Because linear pairs are complementary, the remaining two angles must also be right angles. true or false?

Answer:

50%

half of the numbers are even

Step-by-step explanation:

The probability of the intersection of two events occurring can never be more than the probability of the union of two events occurring.

False.

It should be stated that the likelihood of the intersection of two events occurring is always less than the likelihood of the events occurring together.

It is always less likely than or equal to the likelihood of either event occurring alone for an intersection of two events, which is the chance that both occurrences take place.

In other words, the probability of the intersection and the probability of the union are subsets of one another.

The chance of the intersection of two events occurring can never be greater than the likelihood of the union of two events occurring, hence that is the right statement.

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First, we have to find the slope

It is an horizontal line

Point-slope form= = y - 6 = 0 (x - 3)

Slope-intercept = y=mx + b,

let's find b

y = 0x + 6

y = 6

2 5/12 or 29/12

hope it helps ?

study well:)

Answer:  Deopends.  See below.

Step-by-step explanation:

-5/12 from 2​

The question is poorly worded.  Is it asking us to subtract -5/12 from 2?  Or are we being asked to subtract 5/12 from 2?

Assuming the first:

2 - (-5/12)

2 + 5/12

2 5/12 or 24/12 + 5/12 = 29/12

Assuming the second:

2 -5/12

24/12 - 5/12

19/12

Roy's younger brother's age is 11 years.

According to the question,

We have the following information:

If Roy is 4 years older than his brother and the product of their ages is 165.

Now, let's take the age of Roy's younger brother to be x years.

Age of Roy = 4+x

So, we have the following expression:

x(4+x) = 165

\(x^{2} +4x-165=0\)

Now, we will factorize this equation by splitting the middle term:

\(x^{2}\)+15x-11x-165 = 0

Now, taking x as a common factor from the first two terms and -11 as a common factor from the last two terms:

x(x+15)-11(x+15) = 0

Taking (x+15) as a common factor:

(x+15) (x-11) = 0

x+15 = 0 and x-11 = 0

x = -15 and x = 11

Now, we know that age can not be negative.

Hence, Roy's younger brother is 11 years old.  

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Answer:

Depends on how specific you need it to be, but it is 3.87 round as you need to

Step-by-step explanation:

Please mark brainlest

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) \(\sqrt{32} = 2^{\frac{5}{2} }\)

\(2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ = \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}\)

Thus, the equation is TRUE.

(2) \(16^{\frac{3}{8} } = 8^2\)

\(16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64\)

Thus, the equation is FALSE.

(3) \(4^{\frac{1}{2} } = \sqrt[4]{64}\)

\(4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64} = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2} \times \sqrt{2} \times \sqrt{2} ) = 2\sqrt{2}\)

Thus, the equation is FALSE.

(4) \(2^8 = (\sqrt[3]{16} )^6\)

\(2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256\)

Thus, the equation is TRUE.

(5) \((\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\\)

\(8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4\)

Thus, the equation is FALSE.

The value of C, which represents the upper control limit (UCL) for the X-bar chart in the process of filling baby formula into bottles, is approximately 3.40552. This means that any average amount of baby formula above this limit may indicate a process out of control and require investigation.

To determine the value of C in this scenario, we need to use the formula for the control chart limits for an X-bar chart. The control limits for an X-bar chart with sample size n can be calculated using the following formula:

Upper Control Limit (UCL) = mean + A2 * R

Lower Control Limit (LCL) = mean - A2 * R

In this case:

The target value for the baby formula is 3 ounces.

The average amount of baby formula placed in the bottles is 2.941 ounces (mean).

The sample size is 200 bottles.

The standard deviation of the amounts is 0.1 ounce.

To calculate the value of C, we need to determine the value of A2, which depends on the sample size. The value of A2 can be found in statistical tables or calculated using statistical software. For a sample size of 200, A2 is typically 2.574.

