Block 1, with mass m1 and speed 5.4 m/s, slides along an x axis on a frictionless floor and then undergoes a one-dimensional elastic collision with stationary block 2, with mass m2 = 0.63m1. The two blocks then slide into a region where the coefficient of kinetic friction is 0.53; there they stop. How far into that region do (a) block 1 and (b) block 2 slide? (a) Number Units (b) Number Units

Answers

Answer 1

In an elastic collision, the total momentum and total kinetic energy of the system are conserved. Initially, block 2 is at rest, so its momentum is zero.

Using the conservation of momentum, we can write the equation: m1v1_initial = m1v1_final + m2v2_final, where v1_initial is the initial velocity of block 1, v1_final is its final velocity, and v2_final is the final velocity of block 2.

Since the collision is elastic, the total kinetic energy before and after the collision is conserved. We can write the equation: 0.5m1v1_initial^2 = 0.5m1v1_final^2 + 0.5m2v2_final^2.

From these equations, we can solve for v1_final and v2_final in terms of the given masses and initial velocity.

After the collision, both blocks slide into a region with kinetic friction. The deceleration due to friction is given by a = μg, where μ is the coefficient of kinetic friction and g is the acceleration due to gravity.

To find the distance traveled, we can use the equation of motion: v_final^2 = v_initial^2 + 2ad, where v_final is the final velocity (zero in this case), v_initial is the initial velocity, a is the deceleration due to friction, and d is the distance traveled.

Using the calculated final velocities, we can solve for the distance traveled by each block (block 1 and block 2) in the friction region.

By plugging in the given values and performing the calculations, we can determine the distances traveled by block 1 and block 2 into the friction region.

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Related Questions

A student of 4 feet tall went for swimming in a pool. He saw the depth of water in the pole less than 4 feet .Will he sink , write with reason

Answers

Answer:

he will not be drowned

Explanation:

Question says , the height of the student = 4 feet,

Depth of the pool( in feet ) be x ( say ) which is less than  4 feet,

Clearly, the depth of the pool < height of the student,

This means, if the student goes for swimming in the pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.

A scuba diver fills her lungs to capacity (6.0 L) when 10.0 m below the surface of the water and begins to ascend to the surface. Assume the density of the water in which she is swimming is 1000 kg/{eq}m^3 {/eq} and use g = 10 m/{eq}s^2 {/eq}
A. Assuming the temperature of the air in her lungs is constant, to what volume must her lungs expand when she reaches the surface of the water?
B. What effect would the warming of the air in her lungs have on the volume needed when she surfaces?
C. Assuming the temperature of the air in her lungs is constant, what effect does her ascent have on the vrms of the air molecules in her lungs?

Answers

The lungs of a scuba diver should expand to a volume of 12 L, the volume of air in her lungs will grow with an increase in surface air temperature, and the rms speed of the air velocity in her lungs won't change.

It is stated that water has a density of 1000 kg/m3. The diver's 6L lung capacity allows her to descend 10m under the sea. We may suppose that the water's temperature is constant.

A. The pressure P₁ at the surface of water is 100000 Pa.

So, the pressure at the depth of 10m in water will be given by,

P₂ = 1000x10x10 + P₁

P₂ = 100000 + P₁

P₂ = 200000 Pa

Now, we can write,

P₁V₁ = P₂V₂

Putting values,

6 x 200000 = V₂ x 100000

V₂ = 12L.

Her lungs should thus enlarge to 12L.

B. Because of the continuous pressure at the surface, the air warming will further increase the amount of air in the lungs.

C. The Vrms are provided by,

Vrms = √(3RT/M)

The Vrms won't change if the temperature stays constant since the air's mass will remain constant.

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A student writes: “When I rub my dry hands together on a cold morning, they warm up. However, when I repeat this with soapy water my hands don’t warm up as much.” Explain these observations by considering the energy stores and transfers involved.

Answers

Answer:

Its not getting as hot because water and soap can act as a lubricant and it would not heat up easily because of the soapy water.

Answer:

there is less friction when your hands are soapy

Explanation:

By referring to Standard Method of Measurement 2 (SMM2), explain the following clauses:
i. D.10
ii. D.12.4
iii. D.12.6
iv. D.12.8

Answers

SMM2 refers to the Standard Method of Measurement 2. It is a document that specifies the method and processes used in measuring buildings and civil engineering works. SMM2 is commonly used in the construction industry.

