besides u-235, another isotope that can undergo nuclear fission is

Answers

Answer 1

Besides U-235, another isotope that can undergo nuclear fission is Pu-239. U-235 and Pu-239 are the two isotopes that can sustain a chain reaction, which is necessary for nuclear power generation or nuclear weapons.

Nuclear fission is the process of splitting the nucleus of an atom into smaller fragments, releasing energy in the process.  The splitting of a uranium-235 or plutonium-239 nucleus releases a tremendous amount of energy. This energy is used to generate electricity in nuclear power plants and to propel nuclear submarines and aircraft carriers. Nuclear fission is also used in nuclear weapons, where the energy release is used to cause an explosion. Besides U-235 and Pu-239, other isotopes can undergo nuclear fission but are not suitable for nuclear power generation or weapons development because they either do not release enough energy or are too difficult to produce.

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Related Questions

Gravitational force between two masses m, and m, is represented as F Gm₂ m₂ 7 where = xi+yj + zk and Irl=√√x² + y² + z² G,m,, m₂ are nonzero constants and let's assume that I 0 a) Calculate curl of and divergence of F (4 points) b) Show the integral ffdf is path independent and calculate following (4 points) (11) 우리가 일반물리 시간에 중력장을 이용한 포텐셜은 위치의 함수라는 걸 배운게 기억이 날겁니다. 이 문제는 사실 vector function 에 대한 문제인데 (9.10.11 단원), 우리가 배운 수학적 도구를 가지고 한번쯤 생각해볼 필요가 있어서 넣었습니다.

Answers

Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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How were lion fish introduced to the areas around Florida

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Answer:

I think this will answer your question. This is information is not mine and this rightfully belongs to columbia.edu.

This brightly colored fish is native to the Indo-Pacific from Australia north to southern Japan and south to Micronesia.  The lionfish is usually found in coral reefs of tropical waters, hovering in caves or near crevices.  Native regions as well as Savannah, Georgia; Palm Beach and Boca Raton, Florida; Long Island, New York; Bermuda and possibly Charleston. In southern Florida and off the coast of the Carolinas in early to mid 1990s.

Answer:I really don't know sorry

Explanation:

formulas in the solutions.
1. The Hulk leaps upward, pushing the Earth down (and the Earth
pushes him up). Which of Newton's Laws is the Hulk most closely
demonstrating? Why this law?
Type here

Answers

Answer:

1) The Newton's law the Hulk is most closely demonstrating is the Third Law of motion

Newton's third law of motion states that action and reaction are equal and opposite.

2) The reason why the Newton's Law the Hulk is most closely demonstrating is the Newton's Third Law of Motion is that according to Newton's Third Law of motion, forces exist in pairs, the action of the Hulk when he leaps upward by pushing against the the Earth (which can be assumed stationary in relation to the Hulk), is equal to the reaction of the Earth, which moves down slightly, away from its initial position.

However, due to the large mass of the Earth, compared to the mass of the Hulk, the downward motion of the Earth due to the reaction force (equal to the force with which the Hulk leaps) is negligibly small, such that the Earth can absorb the Hulk's leap force by reacting mainly locally, at the leap point  by forming a crater, while the Earth in general, remains in the same place

Explanation:

31. TRUE or FALSE A cheese puff must contain C since CO2 was produced when it was burned,

I

Answers

Answer:

True

Explanation:

what is the difference between malleability and ductile ??

Please don't post invalid answer please..!!

Please post correct answer please..!!​

Answers

Answer:

A malleable material is one in which a thin sheet can be easily formed by hammering or rolling. ... In contrast, ductility is the ability of a solid material to deform under tensile stress.

what is the difference between malleability and ductile ??Please don't post invalid answer please..!!Please
what is the difference between malleability and ductile ??Please don't post invalid answer please..!!Please

a power loss ride through function is limited to _____ seconds.

Answers

A power loss ride through function is limited to 1-2 seconds.

Power loss function

Typically, the length of the power loss ride-through function is created to offer a long enough buffer time to bridge the gap between the power loss and the power restoration. It enables the system or gadget to securely shut down without causing a sudden disruption to operations.

The application requirements, system criticality, energy storage or backup power capacity, and the time needed for power restoration or alternative power source activation can all be used to establish the precise duration of the ride-through function.