Using the formula for the control limits, we can calculate the upper and lower control limits:

UCL = mean + A2 * R

= 2.941 + 2.574 * 0.18

= 2.941 + 0.46452

= 3.40552

LCL = mean - A2 * R

= 2.941 - 2.574 * 0.18

= 2.941 - 0.46452

= 2.47648

The value of C is the value of the upper control limit (UCL) in this case, which is approximately 3.40552.

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Answer:

9 is the answer to that question

The proportion of people aged 7 to 18 years gave watching television as their favorite type of leisure activity is 300/2,200

There are 900+1,300=2,200900+1,300=2,200 people aged 7 to 18 years.

200 of those people are aged 7 to 12 years and

100 of those people that are aged 13 to 18 years gave watching television as their favorite leisure activity,

so 200+100=300  200+100=300 of the people aged 7 to 18 years gave watching television as their favorite leisure activity.

Thus the proportion of people aged 7 to 18 years who gave watching television as their favorite leisure activity is 300/2,200

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There is no significant difference in the proportion of college enrollees between females and males who have completed high school within the past 12 months.

To determine if the difference in proportions is statistically significant or if it could be due to chance.

We will conduct a hypothesis test. Our null hypothesis (H₀) is that there is no difference in the proportion of college enrollees between females and males. Our alternative hypothesis (H₁) is that there is a difference in the proportion of college enrollees between females and males.

We can use a two-sample z-test to test this hypothesis. The formula for the test statistic is:

z = (p₁ - p₂) / √(p'* (1 - p') * ((1 / n₁) + (1 / n₂)))

where p₁ and p₂ are the sample proportions, p' is the pooled proportion, n₁ and n₂ are the sample sizes.

Given, p₁ = 0.72, p₂ = 0.65, n₁ = 175, n₂ = 160

p' = (x₁ + x₂) / (n₁ + n₂)

x₁ = 126 (0.72 * 175) and x₂ = 104 (0.65 * 160).

p' = (126 + 104) / (175 + 160) = 0.684

By applying the above values we get,

z = (0.72 - 0.65) / √(0.684 * (1 - 0.684) * ((1 / 175) + (1 / 160))) ≈ 2.11

The critical value for a two-tailed test with alpha = 0.01 is approximately ±2.58. Since our calculated z-value (2.11) is less than the critical value, we fail to reject the null hypothesis. This means that there is not enough evidence to conclude that there is a significant difference in the proportion of college enrollees between females and males.

Therefore, there is no significant difference in the proportion of college enrollees between females and males who have completed high school within the past 12 months.

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As a result, the solution is 8 miles 56 yards times 28 is 0.2863636 miles, or around 0 miles 504 yards.

The majority of a yard will likely be a grassland or play area. The area behind a home is alluded to as the backyard, and the yard in front is referred to as the front yard. Since backyards tend to be more private, they are more frequently used as recreational spaces. The size of the yard varies with density of population.

Starting with 8 miles 56 yards, we can change it to just yards, which is:

8 × 1760 + 56 = 14136 yards.

Then, we may convert 14136 yards to yards by multiplying 28.

14136 yards ÷ 28 = 504 yards.

504 yards must now be converted back to kilometers and yards. Since 1 mile is equal to 1760 meters, we can calculate the distance by multiplying 504 by 1760:

504 yards ÷ 1760 yards/mile = 0.2863636 miles (rounded to 7 decimal places).

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Answer:

D. x - 4

Step-by-step explanation:

(x - 4)(x + 10)

= x^2 + 6x - 40

A factor is something that multiplies together with something else to get a product. Here the factors are binomials and the product is a trinomial.

Answer:

volume 1= 175 ft^3

volume 2= 60 m^3

Step-by-step explanation:

volume 1= [(3×7)+(2×(7-5))]×7= 175 ft^3

volume 2= [(3×6)+(1×2)]×3= 60 m^3

Each portion was greater than 13 pound. The correct option is D.

