△BCD≅△GEF
. If BC=10
, CD=3x+8
and EF=4x+6
, then what is the measure of CD
?

Answer:

If there is a very weak correlation between two variables, then the coefficient of determination (R-squared) must be low as well.

This is because the coefficient of determination measures the proportion of variance in the dependent variable that can be explained by the independent variable(s).

When the correlation between the variables is weak, there is less variance in the dependent variable that can be explained by the independent variable(s), resulting in a lower R-squared value. So, the answer is "low".

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Answer:

40+33x+24xy

chile who gave you this problem?

Answer:

61& 7/20

Step-by-step explanation:

There are 90 different ways in which the four scholarships can be distributed such that at least two are awarded to freshman students.

We first need to determine the number of ways in which we can choose two of the six freshman students to receive scholarships. This can be done using the binomial coefficient formula: \(${6 \choose 2} = 15$\).

Next, we need to determine the number of ways in which we can choose two of the four sophomore students to receive scholarships. This can also be done using the binomial coefficient formula: \(${4 \choose 2} = 6$\)

Finally, we need to multiply these two values together to get the total number of ways in which the scholarships can be distributed: 15 * 6 = 90. Therefore, there are 90 different ways in which the four scholarships can be distributed such that at least two are awarded to freshman students.

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a. ΔABE: is a Right Angled Triangle (Has angle 90°)

b. ΔBEC: is an Isoceles Triangle (Has two sides equal)

c. ΔDEF: is an Equilateral Triangle (Has all sides equal)

d. ΔCDF: is a Scalene Triangle (Has no sides equal)

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon.

Triangles can be classified based on the length of the sides or their angle measurements.

The types of triangles based on the length of the sides are –

ΔABE: Right Angled Triangle (Has angle 90°)

ΔBEC: Isoceles Triangle (Has two sides equal)

ΔDEF: Equilateral Triangle (Has all sides equal)

ΔCDF: Scalene Triangle (Has no sides equal)

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For acceptable x values of √12(x-1)+√√2(x-1)², the option is equivalent to the quotient given here (x-1) ² is \($2 \sqrt{3} \sqrt{x-1}-\sqrt{2}(x-1)$\\\) .

The equivalent of the quotient displayed above for allowable x values is

\($\sqrt{1} \cdot 2(x-1)+\sqrt{\sqrt{2}}(x-1)^2$\)

\($2(x-1)+\sqrt[2 \cdot 2]{2}(x-1)^2$\\\)

\(\$2(x-1)+\sqrt[4]{2}(x-1)^2$\\$(2 x-2)+\sqrt[4]{2}\left(x^2+2 x(-1)+(-1)^2\right)$\\$(2 x-2)+\sqrt[4]{2}\left(x^2-2 x+1\right)$\\$2 x-2+\sqrt[4]{2}\left(x^2-2 x+1\right)$\\$2 x+\sqrt[4]{2}\left(x^2-2 x+1\right)-2$\\$2 x+\left(\sqrt[4]{2} \cdot x^2-\sqrt[4]{2} \cdot 2 x+\sqrt[4]{2}\right)-2$\\$2 x+\left(\sqrt[4]{2} \cdot x^2-2 \cdot \sqrt[4]{2} \cdot x+\sqrt[4]{2}\right)-2$\\$2 x+\sqrt[4]{2} \cdot x^2-2 \cdot \sqrt[4]{2} \cdot x+\sqrt[4]{2}-2$\)

\($f(x)=\sqrt{12(x-1)}-\sqrt{2(x-1)^2}$\)

\($\frac{d}{d x}\left(\sqrt{12(x-1)}-\sqrt{2(x-1)^2}\right)$\)

\($\sqrt{12(x-1)}-\sqrt{2(x-1)^2}=2 \sqrt{3} \sqrt{x-1}-\sqrt{2}(x-1)$\)

\($\sqrt{12(x-1)}-\sqrt{2(x-1)^2}$\)

\($\sqrt{12(x-1)}=2 \sqrt{3} \sqrt{x-1}$\)

\($\sqrt{2(x-1)^2}=\sqrt{2}(x-1)$\\$=2 \sqrt{3} \sqrt{x-1}-\sqrt{2}(x-1)$\\\)

Values that might result in a fraction's denominator being equal to zero are excluded. Finding these omitted values is crucial for resolving a rational statement because you cannot divide by 0.

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Answer:

16.28

Step-by-step explanation:

Option d) is correct- No, the data are normally distributed, but there are outliners.

A sample is characterised as a more manageable and compact version of a bigger group. A smaller population that possesses the traits of a bigger group. When the population size is too big to include all participants or observations in the test, a sample is utilised in statistical analysis.

An outlier is a data point that lies outside the overall pattern in a distribution.

In a real-world example, the average height of a giraffe is about 16 feet tall. However, there have been recent discoveries of two giraffes that stand at 9 feet and 8.5 feet, respectively. These two giraffes would be considered outliers in comparison to the general giraffe population.

in this question, the data are normally distributed, but there are outliners.