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Two resistors have resistances r(smaller) and r(larger), where r(smaller) < r(larger). when the resistors are connected in series to a 12.0-v battery, the current from the battery is 1.57 a. when the resistors are connected in parallel to the battery, the total current from the battery is 10.5 a. determine the two resistances.

Answers

The two resistances are calculated to be R = 6.63 ohm and r = 1.01 ohm when two situations are given.

Let the two resistances are r and R.

When they are connected in series,

V = 12 V

i = 1.57 A

When they are joined in series, the equivalent resistance is

Rs = r + R

So, By using Ohm's law

V = i × Rs

Rs = V / i = 12 / 1.57 = 7.64 ohm

R + r = 7.64 ohm  ----(1)

When they are connected in parallel:

V = 12 V

i = 10.5 A

When connected in parallel, the equivalent resistance,

Rp = (R + r)/(R r)

So, By using Ohm's law

V = i Rp

Rp = V / i = 12 / 10.5 = 1.14 ohm ----(2)

(R + r)/(R r) = 1.14

By substituting the value of R + r from equation (1) in equation (2), we get

r R = 7.64/1.14

r R = 6.70 ohm² ----(3)

R - r = √[(R+r)² -4 R r] = √[ 7.64² - 4× 6.7] = √[ 58.37 - 26.8] = √ 31.57 = 5.62 ohm

R - r = 5.62 ----(4)

(1) + (4) = 2R = 13.26

So, R = 6.63 ohm

r = 1.01 ohm

Thus, the two resistances are R = 6.63 ohm and r = 1.01 ohm.

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Two particles, A and B, are in uniform circular motion about a common center. The acceleration of particle A is 8.5 times that of particle B. The period of particle B is 2.0 times the period of particle A. The ratio of the radius of the motion of particle A to that of particle B is closest to

Answers

The ratio of the radius of the motion of particle A to that of particle B is closest to 1:5 or 1/5.

The acceleration of the particle is given as;

a = v²/r

Where v is the velocity of the particle.

Hence, the ratio of the acceleration of the particles is given as;

a₁/a₂ = v₁²/v₂²... (1)

The period of a particle in uniform circular motion is given as;

T = 2πr/v

Where v is the velocity of the particle in circular motion.

Hence, the ratio of the periods of the particles is given as;

T₁/T₂ = r₁/r₂... (2)

From equation (1);

a₁/a₂ = v₁²/v₂²

Let us assume the velocity of the particle B to be V then;

8.5 = v₁²/V²

V = v₁/√8.5

Let the period of particle A be T, then from the question, the period of particle B is 2T.

T₁/T₂ = r₁/r₂

T/T2 = r₁/r₂

From equation (2);

T/T₂ = r₁/r₂

Let the radius of the particle B be r.

Then, the radius of particle A is;

8.5 = v₁²/V²

v₁²/V² = 8.5

v₁/√8.5 = 2.915v₂

v₁/v₂ = 2.915r₂ = r/2

r₁/r₂ = T/T₂ = 1/2r₁/r = 1/5

Therefore, the ratio of the radius of motion of particle A to that of particle B is 1:5, i.e. the closest to 1/5.

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PLS ANSWER CORRECTLY ASAP. What moon phase is 1 WEEK BEFORE first quarter moon? And what moon phase is 1 WEEK AFTER first quarter moon?

I have attached a picture below as well..

PLS ANSWER CORRECTLY ASAP. What moon phase is 1 WEEK BEFORE first quarter moon? And what moon phase is

Answers

Answer:

waxing cresent and waxing gibbous

Answer:

i think it is the full moon

Explanation:

tell me if am wrong

if the mass of an object doubles, the gravitational force between it and another object will double . if the distance between two objects doubles, the gravitational force between them will .

Answers

When the distance between two objects is doubled, the gravitational force between them is reduced by one-fourth.

Newton's law of gravitation states that an object attracts every other object in the universe with a force that is directly proportional to the product of their masses and inversely proportionate to their square distances from one other. This force may be thought of as gravitational attraction.

So, when we double the distance between the two objects then force will get reduced to one-fourth as according to newton's law of gravitation, force is inversely proportional to the square of the distance between them.

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The ground-state electron configuration of neon is 1s²2s²2p⁶ in this arrangement, how many of neon’s p orbitals are completely filled?.

