belinda received a 3+ points on a problem on a quiz what is the absolute value of the number of points she received

The required percentage of the 30 intermediate-level questions is 20%.

Given that,
Practice questions for a textbook are marked with difficulty levels of easy, Intermediate, and difficult. 30 of the 149 practice questions are rated as intermediate, approximately what percentage of the questions are intermediate level is to be determined.

the percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Here,
the required percentage of the intermediate difficult question,
= 30 / 149 * 100
≈ 0.20 * 100
≈ 20%

Thus, the required percentage of the 30 intermediate level question is 20%.

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The inequality that describes how many movies Parv can buy is: n ≤ 10.025

Let's denote the number of movies Parv wants to buy as n. We are given that each movie costs $3.99. To determine the inequality that describes how many movies Parv can buy, we need to consider the amount of money he has remaining after purchasing the pack of games.

Parv starts with a $50 gift card and spends $9.99 on a pack of games. The remaining amount on the gift card is $50 - $9.99 = $40.01.

Now, let's consider the cost of n movies. Each movie costs $3.99, so the total cost of n movies would be n * $3.99.

Since Parv wants to buy the movies using the remaining amount on his gift card, we can set up the inequality:

n * $3.99 ≤ $40.01

This inequality states that the total cost of n movies, represented by n * $3.99, must be less than or equal to the remaining amount on the gift card, which is $40.01.

Simplifying the inequality further, we have:

3.99n ≤ 40.01

Now, if we want to solve for n, we can divide both sides of the inequality by 3.99:

n ≤ 40.01 / 3.99

Calculating this value, we have:

n ≤ 10.02506265664

Therefore, the inequality that describes how many movies Parv can buy is:

n ≤ 10.025

This means that Parv can buy a maximum of 10 movies, as he cannot purchase a fractional part of a movie.

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Answer:

the answer is C:

\(2 \times 10 { - }^{4} \)

Step-by-step explanation:

I hope this helps! ^^

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Answer:

X = 5

Step-by-step explanation:

x in (-oo:+oo)

x/8 = 0.625 // - 0.625

x/8-0.625 = 0

1/8*x-0.625 = 0 // + 0.625

1/8*x = 0.625 // : 1/8

x = 0.625/1/8

x = 5

x = 5

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

:)

Answer:

x = 5

Step-by-step explanation:

First convert the decimal to an improper fraction

That's

So we have

Multiply through by 8

That's

We have the final answer as

Hope this helps you

This is due to the fact that the merry-go-round's passengers are being held in orbit by a gravitational force similar to that experienced by stars in a galaxy. People riding on a merry-go-round that is spinning. Thus, option D is correct.

The action that would best model the role gravity plays in the motions of stars within a galaxy is D. People riding on a merry-go-round that is spinning.

This is because, like stars in a galaxy, the riders on the merry-go-round are experiencing a gravitational force that keeps them in orbit around a central point.

This force, which is proportional to the mass of the objects and inversely proportional to the square of the distance between them, is similar to the force that holds stars in orbit around the centre of a galaxy.

The other options do not accurately model this gravitational force in the same way as a spinning merry-go-round.

Therefore, people riding on a merry-go-round that is spinning.

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Y = (1/6)*e^5t  is  differential equation .

What exactly does differential equation mean?

An equation that connects one or more unknown functions and their derivatives is known as a differential equation in mathematics.  

                                     Applications typically use functions to describe physical quantities, derivatives to indicate the rates at which those quantities change, and differential equations to define a relationship between the two.

y′′−9y′+26y=e^(5t)

The characteristice equation of the differential equation is : r^2 -9r +26 =0

On solving we get the values of r=4.5 + 2.34i (z1) ,  4.5 - 2.4i(z2)--- (complex roots)

homogeneous solution is: yh = c1e^z1t + c2e^z2t

Plug  Y = Ae^5t in the ODE:

=   25Ae^5t -9*5Ae^5t +26Ae^5t =e^(5t)

25A -45A +26A =1 ;  6A = 1; A =1/6

Y = c1e^z1t + c2e^z2t  is a general solution but we wnata particular solution

So, simply Y = (1/6)*e^5t

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Answer:

to what?

Step-by-step explanation:

there's nothing

Carrie will run 12 laps around the gym.

Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication, and division.

Given that Paul runs two laps around the gym. Carrie runs 6 times as many laps as Paul.

If Paul runs 2 laps and Carrie runs 6 times as many laps as Paul, Carrie runs 6 times 2 laps.

The number of the laps covered by Carrie will be calculated as:-

Carrie = 2 x 6

Carrie = 12 laps

Therefore, Carrie runs 12 laps around the gym.

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The complete question is given below.

Paul runs two laps around the gym. Carrie runs 6 times as many laps as Paul. How many laps does Carrie run?

Answer:

3

Step-by-step explanation:

17 * 3 = 51

51 * 3 = 153

153 * 3 = 459

etc.

The value of the expression 9!/3! is 60480.

Option C is the correct answer.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

9!/3!

This can be written as,

9! = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 = 362880

3! = 3 x 2 x 1 = 6

Now,

9!/3! = 362880/6 = 60480

Thus,

The value of the expression 9!/3! is 60480.

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The null hypothesis for this test is that the mean ECLSE test score for the university is equal to 1200. The alternative hypothesis is that the mean is not equal to 1200.

To perform the test, you will need to calculate the t-statistic and the p-value. The t-statistic is calculated by:

t = (sample mean - hypothesized mean) / (sample standard deviation/sqrt (sample size))

In this case, the sample mean is 1180, the hypothesized mean is 1200, the sample standard deviation is 100, and the sample size is 100. Plugging these values into the equation gives:

t = (1180 - 1200) / (100 / sqrt(100)) = -20 / 10 = -2

Next, you will need to calculate the p-value. The p-value is the probability of observing a t-statistic as extreme as the one calculated, given that the null hypothesis is true.

To calculate the p-value, you will need to use a t-distribution table or a software package to find the t-critical value for a one-tailed test with 99 degrees of freedom (since you have a sample size of 100) and a significance level of 0.05. The t-critical value is the value that defines the rejection region for the test. If the t-statistic falls in the rejection region, you can reject the null hypothesis.

If the p-value is less than the significance level of 0.05, you can reject the null hypothesis and conclude that the mean ECLSE test score for the university is not equal to 1200 at the 95% significance level. If the p-value is greater than or equal to 0.05, you cannot reject the null hypothesis and cannot conclude that the mean is different from 1200.

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By applying interior angles of triangles concept, it can be calculated that:

Triangle is a 2D shape that is bounded by three sides and has three vertices.

The three interior angles of triangles will always have a sum of 180°.

ΔABC:

            ∠A + ∠B + ∠C = 180°

4x + (7x - 2) + (5x - 10) = 180°

                       16x - 12 = 180°

                              16x = 192°

                                  x = 12°

Thus, ∠A = 4x = 4*12 = 48°

∠B = 7x - 2 = 7*12 - 2 = 82°

∠C = 5x - 10 = 5*12 - 10 = 50°

ΔDEF:

     ∠D + ∠E + ∠F = 180°

3x + 18x + (5x - 2) = 180°

                26x - 2 = 180°

                      26x = 182°

                           x = 7°

Thus, ∠D = 3x = 3*7 = 21°

∠E = 18x = 18*7 = 126°

∠F = 5x - 2 = 5*7 - 2 = 33°

ΔGHI:

 ∠G + ∠H + ∠I = 180°

16x + 16x + 13x = 180°

                 45x = 180°

                      x = 4°

Thus, ∠G = 16x = 16*4 = 64°

∠H = 16x = 16*4 = 64°

∠I = 13x = 13*4 = 52°

ΔJKL:

                  ∠J + ∠K + ∠L = 180°

(x + 8) + (6x - 5) + (2x - 3) = 180°

                                    9x = 180°

                                      x = 20°

Thus, ∠J = x + 8 = 20 + 8 = 28°

∠K = 6x + 5 = 6*20 - 5 = 115°

∠L = 2x - 3 = 2*20 - 3 = 37°

ΔMNO:

∠M + ∠N + ∠O = 180°, if ∠M = x, then:

     x + 5x + 4x = 180°

                  10x = 180°

                      x = 18°

Thus, ∠M = x = 18°

∠N = 5x = 5*18 = 90°

∠O = 4x = 4*18 = 72°

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The nights required by Quinn in order to knit a total of 70 centimeters of the scarf is equal to 35.

