Block and three cords. In the figure below, a block B of mass M-19.1 kg hangs by a cord from a knot K of mass my, which hangs from a ceiling by means of two cords. The cords have negligible mass, and

Diffraction is the change in a wave's direction as it travels around barriers. Diffraction is observed in both light and sound waves. This means that options 1 and 2 are wrong.

For any opening or slit, waves with longer wavelengths bend more than waves with shorter wavelengths. If the wavelength is smaller than the opening, it would be difficult for diffraction to occur. Thus, the correct option is

It occurs best when the slit width is less than the wavelength of a wave.

Answer:

Concave mirror

Explanation:

Because as we move the object far away from the mirror, the image gets inverted.

Answer:

Concave mirror

Explanation:

Answer:

147 newton.

Explanation:

Force is the product of mass and acceleration. The formula of force is given below: Force =  mass x acceleration, but due to height we put gravity instead of acceleration. So by putting values of mass i. e. 15 kg and gravity i. e. 9.8 meter/ second in the formula we get the net force of the ball which is 147 newton or 147 kg meter/second square.

Answer:

(a) The wavelength of the x-ray used to observe the first-order diffraction maximum is approximately 0.413 nm.

(b) The maximum number of orders that can be observed for this crystal at this wavelength is 1.

Explanation:

(a) To determine the wavelength of the x-ray used to observe the first-order diffraction maximum, we can use the Bragg's law, which relates the wavelength of the incident x-ray, the spacing between planes of atoms, and the angle of diffraction.

Bragg's law is given by:

nλ = 2d sinθ

Where:

n is the order of diffraction (in this case, n = 1 for the first-order diffraction)

λ is the wavelength of the x-ray

d is the spacing between planes of atoms

θ is the angle of diffraction (given as 12.6°)

Rearranging the equation to solve for λ, we have:

λ = (2d sinθ) / n

Substituting the given values:

d = 0.250 nm = 0.250 × 10^(-9) m

θ = 12.6° = 12.6 × π / 180 radians

n = 1

λ = (2 * 0.250 × 10^(-9) m * sin(12.6 × π / 180)) / 1

λ ≈ 0.413 × 10^(-9) m

(b) To determine the number of diffraction orders that can be observed, we need to consider the condition for constructive interference. For a given crystal, the number of orders that can be observed depends on the maximum value of n, which is determined by the crystal's characteristics and the wavelength of the incident x-ray.

In general, the number of orders that can be observed is given by:

n_max = 2d / λ

λ = 2 * 0.250 × 10^(-9) m * sin(12.6°)

λ ≈ 0.087 × 10^(-9) m

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Assuming that the electron-pair geometry of the two ball-and-stick representations is identical, the hybridizаtion of the centrаl аtom is sp².

The hybridization on the central atom would be governed by the type аnd number of electrons involved in the formаtion of the bonds between the centrаl аtoms аnd the outer аtoms.

Electron-pаir geometry determines the spаtiаl аrrаngement of а molecule's bonds аnd lone pаirs. If someone asked what the hybridization on the atom was, we would first draw the Lewis structure. We could then apply VSEPR to the Lewis structure to deduce that the molecular shape was linear and from this, we conclude that the hybridization of the atom is sp.

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The calculation of mercury's density requires the mass of the sample to be provided. Without the specific mass value given, I am unable to generate a precise answer.

However, the density of mercury is known to be approximately 13.6 grams per cubic centimeter (g/cm³) at room temperature.

Density is a measure of mass per unit volume. To calculate density, you need the mass and volume of the substance. The given information mentions the mass of the sample is missing, and therefore, a specific calculation cannot be performed.

However, it is worth noting that mercury is known to have a density of approximately 13.6 g/cm³ at room temperature. This means that for every cubic centimeter of mercury, it has a mass of 13.6 grams. The density of mercury is relatively high compared to other liquids, which is why it is a dense, heavy liquid.

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It takes 1.64 µs for the potential difference between the deflection plates to reach 60 volts.The electric potential difference across the capacitor and resistor will be equal to the applied potential difference, which is 100 volts.

Data from the question: Area of deflection plates = 10 cm x 2 cm = 20 cm²

Gap distance = 1 mm = 0.1 cm

Potential difference = 100 volts

Resistor = 925 ohm

We know that the capacitance of a capacitor can be given as,

C =ε₀A/d

Where, C = Capacitance, ε₀ = Permitivity of free space, A = Area of the capacitor plates, d = Gap distance between the plates.

