Birdman is flying horizontally at a
speed of 17 m/s and a height of 78
m. Birdman releases a turd directly
above the start of the field. How far
from the start of the field should the
robot hold the bucket to catch the
turd?
Answers
Answer:
68 m
Explanation:
Given that the horizontal velocity of the birdman = 17 m/s and
the height, h= 78 m.
The gravitational force is acting in the downward direction, so it will not change the horizontal speed.
The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.
Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, \(u_0=17\) m/s.
In the vertical direction, u = 0,
The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e
s= 78 m
Let t be the time taken to cover a distance of 78 m.
Now, applying the equation of motion in the vertical direction,
\(s=ut+\frac 12 at^2\)
where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.
Here, \(a=g=9.81 m/s^2\), so
\(78=0\times t +\frac 12 (9.81)t^2\)
\(\Rightarrow t^2=(78\times2)/9.81\)
\(\Rightarrow t = 4\) seconds.
Hence, the time taken to reach the ground is 4 seconds.
As the horizontal speed, \(u_0=17\) m/s, is constant throughout the journey, so
the horizontal distance covered by turd
\(= u\times t\)
\(= 17 \times 4 = 68\) m.
So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly above the start of the field.
Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.
Related Questions
The table below describes some processes in which food is changed as it travels through the digestive system.
Which of the processes describe only physical changes in the food particles?
Processes 1, 2, 3, and 4
Processes 1, 3, and 6
Processes 2, 5, and 6
Processes 1, 3, and 4
Answers
Answer:
processes 1,3, and 4
Explanation:
i think
Teeth tear the food, the tongue reforms the food, and the stomach muscles break the food into small pieces are physical changes. Therefore, option (4) is correct.
What is a physical change?A physical change can take place when the identity of the matter does not but some of the characteristics of the matter change. Physical changes of matter are categorized as reversible and irreversible in nature. For example, the freezing of water is a reversible physical change since the ice cube can melt again.
Physical change can be described as a kind of change where only the physical properties of substances such as solubility, color, odor, etc. can change. During physical changes, no chemical bonds are formed or broken between atoms.
The chemical nature and chemical composition of the matter remain unchanged during a physical change.
In the digestive system, the breaking of food by teeth, tongue, and stomach muscles is a physical change. The food mixed with acids and broken by enzymes is a chemical change.
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What is Newton's Second Law?
1.The attraction between objects
2.An object at rest tends to stay at rest and an object in motion tends to stay in motion unless acted upon by an unbalanced force
3.An object's acceleration depends on its mass and on the net force acting on it.
4.For every action there is an equal and opposite reaction
Answers
Answer:
An object's acceleration depends on its mass and on the net force acting on it.
Explanation:
Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.
Answer:
3.An object's acceleration depends on its mass and on the net force acting on it.
use the diagram to identify the four regions of the earthworm.
dorsal side:
ventral side:
anterior end:
posterior end:
here are some pictures
Answers
Answer:
Dorsal side:B
Ventral side:D
Anterior end:A
Posterior end:C
Explanation:
The four regions of the earthworm are, A is the anterior end,B is the dorsal side, C is the posterior end, and D is the ventral side.
What are earthworms?Earthworms are common soil dwellers who are both safe and useful. Earthworms help plants flourish by collapsing dead and decaying organic debris into rich humus soil.
They also aerate the soil and enhance flow by digging small canals and holes.
The four regions of the earthworm are;
A is the Anterior end
B is the Dorsal side
C is the Posterior end
D is the Ventral side
Hence all the regions are clearly defined with the help of digrame.
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Express the length of a marathon run of
26 mi 385 yd in meters.
Answer in units of m.
Answers
Answer:
1 mi = 5280 ft * 12 in/ft = 63360 in
A convenient conversion factor (to remember) is 1 m = 39.37 in
63360 in / (39.37 in / m) = 1609.3 m
26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m
The length of a marathon run of 26 miles 385 yards is approximately 42,195 meters.
To convert the length of the marathon from miles and yards to meters, we need to first convert the miles to meters and then convert the yards to meters.