The following are explanations of the clauses under Standard Method of Measurement 2 (SMM2):

i. D.10: This clause under SMM2 relates to the painting of metal and timber surfaces. It stipulates that when painting the surfaces of timber or metal, the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.

ii. D.12.4: This clause under SMM2 refers to the construction of walls using concrete blocks. It states that the concrete blocks used should have a minimum density of 1500 kg/m3. It also outlines specific measurements for the thickness of the mortar to be used for bonding the blocks together. The clause further specifies the measurement of the joint thickness between blocks.

iii. D.12.6: This clause under SMM2 refers to the rendering of walls with a cement mortar mix. It specifies that before rendering, the surface of the wall must be clean, dry, and free of debris. It also outlines specific measurements for the thickness of the rendering to be applied to the wall. The clause then stipulates that the rendering should be finished with a smooth surface that conforms to the architect's specifications.

iv. D.12.8: This clause under SMM2 refers to the painting of interior plastered walls. It stipulates that the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.

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A merry-go-round moves in a circle at a constant speed. Is the merry-go-round accelerating? Explain your answer.
Uniform Circular Motion:

Uniform Circular motion is the motion of a body that moves at constant angular velocity. Some examples of bodies that move at uniform circular motion are the blades of a fan set at a constant setting and the motion of a compact disc while the player is on.

Answers

The merry-go-round is accelerating since it is moving in a circle despite the fact that it is moving at a constant speed. The fact that an object moves in a circle does not always imply that it is moving at a constant speed. When an object moves in a circle, it changes direction, and this alteration of direction implies that the object is accelerating.

Even if the speed remains constant, it is still accelerating because the velocity is changing. This is referred to as centripetal acceleration. Centripetal acceleration is the acceleration caused by a force that pulls an object towards the center of the circle. Centripetal force is required for a body to move in a circle. A merry-go-round moves in a circle at a constant speed. This implies that the speed of the merry-go-round does not vary. However, the direction of motion changes continuously, indicating that the merry-go-round is constantly accelerating. Therefore, the merry-go-round is accelerating despite the fact that it is moving at a constant speed.

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Pleeeease help! I'll give brainliest if possible!! :)))

Use the scenario to answer the question.


An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.


In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.

Answers

The most scientific guess (hypothesis) based on what is known about the behavior of galaxies is that Galaxies are continuously moving away from each other. This hypothesis can be tested using Hubble's Law.

What does Hubble's Law Say?

Hubble's law indicates that almost all galaxies are moving apart from one another because the universe as a whole is expanding. Choose any two galaxies at arbitrarily, and they're most likely traveling apart from each other.

Hubble discovered that galaxies move away from us at a rate proportionate to their distance: more distant galaxies move away faster than closer ones. The accompanying graphic shows Hubble's classic graph of measured velocity vs. distance for neighboring galaxies.

The graph shows a linear relationship between galaxy velocity (v) and distance (d).

The equation for the above linear relationship is:

                                          v = H₀ x d

Where:

H₀ is the expansion rate

v = velocity of the galaxy; and

d = distance.

Using the above formula, the astronomer can measure or test to know whether indeed the new galaxy is moving relative to the Milky Way galaxy and at what rate.

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How is the frequency of the incident radiation (ν) related to its wavelength (λ) and speed (c)? (IMPORTANT MY MANNSSS)
A. ν = λ/c
B. ν = λc
C. ν = c/λ
D. ν = λc2

Answers

If we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

The correct relationship between the frequency of the incident radiation (ν), its wavelength (λ), and speed (c) is:

A. ν = λ/c

This equation is known as the wave equation and describes the relationship between the frequency, wavelength, and speed of a wave. It states that the frequency of a wave is inversely proportional to its wavelength and directly proportional to its speed. The speed of light (c) is a constant in a vacuum and its value is approximately 3.0 x 10^8 m/s.