Answers

The number of Neon’s p-orbitals that are completely filled in its ground state is 3.

In Neon's case, since its p-orbitals are located on the second energy level, it contains a total of three p-orbitals 2px, 2py and 2pz and all three of them are filled as there are 4 electrons in s orbital and in total of 6 electrons in its p-orbital, thus completely filling it.

This configuration with all the orbitals completely filled also makes it a noble gas. It is due to the fact that it has no extra orbital to exchange electron from other element and form a bond.

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Audent se when the stone me themelo CD The student semblance theo of the a) 2 shows the rings to them and 52.00 450 Mao Mass of Flo.2.1 Record the mass shown by the balance in Table 21 Table 2.1 object mas volumelom density in g/cm A 131 25 10.1​

Answers

Answer:huh

Explanation:

3. The distance from a makeup mirror to C (the radius of curvature) is 70 cm. How far from the mirror
can a person be and still see an upright, magnified image?

Answers

The far point from the mirror can a person be and still see an upright, magnified image is focus i.e. 35cm from mirror.

What is  radius of curvature?

The mirror is made out of a sphere which has its radius called the radius of curvature.

The focal length f is half of the radius of curvature R of the lens.

Given the radius of curvature is 70cm, then focal length will be 70/2 = 35cm.

The makeup mirror is a concave mirror which forms real and upright images. The magnified images are obtained when the object is placed between focus and mirror.

Thus, the far point is focus i.e. 35cm from mirror.

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A school bus in the oncoming lane of a 4-lane road is flashing. You should: * 1 point
-
O A. Stop until the flashing red lights turn off.
O B. Stop only if children are unloading:
O C. Wait until the flashing lights are yellow.
O D. Use caution as you pass the bus.

Answers

Answer:

A

Explanation:

and that is a very strange question in physics ...

it actually depends on what state you are in.

California for example requires all to stop unconditionally, I think. while in many other states it is the rule, if the 4-lane road is separating both driving direction by a barrier or raised intermediate area, you don't have to stop when going in the opposite direction.

so, it is either A or D depending on your state.

B and C never apply.

Answer:

Question

A school bus in the oncoming lane of a 4-lane road is flashing. You should:

\(====================================\)

ANSWER

A. Stop until the flashing red lights turn off.

\(====================================\)

#CarryOnLearning

(ʘᴗʘ✿)

Answer:

Question

A school bus in the oncoming lane of a 4-lane road is flashing. You should:

\(====================================\)

ANSWER

A. Stop until the flashing red lights turn off.

\(====================================\)

#CarryOnLearning

(ʘᴗʘ✿)

One molecule of calcium oxide, Cao, and one molecule of carbon dioxide, CO2, combine in a chemical reaction to form one
substance. Given that matter is neither created nor destroyed, which chemical formula is the product of this reaction? (1 point)
Ca2CO3
CaCO2
Ca203
0 CaCO3

Answers

CaCO3 is the product of this reaction

Here, we are required to determine which chemical formula is the product of the reaction between CaO and C02 given that matter is neither created nor destroyed.

The chemical formula of the product of this reaction is ; CaCO3.

The law of conservation of mass is the basis for the balancing of equations of chemical reactions.

The law states that matter( which is the building block of mass) can neither be created nor destroyed.

Therefore, in a reaction where one molecule of calcium oxide, CaO, and one molecule of carbon dioxide, CO2, combine in a chemical reaction to form one substance;

The chemical formula of the product of this reaction is ; CaCO3.

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explain pleease :( itsreally hard

explain pleease :( itsreally hard

Answers

Answer:

0.5V

Explanation:

The formula for the potential difference is V=W/Q where W is the work and Q is the charge.

10/5 = 0.5

Hope this helped!

Cell phones use electromagnetic radiation with energy of about 1.08J/mol photons. Calculate the wavelength and frequency that can be used to describe light with this energy.