1 mile is equal to 1609.34 meters. Therefore, 26 miles is equal to 26 * 1609.34 = 42195.84 meters.
1 yard is equal to 0.9144 meters. Therefore, 385 yards is equal to 385 * 0.9144 = 351.1376 meters.
Adding the length in meters for both miles and yards gives us a total of 42195.84 + 351.1376 = 42547.9776 meters.
Rounded to three significant figures, the length of a marathon run of 26 miles 385 yards is approximately 42,196 meters.
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Suppose a child swings around her straight arm about her shoulder joint at an angular velocity of 13 rad/s. If her arm is 40. 0 cm long, what is the speed of her hand?.
Answers
Suppose a child swings around her straight arm about her shoulder joint at an angular velocity of 13 rad/s. If her arm is 40. 0 cm long, the speed of her hand will be 5.2 m/s
Angular velocity is a vector quantity and is described as the rate of change of angular displacement which specifies the angular speed or rotational speed of an object and the axis about which the object is rotating.
since , angular velocity = speed / radius
given
angular velocity = 13 rad/sec
radius = arm length = 40 cm = 0.4 m
speed = angular velocity * radius = 13 * 0.4 = 5.2 m/s
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Dolphins, bats, and other animals use echolocation to determine the location of objects. How do blind people use echolocation to detect objects in their environment? What types of technologies and tools would be helpful?
Answers
Answer: Clicking sounds and clicking tools + hearing devices to help hear the clicks in loud situations
Explanation:
Some blind people have developed the ability to make clicking noises, either with their mouth or a clicker, and they can listen for the sound of it bouncing off objects around them. Based on the tone, volume, and depth of the click, these people can tell the distance, size, and sometimes material of an object. A clicking device would be a tool that is helpful, as well as any hearing aid that could allow the wearer to hear the clicks better or clearer in a loud environment. (Note: the sound could be anything. It does not have to be a click. Whistles, beeps, chirps, and other sounds also can work for people.)
The distance from Earth to the North Star is about 430 light-years. Which of the following statements describes why scientists use the light-year unit to measure distance in space?
A.) A light-year is very small and distance in space are very small
B.) A light-year unit is very small and the distance in space are very large
C.) A light-year unit is very large and distance in space are very small
D.) A light-year unit is very large and distance in space are very large
Answers
Answer:
D
Explanation:
D
In lab, you propel a cart with four known forces while using an ultrasonic motion detector to measure the cart's acceleration. Your data are as follows:Force, F(N) Acceleration, a(m/s2)0.25 0.50.5 0.80.75 1.31 1.8Is there another data point that would be reasonable to add, even though you made no measurements?
- (5m/s2, 5N)
- (2m/s2, 3N)
- (0m/s2, 0N)
- None of the above
Answers
Even though you did not take any measurements, (2m/s2, 3N) is another data point that would be fair to provide.
To determine if there is another reasonable data point that can be added, we can plot the force and acceleration data to see if there is a clear relationship between the two variables.
From the plot, we can find that there is a clear linear relationship between the force and acceleration data. We can also calculate the slope of the line using the formula:
slope = Δa / ΔF
where Δa is the change in acceleration and ΔF is the change in force. From the given data, we can use the first and last data points to calculate the slope:
slope = (1.8 m/\(s^2\) - 0.5 m/\(s^2\)) / (1 N - 0.25 N) = 3.6 m/\(s^2\)/N
Now, we can use the slope to predict the acceleration for another force value. For example, we can predict the acceleration for a force of 2 N:
a = slope * F = 3.6 m/\(s^2\)/N * 2 N = 7.2 m/\(s^2\)
Data point to add to the plot is (2 N, 7.2 m/\(s^2\))
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Hi could you please help me answer this question. This is grade 12 electricity
Answers
So here, we use the equation:
W = ΔKE + ΔPE
Recall that: KE = 0.5mv^2, and PE = qdΔV/D
ΔKE = 0.5m(v2)^2 - 0.5m(v1)^2, where v2 and v1 are Initial and final velocity respectively.