We can solve this problem by setting up an inequality based on the information given.

Let x be the size of each portion of flour that William used. Then, he used 3 portions, so the total amount of flour he used is 3x.

According to the problem, he had less than 7 pounds of flour left after using the portions. So, we can write:

\(8 - 3x < 7\)

Simplifying this inequality, we get:

\(3x > 1\)

Dividing both sides by 3, we get:

\(x > 1/3\)

Therefore, each portion was greater than 1/3 of a pound, which is equivalent to 5.33 ounces.

Among the answer choices, the statement that BEST describes the size of the portions is option D: Each portion was greater than 13 pounds. This is because option D is the only one that is always true given that each portion is greater than 1/3 of a pound. Option B is too small, option A is too small and, in any case, less than 13 pounds, and option C is too large since 3 portions greater than 213 pounds would exceed the initial amount of flour William had.

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A swimming pool is 20.6m long, 8.5m broad, and has a water depth of 1.7m on average. The volume of water needed to fill the pool is 297.67 m³.

First we need to find the volume of the pool

length = 20.6

breadth = 8.5

height= 1.7

Volume of the pool = length × breadth × height

= 20.6 × 8.5 ×1.7

= 297.67 m³

volume of water needed to fill the pool = volume of the pool

= 297.67 m³

Volume is a three-dimensional space measurement. It is frequently numerically quantified using SI derived units (such as the cubic metre and litre) or other imperial or US customary measures (such as the gallon, quart, and cubic inch).

Volume is connected to the notion of length (cubed). The volume of a container is commonly believed to be its capacity; that is, the amount of fluid (gas or liquid) that the container can hold, rather than the amount of space that the container occupies.

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Answer: do you still need help

Step-by-step explanation:

Expression is a combination of numbers, variables and operators. x=14 is the solution of the expression x/2 + 4 = 11 .

Expression is a combination of numbers, variables and operators.

The given expression is x/2 + 4 = 11

x by two plus four equal to eleven.

here x is the variable

We have to keep variables on one side and numbers on other side.

Let us subtract 4 on both sides

x/2+4-4=11-4

x/2=7

Multiply two on both the sides

2(x/2)=7×2

x=14.

Among the solution -16 or -4 or 20 or 10. we dont have any value which is 14. Hence the solution is none of them.

Therefore the value of x is 14.

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Answer:

23

Step-by-step explanation:

the difference between each number in the sequence is 4. Taking 4 away from 27 gives you 23

Hope this helps!

The ball will be in the air for approximately 0.07 seconds.

To find the time the ball will be in the air, we need to determine when the height of the ball is equal to zero since the ball will hit the ground at that point.

Given:

Initial height, c = 3.5 feet

Initial velocity, v = 50 feet/second

We can substitute these values into the equation h(t) = -16t² + vt + c and solve for t when h(t) = 0.

0 = -16t² + 50t + 3.5

To solve this quadratic equation, we can use the quadratic formula:

t = (-b ± √(b² - 4ac)) / (2a)

In this case, a = -16, b = 50, and c = 3.5.

t = (-(50) ± √((50)² - 4(-16)(3.5))) / (2(-16))

Simplifying further:

t = (-50 ± √(2500 + 224)) / (-32)

t = (-50 ± √(2724)) / (-32)

Now, we can calculate the values inside the square root:

t = (-50 ± √(2724)) / (-32)

t = (-50 ± 52.2) / (-32)

This gives us two possible values for t:

t₁ = (-50 + 52.2) / (-32) ≈ 0.07 seconds

t₂ = (-50 - 52.2) / (-32) ≈ - 3.23 seconds

Since time cannot be negative in this context, we discard t₂.

Therefore, the ball will be in the air for approximately 0.07 seconds.

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Given

a) sin A = 0.4848

b) cos Y = 0.7431

c) cos X = 0.4226

d) tan B = 19.0811

To find:

Each angle measure to the nearest degree.