Answers

We know that the energy of electromagnetic radiation is given by:

\(E=hf\)

where E is the energy, h is Planck's constant and f is the frequency. Before we can use this formula we need to convert the amount of energy given to J so let's do that:

\(1.08\text{ }\frac{J}{mol}\cdot\frac{1\text{ mol}}{6.022\times10^{23}}=1.793\times10^{-24}J\)

Now that we have the energy of the radiation, we plug it on the energy equation and solve for the frequency:

\(\begin{gathered} 1.793\times10^{-24}=6.63^\times10^{-34}f \\ f=\frac{1.793\times10^{-24}}{6.63\times10^{-34}} \\ f=2.704\times10^9 \end{gathered}\)

Therefore, the frequency of the cell phone electromagnetic radiation is:

\(2.704\times10^9\text{ Hz}\)

Now that we know the frequency we just need to remember that the frequency and wavelength of electromagnetic radiation are related by:

\(\lambda=\frac{c}{f}\)

Then we have:

\(\begin{gathered} \lambda=\frac{3\times10^8}{2.704\times10^9} \\ \lambda=0.111 \end{gathered}\)

Therefore, the wavelength is 0.111 m

when heated the temperature of a water sample increased from 15°C to 39°C. Is absorbed 41840 joules of heat. what is the mass of the sample

Answers

Answer:

Mass of water: 43 g

Explanation

hope it helps

A 0.140 kg baseball is thrown with a velocity of 28. m/s It is struck with an average force of 5000.0 N,which results in a velocity of 37.0 m/s in the opposite direction. How long were the bat and ball in contact?

Answers

Check the images.. it has a few different questions and answers! Hope it helps

A 0.140 kg baseball is thrown with a velocity of 28. m/s It is struck with an average force of 5000.0
A 0.140 kg baseball is thrown with a velocity of 28. m/s It is struck with an average force of 5000.0
A 0.140 kg baseball is thrown with a velocity of 28. m/s It is struck with an average force of 5000.0

4 WILL GIVE YOU BRAINLIST
Which sentence supports this claim:A handmade gift is more meaningful than a store-bought gift?

Handmade gifts are usually less expensive than store-bought gifts.

Handmade gifts remind the receiver of the gift not to be so greedy at gift-giving times of the year.

Handmade gifts tend to look less perfect than store-bought gifts.

Handmade gifts require more of the giver’s time and effort than store-bought gifts.

Answers

the last one, handmade gifts require more of the givers time!
The claim is looking for a statement that supports why handmade gifts are more meaningful.

So the answer is . . .

Handmade gifts require more of the giver’s time and effort than store-bought gifts.

This is the correct answer because putting effort and time into a gift to make it original and one of a kind makes a handmade gift more meaningful than going to the store finding a gift.

A+block+of+1.2kg+is+placed+on+an+included+plane+at+60°+to+the+horizontal.+Calculate.+a.The+force+that+will+make+the+block+to+slide+down+the+plane.B.The+coefficient+of+friction+.C.+The+normal+reaction+d.+The+friction+force

Answers

Answer:

a. 10.2 N b. 1.73 c. 58.8 N d. 10.2 N

Explanation:

a. The force that will make the block slide down the plane

This is the component of the block's weight along the plane F = mgsinθ where m = mass of block = 1.2 kg, g = 9.8 m/s² and θ = angle of incline = 60°.

So, F = mgsinθ = 1.2 kg × 9.8  m/s² × sin60°.= 10.18 N ≅ 10.2 N

b. The coefficient of friction

The coefficient of friction, μ = tanθ = tan60° = 1.73

c. The normal reaction.

This is equal to the vertical component of the block's weight. So, F = mgcosθ. Substituting the values for the variables from above, we have

F = mgcosθ = 1.2 kg × 9.8  m/s² × cos60°.= 58.8 N

d. The frictional force

Since the block does not slide, there is no net force on it. If f is the frictional force, then

F - f = ma. Since a = acceleration = 0,

F - f = 0

f = F = mgsinθ = 1.2 kg × 9.8  m/s² × sin60°.= 10.18 N ≅ 10.2 N

Identify each of the following coordination complexes as either diamagnetic or paramagnetic v(h2)6) 3

Answers

The coordination complex [V(H2O)6]3+ can be identified as paramagnetic. Paramagnetic substances are weakly attracted to a magnetic field and exhibit magnetic properties. Therefore, [V(H2O)6]3+ is paramagnetic.

Paramagnetic substances are attracted to a magnetic field due to the presence of unpaired electrons, whereas diamagnetic substances are not affected by a magnetic field as all the electrons are paired. To determine the magnetic nature of [V(H2O)6]3+, we need to examine the electron configuration of the central vanadium (V) ion.

