I would dissolve non-polar solid iodine in liquid bromine, which is non-polar, as the solvent.
What are polar and non-polar substances?Polar substances are substances whose molecules have oppositely-charged ends. Examples of polar substances are ionic compounds as well as polar covalent compounds like water and hydrogen chloride.
Non-polar substances are substances whose molecules do not have charged ends. Examples of non-polar substances are covalent molecules such as carbon dioxide, bromine, etc.
According to the principle of solutions, like dissolves like. Hence, non-polar solids will dissolve in non-polar solvents.
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after the nutrients are extracted, where does the food go, waiting to be expelled?
Answer:
Nutrients advance through the alimentary canal to the stomach and small intestine, and waste materials continue from the small intestine to the colon (large intestine) and anus.
Explanation:
An important secondary structures of proteins, the _______ forms hydrogen bonds with residues on a nearby strand when the protein folds.Question 10 options: β-pleated sheet random coil α-helix primary structure
In this case, the primary structure forms hydrogen bonds to fold itself.
The answer is primary structure.
Brighter stars will have a (Positive/Negative) Absolute Magnitude?
Brighter stars will have a Negative Absolute Magnitude.
What is absolute magnitude?The absolute magnitude can be defined as the magnitude that a star would appear to have if it were located at a standard distance of 10 parsecs.
Absolute magnitude is a similar measure that represents how bright an object actually is.
In conclusion, we can say that the brightness of the star Vega is used to define an apparent magnitude of zero.
We can also conclude that Stars that has a positive apparent magnitudes appears to the normal eye to be dimmer than Vega, while stars that has negative apparent magnitudes will appear to be brighter than Vega.
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Hexane and air enter the combustion chamber of a well insulated gas turbine engine at 25C. What amount of excess air will be required if the temperature of the products is to be limited to 825C?
The amount of excess air will be required if the temperature of the products is to be limited to 825C is -6.731.This negative value means that we actually need less air than the stoichiometric amount to achieve a product temperature of 825C.
To determine the amount of excess air required for this combustion process, we need to use the stoichiometric equation for the combustion of hexane:
C₆H₁₄+ (19/2)O₂ → 6CO₂ + 7H₂O
This equation tells us that for every mole of hexane, we need 19/2 moles of oxygen (or air) to completely combust the fuel. However, if we want to limit the temperature of the products to 825C, we need to introduce excess air into the combustion chamber. This excess air will help to cool down the products of combustion and prevent them from reaching temperatures that could damage the turbine.
To calculate the amount of excess air required, we can use the equation:
Fuel + (actual air/fuel ratio) x (O₂ in air/stoichiometric O₂) x Air = Products
We know that the initial temperature of the hexane and air is 25C, and we want to limit the temperature of the products to 825C. Therefore, we can assume that the specific heat ratio of the products is constant at 1.4. We also know that the fuel being used is hexane, which has a molecular weight of 86 g/mol.
Using this information and the stoichiometric equation above, we can calculate the amount of excess air required as follows:
1. Calculate the stoichiometric air/fuel ratio:
(19/2) x 32/86 = 7.2
2. Calculate the actual air/fuel ratio required for a product temperature of 825C:
(T2/T1)\(^{0.4}\) = (825 + 273)/(25 + 273) = 3.38
(actual air/fuel ratio) x 7.2 = 3.38
(actual air/fuel ratio) = 0.469
3. Calculate the amount of excess air required:
Air/Fuel ratio - Stoichiometric air/fuel ratio = Excess air/fuel ratio
0.469 - 7.2 = -6.731
Therefore, the answer to the question is that no excess air is required, and the stoichiometric amount of air (7.2 moles per mole of hexane) is sufficient to achieve the desired product temperature.
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determine the concentration of the sugar standards in g/100 ml of solution. the first two have been done for you. note: 1 sugar packet contains 3.5 g of sugar number of packs of sugar dissolved in 100 ml of solution 0 1 2 3 4 g sugar/100 ml (% w/v) 0 3.5 ? ? ? concentration of solution 2 ( g sugar/100 ml): concentration of solution 3 ( g sugar/100 ml): concentation of solution 4 ( g sugar/100 ml):
By using the information provided in the table and the amount of sugar packets added to 100 ml of solution, we can determine the concentration of sugar standards in g/100 ml.