Now, we can calculate the capacitance of the deflection plates as,

C = ε₀A/d = 8.85 × 10^-12 x 20 / 0.1 = 1.77 × 10^-9 F

Also, we know that,C = Q/V. Putting the given values in this equation,

1.77 × 10^-9 F = Q/100V

Thus, the charge on the plates can be given as,

Q = C × V = 1.77 × 10^-9 F × 100 V = 1.77 × 10^-7 C

Now, we know that Current I = V/R, Where V = Potential difference, R = Resistance. We can calculate the current flowing through the circuit as

I = V/R = 100/925 = 0.108 A

Now, we can calculate the time taken for the potential difference to reach 60 volts as,Q = It

Charge, Q = 1.77 × 10^-7 CT = Q/I = 1.77 × 10^-7 / 0.108 = 1.64 × 10^-6 s

Thus, it takes 1.64 µs. For the potential difference between the deflection plates to reach 60 volts. As the plates of the capacitor are connected to a resistor in series, we can assume that the potential difference across the capacitor is equal to the potential difference across the resistor. Therefore, the electric potential difference across the capacitor and resistor will be equal to the applied potential difference, which is 100 volts, after a long time.

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The position on the meter mark where Ari catches up with Amanda is 19.3 m.

The given parameters:

The distance between 6 m mark and 25 m mark is calculated as follows;

\(d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m\)

The distance traveled by Ari before catching up with Amanda is calculated as follows;

total ratio = 7 + 3 = 10

\(distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m\)

The position of Ari from the 6 m mark is calculated as follows;

\(position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m\)

Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.

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Answer:

The above answer is correct! The answer is 19.3 meters :)

Explanation:

adding a ss for proof!

hope this helps :D

A pressure vessel is fitted with a circular manhole. The cover plate has a diameter of 500mm. The minimum thickness of the plate is 0.416 m. The maximum stress in the cover plate is 2.5 MPa.

a) To solve for the integration constants in the boundary conditions, we need to consider the clamped support created by bolting the plate around the perimeter. For a clamped support, the boundary conditions are:

At the inner edge of the plate (where it is clamped), the radial displacement (u) and hoop stress (σθ) are zero.

u = 0

σθ = 0

At the outer edge of the plate (where it is clamped), the radial displacement (u) is zero, but the hoop stress (σθ) will be the service pressure of the vessel.

u = 0

σθ = P

b) To calculate the minimum thickness of the plate, we can use the formula for the deflection of a circular plate under uniform pressure. The maximum deformation should be within the permitted limit of 1.5 mm.

The formula for the deflection (δ) of a circular plate is given by:

δ = (P * \(r^2\)) / (E * \(t^2\))

where P is the pressure, r is the radius of the plate, E is the Young's modulus of the material, and t is the thickness of the plate.

In this case, we are given the diameter of the plate (500 mm), the service pressure (5 bar), and the maximum deformation (1.5 mm). We need to calculate the minimum thickness (t).

First, let's convert the pressure from bar to Pa:

P = 5 bar = 5 * \(10^5\) Pa

We can calculate the radius (r) of the plate:

r = diameter / 2 = 500 mm / 2 = 250 mm = 0.25 m

Now, we can rearrange the formula to solve for the thickness (t):

t = sqrt((P * \(r^2\)) / (E * δ))

t = sqrt((31.25 * 10^4) / (180 * 10^6))

t = sqrt(0.1736)

t ≈ 0.416 m

Therefore, the minimum thickness of the plate, considering a maximum deformation of 1.5 mm.

c) To calculate the maximum stress in the cover plate, we can use the thin-wall pressure vessel formula. The maximum stress occurs at the inner surface of the plate and is the hoop stress (σθ).

The formula for the hoop stress in a thin-wall pressure vessel is given by:

σθ = (P * r) / t

where P is the pressure, r is the radius of the plate, and t is the thickness of the plate.

Using the given service pressure (5 bar) and the radius of the plate (0.25 m), we can calculate the maximum stress (σθ).

σθ = (P * r) / t = (5 * \(10^5\) Pa * 0.25 m) / t = (1.25 * \(10^5\) Pa * m) / 2.5 * \(10^6\) Pa

= 2.5 MPa

Therefore, the maximum stress in the cover plate is 2.5 MPa (Megapascal). The stress is hoop stress (σθ) and it occurs at the inner surface of the plate.

d) The radial and hoop stress distribution across the radial direction of the plate can be represented by a graph. The radial stress (σr) will be zero at the inner and outer edges (clamped boundaries) and will vary linearly between them. The hoop stress (σθ) will be constant throughout the plate and equal to the service pressure.

