Because of wave refraction, erosion along an irregular coastline is greatest in headlands while deposition is greatest in the embayment's with the net result being that it straightens out the coastline.
What exactly is a refraction wave?Refraction of waves refers to a shift in the direction of waves as they move from one medium to another. Refraction, or the bending of the wave's path, is accompanied by a change in the wave's speed and wavelength.
Any type of wave can refract. For instance, waves in deep water move more quickly than those in shallow water. A light beam is bent or refracted when it travels through a glass prism.
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A kid was drinking a soda. He took a sip, felt something in his mouth, and was stung by a bee on the inside of his cheek. It was very painful! For years afterward, he felt very anxious anytime he went to drink soda. Unconditioned Stimulus, Unconditioned Response, Conditioned Stimulus and Conditioned Response.
Answer:
I think its conditioned response
You want to average 90 km/h on a car trip. You cover the first half of the distance at an
average speed of 48 km/h.
a) What average speed must you have for the second half of the trip to meet your goal?
b) Is this reasonable? Note that the velocities are based on half the distance, not half the
time.
(a) The average speed must you have for the second half of the trip to meet your goal is 8 km/h.
(b) The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
What is average velocity?
Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
average velocity = total distance / total time
v = (d)/(0.5d/v₁ + 0.5d/v₂)
where;
v is the average velocityv₁ is the average velocity during the first halfv₂ is the average velocity during the second half90 km/h = (d) / (0.5d/48 + 0.5d/v₂)
90(0.5d/48 + 0.5d/v₂) = d
0.9375d + 0.5d/v₂ = d
d(0.9375 + 0.5/v₂) = d
0.9375 + 0.5/v₂ = 1
0.5/v₂ = 0.0625
v₂ = 0.5/0.0625
v₂ = 8 km/h
Thus, the average speed must you have for the second half of the trip to meet your goal is 8 km/h.
The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
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question is below............
The total distance traveled by the gardener is 8 meters. the magnitude of total displacement is approximately 7 meters.
Total distance covered by gardener = 2 + 1 +2 + 3= 8 meters
For the magnitude of displacement, we will take the shortest path for the gardener movement.
for displacement-
\(=\sqrt{( 0-4^{2}) +( 6-0^{2} )}\\=\sqrt{52} \\=7\)(approximately)
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can any one help me with this?
Consider the collision between the moving cue ball and the red 15 ball
that is at rest on the table pool. All BUT ONE statement describes what
occurs when the cue ball collides with the 15 ball,
A)
Each ball experiences an equal force directed in
opposite directions,
B)
The 15 ball experiences a rightward force that causes
it to speed up.
The acceleration of the 15 ball is greater than that of
the cue ball.
The moving cue ball experiences a leftward force
that causes it to slow down.
9
D)
From the laws of Newton, the balls experiences an equal force directed in opposite directions.
What is collision?Collision is said to occur when on object bumps into another. Collisions are described by the law of conservation of linear mometum which ststes that momentum is neither created nor destroyed.
The question is incomplete hence we can not fully answer the question. However, from the laws of Newton, the balls experiences an equal force directed in opposite directions.
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How do astronomers determine the surface temperature of stars? *
Answer:
To the extent that Stellar spectra look like blackbodies, the temperature of a star can also be measured amazingly accurately by recording the brightness in two different filters. To get a stellar temperature: Measure the brightness of a star through two filters and compare the ratio of red to blue light.
Explanation:
2) Given circuit...V1= 12VR4= 5.00R7= 3.00R2= 4.00R5= 7.00R3= 5.00R6= 3.00R2a) Find the equivalent resistance of the circuit1V1R3b) Find the current through R2R4R5c) Find the current through R3R6d) Find the power used by R4wR7e) Find the power used by R5f) Find the voltage across R6g) Find the voltage across R7
ANSWERS
a) R = 5.404 Ω
b) IR2 = 1.068 A
c) IR3 = 0.667 A
d) PR4 = 5.703 W
e) PR5 = 1.647 W
f) VR6 = 2 V
g) VR7 = 6.663 V
EXPLANATION
a) To find the equivalent resistance of the circuit we have to see which ones are connected in parallel and which ones are in series.