ΔPE = PE2 - PE1
PE2 = 0, since all energy is converted to other forms, mainly kinetic energy.
PE1 = q(d1)ΔV/D
Here, W = 0.
0 = 0.5m(v2)^2 - 0.5m(v1)^2 + 0 - q(d1)ΔV/D
Simplifying a bit, and knowing that d1 = D,
0 = 0.5m((v2)^2 - (v1)^2) - qΔV
Moving qΔV to the other side,
qΔV = 0.5m((v2)^2 - (v1)^2)
Dividing by q and isolating ΔV,
ΔV = 0.5m * ((v2)^2 - (v1)^2) / q
Now, we have ΔV, which is the electric potential difference, in terms of all the variables we know.
m = 9.1 * 10^-31
v2 = 1 * 10^6
v1 = 5 * 10^6
q = 1.602 * 10^-19 (this is a well known constant)
ΔV = 0.5*9.1*10^-31 * ((5*10^6)^2 - (1*10^6)^2) / 1.602*10^-19
Solving and simplifying all of this, we get that
ΔV = 68.25 V
\(0.5mv_2^2\text{ - 0.5mv}_1^2\)2. CHARLES MANSON WAS DIAGNOSED WITH
PERSONALITY DISORDER.
10 points
(A)NARCISSISTIC
(B) BIPOLAR
(C)ANTI-SOCIAL
(D)BORDERLINE
O Other
Answers
Answer:
The answer is C. anti social
Explanation:
Hope that helps!
A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons.
Answers
On a level ice surface, a 55-kilogram skater glides over it while being subject to a friction force of 11 newtons. The skater's acceleration is -0.2 m/s^2.
The force of friction acting on the skater can be calculated as follows:
friction = μ * N
where
μ = coefficient of friction between the ice and skates (assumed to be constant)
N = normal force, which is equal to the weight of the skater
N = m * g
where
m = mass of the skater (55 kg)
g = acceleration due to gravity (9.8 m/s^2)
By substituting the values, we get:
friction = μ * m * g = 11 N
Finally, the net force acting on the skater can be calculated as follows:
net force = friction = -11 N (opposite direction to motion)
The acceleration of the skater can be calculated using Newton's second law of motion:
a = F / m
= -11 N / 55 kg
= -0.2 m/s^2
The acceleration of the skater is -0.2 m/s^2.
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Note: The correct question would be as bellow,
A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons. Find the coefficients of static and kinetic friction between the skates and the ice.
Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b=7 and stiffness constant k=6. Suppose the external forces on the weight are: F ext
(t)=−6te −3t
+e −3t
. y ′′
+7y ′
+6y=−6te −3t
+e −3t
a) Show y(t)=te −3t
is a possible position function for this weight. y ′1
+7y ′
+6y=−6tc −3t
+e −3t
r 2
+7r+6=0
(r+a)(r+1)
e −6t
e −t
y=1e −4t
+1e −t
y ′
=−61)e −4t
+Ae t
y ′
=−609e −4t
+e −+
(6,6e −4t
)+Me −t
b) Find a general equation for all possible position functions. y=Ae −6t
+AC 2
=−6+e 3t
+e −3t
(10 points) c) Find the exact motion equation for this weight if its initial position is y(0)=3, and its initial velocity is v(0)=y ′
(0)=
Answers
a) y(t) = te⁻³ᵗ is a possible position function.
b) General equation: y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B).
c) Exact motion equation: y(t) = (23/5)e^(-2t) - (8/5)e^(-3t) + t(e^(-3t))(At + B), with initial conditions y(0) = 3 and v(0) = -7.
a) To show that y(t) = te⁻³ᵗ is a possible position function, we substitute it into the differential equation:
y(t) = te⁻³ᵗ
y'(t) = e⁻³ᵗ - 3te⁻³ᵗ
y''(t) = -6e⁻³ᵗ + 9te⁻³ᵗ
Substituting these expressions into the differential equation, we have:
-6e⁻³ᵗ + 9te⁻³ᵗ + 7(e⁻³ᵗ - 3te⁻³ᵗ) + 6(te⁻³ᵗ) = -6te⁻³ᵗ - e³ᵗ
Simplifying this equation, we find that both sides are equal, thus confirming that y(t) = te⁻³ᵗ is a possible position function.
b) The general equation for all possible position functions can be written as:
y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B)
c) Given the initial conditions y(0) = 3 and y'(0) = v(0) = -7, we substitute these values into the general equation and solve for the constants:
3 = C₁ + C₂
-7 = -2C₁ - 3C₂
Solving these equations, we find C₁ = 23/5 and C₂ = -8/5.