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Answer:

2,2

Step-by-step explanation:

Answer:

2,3

Step-by-step explanation:

Draw it on a coordinate grid...

Answer:

D

Step-by-step explanation:

if a<b,then b<a is the answer

So a 4-input and gate has 16 possible combinations of binary output, 5 inputs would be 32 outputs, and so on.

Combinations are also called selections. Composition is the selection of one thing from a given set of things. We're not going to fix things here. We will choose them. We note nCr the number of r-choices or unique combinations among a set of n subjects.

Design Procedure:

Step 1:. Derive a truth table that defines the desired relationship between inputs and outputs.

Step 2: Obtain the simplified Boolean function of each output according to the input variables. The simplified expression for the

map is:

A= w

The simplified expression for the map is:

B=w' y+ xz+ wx

Step3. Draw the logic diagram and the binary output are:

A= w

B=w ′y+ xz + wx

C=w ′x ′y ′ +w ′y ′z ′ +xyz + wy

D=x ′z+ w ′xz ′ + wz

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let's call that point C, thus we get the splits of AC and CB

\(\textit{internal division of a line segment using ratios} \\\\\\ A(0,0)\qquad B(6,9)\qquad \qquad \stackrel{\textit{ratio from A to B}}{2:1} \\\\\\ \cfrac{A\underline{C}}{\underline{C} B} = \cfrac{2}{1}\implies \cfrac{A}{B} = \cfrac{2}{1}\implies 1A=2B\implies 1(0,0)=2(6,9)\)

\((\stackrel{x}{0}~~,~~ \stackrel{y}{0})=(\stackrel{x}{12}~~,~~ \stackrel{y}{18}) \implies C=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{0 +12}}{2+1}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{0 +18}}{2+1} \right)} \\\\\\ C=\left( \cfrac{ 12 }{ 3 }~~,~~\cfrac{ 18}{ 3 } \right)\implies C=(4~~,~~6)\)

Answer:

x-int=(-1,0) y-int=(0,2)

Step-by-step explanation:

because on the x axis (x,y) xis on 1 and on the y is on 2 so then fill in the blanks with a zero.

Answer: (-1, 0)

Step-by-step explanation: The x-intercept is the point

on the graph where the line crosses the x-axis.

So the x-intercept for the line in this graph is (-1, 0).

All x-intercepts have a y-coordinate of zero.

Answer:

6/1 · 11/4 = 66/4 = 16 1/2

-10/3 · (-17/5) = 170/15 = 11 1/3

-9/2 · 26/3 = -234/6 = -39

11/6 · (-9/1) = -99/6 = -16 1/2

When the tangent of an angle is given, we need to use the inverse tangent function or arctan function to find the radian measure of the angle. Here are the steps to find the radian measures of angles whose tangent is -0.73:

Step 1: Find the inverse tangent of -0.73 using a calculator or table of values.

Step 2: Add π radians to the result from Step 1 to find the other angle in the second quadrant with the same tangent.π + arctan(-0.73) ≈ 2.4908 radians

Step 3: Subtract π radians from the result from Step 1 to find the other angle in the fourth quadrant with the same tangent.

Therefore, the radian measures of all angles whose tangent is -0.73 are approximately -3.7922 radians, -0.6514 radians, and 2.4908 radians.

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the linear momentum of the particle when x = 8 m is approximately 8.06129 Ns.

To find the linear momentum when x = 8 m, we need to calculate the vertical velocity component vy at that position. Using the equation for y(x) = -4sin(2x), we can differentiate it with respect to x to find the vertical velocity component vy.

By differentiating y(x) = -4sin(2x) with respect to x, we obtain vy = -8cos(2x).

Substituting x = 8 into vy = -8cos(2x), we get vy = -8cos(16).

Now, we can calculate the linear momentum p by multiplying the mass (m = 4 kg) with the magnitude of the velocity vector, which is given by the square root of the sum of the squares of the horizontal and vertical velocity components.

Using the given values, p = 4 × \(\sqrt{vx^{2} +vy^{2} }\) = 4 × \(\sqrt{2^{2} }\) + \((-8cos(16))^{2}\)

Evaluating this expression, we find p ≈ 8.06129 Ns.

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Answer:

  A.  -5

Step-by-step explanation:

You want the slope of a graphed line that crosses grid points (0, 2) and (1, -3).

The sign of the slope is positive if the line goes up to the right. This line goes down to the right, so the sign of its slope is negative. (Eliminates choices C and D)

The magnitude of the slope is the ratio of vertical distance to horizontal distance between two points. This line drops 5 vertical squares for each square to the right, so its slope is ...

  rise/run = -5/1 = -5

The slope is best represented by -5.

__

Additional comment

From a point on the line that is a crossing of grid lines, if the line crosses the next vertical grid line before it crosses the next horizontal grid line, the magnitude of its slope is less than 1.