First we have R2 and R5 in series, so we can find en equivalent resistance that we'll call RA. Also R3 and R6 are series, so that equivalent we'll call RB:
Series resistances have to be added:
\(R_A=R_2+R_5=4+7=11\Omega\)\(R_B=R_3+R_6=5+3=8\Omega\)Then, resistances RB, R4 and RA are parallel. The equivalence we'll call Rc, as shown in the circuit on the right:
\(R_c=\frac{1}{\frac{1}{R_B}+\frac{1}{R_4}+\frac{1}{R_A}}=\frac{1}{\frac{1}{8}+\frac{1}{5}+\frac{1}{11}}\approx2.404\Omega\)Finally R7 and RC are series, so the equivalent resistance of the circuit is:
\(R_{eq}=R_C+R_7=2.404+3=5.404\Omega\)For the following points I'll do them together and separate the information requested in each point.
Voltage across R7 is requested. We can find it with the equivalent circuit B, but first we have to know the total current through the circuit. This is the total equivalent circuit:
The total current is:
\(I=\frac{V}{R_{eq}}=\frac{12}{5.404}\approx2.221A\)We can see in circuit B that Rc and R7 are in series so the current through them is the same. Also, this current is the total current I of the circuit. Therefore we can find the voltage across R7:
\(V_{R7}=I\times R_7=2.221\times3=6.663V\)We can also use this to find the voltage across RC, which will help us find the currents in each resistance:
\(V_{RC}=I\times R_C=2.221\times2.404\approx5.339V\)Now, since RB, R4 and RA are connected in parallel, the voltage across all of them is the same - which is VRC. With this information we can find the currents trough each of these three resistances:
\(I_{R4}=\frac{V_{RC}}{R_4}=\frac{5.339}{5}=1.068A\)\(I_{RA}=\frac{V_{RC}}{R_A}=\frac{5.339}{11}=0.485A\)\(I_{RB}=\frac{V_{RC}}{R_B}=\frac{5.339}{8}=0.667A\)Item d asks for the power in resistence R4 and item e the power used by R5, so now that we have the current in both of them we can find the power they use. Note that the current through R5 is the same as the current through RA, because RA is the equivalente of R5 and R2 in series:
\(P_{R5}=I^2_{RA}\times R_5=0.485^2\times7\approx1.647W\)Power used by R4 is:
\(P_{R4}=I^2_{R4}\times R_4=1.068^2\times5=5.703W\)We have the current through RB, which is the same as the current through R3 (item c) and R6 so we can find the voltage across R6 (item f):
\(V_{R6}=I_{RB}\times R_6=0.667\times3=2V\)We also have the current through R2 (item b) because is the same as the current through RA:
\(I_{R2}=I_{RA}\)Calculate the surface density of atoms in the (111) plane of the body centered cubic lattice. Assume the lattice constant a=5 angstroms. Assume the atoms to be hard spheres, with closest atoms touching each other.
The surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².
To calculate the surface density of atoms in the (1,1,1) plane, we first need to determine how many atoms are in the plane. Since the plane passes through the center of the unit cell, it intersects one-eighth of each of the corner atoms and the full central atom. Therefore, the total number of atoms in the (1,1,1) plane is:
N_atoms = 1 + 8*(1/8) = 2
Next, we need to calculate the area of the (1,1,1) plane. To do this, we can consider the lengths of the sides of the unit cell. Since the BCC lattice has a cubic unit cell, all sides have length a=5 angstroms. The (1,1,1) plane passes through the center of the unit cell and intersects the sides at a 45-degree angle. The distance from the center of the unit cell to the midpoint of one of the sides is a/sqrt(2), so the length of the diagonal of the square face of the unit cell is 2a/√(2) = a√(2). The area of the square face is then (a√(2))² = 2a².