To determine the concentration of the sugar standards in g/100 ml of solution, we can use the information provided in the table. The sugar standards are solutions with varying amounts of sugar dissolved in 100 ml of solution. The sugar concentration is expressed as g sugar/100 ml or % w/v.
According to the table, the first two sugar standards have been done for us. The first standard has 0 g sugar/100 ml, which means no sugar was added to the solution. The second standard has 3.5 g sugar/100 ml, which means one sugar packet was dissolved in the solution.
To determine the concentration of the third sugar standard, we need to know how many sugar packets were dissolved in 100 ml of solution. Since the second standard has 3.5 g sugar/100 ml, we can assume that one sugar packet was used. Therefore, to make the third standard, we need to add two sugar packets to 100 ml of solution, which gives us a concentration of 7 g sugar/100 ml.
Similarly, to determine the concentration of the fourth sugar standard, we need to add three sugar packets to 100 ml of solution, which gives us a concentration of 10.5 g sugar/100 ml.
Therefore, the concentrations of the sugar standards in g/100 ml of solution are:
- Standard 1: 0 g sugar/100 ml
- Standard 2: 3.5 g sugar/100 ml
- Standard 3: 7 g sugar/100 ml
- Standard 4: 10.5 g sugar/100 ml
In summary, by using the information provided in the table and the amount of sugar packets added to 100 ml of solution, we can determine the concentration of sugar standards in g/100 ml.
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Part D
Calculate the following for test tube 1 and for test tube 2, and record the results in the table:
the number of moles of copper(II) sulfate used (Use 159.60 grams/mole as the molar mass of copper(II) sulfate.)
the heat absorbed by the water, in joules (Use Q = mCΔT, where 10.0 milliliters of water has a mass of 10.0 grams. Use 4.186 joules/gram degree Celsius as water’s specific heat capacity.)
the change in internal energy of the copper(II) sulfate (Assume that the energy released by the copper(II) sulfate is absorbed by the water.)
the reaction enthalpy, in joules/mole
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To calculate the following for test tube 1 and test tube 2:
1. The number of moles of copper(II) sulfate used:
Test tube 1: 0.2 g of copper(II) sulfate was used, which is equivalent to 0.001255 moles (0.2 g / 159.60 g/mol).
Test tube 2: 0.4 g of copper(II) sulfate was used, which is equivalent to 0.002510 moles (0.4 g / 159.60 g/mol).
2. The heat absorbed by the water, in joules:
Test tube 1: Q = (10.0 g) x (4.186 J/g°C) x (20.0°C) = 837.2 J
Test tube 2: Q = (10.0 g) x (4.186 J/g°C) x (30.0°C) = 1257.9 J
3. The change in internal energy of the copper(II) sulfate:
Since the energy released by the copper(II) sulfate is absorbed by the water, the change in internal energy of the copper(II) sulfate is equal to the negative of the heat absorbed by the water.
Test tube 1: ΔU = -837.2 J
Test tube 2: ΔU = -1257.9 J
4. The reaction enthalpy, in joules/mole:
The reaction enthalpy can be calculated using the formula ΔH = ΔU + PΔV, where PΔV represents the work done by the system. Assuming that the reaction was carried out at constant pressure (i.e., atmospheric pressure), PΔV can be approximated to zero, and thus the reaction enthalpy is equal to the change in internal energy.
Test tube 1: ΔH = -837.2 J / 0.001255 mol = -666,876 J/mol
Test tube 2: ΔH = -1257.9 J / 0.002510 mol = -500,357 J/mol
Therefore, the results can be recorded in the following table:
| | Moles of CuSO4 used | Heat absorbed by water (J) | Change in internal energy (J) | Reaction enthalpy (J/mol) |
|-----------|---------------------|-----------------------------|---------------------------------|---------------------------|
| Test tube 1 | 0.001255 | 837.2 | -837.2 | -666,876 |
| Test tube 2 | 0.002510 | 1257.9 | -1257.9 | -500,357 |
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Why is water wet??
Only 70%of people know it.
Answer:
yes because wet is water
Answer: Being a liquid, water is not itself wet, but can make other solid materials wet. Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.
What number of cations is present in 1.17g of sodium chloride ?