The number of nights required by Quinn in order to knit a total of 70cm of the scarf can be calculated using multiplication. Multiplication can be described as one of the four basic arithmetic operations in which we perform the repeated addition of the same number or value. This problem can be solved using cross-multiplication as follows;

2 nights = 4 cm of scarf

x nights = 70 cm of scarf

70 × 2 = 4(x)

140 = 4(x)

x = 140 / 4

x = 35

Therefore, Quinn will have to spend 35 nights knitting in order to knit a total of 70 centimeters of the scarf.

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Answer:

y=6+x

Step-by-step explanation:

Answer:

250.8 is the answer

The observed allele frequencies for the T102C locus are as follows: T allele frequency = 0.388 and C allele frequency = 0.612.


To calculate the observed allele frequencies, we divide the number of occurrences of each allele by the total number of alleles observed.

In this case, the T allele is observed in 108 TT genotypes and 194 TC genotypes, giving a total of 108 + 194 = 302 T alleles. Similarly, the C allele is observed in 194 TC genotypes and 48 CC genotypes, giving a total of 194 + 48 = 242 C alleles.

To calculate the T allele frequency, we divide the number of T alleles by the total number of alleles: 302 T alleles / (302 T alleles + 242 C alleles) = 0.388 (or approximately 0.39).

Similarly, the C allele frequency is calculated as: 242 C alleles / (302 T alleles + 242 C alleles) = 0.612 (or approximately 0.61).

Therefore, the observed allele frequencies for the T102C locus are T allele frequency = 0.388 and C allele frequency = 0.612.

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the particular solution of the differential equation dy/dx = 3y + 7 satisfying the initial condition y(0) = 0 is y = -7/3 + 7/\(3e^{(3x)}.\)

To find the particular solution of the differential equation dy/dx = 3y + 7 satisfying the initial condition y(0) = 0, we can use the method of integrating factors.

First, let's rearrange the equation in the standard form:

dy/dx - 3y = 7

The integrating factor (IF) can be found by multiplying the entire equation by the exponential of the integral of the coefficient of y, which in this case is 3:

IF = e^(∫(-3)dx)

= \(e^{(-3x)}\)

Next, multiply both sides of the equation by the integrating factor:

e^(-3x) * dy/dx - 3\(e^{(-3x)}\) * y

= 7\(e^{(-3x)}\)

The left side of the equation can be rewritten using the product rule:

(d/dx)\((e^{(-3x) }\)* y) = 7\(e^{(-3x)}\)

Integrating both sides with respect to x:

∫(d/dx)(\(e^{(-3x)}\)) * y) dx = ∫7\(e^{(-3x)}\) dx

e^(-3x) * y = ∫7e^(-3x) dx

Using integration, we have:

e^(-3x) * y = -7/3 * e^(-3x) + C

Now, applying the initial condition y(0) = 0, we can substitute x = 0 and y = 0 into the equation:

e^(-3(0)) * 0 = -7/3 * e^(-3(0)) + C

0 = -7/3 + C

C = 7/3

Substituting C back into the equation:

e^(-3x) * y = -7/3 * e^(-3x) + 7/3

Dividing both sides by e^(-3x):

y = -7/3 + 7/3\(e^{(3x)}\)

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Writing x^4 + 5x^2 - 8 in quadratic form will result to

Quadratic equation involves having the variables to be in exponents of 2 as the maximum. That is making the equation degree 2

The equation x^4 + 5x^2 - 8 is rewritten by say

x² = y

then we have

y² + 5y - 8

The  equation in quadratic form is  y² + 5y - 8

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Answer:

c = 0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

5(2c−3)=3(3c−5)

(5)(2c)+(5)(−3)=(3)(3c)+(3)(−5)(Distribute)

10c+−15=9c+−15

10c−15=9c−15

Step 2: Subtract 9c from both sides.

10c−15−9c=9c−15−9c

c−15=−15

Step 3: Add 15 to both sides.

c−15+15=−15+15

c=0

The critical point is: (1,1) and the classification is found to be the saddle point.

To find the critical points for the given function f(x, y) = x² - 2xy + 2y² - 2y and to classify each of them as a local maximum, local minimum, saddle point, or none of these, we need to follow these steps:

Finding the critical points - we can do this by solving the system of equations obtained by setting the partial derivatives of the function to zero.