Vanadium (V) has an atomic number of 23, and its electronic configuration in the ground state is [Ar] 3d3 4s2. When vanadium forms coordination complexes, it often utilizes its d-orbitals for bonding. In [V(H2O)6]3+, the vanadium ion is in a +3 oxidation state, which means it has lost three electrons from its neutral state. Therefore, we remove the electrons from the 4s and 3d subshells to obtain the electron configuration of [V(H2O)6]3+ as [Ar] 3d2.

The 3d2 configuration indicates that two of the five 3d orbitals of vanadium are occupied by electrons, leaving three unpaired electrons. Since [V(H2O)6]3+ has unpaired electrons, it is paramagnetic.

Identify each of the following coordination complexes as either diamagnetic or paramagnetic

[ZnCl4^2-]

[Pd(NH3)2CL2]

[V(H2O)6]3+

Ni(en)3]2+

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What is promising evidence of a habitat that might support life
on the planet Mars?
Detailed Answer please, will give thumb up rating definitely

Answers

A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using conservation of energy (start with Ebefore = Eafter).​

Answers

Answer:

\(mgh = \frac{1}{2} m {v}^{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} \: m. {s}^{ - 1} \)

Can y’all help me with these two please, thank you

Can yall help me with these two please, thank you

Answers

Explanation:

Question 4

Force is represented using letter F

the force formula f = ma

Question 5

mass = 0.43kg

acceleration = 49.4m/s²

Force = ?

Remember that force F = ma

Now substitute, F = 0.43 × 49.4 = 21.2N

20 points
A net force of 24 N is applied to an object for 5.0 s. The object is pushed a total of 5.2 m. What is the mass of the object? What equations will be used?

Answers

Answer:

S = V0 t + 1/2 a t^2      net distance traveled

5.2 = a/2 * 25

a = 10.4 / 25 = ,416 m / s^2

F = m * a

m = F / a = 24 / .416 = 57.7 N

A racer covers one lap of a 1200 meter track at a speed of 27 meters per second. How long does it take to ride one lap?

Answers

Answer:

44.44 seconds

Explanation:

You just do 1200/27

uppose a free-fall ride at an amusement park starts at rest and is in free fall. what is the velocity of the ride after 2.3 s? how far do people on the ride fall during the 2.3-s time period?

Answers

The velocity of the ride after 2.3 s is 22.54 m/s and the distance of fall is 25.291 m.

Velocity is the directional speed of an object in motion as a demonstration of its price of change in position as located from a selected frame of reference and as measured by a particular popular of the time.

Velocity is the top indicator of the location in addition to the rapidity of the item. it may be defined as the gap blanketed by means of an item in unit time. pace can be defined because of the displacement of the item in unit time.

Velocity is the quickness of movement or motion. A synonym is a celerity; an easier phrase is velocity. In physics, speed specifically refers to the size of the fee and the path of exchange in the position of an item. it's miles a vector amount that specifies both the speed of a frame and its path of movement.

For velocity:-

v = u + at

  = 0 + 9.8 × 2.3

  = 22.54 m/s

For distance:-

S = ut + 1/2at²

since the initial velocity is 0.

S =  1/2 at²

   = 1/2 × 9.8 × (2.3)²

    = 25.291 m

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A large spring requires a force of 100 n to compress it only 0. 010 m. What is the spring constant of the spring?.

Answers

The spring constant of the spring is 10,000 N/m.

What is the constant ?

The constant is a fixed value that does not change in response to external influences. It is often used in mathematics to represent a number that remains constant despite changes in the context or situation. In physics, constants are used to represent physical properties of matter, such as the speed of light or the force of gravity. In computing, constants are used to represent values that need to be used multiple times within a program. Constants can be used to improve code readability and maintainability, as well as to prevent errors associated with using the same value multiple times.

The spring constant, k, is a measure of how stiff the spring is; it is equal to the ratio of the force applied to the spring divided by the amount of displacement (or compression) of the spring. Therefore, the spring constant of the spring can be calculated as:

k = F/x

= 100 N/0.010 m

= 10,000 N/m

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Draw a ray diagram for a diverging lens that has a focal length of -10 cm when an object is placed 30 cm from the lens's surface. Calculate the position of the image and list the characteristics of the image.

Answers

Explanation:

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Draw a ray diagram for a diverging lens that has a focal length of -10 cm when an object is placed 30
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