Answer:
the property that is used in solving this equation is d.
Step-by-step explanation:
Please help with this question thanks!!
Answer:
(-1,4)
Step-by-step explanation:
Step 1) Change both equations to slope intercept form
3x+y=1 ---> y=-3x+1
5x+y=-1 ---> y=-5x-1
Step 2) Plot lines accordingly on graph
Lines intersect at (-1,4)
What is the minimum velocity attained on the interval 0
Answer:
0.630
Step-by-step explanation:
Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.
Calculate the lengths of the 2 unlabeled sides...
The value of GJ and and JH will be 6.5 and 9.19 respectively
What is angle of elevation?
The angle of elevation is an angle that is formed between the horizontal line and the line of sight. If the line of sight is upward from the horizontal line, then the angle formed is an angle of elevation.
Given data ,
The angle of elevation θ = 45°
The value of GH = 6.5
Now , the ΔJGH is a right triangle , so by Trigonometric relations
tan θ = JG / GH
tan 45° = 1
Therefore , 1 = JG / GH
1 = JG / 6.5
So , JG = GH = 6.5
Now to calculate JH , we use the Pythagoras Theorem ,
where JH² = JG² + GH²
Substituting the values for JG and GH , we get
And JH² = 6.5² + 6.5²
= 42.25 + 42.25
= 84.5
taking square root on both sides
Therefore , JH = 9.19
Hence , The value of GJ and and JH will be 6.5 and 9.19 respectively
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which of the two rational numbers 3/5 and -2/3 is greater
There are 15 teams in a league. in how many ways can the teams finish first, second, third, and forth? (assume there are no ties.)
There are 32,760 ways in which the teams can finish first, second, third, and fourth in the league.
To determine the number of ways the teams can finish first, second, third, and fourth in a league with 15 teams, we can use the concept of permutations.
For the first position, any of the 15 teams can finish first.
For the second position, there are 14 teams remaining that can finish second.
For the third position, there are 13 teams remaining that can finish third.
For the fourth position, there are 12 teams remaining that can finish fourth.
To calculate the total number of ways, we multiply the number of choices for each position:
Total number of ways = 15 * 14 * 13 * 12 = 32,760
Therefore, there are 32,760 ways in which the teams can finish first, second, third, and fourth in the league.
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"
Question 2 ""If the Vpp is 10 V, then the Vavg is:"" O 20 V O 3.53 V O 3.18 V O 5 V
"
The correct answer is option O: 5 V.
To determine the average voltage (Vavg) given a peak-to-peak voltage (Vpp) of 10 V, we need to consider the relationship between Vavg and Vpp in an alternating current (AC) waveform.
The average voltage of an AC waveform is related to its peak-to-peak voltage by the formula: Vavg = 0.5 * Vpp.
Applying this formula to the given Vpp of 10 V, we can calculate the Vavg as follows: Vavg = 0.5 * 10 V = 5 V.
The average voltage is equal to half of the peak-to-peak voltage, resulting in an average voltage of 5 V for a Vpp of 10 V.
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y = 2x - 4 y = x + 1
Solve using substitution.
Step-by-step explanation:
heres tue answer. hope that helps
Answer:
x=5,y=6
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
7. La somme de deux multiples de 3 consécutifs est de 129. Quels sont ces deux nombres?
Answer:
Les deux nombres doivent avoir une différence de 3. Algébriquement, ce serait x + (x + 3) = 129. 2x est alors égal à 126. X est égal à 63 et x + 3 est à 66. Ces nombres sont des multiples consécutifs de 3 dont la somme est de 129.
Step-by-step explanation:
The two numbers must have a difference of 3. Algebraically, it would be x + (x + 3) = 129. 2x then is equal to 126. X equals 63 and x + 3 is 66. These numbers are consecutive multiples of 3 whose sum is 129.
In the coordinate plane, which of the following functions dilates by a factor of 3
about the point (9, 6)?