Answer:
1.2 × 10^22 atoms.
Explanation:
Firstly, cations refers to the positively charged atom in the ionic compound, which is Na+.
Given the mass of NaCl as 1.17g, the number of moles of NaCl can be calculated this:
Molar mass of NaCl = 23 + 35.5
= 58.5g/mol
Mole = mass/molar mass
Mole = 1.17/58.5
Mole = 0.02moles
Using Avagadro's number, 6.022 × 10^23 atoms of Na+ are in 1 mole of NaCl.
In 0.02 moles of NaCl, there are 0.02 × 6.022 × 10^23 of Na+
0.1204 × 10^23 atoms
1.2 × 10^22 atoms of Na+ (cation)
What is the splitting of the signal in the IH NMR spectrum for the methyl protons of I -bromo-2- methylpropane? a. singlet b. doublet c. triplet d. Nonet
The splitting of the signal in the IH NMR spectrum for the methyl protons of 1-bromo-2-methylpropane is a triplet. (C)
In proton NMR, the number of peaks and their relative intensity provides information about the number and types of hydrogen atoms in a molecule.
The splitting of the signal, or the number of peaks, is caused by the interaction between neighboring hydrogen atoms.
For 1-bromo-2-methylpropane, the methyl protons are attached to a carbon atom that is adjacent to two other hydrogen atoms, which causes the signal to split into three peaks of equal intensity, resulting in a triplet.
This splitting pattern is known as a first-order splitting pattern, and the intensity of the peaks is determined by the number of neighboring hydrogen atoms.
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Concert 15 cm3 to liters
The answer to your problem is 0.015 liters. I got the answer because to convert cubic centimeters into liters, you need to divide the cubic centimeters by 1000.
A voltaic cell is based on the reduction of ag+(aq) to ag(s) and the oxidation of sn(s) to sn2+(aq). (a) write half-reactions for the cell's anode and cathode. include the phases of all species in the chemical equation. anode cathode (b) write a balanced cell reaction. include the phases of all species in the chemical equation. tip: plus signs (+) can be typed from the keyboard. reaction arrows can be found in the tools menu of the answer module. include phases in the balanced chemical equation. click on the (aq) button in the tools to select the phase to add. phases should not be subscripted.
1. Reduction half reaction (or cathode reaction):-
Ag+(aq) + e- ---------> Ag(s)..........(1)
2. Oxidation half reaction (or anode reaction) :-
Sn(s) --------> Sn2+(aq) + 2e- ............(2)
3. Overall reaction :-
2*(1) + (2)
or, 2Ag+(aq) + Sn(s) --------> 2Ag(s) + Sn2+(aq)
A galvanic cell, often known as a voltaic cell after the scientists Luigi Galvani and Alessandro Volta, is an electrochemical cell in which an electric current is created by spontaneous Oxidation-Reduction events. A voltaic cell is an electrochemical cell that uses a chemical process to generate electrical energy. The oxidation and reduction processes are split into half-cell sections.
To create an electric current, galvanic (or voltaic) cells employ a thermodynamically advantageous redox process. Each half-reaction occurs in its own compartment, or half-cell, which contains an electrode. The anode is the electrode where oxidation happens, while the cathode is the electrode where reduction occurs.
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PLEASE ANSWER 20 POINTS!!
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
glucose = C₆H₁₂O₆
glucose produced = 1/6 x 23.6 = 3.93 moles
Jeff has 10 grams of water and 10 grams of vegetable oil in separate containers. both liquids have a temperature of 24°c. jeff heats both liquids over a flame for five minutes. when he’s finished, he discovers that the temperature of the oil increased more than the temperature of the water. what can jeff conclude from this experiment?
ANSWER: From this experiment, Jeff can conclude that the heat capacity of oil is lower than that of water which means that oil requires less energy per gram of liquid in order to change its temperature.
Given that mass of Copper sulfate pentahydrate before heating is 1.02g and after heating is 0.75g.
1. Calculate the mass of copper sulfate present after heating. Assume that all of the water was evaporated and that no
decomposition occurred.
2. Calculate the mass of water that was lost from the original compound by heating. Assume that the reduction in
mass is entirely due to the loss of water.