Therefore, if we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

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The total mass of eight identical
building blocks is 31.52 kg. Find the
mass of 1 block.​

Answers

Answer:

3.94

Explanation:

divide total mass by the number of blocks since they are identical

Answer:

3.94

Explanation:

You want to find the mass of one block. Since we know there is 8 blocks with the same mass, you can divide the total mass by 8 since the mass is equally distributed within the 8 blocks

Why is our understanding of the exoplanet formation important

Answers

Our understanding of exoplanet formation is crucial for advancing our knowledge of planetary science, the origins of our own Solar System, the diversity of planetary systems, and the search for life beyond Earth.

1. Origins of the Solar System: Exoplanets provide valuable data and evidence that can help refine our understanding of how planets, including Earth, formed.

2. Planetary Diversity: The factors that contribute to the diversity and gain insights into the conditions necessary for the formation of habitable planets.

3. Habitability and Life: Understanding the conditions and processes that lead to the formation of habitable exoplanets.

4. Planetary Systems and Dynamics: dynamics and stability of planetary systems, including the interactions between planets and their host stars.

5. Evolution of Planetary Systems: Exoplanet formation provides information on the timescales and processes involved in the evolution of planetary systems

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Determine the acceleration of a boat with a final speed of 120 m/s after 30 seconds.

Answers

V=u+at
120=0+a*30
120=30a
a=120/30
a=4 m/s²

Answer:

ehehehshehehehhehesh

Explanation:

ehehehehheheheeheh

identify the forces on the car. check all that apply. identify the forces on the car.check all that apply. gravity f⃗ gf→g normal force n⃗ n→ friction f⃗ f→ drag f⃗ drag

Answers

Gravity, friction, and drag force are the forces that are acted on a car.

What are gravity, friction, and drag force?

Gravity is defined as a force by which one body attracts other objects toward its center. Friction is the force that resists the relative motion of solid surfaces, fluid, and material that are sliding against each other. There are several types of friction force i.e. Dry friction is a type of force that opposes the relative motion of two solid surfaces that are in contact with each other.

Drag is a mechanical force that is generated by the interaction and physical contact of a solid body with a liquid or gas. It is not produced by a field force, gravitational field, or an electromagnetic field, in which one object can affect another object without any physical contact with each other.

So we can conclude that the forces acting on the car are gravity, friction and drag force.

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A wave makes 44 cycles in 10 seconds, what is the frequency

Answers

If any wave makes 44 cycles in 10 seconds, then it has a frequency of 4.4 Hz.

The frequency of a wave is the number of cycles it completes in one second. It is measured in Hertz (Hz). To calculate the frequency of a wave, you can use the formula:
Frequency = Number of cycles / Time in seconds

In this case, the number of cycles is 44 and the time is 10 seconds. So, the frequency of the wave is:
Frequency = 44 cycles / 10 seconds

Frequency = 4.4 cycles/second

Frequency = 4.4 Hz

Therefore, the frequency of the wave is 4.4 Hz.

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what three things would you like to improve in your way of being towards others today if you knew that you would be born again?​

Answers

Answer: I would stop been shy, so I could be able to say what I think to others.  I would be nicer to others, behave better. I would share more with others.

A trebuchet fired a tennis ball with an initial velocity. Determine the following

A trebuchet fired a tennis ball with an initial velocity. Determine the following

Answers

ANSWER

\(\begin{gathered} (a)\text{ }12.61\text{ }s \\ (b)\text{ }194.73m \\ (c)\text{ }608.57\text{ }m \\ (d)\text{ }78.4\text{ }m\/s \end{gathered}\)

EXPLANATION

Parameters given:

Initial velocity, v0 = 78.4

Angle of projectile, θ = 52 degrees

(a) To find the flight time of the tennis ball, apply the formula:

\(t=\frac{2v_0\sin\theta}{g}\)

where g = acceleration due to gravity

Hence, the total flight time of the tennis ball is:

\(\begin{gathered} t=\frac{2*78.4*\sin52}{9.8} \\ t=12.61\text{ }s \end{gathered}\)

(b) To find the maximum altitude of the ball during its flight, apply the formula:

\(H=\frac{v_0^2\sin^2\theta}{2g}\)

Therefore, the maximum height attained by the tennis ball is:

\(\begin{gathered} H=\frac{78.4^2*\sin^2(52)}{2*9.8} \\ H=194.73\text{ }m \end{gathered}\)