A. (, ) = (3 + 9, 3 +6)
B. (, ) = (3( + 9), 3( + 6))
C. (, ) = (9+ 3( − 9), 6 + 3( −6))
D. (, ) = (9+ 3(9− ), 6+ 3(6 − ))
What is the equation of the line that goes through the points 2,9 and 3,1
The equation of the line that goes through the given points is y = -8x + 25.
Given the following points:
Points on the x-axis = (2, 3)Points on the y-axis = (9, 1)To determine the equation of the line that goes through the given points:
First of all, we would determine the slope of this line by using the following formula;
\(Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}\)
Substituting the points into the formula, we have;
\(Slope, \;m = \frac{1 - 9}{3 - 2}\\\\Slope, \;m = \frac{-8}{1}\\\\\)
Slope, m = -8
Now, we can determine the equation of the line by using this formula:
\(y-y_1 =m(x-x_1)\\\\y-9=-8(x-2)\\\\y-9=-8x+16\\\\y=-8x+16+9\)
y = -8x + 25
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Camila is driving on a long road trip. She currently has 10 gallons of gas in her car. Each hour that she drives, her car uses up 1.75 gallons of gas. How much gas would be in the tank after driving for 3 hours? How much gas would be left after tt hours?
Answer:
gas left after 3 hours = 4.75
gas left after t hours = 10-1.75t
Step-by-step explanation:
According to DeltaMath "Since Camila uses 1.75 gallons of gas per hour, she would use 1.75 x 5, or 5.25 gallons in 3 hours. Since Camila started with 10 gallons in the tank, the amount of remaining after 3 hours would be 10-5.25 or 4.75 gallons. "
How to solve lim (x, y) → (0, 0) x4 − 38y2 x2 19y2?
We solve to find that the limit exists and is equal to 0: lim (x, y) → (0, 0) f(x, y) = 0. Therefore, the solution to the limit is 0.
To solve this limit, we need to use the definition of a limit and apply it to the function. The definition of a limit is:
lim (x, y) → (a, b) f(x, y) = L if and only if for every ε > 0 there exists a δ > 0 such that if (x, y) is in the domain of f and 0 < √((x-a)² + (y-b)²) < δ, then |f(x, y) - L| < ε.
We can apply this definition to the function f(x, y) = x^4 − (38y^2)/(x^2 + 19y^2) and the point (0, 0) to find the limit.
First, let's simplify the function:
f(x, y) = x^4 − (38y^2)/(x^2 + 19y^2) = x^4 − 38y^2/(x^2 + 19y^2)
Next, let's substitute the point (0, 0) into the function:
f(0, 0) = 0^4 − 38(0^2)/(0^2 + 19(0^2)) = 0
Now, let's apply the definition of a limit:
lim (x, y) → (0, 0) f(x, y) = 0 if and only if for every ε > 0 there exists a δ > 0 such that if (x, y) is in the domain of f and 0 < √((x-0)² + (y-0)²) < δ, then |f(x, y) - 0| < ε.
We can simplify this further:
lim (x, y) → (0, 0) f(x, y) = 0 if and only if for every ε > 0 there exists a δ > 0 such that if (x, y) is in the domain of f and 0 < √(x² + y²) < δ, then |x^4 − 38y^2/(x^2 + 19y^2)| < ε.
Now, we need to find a δ that satisfies this condition. Let's choose δ = √(ε/2). Then, if 0 < √(x² + y²) < δ, we have:
|x^4 − 38y^2/(x^2 + 19y^2)| < ε
|x^4| + |38y^2/(x^2 + 19y^2)| < ε
|x^4| + |38y^2|/(x^2 + 19y^2) < ε
Since 0 < √(x² + y²) < δ, we have:
|x^4| < (ε/2)^(4/2) = ε^2/4
|38y^2|/(x^2 + 19y^2) < 38(ε/2)^(2/2)/(ε/2)^2 + 19(ε/2)^(2/2) = 38ε/2ε + 19ε/2ε = 57ε/2ε = 57/2
Therefore, |x^4 − 38y^2/(x^2 + 19y^2)| < ε^2/4 + 57/2 < ε for all ε > 0.