3. Determine the number of moles of water that were in the original compound.
4. Do your results support the assertion that the original compound was copper sulfate pentahydrate? Why or why
not? Show your work for any calculations and explain your reasoning.
The mass of copper sulfate present after heating is 0.27 g. The mass of water lost from the original compound is 0.27 g. The number of moles of water is 0.015 mol.
The mass of copper sulfate present after heating can be calculated by subtracting the mass of water lost from the original mass of copper sulfate pentahydrate. Thus, the mass of copper sulfate present after heating is:
Mass of copper sulfate = Mass before heating - Mass after heating
= 1.02 g - 0.75 g
= 0.27 g
The reduction in mass of the compound is entirely due to the loss of water. Therefore, the mass of water lost from the original compound can be calculated as:
Mass of water lost = Mass before heating - Mass after heating
= 1.02 g - 0.75 g
= 0.27 g
To determine the number of moles of water that were in the original compound, we first need to calculate the molar mass of the compound. Copper sulfate pentahydrate has a molar mass of 249.69 g/mol. The number of moles of water can be calculated as:
Moles of water = Mass of water lost / Molar mass of water
= 0.27 g / 18.015 g/mol
= 0.015 mol
The results support the assertion that the original compound was copper sulfate pentahydrate. Copper sulfate pentahydrate contains five molecules of water per molecule of copper sulfate. The calculated number of moles of water lost (0.015 mol) divided by the number of moles of copper sulfate present (0.27 g / 159.61 g/mol = 0.0017 mol) gives a ratio of approximately 9, which is close to the expected ratio of 5. This indicates that the original compound was indeed copper sulfate pentahydrate.
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1.The mass of copper sulfate after heating is 0.75g, 2. The mass of water that was lost from the original compound by heating is 0.27g, 3. The number of moles of water that were in the original compound is 0.015 mol and lastly, 4. Overall, our results do support the assertion that the original compound was copper sulfate pentahydrate
1.The mass of copper sulfate present after heating will be equal to the mass of the compound after heating, since we are assuming that all of the water was evaporated and no decomposition occurred.
2.The mass of water that was lost from the original compound by heating can be calculated by subtracting the mass of the compound after heating from the mass of the compound before heating:
Mass of water lost = Mass before heating - Mass after heating
= 1.02g - 0.75g
= 0.27g
3. The number of moles of water that were in the original compound can be calculated by dividing the mass of water lost by the molar mass of water:
Number of moles of water = Mass of water lost / Molar mass of water
= 0.27g / 18.02g/mol
= 0.015 mol
4. The original compound was copper sulfate pentahydrate, which has the formula CuSO4·5H2O. This means that there should be 5 moles of water for every mole of copper sulfate in the compound. To determine if our results support this assertion, we can calculate the ratio of moles of water to moles of copper sulfate:
Ratio of moles of water to moles of copper sulfate = Number of moles of water / Number of moles of copper sulfate
= 0.015 mol / (0.75g / 159.61g/mol)
= 0.015 mol / 0.0047 mol
= 3.19
This ratio is close to 5, but not exactly 5. This could be due to experimental error or the fact that not all of the water was completely evaporated during heating. Overall, our results do support the assertion that the original compound was copper sulfate pentahydrate, but more accurate measurements and experimentation would be needed to confirm this.
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Maya made this picture to represent a chemical reaction:
Which of the following statements best explains the type of chemical reaction represented by Maya's picture?
It is neither a synthesis reaction nor a decomposition reaction because two reactants form two products.
It represents a decomposition reaction because two reactants break apart and form two products.
It is neither a synthesis reaction nor a decomposition reaction because the total mass of the products is less than the total mass of the reactants.
It represents a synthesis reaction because the same atoms are present in the reactants and products.
Answer:
It is neither a synthesis reaction nor a decomposition reaction because two reactants form two products.
Explanation:
This reaction would be considered a single replacement reaction.
The chemical reaction involves the products and the reactants. The image is neither synthesis nor decomposition as the two products are formed from two reactants. Thus, option A is correct.
What is a chemical reaction?A chemical reaction includes the chemical interaction between the reactants to yield the products. In a synthesis reaction, two reactants interact to produce a different molecule or compound.
In a decomposition reaction, a reactant undergoes splitting to produce products and energy. But in the image two reactants produces two products that neither of the reaction shows.