The exact motion equation for the weight is:
y(t) = (23/5)e⁻²ᵗ - (8/5)e⁻³ᵗ + t(e⁻³ᵗ)(At + B)
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Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b = 7 and stiffness constant k = 6. Suppose the external forces on the weight are: Fₑₓₜ(t) = - 6te⁻³ᵗ - e³ᵗ
y" + 7y' + 6y = - 6te⁻³ᵗ - e³ᵗ
a) Show y(t) = te⁻³ᵗ is a possible position function for this weight.
b) Find a general equation for all possible position functions.
c) Find the exact motion equation for this weight if its initial position is y(0) = 3, and its initial velocity is v(0) = y'(0) = -7.
which route would you run if there were little time on the clock and you were trying to move the ball up field
Answers
To advance the ball fast upfield, select a route that entails rushing straight up the field into the end zone, such as a go or fly route.
A vertical route is defined.A vertical route in football is a lengthy, straight receiver route that is run directly downfield. A vertical route, also called as a vertical stretch, fly route, go route, or streak route, is identical to the post route except that the receiver advances without cutting rather than cutting towards the goal posts.
A tilt and go route is what?Running a Slant route and a Go route in the same play is called the Sluggo. The receiver will begin by running a Slant before cutting it short and finishing with a Go. It's a path intended to trick the defence into believing it will be a quick route down the middle before attacking them deeply over the top.
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using a 673 nm wavelength laser, you form the diffraction pattern of a 1.11 mm wide slit on a screen. you measure on the screen that the 12th dark fringe is 9.91 cm away from the center of the central maximum. how far is the screen located from the slit?
Answers
The screen is located 0.937 m away from the slit.
The position of the nth dark fringe in the diffraction pattern of a single slit can be calculated using the following equation:
y_n = (nλL) / w
where y_n is the distance of the nth dark fringe from the center of the pattern, λ is the wavelength of the light, L is the distance between the slit and the screen, w is the width of the slit, and n is the order of the fringe.
In this problem, we are given that the wavelength of the laser is λ = 673 nm, the width of the slit is w = 1.11 mm, and the distance of the 12th dark fringe from the center of the pattern is y_12 = 9.91 cm.
We can rearrange the equation above to solve for the distance L between the slit and the screen:
L = (y_n * w) / (n * λ)
Substituting the given values, we get:
L = (9.91 cm * 1.11 mm) / (12 * 673 nm)
L = 0.937 m
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Which of these statements best describes what a scientist is?
Answers
A scientist is a person who is trained and educated in a scientific discipline, and who carries out research and experimentation in order to increase our understanding of the natural world
Who is a scientist?
Scientists may work in a variety of fields, including physics, chemistry, biology, earth sciences, and many others.
They use the scientific method to design experiments, make observations, and analyze data in order to test hypotheses and advance our knowledge of the world around us. Scientists also communicate their findings to other scientists and the general public through scientific publications and presentations.
Generally, we can conclude that a scientist is a person who is trained and educated in a scientific discipline, and who carries out research and experimentation in order to increase our understanding of the natural world
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Hai tiếp điểm hình trụ bằng đồng có đầu hình cầu bán kính R = 70mm, lực ép tiếp điểm F = 100N, Mô đun đàn hồi của đồng là 11.8 * 106(N/cm2). Cho biết: a = 0.86 * (F*R/E)1/3, điện trở suất của đồng là 1.62 * 10-8 (Ω/m), với tiếp điểm đồng thì hệ số K1 = 3,16.10-4 (ΩN1/2). Biết các giá trị ứng suất của đồng là: σdh = 38300 N/cm2; σdẻo = 45000 N/cm2; σd.Nát = 51000 N/cm2. Tính điện trở tiếp xúc trong trường hợp thỏa mãn điều kiện tản dòng lí tưởng và trong trường hợp thực nghiệm.