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A clay specimen, 25 mm thick, has been tested in an oedometer apparatus with two way rainage, and it is observed that 50% of the consolidation settlement occurs in 1 hour. A ayer of the same clay is observed to settle 10 mm in 10 years and after many years to settle (total primary consolidation) by 35 mm. Determine the thickness of the clay layer if it drains only from upper surface
The thickness of the clay layer, which drains only from the upper surface, can be determined based on the consolidation settlement observations. With 50% of consolidation settlement occurring in 1 hour for a 25 mm thick specimen, and a total primary consolidation settlement of 35 mm occurring over many years, the thickness of the clay layer is approximately 87.5 mm.
The consolidation settlement of a clay specimen can be used to estimate the thickness of a clay layer that drains only from the upper surface. In this case, the observed settlement data provides valuable information.
Firstly, we know that 50% of the consolidation settlement occurs in 1 hour for a 25 mm thick clay specimen. This is an important parameter for calculating the coefficient of consolidation (Cv) using Terzaghi's theory. From the Cv value, we can estimate the time required for full consolidation settlement.
Secondly, we are given that the same clay settles 10 mm over 10 years and eventually settles a total of 35 mm over a longer period. This long-term settlement is known as the total primary consolidation settlement. By comparing this settlement value with the settlement data from the oedometer test, we can determine the thickness of the clay layer.
To calculate the thickness, we can use the concept of the consolidation settlement ratio. The ratio of the total primary consolidation settlement to the consolidation settlement at 50% completion is equal to the ratio of the total thickness to the thickness at 50% completion. Applying this ratio, we can determine that the thickness of the clay layer, which drains only from the upper surface, is approximately 87.5 mm.
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Which of the following rational functions is graphed below?
The correct option is C, The given graph represents the rational function \(\frac{1}{(x-1)(x-2)}\).
Explain graph.Mathematicians use graphs to variable logically depict or chart sentences or values in a visual way. Usually, a graph point shows the connection between two or more objects. A graph is a particular kind of non-linear side chain up of parts known as nodes as well as lines. The borders, also referred to as nodes, should be joined together with glue. The node numbers in this graph are 1, 2, 3, and 5.
Upon solving the given function,
\(\frac{1}{(x-1)(x-2)}\),
As, it is clear from the function that the value of x cannot be 1 or 2,
So,
The graph doesn't lie on x = 1 or x = 2.
So, it is the correct option.
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Come on y'all dont miss your shot At GETTING MARKET BRAINLIEST AND EXTRA POINTS
Answer:
(Part A) The formula for finding the area of a circle is πr². (Part B) The radius of that circle would be 5.27 m. 10.54 m cut in half would be 5.27 m. (Part C) The area of this circle would be approx. 87.21 m². Using the formula from Part A, first square 5.27. That will equal 27.7729. Now, multiply that by 3.14 (I used that value for π) to get 87.206906 m². However, we have to round to the nearest hundredth, so 87.21 m² is the answer.
Complete the table so that the cost per banana remains the same.
number of bananas cost in dollars
unit price
(dollars per banana)
4 $
$0. 50
6 $
$0. 50
7 $
$0. 50
10 $
$0. 50
$10. 00 $0. 50
$16. 50 $0. 50
To keep the cost per banana the same, the total cost must remain constant as the number of bananas changes. Therefore, for 4 bananas, the cost is $2, for 6 bananas, the cost is $3, for 7 bananas, the cost is $3.50, and for 10 bananas, the cost is $5.
To keep the cost per banana constant, we need to maintain the ratio of the total cost to the total number of bananas. In other words, the unit price (cost per banana) must remain the same regardless of the number of bananas purchased.
