Beginning with interphase, use the letters to order the following events:
A prophase
B telophase
C metaphase
D interphase
E anaphase

The pH of the salt depends on its anion and cation. The following is the breakdown of each salt:A. FeCl3Solution: acidic.

Explanation: Iron (III) chloride hydrolyzes in water to produce hydrogen chloride and iron (III) hydroxide. Hydrogen chloride is an acid, therefore a solution of iron (III) chloride is acidic.B. NaFSolution: pH neutralExplanation: Sodium fluoride is the salt that is formed from a weak base and a strong acid. Since the base is weak and the acid is strong, the salt is expected to have a basic anion and an acidic cation, making it pH neutral. C. CaBr2Solution: pH neutral.

Calcium bromide is an example of a salt that is formed from a strong acid and a strong base. Since both ions are neutral, the solution is pH neutral.D. NH4BrSolution: acidicExplanation: Ammonium bromide hydrolyzes in water to form hydrobromic acid and ammonium hydroxide. Since hydrobromic acid is an acid, a solution of ammonium bromide is acidic.E. C6H5NH3NO2Solution: basicExplanation: The anion of phenylammonium nitrate is nitrate ion, which is a weak base. Phenylammonium cation is acidic, but since nitrate is a weak base, the solution is basic. Therefore, the solution of C6H5NH3NO2 is basic.

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Answer:

33.3gtts/min

Explanation:

We can find the drops/minute with common proportions.

100cc/1hr * 200gtts/1cc * 1hr/60min ≈ 33.3gtts/min

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Answer:

180.6

Explanation:

N2 (g) + 2O2 (g) → 2NO2 (g)   ΔH = 66.4 kJ

2NO (g) + O2 (g) → 2NO2 (g)  ΔH = -114.2 kJ

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Answer:

39.948 u

Explanation:

Answer:

D

Explanation:

I think it is D

Answer:

Magnesium (Mg)

Explanation:

The amount of electrons displayed on this model is 12. Assuming that this is a neutral atom, the amount of electrons is equal to the atomic number of a given element. Therefore, 12 electrons correspond to the twelfth element on the Periodic Table, Magnesium.

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Answer:

Double displacement reaction

Explanation:

Given expression:

          KOH   +    AlCl₃   →   Al(OH)₃  +  KCl

The reaction shown above is a double displacement reaction or double decomposition or double replacement reaction. This type of reaction involves an actual exchange of partners to form new compounds.

For example:

         AB + CD  →   AD + CB

Such reactions are driving by one of the following factors:

To assign each species to a category on the right, we need to understand the properties of each term.

- Strong acids are defined as substances that completely dissociate in water to form H+ ions. Examples of strong acids include HCl, HNO3, and H2SO4.
- Weak acids are defined as substances that only partially dissociate in water to form H+ ions. Examples of weak acids include CH3COOH and H2CO3.
- Strong bases are defined as substances that completely dissociate in water to form OH- ions. Examples of strong bases include NaOH and KOH.
- Weak bases are defined as substances that only partially dissociate in water to form OH- ions. Examples of weak bases include NH3 and C5H11N.

With these definitions in mind, we can now assign each species to a category on the right:

- NaOH: This is a strong base because it completely dissociates in water to form Na+ and OH- ions.
- CH3COOH: This is a weak acid because it only partially dissociates in water to form H+ and CH3COO- ions.
- HI: This is a strong acid because it completely dissociates in water to form H+ and I- ions.
- C5H11N: This is a weak base because it only partially dissociates in water to form OH- ions.
- Clear: This term is not a chemical species and cannot be assigned to any category.

Note: It's important to understand the definitions and properties of each term in order to correctly assign species to their respective categories.

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Answer:palaentologists create a record of history showing how and why things died how and why they adapted to a new climate and why they went extinct giving the future and now ways to see how our climate will change what patterns animals will go through etc

Explanation:

Valence bond theory is one of the various theories used to describe how chemical bonding occurs. It is based on the idea that the formation of chemical bonds occurs as a result of the overlap between atomic orbitals in the valence shell. In the case of sulfur dioxide, SO2, valence bond theory predicts that sulfur will use three hybrid orbitals.