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Answer:

9.8 meters per square second

Explanation:

Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.

The tool that is used to cause the frame eyewire to conform to the meniscus curve of the lens bevel is called a "rimless lens groover."

This groover is specifically designed to create a groove on the eyewire that matches the curvature of the lens bevel. By using this tool, opticians can ensure a precise fit between the lens and the frame, which is essential for rimless or semi-rimless eyewear. The grooving process involves carefully cutting a groove along the eyewire, allowing the lens to be secured in place. This tool helps achieve a seamless and comfortable fit for the wearer, as it allows the lens to sit securely within the frame while maintaining the desired aesthetic. Opticians are trained to use the rimless lens groover effectively and accurately to ensure optimal vision and overall satisfaction for the wearer.

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Answer:

2.66 m/s² .

Explanation:

Initial velocity , u = 0 m/s

Final Velocity , v = 8 m/s

Time Taken , t = 3 s

So , Acceleration = (v-u)/t = (8 m/s - 0 m/s) /3 sec . = 8/3 m/s² = 2.66 m/s²

Answer:

the true about n i b i n is they are Commissioner

Answer:

it was created by FBI and ATF

Explanation:

the closes thing I gound to an answer is:

NIBIN is a nationally networked system administered by ATF to assist law enforcement in solving firearms related violent crimes. IBIS is a collection of electronic images ofballistic evidence recovered from crime scenes and test-fired firearms that have been taken into law enforcement custody in the United States.

The speed of the proton can be calculated as:v = p/m = (1.08 × 10⁻¹⁸ kg m/s)/(1.67 × 10⁻²⁷ kg) = 6.46 × 10⁸ m/s. So, the speed of the proton at 10 MeV is 6.46 × 10⁸ m/s.

Relationship between energy in joules versus eV. The relationship between energy in joules and electron volts (eV) is defined by the conversion factor 1 eV = 1.6 × 10⁻¹⁹ joules. This factor is used to convert energy measurements from one unit to the other. If a proton has an energy of 10 MeV, we can use this conversion factor to determine its energy in joules.10 MeV = 10 × 10⁶ eV = 1.6 × 10⁻¹⁹ J/eV × 10 × 10⁶ eV = 1.6 × 10⁻¹³ J. Speed of a proton at 10 MeV.

The speed of a proton at 10 MeV can be calculated using the relativistic equation: E² = (mc²)² + (pc)², where E is the energy of the proton, m is its mass, c is the speed of light, and p is the momentum of the proton. Let's assume that the mass of the proton is 1.67 × 10⁻²⁷ kg. Then, the momentum of the proton can be calculated as follows:p = √(E² - (mc²)²)/c = √((10 × 10⁶ eV)² - (1.67 × 10⁻²⁷ kg × (2.998 × 10⁸ m/s)²)²)/2.998 × 10⁸ m/s = 1.08 × 10⁻¹⁸ kg m/s. The speed of the proton can be calculated as:v = p/m = (1.08 × 10⁻¹⁸ kg m/s)/(1.67 × 10⁻²⁷ kg) = 6.46 × 10⁸ m/s. Therefore, the answer is 10 MeV is 6.46 × 10⁸ m/s.

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∑ Hey, Lethality ⊃

Answer:

5.30 + 6.2=11.5

640 - 28.3 = 612

7,000 + 5=7005

8,000. - 6.0 = 7994

1.00 + 0.006=1.01

Explanation:

Given:

Add and Subtract these numbers using SIG FIGS. (Significant Figures)

5.30 + 6.2

640 - 28.3

7,000 + 5

8,000. - 6.0

1.00 + 0.006

Solution~:

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 3

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 3

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 4

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Number of significant figures: 4

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 3

-------------------------------------------------------------------------------------------------------------

xcookiex12

8/23/2022

Answer:

vf = 56.7 m/s

Explanation:

vi = 6.7 m/s

a = 5.00 m/s^2

t = 10 sec

vf = ?

a = (vf - vi )/t

5 = (vf - vi)/10

5 * 10 = vf - 6.7          

50 + 6.7 = vf

vf = 56.7 m/s

A(n) closed system is one in which energy moves freely in and out, but no matter enters or leaves the system.