To fill out the table, we can use the formula:
Total cost = unit price × number of bananas
For example, for 4 bananas at a cost of $0.50 per banana, the total cost is:
Total cost = $0.50 × 4 = $2.00
To maintain the same cost per banana for 6 bananas, we need to adjust the unit price so that the total cost is the same as for 4 bananas:
Total cost = $2.00 = unit price × 6
Solving for the unit price, we get:
unit price = $2.00 ÷ 6 = $0.3333 ≈ $0.33 (rounded to two decimal places)
Similarly, for 7 bananas, the unit price must be adjusted so that the total cost is $2.00:
Total cost = $2.00 = unit price × 7
unit price = $2.00 ÷ 7 ≈ $0.29
For 10 bananas, the unit price must also be adjusted to maintain the same cost per banana:
Total cost = $2.00 = unit price × 10
unit price = $2.00 ÷ 10 = $0.20
Finally, for 16.5 bananas, we can use the same formula:
Total cost = $2.00 = unit price × 16.5
unit price = $2.00 ÷ 16.5 ≈ $0.12
Thus, we can fill out the table as follows:
number of bananas cost in dollars
unit price
(dollars per banana)
4 $
$0.50
6 $
$0.33
7 $
$0.29
10 $
$0.20
16.5 $
$0.12
So, we can see that by adjusting the unit price, we can maintain a constant cost per banana for different quantities of bananas.
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What is the measure of AngleC to the nearest whole degree?
Answer: the measure of angle c is 28 degrees
Step-by-step explanation:
5. How is each centimeter on a ruler further divided?
tenths
fourths
sixteenths
O eighths.
Help please urgent please
Answer:
DEA
Step-by-step explanation:
adjacent is next to and DEA is on line CF with CED
M<2=x+73
Find the value of x in the diagram
Answer:
x = -8
Step-by-step explanation:
The triangle is isosceles so the two angles are equal
Equation :
65 = x + 73
Subtract 73 from both sides
-8 = x
Check:
65 = -8 + 73
65 = 65
If my answer is incorrect, pls correct me!
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need answer fast in 5 minutes
Answer:
Each term in pattern B is 9 less than the corresponding term in pattern A.
Shelby made equal deposits at the beginning of every 3 months into an RRSP. At the end of 9 years, the fund had an accumulated value of $55,000. If the RRSP was earning 3.50\% compounded monthly, what was the size of the quarterly deposits? Round to the nearest cent
The size of the quarterly deposits in Shelby's RRSP account was approximately $147.40.
Let's denote the size of the quarterly deposits as \(D\). The total number of deposits made over 9 years is \(9 \times 4 = 36\) since there are 4 quarters in a year. The interest rate per period is \(r = \frac{3.50}{100 \times 12} = 0.0029167\) (3.50% annual rate compounded monthly).
Using the formula for the future value of an ordinary annuity, we can calculate the accumulated value of the RRSP fund:
\[55,000 = D \times \left(\frac{{(1 + r)^{36} - 1}}{r}\right)\]
Simplifying the equation and solving for \(D\), we find:
\[D = \frac{55,000 \times r}{(1 + r)^{36} - 1}\]
Substituting the values into the formula, we get:
\[D = \frac{55,000 \times 0.0029167}{(1 + 0.0029167)^{36} - 1} \approx 147.40\]
Therefore, the size of the quarterly deposits, rounded to the nearest cent, is approximately $147.40.
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A a) Is (x + 4) a factor of (x^ 2 +9x+20)? In other words , does x + 4 divide evenly into x ^ 2 + 9x + 20 ?
Answer:
Yes
Step-by-step explanation:
the factors of (x^ 2 +9x+20) are (x+4)(x+5)
Solve for x. The answer to each problem will match a letter that will allow you to figure out the joke. 1. 5x – 7 = 4x + 3
2. 6 + 2x = 7x – 9
3. 8x + 1 = -8 – x
4. -5 + 12x = 18x + 7
5. -4x + 3 = 5x – 13 - x
The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1. 5x – 7 = 4x + 3.