Explanation:

It is given that,

a) sin A = 0.4848

b) cos Y = 0.7431

c) cos X = 0.4226

d) tan B = 19.0811

That implies,

a) sin A = 0.4848.

Then,

b) cos Y = 0.7431.

Then,

c) cos X = 0.4226.

Then,

d) tan B = 19.0811.

Then,

Hence, the measure of each angle is,

a) A = 30°.

b) Y = 42°.

c) X = 65°.

d) B=87°.

The correct option for the midpoint of the line segment , where (-1,-2) and (4,-2), is  (1.5,-2).

To find the midpoint of a line segment, we use the midpoint formula, which states that the coordinates of the midpoint (M) are the average of the coordinates of the endpoints.

The midpoint formula is given by:

M = ((x1 + x2) / 2, (y1 + y2) / 2)

Let's apply this formula to find the midpoint of the line segment AB:

x1 = -1, y1 = -2 (coordinates of point A)

x2 = 4, y2 = -2 (coordinates of point B)

Using the midpoint formula:

M = ((-1 + 4) / 2, (-2 + (-2)) / 2)

 = (3 / 2, -4 / 2)

 = (1.5, -2)

Therefore, the midpoint of the line segment , with endpoints (-1,-2) and (4,-2), is (1.5, -2).

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Answer:

<ABD = 42 degrees

<ABC = 84 degrees

Step-by-step explanation:

<ABC = 42 + 42 = 84

Answer:

-0.8

Step-by-step explanation:

Given that :

Mean of test score, m = 72

Standard deviation of test score, σ = 5

Trainee's score, x = 68

Since the distribution is Symmetric ;

The Zscore Cann be calculated thus :

Zscore = (x - mean) / standard deviation

Zscore = (68 - 72) / 5

Zscore = - 4 / 5

Zscore = - 0.8

The simplified rational expression for this problem is given as follows:

\(\frac{3\sqrt{21} + 13}{12}\)

The rational expression in the context of this problem is defined as follows:

\(\frac{\sqrt{7} + \sqrt{3}}{2\sqrt{3} - \sqrt{7}}\)

The first step in simplifying the expression is removing the root from the denominator, multiplying numerator and denominator by the conjugate, as follows:

\(\frac{\sqrt{7} + \sqrt{3}}{2\sqrt{3} - \sqrt{7}} \times \frac{2\sqrt{3} + \sqrt{7}}{2\sqrt{3} + \sqrt{7}}\)

Applying the subtraction of perfect squares, the denominator is given as follows:

2² x 3 - 7 = 12.

The numerator is:

\((\sqrt{7} + \sqrt{3})(2\sqrt{3} + \sqrt{7}) = 2\sqrt{21} + 7 + 6 + \sqrt{21} = 3\sqrt{21} + 13\)

Thus the simplified expression is:

\(\frac{3\sqrt{21} + 13}{12}\)

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Answer: A ruler and a protracor

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Initially, there were 80 runners in the race. After the first half, 1/5 of them dropped out (given). Therefore, 4/5*80=64 runners remain. In the second half, 5/8 of these 64 runners drop out, meaning 3/8*64=24 runners finished the race.

Answer:

Step-by-step explanation:

You want to put this linear equation into slope intercept form.

So you would add 2y to both sides to get it on the other side.

\(2y=1+14x\)

Now you are going to divide both sides by 2 to get y by itself.

\(y=7x+\frac{1}{2}\)

Mr. Titus travels a total of 7476 miles annually between Charlotte, North Carolina, and New York City.

Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication, and division.

Given that twelve times a year, Mr. Titus makes the trip from Charlotte to New York City and back. Each round trip covers a total distance of 623 miles.

The total distance will be calculated as:-

Distance = 12 x 623

Distance = 7476 miles

Therefore, Mr. Titus' annual mileage between Charlotte, North Carolina, and New York City is 7476 miles.

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