The (1,1,1) plane intersects the square face at a 45-degree angle, so its area is 2*a²/2 = a².
The surface density of atoms is the number of atoms per unit area. Dividing the number of atoms in the (1,1,1) plane by the area of the plane gives:
surface density = N_atoms / area
= 2 / a² = 2 / (5 angstroms)² = 0.16 atoms/angstrom²
Therefore, the surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².
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A bag of blood with a density of 1050 kg/m3 is raised about 1.00 m higher than the level of a patient's arm. How much greater is the blood pressure at the patient's arm than it would be if the bag were at the same height as the arm?
Answer:
A bag of blood with a density of 1050 kg/m4 is raised about 1.00 m higher than the level of a patient's arm. How much greater is the blood pressure at the patient's arm than it would be if the bag were at the same height as the army is the solisan of kind
The increase in the blood pressure in the patient's arm will be 11433.55 Pascal.
What is blood pressure?The power with which your heart pumps blood around your body is measured by your blood pressure. Blood pressure is expressed as two values in millimeters of mercury.
The given data in the problem is;
\(\rm V_1 = V_2\)
\(\rho\) is the density = 1050 \(Kg /m^3\)
h is the level of height higher than the level of a patient's arm = 1.00 m
From the Bernoullis equation the difference in pressure between the two points is found as;
\(P_1+0.5 \times \rho \times {V_1}^2+ \rho g h_1=P_2+0.5 \rho \times V_2 ^2 + \rho \times g \timews h_2\)
\(\rm V_1 = V_2\)
\(\rm P_2-P_1 = 1050 \times g \times (h_1-h_2) \\\\ \rm P_2-P_1 = 1050 \times 9.81 \times (1.11) \\\\ \rm P_2-P_1 =11433.55 \ Paacal\)
Hence the increase in the blood pressure in the patient's arm will be 11433.55 Pascal.
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Which is NOT a function of the skeletal system?
Answer:produces red and white blood cells
Explanation: the bone marrow helps with the blood but cannot produce red and white blood cells
Answer:
"prevents movement of limbs and digits" is NOT a function of the skeletal system.
find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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How many seconds would it take a Dalmatian to accelerate from rest to its
top speed of 16.5 m/s over a distance of 11 meters?
It take 1.33 second to a Dalmatian to accelerate from rest to its top speed.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
given parameters:
initial speed, u = 0
final speed, v =16.5 m/s.
distance covered, s = 11 meters.
We have to find: time t = ?
We know that:
s = ut +(v-u)t/2
⇒ 11 = 0 + (16.5 -0)t/2
⇒ t = 22/16.5 second = 1.33 second.
So, it take 1.33 second to a Dalmatian to accelerate from rest to its top speed.
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In your business plan, the target market section should clearly identify_____market(s).
A. Both your primary and secondary
B. primary
C. demographic
D. secondary
In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.
Janice has just measured the density of an object. Which value is possible? (Density: D = m)
0-1 g/cm
4 m/s
-3 m/s
6 g/cm3
Explanation:
The density of an object can be calculated using the formula as follows :
\(d=\dfrac{m}{V}\)
Here,
m is mass of the object and V is its volume
The mass of an object can b measured in grams and its volume in cubic cm. So, the density of object is measured in g/cm³. Hence, out of given options the possible value of density of an object is 6 g/cm³.
Answer:
The density of an object can be calculated using the formula as follows :
6 g/cm3
Explanation:
good luck xd
describe how electrons create electricity
describe how electrons create electricity
Atoms are made up of even smaller elements, called protons, electrons and neutrons. When electrical and magnetic forces move electrons from one atom to another, an electrical current is formed
Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity. ... In its balanced state, copper has 29 protons in its nucleus and an equal number of electrons orbiting around it.
Hope It Helps!
How do you find the range of a data set?
Answer: You take the biggest number and subtract it from the smallest number.
Explanation: Hope this helps.
Answer:
Subtract the minimum data value from the maximum data value to find the data range.