Here, the line crosses several horizontal grid lines before it crosses another vertical grid line, so its slope has a magnitude greater than 1. When the choice is between -5 and -1/5, the larger magnitude number is -5.

From two points on the line, you can find the slope using the formula ...

  m = (y2 -y1)/(x2 -x1)

  m = (-3 -2)/(1 -0) = -5/1 = -5 . . . . . . using points (0, 2) and (1, -3)

Answer:

Area = 156.25 Square Feet

Price = $4,373.44

Step-by-step explanation:

Here's ur perfect answer

One possible value of ∠U is 80° (to the nearest degree).

A triangle is a three-sided polygon with three vertices. The triangle's internal angle, which is 180 degrees, is constructed.

To find the possible values of ∠U, we can use the Law of Cosines:

c² = a² + b² - 2ab cos(C)

Where c is the side opposite the angle we want to find (∠U), a and b are the other two sides, and C is the angle opposite side c.

In this case, we want to find ∠U, so we'll use side u as c and sides t and s (which we don't know yet) as a and b, respectively:

u² = t² + s² - 2ts cos(U)

Substituting the given values, we get:

340² = 620² + s² - 2(620)(s)cos(U)

Simplifying:

115600 = 384400 + s² - 1240s cos(U)

Subtracting 384400 and rearranging:

s² - 1240s cos(U) + 268800 = 0

Now we can use the quadratic formula to solve for s:

s = [1240 cos(U) ± √(1240² cos²(U) - 4(1)(268800))]/(2)

Simplifying under the square root:

s = [1240 cos(U) ± √(1537600 cos²(U) - 1075200)]/(2)

s = [1240 cos(U) ± √(409600 cos²(U) + 1742400)]/(2)

s = [620 cos(U) ± √(102400 cos²(U) + 435600)]

Since s must be positive, we can discard the negative solution, and we have:

s = 620 cos(U) + √(102400 cos²(U) + 435600)

Now we can use the fact that the sum of angles in a triangle is 180° to find ∠U:

∠U = 180° - ∠T - ∠S

Since we know ∠T = 110°, we just need to find ∠S. We can use the Law of Sines to do this:

sin(S)/s = sin(T)/t

sin(S) = (s/t)sin(T)

Substituting the values we know:

sin(S) = (620 cos(U) + √(102400 cos²(U) + 435600))/620 * sin(110°)

sin(S) ≈ (1.481 cos(U) + 2.225)/6.959

Now we can use a calculator to find the arcsin of both sides to get ∠S:

∠S ≈ arcsin((1.481 cos(U) + 2.225)/6.959)

Finally, we can substitute the values we found for ∠S and ∠T into the equation we found earlier for ∠U:

∠U = 180° - 110° - arcsin((1.481 cos(U) + 2.225)/6.959)

Simplifying:

∠U = 70° - arcsin((1.481 cos(U) + 2.225)/6.959)

Now we can use trial and error or a graphing calculator to find the values of ∠U that satisfy this equation. One possible solution is:

∠U ≈ 80°

Therefore, one possible value of ∠U is 80° (to the nearest degree).

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Answer:

Wendy does not have enough of money to cover the price of everything

Step-by-step explanation:

If Wendy has $30 and wants to but 5 pairs of socks that cost $1.99($2.00) each and a scarf for $20.49, she wouldn't have enough of money because the 5 pairs of socks would be $10 and if you subtract that from $30, she would only have $20 dollars left, so she wouldn't have enough money to pay for the socks and scarf, which also means she would only have to pick one of the two items she wants, either she pays for the socks, or she pays for the scarf, but she can't pay for both.

A period is the difference in x over which a sine function returns to its equivalent state and the amplitude is A/5.

Amplitude:

The amplitude of a periodic variable is a measure of its change over a period of time, such as a temporal or spatial period. The amplitude of an aperiodic signal is its magnitude compared to a reference value. There are various definitions (see below) of amplitude, which is any function of the magnitude of the difference between the extreme values ​​of a variable. In the previous text, the phase of a periodic function is called the amplitude.

                       X = A sin (ω[ t - K]) + b

A is the amplitude (or peak amplitude),

x is the oscillating variable,

ω  is angular frequency,

t is time,

K and b are arbitrary constants representing time and displacement respectively.

According to the Question:

An equation does not have an amplitude. This "equation" represents the formula of a vibration, and was better written as:

X= A/5* sin(1000.t + 120)

These oscillations have a certain amplitude. X values ​​can vary from minimum to maximum. Normally, the stop position of the oscillation is X=0. In this case, we can see that the maximum occurs when the sine is +1 and the minimum occurs when the sine is -1.

For theses cases X= A/5 respectively -A/5.

Therefore,

The amplitude is A/5.

For formulas of this type, the term in front of the sinus (or cosine) is equal to the amplitude.

Complete question:

Can I find the amplitude of this equation? A/5 *