(c) To find the horizontal distance the tennis ball travels, apply the formula:

\(R=\frac{v_0^2\sin2\theta}{g}\)

Hence, the horizontal distance traveled by the tennis ball is:

\(\begin{gathered} R=\frac{78.4^2*\sin(2*52)}{9.8} \\ R=608.57\text{ }m \end{gathered}\)

(d) To find the final velocity of the tennis ball, apply the formula:

\(v=\sqrt{v_0^2+2h(-g)}\)

where h = initial height = 0 m

Hence, the final velocity of the tennis ball just before impact is:

\(\begin{gathered} v=\sqrt{78.4^2+2(0)(-9.8)} \\ v=\sqrt{78.4^2+0}=\sqrt{78.4^2} \\ v=78.4\text{ }m\/s \end{gathered}\)

a body of mass 10 kg is moving at a constant speed of 20 m s over a frictionless surface the work done by the weight is
a)200j
b)100j
c)0j
d)300j​

Answers

Answer:

200j

Work Done=Wieght×Speed

10×20

Noether's theorem asserts a connection between invariance principles and conservation laws. In Section 7.8 we saw that translational invariance of the Lagrangian implies conservation of total linear momentum. Here you will prove that rotational invariance of ,C implies conservation of total angular momentum. Suppose that the Lagrangian of an N-particle system is unchanged by rotations about a certain symmetry axis.


Required:

Without loss of generality, take this axis to be the z axis, and show that the Lagrangian is unchanged when all of the particles (labelled by a) are simultaneously moved from (ra, θα,Pa) to (Ta, θα, φα +e).

Answers

Invariance principles and conservation laws are connected by Noether's theorem. Invariance is the quality of something that remains the same regardless of change. In mathematical physics, this refers to a scenario where physical laws or properties remain unchanged under some specified transformation.

The Lagrangian is a mathematical model used to derive the equations of motion of a system of particles or fields. The theory of rotational invariance states that the Lagrangian is unchanged under rotations about a particular symmetry axis.Suppose that the Lagrangian of an N-particle system is unchanged by rotations about a certain symmetry axis.

Without loss of generality, let this axis be the z-axis. We need to show that the Lagrangian is unchanged when all the particles (labelled by a) are moved simultaneously from (ra,θα,Pa) to (Ta,θα,φα+e).For a single particle, the Lagrangian L does not change under rotation, as long as the motion is confined to a plane.

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A 60-kg swimmer suddenly dives horizontally from a 150-kg raft with a speed of 1. 5 m/s. The raft is initially at rest. What is the speed of the raft immediately after the diver jumps if the water has negligible effect on the raft?

Answers

The speed of the raft immediately after the diver jumps is 0.6 m/s.

After the swimmer jumps, the momentum of the system is still conserved, but it is no longer zero, since the swimmer is now moving. We can use the equation:

(m1v1 + m2v2)before = (m1v1 + m2v2)after

We want to solve for v2, velocity of the raft immediately after the jump.

Before jump, velocity of  raft is zero, so we can simplify  equation to:

m1v1 = m2v2

Substituting in  values we know, we get:

60 kg * 1.5 m/s = 150 kg * v2

Simplifying, we get:

v2 = (60 kg * 1.5 m/s) / 150 kg = 0.6 m/s

So the speed of the raft immediately after the diver jumps is 0.6 m/s.

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Please help I will send pics in return or I will mark brainliest (depending on what u want) for a good attempt and explanation.

Please help I will send pics in return or I will mark brainliest (depending on what u want) for a good

Answers

The answer would have to be 8.47 m/s/s because the backwards pull + the rate of speed it is going would have to be added to get the answer to compensate for the backwards pull

an electrically charged object can be used to attract:

Answers

An electrically charged object can be used to attract any object with an opposite charge.

This is due to the fundamental principle that opposites attract and repel in physics.

Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.

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A child is on a playground they start to slide down a large slide. At what point is the child in dynamic equilibrium with the slide?(1 point) responses when the child pushes themselves down the slides. When the child pushes themselves down the slides. As the child is in motion as they are sliding down. As the child is in motion as they are sliding down. When the slide ends and the child has stopped moving. When the slide ends and the child has stopped moving. The child will not reach dynamic equilibrium.