This type of reaction is seen as the single replacement reaction where the more reactive element displaces the less reactive from the compound to form the new molecule.
Therefore, option a. Maya's picture represents a single replacement reaction but not a synthesis or decomposition reaction.
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What describes a chemical reaction?
Answer:
A chemical reaction is a process where two different substances or elements are mixed together. They then undergo some sort of chemical change to become a different substance altogether.
Explanation:
Explain how sunlight can cause a crack in the street.
chemistry work, help please.
The average atomic mass of the Mc in the sample, given the that the hypothetical mass spectrum of Mc, is 289.1 amu
How do i determine the average atomic mass of Mc?First, we shall determine the atomic mass of each isotope as shown from the spectrum. Details below:
For 1st isotope
Number of atom = 3Total atoms = 10Atomic mass = 288.2Atomic mass of 1st isotope = ?Atomic mass of 1st isotope = (Number of atom /total atom) × atomic mass
Atomic mass of 1st isotope = (3 / 10) × 288.2
Atomic mass of 1st isotope = 86.46 amu
For 2nd isotope
Number of atom = 5Total atoms = 10Atomic mass = 289.2Atomic mass of 2nd isotope = ?Atomic mass of 2nd isotope = (Number of atom /total atom) × atomic mass
Atomic mass of 2nd isotope = (5 / 10) × 289.2
Atomic mass of 2nd isotope = 144.6 amu
For 3rd isotope
Number of atom = 2Total atoms = 10Atomic mass = 290.2Atomic mass of 3rd isotope = ?Atomic mass of 3rd isotope = (Number of atom /total atom) × atomic mass
Atomic mass of 3rd isotope = (2 / 10) × 290.2
Atomic mass of 3rd isotope = 58.04 amu
Finally, we shall determine the average atomic mass of Mc. Details below:
Atomic mass of 1st isotope = 86.46 amuAtomic mass of 2nd isotope = 144.6 amuAtomic mass of 3rd isotope = 58.04 amuAverage atomic mass of Mc =?Average atomic mass of Mc = sum atomic masses of isotopes
Average atomic mass of Mc = 86.46 + 144.6 + 58.04
Average atomic mass of Mc = 289.1 amu
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Which of the following formulas should be classified as an acid?
O Na₂SO4
O NaHCO3
O NaOH
O H₂SO4
Answer:
D) H₂SO4 is an acid
Explanation:
Please mark branliest
H\(_2\)SO\(_4\) is the chemical formula that should be classified as an acid. Therefore, the correct option is option D.
What is an acid?Any substance that tastes acidic when dissolved in water, alters the colour of some indicators, reacts with the some metals to release hydrogen, reacts using bases to produce salts, and stimulates some chemical reactions is considered to be an acid. The inorganic chemicals referred to as being mineral acids sulfuric, nitrous, hydrochloric, or phosphoric acids are examples of acids.
The phenolic, sulfonic, and carboxylic acid groups of organic molecules. These chemicals contain one or maybe more hydrogen atoms, which are discharged into highly charged hydrogen ions when they are in solution. H\(_2\)SO\(_4\) is the chemical formula that should be classified as an acid.
Therefore, the correct option is option D.
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30 pts for all answers pls
Explanation:
dont know just found it im in fifth grade so....... this is for the first one thats all i could do kk
What is the gravitational potential energy of a 200kg object suspended 5m above the earth's
The gravitational potential energy for the object is 9800 J.
The gravitational potential is the scalar amount characteristic of a point in a gravitational field whose slope breaks even with the escalated of the field and rises to the work required to move a body of unit mass from a given point to a point interminably farther.
The formula referred for calculating the gravitational potential to the ground level is given by
U = mgh
where m is the mass of the object and g is the gravitational constant and last h is the height from the ground where the object is situated.
As we provided with,
g = 9.8 ms-2
m = 200 kg
h = 5m
So substituting the required values in the formula m we get
= 200 x 9.8 x 5
= 9800 J
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If a gas is cooled from 323.0 K to 273.15 K and the volume is kept constant what final pressure, in atm, would result if the original pressure was 750.0 mmHg?
If a gas is cooled from 323.0 K to 273.15 K and the volume is kept constant, 0.77 atm is the final pressure, in atm, would result if the original pressure was 750.0 mmHg.