Classifying the critical points - we can determine the nature of each critical point by analyzing the eigenvalues of the Hessian matrix of the function at that point.

The Hessian matrix is the matrix of second-order partial derivatives of the function.

To start with, let's find the partial derivatives of f(x, y) with respect to x and y respectively:f_x(x,y) = 2x - 2yf_y(x,y) = -2x + 4y - 2

Next, we set these partial derivatives to zero to find the critical points of the function:2x - 2y = 0-2x + 4y - 2 = 0

Solving this system of equations, we get:x = 1, y = 1

We have only one critical point at (1,1).To classify this critical point, we need to find the eigenvalues of the Hessian matrix of f(x, y) at (1,1).

The Hessian matrix is given by:

Hf(1,1) = |f_xx  f_xy ||f_yx  f_yy|

wheref_xx = ∂²f/∂x²f_xy

= ∂²f/∂x∂yf_yx

= ∂²f/∂y∂xf_yy

= ∂²f/∂y²

We compute these second-order partial derivatives of f(x, y) to get:

Hf(1,1) = |-2  2 || 2  4 |

The eigenvalues λ1 and λ2 of Hf(1,1) satisfy the characteristic equation:

Hf(1,1) - λI = 0, where I is the identity matrix of order 2, and are given by:

λ² - (f_xx + f_yy)λ + (f_xx f_yy - f_xy f_yx) = 0

Substituting the values of the second-order partial derivatives of f(x, y) at (1,1), we have:

λ² - (-2 + 4)λ + (-2 x 4 - 2²) = 0

Simplifying,λ² + 2λ - 12 = 0

Solving for the roots of this equation, we get:

λ1 = -6 and λ2 = 2

Therefore, the critical point (1,1) is a saddle point of the function f(x, y).

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 $1.09 is Total return in investment   .

What is investment?

Investments are assets that are bought or invested in to increase wealth and set aside cash from hard-earned income or gain. The main purpose of an investment is to provide an additional source of income or to generate a profit over a certain amount of time.

                                Any strategy for producing future revenue might be referred to as an investment. This involves, among other things, purchasing securities such as bonds, stocks, or real estate.

Total return in dollars = Profit / Initial investment

Highest = $67

Lowest = $32

                         no of shares     price per share      value

                                    a                      b                       c = a * b

lowest price              1000                32                         32000

highest price             1000               67                          67000

profit = sale value - purchase value                                35000

Total return in investment                                                   $1.09

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Answer:

Inequality form: x < 1

Step-by-step explanation:

Answer:C

Step-by-step explanation:

Answer:

Its A

Step-by-step explanation:

the student has left 75 because if you add 5 and 70 it gives you $75 that's how much the student had left.

Point M(-6,8) is dilated from the origin with a scale factor of 1/2, hence the new point is M'(-3, 4)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

Given Point M(-6,8) is dilated from the origin with a scale factor of 1/2, hence the new point is at:

M'(-3, 4)

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Answer:

yes becasue their sides have the same length and angles

Step-by-step explanation:

Answer:

\(x^{15}\)

Step-by-step explanation:

Distribute the ^3 on top

(27 \(x^{6}\) \(y^{-9}\))

distribute the ^ -9 on bottom, only to what is in the parenthesis

(27 \(x^{-9}\) \(y^{-9}\))

the 27's cross out, the \(y^{-9}\) 's cross out

\(x^{6}\)/ \(x^{-9}\) is left

move the  \(x^{-9}\) to the top of fraction to change its sign

\(x^{6}\) · \(x^{9}\) = \(x^{15}\)

Answer:Arrow C

Step-by-step explanation:

Out of three arrows, nearest arrow from the origin will be the best arrow.

Ordered pair for arrow A → (-5, 4)

Distance between A and bullseye =

                                                   =  

                                                   =

                                                   = 6.40 units

Ordered pair for arrow B → (5, -5)

Distance between B and bullseye =

                                                        =

                                                        = 7.1 units

Ordered pair for arrow C → (-2, -6)

Distance between C and the bullseye =

                                                              =

                                                              = 6.32 units

Distance between C and the bullseye is the shortest.

Therefore, arrow C will be the best arrow.