Explanation:
\(Hope\) \(this\) \(helps!\)
If a person Travels 100 metre due east and then returns to the same place his total displacement is 200. (needed ASAP)
A. True
B. False
Distance is the total path covered by the object
Here, 200 m is the distance covered by the person and NOT the displacement
Displacement of an object is nothing more than the shortest path between the initial and the final point
If the person travelled 100m and came back, his initial and final point will remain the same which means that he will have a displacement of 0 m
A set of charged plates is
separated by 2.22*10^-4 m. When
5.24*10^-9 C of charge is placed
on the plates, it creates a potential
difference of 240 V. What is the
area of the plates?
(The answer is *10^-4 m^2. Just fill
in the number, not the power.)
Answer:
5.49×10¯⁴ m²
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 2.22×10¯⁴ m
Charge (Q) = 5.24×10¯⁹ C
Potential difference (V) = 240 V
Permittivity of free space (ε₀) = 8.85×10¯¹² F/m
Area (A) =?
Thus, the area of the plate can be obtained as follow:
Q = ε₀AV /d
5.24×10¯⁹ = 8.85×10¯¹² × A × 240 / 2.22×10¯⁴
5.24×10¯⁹ = 2.12×10¯⁹ × A / 2.22×10¯⁴
Cross multiply
2.12×10¯⁹ × A = 5.24×10¯⁹ × 2.22×10¯⁴
Divide both side by 2.12×10¯⁹
A = (5.24×10¯⁹ × 2.22×10¯⁴) / 2.12×10¯⁹
A = 5.49×10¯⁴ m²
Thus, the area of the plates is 5.49×10¯⁴ m².
Answer:
it's actually 5.48
Explanation:
Three bulbs are connected in series with a battery and a switch. Do all of the bulbs go out when the switch is opened?
A)yes
B) no
C) it is impossible to know
A professor wants to conduct a study to investigate which kind of note-taking technique (hand-written or computer-based) is better for memory and recollection. He decides to split his class into two groups - hand-written notes and computer-based notes - and measure better memory and recollection via the next exam scores. The two note-taking groups are what variable in the study?
independent variable
dependent variable
control variable
extraneous variable
According to the professor's research, both handwritten notes and computer-based notes qualify as independent variables.
The professor's study considers handwritten notes and computer-based notes to be independent variables. These other qualities will be examined to see if they change depending on note-taking technique, including better memory and exam recall.
What kinds of variables are the groupings for taking notes?
Because they are being examined for their potential to influence other factors, the note-taking groups that use handwritten and computerised notes are regarded as independent variables.
Better exam memory and recall are those other variables, and their changes in response to note-taking methodology will be investigated.
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Why does the modern atomic theory used today represent the best explanation scientists have to offer?
Modern technology supports the current atomic theory.
The model of the atom has not changed much in over 75 years.
The modern atomic theory contains over 200 years of research.
Scientists have not been successful in disproving the atomic theory.
Answer:
The answer is C!
Explanation:
Answer:
C- the modern atomic theory contains over 200 years of research.
Explanation:
A moving object of mass 0.01 kg experiences a drag force proportional to its speed square. The proportionality constant is C. If the object has an initial speed v = 10 m/s and after time T has energy 1/8 m v^2, then find C.
The proportionality constant of the moving object experiencing a drag force is 0.01875 Ns²/m².
How to calculate proportionality constant?The work-energy principle states that the work done on an object is equal to its change in kinetic energy. So, the work done by the drag force can be found as follows:
W = (1/8)mv² - (1/2)mv₀²
where m = mass of the object, v = final speed, and v₀ = initial speed.
The work done by the drag force is also given by the formula:
W = ∫F(x)dx
where F(x) = force function and x = position of the object.