Answers

When two surfaces glide past one another, a force known as friction is created.Friction forces that oppose the motion of moving objects cause them to expend energy and slow down.

What is the role of sliding friction in the movement?

An object rolls on a surface, creating rolling friction. When two surfaces rub against one another, sliding friction occurs. The deformation of surfaces causes rolling friction. Because tiny surfaces connect, sliding friction occurs.

Therefore, When the child pushes themselves down the slides. As the child is in motion as they are sliding down.

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Answer:When the child pushes themselves down the slides.

Explanation: i think im not sure

12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.

Answers

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

a. The power necessary to maintain the speed of 15ms^-1 can be found using the equation for power, P = Force * velocity, where P is in watts, force is in newtons and velocity is in meters per second. Substituting the values given in the question, we get:

P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts

Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.

b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:

F = 400 + k * 30^2

F = 12000 N

Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.

c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:

P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts

Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.

This waterbottle has a mass of .5 kg. If the net force acting on the bottle is five and to the right what is the bottles acceleration (hint: use formula a=f/m

Answers

Answer:

a = 10/s^2

Explanation:

Answer:

a=10 m/s *2 right

Explanation:

The net force (0.5 kg) divided by the mass (5 N) = 10

The force moved the object to the right.

So you Would put this in the equation a=___ m/s *2 _____

And you would get a=10m/s*2 right

HOPE YOU LEARNED SOMETHING SO WHEN WE GO BACK TO SCHOOL YOU WILL KNOW WHAT YOU ARE TALKING ABOUT ! : )

You have been asked to measure the temperature of a motor using a Negative Temperature Coefficient (NTC) thermistor with a nominal resistance of 10kΩ at 25 oC room temperature. You have access to an NI 6008 DAQ board with an analog input impedance of 144 kΩ. Please draw the circuit diagram that you will use to conduct this measurement below and calculate the percent error you expect in your voltage reading due to the loading effect.

Answers

In the circuit:(given in the attachment)

Vcc: Power supply voltage for the NTC thermistor.NTC Thermistor: The Negative Temperature Coefficient (NTC) thermistor with a nominal resistance of 10kΩ at 25°C room temperature.Analog Input: The analog input of the NI 6008 DAQ board.Signal Ground: The common ground for the circuit.

The loading effect occurs because the impedance of the DAQ board's analog input (144 kΩ) is in parallel with the NTC thermistor. This parallel combination affects the resistance and, consequently, the voltage divider formed by the NTC thermistor and the input impedance of the DAQ board.

To calculate the equivalent resistance of the parallel combination, we can use the formula:

1 / R equivalent = 1 / Rthermistor + 1 / Rinput

R equivalent = (Rthermistor * Rinput) / (Rthermistor + Rinput)

Substituting the values:

Requivalent = (10kΩ * 144kΩ) / (10kΩ + 144kΩ)

= 1.333kΩ

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The correct question is given below-

You have been asked to measure the temperature of a motor using a Negative Temperature Coefficient (NTC) thermistor with a nominal resistance of 10kΩ at 25 oC room temperature. You have access to an NI 6008 DAQ board with an analog input impedance of 144 kΩ. Please draw the circuit diagram that you will use to conduct this measurement below and calculate the equivalent resistance.

You have been asked to measure the temperature of a motor using a Negative Temperature Coefficient (NTC)

What are the dangers of a hurricane and how do you stay safe during the hurricane

Answers

Answer

hdhcu very much xbeyxbuxbduxb shx

work done ona closed system consisting of 2 kg of water initially at 160 oc, 10 bar undergoes an internally reversible, isothermal expansion during which there is energy transfer by heat into the system of 2700 kj. determine the work done, in kj. the system is negative or positive

Answers

The work done on the closed system consisting of 2 kg of water initially at 160°C and 10 bar, undergoing an internally reversible, isothermal expansion with energy transfer by heat into the system of 2700 kJ, is positive and can be calculated as follows:

The given problem involves an isothermal process, which means the temperature of the system remains constant throughout the process. According to the first law of thermodynamics, for an isothermal process, the work done is equal to the heat transferred into the system.