To solve for x, we can add 7 to both sides of the equation and subtract 4x from both sides:
5x - 7 + 7 = 4x + 3 + 7
5x = 4x + 10
x = 10
2. 6 + 2x = 7x - 9
To solve for x, we can add 9 to both sides of the equation, subtract 6 from both sides and divide both sides by -1:
6 + 2x + 9 = 7x - 9 + 9
2x = -3
x = -3/2
3. 8x + 1 = -8 - x
To solve for x, we can add x to both sides of the equation and add 8 to both sides:
8x + 1 + x = -8 - x + x + 8
9x + 1 = 0
x = -1/9
4. -5 + 12x = 18x + 7
To solve for x, we can subtract 12x from both sides of the equation and add 5 to both sides:
-5 + 12x - 12x = 18x + 7 - 12x
-5 = 6x + 7
x = -6
5. -4x + 3 = 5x - 13 - x
To solve for x, we can add x to both sides of the equation, subtract 3 from both sides and divide both sides by -1:
-4x + 3 + x = 5x - 13 - x + x + 3
-3x = -10
x = 10/3
The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3
That gives you the letters "joke"
Therefore, The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1. 5x – 7 = 4x + 3.
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(pythagorean theorem and the coordinate plane mc) determine the length of the line segment shown. line segment from negative 3 comma 10 to 4 comma negative 1 13 units 12 units 7 units 3 units
Using Pythagorean Theorem, the length of the line segment from (-3, 10) to (4, -1) is 13 units.
Pythagorean theorem describes the relationship between the sides of a right triangle. It states that the square of the hypotenuse is equal to the sum of the squares of the two other side.
c² = a² + b²
Let a = vertical distance between the two points
b = horizontal distance between the two points
c = distance between the two points / length of line segment
Hence, c² = (|y₂ - y₁|)² + (|x₂ - x₁|)².
Substitute the values of x and y and solve for c.
c² = (|y₂ - y₁|)² + (|x₂ - x₁|)²
c² = (|-1 - 10|)² + (|4 - -3|)²
c² = (|-11|)² + (|7|)²
c² = 11² + 7²
c² = 121 + 49
c² = 170
c = 13.04
length of line segment ≅ 13 units
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8+4=
write the answer below
Answer:
12
Step-by-step explanation:
USE LONG DIVISION
Divide.
(3x2 + 3x2 - 42x - 24) + (3x + 12)
Answer:
3x^2-39x-6
Step-by-step explanation:
because math easy
Help Solve
Multiplying Polynomials
10. −5w²(8w²x – 11wx²) + 6x(9wx^4 − 4w − 3x²)
Answer: 5x = 35 x 10-2. = 3.5 x 10-1. 3.5 x 10-¹. The exponent tells how many times 5 is multiplied to itself. Multiply the numbers and add the exponents.
Step-by-step explanation:
ZERO. Write the equation so one side of the equation is zero. ...
FACTOR. Factor the expression.
PROPERTY. Set each factor equal to zero and solve. ...
Check by substituting solutions into the original equation.
Calculate the mean: photo shown upon clicked ( very ez)
Answer:
11.3
Step-by-step explanation:
To find mean: All values added together divided by amount of values:
X: 11+12+13+14 = 50
50 / 4 (amount of values) = 12.5 (mean of x)
F: 8+3+17+12 = 40
40/4 (amount of values) = 10 (mean of f)
To find mean of x and f combined:
10 + 12.5 = 22.5
22.5 / 2 (amount of values) = 11.25 (mean of x and f combined)
To 1 dec pl.
= 11.3
Hope that makes sense
What is the solution?
The annual interest rate of the bank account is 3.1%.
Given:
After 5 years there is $673.40 in the account.
After 8 years there is $737.90 in the account.
Let x and A be the annual interest rate and Amount at first.
A(1+x)^5 = 673.40
A(1+x)^8 = 737.99
A(1+x)^8 / A(1+x)^5 = 737.99/673.40
(1+x)^3 = 1.0959
1+x = \(\sqrt[3]{1.0959}\)
x = 0.3099
x ≈ 0.031
x = 3.1%
Therefore The annual interest rate of the bank account is 3.1%.
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