Answers
Answer:
5dhydydyeze6ese6z7zuezuze6ezyezyezzeze
angular momentum about the center of the planet is conserved. angular momentum about the center of the planet is conserved. true false
Answers
Assuming that the planet is a closed system with no external forces, the statement "angular momentum about the center of the planet is conserved" is: true.
Angular momentum is a physical quantity that is conserved in a closed system, meaning that it remains constant as long as no external forces act on the system. The angular momentum of an object is its tendency to keep rotating about an axis, and is determined by the object's mass, velocity, and distance from the axis of rotation.
In the case of a planet, its angular momentum is determined by the mass, velocity, and distance of all the objects that make up the planet. As long as there are no external forces, the planet's angular momentum will remain constant.
This principle can be applied to various planetary phenomena, such as the rotation of planets, the movement of asteroids, and the formation of planetary rings.
However, if there are external forces acting on the planet, such as gravitational or tidal forces from other celestial bodies, the conservation of angular momentum may no longer hold true.
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two buses are moving in the opposite directories with the velocities 36km/hr and 108km/hr .find the distance between them in 20 minutes.
Answers
The distance between the two buses is 48km.
Let us assume that the velocity of the first bus is 36 km/h and that of the second bus is 108 km/h.
To find the distance between them, we will consider that both buses move in opposite directions.
Distance travelled by bus 1 in 20 minutes = 36 km/h × 20 min ÷ 60 min/h = 12 km
Distance travelled by bus 2 in 20 minutes = 108 km/h × 20 min ÷ 60 min/h = 36 km
Total distance between them = distance travelled by bus 1 + distance travelled by bus 2= 12 km + 36 km= 48 km
Therefore, the distance between them in 20 minutes is 48 km.
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What is the displacement of the elephant between 0s and 16 s?
m
What is the distance traveled by the elephant between 0s and 16 s?
m
Answers
Answer:
Displacement is 9m
Distance traveled is 9m
What method would likely be used to separate a mixture of colored inks?
Answers
This technique is often used in forensic science to identify inks used in forged documents or other types of evidence.
One method to separate a mixture of colored inks is chromatography. Chromatography is a physical separation technique used to separate mixtures based on their molecular properties. In the case of colored inks, paper chromatography is a commonly used technique.
In paper chromatography, a small amount of the ink mixture is spotted onto a piece of chromatography paper, and the paper is placed in a container with a small amount of solvent (e.g. water, alcohol, or acetone). The solvent moves up the paper by capillary action, carrying the ink mixture with it. As the solvent moves up the paper, different components of the ink mixture are separated and are visible as colored bands.
The separation occurs because different components of the mixture have different affinities for the paper and the solvent. Components that are more soluble in the solvent will move up the paper more quickly, while those that are more attracted to the paper will move up more slowly. This results in a separation of the components based on their physical and chemical properties.
By comparing the separated bands of the ink mixture to those of known pure inks, the identity of each component in the mixture can be determined. This technique is often used in forensic science to identify inks used in forged documents or other types of evidence.
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A likely method to separate a mixture of colored inks is through chromatography, a technique used to separate components of a mixture. It separates the ink into its constituent colors by allowing a solvent to travel up a stationary phase like paper, carrying the ink mixture with it.
Explanation:A method that would likely be used to separate a mixture of colored inks is chromatography. Chromatography is a method used in chemistry to separate components of a mixture. It works by using a stationary phase and a mobile phase. In the case of ink separation, the ink mixture would be placed on a stationary phase (like paper), and a solvent (the mobile phase) would be allowed to travel up the paper. As the solvent travels, it moves the mixture along its path. Each component of the ink by their size, chemical properties, and interaction with the solvent and paper will move at different rates, thereby separating the ink into its constituent colors. This method is particularly useful in analyzing the chemical composition of inks and other similar mixtures.