In the case of sulfur dioxide, SO2, valence bond theory predicts that sulfur will use three hybrid orbitals. It is because sulfur has six valence electrons. The hybridization of the orbitals takes place so that they can have the same energy, shape, and orientation for proper overlap. These orbitals combine to form a set of three hybrid orbitals. The valence bond theory is useful in understanding how chemical bonds are formed and how they affect the properties of molecules. It is widely used in the field of chemistry to explain the behavior of molecules and the reactions they undergo. The theory is also helpful in predicting the shapes of molecules and how they interact with other molecules in chemical reactions.

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For the partial pressure in mmHg of hydrogen gas  is mathematically given as

partial p = 257.81mmHg

Generally, the equation for the partial pressure is mathematically given as

partial p = mole of H2/total moles x total pressure

H2 =0.00206/2

H2 = 0.00103

O2 = 0.0811/32

O2 = 0.00253

H20 = 0.0151/18

H2O = 0.000839

total moles = 0.00103+0.000839+0.00253

total moles = 0.00439

therefore

partial p = 0.00103/0.00439 x 1101.1

partial p = 257.81mmHg

In conclusion, the partial pressure in mmHg of hydrogen gas is

partial p = 257.81mmHg

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Answer:

C

Explanation:

Answer C    Full moon occurs approx 2weeks after new moon

n SnCl₄ = m SnCl₄ / Mr SnCl₄

n SnCl₄ = 54.3 / 260.5

n SnCl₄ = 0.208 mol

n Na = V / 22.4 (at STP)

n Na = 23 / 22.4

n Na = 1.027 mol

Mole of Sn produced :

n Sn = (1/1) • 0.208

n Sn = 0.208 mol

m Sn = n Sn • Mr Sn

m Sn = 0.208 • 118.7

m Sn = 24.69 gr

a. substituting in the expression of C(t) obtained in part a, we get,2500 = 12000/ (1 + 12000/ 5000 - 1) * e^(-2*3*t)  we get,t = 1/ (6 * log (2)) * log (5/3)≈ 0.276 h Therefore, it would take approximately 0.276 hours to reduce this concentration into C/2.

The differential equation for the indoor concentration of the given computer industry can be given as follows: dC/dt = P (0- C) - 2C²The above differential equation can be solved by the method of separating the variables as follows: dC/ (P (0- C) - 2C²) = dtIntegrating both sides, we get,-1/ [2P log (C/ (C- P0))] + (P0/ [P (C- P0)]) - (1/ (2C)) = t + c where c is the constant of integration. After simplification, the above equation can be expressed as:C(t) = P0/ (1 + (P0/ Co - 1) e^(-2Pt))The initial particle concentration Co is the value of C at t = 0. Hence, Ce = P0/ (1 + P0/ Co - 1) which can be simplified as Ce = Co/ (1 + P0/ Co - 1) = Co/P0b. Given that Co = 5000 cm³ and C/2 = 5000/2 = 2500 cm³,

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Answer:Mendeleev realized that the physical and chemical properties of elements were related to their mass in a ‘periodic’ way.

Explanation: He arranged them so that the groups of elements with similar properties fell into vertical columns.

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Answer:glucose

Explanation:

Energy released during the breakdown of glucose and other organic fuel molecules from carbohydrates, fats, and proteins during glycolysis is captured and stored in ATP.

Answer:

I would say B

Explanation:

If I'm wrong I apologize, have a good day

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Answer:

Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

Explanation:

Refraction, or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.

A science project in Chemistry that students can carry out is the construction of an electrochemical cell.

Science projects are projects which  are carried out by students as part of their assessment or to improve and enhance their knowledge and ideas about scientific concepts.

A science project in Chemistry that students can carry out is the construction of an electrochemical cell.

An electrochemical cell is a cell that coverts chemical energy to electrical energy.

In conclusion, science projects helps students to develop their own skills in scientific research.

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Answer:

Invention

Explanation:

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Answer:

Explanation:

Here, we want to get how the final digit in a measurement is obtained

Mathematically, the final digit can be obtained by estimation

Hence, we say that the value is uncertain

The final digit is obtained by a mark or between the last mark and the next mark in a measurement

Thus, we call this value uncertain since it is estimated

Alkenes are useful in the production of polymers. They create polymers when smaller molecules are arranged end to end. The smallest molecules are known as monomers. The polymer's tensile strength grows as chain length and cross-linking do.

A monomer is a molecule from a group of substances, primarily organic compounds, that can combine with other molecules to produce much larger molecules, or polymers. A monomer's ability to create chemical interactions with at least two other monomer molecules, known as polyfunctionality, is its primary characteristic.