In this case, the force function is F(x) = -Cv², since the drag force is in the opposite direction of motion. So:
W = ∫-Cv²dx
Since the force is proportional to v², rewrite this as:
W = -C∫v²dx
Integrating both sides with respect to x:
W = -(1/3)Cv³
So, equating the two expressions for W:
(1/8)mv² - (1/2)mv₀² = -(1/3)Cv³
Substituting m = 0.01 kg, v₀ = 10 m/s, and solving for C:
C = -(3/8) × (m/v₀³) × (v² - v₀²) = -(3/8) × (0.01/10³) × (1/8 × 10² - 10²) = 0.01875 Ns²/m²
Therefore, the proportionality constant is C = 0.01875 Ns²/m².
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6. Estimate the line width from thermal Doppler broadening for the CaII K line at 393.3 nm for a star with a temperature of 3,000 K and a star with a temperature of 12,000 K. How does temperature affect line broadening
The line width is calculated as 121.6nm
Data;
Wave length = 393.3nmT1 = 3000kT2 = 12,000KRydberg's FormulaThis is used to calculate the wavelength of an electron when it moves from one state to another.
For Lyman series, n = 1
The energy difference in the two state transitioning are
\(n_2\) = ∞
The formula is given thus;
\(\frac{1}{\lambda}= R(1(n_1)^2 - \frac{1}{(n_1)^2}.Z^2\\\)
R = Rydberg's constant
Z = atomic number
Since the excited electron dropped from the 1st state to the ground state, the finest line of Lyman series would be
\(\frac{1}{\lambda} = R(1(1)^2 - \frac{1}{2^2}).1^2\\z=1\\\lambda = \frac{4}{3} * 912A^o\\\lambda = 121.6nm\)
The line width is calculated as 121.6nm
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Describe the environment of Antarctica.
Answer:
Antarctica is a desert. It does not rain or snow a lot there. When it snows, the snow does not melt and builds up over many years to make large, thick sheets of ice, called ice sheets. Antarctica is made up of lots of ice in the form of glaciers, ice shelves and icebergs.
12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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The equation below can be used to find the specific heat capacity of a substance. What is the specific heat capacity if it takes 1000 J of energy to heat 25 g of this substance by 100°C? Give your answer in J/kg°C.
Answer:
400J/kg°C
Explanation:
The specific heat capacity will be 400 J/kg °C. Specific heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
What is specific heat capacity ?The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly
Mathematically, specific heat capacity is given by;
\(\rm C = \frac{E}{m \times \theta }\)
The given data in the problem is;
The specific heat of the substance is,C in J/kg °C.
The energy is,E =1000 JIs
The mass is,m= 25 g
\(\rm \theta\) Is the temperature difference = 100 °C.
On substituting the given data;
\(\rm C = \frac{E }{m \times \theta } \\\\ C = \frac{1000}{25\times 10^{-3} \times 100 } \\\\ C = 400 \ J/kg^0C.\)
Hence, the specific heat capacity will be 400 J/kg °C.
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Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.
Which processes result in the release of carbon? Select three options.
Animals break down food molecules to obtain energy.
The remains of producers are broken down by decomposers.
The remains of consumers are broken down by soil decomposers.
Producers take in carbon dioxide.
Producers make sugars and starches.
Answer:
The remains of producers are broken down by decomposers.
The remains of consumers are broken down by soil decomposers.
Animals break down food molecules to obtain energy.
Explanation:
Answer:
It is A. B. and C.
Explanation:
Hope this helps
A dog with a mass of 57.0 kg slides down a wet slope with negligible friction. The dog starts from rest and has a speed of 2.10 m/s at the bottom. What is the height of the slope (in m)?
The dog starts from rest and has a speed of 2.10 m/s at the bottom. The height of the slope will be 0.225 m
What is friction?Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.
As there is almost zero friction between the total potential energy height is equal to the kinetic energy
m*g*h = 1/2* m*v²
Where m is the mass of the dog
g is the acceleration due to gravity,h is the height of the slope
v is the velocity of the sliding dog
g*h = 1/2* v²
9.81*h = 0.5* 2.1²
=0.225 m
The height of the slope would be 0.225 m.
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