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HELP ME PLSSS!!! WILL MARK BRAINLIEST!!
Answers
Answer:
D
Explanation:
calculate the volume occupied by 31.1 g of methane gas (ch4) at 25°c and 1.0 atm. r = 0.0821 l · atm/k·mol.
Answers
The volume occupied by 31.1 g of methane gas (CH4) at 25°C and 1.0 atm is approximately 48.05 L. To calculate the volume occupied by 31.1 g of methane gas (CH4) at 25°C and 1.0 atm, follow these steps:
1. Convert the mass of methane gas to moles:
Molecular weight of CH4 = 12.01 (C) + 4(1.01) (H) = 16.05 g/mol
Moles of CH4 = mass / molecular weight = 31.1 g / 16.05 g/mol ≈ 1.937 moles
2. Convert the temperature from Celsius to Kelvin:
T (K) = 25°C + 273.15 = 298.15 K
3. Use the Ideal Gas Law (PV = nRT) to calculate the volume:
V = nRT / P
Where:
- V is the volume of the gas
- n is the number of moles
- R is the gas constant (0.0821 L·atm/K·mol)
- T is the temperature in Kelvin
- P is the pressure in the atm
V = (1.937 moles) x (0.0821 L·atm/K·mol) x (298.15 K) / (1.0 atm) ≈ 48.05 L
So, the volume occupied by 31.1 g of methane gas (CH4) at 25°C and 1.0 atm is approximately 48.05 L.
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A bullet of mass 0.05kg has a speed 400.what is it's kinetic energy.
if the bullet hits a wall of which the average resistive force is 10000 newton.calculate the distance penetrated by the bullet.
Answers
Answer:
K.E =1÷2M×V^2
= 1÷2×0.05×(400)^2
= 4000
Explanation:
plzz help! i need it now!!!!
be 100% sure of the answer plzzz
Answers
The output work is always less than the input work because some of the input work is used to overcome friction
Answer:
Equal effort force
Explanation:
A class 1 lever has the support between the load and the effort hence the load tilts the plain at one end containing the support we would require an effort equal and opposite to the load to ensure movement .
A concave mirror of radius of curvature 40 cm is to be used to obtain a real image of an object. The image is to be one- third as large as the object. Where should the object be placed, and where is the image to be found?
Answers
Answer:
u = 80 cm and v = 80/3 cm
Explanation:
focal length f = +40/2 = 20 cm.
magnification m = v/u = 1/3, thus v = u/3
using 1/u+1/v=1/f gives 1/u=1/(u/3)=20
So u = 80 cm and v = 80/3 cm
A 3000 ww carbon dioxide laser emits an infrared laser beam with a wavelength of 10. 6 μmμm. how many photons are emitted per second?
Answers
The answer is photons are emitted per second \(n=1.599 \times 10^{23}$\)
\(E=p x t......(i)\)
and also
\(E=\frac{n h c}{\lambda}.......(ii)\)
\(E=$ Energy$\\P=P_{\text {ower }}$$\\t=$ time\)
\($\begin{aligned} \frac{n h c}{\lambda} &=p t \\ n &=\frac{p_{\lambda t}}{h c} \end{aligned}$\)
\($n=\frac{3000 \times 10.6 \times 10^{-6} \times 1}{6.626 \times 10^{-3} \times 3 \times 10^{8}}$\)
\(n=1.599 \times 10^{23}$\) photons parsec
What is carbon dioxide emits?
Most of the greenhouse gas emissions from this industry are carbon dioxide \($\left(\mathrm{CO}_{2}\right)$\), although there are also minor emissions of nitrous oxide \($\left(\mathrm{N}_{2} \mathrm{O}\right)$\) and methane \($\left(\mathrm{CH}_{4}\right)$\). These gases are generated when fossil fuels like coal, oil, and natural gas are burned to create power.To learn more about carbon dioxide emits visit:
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Find the temperature at the bottom of the Denmark Strait cataract fall which is 11, 500 feet tall. The water temperature on the top of the fall is 10.0 degree C.