You can have an open or closed system: A system that is totally cut off from its surroundings is referred to as a closed system. We have opted to adopt this definition because it is one that is frequently used in the system literature.

A closed system is one that only permits the transfer of energy within or outside the system but not the transport of matter. For instance, a beaker of evaporating water with a closed top permits the flow of energy to the environment but prevents the evaporation of (matter) water.

closed systems are also referred to as systems that don't allow anything other than energy to enter or exit. A closed water bottle functions as a closed system in this instance.

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The kWh used per week by the electric range whose voltage and current is 240 V and 11 A respectively is 18.48 kWh.

A kilowatt-hour is a unit of energy: one kilowatt of power for one hour. In terms of SI derived units with special names, it equals 3.6 megajoules (MJ).

To calculate the kWh per week of the electric range, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the kWh used per week is 18.48 kWh.

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Answer:

d

Explanation:

I'm not perfectly sure so check again

Answer:-00=;op

Explanation:poop

Answer:

450 hz X 4 = 1800

Explanation: Speed =

Wavelength (4) X frequency (450)

Im not 100% sure though

Answer:

Explanation:

I hope it helps ❤❤

(a) The resulting speed of the block is 1.71 m/s.

(b) The speed of the bullet-block center of mass is 0.554 m/s.

We can use the conservation of momentum principle to solve this problem, assuming that the collision is elastic and the system is isolated.

a. Let's first find the velocity of the block after the collision.

The momentum of the bullet before the collision is:

p₁ = mv₁

= (0.00480 kg)(672 m/s)

= 3.22 kg m/s

The momentum of the bullet after the collision is:

p₂ = mv₂

= (0.00480 kg)(420 m/s)

= 2.02 kg m/s

The total momentum of the system is conserved, so:

p₁ = p₂ + p₃

where p₃ is the momentum of the block after the collision. We can solve for p₃:

p₃ = p₁ - p₂

= 3.22 kg m/s - 2.02 kg m/s

= 1.20 kg m/s

The mass of the block is 0.7 kg, so its velocity after the collision is:

v₃ = p₃/m₃ = 1.20 kg m/s / 0.7 kg = 1.71 m/s

b. The speed of the center of mass of the bullet-block system can be found using:

v_cm = (m₁v₁ + m₂v₂)/(m₁ + m₂)

where m₁ and m₂ are the masses of the bullet and the block, and

v₁ and v₂ are their velocities before the collision.

We can assume that the block is initially at rest,

So v₁ = 672 m/s and v₂ = 0 m/s.

Substituting the values, we get:

v_cm = (0.00480 kg)(672 m/s) + (0.7 kg)(0 m/s) / (0.00480 kg + 0.7 kg)

= 0.554 m/s

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a. The period of the rock's revolution is 1.0 s / 7 = 0.14 s.

b. The speed of the rock when it leaves its circular motion is 61.9 m/s.

5. A sling having a total length of 1.40 m is used to launch a 90 g rock.

a. If the rock makes exactly 7 revolutions in 1.0 s, what is the period of the rock's revolution? Show your work.

The period of the rock's revolution is the time it takes for the rock to make one complete revolution. Since the rock makes 7 revolutions in 1.0 s, the period of the rock's revolution is 1.0 s / 7 = 0.14 s.

b. If the rock makes exactly 7 revolutions in 1.0 s, with what speed will the rock leave its circular motion? Show your work.

The tangential speed of the rock is given by the equation v = rω, where r = radius of the circle and ω = angular velocity of the rock.

The radius of the circle is the length of the sling, which is 1.40 m. The angular velocity of the rock is given by the equation ω= 2π/T , where T = period of the rock's revolution.

The period of the rock's revolution is 0.14 s, so the angular velocity of the rock is ω = 2π/0.14s = 44.2rad/s.

The tangential speed of the rock is therefore v = rω = (1.40m)(44.2rad/s) = 61.9m/s.

Therefore, the speed of the rock when it leaves its circular motion is 61.9 m/s.

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Answer:huh

Explanation:

Answer:

The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction: FA = −FB.

Answer:

1 an object at motion will remain at motion and a object at rest will remain at rest until a outward force acts upon it

2 force is equal to mass multiple acceleration

3 if an object is acted on with a downward force the object will reflect with a same net force in the opposite direction

Explanation: