 100\%=27.37\%\)

Similarly, the mass percentages of hydrogen, carbon, and oxygen are calculated as shown below:

\(\rm \%mass\;of\;hydrogen=\dfrac{2.02\;g}{168.02\;g}\times 100\%=1.20\%\)

\(\rm \%mass\;of\;carbon=\dfrac{24.02\;g}{168.02\;g}\times 100\%=14.30\%\)

\(\rm \%mass\;of\;oxygen=\dfrac{96\;g}{168.02\;g}\times 100\%=57\%\)

Hence, the mass percentages of sodium, hydrogen, carbon, and oxygen are 27.37%, 1.20%, 14.30%, and 57%, respectively.

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To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Answer:

\(c=0.133\ J/g^{\circ}C\)

Explanation:

Given that,

Heat required, Q = 512 J

Mass of the substance, m = 255 g

The change in temperature, \(\Delta T=15^{\circ} C\)

Let c be the specific heat of the substance. We know that the heat required to raise the temperature is given by :

\(Q=mc\Delta T\)

Where

c is the specific heat of a substance

So,

\(c=\dfrac{Q}{m\Delta T}\\\\=\dfrac{512}{255\times 15}\\\\c=0.133\ J/g^{\circ}C\)

So, the specific heat of the substance is equal to \(0.133\ J/g^{\circ}C\).

Answer:

I think It is Covalent. Not 100% sure but like 90% sure.

Energy would it take to heat a section of the copper tubing that weighs about 650.0g, from 15.83°C to 24.11°C is 2.072 KJ.

The formula heat energy is given by :

q = mcΔT

given that :

m = 650.0 g

specific heat of copper c = 0.385 J/g °C

T1 = 15.83°C

T2 =  24.11°C

ΔT = T2 - T1 =  24.11°C - 15.83°C = 8.28 °C

putting all the values in the formula :

q = mcΔT

q = 650.0 g × 0.385 J/g °C × 8.28 °C

q = 2072.2 J = 2.072 KJ

Thus, Energy would it take to heat a section of the copper tubing that weighs about 650.0g, from 15.83°C to 24.11°C is 2.072 KJ.

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Answer:

3 Covalent Bonds and 1 Co ordinate Bond

Explanation:

4 bonds are in NH4¹+

NH4¹+ is the ammonium ion, which consists of a central nitrogen atom (N) and four hydrogen atoms (H). Nitrogen is located in group 15 of the periodic table and has 5 valence electrons. Hydrogen, on the other hand, has 1 valence electron.

To achieve a stable electron configuration, nitrogen needs to share electrons with the hydrogen atoms. Each hydrogen atom can form a single bond with the nitrogen atom by sharing its valence electron.

In NH4¹+, all four hydrogen atoms form single bonds with the central nitrogen atom. These bonds are represented by lines connecting each hydrogen atom to the nitrogen atom.

So, NH4¹+ has 4 bonds. Each bond represents a pair of electrons shared between the nitrogen atom and a hydrogen atom. The bonding arrangement ensures that the nitrogen atom has a complete octet (eight valence electrons) and each hydrogen atom has two electrons, following the stable configuration of helium.

The "+1" charge on NH4¹+ indicates that the ion has lost one electron, resulting in a positive charge. However, the number of bonds remains the same regardless of the charge.

Therefore, the correct answer is 4 for the number of bonds in NH4¹+.

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The reaction of a Grignard reagent with an aldehyde followed by dilute acid gives a secondary alcohol.

Given reaction is followed:

\(CH_{3}CHO \rightarrow CH_{3}COHHph\)  in presence of phMgBr, ether and \(H_{3}O^{+}\)Aldehydes or ketones' carbonyl group, C=O, reacts with organolithium or Grignard reagents to produce alcohols. The type of alcohol produced depends on the carbonyl's substitutes.

A secondary alcohol is a substance that contains a saturated carbon atom with two additional carbon atoms linked to it and a hydroxy group, or OH.

A chemical molecule with the generic formula RMgX, where X is a halogen and R is an organic group, typically an alkyl or aryl, is known as a Grignard reagent or Grignard compound.

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Taking into account the definition of dilution, the final concentration after two dilutions is 0.296 M.

Dilution is the reduction in concentration of a chemical substance in a solution. This is accomplished by adding more solvent to the solution at the same amount of solute.

The amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you have a first dilution where you know:

Replacing in the definition of dilution:

1.70 M× 78 mL= Cf× 218 mL

Solving:

(1.70 M× 78 mL)÷ 218 mL= Cf

0.608 M= Cf

A 109 mL portion of that solution is diluted by adding 115 mL of water. So, you have a second dilution where you know:

Replacing in the definition of dilution:

0.608 M× 109 mL= Cf× 224 mL

Solving:

(0.608 M× 109 mL)÷ 224 mL= Cf

0.296 M= Cf

In summary, the final concentration is 0.296 M.

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Answer:

9.990,123578

Explanation:

0.659248-+780

Answer:

41800 j/g

Explanation:

Your welcome

The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

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Answer:35.24 grams of are required to produce the given amount of Zinc oxide.

Moles of phosphoric acid would be needed : 0.833

Given

15 grams of water

Required

moles of phosphoric acid

Solution

Reaction(decomposition) :

H3PO4 -> H2O + HPO3

mol water (H2O :

= mass : MW

= 15 g : 18 g/mol

= 0.833

From the equation, mol ratio H3PO4 = mol H2O = 1 : 1, so mol H3PO4 = 0.833

Oxygen-16: 8 protons, 8 neutrons, 8 electrons

Oxygen-18: 8 protons, 10 neutrons, 8 electrons

Using atomic and mass numbers, we can find information about the makeup of atoms.

Protons

Every element has a unique number of protons, and every atom of the same element will have the same number of protons. This means that both oxygen atoms must have the same number of protons. The number of protons in an element is equal to its atomic number. Since oxygen has an atomic number of 8, all oxygen atoms will have 8 protons. This means that oxygen-16 and oxygen-18 have 8 protons.

Neutrons

The number of neutrons an atom of a certain element can have varies. Atoms of the same element that have different numbers of neutrons are known as isotopes. The number of neutrons can be found through the mass number. The mass number is the number that follows the dash in the name of the isotope. This number is equal to the protons plus the neutrons. So, to find the number of neutrons in an oxygen atom, subtract 8 protons from the mass number. This means oxygen-16 has 8 neutrons and oxygen-18 has 10 neutrons.

Electrons

Remember that electrons are negatively charged, protons are positively charged, and neutrons have no charge. The number of electrons in an atom determines the charge of the atom. If the number of electrons equals the number of protons, then the charge of the atom will equal 0. If there are more electrons, then the atom will be negatively charged and vice versa. Since neither of the atoms has any indication of a nonzero charge, the number of electrons must equal the number of protons. So, both oxygen atoms have 8 electrons.