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The temperature at the bottom of the Denmark Strait cataract fall, which is 11,500 feet tall, can be estimated based on oceanic thermal characteristics and the vertical temperature profile.
The temperature gradient within the ocean is typically around 0.01 to 0.03 degrees Celsius per meter. Assuming a conservative average of 0.02 degrees Celsius per meter, we can calculate the temperature change over the height of the fall. Given that the fall is 11,500 feet (approximately 3,505 meters) tall, the temperature difference between the top and bottom can be estimated as follows: 0.02 degrees Celsius/meter x 3,505 meters = 70.1 degrees Celsius. Starting from the water temperature at the top of the fall, which is 10.0 degrees Celsius, we can subtract the estimated temperature difference: 10.0 degrees Celsius - 70.1 degrees Celsius = -60.1 degrees Celsius. Therefore, the temperature at the bottom of the Denmark Strait cataract fall is estimated to be approximately -60.1 degrees Celsius. It's important to note that this is a rough estimation based on the assumed temperature gradient, and actual measurements may vary.
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researchers have measured the acceleration of racing greyhounds as a function of their speed; a simplified version of their results is shown in figure the acceleration at low speeds is constant and is limited by the fact that any greater acceleration would result in the dog pitching forward because of the force acting on its hind legs during its power stroke. at higher speeds, the dog's acceleration is limited by the maximum power its muscles can provide. a. what is the agent of the force that causes the dog to accelerate? b. if the dog's mass is , what is the average force acting on it during its initial acceleration phase? c. how far does the dog run in the first ?
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a. The agent of the force that causes the dog to accelerate is the contraction of its muscles, particularly the hind legs, during its power stroke.
b. If the dog's mass is m, the average force acting on it during its initial acceleration phase can be determined using Newton's second law, F = ma, where a is the acceleration. The average force is F = m × a.
c. The distance the dog runs in the first Δt can be calculated using the kinematic equation s = ut + (1/2)at^2, where u is the initial velocity (assumed to be 0 as it starts from rest), a is the acceleration, and t is the time.
a. The force that causes the dog to accelerate is generated by the contraction of its muscles, particularly the hind legs, during the power stroke. This muscular force propels the dog forward, initiating its acceleration.
b. According to Newton's second law (F = ma), the average force acting on the dog during its initial acceleration phase is directly proportional to its mass (m) and acceleration (a). So, the average force can be calculated as F = m × a.
c. To determine the distance covered by the dog in the first Δt, the kinematic equation s = ut + (1/2)at^2 is used. Assuming the dog starts from rest (u = 0), the distance can be calculated by substituting the acceleration (a) and the time interval (Δt) into the equation.
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As shown in the figure below, a cow walks leftward 15\,\text m15m15, start text, m, end text to eat some flowers, then walks rightward 25\,\text m25m25, start text, m, end text to munch on some apples. The cow walks a total time of 510\,\text s510s510, start text, s, end text.
Answers
Answer:
0.0196m/s
Explanation:
Since we are not ask what to calculate but we can calculate the cow's velocity.
Velocity = change in displacement/time
Change in displacement of the cow is +25-15 = 10m
Time taken = 510s
Velocity of the cow = 10/510
Velocity of the cow = 0.0196m/s
Hence the velocity of the cow is 0.0196m/s
Answer:
Explanation:
velocity=0.020
speed=0.078
5.what are typical operating temperatures (or at least the temperature available that can produce power) and pressures for orc?
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55°C (131°F) is typical operating temperatures (or at least the temperature available that can produce power) and pressures for orc.
Heat or cold is measured in terms of temperature. It demonstrates how heat energy naturally flows from a hotter body to a cooler body and may be expressed in terms of any number of arbitrary scales (one at a lower temperature). A match is burning at a far greater temperature than an iceberg, yet an iceberg has a substantially higher total heat energy than a match. Temperature is not the same as the energy of a thermodynamic system.
Temperature, along with pressure, density, and other like qualities, is referred to as an intense property as opposed to extensive features, such as mass or volume—one that is independent of the quantity of stuff being addressed.
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