Monomers include substances like ethylene, amino acids, vinyl chloride, and glucose. Each monomer has a different manner of linking to create a variety of polymers.

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Explanation:

To find the freezing point of the solution, we can use the freezing point depression equation:

ΔT = Kᵣ x m

Where ΔT is the change in freezing point, Kᵣ is the freezing point depression constant of benzene, and m is the molality of the solution.

Substituting the values from the problem, we get:

ΔT = 5.12 °C/m x 2.8 m

ΔT = 14.34 °C

Since ΔT = Tᵢ - T, where Tᵢ is the freezing point of the solvent (benzene) and T is the freezing point of the solution, we can rearrange the equation to solve for T:

T = Tᵢ - ΔT

T = 5.50 °C - 14.34 °C

T = -8.84 °C

Therefore, the freezing point of the solution is -8.84 °C.

Answer:The freezing point of the solution is -8.84 °C.

Explanation:

Answer:

hypothalamus

Explanation:

Answer:

0°C

Explanation:

The melting point of water - the temperature at which solid water begins to melt - is 0°C at a pressure of 1 atm. In the heating curve of water, below 0°C we have solid water. Then, at 0°C the solid water starts to melt by forming liquid water. Above 0°C, when the total amount of water is in the liquid state, the liquid water begins to heat (it increases its temperature).

Answer:

the answer is 0 degrees C.

Explanation:

A germinating seed is one from which a plant has started to grow. A non-germinating seed is usually dry, and a new plant has not yet emerged. The germinating corn seed consumed more oxygen than the non-germinating corn seed. This statement is true.  Therefore, option A is correct.

A dry seed starts to absorb water through its seed coat when it comes into touch with damp soil or growing medium. The seed swells and the seed coat splits open as it absorbs more water. Small shoots and roots make up the embryo inside the seed. First to appear from the seed is the root.

The prerequisites for seed germination include oxygen, water, temperature, and, only for particular seeds, light. The sprouting of seeds is impacted when one or more of these are missing. Similar internal elements that impact this process include seed viability, dormancy, and embryonic maturity.

Thus, option A is correct.

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Answer:

Organessen

Explanation:

The largest element in the nobel gas family is Og, organessen.  Element 188, It has an atomic mass of 294, far ahead of it's closest competitor, Radon (at 222).  Organessen was synthesized in Russia in 2002 and only 6 atoms have been reported.  One may question whether it really should be labelled a nobel gas, but it lies in the correct column.  If giving such a high distinction to such a empheral element makes you queasy, vote for Radon in the next contest.

The correct statement regarding the Hedonic Scale is option b: Participants vote for one of nine codes, which are subsequently totaled and then averaged based on the number of participants.

The Hedonic Scale is a well-established method utilized for the measurement of subjective experiences, encompassing emotions, preferences, or related constructs. It plays a pivotal role in numerous fields, including psychology, market research, and consumer studies.

This approach enables the quantification of subjective experiences or preferences by assigning ratings to specific codes or categories, thus facilitating analysis and providing valuable insights in fields such as psychology, market research, and consumer studies.

In the context of the Hedonic Scale, participants are presented with a set of codes or categories that represent distinct options or aspects. In this case, the scale comprises nine codes. Participants are then requested to select and cast a vote for the code that best reflects their experience or preference.

Following the collection of participant votes, the subsequent step involves the calculation of an overall score or rating. Option b accurately asserts that the scores assigned to each code are aggregated and subsequently averaged based on the total number of participants.

This calculation is performed by summing up the scores for each code and dividing the sum by the total number of participants.

This methodological approach serves to provide researchers with a quantitative understanding of the collective subjective experiences or preferences expressed by the participants.

By analyzing the results, researchers gain valuable insights into the impact and perception of various codes or categories, thereby informing research studies and decision-making processes.

The Hedonic Scale serves as a valuable tool for capturing and assessing subjective experiences within a structured framework, facilitating rigorous analysis and enhancing the depth of understanding in relevant domains.

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The complete question is:

Which of the following statements about the Hedonic Scale is correct?

Select one: a. Participants vote on all nine codes which are totalled and then averaged by the number of participants.

b. Participants vote for one of nine codes which are totalled and then averaged by the number of participants.

c. Participants vote for one of nine codes which are totalled and compared to a standard scoring reference.

d. Participants vote on up to three codes which are totalled and then averaged by the number of participants.