Given:

Mass of water (m) = 2 kg

Initial temperature (T) = 160°C = (160 + 273.15) K = 433.15 K (converting to Kelvin)

Initial pressure (P) = 10 bar = 10 × 10⁵ Pa (converting to Pascal)

Heat transferred (Q) = 2700 kJ = 2700 × 10³ J (converting to Joules)

Since the process is isothermal, the work done (W) is equal to the heat transferred (Q) into the system, i.e., W = Q.

Substituting the given values, we get:

W = 2700 × 10³ J = 2700 kJ

So, the work done on the system is 2700 kJ, and it is positive as the heat is transferred into the system during the expansion process.

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In the circuit in the figure, the capacitors are completely uncharged. The switch is then closed for a long time. As shown, R₁ = 6Ω, R₂ = 40 Ω, R3 = 40 Ω and V = 20V. What is the potential difference (in V) across the R₂ resistor? A) 8; B) 6; C) 0; D) 4; E) 10;

Answers

Potential difference (in V) across the R₂ resistor is option E) 10

In the circuit given below, the capacitors are uncharged. The switch is then closed for a long time. R₁ = 6Ω, R₂ = 40 Ω, R3 = 40 Ω and V = 20V.

Find the potential difference across the R₂ resistor.Circuit Diagram:We can solve this question by following the below steps:

Step 1: Finding the Total Resistance

Let us assume the capacitors to be open circuit initially and solve the resistors R₁, R₂, and R₃ in series,

Rₛ.Rₛ= R₁ + R₂ + R₃= 6 + 40 + 40= 86Ω

Step 2: Calculating the Current

We can calculate the current flowing in the circuit by using Ohm's law, which is given as:

I = V/Rₛ = 20/86= 0.23A

Step 3: Finding the Potential Difference across R₂The potential difference across R₂ is given as:

V₂= IR₂= 0.23 × 40= 9.2V

Therefore, the potential difference (in V) across the R₂ resistor is 9.2V.

The option that matches the value is E. 10.

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match the columns

please answer this question
it's urgent​

match the columnsplease answer this question it's urgent

Answers

Answer:

1. b

2. e

3. a

4. c

5. d

hope dis helps ^-^

Please help mee.
A fisherman casts a lure toward the river at an angle of 25° above the horizontal. The lure reaches a maximum height of 2.9 m above where it was cast.

What is the initial velocity of the lure? Assume that the line exerts no appreciable drag force on the hook.​

Answers

Answer:

17.84 m/s.

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 25°

Maximum height (H) reached = 2.9 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =..?

Thus, we can obtain the initial velocity of the lure as follow:

H = u² sine² θ /2g

2.9 = u² × (sine 25)² / 2×9.8

2.9 = u² × (0.4226)²/19.6

Cross multiply

u² × (0.4226)² = 2.9 × 19.6

u² × (0.4226)² = 56.84

Divide both side by (0.4226)²

u² = 56.84/(0.4226)²

u² = 318.27

Take the square root of both side

u = √318.27

u = 17.84 m/s.

Therefore, the initial velocity of the lure is 17.84 m/s.

Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.

Answers

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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A skateboarder, with an initial speed of 2.1 m/s, rolls virtually friction free down a straight incline of length 20 m in 3.2 s. At what angle is the incline oriented above the horizontal?

Answers

The incline is oriented at an angle of approximately 10.8° above the horizontal.

We can use the equations of kinematics to determine the angle of the incline. The skateboarder is under the influence of gravity and has an initial velocity, so we can use the following equation to solve for the angle:\(d = v0t + 0.5at^{2sinθ}\)where \(d = 20 m, v0 = 2.1 m/s, t = 3.2 s, a = 9.81 m/s^2\) (acceleration due to gravity), and θ is the angle of the incline above the horizontal.Rearranging the equation, we get:\(sinθ = (2d - v0t^2)/2at^2\)Substituting the given values, we get:\(sinθ = (2(20 m) - (2.1 m/s)(3.2 s)^2)/(2)(9.81 m/s^2)(3.2 s)^2\)Simplifying, we get:sinθ = 0.188Taking the inverse sine of both sides, we get:θ = 10.8°Therefore, the incline is oriented at an angle of approximately 10.8° above the horizontal.

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