The force delivered perpendicularly to an object's surface per unit area across which the force is dispersed is known as pressure (symbol: p / P).[1]: 445 The pressure proportional to the surrounding air is known as gauge pressure, also spelt gauge pressure[a].
Pressure is expressed using a variety of units. Some of these are calculated by dividing a unit of force by a unit of area; for instance, the metric system's unit of pressure, a pascal (Pa), is equal to one newton every square metre (N/m2).
P₁/T₁ = P₂/T₂
P₂ = P₁T₂/T₁
= 0.91 atm × 273.15 K / 323 K
= 0.77 atm
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What are the forces on the wooden block when it is resting on a bench
Answer:
As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
Explanation:
Since the static frictional force between the block and the plane is given by F = μN where
μ = coefficient of static friction and
N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where
W = weight of block and
θ = angle of inclined plane
Now, F = μN
F = μWcosθ
Since μ and W are constant, we see that
F ∝ cosθ and cosθ ∝ θ
So, F ∝ θ
Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.
So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
PLEASE HELP WILL GIVE BRAINLIEST!!!!
If the concentration of substance A of a reversible reaction in dynamic equilibrium increases, how will the equilibrium change?
A. It will shift to create more of substance A.
B. It will shift towards the reactants.
C. It will shift towards the products.
D. It will shift to create less of substance A.
Answer:
\(\boxed{It\ will\ shift\ to\ create\ less\ of\ substance\ A}\)
Explanation:
If the concentration of any substance A in a dynamic equilibrium increases, The equilibrium will be shifted to its opposite side so that Substance A can be created less and the substance opposite to A can be created more so that a "dynamic equilibrium" can again be established.
the conjugate base of nh3 is ________.
Answer:
(NH2)-
Explanation:
A conjugate base is formed when a proton is removed from an acid
so NH3 => (NH2)- + H+
so (NH2)- is conjugate base of NH3
Which statement is true of any reversible reaction?
A. It can proceed in either direction
B. It can occur only between gases
C. It has only one product
D. It has more than one reactant
Answer:
A. It can proceed in either direction
Explanation:
A P E X
Reactions can be reversible and irreversible. The reversible reactions can proceed in either direction. Thus, option A is correct.
What are reversible reactions?Reversible reactions can convert the reactants and products into each other and hence, move in both the left and right directions. These types of reactions never get completed and attain equilibrium.
The reactants react to produce the products, and the products re-react to form the reactants of the reaction mixture. The melting of the wax can be a reversible reaction.
Therefore, option A. reversible reactions can occur in both directions is correct.
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Describe what happens to the freezing point when tin is added.
Answer:
The freezing point of a substance is the temperature at which it changes from a liquid to a solid. When tin is added to a substance, it can lower the freezing point of the substance. This is known as a colligative property of matter, which refers to the ability of certain substances, such as solutes, to alter the physical properties of a solvent (such as the freezing point or boiling point) without changing the chemical composition of the solvent.
In the case of tin, when it is dissolved in a solvent, it can disrupt the interactions between the solvent molecules, making it more difficult for the solvent to form a solid. As a result, the freezing point of the solvent is lowered. This effect is more pronounced when the concentration of the solute is higher.
It's important to note that the freezing point depression caused by tin (or any other solute) is dependent on the concentration of the solute and the nature of the solvent. Different solvents will have different freezing points, and the freezing point depression caused by a given solute may vary depending on the solvent used.
Explanation:
26-30. Why is it that a pitcher of orange juice flow smocthly when you transfer it to another container?
A pitcher of orange juice flow smoothly when you transfer it to another container because of lower viscosity value and large proportion of water in it.
What is viscosity?Viscosity is the resistance of a fluid to a change in shape or movement of portions as compared to one another. High viscous moves slowly as compared to less viscous.
So we can conclude that a pitcher of orange juice flow smoothly when you transfer it to another container due to lower viscosity.
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Which of these statements is true about heat?
Answer:
Explanation:
what are the statments i can't help till i have the posable answers
Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.
Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.
What if you don't add it ?If hydroxide is not added, the NH₂ groups will get protonated by H⁺ ions present to give NH₃⁺ groups, which cannot react.
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